The wavelength, period and velocity are related by the equation:
\(v=\frac{\lambda}{T}\)where λ is the wavelength and T is the period. In this case the wavelength is 3.5 m and the period is 0.5 s; plugging these values we have:
\(\begin{gathered} v=\frac{3.5}{0.5} \\ v=7 \end{gathered}\)Therefore, the speed of the wave is 7 m/s
How far does a freely falling apple drop in 5.6 s after being released from rest?
\( \bf \underline{ \underline{Given : }}\)
Time taken by freely falling apple = 5.6 seconds Initial velocity,u = 0 m/s [ Rest ]Acceleration due to gravity,g = 9.8 m/s² [ Constant value ]\( \bf \underline{ \underline{To \: be \: calculated : }}\)
Calculate the height covered by a freely falling apple drop in 5.6 seconds.
\( \bf \underline{ \underline{Solution : }}\)
According to the Second equation for free falling body
\( \sf{h = ut + \frac{1}{2} gt {}^{2} }\)
\( \sf \red\star \: {Substituting \: the \: values}...\)
\( \sf\implies \:h = 0 \times 5.6 + \dfrac{1}{ \cancel{2}} \times \cancel{ 9.8} \times {(5.6)}^{2} \)
\( \sf\implies \: h = 0 + 4.9 \times 31.36\)
\( \sf\implies \: h = 153.66 \: m\)
\( \sf\therefore \: Height \: covered \: by \: an \: apple \: is \: 153.66 \: m.\)
The freely falling apple will drop 153.67 m in 5.6 secs when released from rest
For An apple at rest :
Initial velocity ( u ) = 0 m/s
free fall acceleration ( due to gravity ) (g) = 9.8 m/s²
Time travelled by apple ( t ) = 5.6 s
To determine the how far the apple will travel after been released
we will apply this formula
\(S = ut + 1/2 gt^2\)
S = 0 ( 5.6 ) + 1/2 * ( 9.8 ) * ( 5.6 )²
= 153.67 m
Hence we can conclude that the freely falling apple will drop 153.67 m when released from rest.
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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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A 0.32 kg toy mouse was on a couch that is 0.35m high. A car picks up the mouse and puts it in a nearby bookcase that is 2.85m high. How much work did the cat do?
A 0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.
What is the significance of the work done in the calculation?The work done by the car is calculated by ΔPE = mgh ,
(here the m=mass(0.32 kg)
g = acceleration(9.8 \(m/s^2\))
h= change in height (2.85 m - 0.35 m = 2.50 m)
ΔPE = 0.32 kg x 9.8 \(m/s^2\) x 2.50 m = 7.84 J
Hence, a 0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.
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you are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the mesosphere
PLS I RLLY NEED SOME HELP
The things would which would be needed to survive the mesosphere include the following below:
Food and waterOxygen supply.What is a Mesosphere?This is refereed to as the third layer of the atmosphere which is present above the stratosphere and directly below the thermosphere.
It has a low density of gas and water vapor present in the area which is why it is no place for human life as there is a shortage of oxygen and other gases needed for some biochemical reactions in the ecosystem. This is therefore the reason why things such as food, water and oxygen supply is neeeded tio survive in the mesosphere.
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The force that holds planets, stars, and other heavenly bodies in space is called _____.
inertia
universal force
gravity
cosmic force
Answer:
Gravity
Explanation:
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed speeding up or slowing down
a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.
What do you understand by force and friction?Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.
Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.
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Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”
Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.
According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.
As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.
As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.
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what is work? how do we solve for work?
Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
Answer:Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
what is the speed of light in air ?
\( \\ \)
ty! ~
Answer:
the speed of light in air is about 299,000,000 and 3×10⁸ m/s
Heat can be transferred by conduction when one object is in direct contact with another object. Conduction can occur in solids, liquids, or gases, but it is more effective in A. gases because their particles are moving faster. B. liquids and gases because they occur at higher temperatures. C. liquids because they have a definite volume but not a definite shape. D. solids and liquids because their particles are arranged more closely together.
Answer:
The correct answer is D. solids and liquids because their particles are arranged more closely together.
A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 118 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 33.4°. How wide is the river?
Answer:
68.5 meters
Explanation:
To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.
Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).
sin(33.4°) = opposite/hypotenuse
sin(33.4°) = w/x
w = x * sin(33.4°)
w = 118 m * sin(33.4°)
w = 68.5 m
Therefore, the width of the river is approximately 68.5 meters.
a moterist travels 320km at 80km/h and then 320km at 100km/h what is the average speed of moterist for the entire trip
Answer:
88.89 km/h.
Explanation:
D = S + T
= 320km + 320km = 640km.
T = D/S
T1 = 320km / 80km/h = 4 hours
T2 = 320km / 100 km/h = 3.2 hours
Ttotal = T1 + T2 = 4 hours + 3.2 hours = 7.2 hours.
S = D/T
= 640km / 7.2 hours
= 88.89 km/h.
*Note:
S = Average speed.
D = Total distance.
T = Total time.
The average speed of the motorist for the entire trip is approximately 88.89 km/h.
To calculate the average speed of the motorist for the entire trip, we need to consider the total distance traveled and the total time taken. In this case, the motorist travels 320 km at 80 km/h and then another 320 km at 100 km/h.
First, let's calculate the time taken for each leg of the trip:
Time taken for the first 320 km at 80 km/h:
Time = Distance / Speed = 320 km / 80 km/h = 4 hours
Time taken for the second 320 km at 100 km/h:
Time = Distance / Speed = 320 km / 100 km/h = 3.2 hours
Now, let's calculate the total distance and total time for the entire trip:
Total distance = 320 km + 320 km = 640 km
Total time = 4 hours + 3.2 hours = 7.2 hours
Finally, we can calculate the average speed:
Average speed = Total distance / Total time = 640 km / 7.2 hours ≈ 88.89 km/h
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Which of the following are INCORRECT statements regarding how higher temperatures result in higher reaction rates? Select all that apply, this is a multiple response question. Othe average kinetic energy of reacting molecules is increased Oreacting molecules collide more frequently, and with higher kinetic energies Oreacting molecules have higher kinetic energies but lower collision frequencies Othe activation energy barrier for the reaction is lowered Oendothermic reactions become exothermic reactions at higher temperatures Oa greater fraction of colliding molecules has the minimum energy required to overcome the activation energy barrier
The incorrect statements regarding how higher temperatures result in higher
reaction rates are:
1) Reacting molecules have higher kinetic energies but lower collision frequencies.
2) The activation energy barrier for the reaction is lowered.
3) Endothermic reactions become exothermic reactions at higher temperatures.
Higher temperatures result in an increase in both kinetic energy and collision frequency of molecules.
The activation energy barrier for the reaction does not change with temperature,
But a greater fraction of colliding molecules has the minimum energy required to overcome the activation energy barrier at higher temperatures.
Endothermic reactions do not become exothermic reactions at higher temperatures. These reactions may occur at a faster rate, but the overall energy change of the reaction does not change.
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A first order reaction is 40% completed in 30 minutes. what fraction of reactant remains at 40 minute?
Answer:
Explanation:
ln(A) = ln(A₀) - kt
a 25-cm-long glass stirring rod at a laboratory temeprature of 20 c is placed in an autoclave and heated to 150 c. by about how much does the rod expand
In order to reach a chambers temperature of a minimum of 250°F (121°C) for just a set amount of time—typically 30–60 minutes—autoclaves employ saturation steam with a pressure of around 15 square inches per square.
What kind of heat is in an autoclave?To eliminate any potential microbiological life on a contaminated load, autoclaves use steam heat. Once a cargo, also known as goods, has gone through a complete sterilising cycle, it is deemed sterile.
Why would a lab need an autoclave?An autoclave is used to sterilise surgical instruments, lab equipment, pharmaceutical products, and other things. It has the capacity to sterilise devices of all shapes and sizes as well as hollow items, liquids, solids, and solids. The dimensions, architecture, and operation of autoclaves vary.
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the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x direction. A golfer hits his tee shot a distance of 300.0 m, corresponding to a displacement of r1 = 300.0 mi and then hits his second shot 189.0 m corresponding to a displacement of r2 = 172.0 mi + 80.3 mj. What is the final displacement of the golf ball from the tee? Give your answer as a resultant vector that incorporates horizontal and vertical components.The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x direction. A golfer hits his tee shot a distance of 300.0 m, corresponding to a displacement Δr⃗ 1=300.0miˆ,and hits his second shot 189.0 m with a displacement Δr⃗ 2=172.0miˆ+80.3mjˆ.What is the final displacement of the golf ball from the tee?
Answer:
(472i + 80.3j) m
Explanation:
Given the following :
Distance of tee shot = 300m
Distance of second shot = 189.0 m
Displacement r1 of tee shot :
r1 = 300 mi
Displacement r2 of second shot :
r2 = 172.0 mi + 80.3 mj
The final displacement of the golf ball from the tee:
r_final = r1 + r2
r_final = (300i)m + (172.0i + 80.3j) m
r_final = (300 + 172)i m + 80.3j m
r_final = (472i + 80.3j) m
If f is a linear function, f(0.1) = 10.5, and f(0.4) = −6.6, find an equation f(x) for the function.
The linear equation f(x) for the function is found as :
f(x) = -57x + 16.5.
How to find equation of linear function?The linear function is one that has the formula f(x) = mx + b, in which m denotes the line's slope and b its y-intercept. When two points of such a linear function are supplied, we can get the function by utilizing the two points to determine the line's slope, or m.Then plugging the slope along with one of the awarded numbers into the equation f(x) = mx + b, where b is the unknown. The last step is to enter m as well as b into f(x) = mx + b.For the stated question:
f(0.1) = 10.5, and f(0.4) = −6.6
Slope m = (-6.6 - 10.5) / (0.4 - 0.1)
m = -57
The standard equation is:
10.5 = -57(0.1) + c
c = 16.5
linear equation f(x):
f(x) = -57x + 16.5
Thus, the linear equation f(x) for the function is found as :
f(x) = -57x + 16.5.
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object
Answer:
v = 25.45 m/s
Explanation:
In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:
\(h_{max}=\frac{v_o^2}{g}\) (1)
vo: initial speed of the object = 18 m/s
g: gravitational acceleration = 9.8 m/s²
Furthermore you use the following formula for the final speed of the object:
\(v^2=v_o^2-2gh\) (2)
h: height
You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:
\(v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2\)
Then, you solve the previous result for vo:
\(v_o=\sqrt{2}v=\sqrt{2}(18m/s)=25.45\frac{m}{s}\)
The initial speed of the object was 25.45 m/s
In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?
Answer:
The value is \(m \approx 310\)
Explanation:
From the question we are told that
The focal length of the objective is \(f_o = 1.0 \ cm\)
The focal length of the eyepiece is \(f_e = 2.0 \ cm\)
The tube length is \(L = 25 \ cm\)
Generally the magnitude of the overall magnification is mathematically represented as
\(m = m_o * m_e\)
Where \(m_o\) is the objective magnification which is mathematically represented as
\(m_o = \frac{L}{f_o }\)
=> \(m_o = \frac{25}{1 }\)
=> \(m_o = 25\)
\(m_e\) is the eyepiece magnification which is mathematically evaluated as
\(m_e = \frac{L }{f_e }\)
\(m_e = \frac{25 }{ 2}\)
\(m_e = 12.5 \ cm\)
So
\(m = 25 * 12.5\)
\(m \approx 310\)
Please help me as quick as possible!!!!!!! Please, please please!!!!!!
Answer:
23
Explanation:
3x-4
What is motivation in your own world
Answer:
Motivation is the process that initiates, guides, and maintains goal-oriented behaviors.
In an informative article in a magazine it is stated that tires lose roughly 6 kPa of pressure for every 6 °C drop in outside temperature. Investigate if this is a valid statement. Assume the air in the tire is an ideal gas and its volume remains constant. Take the atmospheric conditions as 25 °C and 1 atm = 100 kPa.
This is a Valid statement about pressure.
What is pressure.
pressure is continues physical force exerted on or against an object by something in contact with.
We know the idol gas equation, idyl gas equation. P v is equals to n r t. We can write the equation. As p is equal to n r upon v into p. Now n r upon v is equals to constant, is equals to constant. So we can write. P is equal to c into t. So now let us consider the ambient condition, which is p not equals to 101325 p. A and t naught is equal to 90 degrees. Fahrenheit will convert this value kelvin and get 5048.37 kelvin. So value of p, not anti. Note is 0 now from the modified idol equation. We have p equal to c t, so we can write it as a p. Not is equal to c and t not so we'll substitute the values 1013 to 5 p, a which is equal to c 2348.37 kelvin. So here we get the value of c, which is equals to 43.147. So from this we can say that the change in pressure for the 10 degree temperature drops so here delta equal to delta, which is equal to 10 degrees fahrenheit. We can again convert this value in the kelvin and we get 260.93 kelvin, so delta p is equal to c into delta. This will be delap equals to 43.147, as we get the value of c and 2 red 60.93 kelvin p, so delta p is equal to 43.147 So from this we can say that the change in pressure for the 10 degree temperature drops so here delta equal to delta, which is equal to 10 degrees fahrenheit. We can again convert this value in the kelvin and we get 260.93 kelvin, so delta p is equal to c into delta. This will be delap equals to 43.147, as we get the value of c and 2 red 60.93 kelvin p, so delta p is equal to 43.147 and 260.93 kelvin upon 694.75 p s. I so we finally get the value of delta p, which is equals to 1.63 p s. I.
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An ionic bond is formed when the valence electrons are
A.completely destroyed
B.unequally shared
C.equally shared
D.completely transferred
Consider a thin, spherical shell of radius 14.5 cm with a total charge of 29.5 µC distributed uniformly on its surface. (a) Find the electric field 10.0 cm from the center of the charge distribution. (b) Find the electric field 21.5 cm from the center of the charge distribution.
Answer:
10.0 zero, by Gauss' Law the symmetrical distribution will produce no internal electric fields
21.5 E = k Q / R^2 behaves as if all charge were at center
E = 9 E9 * 29.5 E-6 / .215^2 = 5.74E6 N/C
is weather chart the same as aneroid barometer
NO
Explanation:
A weather chart is a geographical map while an aneroid barometer is an anhydrous barometer(without liquid)
a healthy person has a body temperature of 37 degree celsius. if they jump into an ice bath after sports training their temperature only decreases slowly. how can you explain this when a lump of metal at 37 celsius degree placed in the same ice bath cools down to 0 celsius degree in only a couple of minutes