What is the result of taking the difference between sample means, minus the null hypothesized difference, divided by the standard error of the difference between means?

Answer:

No they are not equivalent,

Step-by-step explanation:

3 x 6 is 18 and 5 x 6 is 30,  not 32 so it is non-equivalent

Answer:

5^x - 5^-x

Step-by-step explanation:

g(x) = 5^-x

h(x) = 5^x

We want h(x) - g(x)

h(x) - g(x) = 5^x - 5^-x

This cannot be simplified

Answer:

A Japan and B £38

Step-by-step explanation:

Spain £1=€1.41

more €352.50

€352.50÷1.41 ×1 = £250

Japan £1= ¥188

more ¥39856

¥39856÷188×1 =£212

A) Japan is cheaper

B) £250-£212=£38

The values a and b should be replaced to rewrite the given expression as (x + a)(x - b).

Generally speaking, the standard form of a quadratic function is given by this mathematical expression;

ax² + bx + c = 0

Where:

a and b represents the coefficients of the first and second term in the quadratic function.

c represents the constant.

Next, we would solve the above quadratic function by using the factorization method;

x² + x - 72 = 0

x² - 8x + 9x - 72 = 0

x(x - 8) + 9(x - 8) = 0

(x + 9)(x - 8) = 0

(x + 9)(x - 8) = (x + a)(x - b).

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Answer:

3y⁵√2

Step-by-step explanation:

Let

y -----> candle heigh in centimeters

x ----> burning time in hours

In this problem we have the ordered pairs

(5,22.5) and (17,16.5)

step 1

Find out the slope

m=(16.5-22.5)/(17-5)

m=-6/12

m=-1/2 -----> is negative because is a decreasing function

step 2

Find out the equation in slope-intercept form

y=mx+b

we have

m=-1/2

point (5,22.5)

substitute

22.5=-(1/2)(5)+b

solve for b

b=22.5+2.5

b=25

therefore

y=-(1/2)x+25

step 3

For x=7 hours

substitute in the equation

y=-(1/2)(7)+25

y=-3.5+25

The number of years that the glory days of the cowboy period lasted was about 2 decades.

The glory days of the cowboy times is typically deemed as the span between the conclusion of the Civil War in 1865 to around the dawn of the1900s. During these years, cowboys played an indispensable role in boosting and improving the American West peculiarly in the cattle industry.

With bravery and courage, they would drive a herd of cattle across wide expanses frequently grappling with harsh conditions and situations of peril. The genesis of industrialization phased out the cowboy era with train networks expediting the transportation of both bovine species and freight with efficiency.

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The total sum of squares (SST) was 10,800, and the treatment sum of squares (SSTR) was 4,560.

In the given scenario, an analysis of variance (ANOVA) procedure was conducted to analyze the number of units assembled correctly using three different methods. The following results were obtained:

Total sum of squares (SST) = 10,800

Treatment sum of squares (SSTR) = 4,560

The sum of squares (SST) represents the total variation in the data, while the treatment sum of squares (SSTR) represents the variation between the different treatment groups (methods).

To interpret these results, we can calculate the remaining sum of squares, which represents the variation within the treatment groups (individual differences):

SSW = SST - SSTR

SSW = 10,800 - 4,560

SSW = 6,240

Now, we can use these sum of squares values to calculate the mean squares:

Mean square treatment (MSTR) = SSTR / degrees of freedom (dfT)

Mean square error (MSE) = SSW / degrees of freedom (dfE)

Degrees of freedom:

dfT = Number of treatment groups - 1 = 3 - 1 = 2

dfE = Number of observations - Number of treatment groups = 30 - 3 = 27

Calculating mean squares:

MSTR = SSTR / dfT

MSTR = 4,560 / 2

MSTR = 2,280

MSE = SSW / dfE

MSE = 6,240 / 27

MSE ≈ 231.11

Finally, we can calculate the F-statistic:

F = MSTR / MSE

F = 2,280 / 231.11

F ≈ 9.87

The obtained F-statistic value can be compared to the critical F-value at a given significance level to determine if there are significant differences between the means of the treatment groups.

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The vectors u, v, and w are linearly independent if and only if k ≠ -8.

To understand why, let's consider the determinant of the matrix formed by these vectors:

| -4   -3    -4   |

| -3   -3    -11+k |

| 5    -11+k  7    |

If the determinant is nonzero, then the vectors are linearly independent. Simplifying the determinant, we get:

(-4)[(-3)(7) - (-11+k)(-11+k)] - (-3)[(-3)(7) - 5(-11+k)] + (-4)[(-3)(-11+k) - 5(-3)]

= (-4)(21 - (121 - 22k + k^2)) - (-3)(21 + 55 - 55k + 5k) + (-4)(33 - 15k)

= -4k^2 + 80k - 484

To find the values of k for which the determinant is nonzero, we set it equal to zero and solve the quadratic equation:

-4k^2 + 80k - 484 = 0

Simplifying further, we get:

k^2 - 20k + 121 = 0

Factoring this equation, we have:

(k - 11)^2 = 0

Therefore, k = 11 is the only value for which the determinant becomes zero, indicating linear dependence. For any other value of k, the determinant is nonzero, meaning the vectors u, v, and w are linearly independent. Hence, k ≠ 11.

In conclusion, the vectors u, v, and w are linearly independent if and only if k ≠ 11.

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Answer:

i think the answer is 45 degrees

Step-by-step explanation:

Answer:

La probabilidad que hay de que sea fin de semana es \(\frac{2}{7}\)

Step-by-step explanation:

La Probabilidad es la mayor o menor posibilidad de que ocurra un determinado suceso. En otras palabras, la probabilidad establece una relación entre el número de sucesos favorables y el número total de sucesos posibles. Entonces, la probabilidad de un suceso cualquiera A se define como el cociente entre el número de casos favorables (número de casos en los que puede ocurrir o no el suceso A) y el número total de casos posibles. Esta se denomina Ley de Laplace.

\(P(A)=\frac{numero de casos favorables}{numero de casos posibles}\)

En este caso:

Reemplazando:

P(A)= \(\frac{2}{7}\)

La probabilidad que hay de que sea fin de semana es \(\frac{2}{7}\)

For the given problem, the integral of \(\frac{1}{\sqrt{a^2-x^2}}\)  is  \($\sin^{-1}\frac{x}{a} + C$.\)

A mathematical notion that depicts the area under a curve or the accumulation of a quantity over an interval is known as an integral. Integrals are used in calculus to calculate the total amount of a quantity given its rate of change.

The process of locating an integral is known as integration. Finding an antiderivative (also known as an indefinite integral) of a function, which is a function whose derivative is the original function, is what integration is all about. The antiderivative of a function is not unique since it might differ by an integration constant.

For given problem,

\($\int \frac{1}{\sqrt{a^2-x^2}} dx$\)

Let \($x = a \sin\theta$\) , then \($dx = a \cos\theta d\theta$\)

\($= \int \frac{1}{\sqrt{a^2-a^2\sin^2\theta}} a\cos\theta d\theta$\)

\($= \int \frac{1}{\sqrt{a^2\cos^2\theta}} a\cos\theta d\theta$\)

\($= \int d\theta$\)

\($= \theta + C$\)

Substituting back for\($x = a\sin\theta$:\)

\($= \sin^{-1}\frac{x}{a} + C$\)

Therefore, the integral of \(\frac{1}{\sqrt{a^2-x^2}}\) is \($\sin^{-1}\frac{x}{a} + C$.\)

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Answer:

Point Form:

(2,−8)

Equation Form:

x=2 , y=−8

Step-by-step explanation:

Answer:

x=2

y=-8

Step-by-step explanation:

you could calculate it by rearranging and manipulating the equations, but this time I graphed it with desmos as two lines with an intersection

The distance between the sailboat and the dock is approximately 21.006 km

To find the distance between the sailboat and the dock, we can use trigonometry.

Given:

Distance between the lighthouse and dock (north-south direction) = 30 km

Viewing angle between the lighthouse and dock = 35 degrees

We can consider the right triangle formed by the sailboat, the lighthouse, and the dock.

The distance between the sailboat and the dock is the adjacent side of the triangle, while the distance between the lighthouse and the dock is the opposite side.

Using the trigonometric function tangent (tan), we have:

tan(angle) = opposite / adjacent

tan(35 degrees) = opposite / 30 km

Solving for the opposite side (distance between sailboat and dock):

opposite = tan(35 degrees) * 30 km

opposite ≈ 0.7002 * 30 km

opposite ≈ 21.006 km

Therefore, the sailboat is approximately 21.006 km away from the dock.

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Answer:

104.5 is what I got, tell me if that's wrong.

Answer:

104 1/2

Step-by-step explanation:

The answer is 104 1/2 since the formula for volume is LWH. You have to do 6 1/3*3*5 1/2.

6 1/3=19/3

5 1/2=11/2

19/3*3/1=57/3.

57/3*11/2=627/6.

627/6=104.5 or 104 1/2.

Answer:

Step-by-step explanation:

a is the base

b is the power

c is the root

a = 7

b = 9

c = 4

To find the orthogonal projection of a vector onto a subspace, we can use the formula:

projᵥ(u) = A(AᵀA)⁻¹Aᵀᵤ,

where A is a matrix whose columns span the subspace, and u is the vector we want to project.

In this case, the subspace W is spanned by the vector v = [0, 0, 0, 1].

Let's calculate the orthogonal projection of u onto W using the formula:

A = [v]

The transpose of A is:

Aᵀ = [vᵀ].

Now, let's substitute the values into the formula:

projᵥ(u) = A(AᵀA)⁻¹Aᵀᵤ

= v⁻¹[vᵀ]u

= [v][(vᵀv)⁻¹vᵀ]u

Substituting the values of v and u:

v = [0, 0, 0, 1]

u = [1, 0, 0, 0]

vᵀv = [0, 0, 0, 1][0, 0, 0, 1] = 1

[(vᵀv)⁻¹vᵀ]u = (1⁻¹)[0, 0, 0, 1][1, 0, 0, 0] = [0, 0, 0, 1][1, 0, 0, 0] = [0, 0, 0, 0]

Therefore, the orthogonal projection of u onto the subspace W is [0, 0, 0, 0].

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Answer: Choice C

y = 4x

Direct variation

=====================================================

Explanation:

We add 4x to both sides to isolate y. That leads to y = 4x

This is a direct variation equation because it's in the form y = kx, for some constant k.

Answer: D

Step-by-step explanation:

First, we see that each flower basket is the variable x. This is because that is what increases per situation. The constant fee no matter the amount of flower baskets for store A is $15, so for store A our equation is

Total spent=19.25x+15

And similarly, for store B it is

Total spent=17.50x+30

Now, to compare them we want to keep store A LESS THAN (<) store B ,

so we get that 19.25x+15<17.50+30, which is D

The optimal solution is x1 = 2, and the maximum value of the objective function is 3.

To apply the simplex method to the given maximization problem, we first need to convert the problem into standard form by introducing slack variables.

The given problem is:

Maximize: 3x1

Subject to:

-2x1 + x2 + x3 + s1 = 1

2x1 - 3x2 + x4 = 4

x1, x2, x3, x4, s1 ≥ 0

We introduce slack variables s2 and s3 to convert the inequalities into equations:

Maximize: 3x1

Subject to:

-2x1 + x2 + x3 + s1 = 1

2x1 - 3x2 + x4 + s2 = 4

x1, x2, x3, x4, s1, s2 ≥ 0

We create the initial tableau based on the augmented matrix of the system:

   | -2  1  1  0  1  0 |

   |  2 -3  0  1  0  4 |

T = |  3  0  0  0  0  0 |

   |________________|

Next, we need to find the pivot column. We select the column with the most negative coefficient in the objective row, which is column 2.

Dividing the right-hand column by the pivot column, we find that the minimum ratio occurs in row 2 (s2).

We perform the pivot operation by selecting the element in row 2, column 2 as the pivot (which is -3).

The new tableau after the pivot operation is:

   |  0.67  0.33  1  0 -0.33  1.33 |

   |  0.67 -1.00  0  0  0.33  1.33 |

T = |  3.00  0.00  0  0  0.00  0.00 |

   |_____________________________|

The pivot column for the next iteration is column 1 since it has the most negative coefficient in the objective row.

Dividing the right-hand column by the pivot column, we find that the minimum ratio occurs in row 1 (x1).

We perform the pivot operation by selecting the element in row 1, column 1 as the pivot (which is 0.67).

The new tableau after the pivot operation is:

   |  1  0.5   1.5  0 -0.5   2 |

   |  0 -1.5 -0.5  0  0.5   1 |

T = |  0  1.5  -1.5  0  1.5  -3 |

   |________________________|

Since all coefficients in the objective row are non-negative, the current solution is optimal. The maximum value of the objective function is 3, and the optimal values for the variables are:

x1 = 2

x2 = 0

x3 = 0

x4 = 0

s1 = 0

s2 = 1

Therefore, the optimal solution is x1 = 2, and the maximum value of the objective function is 3.

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Answer:

i have no idea what the answer is

Step-by-step explanation:

Marvin should place his ladder approximately 6.58 feet away from the base of the house.

To determine the height of the ladder Marvin needs to safely paint the peak of his house, we can use trigonometry.

Given that the ladder forms a 76-degree angle with the ground, we can use the sine function to calculate the height. The formula for this is:

Height of the ladder = Height of the peak / sin(angle)

Plugging in the values:

Height of the ladder = 24 feet / sin(76 degrees)

Using a scientific calculator or an online trigonometry calculator,

we find that sin(76 degrees) is approximately 0.9781.

Height of the ladder = 24 feet / 0.9781 ≈ 24.56 feet

So, Marvin would need a ladder that is approximately 24.56 feet tall to safely paint the peak of his house.

To determine how far from the base of the house Marvin should place his ladder, we can use the cosine function. The formula is:

Distance from the base = Height of the ladder / tan(angle)

Plugging in the values:

Distance from the base = 24.56 feet / tan(76 degrees)

Using the tangent function, tan(76 degrees) is approximately 3.7321.

Distance from the base = 24.56 feet / 3.7321 ≈ 6.58 feet

So, it is concluded that ladder should be placed approximately 6.58 feet away from the base of the house.

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To properly paint the peak of his house, Marvin requires a ladder that is at least 24 feet tall, and he should position the ladder 6.518 feet away from the foundation of the house.

Trigonometry can be used. OSHA regulations state that the ladder's angle with the ground should be 76 degrees.

Assume that the ladder's base is 'x' feet from the house's foundation. This creates a right triangle, with the ladder serving as the hypotenuse, the distance between the ladder's base and the house serving as the adjacent side, and the height of the ladder required to reach the peak serving as the opposite side.

The ratio of the lengths of the adjacent side to the opposite side determines the angle's tangent in a right triangle. In this situation, we may determine the height of the ladder using the tangent of 76 degrees:

tan(76°) = height of ladder / x

Rearranging the equation to solve for the height of the ladder:

height of ladder = x * tan(76°)

Given that the peak of the house is 24 feet high, the height of the ladder should be at least 24 feet. So we have:

24 = x * tan(76°)

Now we can solve for 'x':

x = 24 / tan(76°)

Using a scientific calculator, we find:

x ≈ 6.518 feet

Therefore, To properly paint the peak of his house, Marvin requires a ladder that is at least 24 feet tall, and he should position the ladder 6.518 feet away from the foundation of the house.

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Based on the given data, the process is out of control.

To determine if the process is still in control, we need to compare the new sample measurements to the control limits established in the X-bar and R control charts.

For the X-bar chart:

The UCL (Upper Control Limit) is calculated as the grand average (X-Double Bar) plus A2 times R-Bar:

UCL = 25 + (0.483 * 5) = 27.415

The LCL (Lower Control Limit) is calculated as the grand average (X-Double Bar) minus A2 times R-Bar:

LCL = 25 - (0.483 * 5) = 22.585

For the R chart:

The UCL (Upper Control Limit) for the R chart is calculated as D4 times R-Bar:

UCL = 2.004 * 5 = 10.020

The LCL (Lower Control Limit) for the R chart is 0.

Given the new sample measurements: 33, 37, 25, 35, 34, and 32, we can determine if any of the measurements fall outside the control limits. If any data point falls outside the control limits, it indicates that the process is out of control.

Upon comparing the new sample measurements to the control limits, we find that the measurement 37 exceeds the UCL of the X-bar chart. Therefore, the process is considered out of control.

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The length of the side AD is 24 inches

Consider the triangle ABC

The area of the triangle = 288 square inches

The length of the side CD = 9 inches

The length of the side DB = 15 inches

The length of the the base = The length of the side CD + The length of the side DB

Substitute the values in the equation

The length of the the base  = 9 + 15

= 24 inches

The area of the triangle = (1/2) × Base × Height

Substitute the values in the equation

288 = (1/2) × 24 × AD

288 = 12 × AD

AD = 288 / 12

AD = 24 inches

Hence, the length of the side AD is 24 inches

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Answer:

24,000

Step-by-step explanation:

I believe the answer is 24,000 because 10^4 is 10,000 and then you multiply 2.4 times 10,000 which is 24,000!! Your welcome

Answer:

rocks. rocks everywhere means no where for trees so no foods.

Step-by-step explanation:

The equation of the amount to be paid by anyone using the ride in slope intercept form is; y = 0.5x + 10

The general form of the equation of a Line in slope intercept form is;

y = mx + b

where;

m is slope

b is y-intercept

Now, we are told that;

Amount charge by Winter Wonderland per child = $0.50

We are told that there is a separate entrance fee.

Amount of times todd sled down the hill = 16 times

Amount paid by todd = $18

Thus, using the slope intercept form, we have;

18 = 0.5(16) + b

18 = 8 + b

b = 10

Thus, the equation of this amount to be paid in slope intercept form is;

y = 0.5x + 10

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Answer:

ab= 11 and bc = 8

Step-by-step explanation:

Answer:

AB = 11 units,   BC = 8 units,

Step-by-step explanation: