What is the value of x when 3x < -2x + 15?
A.x > 3
B.x < 3
C.x < 15
D.x > 15
Help me plzzzzz it’s due today

The area of a rhombus with length of diagonal as 24 inches and 36 inches is 432 in²

Rhombus is a quadrilateral with two pairs of opposite and equal parallel sides. All the sides of a rhombus are equal and the diagonals bisect each other at 90 degrees.

The area (A) of a rhombus is given by:

where p, q are the length of the diagonals.

Given that:

The area of a rhombus with length of diagonal as 24 inches and 36 inches is 432 in²

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Answer:

432

Step-by-step explanation:

Answer:

x= 81°, z= 99°, y°=68°

Step-by-step explanation:

considering the part of the triangle where 36° , 63° and x° is located as ΔABC.

to find the measure of x we use angle sum property.

We know that the sum of the angles of a triangle is always 180°. Therefore, if we know the two angles of a triangle, and we need to find its third angle, we use the angle sum property. We add the two known angles and subtract their sum from 180° to get the measure of the third angle.

so,

∠A + ∠B +∠C = 180°

36° + 63° + x° = 180°

99° + x° = 180°

x° = 180 - 99

x° = 81°

When two lines intersect each other at a single point, linear pairs of angles are formed. If the angles so formed are adjacent to each other after the intersection of the two lines, the angles are said to be linear. If two angles form a linear pair, the angles are supplementary, whose measures add up to 180°.

x° + z° = 180°

81° + z = 180°

z= 180 - 81

z= 99°

considering the next part of the triangle where 13° , z° and y° is located as ΔACD

to find the measure of y we use angle sum property.

∠A + ∠C + ∠D = 180°

13° + z° + y° = 180°

13°+99°+y°= 180°

112°+ y° = 180°

y°= 180- 112

y° = 68°

Answer:

X = 2

Step-by-step explanation:

2 x 2 x 2 = 8

Hope this helps. Pls give brainliest.

Answer:

2 :)

Step-by-step explanation:

Answer:

Pleaseee post the question clearly

Step-by-step explanation:

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Códe to joín :- eqt-kuxy-dpe

Everyone Can Jóin

Answer:

(C) 4y - 3

Step-by-step explanation:

"Taking away" is (-)

Four times y is 4×y or 4y

Since the total distance Xavier traveled by car is a function of time, we can plot the distance on the y-axis and the time on the x-axis. From the information given, we can break down the journey into three parts: 30 minutes of driving, 2 hours of shopping (which does not add to the distance traveled by car), and 15 minutes of driving followed by 1 hour of stopping at a friend's house.

Therefore, the graph would show a horizontal line for the time period of 2 hours (since no distance was traveled during this time), a positive slope for the first 30 minutes of driving, a horizontal line for the 1 hour of stopping at the friend's house (since no distance was traveled during this time), and a positive slope for the final 15 minutes of driving.

Of the four graphs shown, the one that most accurately represents this scenario is graph D, which shows a positive slope for the first and last sections of the journey, and horizontal lines for the periods of shopping and stopping at the friend's house.

I don't want your points, instead give me brainliest

Answer:

π is irrational.

Step-by-step explanation:

That means that π goes on forever. Take a look at its digits. 3.14...

Can you see an unpredictable pattern?

The infinite series solution to the boundary value problem is:

\((x,t) = \sum Bn sin(n\pi x / 2) e^{(-(n\pi/2)}^2 t)\)

Using the method of separation of variables to derive the infinite series solution for (x). We begin by assuming a separable solution of the form:

(x,t) = X(x)T(t)

Substituting this into the heat equation, we get:

X(x)T'(t) =\(2 T(t) (X''(x)/X(x)^2)\)

Dividing both sides by X(x)T(t), we get:

T'(t)/T(t) =\(2 X''(x)/X(x)^2\) = -λ

where λ is a constant. This gives us two separate ODEs:

T'(t) + λ T(t) = 0 with boundary conditions T(0) = 0 and T(/2) = 0

and

X''(x) + λ X(x) = 0 with boundary conditions X(0) = 0 and X'(/2) = 0

Solving the first ODE for T(t), we get:

\(T(t) = c1 cos(\sqrt(\lambda) t) + c2 sin(\sqrt(\lambda) t)\)

Applying the boundary conditions, we get:

T(0) = 0 => c1 = 0

T(/2) = 0 => c2 \(sin(\sqrt(\lambda) (/2))\) = 0

Since \(sin(\sqrt(\lambda) (/2))\) ≠ 0, this implies that c2 = 0. Therefore, T(t) = 0, which means that λ must be negative. Let λ =\(-p^2\), where p > 0. Then the second ODE becomes:

X''(x) + \(p^2\) X(x) = 0 with boundary conditions X(0) = 0 and X'(/2) = 0

The general solution to this ODE is:

X(x) = c3 cos(px) + c4 sin(px)

Applying the boundary conditions, we get:

X(0) = 0 => c3 = 0

X'(/2) = 0 => c4 p cos(p/2) = 0

Since cos(p/2) ≠ 0, this implies that c4 = 0. Therefore, X(x) = 0, which is not a useful solution. To obtain non-trivial solutions, we must have the condition:

p tan(p/2) = 0

This condition has infinitely many solutions, given by:

p = nπ, n = 1, 2, 3, ...

Therefore, the solutions to the ODE are:

Xn(x) = sin(nπ x / 2)

with eigenvalues:

\(\lambda n = -(n\pi/2)^2\)

The general solution to the heat equation is then:

\((x,t) = \sum Bn sin(n\pi x / 2) e^{(-(n\pi/2)^2 t)}\)

where the coefficients Bn are determined by the initial condition.

This series solution satisfies the boundary conditions, and it can be shown to satisfy the heat equation.

Therefore, the infinite series solution to the boundary value problem is:

\((x,t) = \sum Bn sin(n\pi x / 2) e^{(-(n\pi/2)}^2 t)\)

where Bn are constants determined by the initial condition.

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Answer:

Step-by-step explanation:

n/3 - 2 = 4             Add 2 to both sides

n/3 - 2 + 2 = 4+2    Combine

n/3 = 6                  Multiply both sides by 3

3*n/3 = 6 * 3

n = 18

The solution of linear equations y=x-2 and y=-2x+7 is (3,1).

The given linear equation is,

y = x - 2      (equation 1)

y = -2x + 7   (equation 2)

To find the solution for this linear equation, we used the substitution method.

Solve equation 2 for value y,

y = -2x + 7

Put this value of y in equation 1

-2x + 7 = x - 2

-2x -x = - 2 - 7

-3x = -9

dividing into both sides by -3

we get, x = 3.

Put x=3 in equation 1 we get,

y = 3-2 =1

Therefore the solution of the given linear equation is (3, 1).

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Complete question:

Find the solution of the given linear equation.

y=x-2

y=-2x+7

Renee's monthly payment will be $504.46. The closest answer choice is d. $504.46.

To calculate Renee's monthly payment, we need to first determine the total cost of the new car after taxes and fees and subtract the trade-in value of her old car. Then, we can use the loan information to calculate the monthly payment.

Total cost of the new car:

List price: $19,675

Vehicle registration fees: $1,420

Documentation fees: $85

Sales tax: 8.92% of ($19,675 + $1,420 + $85) = $1,894.51

Total cost = $19,675 + $1,420 + $85 + $1,894.51 = $22,074.51

Trade-in value of the old car:

2002 Buick LeSabre in good condition: $3,374 (from the table)

85% of trade-in value: 0.85 x $3,374 = $2,867.90

Net cost of the new car:

$22,074.51 - $2,867.90 = $19,206.61

To calculate the monthly payment, we can use the formula for the present value of an annuity:

PV = PMT x (1 - (1 + r)^(-n)) / r

where PV is the present value of the loan, PMT is the monthly payment, r is the monthly interest rate (11.34%/12), and n is the number of payments (4 years x 12 months/year = 48).

Solving for PMT:

PMT = PV x r / (1 - (1 + r)^(-n))

PMT = $19,206.61 x 0.1134/12 / (1 - (1 + 0.1134/12)^(-48))

PMT = $504.46

Therefore, Renee's monthly payment will be $504.46. The closest answer choice is d. $504.46.

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Answer:

The equation representing the relationship is;

Amount charged to work a dog once a day = $1.25 * Number of days

Step-by-step explanation:

Here, we want to find the equation representing the relationship between the charges and the number of days

Firstly, he charges $6.25 to walk a dog a day for 5 days, the amount charged per day will be $6.25/5 = $1.25

For the 7 days, amount charged = 8.75/7 = $1.25

This means he charges an amount of $1.25 to walk a dog once a day

The equation that represents the relationship is thus;

Amount charged = $1.25 * Number of days

Therefore, the probability that a randomly selected point within the square falls in the red-shaded area is 68%.

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. The probability of an event A is denoted as P(A). To calculate the probability of an event, we divide the number of favorable outcomes by the total number of possible outcomes.

Here,

The area of the red-shaded region is the area of the square minus the area of the white right-angled triangle. The area of the square is the length of one side squared, which is:

Area of square = 5 cm × 5 cm

= 25 cm²

The area of the right-angled triangle is one-half the base times the perpendicular height, which is:

Area of triangle = (1/2) × base × height

= (1/2) × 4 cm × 4 cm

= 8 cm²

Therefore, the area of the red-shaded region is:

Area of red-shaded region = Area of square - Area of triangle

= 25 cm² - 8 cm²

= 17 cm²

To find the probability that a randomly selected point within the square falls in the red-shaded area, we need to divide the area of the red-shaded region by the total area of the square, which is:

Probability = Area of red-shaded region / Area of square

Probability = 17 cm² / 25 cm²

= 0.68 or 68%

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The average velocity from t = 2s to t = 4s would be - 48 ft/s.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is that an object is thrown upward with initial velocity of 48 feet per second from a high of 120 feet. The height of the object t seconds after it is thrown is given by h(t) = - 16t² + 48t + 120.

Average rate of change of velocity with time is called average velocity. Mathematically -

v{avg.} = Δx/Δt                                                         .... Eq { 1 }

Δx = x(4) - x(2)

Δx = - 16(4)² + 48(4) + 120 - {- 16(2)² + 48(2) + 120}

Δx = - 96

Δt = 4 - 2 = 2

So -

v{avg.} = Δx/Δt = -96/2 = - 48 ft/s

Therefore, the average velocity from t = 2s to t = 4s would be - 48 ft/s.

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The true statements are:

The given parameters are:

\(n = 61\) --- the total available number

\(r = 5\) --- the numbers to select

Since the order of selection is not important, we make use of the combination formula as follows:

\(^nC_r = \frac{n!}{(n -r)!r!}\)

So, we have:

\(^{61}C_5 = \frac{61!}{(61 -5)!5!}\)

\(^{61}C_5 = \frac{61!}{56!5!}\)

Simplify

\(^{61}C_5 = \frac{61 \times 60 \times 59 \times 58 \times 57}{5 \times 4 \times 3 \times 2 \times 1} \)

\(^{61}C_5 = \frac{713897640}{120}\)

\(^{61}C_5 = 5949147\)

Hence, there are 5949147 ways, groups of first five different numbers can be selected.

The last number can be any number from 1 to 27.

So, the total number of ways is:

\(Total = 27 \times 5949147 \)

\(Total = 160626969\)

Hence, there are 160626969 possible distinct outcomes

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The missing values of time and distance are 2, 7 and 30 respectively.The solution has been obtained by the concept of linear relationship.

What is linear relationship?

In statistics, a straight line of correlation between two variables is referred to as a linear relationship (or linear association).

We are given a table which represents a linear relationship.

In the table, it can be observed that for covering 18 km of distance, 6 minutes are required.

So, for covering 1 km of distance, 1/3 minutes are required

Therefore, for covering 6 km of distance, time required is

6 * 1/3 = 2 minutes

Similarly, for covering 21 km of distance, time required is

21 * 1/3 = 7 minutes

In 6 minutes, 18 km of distance is covered.

So, in 1 minute, the distance covered is 3 km.

Therefore, in 10 minutes, the distance covered is

10 * 3 = 30 km

Hence, the missing values are 2, 7 and 30 respectively.

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Answer:41

Step-by-step explanation:

378 inches squared

its (18x15)+(6x18)

Using it's concept, it is found that Brandon's net yardage for the game was of 26.

The total net yardage is the sum of all the yardage they gain, that is, the positive gains are added with a plus signal, while the negative gains are added with a negative signal.

Hence, his net yardage, considering that he gained 20 yards on his last 7 carries, is given by:

6 + 20 = 26.

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Answer:

32

Step-by-step explanation:

b^2c^1

Let b=-4 and c= 2

(-4)^2 ( 2)^1

16 * 2

32

Answer:

The correct answer is

-32

Step-by-step explanation:

All you need to do is plug in -4 and 2 into the equation to get:

4^2 times 2^1

This equals ...

-32

Hope this helps!

- xoxo Quinnisa

Answer:

Option 3

Step-by-step explanation:

All equations are in slope-intercept form. \(y=mx+b\)

The 'm' is the slope.

The 'b' is the y-intercept.

The slope is also known as the rate of change. So, we would have to look at what replaces 'm' and select two equations that have the same rate of change.

Let's look over the equations:

\(y=0.3x-6\)

In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.

\(y=3x-8\)

In this equation, 3 replaces 'm', so the rate of change for this equation is 3.

In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.

In this equation, 0.03 replaces 'm', so the rate of change for this equation is 0.03.

Equation C and equation A have 0.3 as the slope. Since the question asks for two equations that have the same rate of change, the answer would be Equations A and C, or Option 3.

The given system of differential equations is:

Jx' = Ax + By

y' = Cx + Dy

To find the solution to the given system of differential equations, let's first rewrite the system in matrix form:

Jx' = A*x + B*y

y' = C*x + D*y

where

J = [-67 -210]

A = [21 66]

B = [0]

C = [0]

D = [1]

Now, let's solve the system using the initial conditions. We'll differentiate both sides of the second equation with respect to t:

y' = C*x + D*y

y'' = C*x' + D*y'

Substituting the values of C, x', and y' from the first equation, we have:

y'' = 0*x + 1*y' = y'

Now, we have a second-order ordinary differential equation for y(t):

y'' - y' = 0

This is a homogeneous linear differential equation with constant coefficients. The characteristic equation is:

r^2 - r = 0

Factoring the equation, we have:

r(r - 1) = 0

So, the solutions for r are r = 0 and r = 1.

Therefore, the general solution for y(t) is:

y(t) = c1*e^0 + c2*e^t

y(t) = c1 + c2*e^t

Now, let's solve for c1 and c2 using the initial conditions:

At t = 0, y(0) = -5:

-5 = c1 + c2*e^0

-5 = c1 + c2

At t = 0, y'(0) = 17:

17 = c2*e^0

17 = c2

From the second equation, we find that c2 = 17. Substituting this into the first equation, we get:

-5 = c1 + 17

c1 = -22

So, the particular solution for y(t) is:

y(t) = -22 + 17*e^t

Now, let's solve for x(t) using the first equation:

Jx' = A*x + B*y

Substituting the values of J, A, B, and y(t), we have:

[-67 -210] * x' = [21 66] * x + [0] * (-22 + 17*e^t)

[-67 -210] * x' = [21 66] * x - [0]

[-67 -210] * x' = [21 66] * x

Now, let's solve this system of linear equations for x(t). However, we can see that the second equation is a multiple of the first equation, so it doesn't provide any new information. Therefore, we can ignore the second equation.

Simplifying the first equation, we have:

-67 * x' - 210 * x' = 21 * x

Combining like terms:

-277 * x' = 21 * x

Dividing both sides by -277:

x' = -21/277 * x

Integrating both sides with respect to t:

∫(1/x) dx = ∫(-21/277) dt

ln|x| = (-21/277) * t + C

Taking the exponential of both sides:

|x| = e^((-21/277) * t + C)

Since x can be positive or negative, we have two cases:

Case 1: x > 0

x = e^((-21/277) * t + C)

Case 2: x < 0

x = -e^((-21/277) * t + C)

Therefore, the solution to the

given system of differential equations is:

x(t) = C1 * e^((-21/277) * t) for x > 0

x(t) = -C2 * e^((-21/277) * t) for x < 0

y(t) = -22 + 17 * e^t

where C1 and C2 are constants determined by additional initial conditions or boundary conditions.

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The value of the third side of the triangle, that is x is 24.

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

The given triangle is a right- angles triangle.

Use the Pythagorean theorem to find the third side of the triangle.

The Pythagorean theorem is given by the following formula:

a^2 + b^2 = c^2

10^2 + b^2 = 26 ^2

100 + b^2 = 676

b^2 = 676 - 100

b^2 = 576

b = 24

Hence, the value of the third side of the triangle, that is x is 24.

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Answer:

\(\frac{0.5(-14 + 12.6)}{9.32 + (-7.92)} = \frac{-0.7}{1.4} = -0.5\)

Step-by-step explanation:

Answer:

Its B

Step-by-step explanation:

I checked it on EDGE 2020!

2 [4( 2³ + 5)] - 4²

2 [ 4 (8 + 5)] - 16

2 [ 4 ( 13)] - 16

2 [ 52 ] - 16

104 - 16

88

Mike comes to a stop 105.3 feet above sea level while trekking on a mountain. The vertical separation between Mike and the mountain's base is 101.5 feet .

Given that,

Mike comes to a stop 105.3 feet above sea level while trekking on a mountain. There are 3.8 feet of sea level below the mountain's base.

We have to find what is the vertical separation between Mike and the mountain's base.

The Mike comes to a stop 105.3 feet above sea level while trekking on a mountain.

3.8 feet of sea level below the mountain's base.

We just have to do the difference of the above sea level feet and below sea level feet.

=105.3-3.8

=101.5

Therefore, the vertical separation between Mike and the mountain's base is 101.5 feet .

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Answer:

The large number is 31, and the small number is 16

Step-by-step explanation:

Given data

let the first number be x

and the second number be y

so

x+y= 47------------1

and

y-x= 15-------------2

from eqn1

x= 47-y

put this in eqn 2

y-(47-y)=15

y-47+y=15

2y= 15+47

2y=62

divide both side by 2

x= 62/2

x=31

From eqn 1

x+y= 47

31+y=47

y=47-31

y=16

Answer:

18/42 or 3/7

Step-by-step explanation:

Answer:

yes is is proportional

x=ydivided by 3.5

Step-by-step explanation:

Answer: multiplying by 3.5

Step-by-step explanation: because if you divide 7 by 2 you will 3.5

Answer:

The awnser to this equation is 120 cents

The cost of using a 200-watt television for 30 days, turned on for 2 hours per day, would be $1.20.  

To calculate the cost of using a 200-watt television for 30 days with 2 hours of daily usage at 10 cents per kilowatt-hour, we need to find the total energy consumption and then multiply it by the cost per kilowatt-hour.

First, let's find the total energy consumption:

1. Daily energy usage: 200 watts * 2 hours = 400 watt-hours
2. Monthly energy usage: 400 watt-hours * 30 days = 12,000 watt-hours

Now, we need to convert watt-hours to kilowatt-hours:
3. Monthly energy usage in kilowatt-hours: 12,000 watt-hours / 1,000 = 12 kWh

Finally, let's calculate the cost:
4. Cost of using the television for 30 days: 12 kWh * 10 cents per kWh = 120 cents

So, the cost of using a 200-watt television for 30 days with 2 hours of daily usage at 10 cents per kilowatt-hour is 120 cents.

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