what iis 5.46 ÷ 0.25 (show ur work)

The firefighters cannot rescue the person if the angle measure is 55°.

Given that there is a fire fighters bus having a height of 8 ft is set to rescue at height of 75 ft from the ground with a ladder of 84 ft,

They set the ladder at an angle of 55°, we need to see if they can rescue with this measurement of angle or not,

So,

The actual height of the building if we do not include the height of the bus = 75 - 8 = 67 ft,

Now,

Using the trigonometric ratios,

We will calculate the ideal measure of the angle so that they can rescue,

So,

Let the angle be x,

Sin x = 67 / 84

x = Sin⁻¹ (67 / 84)

x = 52.90°
Therefore, the ideal angle to rescue the person in the building is 52.90° and not 55°.

Hence, they cannot rescue the person if the angle measure is 55°.

Learn more about height and distance click;

https://brainly.com/question/9965435

#SPJ1

Answer:

7*450*.5%

Step-by-step explanation:

The first physical coordinate y1 can be expressed as y1 = [1 0 0]Y, & The mass-normalised mode shapes can be  normalising the mode shape vectors f1, f2, and f3.

Part (a)

In Equation Q2, the spectral matrix, undamped natural frequencies, damping ratios, and fundamental frequency need to be calculated.

The mass matrix is given by [85.16400 083.3770 0046.999; 0.079400 00.7030 001.07 × 10; 0.013600 03.1390 005.124 × 10].

The stiffness matrix is given by [0.16400 00.3770 000.999; 0.079400 00.7030 001.07 × 10; 0.013600 03.1390 005.124 × 10].

The damping matrix is given by [0 0 0; 0 0 0; 0 0 0].The undamped natural frequencies, damping ratios, and fundamental frequency for the system in Equation Q2 can be calculated from the spectral matrix.

The characteristic equation can be written as det(K-mω^2M)=0.where K is the stiffness matrix, M is the mass matrix, ω is the angular frequency, and m is the mass-normalised mode shape.

The roots of this equation are the undamped natural frequencies, and the damping ratios can be calculated from the undamped natural frequencies and mode shapes.

The mass-normalised mode shapes can be calculated by normalising the mode shape vectors f1, f2, and f3.

Part (b)

The mass-normalised mode shapes can be calculated using the mode shape vectors f1, f2, and f3.Part (c)The response of the system for the first physical coordinate y1 can be calculated using the mode superposition method. The initial modal displacements and velocities are given in terms of the modal coordinates.

The response is then calculated using the equation y(t)= Σ ai φi(t), where ai are the modal amplitudes, and φi(t) are the modal shapes given by the mode shape vectors f1, f2, and f3.

The first physical coordinate y1 can be expressed as y1 = [1 0 0]Y, where Y is the vector of physical coordinates. The modal amplitudes can be calculated from the initial modal displacements and velocities.

Learn more about coordinate  from the given link

https://brainly.com/question/17206319

#SPJ11

The polynomial function has zeros when x=-2,3/4,5 is option D  f(x)=(x+2)(4x-3)(x-5), according to the question.

What do you mean by function?

A function in mathematics from a set X to a set Y assigns exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.

According to the given question,

We have the given options are:

A f(x)=(x-2)(3x+4)(x+5)

B f(x)=(x-2)(4x+3)(x+5)

C f(x)=(x+2)(3x-4)(x+5)

D f(x)=(x+2)(4x-3)(x-5)

We will putting given x=-2,3/4,5 in the given functions one by one,

Option A,B and C are not the required polynomial function.

Now, we will show that the option D is the required polynomial function.

Putting x=-2,

f(x)=(x+2)(4x-3)(x-5)

f(-2)=(-2+2)(4(-2)-3)(-2-5)

= (0)(-8-3)(-7)

= 0

Then, putting x=3/4,

f(x)=(x+2)(4x-3)(x-5)

f(3/4)=((3/4)+2)(4(3/4)-3)((3/4)-5)

\(=(\frac{3+8}{4} )(\frac{12-12}{4} )(\frac{3-20}{4} )\\\\=(\frac{3+8}{4} )(0 )(\frac{3-20}{4} )\\=0\)

Then, putting x=5,

f(x)=(x+2)(4x-3)(x-5)

f(5)=(5+2)(4(5)-3)(5-5)

= (5+2)(4(5)-3)(0)

= 0

Therefore, the polynomial function has zeros when x=-2,3/4,5 is option D  f(x)=(x+2)(4x-3)(x-5).

To learn more about function, visit:

brainly.com/question/5975436?referrer=searchResults

#SPJ1

As a car dealer lowers a vehicle that was worth 18300 to 16000 by applying the formula of change in percentage we get that by 12.569 percentage (approximately) the price gets lowered .

The initial price of the car is set at P = 18300 (units)

The price after lowering drom P becomes A= 16000 (units)

Hence the change in price (or value) of the car, that is the price of the car is lowered by, C = (initial price - lowered price) = (P - A) = (18300 - 16000) units = 2300 units.

The formula for calculating percentage change is given as follows,

Change in percentage = [(Change in value)/ ( Initial value) ]*100

⇒Change in percentage = (C/ P)*100

⇒ Change in percentage =( 2300/ 18300)*100 = 12.569% (approximately)

To know more about change iin percentage here

https://brainly.com/question/14801224

#SPJ4

Answer:

The 15th term is 103

Step-by-step explanation:

Arithmetic Sequence

An arithmetic sequence is a list of numbers with a definite pattern by which each term is found by adding or subtracting a fixed quantity to the previous term. If n is the number of the term, then:

\(a_n=a_{n-1}+d\)

Where d is called the common difference. If we know the first term, the nth term is calculated by:

\(a_n=a_1+(n-1)*d\)

The question asks us to find the term n=15 of an arithmetic sequence with a common difference d=7 and first term a1=5.

Applying the formula above:

\(a_{15}=5+(15-1)*7\)

\(a_{15}=5+14*7\)

\(a_{15}=5+98=103\)

The 15th term is 103

Answer:

$8,711.99

Step-by-step explanation:

The formula for calculating the compound interest in expressed as;

A =P(1+r/n)^nt

Principal P = $4000

r is the rate = 7.2% = 0.072

t is the time = 15years

n = 1/12

Substitute

A = 4000(1+0.072(1/12))^15/12

A = 4000(1+0.072(12))^1.25

A = 4000(1+0.864)^1.25

A = 4000(1.864)^1.25

A = 4000(2.1779)

A = 8,711.99

Hence the final investment after 15years is $8,711.99

Using the equation h = 98 - 18t², the values are -

a) The height of acorn is obtained to be 26 feet.

b) The time when acorn hits the ground is obtained as 2.3 seconds.

What is an equation?

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("=").

a) When t = 2 seconds, we can find the height of the acorn by plugging in t = 2 into the equation for height -

h = 98 - 18t²

h = 98 - 18(2)²

h = 98 - 18(4)

h = 98 - 72

h = 26 feet

Therefore, when t=2 seconds, the height of the acorn is 26 feet.

b) We can find the time it takes for the acorn to hit the ground by setting h to 0 in the equation for height and solving for t -

h = 98 - 18t²

0 = 98 - 18t²

18t² = 98

t² = 98/18

t² ≈ 5.4444

t ≈ √5.4444

t ≈ 2.33 seconds (rounded to the nearest tenth)

Therefore, the acorn hits the ground after approximately 2.3 seconds.

To learn more about equation from the given link

https://brainly.com/question/28871326

#SPJ1

Answer:  resultant

Step-by-step explanation:

Answer:

Step-by-step explanation:

The slope of the perpendicular line with y = 2x + 3 is m = - 1/2.

Use point-slope form to find its equation:

or

or

Answer:

See below

Step-by-step explanation:

The slope of the perpendicular line with y = 2x + 3 is m = - 1/2.

Use point-slope form to find its equation:

y - y₁ = m(x - x₁)

y - 2 = - 1/2(x - 1)

or

y = -1/2x + 2 1/2

or

y = -0.5x + 2.5

give brainliest to me or to the person below or up bc I ctrl+c and ctrl+v

bc is soooo coool the other one lol

Answer:

x=180-(67+52)

Step-by-step explanation:

a linear pair is 180

we are already have two angles add them together

subtract that from 180 and you will get the last angle

The perimeter of the given shape above would be = 40.56in.

To calculate the perimeter of the given shape, the formula for the perimeter of a rectangle and a semi circle is used.

Perimeter of rectangle =2(l+w)

where,

length = 8in

width = 6in

perimeter = 2(6+8)

= 2×14 = 28in

perimeter of semi circle ;

= 2πr/2

where;

r = 8/2 = 4 in

= 2×3.14× 4/2

= 3.14×4 = 12.56in

Perimeter of the shape = 28+12.56 = 40.56

Learn more about perimeter here:

https://brainly.com/question/31068918

#SPJ1

Answer:

-8100

Step-by-step explanation:

(2/5)^-2(-3)^4

Given data

and second term

The first term=  (2/5)^-2  and

Second term=(-3)^4

Simplify the first term

(2/5)^-2= 2^-2/ 5^-2= 1/2^2 * 1/5^2

=1/4/ 1/25

=1/4*25/1

=100

Simplify the second term

=(-3)^4

= -81

Hence, 100*81

=-8100

Answer:

x = 45°, y= 5°

Step-by-step explanation:

x = 9y

90+2x = 180

2x = 90

x = 45

so x = 45

9y = 45

y = 5

Answer:

It's a positive slope

:)

Answer:

+++++++++++++++++++++++++++++++++++++

Step-by-step explanation:

According to the question we have the solution of the  given differential equation initial value problem is: g(x) = (3/4)x^4 - x + 9/4 .

To solve the given initial value problem, we need to integrate both sides of the differential equation. We have:

g'(x) = 3x(x^2 - 1/3)

Integrating both sides with respect to x, we get:

g(x) = ∫[3x(x^2 - 1/3)] dx

g(x) = ∫[3x^3 - 1] dx

g(x) = (3/4)x^4 - x + C

where C is the constant of integration.

To find the value of C, we use the initial condition g(1) = 2. Substituting x = 1 and g(x) = 2 in the above equation, we get:

2 = (3/4)1^4 - 1 + C

2 = 3/4 - 1 + C

C = 9/4

Therefore, the solution of the given initial value problem is:

g(x) = (3/4)x^4 - x + 9/4

In more than 100 words, we can say that the given initial value problem is a first-order differential equation, which can be solved by integrating both sides of the equation. The resulting function is a family of solutions that contain a constant of integration. To find the specific solution that satisfies the initial condition, we use the given value of g(1) = 2 to determine the constant of integration. The resulting solution is unique and satisfies the given differential equation as well as the initial condition.

To know more about differential visit :

https://brainly.com/question/31383100

#SPJ11

The surface area of the cylindrical soup can is approximately 150.7 sq. cm.

To find the surface area of a cylindrical soup can, we need to add up the area of the top and bottom circles, as well as the area of the curved side.

The area of each circle is πr^2, where r is the radius. So the area of both circles is 2π(3cm)^2 = 56.5 sq. cm (rounded to the nearest tenth).

The area of the curved side is the height times the circumference of the circle, which is 2πr. So the area of the curved side is 2π(3cm)(2cm) = 37.7 sq. cm (rounded to the nearest tenth).

To find the total surface area, we just add up these three areas:

56.5 + 56.5 + 37.7 = 150.7 sq. cm (rounded to the nearest tenth).

Therefore, the surface area of the cylindrical soup can is approximately 150.7 sq. cm.

To know more about surface areas refer here :

https://brainly.com/question/29101132#

#SPJ11

Answer:

Step-by-step explanation:

The expression 191 divided by 3 equals 63.66666666666667 (approximately 64)

The value at function when x is (-6) is approximately 0.070 and function when x is (-12) is approximately 0.000066 for the function f(x)= 9x²-18x^2/8x^5 +4 .

(a) To find the value of f(x) at x = -6, we substitute -6 into the function:

f(-6) = 9(-6)² - 18(-6)² / (8(-6)⁵ + 4).

Simplifying the numerator and denominator:

f(-6) = 9(36) - 18(36) / (8(-6)⁵ + 4)

     = 324 - 648 / (-4,608 + 4)

     = -324 / -4,604

     = 0.070.

Therefore, f(-6) = 0.070.

(b) To find the value of f(-12), we substitute -12 into the function:

f(-12) = 9(-12)² - 18(-12)² / (8(-12)⁵ + 4).

Simplifying the numerator and denominator:

f(-12) = 9(144) - 18(144) / (8(-12)⁵ + 4)

      = 1,296 - 2,592 / (-19,660,928 + 4)

      = -1,296 / -19,660,924

      = 0.000066.

Therefore, f(-12) = 0.000066.

Learn more about function here : brainly.com/question/31549816

#SPJ11

The partial pressure of oxygen in the venous circulation of an exercising individual at sea level is approximately 149 mm Hg.

In the given scenario, the total atmospheric pressure is 760 mm Hg, and the partial pressure of oxygen in the tissues is 10 mm Hg. To find the partial pressure of oxygen in the venous circulation, we subtract the tissue partial pressure from the total atmospheric pressure: 760 mm Hg - 10 mm Hg = 750 mm Hg. Therefore, the partial pressure of oxygen in the venous circulation of an exercising individual at sea level is approximately 149 mm Hg (20.93% of 750 mm Hg).

It's important to note that this calculation assumes ideal conditions and simplified models. In reality, oxygen transport in the human body is a complex process influenced by factors such as gas exchange in the lungs, oxygen binding to hemoglobin, and tissue oxygen consumption. These factors can vary among individuals and under different physiological conditions.

Learn more about Circulation:

brainly.com/question/28269937

#SPJ11

Answer:

Let y be the height above the camera platform of the painting.

tan (40degrees) = y/58

y = 58[tan(40)] = 58(0.8391) = 48.67 feet.

y = 48.67 feet

Step-by-step explanation:

Answer:

This is absolutely amazing! I love the passion in your anger. I can tell that this was a real life experience, and if it wasn't, your songwriting abilities are at a peak. at the melody that I read it in, it sounded sort of indie pop.

Step-by-step explanation:

Incredible story, loved it.

and the "your probably with that girl" really gave Olivia Rodrigo! love it so much.

Answer:

I love it.

Step-by-step explanation:

I really like it but one thing I learned about songwriting, make sure you are putting it through eyes.

The value of the given integral is: v = [(4√(3) - 5)π/3]

To evaluate the given integral, let's calculate it step by step:

First, let's integrate with respect to z from 1 to √(4 - x² - y²):

∫[1, √(4 - x² - y²)] dz = √(4 - x² - y²) - 1

Next, let's integrate the above expression with respect to y from -√(3 - x²) to √(3 - x²):

∫[-√(3 - x²), √(3 - x²)] (√(4 - x² - y²) - 1) dy

To simplify the integration, let's convert to polar coordinates:

x = r cosθ

y = r sinθ

The bounds of integration in polar coordinates will be:

r: 0 to √(3)

θ: 0 to 2π

Now, we can rewrite the integral in terms of polar coordinates:

∫[0, 2π] ∫[0, √(3)] (√(4 - r²) - 1) r dr dθ

Evaluating the inner integral with respect to r:

∫[0, 2π] [(-1/3) (4 - r²)\(^{3/2}\) - (1/2) r²] | [0, √(3)] dθ

∫[0, 2π] [(2√(3)/3) - (1/3)(4 - 3)\(^{3/2}\) - (1/2)(√(3))²] dθ

Simplifying further:

∫[0, 2π] [(2√(3)/3) - (1/3) - (3/2)] dθ

∫[0, 2π] [(2√(3)/3) - (5/6)] dθ

Now, integrating with respect to θ:

[(2√(3)/3)θ - (5/6)θ] | [0, 2π]

[(2√(3)/3)(2π) - (5/6)(2π)] - [(2√(3)/3)(0) - (5/6)(0)]

[(4√(3)/3)π - (5/3)π] = [(4√(3) - 5)π/3]

Therefore, the value of the given integral is: v = [(4√(3) - 5)π/3]

Complete Question:

Evaluate the integral:

v = ∫∫∫ [−√3, √3] [−√(3−x²), √(3−x²)] [1, √(4−x²−y²)] dz dy dx

To know more about integral, refer here:

https://brainly.com/question/31059545

#SPJ4

a) ℓ is equal to the number of leaf nodes in the graph.  If we have n nodes in the graph, then the maximum number of leaf nodes that we can have is n-1 (when the graph is a tree).

b) k = (n-1) - (number of connected components).  

To remove the minimum number of roads from the neighborhood such that the requirements are satisfied, we need to remove bridges.

Explanation:

Part a)  To begin with, it is stated that we have a neighborhood of n houses. For any two houses we pick, there is a road between them. The landlord wants to cut maintenance costs by removing some of the roads. Let k be the minimum number of roads he can remove such that the neighborhood is still connected (every house can be walked to from every other house) and there are no cycles.

To find the minimum number of roads that he can remove, such that the neighborhood is still connected and there are no cycles, let us start by finding the total number of roads required for a connected neighborhood with n houses, where every house can be walked to from every other house.  

We can use the formula for the minimum number of edges required for a connected graph, which is given by (n-1).

Thus, for n houses, we need n-1 roads.  

But we have n houses and for any two houses we pick, there is a road between them.

Therefore, the total number of roads in the neighborhood is greater than or equal to n-1.  

Suppose the landlord removes k roads. This means that there will be multiple disconnected components and to keep the neighborhood connected, we need to add edges between these components.

Thus, k is equal to the number of edges that need to be added to get a connected graph.  

Therefore,

k = (n-1) - (number of connected components).  

To remove the minimum number of roads from the neighborhood such that the requirements are satisfied, we need to remove bridges. Bridges are roads which if removed, increase the number of connected components. Removing a bridge will never create a cycle. Thus, we can start by identifying bridges and then removing them.

Part b)

Suppose now instead that the landlord wants to remove houses. Let ℓ be the minimum number of houses that must be removed such that the neighborhood is still connected and has no cycles.

Removing a house also removes the roads it is connected to. Determine the value of ℓ as an expression in terms of n. Then indicate how to remove the minimum number of houses from the neighborhood such that the requirements are satisfied.

To remove the minimum number of houses from the neighborhood such that the requirements are satisfied, we can start by finding the number of nodes that we can remove while keeping the graph connected.  

Let G be a connected graph with n nodes. If we remove a node v from G along with its incident edges, then the graph will be disconnected into components.

However, if v is a leaf node (a node with degree 1), then we can remove the node and its incident edge without disconnecting the graph.  If G has no leaf nodes, then it must have a cycle. Removing any node from a cycle will break the cycle and create at least one leaf node.  

Thus, to remove the minimum number of nodes, we need to identify the leaf nodes and remove them until no more leaf nodes are left.  The minimum number of nodes that can be removed without disconnecting the graph is equal to the number of leaf nodes in the graph.  

Therefore, ℓ is equal to the number of leaf nodes in the graph.  If we have n nodes in the graph, then the maximum number of leaf nodes that we can have is n-1 (when the graph is a tree).

To know more about  connected graph, visit:

https://brainly.com/question/31616043

#SPJ11

With a running time of 4.5 hours and speeds of 24 mph and 30 mph, respectively, the bus covered a one-way distance of 72 miles.

With a running time of 4.5 hours and speeds of 24 mph outgoing and 30 mph inbound, the bus covered a one-way distance of 72 miles.

As the outgoing and inbound timings were equal, the computation was performed by multiplying the outbound trip's speed by the entire running time, and then dividing the result by two. Therefore, 108 miles are equal to 24 mph times 4.5 hours. The one-way distance is equal to 72 miles when you divide this result in half. When both directions' speeds are known, this calculation can be used to determine the overall distance of a round trip.

Learn more about distance here

https://brainly.com/question/28956738

#SPJ4