What is the mass of 1 mole of magnesium oxide?

Vapor density is defined as the amount of weight of a gas or vapor in comparison to air.

The relative weight of a gas or vapor in comparison to air, which has an arbitrary value of one, is defined as vapor density. If a gas's vapor density is less than one, it will rise in air. When the vapor density exceeds one, the gas will normally sink in air.

Vapor density is only a broad concept used to estimate where vapors might be discovered when released. This physical parameter, however, is not absolute and can be influenced by:

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At high temperatures, a diatomic molecule possesses a total of six degrees of freedom.

Because a gas molecule may travel in any direction, it has three translational degrees of freedom. This is true for all gas molecules, whether monatomic, diatomic, or polyatomic, since every molecule in three-dimensional space may travel freely in all directions.

As a result, a diatomic molecule possesses five degrees of freedom: three translational and two translational.

As a result, a diatomic gas molecule possesses 6 degrees of freedom. This set may be divided into molecular translations, rotations, and vibrations. Three degrees of freedom are accounted for by the whole molecule's center of mass motion.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 13 g

density = 19.3 g/cm³

We have

\(volume = \frac{13}{19.3} \\ = 0.673575...\)

We have the final answer as

Hope this helps you

Answer:

Explanation:

3× 22+2×32+ 6×16=

66+64+96=236

The standard reduction potential of a species is the tendency of that species to get reduced. It measures the reduction tendency of a chemical species.

What is reduction?

Reduction in a chemical reaction is the increase in the number of electrons of the atoms or group of atoms involved. The reaction which loses oxygen or gains hydrogen can also be termed as reduction.

Standard reduction potential measures the tendency of a chemical species to get reduced. It can be calculated by subtracting the standard reduction potential at anode from the standard reduction potential at the cathode.

Therefore, standard reduction potential of a given species is the tendency of that species to undergo reduction in a redox reaction.

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Answer:

a

Explanation:

Answer:

1+

Explanation:

Hope this helped!

Answer:

I believe B

Explanation:

Hope this helps

By performing these qualitative tests, you can distinguish between benzoic acid and benzyl alcohol based on their solubility, reaction with sodium bicarbonate, formation of a complex with ferric chloride, and their ability to undergo oxidation. Remember to conduct these tests in a well-ventilated area and use proper safety precautions.

To distinguish between benzoic acid and benzyl alcohol using qualitative tests, you can perform the following tests:

1. Solubility Test: Both benzoic acid and benzyl alcohol are soluble in organic solvents like ethanol and acetone. However, benzoic acid is not soluble in water, while benzyl alcohol is.

2. Sodium Bicarbonate Test: Add a small amount of sodium bicarbonate to separate test tubes containing each compound. Benzoic acid will react with sodium bicarbonate to produce effervescence (bubbles) due to the release of carbon dioxide gas. Benzyl alcohol, on the other hand, will not react.

3. Ferric Chloride Test: Add a few drops of ferric chloride solution to separate test tubes containing each compound. Benzoic acid will form a deep purple color due to the formation of a complex with ferric chloride. Benzyl alcohol will not show any significant color change.

4. Oxidation Test: Benzoic acid can be oxidized to form benzaldehyde by using an oxidizing agent like potassium permanganate. Benzyl alcohol, on the other hand, will not undergo oxidation.

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Answer:gas, solid

Explanation:ck12

In a solution of hydrogen in palladium, gas is used as a solute and solid is used as a solvent.

This is defined as a homogenous mixture which comprises of two or more substances.  Solute usually dissolves in the solvent to form it.

The hydrogen acts as the solute while the palladium acts as the solvent in this case.

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Answer:

The answer is 101.1032

Explanation:

Answer:

A. Two water molecules interact due to partial charges on the oxygen and hydrogen atoms

Explanation:

Answer:

geosphere

Explanation:

Answer:

differential weathering.

Explanation:

The Sun doesn't heat the Earth evenly. Because the Earth is a sphere, the Sun heats equatorial regions more than polar regions. The atmosphere and ocean work non-stop to even out solar heating imbalances through evaporation of surface water, convection, rainfall, winds, and ocean circulation.

If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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It's possible that the student made an error during the experiment, such as not measuring the volume of water correctly or making a mistake in the calculation. It's also possible that there were external factors that affected the measurement, such as the temperature of the water, the equipment used, or the presence of impurities in the water.

What is Density?

Density is a physical property of matter that describes how much mass is contained in a given volume of a substance. It is calculated by dividing the mass of an object by its volume, and is typically expressed in units such as grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

In simpler terms, density is a measure of how closely packed the atoms or molecules are within a substance. Substances with a higher density have more mass per unit volume, while substances with a lower density have less mass per unit volume. For example, lead is a dense material with a density of about 11.3 g/cm³, while air is much less dense with a density of about 0.0012 g/cm³ at room temperature and atmospheric pressure.

To determine the cause of the discrepancy, the student could repeat the experiment multiple times to see if the results are consistent, use different methods or equipment to measure the density of water, or compare the results with other published values to see if they are within an acceptable range. It's important for the student to identify and correct any sources of error to ensure the accuracy of their results.

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Energy required to take a 22. 0-g sample of liquid water at 25. 0 °c to steam at 145. 0 °c is 58.6 KJ.

q1 = heat required to warm the water from 25.0 °C to 100.0 °C.

    = mCΔT

    = 22.0 g x  4.184 J∘C−1g−1 x 75

    = 6903.6 J

q2 = heat required to vapourize the water to steam at 100 °C.

    = mΔH vap  

    = (22.0 g  x 40.7  103  J/ mol )/18 g/ mol

    = 49744. 4 J

q3= heat required to warm steam from 100°C to 145.0 °C.

    = mCΔT

    = 22.0 g x  2.01 J∘C−1g−1 x 45°C

    =  1989.9 J

Total energy required to  take a 22.0 g sample of liquid water at 25.0 degrees Celsius to steam at 145.0 degrees Celsius is:

   =  q1   +  q2  + q3

   =  6903.6 J  + 49744. 4 J + 1989.9 J

   = 58,637.9 J

   = 58.6379 KJ

   = 58.6 KJ

Energy is described as having the "ability to conduct work, which is the capacity to apply a force that causes an item to be displaced.

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KNO₃  in H₂O gives a more concentrated solution than KNO₃ in CCl₄

1. KNO₃ in H₂0

• KNO₃ contains potassium and nitrate ions and so is an ionic compound held by ionic bond

• Ionic compounds dissolve in water because water being polar in nature, break the ionic bond and interact strongly with positive and negative ions of the ionic compound. Therefore, Kno3 in water is more concentrated.

2. KNO₃ in CCl₄

• CCl₄is an organic, non-polar solvent

• Ionic compounds does not dissolve in CCl₄ because CCl₄ being non polar in nature, cannot decrease the force of attraction between the ions.  Therefore, KNO₃ in CCl₄ is less concentrated.

Thus we can conclude that ionic compounds dissolve in polar solvents but not in non-polar solvents.

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The molar mass of the metal is 191.1g/mol.

Solution:

Since the formula for faraday's law of electrolysis is given by

Since m = 0.1427g, I = 144.2mA = 144.2mA *(1A/1000mA) = 0.1442 A= 0.1442C/s, t = 16min39s = 16min*(60s/1min) = 960+39 = 999 second Z = 2e-mol

Now put all values in the above formula

0.1427 g = (0.1442 C*999s*M*1 mole e-*1 mol/96485C*s*2e-mol)

M = (0.1427g*96485*2/0.1442*999*1)

M = 191.1538 g/mol = 191.1g/mol

Therefore the molar mass of metal will be 191.1g/mol.

For chemical elements that do not have isolated molecules such as carbon and metals, the molar mass is instead calculated by dividing by the number of atomic moles. Molar mass is defined as the mass in grams of one mole of a substance. The unit of molar mass is gram/mole, abbreviated g/mol.

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The commercial preparation's enzyme concentration is 500 [E]T.

Let X represent the enzyme concentration in the prepared product.

Step 1: Initial dilution: A commercial product in the amount of 0.100 mL was diluted to a final volume of 25.0 mL. This final solution will be known as solution 1.

Utilizing the formula C1V1 (commercial preparation) = C2V2 (solution 1)

Alternatively, X 0.100 mL = C2 25.0 mL

Alternatively, C2 = (X x 0.100 mL) / (25.0 mL) = 0.004X

Consequently, solution 1's enzyme concentration is 0.004X.

Step 2: Second dilution: The substrate and solution 1 were combined in a volume of 1.0 mL.

As a result, the reaction mixture's total volume (dilution) is equal to 1.0 mL plus 1.0 mL.

Prepare a 0.5% solution (0.5 g in 100 ml) initially, then dilutions of 0.25, 0.1, 0.025, and 0.05% to respective concentrations of the half, one-fifth, one-twentieth, and one-tenth. For example, to ten times dilution and a concentration of 0.05%, add 9 ml water to 1 ml of the stock solution.

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Answer:

pH≈10.5

Explanation:

-log(3 x 10-11)≈10.5

Answer:

The answer is allotropes

Explanation:

As known by studying and research the ansqer came out to be allotropes

Answer:

Chemically

in chemistry

Given your question, this chemical element most likely belongs to: C. The halogens, Group 17.

Valence electrons is the number of electrons that is present in the outermost shell (energy level) of an atom.

In Chemistry, valence electrons are used in the following ways:

Halogens are chemical elements belonging or found in Group seven (7) of the periodic table. Thus, these group of chemical elements are characterized by the need for a single electron to to complete its valence shell (outermost energy level).

In conclusion, the halogens, Group 7 needs only one electron to fill their valance shell.

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Your question is lacking the necessary answer options, so I will be adding them here:

A. The alkali metals, Group 1

B. The alkali metals, Group 2

C. The halogens, Group 7

D. The halogens, Group 18

Option D I got it right

ANSWER: C (ENERGY WAS RELEASED WHEN THE MOLECULE WAS FORMED FROM ITS ELEMENTS.)

HOPE THE OTHER PERSON IS WRONG!

Answer:

Element A is pottassium an alkali metal

Element B is a noble gas

Element C is bromine I think which is a halogen

Element D is lithium I think...or some other from group 2 or 1