What is the name of an ammonia molecule in which one of the
hydrogen atoms is replaced by a propyl group?
Group of answer choices:
a. Propylamide
b. Propaneamine
c. Propanamide
d. Propylamine

For a  concentration of  is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B  is mathematically given as

x=3.0*10^{-7}m

Generally, the equation for the  change in Gibbs free energy   is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m

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a) y[n]= 3x[2n] is stable, b)  y[n] = n^2x[n+l] is unstable, c) y[n] = Cos(omega 0 n) x[n-5] is stable, and d) y[n] = e^n x[5-n] is unstable.

The first system, y[n] = 3x[2n], is stable. This is because the output of the system is determined by the input and the response of the system to a given input is always the same, regardless of the number of time steps passed.

The second system, y[n] = n^2x[n+1], is unstable. This is because the output of the system is dependent on the input as well as the number of time steps passed. This means that the response of the system can vary over time, making it an unstable system.

The third system, y[n] = Cos(omega 0 n) x[n-5], where omega 0 is a constant, is stable. This is because the output of the system is determined by the input and the frequency of the oscillation, which is constant. This means that the response of the system will be consistent regardless of the number of time steps passed.

The fourth system, y[n] = e^n x[5-n], where N is a constant, is unstable. This is because the output of the system is dependent on the input as well as the number of time steps passed. This means that the response of the system can vary over time, making it an unstable system.

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Answer:a mouse

Explanation:

Answer: a mouse

Explanation:

Explanation: To dissolve an ionic compound, the water molecules must be able to stabilize the ions that result from breaking the ionic bond. They do this by hydrating the ions. ... When you place an ionic substance in water, the water molecules attract the positive and negative ions from the crystal.

The correct reactant ratio for the reaction 2Fe + 3Cl2 → 2FeCl3 is 2 moles of iron (Fe) for every 3 moles of chlorine (Cl2).

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The reaction with S_N₂mechanism is likely to be faster than the reaction with S_N₂ mechanism. This is because the carbocation intermediate formed in S_N₁ mechanism is more stable.

The pair of reactions given below is:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH₃OH + NaI

The type of substitution mechanism:

The first reaction involves S_N₁ mechanism (unimolecular nucleophilic substitution). The second reaction involves S_N₂ mechanism (bimolecular nucleophilic substitution).

Prediction of the reaction that will occur at a faster rate:

The reaction with S_N₁ mechanism is likely to be faster. The rate of this reaction mainly depends on the stability of the carbocation intermediate formed after the initial step. In this case,CH₃Cl reacts to form a tertiary carbocation which is more stable than the primary carbocation formed in CH₃I.

Drawing the correct organic product:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH_3OH + NaI

CH₃C reacts with NaOHin an S_N₁ mechanism to produceCH₃OH and NaCl.


CH₃ reacts withNaOH in an S_N₂mechanism to produce CH₃OH and NaCI.


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Answer:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Best regards!

Answer:

volume = 16.8

Explanation:

From the question

The Mass = 1.5g.

Molar mass = H2

= 1×2 =2

mole = ?

\(mole = \frac{mass}{molar \: mass} \\ mole = \frac{1.5}{2} \\ mole = 0.75mol\)

Therefore the volume =

\(v = v {dm}^{3} \times n\)

Where mole(n)=0.75mol.

vdm³=22.4dm³

\(v = 22.4 \times 0.75 \\ v = 16.8\)

Therefore the volume = 16.8.

Jasmine's velocity was 2.8 meters per second. However, we don't know if this was enough to catch up with her friend who was rollerblading at 12 meters per second.

What is Velocity?

The pace at which the position of an object changes with respect to time is known as its velocity. Due to the fact that it is a vector quantity, it possesses both magnitude and direction.

Mathematically, velocity is expressed as:

velocity = displacement / time

where displacement is the change in an object's position from one point to another, and time is the duration of the motion. Velocity is measured in units of distance per time, such as meters per second (m/s) or kilometers per hour (km/h).

To calculate Jasmine's velocity, we need to use the formula:

velocity = distance / time

Jasmine ran a distance of 98 meters in 35 seconds, so her velocity is:

velocity = 98 meters / 35 seconds

velocity = 2.8 meters per second

Therefore, Jasmine's velocity was 2.8 meters per second. However, we don't know if this was enough to catch up with her friend who was rollerblading at 12 meters per second.

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The given statements I (For a strong acid-strong base titration, the pH at the equivalence point is equal to 7) and II (For a weak acid-strong base titration, the pH at the equivalence point is greater than 7) are true, while statement III (dding a common-ion to the solution will increase the solubility of the insoluble salt) is false.

In a strong acid-strong base titration, statement I is true. When a strong acid reacts with a strong base, the products are a salt and water, leading to a neutral solution with a pH of 7 at the equivalence point. This occurs because the strong acid and strong base completely dissociate, and their respective ions combine to form water.

Statement II is also true. In a weak acid-strong base titration, the pH at the equivalence point is greater than 7. This is because a weak acid does not completely dissociate in water, leaving a significant amount of conjugate base in the solution when it reacts with the strong base. The conjugate base from the weak acid can accept a proton from water, resulting in an increase in hydroxide ions (OH-) and a pH above 7 at the equivalence point.

However, statement III is false. Adding a common-ion to a solution containing an insoluble salt will decrease the solubility of the salt, not increase it. This occurs due to the common-ion effect, which states that the presence of a common ion suppresses the ionization of a weak electrolyte, causing the equilibrium to shift towards the formation of the insoluble salt and leading to a decrease in solubility.

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Answer: Ionic Bond

Explanation: They form when the cation and the anion have opposite charges, and attract each other

Answer:

There isn't any picture for me to see

have a good day :)

Explanation:

This particular alkane is distinguished from all the other alknes by reason of the shape of the alkane.

The term alkanes has to do compounds that have only a carbon to carbon single bond. We have to note that alknaes can be cyclic, linear or branched. All this types of alkanes are easily recognized by shape.

This particular alkane is distinguished from all the other alknes by reason of the shape of the alkane.

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Answer: A) The shape

Explanation:

edge 22 - took the quiz and got it correct

hope it helps <3

The given density of ethanol solution is 0.9645 g/ml and the concentration of ethanol solution is 2.55 m.

To calculate the molality of the solution, first, we need to calculate the molar mass of ethanol, which is given as follows:

Molar mass of C₂H₅OH = (2 × 12.01) + (6 × 1.01) + 16.00 = 46.07 g/mol

Now, we can calculate the molality of the solution as follows:

Molality (m) = moles of solute / mass of solvent (kg)Now, we need to find out the mass of the solvent that is present in the solution.

We know that the density of the solution is given as follows:

density = mass / volume0.9645 g/mL = mass / 1 mL

mass of solution = density × volume = 0.9645 g/mL × 1000 mL= 964.5 g = 0.9645 kg

Volume of solution = 1000 mL = 1.0 L

Now, we can calculate the moles of ethanol (C₂H₅OH) as follows:

Moles of C₂H₅OH = concentration × volume of solution= 2.55 m × 1.0 L= 2.55 mol

Now, we can calculate the molality of the solution as follows:

Molality (m) = moles of solute / mass of solvent (kg)= 2.55 mol / 0.9645 kg= 2.648 m

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Answer:

A: Aluminum

Explanation:

You are more likely to find pure aluminum than any other of the materials on the list because aluminum is one of the most abundant materials on Earth, making up about 8% of the Earth's crust, and it can be found in over 270 naturally occuring minerals.

Answer:

The answer is "aluminum" brother.

Explanation:

I've been studying brother.

Answer:

A: electrons

Explanation:

Answer:

C

Explanation:

others are boring or gems

Answer:

c

Explanation:

i took the test

Answer:

General equation for a double-displacement reaction:  

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄  

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄  

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄  

Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄

The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃  

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃  

NaOH + AgNO₃   --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃  --> NaNO₃ +  Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

The two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate are copper(II) phosphate and sodium chloride.

The empirical formula of the copper phosphate =\(Cu_3P_2O_8\)

The empirical formula of the sodium chloride = \(NaCl\)

Explanation:

\(3CuCl_2(aq)+2Na_3PO_4(aq)\rightarrow Cu_3(PO_4)_2(s)+ 6NaCl(aq)\)

Charge on the copper(II) ion = +2

Charge on the phosphate ion = -3

The ratio of a number of copper, phosphorus, and oxygen atoms:

\(Cu:P:O=3:2:8= 3:2:8\)

The empirical formula of the copper phosphate =\(Cu_3P_2O_8\)

Charge on the sodium ion = +1

Charge on the chloride ion = -1

The ratio of a number of sodium and chlorine atoms:

\(Na:Cl=1:1=1:1\)

The empirical formula of the sodium chloride = \(NaCl\)

The two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate are copper(II) phosphate and sodium chloride.

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The volume of calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point is 87.5 mL.

In the given case, we have to calculate the volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point.

The chemical equation for the reaction of phosphoric acid with calcium hydroxide is given below:

H₃PO₄ + Ca(OH)₂ → Ca(H₂PO₄)₂ + 2H₂O

Molar mass of H₃PO₄ = 3(1.008) + 1(30.974) + 4(15.999)

                                    = 98.0 g/mol

Molar mass of Ca(OH)₂ = 1(40.078) + 2(15.999)

                                         = 74.1 g/mol

Number of moles of H₃PO₄ in 35.0 mL of 0.440 M

phosphoric acid= Molarity × Volume(in liters)

= 0.440 × (35.0/1000)

= 0.0154 mol

Number of moles of Ca(OH)₂ required to react completely with 0.0154 mol of H₃PO₄= 0.0154 mol

Number of moles of Ca(OH)₂ present in the solution

= Molarity × Volume(in liters)

= 0.530 × Volume

Calcium hydroxide will react with phosphoric acid until the third equivalence point is reached.

Ca(OH)₂ + 2H₃PO₄ → Ca(H₂PO₄)₂ + 2H₂O(moles)

0.0154         0.031                0.0464

(Molarity) 0.53              0.53              0.53

(Volume)    V₁                   V₂                         V₃

Equivalence point is the point where the number of moles of two reactants is equal to each other.The number of moles of H₃PO₄ is equal to the number of moles of Ca(OH)₂ at the third equivalence point,

So, 0.0464 mol of Ca(OH)₂ is required to react completely with 0.0154 mol of H₃PO₄  .

Volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point

= (0.0464 mol)/(0.530 mol/L)

= 0.0875

L= 87.5 mL (rounded to three significant figures)

Therefore, the volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point is 87.5 mL.

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To calculate the amount of energy required to melt 235 grams of aluminum, we need to use the equation Q = m * ΔHf

Where Q is the heat energy, m is the mass of the substance, and ΔHf is the heat of fusion.

First, we need to convert the mass of aluminum from grams to moles. The molar mass of aluminum (Al) is 26.98 g/mol.

moles of Al = mass of Al / molar mass of Al

moles of Al = 235 g / 26.98 g/mol ≈ 8.71 mol

Next, we can calculate the heat energy required to melt the aluminum:

Q = m * ΔHf

Q = 8.71 mol * 10.6 kJ/mol

Multiplying the moles by the heat of fusion, we get:

Q = 92.326 kJ

Therefore, approximately 92.326 kilojoules (kJ) of energy are required to melt 235 grams of aluminum at its melting temperature of 658°C.

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The amount of sodium carbonate present in 575 L is 6,133.33 g.

First, we need to determine the amount of sodium carbonate present in 15 mL. Let's assume that the concentration of sodium carbonate is 0.1 M. This means that there are 0.1 moles of sodium carbonate in 1 liter of solution. Therefore, in 15 mL of solution, there are:

0.1 mol/L x 0.015 L = 0.0015 moles of sodium carbonate.

Next, we need to convert this value to grams. The molar mass of sodium carbonate (Na2CO3) is 105.99 g/mol. Therefore, the mass of 0.0015 moles of Na2CO3 is:

0.0015 mol x 105.99 g/mol = 0.16 g of Na2CO3.

To find out how much sodium carbonate is present in 575 L, we need to use a conversion factor. There are 1000 mL in 1 L, so there are:

575 L x 1000 mL/L = 575,000 mL of solution.

Therefore, the amount of sodium carbonate in 575 L of solution can be calculated as:

0.16 g x (575,000 mL / 15 mL) = 6,133.33 g or approximately 6.13 kg of Na2CO3.

There are approximately 6.13 kg of sodium carbonate present in 575 L of solution, assuming a concentration of 0.1 M. This calculation was done by first determining the amount of sodium carbonate in 15 mL of solution and then using a conversion factor to scale up to 575 L.

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Answer:

Explanation:

Number of moles = mass/molar mass

molar mass of MgSO4 = 24 +32+16(4)

= 120g/mol

number of moles=17/120

=0.141 moles

Answer:

\(\boxed {\boxed {\sf 0.14 \ mol \ MgSO_4}}\)

Explanation:

We are asked to find the number of moles in 17 grams of magnesium sulfate or MgSO₄.

We convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. The values are found on the Periodic Table because they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up the molar masses of the individual elements: magnesium, sulfur, and oxygen.

Notice the formula contains a subscript of 4 after the symbol O. There are 4 moles of oxygen in 1 mole of magnesium sulfate. We must multiply oxygen's molar mass by 4 before adding the other molar masses.

We will convert using dimensional analysis, so we set up a ratio.

\(\frac {120.371 \ g \ MgSO_4}{ 1 \ mol \ MgSO_4}\)

We are converting 17 grams of magnesium sulfate to moles, so we multiply the ratio by this value.

\(17 \ g \ MgSO_4 *\frac {120.371 \ g \ MgSO_4}{ 1 \ mol \ MgSO_4}\)

Flip the ratio so the units of grams of magnesium sulfate cancel.

\(17 \ g \ MgSO_4 *\frac{ 1 \ mol \ MgSO_4} {120.371 \ g \ MgSO_4}\)

\(17 *\frac{ 1 \ mol \ MgSO_4} {120.371 }\)

\(\frac{17} {120.371 } \ mol \ MgSO_4\)

\(0.1412300305 \ mol \ MgSO_4\)

The original measurement of grams (17) has 2 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 1 in the thousandth place tells us to leave the 4 in the hundredth place.

\(0.14 \ mol \ MgSO_4\)

17 grams of magnesium sulfate are equal to 0.14 moles of magnesium sulfate.

When the enthalpy is positive (H > 0), the reaction is endothermic, that is, it absorbs energy.

When the enthalpy is negative (H< 0), the reaction is exothermic, that is, it releases energy.

Therefore, the correct matches are

Endothermic:

• Positive H Value.

• Absorbs Heat.

• Products have higher energy.

Exothermic:

• Negative H Value.

• Releases Heat.

• Products have lower energy.

Answer

A compound made of two ions.

Explanation

A binary compound is a compound formed from two different elements. There may or may not be more than one of each element.

For a binary ionic compound, a metal will always be the first element in the formula, while a nonmetal will always be the second.

Hence, a binary ionic compound is a compound made of two ions.

2,5 are the two phrases describing the synthesis of amino acids are accurate.

Alpha-ketoglutarate is transaminated in the human body to produce lysine, an important amino acid. The precursor is reduced during the amino acid alanine's synthesis, and oxidation occurs during alanine's breakdown.

The precursor is reduced during the amino acid alanine's synthesis, while oxidation occurs during alanine's breakdown. Metabolic pathway intermediates and alpha-keto acids are the carbon sources for the production of non-essential amino acids.

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Answer:

18.0 g

Explanation:

M(H2) = 2.0 g/mol

32.0g * 1 mol/2 g= 16 mol H2

M(O2) = 32 g/mol

16.0 g * 1mol/32 g= 0.5 mol O2

                                      2H2 + O2 ---> 2H2O

from reaction              2 mol    1 mol

given                         16 mol     0.5 mol

We see that O2 is a limiting reactant.

                                    2H2 + O2 +-------> 2H2O

from reaction                         1 mol            2 mol

given                                      0.5 mol        x mol

x =(0.5*2)/1= 1 mol H2O

M(H2O)= 18 g/mol

18 g/mol* 1 mol = 18 g H2O

When the reaction is subjected to pressure, the equilibrium will shift to the side with fewer gas molecules, which is the left side. Therefore, the answer is c. left.

According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in pressure, it will respond by shifting in a way that reduces the effect of the change. In this case, increasing the pressure would cause the equilibrium to shift towards the side with fewer gas molecules to alleviate the increase in pressure.

Since there are fewer gas molecules on the left side of the reaction (2 CO + O2), the equilibrium will shift to the left to reduce the total number of gas molecules. This means that the concentrations of CO and O2 will increase, while the concentration of CO2 will decrease until a new equilibrium is established. Thus, the equilibrium will shift to the left.

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Answer:Ratio of proton to electron mass: 1,836.2.

Explanation: