The pH of a 0.10 M solution of carbonic acid is 3.12.
To calculate the pH of a solution, we use the equation pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. In the case of carbonic acid, the dissociation equation is:
H2CO3 → H+ + HCO3-
The concentration of hydrogen ions in the solution is equal to the concentration of carbonic acid, which is 0.10 M. Plugging this value into the equation for pH, we get:
pH = -log[0.10]
pH = 3.12
Therefore, the pH of a 0.10 M solution of carbonic acid is 3.12.
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What is the second quantum number of a 1s^2 electron in phosphorus,
1s22s22p63523p3?
O A. ) = 3
B. /= 0
O C. 1 = 1
D. /= 2
The second quantum number of a 1s²electron in phosphorus,1s²2s²2p⁶3s²3p³ is zero as principal quantum number is 1 so (n-1) is 0.
What are quantum numbers?Quantum numbers are the numbers which describe the values of conserved quantities with respect to the dynamics of a quantum system.They correspond to the Eigen values of operators which commute with the Hamiltonian quantities.
The Hamiltonian quantities can be known with precision simultaneously with the system's energy.Quantum numbers can take values of discrete sets of integers or even half-integers even though they can approach infinity in some cases.
They can specifically describe energy levels of electrons, and can also explain angular momentum,spin,etc.These are used to describe the path of an electron in an atom ,when the quantum numbers of all atoms are combined they must comply with the Schrodinger equation.
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Type the correct answer in each box.
Balance the equation.
SiO2 +
CaC2 →
Si +
CaO +
CO2
Answer:
5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2
Explanation:
balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.
chloride per milliliter (MW of CaCl2 = 147) [Round to the nearest whole number 5. What weight of magnesium chloride (MgCl2, formula weight = 95.3) is required to prepare 200 ml solution that is 5.0 mi
The weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.
To calculate the weight of magnesium chloride (\(MgCl_{2}\)) required to prepare a 200 ml solution that is 5.0 M, we need to use the formula: Weight (in grams) = Volume (in liters) × Concentration (in moles/liter) × Molecular Weight (in grams/mole)
First, we convert the volume from milliliters to liters by dividing it by 1000: Volume = 200 ml ÷ 1000 = 0.2 L. Next, we multiply the volume, concentration, and molecular weight: Weight = 0.2 L × 5.0 mol/L × 95.3 g/mol = 47.65 grams
Rounding to the nearest whole number, the weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.
This calculation ensures that the desired concentration is achieved by accurately measuring the appropriate amount of magnesium chloride, taking into account its molecular weight and the desired volume of the solution.
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how can the absorbance of the solution containing fescn2 be used to calculate the [fescn2 ] at equilibrium?
The absorbance of the solution containing FeSCN2 can be used to calculate the [FeSCN2] at equilibrium by using the following equation:
A = ε * b * [FeSCN2]
Where A is the absorbance of the solution, ε is the molar absorptivity of FeSCN2, b is the path length of the cuvette, and [FeSCN2] is the molar concentration of FeSCN2.
What is the purpose of iron III thiocyanate?
The ferric thiocyanate assay, which involves oxidizing ferrous to ferric ions and then complexing the latter with thiocyanate, is used to detect the presence of different oxidizers like lipid hydroperoxides and assess the effects of antioxidants.Thiocyanates have a variety of uses in the construction industry, agriculture, metal and steel industry, textile and fiber industry, and so forth.To learn more about fescn2, follow the link https://brainly.com/question/17095228
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What could happen if a person conducts an investigation but doesn't follow the steps of
the scientific method?
The action of investigating something or someone; formal or systematic examination or research.
There are five main steps involved in the scientific method: stating the problem, forming the hypothesis, collecting the data by observing and experimenting, interpreting these data, and drawing conclusions.Define a Question to Investigate. As scientists conduct their research, they make observations and collect data. ...Make Predictions. Based on their research and observations, scientists will often come up with a hypothesis. ...Gather Data. ...Analyze the Data. ...Draw Conclusions.Scientific investigation is a quest to find the answer to a question using the scientific method. In turn, the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis. Finally, a hypothesis is a proposed explanation for some observed phenomenon, based on experience or research.Scientific investigation is what people like you and me use to develop better models and explanations for the world around them.
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Which statement explains how the Sun influences movement in the Earth's atmosphere?
The Sun heats the Earth evenly; this heating pattern then causes conduction in the atmosphere.
The Sun heats the Earth unevenly; this heating pattern then causes conduction in the atmosphere.
The Sun heats the Earth evenly; this heating pattern then causes convection currents in the atmosphere.
The Sun heats the Earth unevenly; this heating pattern then causes convection currents in the atmosphere.
Give the following acid/base reaction:
HI(aq) + NH3(aq) ↔ NH4+(aq) + I-(aq)
Determine which substance is the acid, base, conjugate acid, and conjugate base.
Column A Column B:
1. Acid 1: I-
2. Base 2: HI
3. Conjugate base 3: NH3
4. Conjugate acid 4: NH4+
Answer:
6=100
Explanation:
if 10 percent of the food energy not used by cows could be captured as chemical en-ergy from gas released by manure, what would be the energy efficiency of convert-ing corn into milk? (2 point
The energy efficiency of converting corn into milk, considering the capture of 10 percent of the unused food energy from cows' gas released by manure, would be higher than without capturing the gas.
When corn is converted into milk, there is an inherent loss of energy at various stages of the process. However, if we consider capturing 10 percent of the food energy that is not utilized by cows and converting it into chemical energy from the gas released by their manure, the overall energy efficiency would improve. This captured energy can be harnessed and used for other purposes, thereby reducing wastage.
By capturing the gas released by manure, we are essentially tapping into a potential energy source that would otherwise be lost. This additional energy can be utilized to generate electricity, produce biogas, or even power machinery within the dairy farm. By incorporating this energy capture system, the overall energy efficiency of converting corn into milk would increase, as a portion of the previously wasted energy is now being utilized effectively.
This approach not only helps in improving the energy efficiency of milk production but also contributes to sustainability efforts by reducing greenhouse gas emissions. The captured gas can be used as a renewable energy source, reducing the dependency on non-renewable energy options.
In conclusion, by capturing 10 percent of the unused food energy from cows as chemical energy from gas released by manure, the energy efficiency of converting corn into milk would be higher than in traditional processes. This method allows for the effective utilization of otherwise wasted energy, leading to a more sustainable and efficient milk production process.
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The payload of a rocket includes fuel and oxygen for combustion of the fuel. Reactions 1 and 2 describe the combustion of dimethylhydrazine and hydrogen, respectively.
Calculate the energy change for the below reaction in kJ per pound.
(CH3)2NNH2(l)+4H2O(g)=N2(g)+4H2O(g)+2CO2(g)
ΔHrxn = -1694 KJ
Calculate the energy change for the below reaction in kJ per pound.
H2(g)+1/2O2(g) = H2O(g)
ΔHrxn=−286kJ
-12833.33 kJ/lb is the energy change for the first reaction in kJ per pound. -65000 kJ/1b is the energy change for the second reaction in kJ per pound.
Energy change in chemistry refers to the variation in a system's overall energy between two states or circumstances. It is a crucial idea in comprehending how matter behaves and how chemicals react.
Dimethyl hydrazine gives 1694 kJ of energy per mole of compound
molar mass = 60.01g/mol
mass of Dimethyl hydrazine, m = 1 mol x60.01g/mol
= 60.01gx{1lb/453.59 g}
= 0.1321b
calculate the energy change for 1st reaction in kJ/lb as follows:
=ΔΗrxn/m
=-1694 kJ/0.132lb
=-12833.33 kJ/lb
molar mass of \(\rm H_2\) = 2 gm/mol
mass of \(\rm H_2\) = 1molx 2 gm/mol
= {2 gm x 1lb/453.59 g}
= 0.00441b
calculate the energy change for 2nd reaction in kJ/lb as follows:
=ΔΗ/m
=-286 kJ/0.0044lb
=-65000 kJ/1b
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The difference in the amounts of chemical energy that are stored in the products and reactants accounts for the energy change in a chemical reaction. The energy change for the first reaction is -12833.33 kJ/lb and that of the second is -65000 kJ/lb.
Usually, energy shifts are connected with phase transitions. For instance, carbon dioxide molecules take in energy when solid dry ice vaporizes (physical change). Energy is released when liquid water freezes.
Dimethyl hydrazine gives 1694 kJ of energy per mole of compound
Molar mass = 60.01g/mol
Mass of Dimethyl hydrazine, m = 1 mol x60.01g/mol
m = 60.01gx[1lb/453.59 g]
m = 0.132lb
The energy change for 1st reaction in kJ/lb as follows:
Energy change = ΔΗrxn/m
E = -1694 kJ/0.132lb
E = -12833.33 kJ/lb
Molar mass of H₂ = 2 gm/mol
Mass of H₂ = 1molx 2 gm/mol
m = [2 gm x 1lb/453.59 g]
m = 0.0044lb
The energy change for 2nd reaction in kJ/lb as follows:
Energy change = ΔΗ/m
E = -286 kJ/0.0044lb
E = -65000 kJ/lb
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Answer rating0.0
(0 votes)
what is the density of an 85.7 g sample of unknown susbstance if the sample occupies 32.4mL
Answer:
m= 85.7g
V= 32.4mL
d= m/V
d= 2.65g/mL
How do I find the pH of two different solutions if they have the same number of moles?
Answer:
You can use a PH tester do identify the PH of each solution. Depending on what solutions ur testing, u shouldn't mix them as for there could be either a minor or bad chemical reaction
Explanation:
what is the mass of 0.0714 moles of H3PO4
The material in which a wave travels is called a ____
Answer:
medium
Explanation:
what volume of carbon dioxide will be collected at stp when 25.6 g of calcium carbohydrate undergoes decomposition? Balanced reaction: CaCO2 -> CaO + CO2
Answer:
V = 5.74 L
Explanation:
Given data:
Volume of carbon dioxide produced = ?
Temperature and pressure = standard
Mass of calcium carbonate = 25.6 g
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of calcium carbonate:
Number of moles = mass / molar mass
Molar mass of calcium carbonate = 100 g/mol
Number of moles = 25.6 g/ 100 g/mol
Number of moles = 0.256 mol
Now we will compare the mole of calcium carbonate with carbon dioxide.
CaCO₃ : CO₂
1 : 1
0.256 : 0.256
Volume of CO₂:
PV = nRT
R = general gas constant = 0.0821 atm/L / mol.K
By putting values,
1 atm× V = 0.256 mol × 0.0821 atm/L / mol.K× 273.15 K
V = 5.74 atm/L / 1 atm
V = 5.74 L
0.795 mol sample of carbon dioxide gas at a temperature of 19.0 °C is found to occupy a volume of 27.5 liters. The pressure of this gas sample is __ mm Hg.
A sample of helium gas collected at a pressure of 315 mm Hg and a temperature of 303 K has a mass of 2.45 grams. The volume of the sample is __ L.
A 17.4 gram sample of argon gas has a volume of 843 milliliters at a pressure of 3.93 atm. The temperature of the Ar gas sample is __°C.
1. The pressure of the carbon dioxide gas sample is approximately 46.9 mm Hg.
2. The temperature of the argon gas sample is approximately 299 °C.
3. The volume of the helium gas sample is approximately 0.0686 L.
1. To find the pressure of the gas sample, we can use the ideal gas law equation:
PV = nRT
Given that the temperature is 19.0 °C (which needs to be converted to Kelvin by adding 273.15) and the volume is 27.5 liters, we have:
P * 27.5 = 0.795 * R * (19.0 + 273.15)
Simplifying the equation, we can solve for P:
P = (0.795 * R * (19.0 + 273.15)) / 27.5
Using the ideal gas constant value of R = 0.0821 L·atm/(mol·K), we can substitute it into the equation to calculate the pressure P. The result will be in atmospheres (atm), so we need to convert it to millimeters of mercury (mm Hg) by multiplying it by 760.
2. We can use the ideal gas law equation to find the volume of the gas sample:
PV = nRT
Given that the pressure is 315 mm Hg (which needs to be converted to atmospheres by dividing by 760), the temperature is 303 K, and the mass is 2.45 grams (which needs to be converted to moles by dividing by the molar mass of helium), we have:
(315/760) * V = (2.45 / molar mass of helium) * 0.0821 * 303
Simplifying the equation, we can solve for V (volume):
V = ((2.45 / molar mass of helium) * 0.0821 * 303) / (315/760)
Substituting the given values and the molar mass of helium (4.00 g/mol), we can calculate the volume V in liters.
3. To find the temperature of the gas sample, we can use the ideal gas law equation:
PV = nRT
Given that the pressure is 3.93 atm, the volume is 843 milliliters (which needs to be converted to liters by dividing by 1000), and the mass is 17.4 grams (which needs to be converted to moles by dividing by the molar mass of argon), we have:
(3.93 * (843/1000)) = (17.4 / molar mass of argon) * R * T
Simplifying the equation, we can solve for T (temperature):
T = (3.93 * (843/1000)) / ((17.4 / molar mass of argon) * R)
Substituting the given values and the molar mass of argon (39.95 g/mol), we can calculate the temperature T in Kelvin. The result needs to be converted to Celsius by subtracting 273.15.
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Ammonium (NH4+), carbonate (CO32−), and phosphate (PO43−) are all examples of: (a) multivalent metals (b) polyatomic ions (c) covalent molecules (d) molecular compounds. Help pleasee
Answer:
Option b) polyatomic ions
Explanation:
Polyatomic ions are ions consisting of two or more atoms.
From the question given above, we can see that each ions consist of more than one atom as shown below:
Ions >>>>>> Number of atom present
NH4+ >>>>> 2
CO32− >>>> 2
PO43− >>>> 2
Thus, we can say that the above ions are polyatomic ions.
Answer:
It's C.
Explanation:
Nitrite reductase contains two histidine amino acids that coordinate a Cu2 ion. When the ion is present in the enzyme, the ion is a __________ and the enzyme is a __________.
When the Cu2 ion is present in nitrite reductase, the ion is a cofactor and the enzyme is an apoenzyme.
What are the states of the Cu2 ion and the enzyme?Nitrite reductase is an enzyme that reduces nitrite to nitric oxide in bacteria and plants. The enzyme contains two histidine amino acids that coordinate a Cu2+ ion, which is an important cofactor in the reaction. The Cu2+ ion is bound to the two histidine residues through its imidazole rings, forming a coordination complex.
When the Cu2+ ion is present in the enzyme, it is in a reduced form, which means that it has lost one electron and is positively charged. The ion is also in a low-spin state, which means that the electrons in its d-orbitals are paired.
The enzyme, on the other hand, is in an oxidized state when the Cu2+ ion is present. This is because the enzyme is responsible for catalyzing the reduction of nitrite, which involves the transfer of electrons from the nitrite molecule to the Cu2+ ion. Therefore, the enzyme is a reducing agent in this reaction.
In summary, when the Cu2+ ion is present in nitrite reductase, it is a reduced species and the enzyme is a reducing agent.
Therefore the complete line would be "When the Cu2 ion is present in nitrite reductase, the ion is a cofactor and the enzyme is an apoenzyme."
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1.How many protons are in the nucleus of an aluminum atom? 2.How many electrons does an aluminum atom have?
Answer:
There are 13 numbers in an aluminum atom and 13 electrons.
Explanation:
This is because the atomic number equals the number of protons and the atomic number of Al is 13. The number of electrons also equals the number of protons.
Answer:
13, 13
Explanation:
what is the dot-and-cross diagram for magnesium chloride (MgCl2)??
Answer: Lewis dot structures aren't drawn for ionic compounds, such as MgCl2. Because there aren't any shared electron pairs in an ionic compound. Lewis structure are only drawn for molecular compounds, atoms, or some individual ions. If we want to visualize a chloride ion (Cl -), it's Lewis structure will show Cl with complete octet.
Explanation: Hope this helps you
Determinación de pH Expresa las siguientes concentraciones de [H+ ] en función del pH • [H+] = 0.001 M • [H+] = 0.002 M • [H+] = 2.45X10-4 M • [H+] = 5.2X10-9 M • [H+] = 0.04 M
Answer:
• pH = 3.0
• pH = 2.70
• pH = 3.61
• pH = 8.28
• pH = 1.40
Explanation:
El pH es una medida en química usada para determinar el grado de acidez o basicidad en una solución.
Se define como:
pH = -log₁₀ [H⁺]
El - logaritmo de la concentración molar de H⁺
Para las concentraciones de H⁺ dadas:
• [H+] = 0.001 M
pH = -log (0.001M) = 3
pH = 3.0
• [H+] = 0.002 M
pH = -log (0.002M)
pH = 2.70
• [H+] = 2.45X10-4 M
pH = -log (2.45X10-4 M )
pH = 3.61
• [H+] = 5.2X10-9 M
pH = -log (5.2X10-9 M)
pH = 8.28
• [H+] = 0.04 M
pH = -log (0.04M)
pH = 1.40
an aqueous solution contains 0.25 m potassium nitrite. one liter of this solution could be converted into a buffer by the addition of:
One liter of this solution could be converted into a buffer by the addition of 0.25mol NH₄Cl, and 0.12 mol HCl.
A buffer is a substance that can withstand a pH change when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the pH of the solution largely constant. For procedures and/or reactions that call for particular and stable pH ranges, this is significant. The pH range and capacity of buffer solutions determine how much acid or base can be neutralized before pH changes and how much pH will vary.
A weak acid and its conjugate base, or vice versa, are combined in solution to form a buffer.
The conjugate base of ammonia (NH3), which is a weak base, is NH4+. Therefore, adding 0.25 mol of NH4Cl will change the solution into a buffer. Additionally, NH3 and HCl interact to form NH4+. Therefore, 0.12 mol of HCl added will result in NH4+. All of the NH3 is consumed by 0.25 mol HCl.
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The disappearing spoon chapter one summary
Chapter One of the book "The Disappearing Spoon" by Sam Kean is titled "Ruthenium, Rhodium, and Palladium." This chapter explores the fascinating history, properties, and uses of these three elements from the periodic table.
The chapter begins with the story of a chemical spill in the town of Norilsk, Russia, which is home to the world's largest nickel mine. The spill caused massive environmental damage and raised concerns about the toxic effects of metals.
This incident sets the stage for the exploration of elements that possess unique properties and have played significant roles in scientific and industrial advancements.
The author then introduces the readers to the periodic table and its significance in understanding the behavior and characteristics of elements. He explains the arrangement of elements and how they are grouped based on their chemical properties.
Moving on, Kean delves into the history and properties of ruthenium, rhodium, and palladium. He shares interesting anecdotes about their discoveries, including the challenges faced by scientists in isolating and identifying these elements. The author highlights the rarity and value of these metals and their importance in various fields, such as catalysis, electronics, and jewelry making.
Furthermore, Kean discusses the cultural and societal impact of these elements, including their use in the automotive industry, where palladium plays a crucial role in catalytic converters. He also explores the darker side of these elements, such as their involvement in illegal activities, including theft and smuggling.
Overall, Chapter One of "The Disappearing Spoon" provides an engaging introduction to the world of elements and sets the stage for further exploration of the periodic table and its fascinating stories.
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which pair of elements are inner transition metals
Inner transition metals are elements that are located in the f-block of the periodic table. They are sometimes also called "rare earth elements" due to their relative scarcity and difficulty in extraction. The f-block of the periodic table consists of two rows, one located at the bottom of the main periodic table and another row that is usually shown as a separate block beneath the main table.
One pair of inner transition metals are cerium (Ce) and europium (Eu). Cerium is a silvery-white metal that is soft and ductile. It is the most abundant of the rare earth elements and is widely used in various applications, such as catalytic converters, glass polishing, and metallurgy. Europium, on the other hand, is a shiny, silvery metal that is also soft and ductile. It is used in the production of fluorescent lamps, computer screens, and in the nuclear industry.
Another pair of inner transition metals are neodymium (Nd) and gadolinium (Gd). Neodymium is a soft, silvery metal that is used in the production of powerful magnets. It is also used in lasers, glasses, and as a catalyst in various chemical reactions. Gadolinium, on the other hand, is a silvery-white metal that is used as a contrast agent in magnetic resonance imaging (MRI) scans. It is also used in nuclear reactors, computer memory, and electronic components.
In summary, cerium and europium, as well as neodymium and gadolinium, are two pairs of inner transition metals that have unique properties and various applications in different fields.
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for the following reaction, calculate the keq at 25°c. succinyl-coa acetoacetate ⟶ acetoacetyl-coa succinate δg°' = -1.25 kj/mo
The value the keq at 25°C succinyl-coa acetoacetate ⟶ acetoacetyl-coa succinate δg°' = -1.25 kj/mo is 3.85.
The Gibbs free energy change (ΔG°') for the following reaction is -1.25 kJ/mol.
succinyl-CoA + acetoacetate ⇌ acetoacetyl-CoA + succinate
The formula for calculating the equilibrium constant (Keq) at a specific temperature (T) is,
ΔG°' = -RTlnKeq
where
R = 8.314 J/mol-K (gas constant)
T = temperature in K
ΔG°' = Gibbs free energy change at standard conditions (298 K)
Rearranging this equation to solve for Keq,
Keq = e^(-ΔG°'/RT)
Substitute the given values,+
ΔG°' = -1.25 kJ/mol = -1250 J/mol
R = 8.314 J/mol-KT = 25°C + 273.15 = 298.15
Keq = e^(-ΔG°'/RT)= e^(-(-1250)/(8.314 × 298.15))≈ 3.85
Therefore, the Keq for the given reaction at 25°C is approximately 3.85.
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Draw the product of the hydration of 2-butene.
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single
bond is active by default. Include all hydrogen atoms.
► View Available Hint(s)
DC H 120 EXP CONT
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(1)
A
Marvin JS
by ChemAxon
IU ZOS-a
Review | Constants | Periodic Table
F
E
The product of the hydration reaction of 2-butene is 2-butanol.The H+ from the water attach to one double bonded carbon and the OH group attaches to the second double bonded carbon atom as shown in the image.
What is hydration of alkenes?Alkenes are unsaturated hydrocarbons with one or more double bonds between carbon atoms. They are highly reactive due to the electron deficient center.
When alkenes are treated with water, according to rule of Markonikoves, H+ will attach at the most substituted double bonded carbon and OH with least substituted one.
Here in 2- butene it is a symmetric alkene hence both double bonded carbon are singly occupied by one hydrogen. Then , the major product is 2- butanol.
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explain a mixture of molecules
Answer:
A mixture of molecules is a group of molecules in which there are multiple different elements and atoms, that are in either fixed proportions or random. There are heterogeneous and homogenous mixtures.
Explanation:
what is the binding energy in kj/mol cl for chlorine-37? kj/mol 17 20 the required masses (g/mol) are:= 1.00783 ;= 1.00867 ;= 36.94740
The Binding Energy in Kj/mol Cl for chlorine-37 is 3.15 x 10^5 kj/mol. Cl-37 has 17 protons and 20 neutrons. To compute the binding energy, the mass of a single atom should first be calculated.
Using the masses given in the question (in g/mol):Mass of 17 protons (17 x 1.00783) = 17.16311 g/mol Mass of 20 neutrons (20 x 1.00867) = 20.1734 g/mol Mass of Cl-37 (36.94740) = 36.94740 g/mol Total mass = 74.28391 g/mol Using the c^2 factor, the mass of 1 atom can now be converted to energy:74.28391 g/mol x (1 mol/6.022 x 10^23 atoms) x (2.998 x 10^8 m/s)^2 = 6.305 x 10^-10 J/atom The energy per mole of atoms is computed as follows:6.305 x 10^-10 J/atom x (6.022 x 10^23 atoms/mol) = 3.796 x 10^14 J/mol Finally, this value must be converted to kilojoules per mole:3.796 x 10^14 J/mol x (1 kJ/1000 J) = 3.796 x 10^11 kJ/mol (rounded to 3 significant figures)The binding energy per mole of Cl-37 is 3.796 x 10^11 kJ/mol. The value must be divided by Avogadro's number to find the binding energy per atom:3.796 x 10^11 kJ/mol / 6.022 x 10^23 atoms/mol = 3.15 x 10^-13 kJ/atom (rounded to 3 significant figures) Therefore, the binding energy in Kj /mol Cl for chlorine-37 is 3.15 x 10^5 Kj /mol.
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Ethanolic fermentation is used in making beverages such as beer, wine, and pulque. It is carried out by yeast and ...
A) clostridium.
B) zymomonas.
C) leuconostoc.
D) lactobacillus.
E) propionibacterium.
The correct answer is B) zymomonas. Ethanolic fermentation, which is the process of converting sugars into ethanol (alcohol) and carbon dioxide by yeast, is commonly used in the production of beverages like beer, wine, and pulque.
While there are various microorganisms that can carry out fermentation, yeast is the primary organism involved in ethanolic fermentation.
Zymomonas is a type of bacteria that is known for its ability to perform ethanolic fermentation. It can efficiently convert sugars into ethanol and carbon dioxide, making it suitable for industrial applications such as the production of alcoholic beverages.
Clostridium, Leuconostoc, Lactobacillus, and Propionibacterium are other types of microorganisms, but they are not primarily involved in ethanolic fermentation. They may have different metabolic pathways or be associated with other fermentation processes, but they are not the main organisms responsible for the production of ethanol in the context of beverage production.
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If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?
0.0337 g
17.3 g
0.239 g
0.300 g
Answer:
17.3 g
Explanation:
Given the following data;
Quantity of heat, Q = 0.507 JTemperature = 0.007°CSpecific heat capacity of water = 4.2 J/g°CMathematically, Heat capacity is given by the formula;
\( Q = MCT \)
Where;
Q represents the heat capacity or quantity of heat.M represents the mass of an object.C represents the specific heat capacity of water.T represents the temperature.Making "M" the subject of formula, we have;
\( M = \frac {Q}{CT} \)
Substituting the values into the formula, we have;
\( M = \frac {0.507}{4.2*0.007} \)
\( M = \frac {0.507}{0.0294} \)
Mass, m = 17.3 grams
Any observations collected from Parts A and B were obtained by testing solutions with a single cation present. Would the presence of two cations in one solution (like that of the unknown) affect the cation identification in Part C?
A. No, at room temperature the blue pigment cation will react with the reagent for a particular test allowing you to identify the first cation. When you heat the solution up, the white pigment cation reacts with that reagent and can be identified.
B. Yes, the two cations in the unknown can react with the reagent added for a particular test. The observation of the reaction for one cation can mask the other cation in solution making it difficult to identify either cation.
C. Yes, the cations can react with each other to form a precipitate. Therefore, the cations are no longer available to react with the reagent added for a particular test making it impossible to identify the cations.
D. No, it does not matter how many cations are in solution. After centrifugation, the less dense white pigment cation will be at the top and the more dense blue pigment cation will be at the bottom. This makes cation identification very straight forward.
The presence of two cations in the unknown solution can affect cation identification in Part C. This is because the cations can react with each other to form a precipitate, which will make it impossible to identify either cation.
The cations can also react with the reagent added for a particular test and the observation of the reaction for one cation can mask the other cation in solution, making it difficult to identify either cation.
In addition, the two cations can have different densities, which can make cation identification difficult. Thus, the presence of two cations in a solution can affect cation identification. It is important to take this into account when performing the cation identification experiment.
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