what is the mass (in grams) of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride?
Answers
The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.
The balanced chemical reaction is :
2Na + Cl₂ → 2NaCl
Given data :
Mass of sodium = 10.0 g
Number of moles of Na -
Number of moles = Given mass
Molar mass
Number of moles = 10.0 g = 0.43 mol
23 g
Comparing moles of Na and Cl₂ from the balanced chemical equation,
Na : Cl₂
2 : 1
0.43 : 1 x 0.43 = 0.215 mol
2
Mass of chlorine gas :
(molar mass of chlorine = 71 g)
Mass of chlorine = number of moles x molar mass
Mass = 0.215 mol x 71 g/mol
= 15.26 g
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Related Questions
Fe +H₂SO4→Fe₂(SO4)3 +H₂
Can someone balance this for me
Answers
Answer:
2 Fe+ 3H₂SO₄=Fe₂(SO₄)₃+3H₂
Explanation:
The reaction type is a single replacement.
Examine the chemical reaction. What coefficient of o2 should be added so the number of atoms of oxygen is conserved on both sides of the reaction equation?.
Answers
Examine the chemical reaction \(C_3H_8+O_2\) ----> \(4H_2O+3CO_2\) coefficient of \(O_2\) should be included to bring the total number of oxygen atoms to 5.
Each element's number of atoms in the reactant and product sides of a chemical equation must be equal. It is a balanced chemical equation because the amounts of zinc, hydrogen, and sulfate in this equation are equal on both the reactant and product sides.
step to Balance a Chemical Equation are:-
Step 1: The Unbalanced Chemical Equation.
Step 2: Make a List.
Step 3: Identifying the Atoms in Each Element.
Step 4: Multiplying the Number of Atoms.
Step 5: Molecules are placed in front of coefficients.
Step 6: Check the Equation.
Step 7: Balanced Chemical Equation.
Given the reaction; \(C_3H_8+O_2\) ----> \(4H_2O+3CO_2\), the only time it will balance is when the coefficient of \(O_2\) is 5.
The number of atoms in the reactants and products of balanced chemical equations are the same for each type of element. The type of chemical equation depends on the number of atoms, and unbalanced chemical equations have varying numbers of atoms of various elements in the reactants and products.
The right outcome requires that chemical equations always be balanced. The number and type of each atom in balanced chemical equations are the same on both sides of the equation.
The simplest whole number ratio must be used as the coefficients in a balanced equation. In chemical reactions, mass is always conserved.
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What is the percent composition of hydrogen in the compound
Answers
Mass of each element in one mole of sulfuric acid: Mass of hydrogen = 2 × (1.008) = 2.016 g/mol. Mass of sulfur = 1 × 32.06 = 32.06 g/mol.
...
What is the percent composition of NaHCO₃?
Element Percent Composition
Sodium (Na) 27.367%
Hydrogen (H) 1.2%
Carbon (C) 14.298%
Oxygen (O) 57.14%
Would you expect the shielding effect to be greater in bromine than in chlorine?
A. Yes, because there are more filled orbitals in bromine.
B. Yes, because bromine has a higher atomic number.
C. No, because they are both in the same family.
D. No, because chlorine has a higher electronegativity than bromine.
Answers
The shielding effect of bromine is greater than chlorine because there are more filled orbitals than in chlorine.
Shielding EffectThis is the process where by electrons are protected by the pull attraction of the nucleus with the use of electron shells. The shielding effect increases down the group of the periodic table and increases across the period. This is because when you move down the group, there's an increase in the number of shell by 1 and it helps to reduce the effect of nuclear attraction on the electrons. However when you move across the period, there's an increase in the numbers of electron with the same shielding electrons from group 1(a) across the period to group 7(a).
Factor that affect the shielding effect of an electronThe numbers of electrons on the inner shells.Type of orbital which the electron is located.Shielding effect is primarily dependent on the numbers of electrons in the inner shells as well as the type orbitals.
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I need help pls help ASAP I'll give brainliest
Answers
Answer: A
Explanation:
Answer:
The answer is A
Explanation:
Find grocery items in your home look and see the product label at the back of each item identify the elements or compounds on each item use the table below for this activity grocery time 123456789 10 elements compounds
Answers
The chemical elements and compounds that are present in a grocery item such as mayonnaise include:
OilEmulsifier Vinegar SpicesSugarWhat is a product label?A product label can be defined as a paper document which contains information about the nutrients, chemical elements, and other compounds that are present in a product such as a battery, food or an edible material.
This ultimately implies that, a product label is a paper document which is used by manufactures to specify the nutrients, chemical elements, and other compounds that were used to make a particular product.
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What is the pH of a solution obtained by adding 5.00 g of HI to 295 mL of a 0.786 M solution of HNO3? Assume that the HI addition does not change the volume of the resulting solution.
Answers
To find the pH of the resulting solution, we need to determine the concentration of H+ ions present in the solution. We can use the following steps to calculate the concentration of H+ ions:
Find the moles of HNO3 present in 295 mL of a 0.786 M solution of HNO3.
Molarity (M) = moles of solute/volume of solution in liters
0.786 M = moles of HNO3 / 0.295 L
moles of HNO3 = 0.786 x 0.295 = 0.23187 mol
Find the moles of HI added to the solution.
Molar mass of HI = 127.91 g/mol
moles of HI = 5.00 g / 127.91 g/mol = 0.03905 mol
Determine the moles of H+ ions produced by the reaction between HNO3 and HI.
The balanced chemical equation for the reaction between HNO3 and HI is:
HNO3 + HI → H2O + NO2 + I2
From the equation, we can see that one mole of HNO3 reacts with one mole of HI to produce one mole of H+ ions. Therefore, the moles of H+ ions produced by the reaction are equal to the moles of HNO3.
moles of H+ ions = 0.23187 mol
Find the total volume of the solution.
The volume of the solution is 295 mL (the volume of the HNO3 solution), as the addition of HI does not change the volume.
Calculate the concentration of H+ ions in the solution.
[H+] = moles of H+ ions/volume of solution in liters
volume of solution = 0.295 L
[H+] = 0.23187 mol / 0.295 L = 0.785 M
Calculate the pH of the solution.
pH = -log[H+]
pH = -log(0.785)
pH = 0.105
Therefore, the pH of the solution obtained by adding 5.00 g of HI to 295 mL of a 0.786 M solution of HNO3 is approximately 0.105.
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4. The table below shows liquids that are miscible and those that are immiscible Liquid L3 14 LI L2 Miscible Miscible Miscible immiscible the information given to answer the questions that follow. a) Name the method that can be used to separate L1 and L3 from a mixture of th (Imk)
Answers
L1 and L2 can be separated by the process of fractional distillation and L2 and L4 can be separated by the process of separation.
Fractional distillation :The method for separating crude oil into clusters of hydrocarbons with similar numbers of carbon molecules is known as fractional distillation. These groups of hydrocarbons are referred to as "fractions." Hydrocarbons with short chains. Short-chain hydrocarbons are hydrocarbons with few carbon atoms.
What is fractional distillation mainly used for?Fractional distillation is used to purify water as well as separate ethanol and water. Fractional distillation is used in many industries, including oil refineries and chemical plants, to purify and separate many organic compounds.
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I understand the question you are looking for :
1. The table below shows liquids that are miscible and those that are immiscible
Liquid L3 L4
L1 Miscible Miscible
L2 Miscible Immiscible
Use the information given in the table to answer that questions that follow;
i) Name the method that can be used to separate L1 and L2 from a mixture of the two
ii) Describe how a mixture of L2 and L4 can be separated
Identify the products of the reaction between 2KOH and H₂SO4.
O KSO and H2₂O
OK2SO4 and H₂O
O H₂O and K₂SO4
O KH2 and SO4
Answers
Answer:
C.) H₂O and K₂SO₄
Explanation:
This appears to be a double-displacement reaction. In these reactions, the cation of one substance is swapped with the cation of another.
So, K⁺ from KOH is swapped with the H⁺ from H₂SO₄. The new compounds should have an overall charge of 0. Therefore, it may be necessary to modify the amount of each ion (not just be 1:1).
K₂SO₄
-----> K⁺ and SO₄²⁻
-----> + 1 + 1 + (-2) = 0
H₂O
-----> H⁺ and OH⁻
-----> + 1 + (-1) = 0
automobile bodies contain significant amounts of iron. the iron is protected by the addition of zinc. this is called galvanization, the protection of one metal the sacrifice of a more reactive metal. write the balanced chemical equations using smallest whole number coefficients for the following processes. do not include states-of-matter:
Answers
the balanced chemical of the corrosion presented by galvanization is
Fe ⇒ Fe²⁺+ 2e
Corrosion is the process by which metals are converted to oxides by exposure to the atmosphere. Corrosion is a type of atmospheric oxidation of metals.
One way to prevent corrosion is to use a sacrificial anode. A more reactive metal can be used as the anode to protect the desired metal from corrosion. The formula for iron corrosion is: Fe ⇒ Fe²⁺+ 2e
Iron is protected by the addition of zinc. This is called electroplating( galvanization), and it protect one metal at the expense of a more reactive metal.
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how can we separate the sugar from sugar solution
Answers
how many moles are in 37.5 g nitrogen
Answers
Use Le Châtelier’s Principle to predict the shift in equilibrium (Left, Right, No Change) for each of the following:
REACTIONS:
A. CH4(g) + 2 O2(g) ⇌ CO2(g) + 2 H2O(g) ΔH = -230 kJ
4 Al(s) + 3 O2(g) ⇌ 2 Al2O3(s) + 150 kJ
C. N2(g) + 3 H2(g) ⇌ 2 NH3(g) ΔH = + 22 kJ
D. 2 H2O(l) + 58 kJ ⇌ 2 H2(g) + O2(g)
_____ 1. Pressure decrease for reaction A
_____ 2. Pressure increase for reaction B
_____ 3. Adding heat in reaction C
_____ 4. Decreasing heat in reaction D
_____ 5. Increasing [N2] in reaction C
_____ 6. Decreasing [H2O] in reaction D
_____ 7. Adding heat in reaction A
_____ 8. Pressure increase for reaction D
_____ 9. Increasing [Al2O3] in reaction B
_____ 10. Pressure decrease for reaction C
_____ 11. Decreasing [CO2] in reaction A
_____ 12. Decreasing heat in reaction B
_____ 13. Addition of a catalyst to reaction B
_____ 14. Increasing [O2] in reaction B
_____ 15. Pressure increase for reaction C
Answers
2. No Change
3. Left
4. Right
5. Right
6. Left
7. Left
8. No Change
9. No Change
10. Right
11. Left
12. Right
13. No Change
14. No Change
15. Left
Explanation:
1. According to Le Châtelier's Principle, a decrease in pressure favors the side with fewer moles of gas. In this case, the reaction will shift to the right to produce more gaseous products and decrease the pressure.
2. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, there is no change in the number of moles of gas on either side of the reaction, so the equilibrium position will not shift.
3. Adding heat to an exothermic reaction (one with a negative ΔH value) will shift the equilibrium to the left to absorb the excess heat.
4. Decreasing heat in an endothermic reaction (one with a positive ΔH value) will shift the equilibrium to the left to generate more heat.
5. Increasing the concentration of a reactant will shift the equilibrium to the right to counteract the increase.
6. Decreasing the concentration of a reactant will shift the equilibrium to the left to counteract the decrease.
7. Adding heat to an exothermic reaction (one with a negative ΔH value) will shift the equilibrium to the left to absorb the excess heat.
8. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, there is no change in the number of moles of gas on either side of the reaction, so the equilibrium position will not shift.
9. Adding product to a reaction will not shift the equilibrium position, according to Le Châtelier's Principle.
10. Decreasing the pressure of a reaction favors the side with more moles of gas. In this case, the reaction will shift to the right to produce more gas and increase the pressure.
11. Decreasing the concentration of a product will shift the equilibrium to the right to counteract the decrease.
12. Decreasing the temperature of an endothermic reaction (one with a positive ΔH value) will shift the equilibrium to the right to generate more heat.
13. Adding a catalyst will not shift the equilibrium position, according to Le Châtelier's Principle.
14. Increasing the concentration of a reactant will not shift the equilibrium position, according to Le Châtelier's Principle.
15. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, the reaction will shift to the left to decrease the number of gaseous molecules and decrease the pressure.
in a titration, 14.5cm3 of nitric acid, HNO3 neutralised exactly 25cm3 of 0.05 mol/dm3 sodium hydroxide, NaOH
calculate the concentration of the nitric acid solution in mol/dm3
Calculate the concentration of the nitric acid in g/dm3
Answers
The concentration of the nitric acid solution is 0.0862 mol/\(dm^3\) and the concentration of the nitric acid in g/\(dm^3\) is 5.431 g/\(dm^3\).
What is titration?
A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.
According to the neutralization law,
\(n_1M_1V_1 = n_2M_2V_2\)
\(n_1\)is the basicity of \(HNO_3\) =1
\(M_1\) is the molarity of \(HNO_3\) =0.05 mol/\(dm^3\)
\(V_1\) is the volume of \(HNO_3\) solution = 25\(cm^3\)
\(n_2\) is the acidity of NaOH =1
\(M_2\) is the molarity of NaOH =?
\(V_2\) is the volume of NaOH solution =14.5\(cm^3\)
Putting in the values we get:
\(n_1M_1V_1 = n_2M_2V_2\)
1 x 0.05 mol/\(dm^3\) x 25cm^3 = 1 x \(M_2\) x 14.5\(cm^3\)
\(M_2\) = 0.0862 mol/\(dm^3\)
Hence. the concentration of the nitric acid solution in 0.0862 mol/\(dm^3\) and the concentration of the nitric acid in g/dm3 is 0.0862 x63.01 g/\(dm^3\)= 5.431 g/\(dm^3\).
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Consider the following reaction in a gas phase:C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0. 2 at 1000 °CCalculate the concentration of CO in an equilibrium mixture (in mol/L) if a reaction mixture initially contains only reactants, and the equilibrium concentration of H2O(g) is [H2O] = 0. 500 M at 1000 °C
Answers
The concentration of CO (g) in the equilibrium mixture is 0.020 M. In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.
The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.
Given that the concentration of H2O (g) is [H2O] = 0.500 M at 1000°C, and the reaction is:
C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0.2 at 1000°C
We need to determine the concentration of CO in an equilibrium mixture (in mol/L)
if a reaction mixture initially contains only reactants.
We can solve this problem using the ICE table method as follows:
Let x be the change in concentration of H2O (g) and CO (g) when they reach equilibrium.
Then the equilibrium concentrations of CO (g) and H2 (g) are equal to x. Hence, the equilibrium concentration of H2O (g) is (0.500 - x) M. Substitute these values in the expression for Kc and solve for x.
Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]
= 0.2[CO (g)] = Kc [H2O (g)] [C (s)] / [H2 (g)]
= 0.2 × (0.500 - x) / x
We can simplify this expression by cross-multiplication to get:
5x = 0.1 - 0.2xx = 0.02 M
Substituting x = 0.02 M in the expression for [CO (g)], we get:
[CO (g)] = 0.2 × (0.500 - 0.02) / 0.02 = 5.8 M (approx.)
Therefore, the concentration of CO (g) in an equilibrium mixture (in mol/L) is 5.8 M. The problem requires us to find the equilibrium concentration of CO (g) in a mixture that initially contains only reactants.
To solve this problem, we need to use the expression for the equilibrium constant Kc, which is given by:
Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]
We can also use the ICE table method to solve this problem. In this method, we start with the initial concentration of the reactants and calculate the change in concentration of each species as they reach equilibrium.
We then use the equilibrium concentrations to calculate the value of Kc and solve for the unknowns. Here is how we can set up the ICE table for this problem: Reaction:
C(s) + H2O(g) ⇄ CO(g) + H2(g)
Initial: [C] = [H2]
= 0 M,
[H2O] = 0.500 M
Equilibrium: [C] = [H2] = x,
[H2O] = 0.500 - x,
[CO] = [H2] = x
Change: +x +x -x -x
Substituting the equilibrium concentrations into the expression for Kc, we get:
Kc = [CO] [H2] / [H2O] [C]
= x² / (0.500 - x)
= 0.2
Solving for x, we get: x = 0.020 M
Substituting this value of x into the expression for [CO], we get:
[CO] = x = 0.020 M
Therefore, the concentration of CO (g) in the equilibrium mixture is 0.020 M.
In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.
The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.
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Which diagram shows the correct electron configuration for nitrogen (N)?
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third arrow has an up and a down arrow; the fourth has an up arrow only, and the third has no arrows. The third, fourth, and fifth lines are bracketed with the label 2 p.
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third, fourth, and fifth lines each have an up arrow and are bracketed with the label 2 p.
A group of five short lines. The first line has an up and a down arrow above it and is labeled 1 s below. The second line has an up and a down arrow and is labeled 2 s. The third and fourth lines each have an up arrow; the fifth line has a down arrow. The third, fourth, and fifth lines are bracketed with the label 2 p.
Answers
Answer:
the second one is the correct answer
Answer:
its b
Explanation:
to find the ph of a buffer composed of h2po−4(aq)h2po4−(aq) and hpo2−4(aq)hpo42−(aq) , which p Kaka value should be used in the henderson–hasselbalch equation?
Answers
The pH of a buffer composed of H2PO−4(aq)/H2PO4−(aq) and HPO2−4(aq)/HPO42−(aq), we need to use the pKa value of the specific acid-base pair involved.
In this case, the Henderson-Hasselbalch equation can be written as:
pH = pKa + log([A-]/[HA])
Here, [A-] represents the concentration of the conjugate base (H2PO4− or HPO42−) and [HA] represents the concentration of the acid (H2PO−4 or HPO2−4).
For H2PO−4(aq)/H2PO4−(aq) pair, the pKa value of H2PO−4(aq) should be used.
For HPO2−4(aq)/HPO42−(aq) pair, the pKa value of HPO2−4(aq) should be used.
It is important to note that the pKa values for these acid-base pairs can vary depending on the temperature and ionic strength of the solution. It is recommended to refer to reliable sources, such as chemistry textbooks or scientific literature, to obtain the accurate pKa values for these species at the specific conditions you are working with.
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How many unpaired electrons are in the ground state electron configuration 4s23d9?
Answers
ANSWER
The number of the unpaired electrons is 1
STEP-BY-STEP EXPLANATION:
The electronic configuration of a particular element is given below as
\(4s^23d^9\)From the electronic configuration above, you will see that the 4s-orbital has two electrons and the 3d-orbital has 9 electrons
According to Hund's Rule, it "states that electron goes into orbital singly before pairing commences."
To determine the number of unpaired electrons, we need to study the total number of electrons in the d-orbital as given by the question.
Note that, the maximum number of electrons that can enter into the d-orbital is 10
The next step is to fill in the electrons into the orbital
From the above structure, you will see that the number of paired electrons is 4 and the number of unpaired electrons is 1
Therefore, the number of the unpaired electrons is 1
If the balloon had a volume of 33000 L , how many kilograms of hydrogen were needed to fill the balloon at STP?
Answers
If a balloon has a volume of 33000 L, the amount of hydrogen that would be needed to fill will be 29.46 kg.
Volume of gas at STPAt standard temperature and pressure, 1 mole of any gas is equivalent to 22.4 L of the gas.
The capacity of the balloon is 33000 L. The number of moles of hydrogen gas that will fill the balloon can be calculated using dimensional analysis as follows:
1 mole = 22.4 L
33000 L = 1 x 33000/22.4
= 1473.21 moles
This means that 1473.21 moles of hydrogen will be required to fill the balloon.
Recall that: mole = mass/molar mass
Hence: mass = mole x molar mass
Molar mass of hydrogen gas = (1+1)
= 2 g/mol
We can then use the above formula to calculate the mass of 1473.21 moles of hydrogen.
mass of 1473.21 moles hydrogen = 1473.21 x 2
= 2946.43 grams
2946.43 grams to kg = 2946.43/1000
= 29.46 kg
In other words, if a balloon has a capacity of 33000 L, the amount of hydrogen that would be required to fill it will be 29.46 kg.
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Aluminum bromide and chlorine gas react to
form aluminum chloride and bromine gas.
Answers
Answer:
ok
Explanation:
A flat sheet of paper of area 0.130 m2 is oriented so that the normal to the sheet is at an angle of 56 ∘ to a uniform electric field of magnitude 18 N/C .
Answers
The value of electric flux is 2.45N.m²/C.
A flat sheet of paper of area 0.130 m² is oriented so that the normal to the sheet is at an angle of 56 ∘ to a uniform electric field of magnitude 18 N/C.
The electric flux through the paper is given by;
ϕ=E.A.cosθϕ
= Electric fluxE
= Electric field intensityA
= Area of the surfaceθ
= Angle between electric field intensity and normal to the surface
Given,E = 18 N/C A = 0.130 m² θ = 56°
The electric flux through the paper is :
ϕ=E.A.cosθϕ
= (18 N/C)(0.130 m²)cos56°ϕ
= 2.45 N.m²/C
The electric flux through any closed surface is proportional to the charge enclosed by the surface. The electric flux through an open surface can be calculated by multiplying the electric field intensity with the area of the surface and the cosine of the angle between the electric field intensity and the normal to the surface.
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Complete question:
A flat sheet of paper of area 0.130 m2 is oriented so that the normal to the sheet is at an angle of 56 ∘ to a uniform electric field of magnitude 18 N/C .Find the amount of elctric flux passing through the sheet?
Which property of matter is conserved in chemical reactions and shown by balanced equations?
Answers
The property of matter that is conserved in chemical reactions and shown by balanced equations is known as the Law of Conservation of Mass. According to this law, mass can neither be created nor destroyed in a chemical reaction; it can only be transformed from one form to another.For instance, when two substances are combined, they react and form a new substance.
The products that are formed contain the same number of atoms as the reactants, but in different configurations. To keep track of the number of atoms on either side of the equation, we use coefficients, which indicate the number of molecules or atoms of each substance in the reaction. However, when a chemical equation is written, it must adhere to the law of conservation of mass.The law of conservation of mass is critical in chemical reactions because it ensures that the amount of reactants that go into a reaction equals the amount of products that come out of it. This means that the total mass of reactants must equal the total mass of the products. As a result, the balanced chemical equation must reflect this law.For example, consider the reaction between hydrogen gas and oxygen gas, which forms water. The balanced chemical equation is as follows:2H2 + O2 → 2H2OIn this reaction, two molecules of hydrogen gas react with one molecule of oxygen gas to produce two molecules of water. The coefficients in the balanced chemical equation indicate that two molecules of hydrogen and one molecule of oxygen combine to form two molecules of water, obeying the law of conservation of mass.In conclusion, the Law of Conservation of Mass is a fundamental principle in chemistry that is used to balance chemical equations. It is critical in chemical reactions because it ensures that the total mass of reactants equals the total mass of products, allowing scientists to accurately predict the outcome of a chemical reaction.For such more question on chemical reaction
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Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecules by:____.
Answers
Answer:
hydrogen bonds
Explanation:
this is because the type of bonding occurs between electropositive forces.
Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecules by Hydrogen bonds.
Hydrogen Bond
Between a hydrogen (H) atom that is covalently bonded to a more electronegative "donor" atom or group and another electronegative atom bearing a lone pair of electrons—the hydrogen bond acceptor—a hydrogen bond (or H-bond) forms (Ac). The second-row elements fluorine, oxygen, and nitrogen are the most common donor and acceptor atoms (F).
It may take place either intramolecularly or intermolecularly (between different molecules) (occurring among parts of the same molecule). The energy of a hydrogen bond can range from 1 to 40 kcal/mol and is influenced by the shape, surroundings, and nature of the particular donor and acceptor atoms.
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URGENT:
Do you switch charges for ionic or covalent bonds when naming them?
Answers
Answer:
ionic
Explanation:
The Keq for the interconversion for the two chair conformers of methylcyclohexane at 25 °C is 18. What % of the chair conformers have an axial methyl group?
A) 95 B) 75 C) 50 D) 25 E) 5
Answers
The Keq for the interconversion for the two chair conformers of methylcyclohexane at 25 °C is 18. The % of the chair conformers having an axial methyl group is A) 95%.
If the value of Keq is higher than 1, that means the reaction is favored in the forward direction. If the value of Keq is lower than 1, that means the reaction is favored in the reverse direction.If the value of Keq is equal to 1, that means the reaction is at equilibrium.Methylcyclohexane is an example of the cyclohexane molecule in which there is a substitution of a methyl group on one of the six carbon atoms in the ring structure. The two chair conformers of methylcyclohexane are the axial and equatorial conformers, in which the methyl group is either in an axial or equatorial position, respectively.
The percentage of chair conformers having an axial methyl group can be calculated using the following formula:
% axial conformer = Keq / (1+Keq) × 100
Putting the value of Keq in the formula:
axial conformer = 18 / (1+18) × 100%
axial conformer = 18/19 × 100%
axial conformer = 94.7%
The value of percentage has been rounded off to the nearest whole number, which is 95. Therefore, the answer is (A) 95.
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Determine the number of moles of chlorine gas that must be added to the container to make the new equilibrium concentration of SbCl3(g) to be half that of the original equilibrium concentration.
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To determine the number of moles of chlorine gas required to achieve the desired change in the equilibrium concentration of SbCl₃(g), we need to consider the stoichiometry of the balanced chemical equation for the reaction involving antimony trichloride (SbCl₃) and chlorine gas (Cl₂). The number of moles of chlorine gas that must be added to the container is (3/2) moles.
The balanced chemical equation for the reaction is:
2 SbCl₃(g) + 3 Cl₂(g) ⇌ 2 SbCl₅(g)
According to the equation, the stoichiometric ratio between SbCl₃ and Cl₂ is 2:3. This means that for every 2 moles of SbCl₃, we require 3 moles of Cl₂ to react completely.
Since we want the new equilibrium concentration of SbCl₃ to be half of the original equilibrium concentration, it implies that the reaction has shifted to the left, resulting in a decrease in the concentration of SbCl₃.
To achieve this, we need to remove some SbCl₃ by consuming it in the reaction. From the stoichiometric ratio, we can see that the ratio of moles of SbCl₃ to moles of Cl₂ is 2:3. Therefore, to reduce the concentration of SbCl₃ by half, we need to consume 1 mole of SbCl₃.
Using stoichiometry, we can determine the corresponding amount of Cl₂ required. Since the ratio of SbCl₃ to Cl₂ is 2:3, if we require 1 mole of SbCl₃, we will need (3/2) moles of Cl₂.
Therefore, the number of moles of chlorine gas that must be added to the container is (3/2) moles.
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In a chemical reaction, one reactant, called the ___________ reactant, will control the extent of the reaction. A portion of the other reactants, called the ___________ reactants, will remain.
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In a chemical reaction, one reactant, called the limiting reactant, will control the extent of the reaction. A portion of the other reactants, called the excess reactants, will remain.
What is a limiting reactant?A limiting reactant is the chemical reactant that limits the progress of the reaction and the amount of product produced. When one reactant is entirely consumed in the chemical reaction, the reaction ceases, and additional reactants remain unconsumed.
Therefore, the quantity of the product generated in a reaction is determined by the limiting reactant, which is the limiting factor in a chemical reaction. The term limiting factor may be used in place of limiting reactant to describe the reactant that limits the reaction's pace or quantity.
The excess reactant is the chemical reactant in a chemical reaction that is not entirely consumed. It is the reactant that is not used up when the reaction is finished, implying that it has a large quantity available but is not required in excess to react fully with the limiting reactant.
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Describe each material below as an element, compound, solution or heterogeneous mixture: Their Sea water - Click here to enter answer- Aluminum - Click here to enter answer- hanges Beer Potassium bromide Click here to enter answer- Hydrogen peroxide Click here to enter answer- Vodka - Click here to enter answer - Click here to enter answer- Fluorine Click here to enter answer Pork chop - Click here to enter answer- Raisin bread Click here to enter answer-
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The material are sea water,alumnium ,beer,potassium bromide an element, compound, solution or heterogeneous mixture.
Sea water: A solution of salt, minerals, and dissolved gases. The salt in sea water is a compound, while the other substances are elements.
Aluminum: An element that is found on the periodic table. It is a silvery-white metal that is very strong and lightweight.
Beer: A solution of water, alcohol, carbohydrates, and other substances. The alcohol in beer is a compound, while the other substances are elements or other compounds.
Potassium bromide: A compound that is made up of the elements potassium and bromine. It is a white solid that is used in medicine and photography.
Hydrogen peroxide: A compound that is made up of the elements hydrogen and oxygen. It is a clear liquid that is used as a disinfectant and bleach.
Vodka: A solution of ethanol (alcohol) and water. It is a clear liquid that is typically bottled at 40% alcohol by volume.
Fluorine: An element that is found on the periodic table. It is a pale yellow gas that is very reactive.
Pork chop: A heterogeneous mixture of meat, fat, and bone. The meat and fat are both elements, while the bone is a compound.
Raisin bread: A heterogeneous mixture of bread, raisins, and other ingredients. The bread is a compound, while the raisins are elements.
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According to the information the correct description for each material is: sea water - Solution, aluminum - Element, beer - Heterogeneous mixture, potassium bromide - Compound, hydrogen peroxide - Compound, vodka - Solution, fluorine - Element, pork chop - Heterogeneous mixture, raisin bread - Heterogeneous mixture
What is the correct description for each material?Sea water is a solution because it consists of a mixture of different substances dissolved in water.Aluminum is an element because it is a pure substance made up of only one type of atom.Beer is a heterogeneous mixture because it contains visible particles that do not fully dissolve and can be seen.Potassium bromide is a compound because it is a pure substance made up of two or more different types of atoms chemically bonded together.Hydrogen peroxide is a compound because it consists of two different elements (hydrogen and oxygen) chemically bonded together.Vodka is a solution because it is a mixture of alcohol and water that forms a homogeneous mixture.Fluorine is an element because it is a pure substance made up of only one type of atom.A pork chop is a heterogeneous mixture because it consists of different parts, such as meat, fat, and bone, that can be seen and distinguished.Raisin bread is a heterogeneous mixture because it contains visible particles (raisins) dispersed within the bread, creating a non-uniform mixture.Learn more about compounds in: https://brainly.com/question/24972577
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ASAP! What is the total number of electrons that can occupy the f sublevel? a 2 electrons b 6 electrons c 10 electrons d 14 electrons
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Answer:
D) 14 Electrons
Explanation:
I took the test and got it right
The total number of electrons that can occupy the f sublevel is 14 electrons. Thus option D is correct.
What are electrons?Electrons can be defined as a negatively charged subatomic particle that together with protons and neutrons forms an atom's nucleus. It is the lightest subatomic particles.
s orbital has 2 electrons in pair
p orbital has 6 electrons in pair
d orbital has 10 electrons in pair
f orbital has 14 electrons in pair.
Thus, the total number of electrons that can occupy the f sublevel is 14 electrons. Thus option D is correct.
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what does a purple color change for the acid phosphatase test, a negative microscopic exam, and two lines on the p30 test indicate?
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A purple color change for the acid phosphatase test, a negative microscopic exam, and two lines on the p30 test are all results that are used to diagnose the presence of prostatic adenocarcinoma (cancer of the prostate gland).
The acid phosphatase test is used to detect the presence of the acid phosphatase enzyme, which is often elevated in prostate cancer. The negative microscopic exam is used to rule out the presence of any other underlying conditions that may be causing symptoms similar to prostate cancer. The p30 test is used to detect the presence of a protein known as prostate-specific antigen (PSA), which is often elevated in men with prostate cancer. The two lines on the p30 test indicate the presence of PSA and provide a positive result for prostate cancer.
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