Answer: The empirical formula is \(CaS\)
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of Ca= 55.6 g
Mass of S = 44.4 g
Step 1 : convert given masses into moles.
Moles of Ca =\(\frac{\text{ given mass of Ca}}{\text{ molar mass of Ca}}= \frac{55.6g}{40.08g/mole}=1.38moles\)
Moles of S =\(\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{44.4g}{32.06g/mole}=1.38moles\)
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Ca = \(\frac{1.38}{1.38}=1\)
For S = \(\frac{1.38}{1.38}=1\)
The ratio of Ca : S = 1:1
Hence the empirical formula is \(CaS\)
a famous motorcycle company
Harley Davidson, Vespa, Benelli, Aprilla, and Bimota
Convert a measurement of 89 cg to its equivalent in mg
Answer:
1 cg = 10 mg
Explanation:
So, 89cg = 89 * 10 = 890mg!
Pls thank, 5star, and brainliest!
1. The author says that bog bodies were discovered as long ago as the 1600s, but the only ones existing today are those found after the late 1800s. What hap- pened to the earlier bog bodies?
Answer:
The earlier bog bodies that were discovered in the 1600s might have not been preserved properly due to a lack of knowledge on how to preserve them or a lack of awareness of their significance. It is also possible that they might have decayed and decomposed over time and not survived till the present day. However, the bog bodies found after the late 1800s were preserved and studied extensively due to the increasing awareness and understanding of their historical and archaeological significance.
Explanation:
Hope this helped!! Have a great day/night!!
An area has a few days of low humidity, warm air temperature, and high air pressure. What kind of weather is this area experiencing?
Answer:
Sun.
Explanation:
Weather can be defined as the atmospheric conditions of a particular area over a short period of time.
The elements of weather include precipitation, wind, temperature, atmospheric pressure, relative humidity, cloud, and wind speed.
Temperature can be defined as a measure of the degree of coldness or hotness of a physical object. It is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).
Humidity refers to the concentration (amount) of water vapor that is present in the air. It is high when there's a lot of water vapor in the air and low when the level of water vapor is small.
Additionally, at constant humidity, relative humidity is inversely proportional to temperature i.e as the temperature decreases, relative humidity increases.
In this scenario, an area has a few days of low humidity, warm air temperature, and high air pressure. Thus, the kind of weather this area is experiencing is a sun i.e a sunny weather in which the air temperature is warm while having a high atmospheric pressure and low humidity.
Answer:
D. Sun
Explanation:
i just did it on edge
What is the heat capacity of 185g of liquid water?
The heat capacity of 185g of liquid water is 4.421 J/g°C
Heat capacity is defined as the amount of heat energy required to raise the temperature of a given quantity of matter by one degree Celsius
Here given data is
Mass = 185g
We have to calculate the heat capacity = ?
So the formula is
q = m×c×ΔT
c = ?
q = 4.184 J
m = 185g
ΔT = 100°C
c = m× ΔT/q
c = 185g ×100°C/ 4.184 J
c = 4.421 J/g°C
Heat capacity of 185g of liquid water is 4.421 J/g°C
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the ph of a 0.060-m solution of hypobromous acid is 4.96. calculate .
The Ka value for hypobromous acid (HBrO) is approximately 2.8 x 10^-9.
The pH of a solution can be used to calculate the concentration of H3O+ ions, which can then be used to determine the concentration of the acid (in this case, HBrO). The formula to calculate pH is pH = -log[H3O+].
Given that the pH of the solution is 4.96, we can calculate the concentration of H3O+ ions using the equation 10^(-pH) = [H3O+]. Substituting the given pH value, we have 10^(-4.96) = [H3O+].
Calculating this, we find that the concentration of H3O+ ions is approximately 1.07 x 10^(-5) M.
Since HBrO is a weak acid, we can assume that the concentration of H3O+ ions is equal to the concentration of HBrO. Therefore, the concentration of HBrO is also approximately 1.07 x 10^(-5) M.
The equilibrium expression for the dissociation of HBrO is: Ka = [H3O+][BrO-]/[HBrO]. We can substitute the calculated concentration values to obtain Ka = (1.07 x 10^(-5))^2 / (1.07 x 10^(-5)) = 1.07 x 10^(-5) M.
Therefore, the Ka value for hypobromous acid is approximately 2.8 x 10^-9.
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Match each atomic combination to the appropriate functional group.
- A. B. C. D. C-O-C
- A. B. C. D. O=C-O-H
- A. B. C. D. O=C-O-C
- A. B. C. D. C-O-H
A. Alcohol
B. Carboxylic acid
C. Ester
D. Ether
Answer:
The atomic combinations can be matched to the appropriate functional groups as follows:
- A. C-O-C: C. Ester
- B. O=C-O-H: B. Carboxylic acid
- C. O=C-O-C: C. Ester
- D. C-O-H: A. Alcohol
Explanation:
things that happened to the organisms I tracked: (example: was eaten by other organisms)
Reproduced, transferred their genes to progeny, died from natural causes, fell ill or contracted a disease, became prey for a predator or were devoured by a scavenger, or moved to a new area.
What kind of non-living entity might be present in an ecosystem?Non-living things include items like rocks, water, the atmosphere, the climate, and natural occurrences like earthquakes and rockfalls. One of the qualities that characterises living beings is their capacity for reproduction.
What are five non-living examples?Its definition includes glass, the sun, water, sand, and rock as non-living objects. They show absolutely no signs of life. Some people define a non-living object as anything that once belonged to a live entity.
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Calculate the pH of the buffer that results from mixing 60.0 mL of 0.250 M HCHO2 and 15.0 mL of 0.500 M NaCHO2.
When mixing 60.0 mL of 0.250 M HCHO2 and 15.0 mL of 0.500 M NaCHO2, the resulting buffer has a pH of 3.45.
To calculate the pH of the resulting buffer, we can use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA]).
In this case, HCHO2 is the weak acid (HA) and NaCHO2 is the salt providing the conjugate base (A-). First, we need to determine the moles of HCHO2 and NaCHO2.
Moles of HCHO2 = (60.0 mL)(0.250 M) = 15.0 mmol
Moles of NaCHO2 = (15.0 mL)(0.500 M) = 7.5 mmol
Next, calculate the total volume of the mixture:
Total volume = 60.0 mL + 15.0 mL = 75.0 mL
Now, determine the concentration of each species in the buffer:
[HCHO2] = (15.0 mmol) / (75.0 mL) = 0.200 M
[NaCHO2] = (7.5 mmol) / (75.0 mL) = 0.100 M
The pKa of HCHO2 is 3.75, so using the Henderson-Hasselbalch equation:
pH = 3.75 + log(0.100/0.200)
pH = 3.75 - 0.301
pH = 3.45
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How does gravity depend on the mass of two objects
Gravity increases as the mass of either object increases.
What is gravity?Gravity is the force by which a planet or other body draws objects toward its centre. The force of gravity keeps all of the planets in orbit around the sun.
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
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Vinegar is sold as a 5.00% solution of acetic acid. How many mL of water is in a 455mL bottle of vinegar?
430 mL of water is found in a 455 mL bottle of vinegar.
How to find the mL of water?The bottle of vinegar is labeled as 5.00% solution of acetic acid, meaning that 5% of the solution is acetic acid and the rest is water.
To find the amount of water in the bottle, we can subtract the portion that is acetic acid from the total volume.
This can be done by multiplying the volume of the bottle by the percentage of acetic acid, and then subtracting this result from the total volume:
Volume of water = Total volume - (Total volume * % acetic acid)
Volume of water = 455 mL - (455 mL * 5%) = 455 mL - (455 mL * 0.05) = 455 mL - 22.75 mL = 432.25 mL
So, there is approximately 432.25 mL of water in a 455 mL bottle of vinegar.
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What are the major disadvantages of using ozone instead of chlorine to disinfect water? O Ozonation is more expensive than chlorination and ozone leaves an odor in the water O Ozonation causes trihalomethane formation and leaves an odor in the treated water O Ozone decomposes quickly and does not provide long-term protection against possible contamination as the water is piped through a municipal distribution system O Ozonation causes trihalomethane formation and is more expensive than chlorination
The major disadvantage is - Ozone decomposes quickly and does not provide long-term protection against possible contamination as the water is piped through a municipal distribution system.
The gas ozone (O3) is unstable. As a result, it breaks down quickly, oxidizing any organic impurities present in the water including bacteria, viruses, and germs, but because it is a gas, it leaves the water after the oxidation is complete. Therefore, when the ozone started to disintegrate at first, the water may have various additional contaminants that mix with it as it travels through the municipal distribution system. Water carries through the new pollutants from the pipes. Ozone therefore has no long-term effect.
Chlorination produces trihalomethane, not ozonation, hence the expansiveness of ozone is dependent on the impurity of the water. Trihalomethane is produced by chlorination, not ozonation. Although ozone as a gas has a faint odor, when it is combined with water, it oxidizes the pollutant and breaks down, leaving no ozone in the water. Therefore, water does not smell like ozone.
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If
two open cans of different diameters were left
out in the rain, how would the amount of
water they collected compare? How would the
depth of water in the cans compare?
according to the phase diagram below a sample of water exists in two phas w at a pressure of 1 atm and a temperature of 0C
If the pressure is increased from 1 atm to 10 atm maintaining the constant temperature of 0℃, Ice will change to liquid water
We know that, pressure is inversely proportional to volume. When pressure in a system increases, the volume would decrease or vice versa.
In the given scenario, the pressure is increased from 1 atm to 10 atm. As the pressure is increased, the volume would decrease.
At 0℃, the volume of ice is higher than the volume of water. The forward reaction is the formation of water which has lower volume from ice. Thus, increasing the pressure would cause the ice to melt and results in the formation of water in liquid state.
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Could someone plz help me
Answer:
A
Explanation:
B: not B. Opinions don't matter. Facts do.
C: its a consideration. It will limit the scope of the experiment. But it's not relevant to the investigation. Not C
D: You might want to contact some scientists to see what they think about your investigation, but randomly interviewing anyone and everyone is not the answer.
You want to do A for certain.
The exothermic reaction between solid aluminium powder and solid manganese (IV) oxide, produces solid manganese and
another product. How many moles of aluminium powder are needed to produce 203.7 grams of manganese?
The number of moles of aluminum powder needed to produce 203.7 grams of manganese is 5 moles.
How to calculate the number of moles of Aluminium powder?Heat, Mn, and Al2O3 are produced when aluminum powder and manganese dioxide are heated.
\(3MnO_{2} + 4Al - > 3Mn + 2Al_{2} O_{3} + Heat\)
The balanced chemical equation in this situation indicates that there are 3 moles of manganese and 4 moles of aluminum involved in the reaction, which results in a 3:4 mole ratio.
You may make use of this mole ratio by calculating how many moles of aluminum are required to react with the 203.7g of Manganese. So,
Firstly, the mass of Aluminium has to be taken out
Let the mass be considered x.
So, the number of moles of Aluminium = x/27
Number of moles of Manganese = 203.7/54
Hence, the mass x will be,
\(x = 4 *203.7 * 27 / 3 * 54\)
\(x = 135.8g\)
Hence, the number of moles of Aluminium is = 135.8/27 = 5 moles.
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Can someone help me plz
Which best describes why carbocation formation is the rate determining step of a unimolecular substitution reaction? A. The ABC step is slow. B. The nucelophile is too weak to attack without a carbocation present. C. The carbocation formed is unstable and high in energy. D. Carbocation formation is reversible so it doesn't readily occur. E. The solvent is acting as the nucleophile.
The correct answer is C. In a unimolecular substitution reaction, the rate determining step is typically the formation of a carbocation intermediate.
This is because the carbocation is a high-energy, unstable species, and the process of forming a carbocation requires a significant amount of energy. Once the carbocation has formed, the reaction can proceed quickly through attack by a nucleophile. Additionally, the formation of a carbocation is irreversible under typical reaction conditions, so it does not readily undergo back reaction.
The other answer choices are not correct: A refers to a different type of reaction mechanism, B is not typically observed in unimolecular substitution reactions, D is incorrect because carbocation formation is not reversible, and E is also not typically observed in unimolecular substitution reactions.
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Describe the proper way to tighten a clamp...
The proper way to tighten a clamp depends on the type of clamp being used. In general, however, the first step is to ensure that the clamp is properly positioned and secured. Once this is done, the clamp can be tightened by turning the screw or lever that is used to adjust the pressure.
If you are using a screw-type clamp, start by loosening the screw enough to allow the jaws to open wide enough to fit around the object you are clamping. Then, position the jaws around the object and begin to tighten the screw by turning it clockwise. Be sure to apply even pressure to both sides of the clamp to ensure a secure hold. Do not over-tighten the clamp, as this can damage the object being clamped or cause the clamp to break.
If you are using a lever-type clamp, simply flip the lever down to close the jaws around the object, and then flip the lever up to tighten the clamp. Again, be sure to apply even pressure to both sides of the clamp.
In either case, once the clamp is tightened to the desired level of pressure, double-check that it is securely in place and will not slip or come loose. This will ensure that the clamp holds the object firmly in place as needed.
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elect all that apply Which of the following couples are buffer systems? (a) KF/HF(b) KBr/HBr(c) Na^CO3/NaHCO3 A. KF/HF B. KBr/HBr □ C. Na2CO3/NaHCO3 □ D. none
Of the following given compound or couples KF/HF, Na^CO3/NaHCO3 are the buffer systems as they consist of both weak base or acid.
What is buffer systems?Buffer systems is the acid-base homeostatic mechanism. It is helpful in maintaing the pH in blood by balancing the carbonic acid, bicarbonate ion, and carbon dioxide .
Formation of buffer systems:Buffer systems are made of weak Base-acid mixed with its conjugate base-acid dissolved in water. The conjugate acid-base should be from its Salt.
Hence, Of the following given compound or couples KF/HF, Na^CO3/NaHCO3 are the buffer systems as they consist of both weak base or acid.
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At what temperature will 120 grams of argon gas have a volume of 0.25 Lat a pressure of
200 kPa?
Answer:
-245.5°C or 27.7 K
Explanation:
To solve this problem, we can use the ideal gas law:
PV = nRT
∴ P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to calculate the number of moles of argon gas using its mass and molar mass:
n = m/M
∴ m is the mass of argon and M is its molar mass. The molar mass of argon is approximately 39.95 g/mol.
n = 120 g / 39.95 g/mol = 3.003 mol
Next, we can rearrange the ideal gas law to solve for the temperature:
T = PV/nR
Substituting the given values:
T = (200 kPa) (0.25 L) / (3.003 mol) (8.314 J/(mol·K))
T = 27.7 K
Therefore, the temperature at which 120 grams of argon gas will have a volume of 0.25 L at a pressure of 200 kPa is approximately -245.5°C (27.7 K - 273.15).
Draw diagrams to show the arrangement of particles in a
Salid a liquid, and a gas
Answer:
solid(particles are rightly packed)
liquid(particles are losely packed)
gas(particles move freely)
Explanation:
there u go, hope it helps
work in your groups to identify cellular and molecular concepts connected to this diagram. how many can you find?
The binding of the odorant molecule triggers an action potential by activating the CNG (cyclic nucleotide-gated) channels, leading to depolarization and subsequent opening of voltage-gated Na⁺ channels in the olfactory neuron.
Determine the cellular and molecular concepts?The diagram represents the cellular and molecular events involved in signaling within an olfactory neuron. When an odorant molecule binds to the CNG channels located in the plasma membrane of the neuron, it initiates a cascade of events.
Initially, the binding of the odorant molecule to the CNG channels allows the influx of Na⁺ and Ca²⁺ ions into the neuron, resulting in depolarization of the membrane potential. This depolarization reaches a threshold value of -55 mV, which triggers the opening of voltage-gated Na⁺ channels.
The opening of voltage-gated Na⁺ channels causes a rapid influx of Na⁺ ions into the neuron, further depolarizing the membrane potential and generating an action potential. This action potential propagates along the axon of the neuron, allowing the transmission of the olfactory signal to the brain.
Following the action potential, repolarization occurs through the opening of voltage-gated K⁺ channels. These channels facilitate the efflux of K⁺ ions from the neuron, restoring the resting membrane potential.
The diagram also includes additional cellular and molecular components involved in the signaling process, such as CAMP (cyclic AMP), ATP (adenosine triphosphate), transcription factors, and gene transcription, which collectively contribute to the activation and regulation of the olfactory pathway.
To maintain ion homeostasis and restore the resting potential, the Na⁺/K⁺ pump actively transports Na⁺ ions out of the neuron and K⁺ ions back into the neuron.
Therefore, the odorant molecule binding activates CNG channels, causing depolarization and opening of voltage-gated Na⁺ channels. This triggers an action potential in the olfactory neuron, enabling the transmission of the olfactory signal.
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Complete question here:
Work in your groups to identify cellular and molecular concepts connected to this diagram How many can you find? + OUT +30 Resting Potential Na K pump -IN 0 2 OUT 2 Membrane potential (mV) Depolarization Voltage-gated Na' channel IN • OUT 3 -55 -Threshold Repolarization Voltage-gated channel -70 + OUT Resting Potential Na-/Kºpump 2 3 Time (msec) Odorant compound Na CNG channel 30 CH channel Plasma membrane OR AC3 (G , GB Cytosol ATP Knases CAMP Transcription factors Growth cone Gene transcription Look again at this diagram of signaling in an olfactory neuron.
How does the binding of the odorant molecule trigger an action potential?
what is the difference between reactibe and non-reactive nitrogen
Reactive nitrogen refers to nitrogen compounds that are chemically active and can participate in various biological and environmental processes, while non-reactive nitrogen refers to nitrogen in unreactive forms, such as molecular nitrogen (N2) or nitrogen gas.
Reactive nitrogen refers to nitrogen compounds that are chemically active and can undergo transformations or participate in various biological and environmental processes. These compounds include ammonia (NH3), nitrate (NO3-), nitrite (NO2-), and organic nitrogen compounds. Reactive nitrogen is involved in essential processes such as nitrogen fixation, nitrification, denitrification, and nitrogen assimilation in living organisms. It plays a vital role in the nitrogen cycle and can have both positive and negative impacts on ecosystems and the environment, depending on the context.
Non-reactive nitrogen, on the other hand, refers to nitrogen in its unreactive forms, primarily as molecular nitrogen (N2) or nitrogen gas. Molecular nitrogen is chemically stable and relatively inert, meaning it does not readily participate in chemical reactions or biological processes. Non-reactive nitrogen is often considered biologically unavailable until it undergoes nitrogen fixation, a process where certain microorganisms convert N2 into reactive forms that can be used by organisms. In summary, reactive nitrogen compounds are chemically active and participate in various processes, while non-reactive nitrogen exists in its unreactive forms, primarily as molecular nitrogen, and requires conversion to reactive forms to be utilized by living organisms.
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Which type of weathering occurred to form the Malham Pavement
Answer:
carbonation
Explanation:Please dont delete my answer again cause its correct, I had the same question on my test so I know its righ!!!!
How many moles of NaF are produced in the resction between sodium bromide and calcium fluoride when 550 grams of sodium bromide are used
Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.
Explanation:
From the question, the balanced chemical formula is illustrated below:
2NaBr + CaF2 → 2NaF + CaBr2
From the equation above;
Molecular mass of NaBr = 23 + 80 = 103g/ mol
Molecular mass of CaF2= 40+ (19×2)= 78g/ mol
Molecular mass of NaF = 23+19 = 42g/ mol
From the balanced chemical equation;
2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.
That is, 2 moles of NaBr= 2× 103 = 206g
2moles of NaF = 2×42= 84g
If 206g of NaBr yielded 84g of NaF
Therefore 550g of NaBr will yield Xg of NaF
X= 550×84/206
X= 224.27g of NaF
But 42g = 1 mole of NaF
Therefore 224.27g = X mole of NaF
X= 224.27 ×1/42
X is approximately 5moles.
A copper atom has a mass of 1.06 x 10 g and a penny has a mass of 2.5 g. a Use this information to answer the question below. Be sure your answers have the correct number of significant digits. How many moles of copper atoms have a mass equal to the a mass of a penny?
Approximately 0.0394 moles of copper atoms have a mass equal to the mass of a penny.
To determine the number of moles of copper atoms that have a mass equal to the mass of a penny, we can use the molar mass of copper and the mass of the penny.
The molar mass of copper (Cu) is 63.55 g/mol.
First, we need to calculate the number of moles of copper atoms in 2.5 grams, which is the mass of a penny:
Number of moles = Mass / Molar mass
Number of moles = 2.5 g / 63.55 g/mol
Number of moles ≈ 0.0394 mol
Therefore, approximately 0.0394 moles of copper atoms have a mass equal to the mass of a penny.
The molar mass of an element represents the mass of one mole of that element.
In this case, the molar mass of copper is 63.55 g/mol.
To find the number of moles, we divide the given mass of the penny (2.5 g) by the molar mass of copper.
By performing the calculation, we find that approximately 0.0394 moles of copper atoms have a mass equal to the mass of a penny.
Approximately 0.0394 moles of copper atoms have a mass equal to the mass of a penny. This calculation is based on the molar mass of copper and the given mass of the penny (2.5 g).
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NH_3 + H_2O <-> NH_4(+) + OH(-)
Given the dissociation equation for ammonia, would you predict ammonia is a good conductor of electricity? Explain in terms of ions present in solution and level of dissociation. .
\((NH_4(+))\) No, ammonia is not a good conductor of electricity due to its low level of dissociation and the resulting low concentration of ions in the solution.
Ammonia (NH3) is not a good conductor of electricity in aqueous solution. In the dissociation equation \(NH_3 + H_2O < - > NH_4(+) + OH(-)\) , it can be observed that ammonia (\(NH3\)) reacts with water (H2O) to form ammonium ions \((NH_4(+))\) and hydroxide ions\((OH(-))\).Ammonium ions \((NH_4(+))\) and hydroxide ions \((OH(-))\)are present in the solution and can conduct electricity. However, the level of dissociation of ammonia is relatively low. Ammonia molecules tend to stay intact rather than dissociating into ions. As a result, the concentration of ions in the solution is low, leading to a poor conductivity of electricity.In order for a substance to be a good conductor of electricity, it requires a high concentration of ions and a significant level of dissociation. In the case of ammonia, the limited dissociation hinders the formation of a substantial number of ions in the solution, thereby reducing its conductivity.For more questions on electricity
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How many molecules are in 15.0 g of silicon tetrafluoride?
There are approximately 8.675 × 10^22 molecules in 15.0 g of silicon tetrafluoride.
To determine the number of molecules in 15.0 g of silicon tetrafluoride (SiF4), we need to use the concept of moles and Avogadro's number.
Calculate the molar mass of SiF4:
The molar mass of silicon (Si) is approximately 28.09 g/mol, and the molar mass of fluorine (F) is approximately 18.998 g/mol. Since silicon tetrafluoride has four fluorine atoms, we can calculate the molar mass as follows:
Molar mass of SiF4 = (1 × molar mass of Si) + (4 × molar mass of F)
= (1 × 28.09 g/mol) + (4 × 18.998 g/mol)
= 104.09 g/mol
Convert the given mass to moles:
Using the molar mass calculated in the previous step, we can convert the mass of silicon tetrafluoride to moles:
Moles = Mass / Molar mass
= 15.0 g / 104.09 g/mol
≈ 0.144 moles
Apply Avogadro's number:
Avogadro's number (6.022 × 10^23) represents the number of particles (atoms, molecules, etc.) in one mole of a substance. In this case, we're interested in the number of molecules in the given moles of silicon tetrafluoride:
Number of molecules = Moles × Avogadro's number
= 0.144 moles × (6.022 × 10^23 molecules/mol)
≈ 8.675 × 10^22 molecules
Therefore, there are approximately 8.675 × 10^22 molecules in 15.0 g of silicon tetrafluoride.
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The hydrogen gas foed in a chemical reaction is collected over water at 30 ∘C-at a total pressure of 742 mmHg. The vapor pressure of water at 30 C is 31.8 mmHg Part A What is the partial pressure of the hydrogen gas collected in this way? Express your answer in millimeters of mercury to three significant figures.
The partial pressure of the hydrogen gas collected in this way is 710 mmHg. When collecting a gas over water, the total pressure of the system includes the vapor pressure of water at that temperature
When collecting a gas over water, the total pressure of the system is the sum of the partial pressure of the gas and the vapor pressure of water at that temperature. In this case, the total pressure is given as 742 mmHg, and the vapor pressure of water at 30°C is 31.8 mmHg.
To find the partial pressure of the hydrogen gas, we need to subtract the vapor pressure of water from the total pressure. Therefore, the partial pressure of the hydrogen gas can be calculated as:
Partial pressure of hydrogen gas = Total pressure - Vapor pressure of water
Partial pressure of hydrogen gas = 742 mmHg - 31.8 mmHg
Partial pressure of hydrogen gas = 710 mmHg
In this chemical reaction, the collected hydrogen gas exerts a partial pressure of 710 mmHg.
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