What if we minned astroids

AnswerAnswerAnswerAnswerAnswer:0.3571m

Explanation:

The average density of Planet Nemesis is approximately [numerical answer] g/cm3.

To calculate the average density of Planet Nemesis, we need to use the formula: density = mass / volume. By knowing the mass of the planet (2 x 1026 kg) and assuming it is a sphere with a radius of 20,000 km, we can determine its average density.

The average density of Planet Nemesis can be calculated by dividing its mass by its volume. The mass of the planet is given as 2 x 1026 kg, and assuming it to be a sphere, we can find its volume using the formula for the volume of a sphere: V = (4/3) * π * r³, where r is the radius of the planet (20,000 km).

Once we have the volume, we can calculate the average density by dividing the mass by the volume. By converting the units, we can express the density in g/cm3.

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The average density of Planet Nemesis is 5.22. The orbital speed of Caprica is 5.93 km/s.

1. To calculate the average density of Planet Nemesis, use the formula:

density = mass/volume.

The volume of a sphere can be calculated using the formula:

volume = (4/3)πr^3.

For Planet Nemesis, the volume is (4/3)π(20,000 km)^3. Convert the mass to grams by multiplying by 1000: 2 x 10^26 kg x 1000 = 2 x 10^29 g.

Then, calculate the density: (2 x 10^29 g)/volume. The numerical value of the average density is approximately 5.22.

2. To find the orbital speed of Planet Caprica, use the formula:

orbital speed = 2πa/T,

where a is the semi-major axis (distance from the host star) and T is the orbital period.

Convert the distance from AU to km: 20 AU x 1.496 x 10^8 km/AU = 2.992 x 10^9 km.

The orbital speed is then (2π(2.992 x 10^9 km))/100 years.

Convert the orbital period to seconds: 100 years x 3.1536 x 10^7 s/year = 3.1536 x 10^9 s.

Finally, calculate the orbital speed: (2π(2.992 x 10^9 km))/(3.1536 x 10^9 s). The numerical value of the orbital speed is approximately 5.93 km/s.

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without additional information about the object's position, we cannot determine the exact location of the image.

To determine the position of the image formed by a lens with a focal length of f = -125 mm, we need to apply the sign conventions used in lens imaging.

In the sign convention:

Distances measured from the lens towards the object are positive.

Distances measured from the lens towards the image are negative.

Focal length (f) is positive for a converging lens (convex) and negative for a diverging lens (concave).

Since the given focal length is f = -125 mm (negative value), we know that we are dealing with a diverging lens.

Now, without specific information about the object's position, we cannot determine the exact location of the image. The position of the image depends on the location of the object relative to the lens.

If the object is placed beyond the focal point (f) of a diverging lens, the resulting image is virtual, upright, and located on the same side as the object. The image will be magnified and appear smaller than the object.

If the object is placed between the focal point (f) and the lens, the resulting image is virtual, upright, and located on the same side as the object. The image will be magnified and appear larger than the object.

If the object is placed at the focal point (f), the rays of light become parallel after passing through the lens, and no real image is formed.

If the object is placed closer to the lens than the focal point (f), the resulting image is virtual, upright, and located on the same side as the object. The image will be magnified and appear larger than the object.

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The wavelength of this 512-hertz sound wave traveling through air at STP is approximately 0.67 meters.

To calculate the wavelength of a 512-hertz sound wave traveling 100 meters through air at STP (Standard Temperature and Pressure), we will use the formula:
wavelength (λ) = speed of sound (v) / frequency (f)
First, we need to find the speed of sound in air at STP, which is approximately 343 meters per second.
Next, we have the frequency (f) of the sound wave, which is given as 512 hertz.
Now, we can use the formula to find the wavelength:
λ = v / f
λ = 343 m/s / 512 Hz
λ ≈ 0.67 meters.

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Answer:

Iron expands because heating increases the space between the molecules

Explanation:

According to the kinetic molecular theory, all matter is composed of atoms and molecules which are in constant motion.

When a substance is heated, molecules of the substance begin to vibrate faster. This faster vibration leads to increased space between the molecules (expansion) . The kind of motion motion and degree of spacing of the molecules determine the state of matter in which the substance is found.

Hence, when an iron bar is heated, it expands due to increased motion of its molecules leading to spaces between them.

Answer:

If you're looking for an answer in m/s then 8.33.. ms^-1

Explanation:

To determine average speed then we simply need to divide the total distance travelled by the total time it took to travel that distance.

I.e. 250/30=8.33m/s

To convert this to km/h we simply need to multiply the answer in m/s by 3.6 which gives us approximately 30km/h

The sky diver falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall.

What is Acceleration?

Acceleration is the rate of change of velocity over time. It is basically a vector quantity, meaning it has both magnitude and direction. Acceleration is caused by a force and is measured in meters per second squared (m/s2).

a) The speed of the skydiver when the parachute opens can be found by using the equation

v=gt,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the speed.

v=gt

v=(32ft/s^2)(10s)

v=320ft/s

b) The distance fallen before the parachute opens can be found by using the equation

s=1/2gt^2,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the distance.

s=1/2gt^2

s=(1/2)(32ft/s^2)(10s)^2

s=16000ft.

c) The limiting velocity after the parachute opens can be found by using the equation

v_L=√(2mg/ρA)

where m is the mass of the skydiver, g is the acceleration due to gravity, ρ is the density of air, and A is the projected area of the parachute.

We can substitute the given values into the equation to find the limiting velocity.

v_L=√(2(180lb)(32ft/s^2)/(1.225kg/m^3)(6m^2))

v_L=30.68ft/s.

d) The time the sky diver is in the air after the parachute opens can be found by using the equation

t=v/a

where v is the initial velocity, and a is the acceleration due to air resistance.

We can substitute the given values into the equation to find the time.

t=v/a

t=(320ft/s)/(12ft/s^2)

t=26.67s.

So, the sky diver is in the air for 26.67s after the parachute opens.

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a) In two cases is the change in momentum Δ\(P_{B}\) is largest Δ\(P_{B}\) greater than Δ\(P_{A}\).

b) Change of momentum is larger in case B than case A when average force involved.

c)  Pi ≠ Pf initial momentum of the ball is not equal to final momentum of the ball, momentum not conserved in this collision.

Momentum is best described as strength or force gained through motion or a sequence of events. Rolling down the hill, the waggon gained speed.

Concept: Body of mass m moves with a velocity u towards a rest object, if it bounces back with same velocity, the change in momentum is,

ΔP = mu - (mu)

ΔP = 2mu

a) Case A- A ball of mass m thrown with a velocity u against the wall and the ball doesn't bounce back Hence its returns velocity is o

Thus, change in momentum of the ball in this case is,

Δ\(P_{A}\) = mu - m(0)

Δ\(P_{A}\) = mu  (1)

Case B- A Same ball of mass m thrown with a velocity u against the will and the ball bounce back with same velocity, Hance its returns velocity is (-u)

This change in momentum of the ball in this call is,

Δ\(P_{B}\) = mu - m(-u)

Δ\(P_{B}\) = 2mu  (2)

As, Δ\(P_{B}\) greater than Δ\(P_{A}\)

The change in momentum in case B is larger than case A

b) As change in momentum is product of average force exerted with time of for which momentum change takes place. For some time involved in both cases, change of momentum is directly proportional to avenge force exerted

But is change of momentum is larger in case B than case A

c) Case A:- Initial momentum of the ball Pi = mu

Final momentum of the ball Pf = m(0) = 0

As Pi & Pf Initial momentum of the ball is not equal to final momentum of the ball, momentum not conserved in this collision

Case B  initial momentum of the ball Pi = mu

Final momentum of the ball Pf = m(-u) = -mu

As, Pi ≠ Pf initial momentum of the ball is not equal to final momentum of the ball, momentum not conserved in this collision.

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A third positive charge \(x = \frac{2\sqrt{2}a }{1+\sqrt{2} }\) can be placed on the x-axis so that the net electric force on it is zero.

whilst -factor charges are in touch, there may be

\(F = k \frac{q_{1}q_{2} }{ r^{2} }\)

Where

\(k = 9 * 10^{9} Nm^{2}C^{-1}\) = the coulomb constant.

The charges' magnitudes are \(q_{1}\) and \(q_{2}\).

r is the separation of the charges.

Let,

The third charge equals Q at, x equals x from the source.

because there is no net force acting on the third charge.

Hence,

\(f_{1} + f_{2} = 0\)

⇒ \(k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0\)

⇒ \(\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0\)

⇒ \(\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }\)

⇒ \(\frac{\sqrt{2} }{x} = \frac{1}{2a-x}\)

⇒ \(2\sqrt{2}a - \sqrt{2} = x\)

⇒ \(x = \frac{2\sqrt{2}a }{1+\sqrt{2} }\)

handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.

at the same time as the pressure between  identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.

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Cost savings (units of $) of the LED bulb is $0.69.Cost savings (units of $) of the LED bulb is calculated by using the formula

Energy Consumed = Power x Time, Cost of Energy Consumed = Energy Consumed x Cost per kWh,
In this case, the incandescent bulb consumed 97 W and was operated for 100 hours, so the energy consumed by the bulb is :
Energy Consumed by Incandescent bulb = 97 W x 100 hrs = 9700 Wh. Similarly, the LED bulb consumed 18 W and was operated for 100 hours so the energy consumed by the bulb is:
Energy Consumed by LED bulb = 18 W x 100 hrs = 1800 Wh. Now, the cost of energy consumed by the bulbs can be calculated using the formula:
Cost of Energy Consumed = Energy Consumed x Cost per kWh.
Given that the cost per kWh is $0.10, so the cost of energy consumed by the incandescent bulb is:
Cost of Energy Consumed by Incandescent bulb = 9700 Wh x $0.10/kWh= $9.70.
Similarly, the cost of energy consumed by the LED bulb is:
Cost of Energy Consumed by LED bulb = 1800 Wh x $0.10/kWh= $1.80.
Therefore, the cost savings (units of $) of the LED bulb as compared to the incandescent bulb is:
Cost savings (units of $) = Cost of Incandescent bulb - Cost of LED bulb= $9.70 - $1.80= $7.90
Hence, the cost savings (units of $) of the LED bulb is $7.90.

The cost savings (units of $) of the LED bulb is $7.90.

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Answer:

lCdfKFBWRblNLWFNJLBe

Explanation:

jk jk Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light

Answer:

The answer is the third one.

C.

Hope this helps!

Atoms of the pair of elements that will form ionic bonds in a compound are : C.) I and F.

Ionic bonds are a type of linkage created by electrostatic attraction between ions with opposing charges in chemical compounds.

Iodine has electronegativity of 2.66 and Fluorine has electronegativity of 3.98, which is a difference of 1.32. This large difference in electronegativity makes it favorable for Iodine to lose an electron and for Fluorine to gain an electron, forming ionic bond in compound.

The formation of ionic bonds occurs between atoms with large difference in electronegativity, where one atom loses electrons and other gains electrons to achieve  stable electron configuration.

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The lightweight glass sphere, if positively charged, will be weakly attracted to the magnet due to polarization of the magnet.

When a positively charged sphere is brought near a north pole of a bar magnet, it will produce a south pole due to the separation of charges. This produces a weak magnetic field that interacts with the north pole of the bar magnet, causing the sphere to be weakly attracted to the magnet. However, the interaction is not as strong as with a negatively charged sphere, which would be strongly attracted to the magnet. It is important to note that the sphere's attraction to the magnet is due to its electrostatic charge and not its magnetic properties.

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Answer: Acceleration is 0.25m/s^2

Explanation:

Answer:

Essential processes happen in a cell: Onion plant and Diatom

A cell is its basic unit of structure: Onion plant and Diatom

Made up of one cell: Diatom

Made up of many cells: Onion plant

Hi there!

We can begin by calculating the acceleration using the kinematic equation:

d = vit + 1/2at²

Since the rocket starts from rest, we can rewrite this as:

d = 1/2at²

Plug in given values:

4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²

Now, we can use Newton's Second Law to find the appropriate force:

∑F = m · a

∑F = 50,000 · 447.55 = 22,377,500 N

a) Angular frequency is  12.75 rad/s b)  The wave number is 33.59m c)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75t)

Given,

wavelength = λ = 18.7 cm

                   = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A) angular frequency = ?

f = v/λ

f = 0.38/1.87 = 2.03

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number,

K = 2π/λ = 33.59m

c) as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75t)

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Answer:

violet light bends the most as it has a shorter wavelength

Explanation:

Answer:

27.34 (no unit)

Explanation:

26.975*82.33%+29.018*17.67%

=27.34

Answer:

Kepler's third law:

P^2 = K R^3  the period squared is proportional to the cube of the radius

Ps^2 = K Rs^3

Pe^2 = K Re^3

Ps^2 / Pe^2 = Rs^3 / Re^3        dividing equations

Ps = (Rs / Re)^3/2 * Pe

Ps = (1.4E9 / 1.5E8)3/2 * 1 yr

Ps = 28.5 yrs

(Actual = 10759 da / 365.25 da = 29.5)

The speed of the bat emitting sound at a frequency of 30.0 kHz is closest to 10.0 m/s.

Based on the given information, we can find the speed of the bat using the formula:

Speed of sound = Frequency x Wavelength

Since the frequency of the sound emitted by the bat is 30.0 kHz (30,000 Hz) and the frequency of the echo is 900 Hz higher, the frequency of the echo is 30,000 Hz + 900 Hz = 30,900 Hz.

We can calculate the wavelength of the emitted sound using the formula:

Wavelength = Speed of sound / Frequency

Using the given speed of sound in air, which is 340 m/s, and the frequency of the emitted sound, we get:

Wavelength = 340 m/s / 30,000 Hz = 0.0113 meters

Since the frequency of the echo is higher, it means that the bat is moving towards the wall. In this case, the Doppler effect causes the frequency to increase.

The Doppler effect formula is:

Change in frequency / Frequency = Speed of observer / Speed of sound

We know the change in frequency is 900 Hz, the frequency is 30,000 Hz, and the speed of sound is 340 m/s.

900 Hz / 30,000 Hz = Speed of observer / 340 m/s

Speed of observer = (900 Hz / 30,000 Hz) x 340 m/s = 10.2 m/s

Therefore, the speed of the bat is closest to 10.0 m/s.

The question should be:

The bat emits sound at a frequency of 30.0 kHz as it moves closer to a wall. The bat detects beats where the frequency of the echo is 900 Hz greater than the emitted frequency. The speed of sound in air is 340 meters per second.The speed of the bat is closest to Group of answer choices 10.0 m/s 30.0 m/s 0 20.0 m/s 530 m/s. 5.02 m/s

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The length of the edge of its unit cell  is  mathematically given as

a = 420 pm

Extending from one point to another, length is the unit of measurement for distance.

According to the SI, length is a distance dimension. Typically, a length unit is selected as the basis for the system, with all other units of measurement being derived from it.

The metre is the fundamental length standard used throughout the International System of Units.

Generally, the equation for density  is  mathematically given as

density = Z x M / No x a3

Therefore

density = 4 x 74.6 / 6.02x10^23

density = 6.67 g/cm3

In conclusion,

6.67 g/cm3 = (4)(74.6) / (6.02x1023)(a3)

a3 = 7.43x10-23 cm3

a = 420 pm

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

Hope that helps. x

Answer:

Pumice is trapped in gas when the temperature is warm, but as the temp drops, it becomes dense, due to air bubbles. Iron wood is denser than water, thus making it sink.

Explanation:

To find the height of the fence, we need to find the final height of the ball after it was hit and then subtract the height of the fence.The final height of the ball can be found using kinematic equations. Using the initial velocity, acceleration due to gravity, and time elapsed, we can find the final height of the ball:h = vi * t + 0.5 * a * t^2whereh = final height

vi = initial velocity (0, since it was hit from ground level)

t = time elapsed (3.0 s)

a = acceleration due to gravity (-32.2 ft/s^2)Substituting the values,h = 0 + 0.5 * -32.2 * (3.0)^2 = 45.3 ftNext, we need to find the height of the ball 2.5 seconds after it reached its maximum height.Using the same kinematic equation,h = vi * t + 0.5 * a * t^2whereh = final height

vi = initial velocity (0, since it was at its maximum height)

t = time elapsed (2.5 s)

a = acceleration due to gravity (-32.2 ft/s^2)Substituting the values,h = 0 + 0.5 * -32.2 * (2.5)^2 = 18.825 ftFinally, subtracting the final height of the ball from the height of the fence:fence height = 320 ft - 18.825 ft = 301.175 ftSo, the fence is 301.175 ft high

Explanation:

he is very keen on taking up and is the age

Answer:

Atoms of elements with the same electons in the outer most shell they are put in the same group on the periodic table