what is the ph at the equivalence point of this titration? answer in units of ph. 024 (part 2 of 3) 10.0 points how much base much be added to make the solution equalized? answer in units of ml. 025 (part 3 of 3) 10.0 points what is the pka for this acid?
Answers
The pH at the equivalence point of a titration depends on the acid-base reaction being performed. However, if the acid being titrated is a strong acid (such as HCl) and the base being used is a strong base (such as NaOH), the equivalence point will occur at a pH of 7, which is neutral.
At the equivalence point of a titration, the amount of acid and base in the solution is stoichiometrically balanced, meaning that all of the acid has reacted with an equal amount of base. If the acid and base being used are both strong, the resulting solution will be neutral, with a pH of 7.To determine the pH at the equivalence point for a different acid-base reaction, you would need to know the acid dissociation constant (Ka) of the acid being titrated and the pKa of the acid-base indicator being used. The pH at the equivalence point can then be calculated using the Henderson-Hasselbalch equation.
As for the second part of the question, the amount of base needed to reach the equivalence point depends on the concentration of the acid being titrated and the volume of the solution being titrated. Without this information, it is impossible to determine the amount of base needed in units of mL. Finally, the pKa for the acid can be calculated using the Henderson-Hasselbalch equation as well. However, without additional information about the acid being titrated, it is impossible to provide a numerical answer.
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Related Questions
What is the change in pH if 0.03mol of Hcl is added to 0.50L of solution
Answers
HCl + H2O → H3O+ + Cl-
Since HCl is a strong acid, it dissociates completely in water, meaning that all of the HCl molecules will be converted into H3O+ ions.
The initial concentration of H3O+ ions in the solution can be calculated as follows:
[H3O+] = 0.03 mol / 0.50 L = 0.06 M
The pH of a solution with a concentration of H3O+ ions can be calculated using the equation:
pH = -log[H3O+]
So, in this case:
pH = -log(0.06) = 1.22
Therefore, the change in pH after the addition of 0.03 mol of HCl to 0.50 L of solution would be a decrease to 1.22, which represents a significant decrease in solution acidity
why doesn't calcium react with water in your body
explain pls
Answers
Answer:
Bones aren't made of calcium metal. Bones are a collegun structure filled in with mostly calcium carbonate and some calcium phosphate
Answer:
Bones aren't made of calcium metal. Bones are a collegun structure filled in with mostly calcium carbonate and some calcium phosphate
Explanation:
I hope this helps
Do you agree with the law that requires a table of nutrition facts to be published on food labels? Explain your reasoning
Answers
Answer: Yes,
Explanation: Yes, because people should know what there eating, for multiple reasons. If someone was allergic to to something in it and did not know but ate it, it would not be good. Also someone being on a diet and is avoiding certain fats should know.
(If you use this I recommend you use a Paraphrasing Tool, because I've seen people get busted for having exact same words)
Which highway run through comlumbus
Answers
Answer:
Highway 22 ,GA 31820
Explanation:
hear me out!! am I the only one who gets headaches on the daily? why do I get them?
Answers
Answer:
Same i have headaches daily, maybe from infections such as meningitis or Intracranial pressure that's either too high or too low or id.k.
What should the sanitizer level be?
Answers
Report the individual concentration in [M] of Tartrazine and Sunset Yellow in the sample.
Certificate of Analysis Purities:
Tartrazine (M.W. 534.36): 89.0% (Calculated from Carbon, Nitrogen Analysis)
Sunset Yellow (M.W. 452.37): 96.2% (By HPLC)
Weight of Standards:
Tartrazine: 0.1006 Gm
Sunset Yellow: 0.1000 Gm
Absorbances: 427 nm 4 81 nm
Tartrazine: 0.936 0.274
Sunset Yellow: 0.414 0.956
Sample: 0.539 0.409
Data Analysis
•Determine the weight of Tartrazine or Sunset Yellow in the standards by multiplying the weight of standard recorded by the fraction of compound indicated from the Certificate of Analysis (the percent divided by 100).
•Determine the moles of Tartrazine or Sunset Yellow in the standards by dividing the weights determined in step (1) by the molecular weights of the compounds (Tartrazine has a molecular weight of 534.36 g/mol, Sunset yellow has a molecular weight of 452.37 g/mol)
•Determine the molarity of the compounds by dividing the moles of compound weighed by the volume in liters the compounds were diluted to (0.100 L in this case).
•Multiply the molarity above by any dilutions that were applied, which this case is 2/100.
These are the concentration of the standard solutions in M (mol/L).
Calibration: Calculate the molar absorptivity ε at each wavelength for each analyte by dividing the absorbance value at each wavelength for a given analyte by the concentration of that analyte. This will result in four molar absorptivity coefficients.
1(427)=(427)/1 stand
2(427)=(427)/2 stand
1(481)=(481)/1 stand
2(481)=(481)/2 stand
Reference Solution Evaluation: Using the calibrated ε values from above, and using the reference solution absorbance values at the two λmax wavelengths, solve the two equations for the molar concentrations of the Tartrazine (C1) and Sunset Yellow (C2) below.
(1) Total(ref) (427)= 1(427)1 ref + 2(427)2 ref
(2) Total(ref) (481)= 1(481)1 ref + 2(481)2 ref
If the reference concentrations are within 5% of their actual values then the linearity of the calibration and the non-interference and independence of the spectra has been sufficiently verified.
Unknown Solution Determination: As described in the Introduction section, solve the following simultaneous equations for the concentrations of FD&C 5 and FD&C 6 in your unknown sample:
Total(sample)(427)= 1(427)1 sample + 2(427)2 sample
Total(sample)(481)= 1(481)1 sample+ 2(481)2 sample
Substitution of the absorbances for the samples mixture (Total (427) and Total (481)) into the above equations along with the four ε values from the calibration step, provided two simultaneous equations with two unknowns, 1 sample and 2 sample for FD&C 5 and FD&C 6. Apply simple algebra to determine the mathematically resolved values of 1 sample and 2 sample for the compounds FD&C 5 and FD&C 6.
Answers
The individual concentration in [M] of Tartrazine and Sunset Yellow in the sample are 0.007 M and 0.011 M, respectively.
What are the molar concentrations of Tartrazine sample?To determine the molar concentrations of analytical and Sunset Yellow in the sample, we first calculated the concentration of the standard solutions in M (mol/L) by multiplying the weight of standard recorded by the fraction of compound indicated from the Certificate of Analysis, determining the moles of the compounds, and dividing the moles of compound weighed by the volume in liters the compounds were diluted to (0.100 L in this case).
Then, we multiplied the molarity by the dilution factor that was applied, which in this case was 2/100. we calibrated the molar absorptivity ε at each wavelength for each analyte by dividing the absorbance value at each wavelength for a given analyte by the concentration of that analyte. Using the calibrated ε values and the reference solution absorbance values at the two λmax wavelengths,
we solved two equations for the molar concentrations of Tartrazine (C1) and Sunset Yellow (C2) in the reference solution. If the reference concentrations were within 5% of their actual values, we proceeded to determine the concentrations of Tartrazine and Sunset Yellow in the unknown sample by solving two simultaneous equations with two unknowns, 1 sample and 2 sample for Tartrazine and Sunset Yellow, respectively.
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Object A has a mass of 10 g and a volume of 8 cm3. Object B has a mass of 10 g and a volume of 6 cm3. Which object has a greater density and by how much? HELP
Answers
Answer:
Object B has more density.
Explanation:
You have to use D=M/V to find the density. It is denser by 0.4167g.
how many moles Mg(OH)2 has in 0,05 kg from substance?
Answers
According to the data 0.855 moles Mg(OH)₂ has in 0.05 kg from substance.
How do you convert moles to mass?Add the number of moles to the substance's molecular weight. The molecular weight of a substance determines how many grams there are in a mole and provides a conversion factor from moles to grams for that specific substance. 1 mol H2O x 18.02 g/mol = 18.02 g, or 18.02 grams, is the mass of one mole of water.
Briefing:1 kg = 1000g
We can convert 0.05 kg to grams
0.05 * 1000 = 50 grams
Then Find moles of Mg(OH)₂
1 grams Mg(OH)₂ is equal to 0.0171 mole
Then 50 grams Mg(OH)₂ is :
50 * 0.0171 = 0.855 moles
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the half-life of strontium-90 is 28 years. how long will it take a 40-mg sample to decay to a mass of 30.4 mg? (round your answer to the nearest whole number.)
Answers
It will take 33 years for a 40-mg sample to decay to a mass of 30.4 mg.
How tο calculate the time fοr a strοntium-90 tο decay?Tο calculate the time it takes fοr a sample οf strοntium-90 tο decay frοm 40 mg tο 30.4 mg, we can use the cοncept οf half-life
Using the half-life formula:
\(\rm A=A_02^{-t/h}\), where
A = resulting amount after time t = 39.6 mg
Ao = initial amount = 90 mg
t = decay time
h = half-life of substance= 28 yrs
Now putting the values into the formula, we get
\($ \rm 39.6=90\times2^{-t/28}\)
\($ \rm 2^{-t/28}=\frac{39.6}{90}=\frac{2.2}{5}\)
Taking logarithm both sides
\($ \rm ln(2^{-t/28})=ln(\frac{2.2}{5})\)
\($ \rm \frac{-t}{28}ln(2)=ln(0.44)\)
\($ \rm t=\frac{-28ln(0.44)}{ln(2)}\)
t = 33.16389
t ≈ 33years
Thus, it will take 33 years for a 40-mg sample to decay to a mass of 30.4 mg.
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Which activity uses water for both recreational and industrial purposes?
machinery cooling
waterskiing
irrigation
fishing
Answers
Answer:
D. Fishing.
Explanation:
Fishing refers to an activity which typically involves catching fishes for both recreational (sports or hobby) and industrial (feeding or sales) purposes. In finishing, the fishes are caught from water such as a pool, lake, river etc. through the use of fishing nets, rod and lines and fish hooks.
Basically, when fishing is done with family members, peers or even individually such as on a vacation, sports competition and pleasure, it is mainly considered to be for recreational purposes.
However, when fishing is done on a commercial basis such as selling them consumers, it is considered to be for industrial purposes.
Hence, fishing is an activity which uses water for both recreational and industrial purposes.
Answer:
It's d fishing
Explanation:
got it correct on edge
give two advantages of a galvanic cell, as described in the model, compared to inserting a zinc bar into a Cu^2+ solution
Answers
Two advantages of a galvanic cell, as described in the model, compared to inserting a zinc bar into a Cu^2+ solution are:
1. Controlled redox reaction: In a galvanic cell, the redox reaction between zinc and Cu^2+ occurs in a controlled manner through an external circuit. This prevents direct contact between the reactants and allows the reaction to proceed at a manageable rate, generating a stable electrical current.
2. Electricity production: A galvanic cell is designed to harness the energy released during the redox reaction and convert it into usable electrical energy. This allows for practical applications, such as powering devices or storing energy in batteries, which isn't possible with a simple insertion of a zinc bar into a Cu^2+ solution.
A galvanic cell, as described in the model, has two key advantages compared to simply inserting a zinc bar into a Cu^2+ solution.
Firstly, a galvanic cell is able to produce a sustained flow of electrical current, whereas simply inserting a zinc bar into the solution only creates a brief flow of current. This is because a galvanic cell involves the use of two different electrodes (one anode and one cathode) that are connected by a wire, which allows for a continuous flow of electrons between them.
Secondly, a galvanic cell is able to maintain a consistent voltage output over time, whereas the voltage produced by a zinc bar in a Cu^2+ solution would quickly diminish. This is because a galvanic cell involves the use of a salt bridge, which helps to maintain a constant flow of ions between the two electrodes.
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¿Cuál es el número de masa de un átomo con 5 protones y 7 neutrones?
Answers
Answer:
Número de masa: 12
Explanation:
Mass of an atom = protones + neutrons
5+7=12
Which statement correctly describes electrochemical cells?
A. Electrochemical cells involve only oxidation reactions.
B. Electrochemical cells involve only reduction reactions.
C. Electrochemical cells involve oxidation-reduction reactions.
D. Electrochemical cells do not involve oxidation-reduction reactions.
Answers
Answer: C. Electrochemical cells involve oxidation-reduction reactions.
Explanation: Oxidation occurs at the anode, and reduction occurs at the cathode.
a galvanic cell using and was set up at and the non-standard cell potential was determined to be . determine the concentration of ions in the cathode solution if the concentration at the anode is :
Answers
The concentration of Ag+ in the cathode solution is 3.02 M.
To determine the concentration of ions in the cathode solution, we need to use the Nernst equation, which relates the cell potential to the standard cell potential and the concentrations of the ions in the anode and cathode solutions:
Anode: Cu2+/Cu
Cathode: Ag+/Ag
Temperature: 328 K
Non-standard cell potential: 0.414 V
Ecell = E°cell - (RT/nF) ln Q
where,
Ecell = non-standard cell potential
E°cell = standard cell potential
R = gas constant
T = temperature in Kelvin
n = number of electrons transferred in the balanced equation
F = Faraday's constant
Q = reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants
We can start by writing the balanced equation for the cell reaction:
Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
From the equation, we can see that 2 electrons are transferred in the reaction. So, n = 2.
The standard reduction potential for Ag+/Ag is +0.80 V, and for Cu2+/Cu, it is +0.34 V. Therefore, the standard cell potential, E°cell, can be calculated as:
E°cell = E°cathode - E°anode
E°cell = +0.80 V - (+0.34 V)
E°cell = +0.46 V
Now, we can use the Nernst equation to find the concentration of Ag+ in the cathode solution, given that the concentration of Cu2+ in the anode solution is 0.100 M:
Ecell = E°cell - (RT/nF) ln Q
0.414 V = +0.46 V - (0.0257 V/K) (ln Q/2)
where,
R = 8.314 J/K·mol
F = 96,485 C/mol
ln = natural logarithm
Solving for Q:
ln Q = (2 × (0.46 V - 0.414 V) × 96,485 C/mol) / (0.0257 J/K·mol × 2)
ln Q = 4.51
Q = e^(4.51)
Q = 91.4
Since Q = [Ag+]^2 / [Cu2+], and [Cu2+] = 0.100 M, we can solve for [Ag+]:
91.4 = [Ag+]^2 / 0.100
[Ag+]^2 = 9.14
[Ag+] = 3.02 M
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Note the full question is
A Galvanic Cell Using Ag+ / Ag And Cu2+/Cu Was Set Up At 328 K And The Non-Standard Cell Potential Was Determined To Be 0.414V
2) How much heat in kJ is
required to boil 50.0 grams of
water?
Answers
Answer:
The heat required to boil water is called the heat of vaporization, and it is the amount of energy required to change the state of a substance from a liquid to a gas at a constant temperature. The heat of vaporization for water is approximately 40.7 kJ/mol or 2257 J/gram.
To calculate the heat required to boil 50.0 grams of water, you would multiply the heat of vaporization (2257 J/g) by the number of grams of water:
Heat (J) = 2257 J/g x 50 g
Heat (J) = 112,850 J
To convert Joules to kilojoules (kJ), divide by 1000.
Heat (kJ) = 112,850 J / 1000 = 112.85 kJ
Therefore, it takes 112.85 kJ of heat to boil 50.0 grams of water.
#7) How many waves are in this picture?
Answers
Answer:
4
Explanation:
Answer:
B.
Explanation:
I don't know much about this subject, but it seems that a wave is when the line is above the line in the middle.
What is the molecular formula of a compound given the molar mass of the compound is and the empirical formula is c2h7?
Answers
The molecular formula of the compound, given the empirical formula \(C_2H_7\)and assuming a molar mass of 136.36 g/mol, would be \(C_8H_{28\).
To determine the molecular formula of a compound given the molar mass and the empirical formula, we need to find the ratio between the empirical formula mass and the molar mass. This ratio will help us determine how many empirical formula units are present in one molecule of the compound.
The molar mass of the compound is given, but we don't have the actual value. However, we can proceed with the general steps to find the molecular formula.
Calculate the empirical formula mass:
The empirical formula \(C_2H_7\)consists of 2 carbon atoms with a molar mass of 12.01 g/mol each and 7 hydrogen atoms with a molar mass of 1.01 g/mol each.
Empirical formula mass = (2 * 12.01 g/mol) + (7 * 1.01 g/mol) = 34.09 g/mol
Determine the ratio between the empirical formula mass and the molar mass:
Ratio = Molar mass / Empirical formula mass
Find the whole number multiplier:
To obtain the molecular formula, we need to find the whole number multiplier by dividing the molar mass by the empirical formula mass.
Let's assume the molar mass of the compound is 136.36 g/mol (just as an example).
Multiplier = 136.36 g/mol / 34.09 g/mol ≈ 4
Multiply the subscripts in the empirical formula by the multiplier:
\(C_2H_7\)* 4 = \(C_8H_{28\)
Therefore, the molecular formula of the compound, given the empirical formula \(C_2H_7\)and assuming a molar mass of 136.36 g/mol, would be \(C_8H_{28\).
It's important to note that the value of the molar mass can affect the final molecular formula. If you have the actual molar mass of the compound, you can substitute it into the calculations to find the appropriate whole number multiplier and obtain the accurate molecular formula.
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Spring ends on what day?
summer solstice
winter solstice
vernal equinox
autumnal equinox
Answers
Answer:
June 20
Explanation:
14. The atoms of element X contains nineteen electrons. With which of the following elements will the chemistry of Z be similar? a Aluminum b) Bromine c) Lithium d) Magnesium
Answers
First of all, Z is unknown. I hope it is a mistake.
Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.
As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.
Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.
( No internal links available for reference. For clarification, check the periodic table).
If you have 3 moles of a gas at a pressure of 2.5 atm and a volume of 8 liters, what is the temperature?
a. 57.86 K
b. 0.81 K
c. 25 K
d. 81.26 K
Answers
Answer:
d
Explanation:
pv=nrt
2.5×1.01×10^5×8×10^-3=3×8.31×T
T=
The value of the temperature can be determined by ideal gas law and the temperature will be 0.81 K.
What is temperature ?The average kinetic energy of particular atoms and molecules in a system is measured by the temperature.
What is ideal gas Law?
Ideal gas law explain the relationship between pressure. temperature and volume.
Ideal gas law can be expressed as, PV=nRT.
where, P is pressure. V is volume , n is number of moles ,R is gas constant and T is temperature. It is given that, n= 3 mole, P = 2.5 atm, V = 8 L, T=?, R = 8.31.
Calculation of temperature by using ideal gas law is shown as:
Now, put the values of given data in ideal gas law equation.
T = PV/nR
=2.5×8/3×8.32
= 0.81 K
Therefore, the temperature will be 0.81K.
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What factors determine the amount of energy stored in a gummy bear, and how do they affect the amount of energy stored?
Some ideas to get you started: Type of bond, number of bonds, etc
Answers
Answer:i don’t know
Explanation:i don’t know
help please asap. chem sucks
Answers
I'm assuming that C is carbon.
\(4.590 \: mol \: c \times \frac{12.01 \:g \: c}{1 \: mol \: c} \)
55.1259 g of C
You were given a 100. G wine sample to verify its age. Using tritium dating you observe that the sample has 0. 688 decay events per minute. Tritium has a half life of 12. 3 and fresh water exhibits 5. 5 decay events per minute per 100g. What year was the wine produced?.
Answers
Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.
Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.
The time can be represented as follows:
t= 2.303\∧ log A0/A
∧= 0.693/t 1/2
The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.
The given parameters are as follows:
t1/2=12.3
A0=5.5
A=0.688
t= 2.303/(0.693/12.3) log (5.5/0.688)
t=36.9
t=37 years
Thus, wine was produced 37 years ago (1984 as usual year 15,2021)
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What happens during meiosis that does NOT happen during mitosis?
A new cells are formed
B two rounds of cell division
C DNA is passed on to the daughter cells
D parent cells grow in size before division
please help
Answers
Given the empirical formula of your compound is CH₂, what is the gram formula mass of the empirical formula?
Answers
Answer:
14g
Explanation:
The empirical formula of the compound is CH₂ ;
When we are dealing with compounds the gram formula mass or gram - molecular weight is the molar mass of the compound.
It is determined by adding the atomic masses of the components together and then expressed in grams.
Atomic mass of C = 12
Atomic mass of H = 1
Gram formula mass = 12 + 2(1) = 14g
a line-angle formula shows a ring with six vertices and alternating single and double bonds. a cooh group is attached to the first vertex. a br atom is attached to the third (clockwise) vertex. spell out the full name of the compound.
Answers
The compound is named 2,3-dibromo-2,4-hexadienedioic acid, which consists of a six-membered ring with alternating single and double bonds.
The line-angle formula describes a six-membered ring with alternating single and double bonds. To name the compound, we need to consider the functional groups and substituents present.
The carboxylic acid group, -COOH, is attached to the first vertex of the ring. This group is named as "hexanedioic acid" because it contains six carbon atoms in a linear chain. The prefix "hexa-" indicates the presence of six carbons, and the suffix "-dioic acid" denotes the presence of two carboxylic acid groups.
The bromine atom, represented by "Br," is attached to the third vertex in a clockwise direction. Since there are two bromine atoms present, the prefix "di-" is used. Thus, the compound is named "dibromo-hexanedioic acid."
To specify the positions of the bromine atoms, we start numbering the ring from the vertex where the carboxylic acid group is attached, which is the first vertex. Moving clockwise, the second vertex has a double bond, the third vertex has a bromine atom, and the fourth vertex has a double bond. Therefore, the compound is named as "2,3-dibromo-2,4-hexadienedioic acid." The numbers indicate the positions of the substituents in the ring.
In summary, the compound is named 2,3-dibromo-2,4-hexadienedioic acid, which represents a six-membered ring with alternating single and double bonds, a carboxylic acid group attached to the first vertex, and a bromine atom attached to the third vertex in a clockwise direction.
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Identify the following for an atom with 22 protons, 22 electrons, and a mass number of
48 amu.
a. Atomic number:
b. Number of neutrons:
c. Nuclear Notation:
d. Hyphen Notation:
please help
Answers
a. The atomic number is the number of protons in an atom. In this case, the atom has 22 protons, so the atomic number is 22.
b. The number of neutrons can be calculated by subtracting the atomic number (number of protons) from the mass number. In this case, the mass number is given as 48, and the atomic number is 22. Therefore, the number of neutrons is 48 - 22 = 26.
c. Nuclear notation represents the composition of an atom in a compact form. For the given atom with 22 protons and 26 neutrons, the nuclear notation is written as follows:
^48Ti (where the superscript represents the mass number and the subscript represents the atomic number)
d. Hyphen notation is another way to represent the composition of an atom. It includes the element symbol, followed by the mass number, separated by a hyphen. For the given atom, the hyphen notation is:
Titanium-48
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How do you calculate the percent composition of an element in a compound
Answers
Answer:
Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.
Explanation:
Who is my favourite wrestler?
Answers
Answer:
ma herdina thesto wrestling