what is the thermal energy of 100 cm3 of aluminum at 100 ∘c ?
Answers
The thermal energy of 100 cm³ of aluminum at 100 °C is 24,459 Joules.
To calculate the thermal energy of 100 cm³ of aluminum at 100°C, we need to use the specific heat capacity of aluminum and the formula for thermal energy:
Q = mcΔT
where Q is the thermal energy, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
The specific heat capacity of aluminum is 0.903 J/g°C.
First, we need to convert the volume of aluminum to its mass. The density of aluminum is 2.7 g/cm³, so:
mass = volume x density = 100 cm³ x 2.7 g/cm³ = 270 g
Next, we calculate the change in temperature:
ΔT = 100°C - 0°C = 100°C
Now we can plug in the values:
Q = (270 g) x (0.903 J/g°C) x (100°C) = 24,459 J
Therefore, the thermal energy of 100 cm³ of aluminum at 100°C is 24,459 J.
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Related Questions
You may have had an opportunity to skip rope or watch someone else skip rope. If you have one rope, you can skip a yourself or you can include two friends, each friend holding one end of the rope and you skipping in the middle. In this instance your friend represent notes and you were anti-node. Is it possible to skip rope with three friends with two of you in yhe middle jumping at different times?.
Answers
Answer:
What is skip rope?
Explanation:
Sorry this wont help
two common sources of electric current are generators and:
Answers
The second common source of electric current is batteries.
Electricity is a type of energy that is essential in our daily lives. It's used to power machines, light up homes, charge smartphones, and much more. To make all of this possible, a source of electric current is necessary. Generators and batteries are two common sources of electric current.
Generators are devices that convert mechanical energy into electrical energy. Generators use turbines or engines to create motion, which is then converted into electricity. They are commonly used in power plants to generate electricity on a large scale.
They are also used in portable generators for remote power in areas without electricity. The generators function as backup power for data centers, hospitals, and emergency services.Batteries are another source of electric current. Batteries produce electric current through a chemical reaction.
The reaction generates a flow of electrons from the anode to the cathode. Batteries come in various sizes and types, from small disposable batteries used in flashlights to large batteries used in electric cars, and even large-scale battery systems used to store energy from renewable sources. Batteries are commonly used in portable electronic devices, such as smartphones, laptops, and cameras.
In conclusion, generators and batteries are two common sources of electric current. Generators convert mechanical energy into electrical energy, while batteries produce electric current through a chemical reaction. Both are essential sources of energy in our daily lives, powering everything from our homes to our cars.
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Love, which can’t be observed or measured directly, is an example of a psychological construct.
Please select the best answer from the choices provided
T
F
Answers
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s east. Find the velocity of the tennis racket after the collision.
Answers
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of tennis racket = 0.311 kg
m₂ = mass of the ball = 0.057 kg
u₁ = velocity of tennis racket before collision = 30.3 m/s
u₂ = velocity of the ball before collision = -19.2 m/s
v₁ = velocity of tennis racket after collision
v₂ = velocity of the ball after collision
Right (+) , Left (-)
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)
= 14.966 m/s.
So, the velocity of the tennis racket after the collision 14.966 m/s.
How much work is done when 5 newtons move through 3 meters?
Answers
Answer:
15 j
Explanation:
Work = F * d
= 5 N * 3 m = 15 j
A box is being pushed to the right with a force of 300 Newton’s, and to the left with a force of 400 Newton’s. What is the magnitude of the net force on the box?
Answers
100 Newtons (to the left)
a. l1 =20 A and l2 =24 A
B. l1 = 20A and l2 = 12 A
C. l1 = 26 A and l2 = 12 A
D. l1 = 24 A and l2 = 8 A
Answers
Answer:
when u find out pls lmk! i have the same question and I've been stuck for a while lol
Can someone answer 1 2 3 4 6
Answers
EDGE— Sometimes doctors have difficulty seeing tumors on images of the brain when they are very small. Which form of nanotechnology is most likely to help improve brain imaging?
Answers
Dendrimers are the form of nanotechnology is most likely to help improve brain imaging.
What is nanotechnology?Nanotechnology is the near-atomic manipulation of matter to create new structures, materials, and gadgets.
The technique offers scientific improvement in a variety of fields, including medical, consumer goods, energy, materials, and manufacturing.
Dendrites are a kind of nanoparticle that has been studied extensively for a variety of medicinal applications, including medication administration, imaging, and diagnostics in the brain.
Hence,dendrimers are the form of nanotechnology is most likely to help improve brain imaging.
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Answer:
B. Quantum Dots
Explanation:
Nanotechnology with quantum dots allows for better imaging while examining the body.
Plzzz help. Will give branliest.
Why should experiments be replicable?
A. So that the materials used can be validated.
B. So that scientists can gain popularity in the community.
C. So that fewer errors will be made and the data appear to be more correct.
D. So that others can repeat experiment and obtain similar results.
Answers
D. So the scientists can repeat the same experiment and get the same or similar results.
Answer:
C
Explanation:
a crane lifts a piano that weighs 3,240 n in the air 10m in 60 seconds. how much power does the crane have?
Answers
The crane has a power of 540 watts when it lifts the 3,240 N piano 10 meters in 60 seconds.
To calculate the power of the crane, we need to use the formula:
Power = Work / Time
The work done by the crane is equal to the force it applies multiplied by the distance it lifts the piano, which is:
Work = Force x Distance
Work = 3,240 N x 10 m
Work = 32,400 Joules
The time it takes for the crane to lift the piano is given as 60 seconds.
Now we can substitute these values into the formula for power:
Power = Work / Time
Power = 32,400 J / 60 s
Power = 540 watts
The 3,240 N piano is lifted 10 metres in 60 seconds by the crane, which has a power of 540 watts.
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A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the arm of the centrifuge is 21m what is the speed of the centrifuge?
Answers
Answer:
\(approx.= 25\frac{m}{s}\)
Explanation:
Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:
\(a=\frac{V^{2} }{r}\)
which allows us to solve for the velocity:
\(V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...\)
Answer:
25 m/s
Explanation:
A = v^2r
The square root of Ar = v
V = square root of 3.04 x 21 x 9.8 = 25m/s
Make sure to add 9.8 as acceleration is 3.04g or 3.04 x 9.8
A double inclined plane that moves is a(n) .
Answers
Answer:
a wedge.
Explanation:
it moves when you apply force to one end of the wedge.
the earth rotates once every 24 hrs. a person in north america is 4.88*10^6 m from the earth's axis. what is the person's linear speed?
Answers
Answer:
The linear speed is approximately 354.88361 m/s
Explanation:
The given parameters are;
The time it takes the Earth to make one complete rotation = 24 hrs.
The distance of the location of the person in North America from the axis, r = 4.88 × 10⁶ m
The rotation per 24 hours = 1 rev/(24 h)
24 hours = 24 hours ×60 minutes/hour × 60 seconds/minute = 86,400 seconds
Therefore, we have, the rotation rate per second, n = 1 rev/(86,400 s)
The angular speed, ω = 2·π·(1 rev/(86,400 s)) ≈ 7.2722052 × 10⁻⁵ rad/s
The linear speed, v = ω × r
Therefore, v ≈ 7.2722052 × 10⁻⁵ rad/s × 4.88 × 10⁶ m = 354.88361 m/s.
The linear speed, v ≈ 354.88361 m/s.
How much force is applied if a 130 kg mass is accelerated at 5 m/s^2
Answers
Answer:
650N
Explanation:
f = ma
130kg x 5 m/s^2 = 650N
what is the value of the electric field .3 m from a square piece of metal which is 1.5 km x 2 km and has a net charge of 26 mc?
Answers
The electric field is 490 N/C.
Electric field can be considered as an electric property associated with each point in the space where a charge is present in any form. An electric field is also described as the electric force per unit charge.The formula of the electric field of a charge sheet in terms of surface charge density σ and the formula of surface charge density are shown below:
E = σ/2ε and σ = q/A
Using these two, we get:
E = q/2Aε
Where,
q = charge = 26mC = 26* 10^-3 C
A = Area of sheet = 1.5*2 = 3 km^2 = 3 * 10^3 m^2
ε = permeability = 8.85 * 10^-12
Putting these values in above equation we get: E = 490 N/C
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Bumper car A (281 kg) moving
+2.82 m/s makes an elastic
collision with bumper car B
(209 kg) moving -1.72 m/s.
hat is the velocity of car A after
the collision?
(Unit = m/s)
Answers
The quantity "moment of inertia" (in terms of the fundamental quantities of mass, length, and time) is equivalent to:
ML2T2
ML
ML2
ML-1T2
Answers
The quantity "moment of inertia" (in terms of the fundamental quantities of mass, length, and time) is equivalent to ML^2.
The moment of inertia is a measure of an object's resistance to rotational motion about a particular axis. It depends on both the mass of the object and the distribution of the mass relative to the axis of rotation. In terms of the fundamental quantities of mass (M), length (L), and time (T), the moment of inertia is equivalent to ML^2.
This means that the moment of inertia is directly proportional to the mass of the object and the square of the distance from the axis of rotation. It does not depend on time, as it is a static property of an object's mass distribution. When the mass is concentrated closer to the axis of rotation, the object will have a smaller moment of inertia, making it easier to rotate.
Conversely, when the mass is distributed further away from the axis of rotation, the object will have a larger moment of inertia, making it more difficult to rotate.
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The removal of a stimulus following a given behavior in order to decrease the frequency of that behavior.
Answers
The concept you are describing is known as negative reinforcement, which involves removing a stimulus after a behavior occurs in order to increase the likelihood that the behavior will be repeated in the future. the presentation of an aversive stimulus following a behavior with the goal of decreasing the frequency of that behavior
However, your description seems to be referring to punishment, which involves the presentation of an aversive stimulus following a behavior with the goal of decreasing the frequency of that behavior. So, to clarify, punishment involves adding an aversive stimulus, while negative reinforcement involves removing a stimulus.
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A car has an initial velocity of 24 km/h, the car then accelerates at 2 m/s² for 6 seconds. Calculate the final velocity in km/h.
Answers
Answer:
final velocity in km/h= 67.2km/h
Explanation:
Data
initial velocity (u)= 24km/h
from 36km/h = 10m/s
then 24km/h= u
hence,
\(u= \frac{24}{36} \times 10\)
u= 20/3 m/s
Time= 6s
Acceleration= 2m/s²
\(v = u + at\)
\(v = \frac{20}{3} + 2(6)\)
\(v = \frac{20}{3} + 12\)
\(v = \frac{56}{3} \)
final velocity = 56/3 m/s
From 10m/s=36km/h
56/3 m/s = V
V(km/h)=
\( \frac{56}{3} \times \frac{36}{10} \)
V(km/h)=67.2km/h
A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.
Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?
Answers
Answer:
a) The bullet will penetrate 0.375 meters into the bag of sand.
b) The average force exerted by the sand is 15 newtons.
Explanation:
The statement is incorrectly written. The correct form is presented below:
A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.
a) How far the bullet will penetrate into the bag of sand?
b) The average force exerted by the sand?
b) The average force exerted by the sand on the bullet (\(F\)), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:
\(F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}\) (1)
Where:
\(m\) - Mass of the bullet, measured in kilograms.
\(v_{o}\), \(v_{f}\) - Initial and final speeds of the bullet, measured in meter per second.
\(\Delta t\) - Impact time, measured in seconds.
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(\Delta t = 0.05\,s\), then the average force exerted by the sand is:
\(F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}\)
\(F = -15\,N\)
The average force exerted by the sand is 15 newtons.
a) The distance travelled by the bullet (\(\Delta s\)), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:
\(\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }\) (2)
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(F = -15\,N\), then the distance travelled by the bullet is:
\(\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}\)
\(\Delta s = 0.375\,m\)
The bullet will penetrate 0.375 meters into the bag of sand.
Two satellites A and B of the same mass are going around earth in concentric orbits. The distance of satellite B from earth's center is twice that of satellite A. What is the ratio of the centripetal force acting on B compared to that acting on A?
Answers
To determine the ratio of the centripetal force acting on satellite B compared to that acting on satellite A, let's consider the given information and use the formula for centripetal force:
1. Both satellites have the same mass (m).
2. The distance of satellite B from Earth's center is twice that of satellite A (rB = 2rA).
The formula for centripetal force (Fc) is:
Fc = (G * m * M) / r^2
where G is the gravitational constant, m is the mass of the satellite, M is the mass of Earth, and r is the distance between the satellite and Earth's center.
For satellite A:
FcA = (G * m * M) / rA^2
For satellite B:
FcB = (G * m * M) / rB^2
Now we find the ratio of FcB to FcA:
FcB / FcA = [(G * m * M) / (2rA)^2] / [(G * m * M) / rA^2]
Since G, m, and M are constant, we can simplify this expression:
FcB / FcA = (rA^2) / (2rA)^2 = 1 / 2^2 = 1 / 4
The ratio of the centripetal force acting on satellite B compared to that acting on satellite A is 1:4.
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People who do very detailed work close up, such as jewelers, often can see objects clearly at a much closer distance than the normal 25.0 cm. What is the power of the eyes of a woman who can see an object clearly at a distance of only 9.75 cm
Answers
The power of the woman's eyes is 10.26 diopters. This means that her eyes have a greater ability to converge light than a normal eye, allowing her to see objects at a closer distance in focus.
The power of the eye is given by the formula:
P = 1/f
where P is the power in diopters (D) and f is the focal length in meters.
Assuming a normal near-point distance of 25 cm, the power of the eye is:
P = 1/f = 1/0.25 = 4 D
To find the power of the eye of a woman who can see an object clearly at a distance of only 9.75 cm, we need to calculate the new focal length:
1/f' = 1/0.0975
f' = 0.0975 m
Now we can calculate the power of the eye:
P' = 1/f' = 1/0.0975 = 10.26 D
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If you pull an object horizontally, what part of your force does work?
Answers
QUESTION 6 New cars have a crumple zone to help minimise injuries during accidents. In addition seat belts, air bags and padded interiors can reduce the chance of death or serious injury.
6.1 Use principles in Physics to explain how air bags can reduce the chance of death or injury. (3)
Answers
Using principles in Physics the way in which air bags can reduce the chance of death or injury is that the airbag increases the time over which the velocity of the head changes so that the acceleration is reduced, and thus the force is reduced.
What is an Airbag?This is referred to as a vehicle occupant-restraint system using a bag designed to inflate extremely quickly, then quickly deflate during a collision.
The gas in the bag can only leave at a certain rate which makes it deflates slowly, and the time duration of the deceleration increases which therefore leads to the force being reduced during a collission and reduces the risk of injury.
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Which two changes would decrease the electric force between two charged
particles?
A. Increase the distance between the particles.
B. Decrease the distance between the particles.
C. Increase the charge of both particles.
D. Increase the charge of one of the particles.
E. Decrease the charge of one of the particles.
Answers
Answer:
Decrease the charge of one of the particles
a certain spring stretches 7.0 cm when a load of 36 n is suspended from it. how much will the spring stretch if 48 n is suspended from it (and it doesn't reach its elastic limit)?
Answers
The spring will stretch 9.3 cm when a 48 N load is suspended from it, provided it doesn't reach its elastic limit.
Hooke's Law states that the force (F) is proportional to the displacement (x) of the spring, with a constant of proportionality called the spring constant (k).The spring constant (k) can be calculated using Hooke's Law: F = kx, where F is the force applied, x is the displacement, and k is the spring constant. In this case, we can solve for k by rearranging the formula: k = F/x.
Substituting the values given, we have:
k = 36 N / 0.07 m
k = 514.3 N/m
To find out how much the spring will stretch when 48 N is suspended from it, we can use the same formula and solve for x:
x = F/k
x = 48 N / 514.3 N/m
x = 0.093 m
Therefore, the spring will stretch by 9.3 cm when 48 N is suspended from it.
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Which applications, either for diagnostic purposes or for therapeutic purposes, involve radioactive materials placed in the body? Check all that apply.
radiopharmaceuticals
MRI
laser eye surgery
external beam radiation therapy
lithotripsy
brachytherapy
radioisotope imaging
Answers
Answer:
radiopharmaceuticals
brachytherapy
radioisotope imaging
Explanation:
edge 2020
When a radioactive material is required to be placed in the body, the applications are brachytherapy and radioisotope imaging.
Radioactive materials are elements which has the ability to disintegrate by emitting radioactive substance or radiation. A good example of this is Cobalt-60, Titanium-99 etc.
Brachytherapy is a therapeutic process in which radioactive material is inserted into the body in close proximity to the region affected. The radioactive material emits radiations which are required to control the unwanted biological material in the body. A good application of this is the treatment of cancer using Cobalt-60.
Radioisotope imaging is a diagnostic process which is an imaging technique that may require placing a radioactive material in the body so as to trace or locate the affected part of the body. In this case, the material is used as a tracing element.
The applications that require the placing of radioactive materials in the body are brachytherapy and radioisotope imaging.
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These types of electromagnetic waves are listed in order of increasing frequency:
microwaves, visible light, ultraviolet, and X-rays. Which type has the greatest energy?
A. Microwaves
B. X-rays
C. Visible light
D. Ultraviolet
the answer is ( B x-rays)
Answers
Answer:
B. X-rays
Explanation:
From the given choices, x-rays will have the highest energy of the given waves.
The energy of electromagnetic waves is highly dependent on their frequency and wavelength.
Electromagnetic waves with a high frequency and small wavelength will have higher energy compared to those with low frequency and high wavelength.
X-rays are one the most energetic waves on the periodic table. They have a very high frequency and low wavelength.
Answer: B. X-rays
Explanation:
Which law best describes this behavior of gases in the Sun?
Answers
Answer:
The extreme pressure from the weight of the gases that make up the Sun raises the temperature of the core enough for the nuclear reactions to take place, Which law best describes this behavior of gases in the Sun? A. Charles law.
Explanation:
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