What is the total voltage of a parallel circuit with resistances of 3.1002, 4.2302 and 3.1502 and a current of 80 amperes?

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

The system is open, because there is a net force exerted on the block.

An individual strolling, a taking off baseball, a piece tumbling from a table and a charged molecule in an electric field are instances of dynamic energy at work. An item that isn't moving has zero motor energy.

The energy an item has as a result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed.

According to question:

On graphing free body diagram of the problem

There is a force = mgsin(37°)

So, the it is a open system.

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Answer:

-79.6

-80

-81.2

Explanation:

Fart

What is the change in temperature for the aluminum wire?

-79.6

What is the change in temperature for the steel wire?

-80

What is the change in temperature for the lead pellets?

-81.2

Time to collision is 7.5 seconds, rounding up the response.

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To show that the electric field anywhere inside the plane of the charged circular ring would be zero if the electric field was inversely proportional to r (not r^2), we can examine the symmetry of the system.

Consider a point P located inside the plane of the ring, at a distance r from the center of the ring. To simplify the analysis, let's focus on a specific point on the ring, labeled as point A. At point A, the electric field due to the charge q on the ring will have a magnitude inversely proportional to the distance between point A and point P, which is r.
Now, let's consider another point B on the ring that is diametrically opposite to point A. Since the ring is symmetrical, the charge distribution is also symmetrical. The electric field at point B, which is also at a distance r from point P, will have the same magnitude as at point A but will be directed in the opposite direction. If we continue this analysis for all points on the ring, we find that for every point with a certain magnitude of electric field directed towards point P, there is an opposite point with the same magnitude of electric field directed away from point P. These pairs of opposite points cancel each other's electric field contributions, resulting in a net electric field of zero at point P.
This can be visually represented by a graphical analysis, where vectors representing the electric field at different points on the ring are shown and their cancellation is observed.Therefore, for a charged circular ring with an electric field that is inversely proportional to r, the electric field anywhere inside the plane of the ring would be zero due to the symmetry of the system.

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When a body is moving in the same direction, its relative speed is 6m/s, while when it is moving in the opposite direction, it is 42 m/s.

The units used to measure speed and velocity are the same. The meter is the SI unit for measuring both distance and displacement. The second is the second as defined by the International System of Units. Two meters per second divided by two is the SI unit of velocity and speed.

It is calculable using an intermediary reference frame. The velocity vector sum can be used to represent this simply. vAB = vA - vB is the way to express the relative velocity formula.

velocity is the same as the relative velocities of A and B.

A=24,B=18

Vab=24-18=6m/s

In opposite direction

Vab=24-(-18)=42m/s

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The centripetal force on the model helicopter is 6.25N.

The radius of the curve of the model helicopter is 30m and the mass of the helicopter is 300g, it is travelling with a speed of 90km/h.

Converting the speed into m/s, speed is 25m/s.

The centripetal force on a body is given by,

F = Mv²/r

Where,

F is the force,

V is the speed,

r is the radius,

So, putting values for helicopter,

F = 0.3 x 25 x 25/30

F = 6.25 N.

So, the centripetal force is 6.25 N.

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The magnitude of the force F experienced by a charge q that moves in a direction perpendicular to a magnetic field B with a speed v is given by:

Isolate B from the equation:

Replace F=22.394N, q=0.049C and v=272.4m/s to find the strength of the magnetic field:

Therefore, the magnetic field strength is approximately 1.7T.

The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.

Evidence 1: Effect of Air Quality

Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.

Environmental impact is evidence number two

Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.

Evidence 3: Worker health effects

Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.

Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.

Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.

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Answer:

Weight = 3217.68

Explanation:

N times Gravity = weight

Gravity= 9.81

The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.

Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -

W = m x g

where -

[m] is the mass of object

[g] is acceleration due to gravity

Given is the mass of an emperor penguin as 328 Kg.

We can write -

Mass [m] = 328 kg

Acceleration due to gravity [g] = 9.8 m/s²

Therefore, the weight of the emperor penguin will be

W[P] = m x g = 328 x 9.8 = 3214.4 Newtons

Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons

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Answer:

v = 2.94 m/s

Explanation:

When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.

Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.

Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means

(1/2)kx^2 = (1/2)mv^2

kx^2 = mv^2

v^2 = (kx^2)/m

v = sqrt((kx^2)/m)

v = x * sqrt(k/m)

v = 0.122 * sqrt(125/0.215)        <--- units converted to m and kg

v = 2.94 m/s

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 84 × 6.4

We have the final answer as

Hope this helps you

To reduce refrigerant loss from a purge unit on a R-123 chiller, the first step is to perform a leak test on the chiller to identify any leaks that may be present. Once the leaks are identified, they should be repaired immediately to prevent further refrigerant loss. It is important to use the charge stated on the equipment nameplate to ensure the chiller is operating at optimal capacity.

In addition to leak testing and repairs, regular maintenance of the chiller can help prevent refrigerant loss. This includes cleaning the chiller coils and replacing any worn or damaged components. Properly training personnel on the operation and maintenance of the chiller can also help reduce refrigerant loss by ensuring that any issues are identified and addressed promptly.

Finally, it is important to properly dispose of any refrigerant that is removed from the chiller during repairs or maintenance. This can be done by using a certified refrigerant reclaimer or disposal service, which will safely recover and recycle or dispose of the refrigerant according to regulations. By taking these steps, refrigerant loss from a purge unit on a R-123 chiller can be reduced, helping to protect the environment and ensure the continued efficient operation of the chiller.

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The heat lost by water is equal to the heat gained by ice here. The heat lost from water for a temperature change of 25 to 10 degree Celsius is 12300 J.

Calorimetry is an analytical technique used to determine the heat energy absorbed or evolved by a system. The calorimetric equation relating the heat energy q with the mass m, specific heat c and the temperature difference ΔT is :

q = m c ΔT

Here, the heat energy gained by the dry ice is equal to the heat lost from water.

temperature difference for water = 25- 10 °C = 15°C

thus, 15°C is lost from water.

mass of water = 200 g

q =200 g × 4.12 J/°C g × 10°C = 12300 J

Therefore, the heat energy lost from water is 12300 J.

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Answer:

25000 N

Explanation:

\(force \: = pressure \times area \\ = 50000 \times 0.5 \\ = 5000 \times 5 \\ = 25000 \: N\)

Answer:

m = 96.53 grams

Explanation:

Given that,

The density of metallic platinum, d = 21.5 g/cm³

Volume, V = 4.49 cm³

We need to find the mass. Let it is m. We know that the density is equal to the mass per unit volume. So,

\(d=\dfrac{m}{V}\\\\m=d\times V\\\\m=21.5\times 4.49\\\\m=96.53\ g\)

So, the required mass is 96.53 grams.

The statement is absolutely true. H differs from 2H.

Justification:

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

All black holes contain singularities, however not all singularities involve black holes. A neutron star may be dense, matter the size of a pinhead can weigh as much as the earth, but there seems to be a mathematical cut-off point beyond which a black hole is formed.

If a star is moving towards Earth, shift towards the blue end of the spectrum, this is called blue shift. If the star is moving away from Earth the light from that star will be red and is called red shift .

The faster a star moves towards the earth, the more its light is shifted to higher frequencies. In contrast, if a star is moving away from the earth, its light is shifted to lower frequencies on the color spectrum

if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.

If the star is moving away from Earth, its light will lose energy to reach Earth, therefore the light from that star will be red and is called red shift

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The equation dT/dt = -k(T - To) represents the rate of change of temperature with respect to time, where T is the temperature of the metal ball at a given time, To is the ambient temperature, k is the cooling constant, and dT/dt denotes the derivative of temperature with respect to time.

We can solve this first-order differential equation to find the time it takes for the metal ball to reach a temperature of 40°C.
Given:
Initial temperature (T0) = 100°C
Final temperature (T) = 40°C
Ambient temperature (To) = 30°C
The equation can be rewritten as:
dT / (T - To) = -k dtIntegrating both sides:
∫ dT / (T - To) = -k ∫ dt
Applying the natural logarithm:
ln|T - To| = -kt + C
To determine the constant C, we use the initial condition:
ln|T0 - To| = -k(0) + C
ln|T0 - To| = C
Substituting the values:
ln|100 - 30| = ln|70| = C
The equation becomes:
ln|T - To| = -kt + ln|70|
Now, we can solve for the time it takes for the metal ball to reach a temperature of 40°C.
ln|T - To| = -kt + ln|70|
ln|40 - 30| = -k(t) + ln|70|
ln|10| = -kt + ln|70|
ln(10) - ln(70) = -kt
Simplifying,
ln(10/70) = -kt
Rearranging the equation to solve for time (t):
t = -ln(10/70) / k
To find the value of the cooling constant k, we can use the given information that the metal ball cools from 100°C to 70°C in 15 minutes.
ln(70 - 30) = -k(15)
ln(40) = -15k
Solving for k:
k = -ln(40) / 15
Now we can substitute the value of k into the equation for time (t):
t = -ln(10/70) / (-ln(40) / 15)
t ≈ 10.97 minutes
Therefore, it will take approximately 10.97 minutes for the metal ball to reach a temperature of 40°C.

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The reason why a dropped object only fall 5 m down and after 1 second, the speed is 10 m/s is because the acceleration due to gravity is 10 m/s².

From the question given above, we obtained the following:

Thus, we can obatin speed after 1 second as illustrated below:

v = u + gt

v = 0 + (10 × 1)

v = 0 + 10

v = 10 m/s

Thus, we can see that the speed is 10 m/s as long as the acceleration due to gravity actiing on it is 10 m/s²

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Answer:

Balanced

Explanation:

If a stationary object is staying still (in this case it's the ball) all of the forces acting upon it are balanced. If an object moving has balanced forces, it would move in the same direction at the same speed until a different outside force interrupts the equilibrium.

Hope this helps :)

This question involves the concepts of Newton's Second Law and Balanced Force.

The forces acting upon the ball are "Balanced".

According to Newton's Second Law whenever an unbalanced force is applied on an object, it produces an acceleration in the object in the direction of the force itself. This acceleration is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

Since, the ball is at rest and not moving. Hence, it has no acceleration and no unbalanced force is applied on it. The weight of the ball is balanced by the normal reaction provided by the table. Therefore, the forces acting on the ball are Balanced Forces.

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With the equation: it is possible to determine t for each of the four ramp segments. t 1 = t 2 - t 1, and t 2 = t 4 - t 3 Likewise, x is the distance between the designated spots for times 3 and 4, respectively.

Although the gravitational force is same when you roll the ball down a ramp, it is no longer in free fall. Now, it has a vector structure. Knowing the downward force and the ramp's incline makes the problem appear to be Pythagorean. Keep in mind that the ball will go at the same speed at the bottom of the ramp as it would have. A ball begins rolling down a ramp with constant acceleration at time zero (t=0), initially at rest. It moves 1 foot between t=0 and t=1 seconds, you see. How much movement occurs between t = 1 second and a.

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Answer:

a)  S = V0 t + 1/2 a t^2     distance ball travels in time t

0 = V0 t - 1\2 * 9.8 * t^2       ball returns to original height

V0 = 4.9 * 4.5 = 22.05 m / s      original speed

b) Since V0 = g t   time to decelerate to zero

t = 22.05 / 9.8 =  2.25 sec       time up equals time down

c) S = V0 t + 1/2 a t^2  

S = 22.05 * 2.25 - 9.8 / 2 * 2.25^2 = 24.8     Max height

Check: Avg speed = 22.05 / 2 = 11.025 m/s

Time to fall from max height = 11.025 * 2.25 = 24.8 ft

After a batter pops a ball straight up we have:

a) The initial speed of the ball before it returns to the height from which it was hit 4.5 seconds later, is 22.07 m/s.

b) The ball reaches its maximum height 2.25 s after it was hit.  

c) The maximum height of the ball, s measured from the point where it was hit, is 24.8 m.          

a) The initial speed can be calculated with the following equation:

\( v_{f} = v_{0} - gt \)

We will use this equation to find the initial speed when the ball is moving upward.

Where:

\(v_{0}\): is the initial speed =?

\(v_{f}\): is the final speed = 0 (at the maximum height)

g: is the acceleration due to gravity = 9.81 m/s² (it is negative because its direction is in the opposite direction to the movement of the ball when it is going up)

t: is the time when the ball is going up

When the ball is going up, the time is:

\( t = \frac{4.5 s}{2} = 2.25 s \)

Hence, the initial speed is:

\( v_{0} = gt = 9.81 m/s^{2}*2.25 s = 22.07 m/s \)

b) The ball reaches its maximum height 2.25 s after it was hit because the ball returns to the height from which it was hit. The rise time is equal to the fall time.  

c) The maximum height of the ball is the following:

\( v_{f}^{2} = v_{0}^{2} - 2gh \)  

Where:

h: is the maximum height

Then, the maximum height is:

\( h = \frac{v_{0}^{2}}{2g} = \frac{(22.07 m/s)^{2}}{2*9.81 m/s^{2}} = 24.8 m \)

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The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

Explanation:

yan lng po Alam ko

Answer:

Explanation:

Given maximum height reached by the ball as H = 40 metres

Since the ball rises straight up when hit by a ball, then the angle of launch will be perpendicular to the ground and that is 90°.

To determine the upward speed of the ball in meters per second after it got struck by the bat, we will use the formula for calculating the maximum height according to projectile motion;

Maximum Height H = \(\frac{u^2sin^2\theta}{2g}\) where;

u is the speed of the ball

\(\theta\) is the angle of launch

g is the acceleration due to gravity = 9.81m/s²

Substituting the given parameters into the formula;

\(40 = \frac{u^2sin^2(90)}{2(9.81)}\\ \\40 = \frac{u^2}{2(9.81)}\\ \\40 = \frac{u^2}{19.62} \\cross\ multiply\\\\u^2 = 40*19.62\\u^2 = 784.8\\u = \sqrt{784.8}\\ u = 28.01 m/s\)

Hence the upward speed of the ball in meters per second after it got struck by the bat is 28.01m/s.

Answer:

Explanation:

For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or boyle's law is a gas, law, starting that the pressure and volume of a gas have an inverse relationship. If volume encreases, then pressure decreases and vice versa,when the temperature is held constant.

In 160 mL of 0.415 M solution, approximately 21.83 grams of Pb(NO₃)₂ are required.

To determine the number of grams of solute needed in a solution, we can use the formula:

grams of solute = (volume of solution in liters) x (molarity of the solution) x (molar mass of the solute)

Given:

Volume of solution = 160 mL = 160/1000 = 0.160 L

Molarity of the solution (Pb(NO₃)₂) = 0.415 M

The molar mass of Pb(NO₃)₂ can be calculated by adding up the atomic masses of lead (Pb), nitrogen (N), and oxygen (O):

Molar mass of Pb(NO₃)₂ = (atomic mass of Pb) + 2 x (atomic mass of N) + 6 x (atomic mass of O)

Plugging in the atomic masses, we have:

Molar mass of Pb(NO₃)₂ = (207.2 g/mol) + 2 x (14.0 g/mol) + 6 x (16.0 g/mol)

Calculating this expression gives us:

Molar mass of Pb(NO₃)₂ = 331.2 g/mol

Now, we can calculate the grams of solute using the formula mentioned earlier:

grams of solute = (0.160 L) x (0.415 M) x (331.2 g/mol)

Calculating this expression gives us:

grams of solute = 21.83 g

Therefore, approximately 21.83 grams of Pb(NO₃)₂ are needed in 160 mL of a 0.415 M solution.

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