What phenomenon is exhibited by an element P37 17 and P35 17​

Explanation:

the electrostatic force is decreased by a factor of four (2 raised to the second power).

A. The hydronium ion concentration, [H₃O⁺] of the solution is 4.57×10⁻⁸ M

B. The hydroxide ion concentration, [OH⁻] of the solution is 1.28×10⁻⁶ M

C. The hydroxide ion concentration, [OH⁻] of the solution is 1.80×10⁻¹¹ M

We can determine the [H₃O⁺] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

[H₃O⁺] × 2.19×10⁻⁷ = 10¯¹⁴

Divide both side by 2.19×10⁻⁷

[H₃O⁺] = 10¯¹⁴ / 2.19×10⁻⁷

[H₃O⁺] = 4.57×10⁻⁸ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

7.81×10⁻⁹ × [OH⁻] = 10¯¹⁴

Divide both side by 7.81×10⁻⁹

[OH⁻] = 10¯¹⁴ / 7.81×10⁻⁹

[OH⁻] = 1.28×10⁻⁶ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

5.57×10⁻⁴ × [OH⁻] = 10¯¹⁴

Divide both side by 5.57×10⁻⁴

[OH⁻] = 10¯¹⁴ / 5.57×10⁻⁴

[OH⁻] = 1.80×10⁻¹¹ M

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The arrow in a chemical reaction can be translated as the following:

A. yields

C. react to form

Answer:

A

Explanation:

I took the quiz

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

From the question we have

\(volume = \frac{244}{2.7} \\ = 90.370370...\)

We have the final answer as

Hope this helps you

Answer:

The total volume of water is 222 ml.

Explanation:

Given that,

Volume of water by  different devices are,

First large cylinder =164 ml

Second small cylinder = 39.7 ml

Third calibrated burette = 18.16 ml

We need to calculate the total volume of water

Using given data

volume of total water=volume by large cylinder+volume by small cylinder+volume by calibrated burette

Put the value into the formula

\(V_{w}=164+39.7+18.16\)

\(V_{w}=221.8\approx 222\ ml\)

Hence, The total volume of water is 222 ml.

Answer:

She will have an active imagination.

Explanation:

I took the test and i got 90%

But this one is right, hope this helps ( :

Answer:

a

Explanation:

give the person above me brainlest :)

At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.

If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.

When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.

If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.

Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.

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Answer:C

Explanation:I took the test

Answer:

It is a south pole because the field lines enter the magnet at this end.

Explanation:

KCN is potassium cyanide, and NaBrO2 is sodium bromide, strontium hydroxide (SrOH), iron carbonate (Fe2CO3)3, and chromium nitrate (CrNO3)3.

Ammonium NH4+ and sulfate SO42- are the two polyatomic ions that make up the ionic compound Ammonium Sulfate. To balance the sulfate ions, Ammonium Sulfate (NH4)2SO4 is produced by removing one electron from ammonium. Two NH4+ particles and one SO4 2-particle is found in every atom of ammonium sulfate.

Monosodium phosphate, monosodium dihydrogen orthophosphate, and monosodium phosphate are the three types of sodium phosphate. Formula Linear: NaH2PO4.

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Answer:

Because i want to. would be the reply

Explanation:

VOTE ME BRAINLIEST PLSSSSSSSSS

Answer:

none of the above

option d

Answer:

true

Explanation:

Answer: A

Explanation:

Answer:

Search it up. It says it on this link:

Answer:

Leaches aluminum from the soil.

Explanation:

A weak acid (or base) and its corresponding conjugate base (or acid) make up a buffer solution. If only a modest amount of base or acid is supplied, it can withstand pH fluctuations. pH of the solution is 3.48 .

Thus, The Henderson-Hasselbalch equation can be used to express the pH of a buffer solution.

The pH scale gauges a substance's acidity or basicity. The pH scale has numbers 0 through 14. Seven is the neutral pH. Acidic conditions have a pH under 7. More than 7 pH is considered basic.

Each whole pH number below 7 is ten times more acidic than the next higher value since the pH scale is logarithmic. For instance, pH 4 is 100 times (10 times 10) more acidic than pH 6, while pH 5 is ten times (10 times) more acidic than pH 4.

Thus, A weak acid (or base) and its corresponding conjugate base (or acid) make up a buffer solution. If only a modest amount of base or acid is supplied, it can withstand pH fluctuations. pH of the solution is 3.48 .

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Answer:

Haematology is the specialty important for the diagnosis and management of a wide range of benign and malignant disorders of the red and white blood cells, platelets and the coagulation system in adults and children.

Answer:

8 atoms

Explanation:

2N^4 = 8 atoms because 4 atoms per molecule and two molecules would be 8 atoms total.

Paper used as a writing material is made of pulp (wood).

Paper is a sheet material used for writing on or printing on (or as a non-waterproof container), usually made by draining cellulose fibres from a suspension in water.

Paper is made from cellulose found in trees, which are the main source of cellulose fibre (or woodpulp). Besides woodpulp, paper can be made from other materials such as cotton, flax, esparto, straw, hemp, manilla and jute.

Wood pulp is usually a softwood, used for pulping to make paper.

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Answer:

Approximately \(21\; \rm g\).

Explanation:

\(\rm H_2SO_4\) (a diprotic acid) reacts with \(\rm NaOH\) (a monoprotic base) at a one-to-two ratio:

\(\rm 2\; NaOH\, (s) + H_2SO_4\, (aq) \to Na_2SO_4\; (aq) + 2\; H_2O\, (l)\).

In other words, if \(n(\mathrm{NaOH})\) and \(n(\mathrm{H_2SO_4})\) represent the number of moles of the two compounds reacted, then:

\(\displaystyle \frac{n(\mathrm{H_2SO_4})}{n(\mathrm{NaOH})} = \frac{1}{2}\).

Look up the relative atomic mass data on a modern periodic table:

Calculate the (molar) formula mass of \(\rm H_2SO_4\) and \(\rm NaOH\):

\(M(\mathrm{H_2SO_4}) = 2 \times 1.008 + 32.06 + 4 \times 15.999 = 98.072\; \rm g \cdot mol^{-1}\).

\(M(\mathrm{NaOH}) = 22.990 + 15.999 + 1.008 = 39.997\; \rm g \cdot mol^{-1}\).

Calculate the number of moles of formula units in that \(33.8\; \rm g\) of \(\rm NaOH\):

\(\begin{aligned}n(\mathrm{NaOH}) &= \frac{m(\mathrm{NaOH})}{M(\mathrm{NaOH})} \\ &= \frac{33.8\; \rm g}{39.997\; \rm g \cdot mol^{-1}} \approx 0.845\; \rm mol\end{aligned}\).

Apply the ratio \(\displaystyle \frac{n(\mathrm{H_2SO_4})}{n(\mathrm{NaOH})} = \frac{1}{2}\) to find the (maximum) number of moles of \(\rm H_2SO_4\) that would react with the \(33.8\; \rm g\) of \(\rm NaOH\):

\(\begin{aligned}n(\mathrm{H_2SO_4}) &= \frac{n(\mathrm{H_2SO_4})}{n(\mathrm{NaOH})} \cdot n(\mathrm{NaOH})\\ &= \frac{1}{2} \times 0.845 \approx 0.4225\; \rm mol\end{aligned}\).

Calculate the mass of that \(0.4225\; \rm mol\) of \(\rm H_2SO_4\):

\(\begin{aligned}m(\mathrm{H_2SO_4}) &= n(\mathrm{H_2SO_4}) \cdot M(\mathrm{H_2SO_4})\\ &= 0.4225 \; \rm mol \times 98.072\; \rm g \cdot mol^{-1} \approx 41.435\; \rm g \end{aligned}\).

When the maximum amount of \(\rm H_2SO_4\) is reacted, the minimum would be in excess. Hence, the minimum mass of

\(62\; \rm g - 41.435\; \rm g \approx 21\; \rm g\) (rounded to two significant figures.)

Given that:

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

\(\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}\)

where;

P1 and P2 correspond to the temperature at T1 and T2.

∴

replacing the values into the given equation, we have;

\(\mathbf{In \dfrac{P_2}{1\ atm} = -\dfrac{22440 \ J/mol}{8.314 \ J/mol.K}(\dfrac{1}{251 \ K} - \dfrac{1}{272.6 \ K})}\)

\(\mathbf{In \dfrac{P_2}{1\ atm} =-(0.852053785)}\)

\(\mathbf{P_2=0.427 \ atm}\)

As such, at -22° C; the vapor pressure = 0.427 atm

Now, using the ideal gas equation:

PV = nRT

where:

∴

Making (n) the subject of the formula:

\(\mathbf{n = \dfrac{PV}{RT}}\)

\(\mathbf{n = \dfrac{0.427 atm \times 0.250 L}{(0.08206 \ L.atm/k.mol) \times 251}}\)

\(\mathbf{n =0.00518 mol}\)

We all know that the standard molecular weight of butane = 58.12 g/mol

∴

Using the relation for the number of moles which is:

\(\mathbf{number \ of \ moles = \dfrac{mass}{molar mass}}\)

mass = 0.00518 mole × 58.12 g/mol

mass = 0.301 g

∴

The mass of butane in the flask = 0.301 g

But the mass of the butane present as a liquid in the flask is

= 0.8 g - 0.301 g

= 0.499 g

In conclusion, the mass of the butane present as a liquid in the flask is 0.499 g

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Answer:

7

Explanation:

The chemical formula for x and y is Cu₂O and CuO. The mass cooper which can react with 0.5g of oxygen to yield x and y is 2.745 g.

A chemical formula is a phrase that lists the constituent parts of a compound together with their relative quantities. No subscript is used if there is just one atom of a certain kind. A subscript is added to the symbol of an atom if it contains two or more of a certain type of atom.

1. 1.535 g of X → 1.365 g of Copper

1.535 – 1.365 = 0.170g of Oxygen

Atomic weight of Cu = 63.5,

Atomic weight of Oxygen = 16

For Cu 1.365 g / 63.5 = 0.02 mol

For Oxygen 0.170 g / 16 = 0.01 mol

X = Cu₂O

1.450 g of Y → 1.160 g of Cu

1.450 – 1.160 = 0.290 g of Oxygen

For Cu = 1.160 g / 63.5 = 0.018 mol

For Oxygen = 0.290 g / 16 = 0.018 mol

Y = CuO

2. The total mass of Oxygen = 0,170 g + 0,290 g

= 0.460 g

Total mass of Cu = 1.160 g + 1. 365 g

= 2.525 g

0.460 g of Oxygen → 2.525 g of Cu

0.500 g of Oxygen → (2.525 x 0.5) / 0.460

= 2.745 g of Cu

Thus, The law of multiple proportions was formulated by John Dalton in 1804.

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When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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The compound that acts as the precipitate in this reaction is Pbl₂, or lead(II) iodide.

In the given reaction equation:

KI + Pb(NO3)2 → KNO3 + Pbl₂

The precipitate formed is Pbl₂, which is lead(II) iodide. In the reaction, potassium iodide (KI) reacts with lead(II) nitrate (Pb(NO3)2) to form potassium nitrate (KNO3) and lead(II) iodide (Pbl₂).

Lead(II) iodide is insoluble in water, as mentioned in the statement. When the two chemicals are mixed, lead(II) iodide is formed as a solid precipitate, which appears as a golden substance, as described.

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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Answer:

Q1 D

Explanation:

Q2 C

Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:

M = n/V

Where:

n = number of moles, 1.7 moles

V = volume in Liters, 2.8 Liters

Now we add these values into the formula:

M = 1.7/2.8

M = 0.61

The Molarity is 0.61 M