what is 9 x 10^2/3 x 10^12 in scientific notation?

Compatibility of types of substances based on the description according to the Arrhenius acid-base definition is -A base contains the unit: OH in its formula.

Acid is a substance that when dissolved in water will decompose and produce H+ ions. Examples of acids such as hydrogen chloride (HCl), when dissolved in water will decompose into H+ ions and Cl- ions.

While a base is a substance that when dissolved in water produces OH- ions. An example is the compound sodium hydroxide NaOH which when dissolved will decompose Na+ and OH-. The reaction of a base with an acid will produce a 'salt' compound.

According to the Arrhenius definition, acids and bases are acids as substances that when dissolved in water produce hydronium ions (H+). Meanwhile, a base according to Arrhenius is a substance that can produce hydroxide ions when dissolved in water, or in its formula it is called (OH−).

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Answer:

Copper will start to react with the oxygen in the air to form copper oxide. The copper oxide will continue reacting to oxygen over time. As the copper oxide continues to react with carbon dioxide and water in the air it coats the surface with that iconic blue-green patina colour

Anwser:

Research scientific principles involved in water availability.

Explanation:

Before building or investment you always want to see and know what your up against and what the best way to help or solve is. Researching why there's a problem in water availability or/and the principals to water availability will help you see what the problem is with what's happening to and around the process and it's environment.

C) decreased; acid

Coral reefs are sensitive to changes in ocean temperatures and acidity levels, so their health and survival are threatened when the temperatures go down and acidity levels up.

Answer: In bold and underlined

The Indian Ocean is experiencing the loss of coral reefs at an increasing rate. This is due in part to Decreased ocean temperatures and increased Acid levels.

Coral reefs are sensitive to changes in ocean temperatures and acidity levels, so their health and survival are threatened when the temperatures go down and acidity levels up.

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

Answer:

48g

Explanation:

5 half-lives have passed. Therefore the amount was 32 times the current amount.

Answer:

C

Explanation:

When Beta decay happens, the atomic number of an element goes up, and that means there is an extra proton. A is not the answer because unstable atoms cause decay. B is also not correct because this is what happens in Beta decay: a neutron becomes a proton. D is not correct because an electron is actually emitted from the nucleus.

Answer:

It is an Anion because there are more electrons than protons making it negative

Marlon can conclude that the cell belongs to the Kingdom Protista if he observes that the paramecium has a nucleus.

The presence of a nucleus is a characteristic feature of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. Therefore, if Marlon observes that the paramecium has a nucleus, he can conclude that the cell belongs to the Kingdom Protista, which includes unicellular eukaryotic organisms.

The presence of a nucleus is one of the defining features of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. The Protista Kingdom includes unicellular organisms that have a nucleus and other membrane-bound organelles.

However, he would need to observe other features of the cell to further classify it into a specific group or species within the Protista Kingdom.

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Answer:

In chemistry, a compound is a substance made up of two or more different chemical elements combined in a fixed ratio. When the elements come together, they react with each other and form chemical bonds that are difficult to break.

Explanation:

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The energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm? can be expressed as 2.9*10^5 J

From the question we were told to find the energy and the parameters that is needed to calculate these are;

c=3*10^8

h= 6.626 * 10^-34 J.s

1 mol photons = 6.023x10^23 photon

λ = 4.11×10^2 nm  = 4.11 × 10-7 meters

The parameters can be input  as Energy of one mole photon (E) = ( 6.023x10^23 * 6.626 * 10^-34 * 3*10^8)/ (4.11 × 10^-7)

=291302

=2.9*10^5 J

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The sample of the gas will occupy 0.947 L.

Since there are no changes in the temperature, we use the following formula to relate both values of pressure:

Then, we replace the values to find the volume:

So, the sample of the gas will occupy 0.947 L.

Answer:

I think the answer is letter C

The balanced chemical equation is: C3H8 + 5O2 → 3CO2 + 4H2O

Chemical equations may only be balanced by changing the coefficients; subscripts cannot be changed. The ratios of the atoms in the molecule and the resulting chemical characteristics alter when subscripts are changed.

First, let's balance the carbon and hydrogen atoms by placing a coefficient of 3 in front of CO2 and 4 in front of H2O:

C3H8 + 5O2 → 3CO2 + 4H2O

Now, let's balance the oxygen atoms by placing a coefficient of 5 in front of O2:

C3H8 + 5O2 → 3CO2 + 4H2O

The equation is now balanced with coefficients of 1, 5, 3, and 4, respectively.

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Answer:

Explanation:

In the qualitative analysis of metal salts , we see that in group I , metal chlorides are precipitated out . It is so because their metal chlorides are insoluble in water  .

In this group following metal ions are present

Ag+,

Hg₂²⁺

Pb²⁺

Answer:

17.4 mols

Explanation:

Use the ideal gas Law: Pv=nRt where P is pressure, V is volume, n is the number of mols, R is the Gas constant (0.08206 L*atm/mol*K), and T is the temperature in Kelvin.

Convert temperature to Kelvin: 43.65 C+273= 316.65 K

Pv=nRt -----> Plug in what is given and Solve the equation for n

7.07 atm*64.01 L= n *(0.08206 L*atm/mol*K)* 316.65 K

n= 17.4 mols

The correct symbol for Cl with 20 neutrons and 12 electrons is 37/17 C1⁵+ (option D).

Atomic number is the number of protons in an atom. The number of protons and electrons in a neutral atom is the same i.e. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral.

The charge on an atom is related to its valence electrons or oxidation state.

The overall charge of an atom is determined by the number of protons and electrons in the atom. For example; an atom with more protons will be positively charged while an atom with more electrons eill be negatively charged.

According to this question, a chlorine atom has 20 neutrons and 12 electrons. The proton number of chlorine is 17.

This means that the mass number of chlorine is 20 + 17 = 37 and the charge is 17 - 15 = 2+.

Therefore, the correct symbol for Cl with 20 neutrons and 12 electrons is 37/17 C1⁵+.

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Answer:

C₂H₆(g) + 7/2 O₂(g) → 2 CO₂ + 3 H₂O

Explanation:

To balance equations of combustion (Chemical + O₂ producing CO₂ and water you must do:

1. Write as CO₂ as carbons in the chemical you have:

For the reaction:

C₂H₆(g) + O₂(g) → CO₂ + H₂O

As you have 2 carbons in ethane:

C₂H₆(g) + O₂(g) → 2 CO₂ + H₂O

2. Write the half of H₂O as hydrogen you have:

There are 6 hydrogens → You must place 3 H₂O:

C₂H₆(g) + O₂(g) → 2 CO₂ + 3 H₂O

3. The last step is to write the half of oxygens you have in products.

4 Oxygens from CO₂ and 3 from water:

Mass of water vapor produced : 0.90 g

Given

0.10 g of hydrogen reacted with 0.80 g of oxygen

Required

mass of water vapor produced

Solution

Reaction

2H₂ + O ⇒ 2H₂O

If we refer to the law of conservation of mass which states that the mass before and after the reaction is the same, then the mass of water vapor formed as a product is:

mass reactants = mass products

mass of Hydrogen + mass of Oxygen = mass of water vapor

0.1 g + 0.8 g = 0.90 g

Or we can also solve by using stochiometry (using the concept of moles) to find the mass of water vapor

Answer:

49 Newtons

Explanation:

The weight of the rock is the product of it's mad and the acceleration due to the earth's gravity(which is 9.8 meters per squared second)

So 5.0kg times 9.8 equals 49 Newtons.

7. D. 668 joules

8. B. 3 grams

Given

2 grams of water

6768 joules of energy

Required

Energy

Mass of water

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Q = m.Lv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

7. phase change (ice to water)⇒Heat of fusion water=334 J/g

Q = 2 g x 334 J/g

Q = 668 J

8. phase change(water to vapor)⇒heat of vaporization water=2260 J/g

6768 J = m x 2260 J/g

m = 3 g

The numerical value of Kc for the given reaction, with the equilibrium mixture containing 0.0450 M PCl3, 0.116 M Cl2, and 25.8 M PCl5, is approximately 4942.03.

To calculate the numerical value of Kc for the given reaction, we need to set up an expression for the equilibrium constant using the concentrations of the species involved.

The balanced equation for the reaction is:

PCl3 (g) + Cl2 (g) ⇌ PCl5 (g)

The equilibrium constant expression, Kc, is given by:

Kc = [PCI5] / ([PCl3] * [Cl2])

Given the equilibrium concentrations:

[PCl3] = 0.0450 M

[Cl2] = 0.116 M

[PCI5] = 25.8 M

Substituting these values into the equilibrium constant expression, we have:

Kc = (25.8 M) / ((0.0450 M) * (0.116 M))

Calculating Kc:

Kc = 25.8 M / (0.00522 M^2)

Kc = 4942.03

Therefore, the numerical value of Kc for the given reaction, with the equilibrium mixture containing 0.0450 M PCl3, 0.116 M Cl2, and 25.8 M PCl5, is approximately 4942.03.

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Answer:

\(Key=2.5x10^{-9}\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

\(2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)\)

By knowing that the equilibrium expression is actually:

\(Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}\)

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

\(Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}\)

Regards!

Answer:

okay that is cool

Explanation:

Answer:

I hope it helps u! :)

Explanation:

The final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.

The enthalpy change (ΔH) for the reaction CO2 + 2H2O → H2CO3 can be calculated by multiplying the stoichiometric coefficients of the balanced equation by the enthalpy values of the corresponding compounds involved in the reaction.

In the given reaction, the enthalpy change is -1410 kJ. However, it's important to note that this enthalpy change corresponds to a specific reaction and may not directly apply to the formation of CO2 and 2H2O from another reaction or process.

If we assume that the reaction is the formation of one mole of CO2 and two moles of H2O, we can say that the enthalpy change for this specific formation reaction is -1410 kJ.

Therefore, the final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.

It's worth mentioning that the enthalpy change can vary depending on the specific conditions (temperature, pressure, etc.) and the reactants involved in the reaction. Therefore, it's crucial to specify the conditions and reaction context when referring to enthalpy values.

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