What is the error? 1.5x-2=-2+1.5x

-2=2

On solving the provided question, we cans ay that lateral surface area of cuboid = 2h(l+b) = 2*2(5+4) = 36 cm sq.

A cuboid is a solid or three-dimensional form in geometry. A cuboid is a convex polyhedron having 8 vertices, 12 sides, and 6 rectangular faces. Another name for a cuboid is a cuboid. A cube is a cuboid with six square faces. Boxes include things like books and bricks. The following are the key variations between cubic and cubic: In contrast to a cube, which has rectangular faces, a cube has six equally sized square faces. Even though the cube and cuboid structures have a similar appearance, they differ in some ways in terms of side length, diagonal, and area.

lateral surface area of cuboid = 2h(l+b)

h = 2cm

l = 5cm

b = 4cm

lateral surface area of cuboid = 2h(l+b) = 2*2(5+4) = 36 cm sq.

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Answer:

\(V = \frac{4}{3} \pi {r}^{3} \\ \\ 3V = 4\pi {r}^{3} \\ {r}^{3} = \frac{3V}{4\pi} \\ \\ r = \sqrt[3]{ \frac{3V}{4\pi} } \)

The area of the semicircle is A = 1187.9 cm².

The area of a circle with a radius of r is A = πr².

Given that, the diameter of the semicircle is 55 cm.

The radius of the semicircle is,

r = 55/2

The area of a semicircle is given by,

A = (1/2)πr²

Substitute the values,

A = (1/2)π(55/2)²

A = 1187.9

Hence, the area of the semicircle is A = 1187.9 cm².

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The value of 8,590 − 4,586 is half the value of 2 x (8,590 − 4,586).

An equation is an expression that shows the relationship between two or more numbers and variables. The basic operations performed on an equation are addition, subtraction, multiplication and division.

The value of 8,590 − 4,586 = 4004

Half the value of 2 x (8,590 − 4,586) = (1/2) of 2 x (8,590 − 4,586) = 4004

The value of 8,590 − 4,586 is half the value of 2 x (8,590 − 4,586).

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The graph that contains the 3 points is the bottom right graph.

We want to see which of the graphs contains the 3 ordered pairs:

(20, -29.5),(21, -31), and (22, -32.5)

So we just need to look at the graphs and see which one has these points, notice that as x increases y decreases, so we have a decreasing line.

The slope of the decreasing line is:

a = (-31 + 29.5)/(21 - 20) = -1.5

The graph with this slope is the last one (bottom right, the other decreasing line has a slope of -1). So that is the correct option.

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(a) Randomized experiment, (b) There are three criteria for a randomized experiment

a) This is a randomized experiment.

b) The three criteria for a randomized experiment are:

Random assignment, the children were randomly assigned to the xylitol or placebo group.

Control group, a placebo group was used as a control.

Manipulation, the children were given different forms and doses of xylitol or placebo.

c) The explanatory variable is the form and dose of xylitol or placebo given to the children. The response variable is the incidence of ear infections.

d) Diagram of the randomized comparative experiment:

Population of healthy children in daycare centers

↓

Random assignment to xylitol or placebo group

↓

Intervention group: given xylitol in syrup, gum or lozenge form

Control group: given a placebo in gum, syrup or lozenge form

↓

Comparison of incidence of ear infections in intervention and control groups

↓

Analysis of results to determine the effectiveness of xylitol in reducing ear infections.

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Answer:

A) s = $40 (in thousands of dollars)

B) point of diminishing returns is at;

(20, 2000) in thousands of dollars

Step-by-step explanation:

We are given the profit function as;

P = −0.1s³ + 6s² + 400

A) To maximize the profit, we need to find the first derivative and equate it to zero.

Thus;

dP/ds = -0.3s² + 12s

At dP/ds = 0, we have;

-0.3s² + 12s = 0

0.3s² = 12s

0.3s = 12

s = 12/0.3

s = $40 (in thousands of dollars)

B) To find the point of diminishing returns, we need to find the 2nd derivative of the given profit function and equate to zero.

Thus;

d²P/ds² = -0.6s + 12

At d²P/ds² = 0, we have;

-0.6s + 12 = 0

0.6s = 12

s = 12/0.6

s = 20

At s = 20,

P = −0.1(20)³ + 6(20)² + 400

P = -800 + 2400 + 400

P = 2000

Thus; point of diminishing returns is at;

(20, 2000) in thousands of dollars

Answer:

Step-by-step explanation:

Le the numbers be x and y

Then we have equations:

As per the first equation:

Substitute in the second equation

Then finding the value of y

Answer:

3/8

Step-by-step explanation:

Answer:

The probability of selecting the color of ball that you just selected(a red ball) is \(P(r) =  \frac{2}{10}\)

Step-by-step explanation:

From the question we are told that

  The total number of colored balls  is  n  =  10

   The number of red balls is r =  2 red

    The number of white ball is  w =  4

    The number of blue balls is  b  =  4

   The number of balls to be selected is  N  =  2 balls

    The cost of playing picking a ball is  c  =  $10

    The winnings is \(k =  \$ P(A)\)

Here P(A) is the probability of obtaining the exact sequence of result  and from the question it  is  P(A) =  0.10

Generally my price according to the question is  

     \(k =  \frac{0.10 }{10}\)

=>   \(k =  0.01 \)

Let assume we selected a red ball

 Generally the probability of selecting a red ball is  mathematically represented as

       \(P(r) =  \frac{2}{10}\)

Answer:

Step-by-step explanation:

Given the expression -8/13×26/-3, getting the equivalent expression means multiplying the two fractions -8/13 and 26/-3 together as shown;

\(\frac{-8}{13} * \frac{26}{-3}\\ \\= \frac{-8*26}{13*-3}\\ \\multiplying\ out \ the\ numerator\ and\ denominator;\\\\= \frac{-208}{-39} \\\\cancelling out the negative sign we will have;\\\\= \frac{208}{39}\\\\= 5.33\\The\ resulting\ value\ is\ 5.33\)

Jordan spend 25 minutes writing each dayNoHow much time does Jordan spend writing each dayFrom the question, we have the following parameters that can be used in our computation:D + W = 75W + 25 = DSo, we haveW + W + 25 = 75EvaluateW = 25This means that Jordan spends 25 minutes on writing is it possible?Based on the answer in (a), the truth statement is No

Answer:

A = 36π units²

Step-by-step explanation:

the area (A) of a circle is calculated as

A = πr² ( r is the radius )

here r = 6 , then

A = π × 6² = 36π units²

Answer:

A total= 0.6703125 ft²

Step-by-step explanation:

A1= 3.9× 14.3= 55.77 in²

A2=1/2 × 14.3× ( 9.6-3.9)= 40.755 in²

A total= A1+ A2= 55.77+40.755=96.525 in²

1 ft= 12 in , 1ft²= 144 in²

Atotal= 96.525÷144= 0.6703125 ft²

Step-by-step explanation:

CFB reads as twenty five degrees

complementary angle  will add to it to sum 90 degrees  = sixty five degrees

   angle CFD is sixty five degrees

To find out how many of the 39 practice trials would be faster than 62 seconds, we need to calculate the proportion of trials that fall within the range of more than 62 seconds.

We can use the z-score formula to standardize the values and then use the standard normal distribution table (also known as the z-table) to find the proportion.

The z-score formula is:

z = (x - μ) / σ

Where:

x = value (62 seconds)

μ = mean (61 seconds)

σ = standard deviation (1.5 seconds)

Calculating the z-score:

z = (62 - 61) / 1.5

z ≈ 0.6667

Now, we need to find the proportion of values greater than 0.6667 in the standard normal distribution table.

Looking up the z-score of 0.6667 in the table, we find the corresponding proportion is approximately 0.7461.

To find the number of trials faster than 62 seconds, we multiply the proportion by the total number of trials:

Number of trials = Proportion * Total number of trials

Number of trials = 0.7461 * 39

Number of trials ≈ 29.08

Rounding to the nearest whole number, approximately 29 of the 39 practice trials would be faster than 62 seconds.

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Answer:

D

Step-by-step explanation:

a. The areas of the square is 81m² and for rectangle is 72m²

b. The perimeter of the square is 40m

a. To determine the area of the shapes in which we have that have a perimeter of 36m, we can consider rectangle and square.

For a square;

Perimeter of square = 4L

36 = 4L

L = 9m

The area of the square will be L² = 9² = 81m²

For a rectangle;

The perimeter of rectangle is;

P = 2(L + W)

We can assume that two numbers which will represent the length and width are;

L = 12m, W = 6m or L = 6m, W = 12m

A = 12 * 6 = 72m²

b.

The area of the wire is 100m², the perimeter for this can be calculated when we consider square and rectangle;

Perimeter of square = 4L

Area of square = L² = 100m²

L = 10m

The perimeter of the wire is 4(10) = 40m

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Comparing the median of each box-and-whisker plot, the type of transportation that is LEAST likely to take more than 30 minutes is: d. train.

How to Interpret a Box-and-whisker Plot?

In order to determine the transportation that is LEAST likely to take more than 30 minutes, we have to compare the median of each data set represented on the box-and-whisker plot for each transportation.

The box-and-whisker plot that has the lowest median would definitely represent the the transportation that is LEAST likely to take more than 30 minutes, since median represents the typical minutes or center of the data.

Therefore, from the box-and-whisker plots given, the one for train has the lowest median. Therefore train would LEAST likely take more than 30 minutes.

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Natalie will pay her parents $9 each week, and the initial amount she still owed was $180.

We can see that Natalie is reducing the amount she owes by $18 every two weeks.

Therefore, the amount she owes after 2 weeks is $180 - $18 = $162, after 4 weeks is $144, after 6 weeks is $126, and after 8 weeks is $108.

This means that after n weeks, the amount she still owes is:

$180 - $18n

Since she will pay the same amount each week, let's call the weekly payment P. After one week, she will owe:

$180 - P

After two weeks, she will owe:

($180 - P) - P = $180 - 2P

After four weeks, she will owe:

($180 - 2P) - P - P = $180 - 4P

After six weeks, she will owe:

($180 - 4P) - P - P = $180 - 6P

And after eight weeks, she will owe:

($180 - 6P) - P - P = $180 - 8P

We can set up an equation using the information we have:

$180 - 8P = $108

Solving for P, we get:

P = $9

Therefore, Natalie will pay her parents $9 each week, and the initial amount she still owed was $180.

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The complete question:

Natalie borrowed money from her parents to pay for a trip. ​Natalie will ​pay her parents in equal amounts every week until she pays back the ​entire amount she borrowed. ​ ​The table below shows the amount of ​money Natalie still owes her parents at the end of every two weeks for ​the first eight weeks. How much does Natalie pay her parents each week? What is the initial amount Natalie still owes?

Week 0 = $180

Week 2 = $162

Weeks 4 = $144

Week 6 = $126

Week 8 = $108

Answer:

\(9 \frac{ {d}^{2}y }{ {dx}^{2} } - 12 \frac{dy}{dx} + 4y = 0) \div 9 \\ \frac{ {d}^{2}y }{ {dx}^{2} } - \frac{4}{3} \frac{dy}{dx} + \frac{4}{9} y = 0 \\ y_{1}(x) = {e}^{ \frac{2}{3} x} \\ p(x) = - \frac{4}{3} \\ y_{2}(x) = y_{1}(x) \int \frac{ {e}^{ - \int \: p(x)dx} }{ {(y_{1}(x))}^{2} } dx \\ = {e}^{ \frac{2}{3} x} \int \frac{ {e}^{ \int \: \frac{4}{3} dx} }{ { ({e}^{ \frac{2}{3} x})}^{2} } dx \\= {e}^{ \frac{2}{3} x} \int \frac{ {e}^{ \frac{4}{3} x} }{ { {e}^{ \frac{4}{3} x}}} dx \\ = {e}^{ \frac{2}{3} x} \int dx \\ \boxed{y_{2}(x) =x{e}^{ \frac{2}{3} x}}\)

Answer:

y=-3x-6

Step-by-step explanation:

go down 3

over 1

rise over run 3/1

it's already on -6

Each of the 4 angles has a measure of 22.5 degrees.

What is the pοlygοns interiοr angles?

The sum of the interior angles of a polygon with n sides is given by the formula:

Sum of Interior Angles = (n - 2) × 180 degrees.

Since the floor is a regular 16-sided polygon, it is divided into 16 congruent interior angles with the same measure. The sum of the interior angles of a polygon with n sides is given by the formula:

Sum of interior angles = (n - 2) x 180 degrees

Substituting n = 16, we get:

Sum of interior angles = (16 - 2) x 180 = 2520 degrees

Since the 4 sections of flooring divide the corner into 4 equal angles, the sum of these 4 angles is 90 degrees. Therefore, each of the 4 angles has a measure of:

90 degrees / 4 = 22.5 degrees

Hence, each of the 4 angles has a measure of 22.5 degrees.

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Answer:

1/2 is 1 example

Step-by-step explanation:

what

A fraction that is less than 5/8 is 4/8

The fraction is given as:

Fraction = 5/8

A fraction less than 5/8 will have the same denominator but a smaller numerator compared to 5/8

Take for instance, the numerator can be

1 to 4

So, we have;

Smaller fraction = 4/8

Hence, a fraction that is less than 5/8 is 4/8

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Answer:

y = - \(\frac{1}{3}\) x + 7

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 3 ← is in slope- intercept form

with slope m = 3

given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{3}\) , then

y = - \(\frac{1}{3}\) x + c ← is the partial equation

to find c substitute (- 6, 9 ) into the partial equation

9 = - \(\frac{1}{3}\) (-6) + c = 2 + c ( subtract 2 from both sides )

7 = c

y = - \(\frac{1}{3}\) x + 7 ← equation of perpendicular line

The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.

We have,

In set theory, a proper class is a class that is not a set.

A class is a collection of objects, and a set is a class that can be a member of other classes.

On the other hand, a proper class cannot be a member of another class.

The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.

This means that V cannot be an element of any other class or set within the context of the set theory being considered.

The concept of proper classes is used to prevent paradoxes and contradictions that can arise when unrestricted comprehension is allowed in set theory.

Thus,

The statement "the universal class V is a proper class" means that class V, which represents the universal set that contains all sets, is not itself a set but rather a proper class.

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