What is the name in a position called

Answer:

i think the answer should be a

a. As per the balanced reaction, 2 moles of hexane gives 12 moles of carbon dioxide. Then, 7.77 moles of hexane will give 46.2 moles of carbon dioxide.

Combustion is an exothermic reaction in which a gas reacts with oxygen to give carbon dioxide and water. Given the combustion reaction of hexane gas.

b. molar mass of hexane = 86 g/mol

no.of moles in 8.11 g = 8.11 /86 = 0.094 g

2 moles of hexane gives 12 moles of carbon dioxide. Then 0.094 moles of hexane will give

0.094 × 12/2 = 0.56 moles

molar mass of carbon dioxide = 44 g/mol

then, mass of 0.56 moles = 0.56 × 44 = 24.6 g

c. 2 moles of hexane reacts with 19 moles of oxygen gas. Then, 25 moles of hexane needs to reacts with 237.5 moles of oxygen gas.

mass of oxygen gas = 32 g/mol

mass of 237.5 moles = 32 × 237.5 = 7600 g of oxygen is needed.

d. 2 moles of hexane gives 14 moles of water vapor. That is 172 g of hexane gives (18 × 14) 252 g of water.

then, 55.3 kg of hexane gives:

(55.3 kg × 0.252 kg)/0.172 kg = 81 kg.

Therefore, 81 kg of water vapor is produced from 55.3 kg of hexane.

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Answer: A

Explanation:. In a cactus, carbon is fixed only during the day

Answer:

C and D

Explanation:

The answer is C and D

Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Answer: oxide

Explanation:..

2.87 L of water vapor would be produced for every 1.9 L of consumed ammonia.

One nitrogen atom and three hydrogen atoms make up the colorless gas known as ammonia, which has a strong odor. It has the molecular formula NH3. Ammonia is very soluble in water, making liquid form convenient to handle and store.

The balanced chemical formula for the ammonia and oxygen reaction that produces water vapor and nitrogen monoxide is:

4 NH3(g) + 5 O2(g) =  4 NO (g) + 6 H2O(g)

We can see from the equation that everything balances out that 6 moles of water vapor are created for every 4 moles of ammonia that is consumed. This ratio can be used to determine how much water vapor will be created when 1.9 L of ammonia is consumed.

We must first translate the amount of ammonia from liters to moles. Every gas has a 22.4 L/mol molar volume at standard temperature and pressure (STP).

1.9 L of ammonia is equal to:

 1.9 l / 22.4 l/mol=0.085 moles of ammonia.

Next, we can determine how many moles of water vapor were created using the mole ratio from the balanced equation:

6 moles of H2O are created from 4 moles of NH3.

x moles of H2O are produced from 0.085 moles of NH3.

x=(0.085 moles NH3) x (6 moles H2O/ 4 moles NH3) = 0.128 moles H2O

Using the molar volume, we can finally convert the moles of water vapor generated at STP to volume:

0.128 moles of H2O x 22.4 L/mol = 2.87 L of H2O

Consequently, 2.87 L of water vapor would be produced for every 1.9 L of consumed ammonia.

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The amount of hydrogen left over is 9.683 g.

The balanced chemical equation for the reaction between molecular hydrogen (H₂) and oxygen (O₂) to form water (H₂O) is:

2H₂ + O₂ -> 2H₂O

The equation shows that two moles of hydrogen react with one mole of oxygen to produce two moles of water.

To determine which reactant is left over, we need to calculate how much of each reactant is required for the reaction and compare it with the actual amount provided.

The reactant that is not completely consumed will be left over.

First, we need to convert the masses of hydrogen and oxygen to moles using their respective molar masses:

Molar mass of hydrogen (H2) = 2.016 g/mol

Molar mass of oxygen (O2) = 31.9988 g/mol

Number of moles of hydrogen = 10.0 g / 2.016 g/mol = 4.96 mol

Number of moles of oxygen = 10.00 g / 31.9988 g/mol = 0.3125 mol

From the balanced equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen.

Therefore, the number of moles of oxygen required to react with 4.96 moles of hydrogen is:

0.5 x 4.96 = 2.48 mol

Since we only have 0.3125 mol of oxygen, it is the limiting reactant, and hydrogen is in excess.

To find out how much hydrogen is left over, we need to calculate how much hydrogen was used in the reaction:

Number of moles of water produced = Number of moles of oxygen used = 0.3125 mol

Number of moles of hydrogen used = 0.5 x 0.3125 = 0.15625 mol

The total number of moles of hydrogen we started with was 4.96 mol, and 0.15625 mol of hydrogen was used in the reaction.

Therefore, the amount of hydrogen left over is:

4.96 mol - 0.15625 mol = 4.80375 mol

Finally, we can convert this back to a mass:

Mass of hydrogen left over = 4.80375 mol x 2.016 g/mol = 9.683 g

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Answer:

The amount of hydrogen left over is 9.683 g.

Explanation:

Answer:

D. all of the above

Explanation:

need brainliest

Answer:

The periodic table is important because it is organized to provide a great deal of information about elements and how they relate to one another in one easy-to-use reference. The table can be used to predict the properties of elements, even those that have not yet been discovered.

The oxidation number of chlorine in KClO3 is +5 (option A).

The oxidation number of an element is the hypothetical charge of an atom within a molecule.

The oxidation number of an element like chlorine in a compound like Pottasium chlorate can be calculated as follows:

The oxidation number of the elements in KClO3 is as follows:

1 + x - 2(3) = 0

x - 5 = 0

x = +5

Therefore, the oxidation number of chlorine in KClO3 is +5.

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Answer:

0.0069 mol

Explanation:

Given data:

Temperature = 25°C

Volume of gas = 0.044 L

Pressure of gas = 3.81 atm

Number of moles of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

3.81 atm × 0.044 L = n × 0.0821 atm.L/ mol.K  ×  298 K

0.17  atm.L = n ×24.47 atm.L/ mol

n = 0.17  atm.L/24.47 atm.L/ mol

n = 0.0069 mol

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

The gas has been exhibiting the ideal nature. According to the ideal gas equation:

PV =nRT

P = pressure = 3.81 atm

V = volume = 0.044 L

R = constant = 0.0821

T = temperature = 25 \(\rm ^\circ C\) = 298 K

Substituting the value:

3.81 \(\times\) 0.044 = n \(\times\)  0.0821 \(\times\)  298

0.16764 = 24.4658 n

n = 0.00685 mol

n = 6.85 mmol

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

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Answer: A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances or phases. ... Solutions have particles which are the size of atoms or molecules - too small to be seen.

The number of moles of AgCl formed during the reaction is 0.0125 mol.

Given the reaction:2AgNO3(aq) + MgCl2(aq) → 2Ag Cl(s) + Mg (NO3)2(aq)We are supposed to determine the moles of solid AgCl formed when 50.0 ml of 0.250 M AgNO3 reacts with excess MgCl2 and in the previous step, we found that 0.0125 mol of AgNO3 reacts.

We can use the stoichiometry method to find the moles of AgCl formed.

To do so, we will have to balance the given chemical equation and find out the number of moles of AgCl formed from the given reactants.

The balanced chemical equation is:2AgNO3(aq) + MgCl2(aq) → 2Ag Cl(s) + Mg (NO3)2(aq)From the equation, we can say that 2 moles of AgCl form from 2 moles of AgNO3 reacted.

In the previous step, we have found the number of moles of AgNO3 reacted, which is 0.0125 mol.

As per the balanced chemical equation, 2 moles of AgCl form from 2 moles of AgNO3 reacted.

Therefore, the number of moles of AgCl formed = (0.0125 mol AgNO3 reacted × 2 moles AgCl / 2 moles AgNO3) = 0.0125 mol AgCl.

The number of moles of AgCl formed during the reaction is 0.0125 mol.

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Answer:

removal of H2O

✔ System will shift toward the products.

addition of O2      

✔ System will shift toward the products.

decrease in pressure

✔ System will shift toward the reactants.

increase in temperature      

✔ System will shift toward the reactants.

Explanation:

The reaction Equation :

2H₂ (g)  + O₂ (g) ↔ 2H₂O (g) + heat

Answer :

a) Removal of H₂O : The system will move towards the products of the reaction

b) addition of O₂ : The system will move towards the products of the reaction

c) decrease in pressure : The system will tend to move towards the reactants

d) Increase in temperature: The system will tend to move towards the reactants as well

Reason

In an equilibrium reaction changes to reactant components surroundings/conditions in which the reaction is been carried out can cause a significant change in the entire reaction process.

Hence; Removal of H₂O will cause the reaction system to move towards the products also the addition of O₂ will make the equation of the  reaction system move towards the product

Decrease in pressure and Increase in temperature causes the equation to move towards the reactants of the reaction

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

Explanation:

11- d

12- dont know

13- c

14- d = 30

15-  b =64

16- c = 34

17-  positive= 19 protons , negative= 19electrons , neutral = 39 - 19 = 20 notrons

18- chlorine-35

because atomic mass (35.453) is close to (35)

Explanation:

A kind of chemical reaction in which a reaction between any combustible substance and an oxidizer takes place in order to form an oxidized product.

Eg: Fuel + O2 → CO2 + H2O.

The burning of charcoal is a combustion reaction.

A synthesis reaction occurs when two or more reactants combine to form a single product.

Eg: Na + Cl → NaCl

An example of a synthesis reaction is the combination of sodium (Na) and chlorine (Cl) to produce sodium chloride (NaCl).

A decomposition reaction occurs when one reactant breaks down into two or more products.

Eg: NaCl → Na + Cl

An example of a decomposition reaction is the breakdown of Sodium chloride to give sodium and chloride.

A single replacement reaction, sometimes called a single displacement reaction, is a reaction in which one element is substituted for another element in a compound.

Eg: Zn + 2 HCl → 2 ZnCl + H2

The reaction between zinc metal and hydrochloric acid to produce zinc chloride and hydrogen gas is an example of a single-displacement reaction.

A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.

Eg: AgNO 3 + NaCl → AgCl + NaNO

The reaction between silver nitrate and sodium chloride to produce silver chloride and sodium nitrate is an example of a double-displacement reaction.

Answer:

The forensic laboratory system in the United States consists of private and public labs. One well-known public lab is the FBI (the Federal Bureau of Investigation) Public labs are mostly run by police officers and state employees, while private labs are organized as a fee-for-service and they are small with a few large and medium=sized operations.

Explanation:

Idk and it's not even 100 points but I hope this helps.

Answer:

0.378 g of H₂₂O can be produced.

Explanation:

The combustion reaction is:

2CH₃(CH₂)₂CH₃  +  13O₂  →  8CO₂  +  10H₂O

We convert the mass of reactants to moles:

0.58 g . 1mol / 58.1g = 0.00998 moles of butane

0.874 g . 1mol / 32g = 0.0273 moles of O₂

Oxygen is the limiting reactant. Look at stoichiometry.

2 moles of butane need 13 moles of oxygen to react

Then, 0.00998 moles of gas may react to (0.00998 . 13) / 2 = 0.06487 moles of oyxgen. I only have 0.0273 moles, so i do not have enough oxygen to complete the reaction.

Let's find out the product.

13 moles of oyxgen can produce 10 moles of water.

Then 0.0273 moles of O₂ may produce (0.0273 . 10)/13 =  0.021 moles

We convert to mass  →  0.021 mol . 18g /1mol = 0.378 g

Answer:

The trigger

Explanation:

Answer:

she should never touch the triggertriggertriggertritriggertrigger

Explanation:

The statement which is most likely correct about Newton's law on gravity is that It does not explain why objects exert gravitational force and the correct option is option 1.

As per the Newton's law of gravitation he said that two objects of different masses are placed at some distance from each other then the gravitational attraction force between two masses is

As per Universal law of gravitation Newton gives an experimental result about the gravitational force while the theoretical  explanation why the gravitational force exist is not explained by Newton's law of gravitation.

Thus, the ideal selection is option 1.

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First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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Answer: 4240.08

Explanation: 29 grams of NaOH is equivalent to .725 moles of NaOH since the molar mass of NaOH is 39.997. We do the calculation 29/39.997 to find the number of moles.

The unit M or molarity represents moles per liter. .171 M NaOH means there are .171 moles of NaOH in one liter of the solution. To find the volume needed, we can divided the number of moles we have which is .725 by .171 to find liters. This gives us 4.240 L or 4240.08 ml.

If you are confused by the calculation, you can look at how the units change: M=Mol/L .725 is in moles. We do mol/(mol/L) which is the same as mol*(L/mol) so the mol cancels and we are left with a unit in liters which we can easily convert to milliliters.

The number of moles of cesium chloride produced 0.183 moles.

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.

According to this question, the chemical formula for cesium chloride is CsCl. A chemist measured the amount of cesium chloride produced during an experiment. She finds that 30.8 g of cesium chloride is produced.

The molar mass of Cesium chloride is 168.36 g/mol

Moles = 30.8g ÷ 168.36g/lol

moles = 0.183 moles

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Answer:

342.29648 g/mol

Explanation:

Mass of sugar C₁₂H₂₂O₁₁ is required to provide 2.50 x 10²³ molecules of O₂ is 11.84.

Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.

No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.

Mass of a particular product is also find out by stoichiometry of a reaction as per the no. of mole given in the reaction.

Reaction is-

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

1 mole of C₁₂H₂₂O₁₁ forms 12 moles of O₂.

12 × 6.02214076 × 10²³ molecules of O₂ formed by 342.3 g of C₁₂H₂₂O₁₁.

1 molecule of O₂ formed by 4.73 × 10⁻²³  g of C₁₂H₂₂O₁₁.

2.50 × 10²³ molecules of O₂ formed by 11.84 g of C₁₂H₂₂O₁₁.

Therefore, Mass of sugar C₁₂H₂₂O₁₁ is required to provide 2.50 x 10²³ molecules of O₂ is 11.84.

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71. The broad, painless, pink-gray, wart-like infectious lesions that may develop on the vulva, perineum, or anus in syphilis are called "condyloma lata."

72. In suspected syphilis infection, the term RPR stands for "Rapid Plasma Reagin." It is a blood test used to screen for syphilis.

73. The recommended dosage of Benzathine Penicillin in an adult in Zambia may vary depending on the stage and severity of the syphilis infection. It is best to consult local guidelines or a healthcare professional for the specific recommended dosage in Zambia.

74. The recommended drug for the treatment of gonorrhea when using syndromic management may vary depending on local guidelines and antibiotic resistance patterns. Commonly used antibiotics include ceftriaxone in combination with azithromycin or doxycycline.

75. The causative organism for chancroid is called "Haemophilus ducreyi."

76. The commonest type of HIV is "HIV-1."

77. The assertive, problem-solving approach to the identification and treatment of the patient's problems is called "clinical decision-making."

78. A tumor arising from the cells producing melanin is also known as "melanoma."

79. The type of sound described as drum-like, loud, and empty quality felt over a gas-filled stomach, intestine, or pneumothorax during percussion is called "tympany."

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Answer: The half-life of the compound is 93 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

\(t=\frac{2.303}{k}\log\frac{a}{a-x}\)

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant =100

a - x = amount left after decay process = (100-36) = 64

a) for completion of 36 % of reaction

\(60=\frac{2.303}{k}\log\frac{100}{100-36}\)

\(k=\frac{2.303}{60}\log\frac{100}{64}\)

\(k=0.0074min^{-1}\)

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

\(t_{\frac{1}{2}}=\frac{0.693}{k}\)

\(t_{\frac{1}{2}}=\frac{0.693}{0.0074min^{-1}}=93min\)

The half-life of the compound is 93 minutes

If you have 2.60 x 10²³ molecules of (NH₄)₃PO₄, you have 64.7 grams of it.

The number of particles contained in a sample is measured in terms of the mole. One mole of a compound is the quantity of that substance that has a mass in grams equal to its relative atomic or molecular mass (atomic weight).To find the number of moles of (NH₄)₃PO₄, we'll need to use the Avogadro constant, which is 6.02 x 10²³. We can use the formula:moles = particles ÷ Avogadro constantThe number of particles is given as 2.60 x 10²³. Substituting the values:moles = 2.60 x 10²³ ÷ 6.02 x 10²³moles = 0.432Molar massNow that we have the number of moles of (NH₄)₃PO₄, we can compute its mass. The molecular mass of (NH₄)₃PO₄ is 149.0 g/mol. We can use the formula:mass = moles x molecular mass Substituting the values:mass = 0.432 x 149.0mass = 64.7 grams

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The theoretical yield of Acetylsalicylic acid is found out to be: 3.01 grams.

The limiting reagent is a substance that prevents a chemical reaction from occurring completely.

When a limiting reagent is used in a chemical reaction, the atoms, molecules, or ions of the other reactant that it (the limiting reagent) reacts with will either stay free or unreacted.

Popular compounds called acids and bases interact with one another to create salt and water. The Latin word "acere," which meaning "sour," is where the term "acid" originates.

According to the problem, we have 2.31 grams of salicylic acid. We need to determine the theoretical yield of acetylsalicylic acid.

The molar mass of salicylic acid is 138.12 g/mol. Therefore, the number of moles of salicylic acid we have is:

n = mass / molar mass

n = 2.31 g / 138.12 g/mol

n = 0.0167 mol

According to the balanced equation, 1 mole of salicylic acid reacts with 1 mole of acetic anhydride to produce 1 mole of acetylsalicylic acid. Therefore, the number of moles of acetylsalicylic acid produced is also 0.0167 mol.

The molar mass of acetylsalicylic acid is 180.16 g/mol. Therefore, the theoretical yield of acetylsalicylic acid is:

mass = n x molar mass

mass = 0.0167 mol x 180.16 g/mol

mass = 3.01 g

Therefore, the theoretical yield of acetylsalicylic acid is 3.01 grams.

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