When a heat source is removed, the convection currents that were driven by the heat source will gradually weaken and eventually stop. Convection currents occur when a fluid or gas is heated, causing it to expand and become less dense.
The less dense, warm fluid rises while the cooler, denser fluid sinks, creating a circular flow pattern. When the heat source is removed, the fluid or gas will start to cool down. As it cools, its density increases, causing it to become denser than the surrounding fluid or gas. This denser fluid will sink, displacing the warmer fluid that was previously rising. As this process continues, the temperature difference between the fluid layers decreases, resulting in a decrease in the strength of convection currents. Over time, without a heat source to sustain the temperature difference, the fluid or gas will reach thermal equilibrium, where the temperature is uniform throughout. At this point, convection currents will cease entirely, and the fluid or gas will remain still. It's worth noting that the exact behavior of convection currents after the heat source is removed can depend on various factors, such as the specific properties of the fluid or gas, the initial temperature difference, and the presence of other external influences like gravity or external cooling. However, in general, the absence of a heat source will lead to the dissipation and eventual cessation of convection currents.
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Introduction This section describes the principles and concepts related to the experiment. It is used to help the person reading your report to understand the information that serves as foundation for the experiment. It also includes a brief statement about the purpose of the lab. Example: Surface tension is the attractive force exerted upon the surface molecules of a liquid by the molecules beneath. Water has a high surface tension because there are strong attractive forces between water molecules. Adding surfactants, like soap, can reduce the surface tension of a liquid. The purpose of the experiment was to determine the effect of soap on the surface tension of water.
Answer:
See explanation
Explanation:
It is a common observation that when water drops on a clean glass surface, it appears as little bags of water.
Surface tension makes water surface act like a stretched elastic skin bag.
Surface tension is caused by attractive forces between the molecules at the surface and the molecules in the bulk of a liquid. Remember that the forces of cohesion between water molecules are very strong.
When surfactants such as soap are added to water, the surface tension of water is decreased, hence the experiment.
Which of these terms means an object's resistance to changing its motion?
Question 1 options:
inertia
velocity
newton
power
Question 2 (1 point)
Which of these equations is a representation of the 2nd Law of Motion?
Question 2 options:
v=d/t
W=Fd
F=ma
a=v/t
Question 3 (1 point)
Which words correctly complete the 3rd Law of Motion?
For every ___________ there is an equal and opposite ___________.
Question 3 options:
cause, effect
action, reaction
distance, velocity
cost, benefit
Question 4 (1 point)
Which of these could be a force that changes the motion of an object?
Question 4 options:
friction
a push or pull
air resistance
all of the above
Question 5 (1 point)
According to the second law of motion, which statement is TRUE?
Question 5 options:
every action has a reaction
a heavy object requires more force to push than a lighter object
an object at rest, stays at rest
heavy objects accelerate faster than lighter elements with the same force
Answer:
Inertia
F=ma
Action, reaction
All of the above
A heavy object requires more force to push than a lighter object.
Superman does an exhibition run at a track meet. When he runs the 200 m
dash, he accelerates at 10 m/s/s for the entire distance. Approximately
how much time will it take him to run the 200 m? *
Answer:
6.32s
Explanation:
Given parameters:
Length of track and distance covered = 200m
Acceleration = 10m/s²
Unknown:
Time taken to cover the track = ?
Solution:
To solve this problem, we apply one of the motion equations as shown below:
S = ut + \(\frac{1}{2}\) at²
S is the distance covered
t is the time taken
a the acceleration
u is the initial velocity
The initial velocity of Superman is 0;
So;
S = \(\frac{1}{2}\) at²
200 = \(\frac{1}{2}\) x 10 x t²
200 = 5t²
t² = 40
t = 6.32s
A star of apparent magnitude +1 appears _____ than a star of apparent
magnitude +2.
O fainter
O farther away
o either brighter or fainter, depending on the distance to the stars
O brighter
A star of the apparent magnitude of +1 would appear farther away than a star of the apparent magnitude of +2. Hence, option B is correct.
What is a star?In astronomy, a star is a brilliant plasma spheroid that is held together through gravity. The Sun is the planet's closest star. The human eye can see a great number of other stars at night, but due to our planet's size, they seem alike stationary points of light.
Numerous of the shining stars were given names, whereas the most notable stars have been grouped into constellations and asterisms. The known stars have been recognized and given standard designations in star inventories that astronomers have put together.
The birth of a star is caused by the gravitational attraction of a gaseous nebula made largely of hydrogen, helium, and traces of transition metals. Its overall mass is the primary factor influencing how it will develop and end up.
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a planet of mass =7.15×1024 kg orbits a star of mass =1.95×1029 kg in a circular path. the radius of the orbit is =5.95×107 km. what is the orbital period planet of the planet in earth days?
The angular frequency obtained is 3.76 × 10⁻⁷ rad/sec. The orbital period planet of the planet in Earth days is 193.51 days.
Given data:
Mass of the planet (m) = 7.15 × 10²⁴ kg
Mass of the star (M) = 1.95 × 10²⁹ kg
Radius of the orbit (r) = 5.95 × 10⁷ km
Orbital period is given by T = (2π) ÷ ω
we know that,
(GMm) ÷ (R)² = mω²R
ω = √(GM) ÷ R³
On substituting the value:
ω = 3.76 × 10⁻⁷ rad/sec
The time period is:
T = (2π) ÷ 3.76 × 10⁻⁷
T = 16719389.62 sec
Hence on converting from seconds to days the time period obtained is:
T = 193.51 days.
Therefore, The orbital period planet of the planet in Earth days is 193.51 days.
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your weight is the result of a gravitational force of the earth on your body. what is the corresponding reaction force?
Your body is pulling on the Earth with the same reaction force that the Earth is pulling on you.
What is gravitational force?The gravitational force, which is what pushes mass-containing objects toward one another. We frequently consider the pull of gravity from the Earth. Your body is kept on the ground by this force. However, all mass-bearing objects are pulled toward one another by gravity.
What is reaction force?An action force with an opposite direction has an effect called a reaction force. These two forces—also referred to as action and reaction forces—are covered by Newton's third law of motion. According to Newton's third law, there is an equal and opposite reaction to every action.
What is weight?The gravitational force that pulls a body toward the earth or another celestial body; it is equal to the mass times the acceleration due to local gravity.
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what would be the acceleration in a body moving with uniform velocity and why
Answer:
If a body is moving with uniform velocity, acceleration is zero. So net force acting on it will be also zero. But the body has energy due to its constant motion.
Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segundo. Que forma un campo magnético de 0.8 Teslas. Recuerda que la carga de un electrón es de 1.602 X 10 a la menos 19 [Coulombs]
Answer:
La fuerza magnética del electrón es 6.41x10⁻¹³ N.
Explanation:
Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:
\( F = qv\times B \)
En donde:
q: es la carga del electrón = 1.602x10⁻¹⁹ C
v: es la velocidad del electrón = 5x10⁶ m/s
B: es el campo magnético = 0.8 T
\( F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N \)
Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.
Espero que te sea de utilidad!
Write down the names of three mar-made devices in everyday use that depend,
for their action, upon the moments of forces.
Answer:
Scissors
Tap
Spanner
Explanation:
Dennis the Menace is shooting a rock with his slingshot with an initial height of 5 feet. The height in feet, of the rock above the ground is given by s(t)=-16t^2+44t+5, where t is time in seconds and t is >= 0. At what time will the rock be 15 ft above the ground?
Answer: 32
The average velocity of the rock would be 32 ft per second.
The rock will be 15ft above the ground 0.25 and 2.5secs after
The height of the rock above the ground is expressed according to the expression \(s(t)=-16t^2+44t+5\)
In order to get the time the rock will be 15ft above the ground, we will substitute s(t) = 15 ft into the formula above;
\(15= -16t^2+44t+5\\-16t^2+44t = 15 -5\\-16t^2+44t = 10\\-16t^2+44t- 10 = 0\\16t^2-44t+10=0\)
Factorize the expression to get the value of "t"
2(4t−1)(2t−5) = 0
4t - 1 = 0
4t = 1
t = 0.25secs
Similarly 2t - 5 =0
2t = 5
t = 5/2 = 2.5secs
This shows that the rock will be 15ft above the ground 0.25 and 2.5secs after
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A 51 cm diameter wheel accelerates uniformly about its center from 150 rpm to 290 rpm in 4.0 s. (A)Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.1 s after it has started accelerating.
Radial component of the linear acceleration = 99.47 m/s^2
Explanations:The diameter of the wheel, d = 51 cm
The radius, r = d/2 = 51/2 = 25.5 cm
r = 25.5/100 = 0.255 m
r = 0.255 m
\(\begin{gathered} N_{i\text{ }}=\text{ 150 rpm} \\ w_i=\text{ 150}\times\frac{2\pi}{60} \\ w_i=\text{ }15.71\text{ rad/s} \end{gathered}\)\(\begin{gathered} N_f=\text{ 290 rpm} \\ w_f=\text{ 290}\times\frac{2\pi}{60} \\ w_f=\text{ }30.37\text{ rad/s} \end{gathered}\)\(\begin{gathered} w_f=w_i+\alpha t \\ 30.37=15.71+4\alpha \\ 4\alpha=30.37-15.71 \\ 4\alpha=\text{ }14.66 \\ \alpha=\frac{14.66}{4} \\ \alpha\text{ = }3.67rad/s^2 \end{gathered}\)At t = 1.1, first calculate the new angular velocity
\(\begin{gathered} w=w_1+\alpha t \\ w\text{ = 15.71+3.67(1.1)} \\ w\text{ = 15.71+}4.04 \\ w\text{ = }19.75\text{ rad/s} \end{gathered}\)The radial component of the linear acceleration is given as:
\(\begin{gathered} a_r=w^2r \\ a_r=19.75^2\times0.255 \\ a_r=\text{ }99.47\text{ m/}s^2 \end{gathered}\)4. A desk with a mass of 10 kg is pushed across a floor with an acceleration of 4 m/s?. What
is the force on the desk? Use the equation F = ma.
Answer:
Below
Explanation:
All we need to do for this question is to plug in our values and solve!
Force = mass x acceleration
Force = 10 kg x 4 m/s^2
Force = 40 Newtons or 40 N
If your teacher requires you to round to sig figs it would be :
F = 4 x 10^1 N
Hope this helps!
Comparing capacitors Four parallel-plate capacitors are constructed using square plates, and each has a dielectric inserted between the plates. Rank the capacitance of each capacitor in order from highest to lowest.
The ranks are:
Capacitor C: side length 2l, distance between plates d, dielectric constant 2K. > Capacitor B: side length 1/2, distance between plates d/2, dielectric constant 4K. > Capacitor A: side length l, distance between plates d, dielectric constant K. = Capacitor D: side length l, distance between plates 2d, dielectric constant 2K.
Capacitor working principleThe structure of a capacitor is made of 2 metal plates separated by a dielectric material.
If both ends of the metal plate are given an electric voltage, positive charges will collect on one of the metal legs (electrodes) and at the same time negative charges collect on the other end of the metal.
Positive charge cannot flow towards the end of the negative pole and vice versa negative charge cannot go to the end of the positive pole, because it is separated by a non-conductive dielectric material.
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thế nào là gương cầu lồi
Answer:
I know I am a very good answerable teacher but I can't answer this question I don't know what
Remy wonders if the height of the mountain has anything to do with the eventual size of the tsunami wave. How should Remy test this? A. Cause avalanches on several different mountains and see how large each resulting tsunami is. B. Build different-sized model mountains at the edge of a pool, pour sand down the side of each mountain, and see how large each resulting wave is. C. Pour different amounts of sand down the side of a model mountain into a pool and see how large each resulting wave is. D. Build a model town at the edge of a pool and see how large waves must be to cause damage to the buildings.
Answer:
The answer is B
Explanation:
I got this from study island
A 7.12 μC charge is moving at the speed of light in a magnetic field of 4.02 mT. What is the force on the charge?
Answer:
858.7 N
Explanation:
The magnetic force on the charge F = Bqv where B = magnetic field strength = 4.02 mT = 4.02 × 10⁻³ T, q = charge = 7.12 μC = 7.12 × 10⁻⁶ C and v = c = speed of light = 3 × 10⁸ m/s
F = Bqc
= 4.02 × 10⁻³ T × 7.12 × 10⁻⁶ C × 3 × 10⁸ m/s
= 858.7 N
what kind of mirror do u think s used in the side-view mirror of cars?
Answer:
The Convex Mirror is used.
Explanation:
The midrange gain of an amplifier is 600 mW. What is the power gain if the gain falls by 3 dB? A 235.4 mW B 300 mw C 119.7 mW D 244.2 mW
The power gain when the gain falls by 3 dB is approximately 300.7 mW, which is closest to option D: 244.2 mW.
The power gain of an amplifier can be calculated using the formula:
Power Gain (dB) = 10 * log10(Pout / Pin)
where Pout is the output power and Pin is the input power. In this case, the midrange gain of the amplifier is given as 600 mW.
To calculate the power gain when the gain falls by 3 dB, we need to find the new output power. Since the gain is decreasing, the new output power will be lower than the initial power.
First, we convert the midrange gain from milliwatts to watts:
Midrange Gain = 600 mW = 0.6 W
Next, we use the formula:
Pout / Pin = 10^(Power Gain / 10)
Since the gain falls by 3 dB, the new power gain is:
Power Gain = -3 dB
Now we substitute the values into the formula:
Pout / Pin = 10^(-3 / 10)
Pout / Pin = 10^(-0.3)
Pout / Pin = 0.5012
To find the new output power (Pout), we multiply the input power (Pin) by the ratio:
Pout = Pin * 0.5012
Pout = 0.6 W * 0.5012
Pout = 0.3007 W
Finally, we convert the output power back to milliwatts:
Pout = 0.3007 W = 300.7 mW
Therefore, the power gain when the gain falls by 3 dB is approximately 300.7 mW, which is closest to option D: 244.2 mW.
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A 5.0-kg block suspended from a spring scale is slowly lowered onto a vertical spring (Figure 1) .
Part A
What does the scale read before the block touches the vertical spring?
Part B
If the scale reads 34N when the bottom spring is compressed 30 mm, what is k for the bottom spring?
Part C
How far does the block compress the bottom spring when the scale reads 0?
Express your answer with the appropriate units. Enter positive value if the spring is stretched and negative value if the spring is compressed.
A 5.0-kg block suspended from a spring scale is slowly lowered onto a vertical spring
Part A: The scale reads 49.05 N before the block touches the vertical spring.
Part B: If the scale reads 34N when the bottom spring is compressed 30 mm, k for the bottom spring is 500 N/m.
Part C: The block compresses the bottom spring by 0.0981 m (or 98.1 mm) when the scale reads 0.
Part A:
Before the block touches the vertical spring, the only force acting on it is gravity. To find the scale reading, we can use the weight formula:
Weight = mass × gravity
Weight = 5.0 kg × 9.81 m/s²
Weight = 49.05 N
The scale reads 49.05 N before the block touches the vertical spring.
Part B:
To find the spring constant (k) for the bottom spring, we can use Hooke's Law:
F = k × Δx
The force applied on the spring is the difference between the weight of the block and the scale reading:
Force = Weight - Scale reading
Force = 49.05 N - 34 N
Force = 15 N
The compression distance (Δx) is given as 30 mm, which is equivalent to 0.03 m.
Now we can find k:
15 N = k × 0.03 m
k = 15 N / 0.03 m
k = 500 N/m
The spring constant (k) for the bottom spring is 500 N/m.
Part C:
When the scale reads 0, the force applied by the spring is equal to the weight of the block. We can use Hooke's Law again:
F = k × Δx
Substitute the values we know:
49.05 N = 500 N/m × Δx
Δx = 49.05 N / 500 N/m
Δx = 0.0981 m
The block compresses the bottom spring by 0.0981 m (or 98.1 mm) when the scale reads 0.
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a river 100 m wide flows due south at 1 m/s, a boat that goes 1 m/s relative to the water is pointed due east as it crosses from the west bank - the boat reaches the east bank
A river 100 m wide flows due south at 1 m/s, a boat that goes 1 m/s relative to the water .The resultant distance will be 141m.
Option A is correct.
The sum of an object's individual vector velocities is its final velocity. The scalar product of an object's mass and its acceleration vector is equal to the sum of its vector forces.
Elaborating:Considering that the boat travels in a river that flows 1 m/s due south at a speed of 1 m/s due east.
The positive x and y axes should be represented by the north and east, respectively.
After that, we can convert the boat's resulting velocity into a vector.
Vr = i - j ( 1 m/s on x axis and -1m/s on y axis)
The time required to travel 100m from west to east at a speed of 1m/s is;
Time t = distance/speed = 100m/1m/s = 100s
Distance = velocity × time = (i - j) × 100 = 100i - 100j
Distance = 100i - 100j (in vector form)
Magnitude of the Resultant distance can be given as:
dr = √(dx ²+ dy²)
dr = √(100² + 100²)
dr = √(20000)
dr = 141.42m
dr = 141m
What are relative and resultant velocity?The relative velocity refers to how one observer would perceive another moving object within their own frame. The velocity of an object when there are multiple influences on its motion in a fixed reference frame is known as the resultant velocity.
How is the boat's resulting velocity determined?At the point when an item, say, a boat, goes at a specific speed, and the medium through which it voyages, say, a stream, has its own speed, we can track down the resultant speed of the item by adding the two speeds. We find the boat's resulting velocity vector in this example.
Incomplete question:
A river 100 m wide flows 1 m/s due south. A boat that travels 1 m/s relative to the water is pointed due east as it crosses from the west bank. Relative to its starting point, the boat travels
A) 141 m.
B) 100 m.
C) 200 m.
D) more than 200 m.
E) nowhere
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1. When the speed of your car is doubled, by what factor does its kinetic energy increase?
(a.) 2
(b) 2.
(c) 4.
(c) 8.
The new kinetic energy (KE') is twice the οriginal kinetic energy (KE), which means it increases by a factοr οf 2. Therefοre, οptiοn (a) is cοrrect.
How to find the new kinetic energy?When the speed οf a car is dοubled, the kinetic energy increases by a factοr οf 4.
The kinetic energy (KE) οf an οbject is given by the equatiοn:
KE = (1/2) × m × v²
where m is the mass οf the οbject and v is its velοcity (speed).
When the speed is dοubled, the new velοcity becοmes 2v. Substituting this intο the kinetic energy equatiοn:
KE' = (1/2) × m × (2v)²
= (1/2) × m × 4v²
= 2× * (1/2) × m × v²
= 2 × KE
The new kinetic energy (KE') is twice the οriginal kinetic energy (KE), which means it increases by a factοr οf 2. Therefοre, οptiοn (a) is cοrrect.
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1) An astronaut has a mass of 40Kg. Calculate his weight on earth if Gravity (g) = 10m/s^2.
2) The same astronaut goes to the International Space Station. Here the gravitational pull is equal to .5 m/s^2. Calculate his weight.
3) Our astronaut friend is assigned to study a neutron star. He travels to the surface using a special suit. Here the gravitational force is terrible at 150m/s^2 What is the astronaut’s weight?
Answer:
The formula is W=mg.
1.) W=40×10=400.
2.)W=40×5=200.
3.)W=40×150=6000.
Two people try to lift a heavy box. Jack pulls upward with a 100-newton
force. Jill pulls upward with a 50-newton force, but neither person moves the
box.
Compare the amount of work done on the box by Jack and Jill.
OA) Jack did twice as much work as Jill.
OB) Jack did fifty times more work than Jill.
OC) Jack and Jill did the same amount of work.
Answer:
A ( Jack did twice as much work as Jill
Explanation:
It takes 6s for a stone to fall from the top of a building to the ground calculate i.the height of the building ii.the speed of the stone just before it strikes the ground (g=10ms^-2
Answer:
fffffff
Explanation:
30. Determine the momentum of a system that consists of two objects. One object, mi, has a mass of 6 kg and a velocity of 13 m/s in the direction of the positive x-axis and a second object, mz, has a mass of 14 kg and a velocity 7 m/s in the direction of the negative x-axis.
The momentum of the system is -20 kg*m/s in the negative x-axis direction.
What is momentum?
Momentum is a fundamental concept in physics that describes the motion of an object. It is a vector quantity, meaning it has both magnitude and direction. The momentum of an object is equal to its mass multiplied by its velocity, or p = mv. The direction of the momentum is the same as the direction of the velocity.
The momentum of a system can be determined by summing the momenta of the individual objects in the system. The momentum of an object is equal to its mass multiplied by its velocity. The direction of the momentum is the same as the direction of the velocity.
For the first object, the momentum is:
p1 = mi * vi
p1 = 6 kg * 13 m/s
p1 = 78 kg*m/s (in positive x-axis direction)
For the second object, the momentum is:
p2 = mz * vz
p2 = 14 kg * -7 m/s
p2 = -98 kg*m/s (in negative x-axis direction)
To find the total momentum of the system, we add the momenta of the two objects:
p_total = p1 + p2
p_total = 78 kgm/s + (-98 kgm/s)
p_total = -20 kg*m/s (in negative x-axis direction)
So the momentum of the system is -20 kg*m/s in the negative x-axis direction.
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Explain the conditions through which friction can be increased.
Answer:
Friction can be increased the longer two objects are rubbed together, since the longer they are rubbed is the more heat produced.
Explanation:
Answer:
walking, car moving
Explanation:
basically anything with two surfaces pressing together ig
an eagle flew for 3 hours at 115km/h and 5 hours at 136 km/h. how far did the eagle fly?
Answer:
1025meter
Explanation:Distance is speed times time.so 3hx115km/h=345km
5hx136km/h=680km
345km+680km=1025km
Answer:
1025
Explanation:
what is the wavelength (in nanometers) of gamma rays of frequency 6.52×1021 hz ? express your answer in nanometers.
We can use the equation c = λf, where c is the speed of light, λ is the wavelength, and f is the frequency. Therefore, the wavelength of these gamma rays is approximately 0.459 nanometers.
We can use the equation c = λf, where c is the speed of light, λ is the wavelength, and f is the frequency.
c = 299,792,458 m/s (speed of light)
f = 6.52 × 10^21 Hz (given frequency)
Solving for λ:
λ = c / f
λ = 299,792,458 m/s / 6.52 × 10^21 Hz
λ = 4.59 × 10^-14 m
To express the wavelength in nanometers, we can multiply by 10^9:
λ = 4.59 × 10^-14 m * 10^9 nm/m
λ ≈ 0.459 nm
Therefore, the wavelength of these gamma rays is approximately 0.459 nanometers.
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You are sharing a house with a few roommates. One of them plays on the basketball team, and is exactly 200 cm tall. The heights of you and the other roommates are 188 cm, 175 cm, and 160 cm. You want to buy the minimum height mirror that will allow all of you to see your entire selves, when the mirror is mounted in a fixed position on the wall. Assume each person's eyes are at a level 95% of their height. How tall a mirror should you buy
Answer:
119 cm
Explanation:
Given heights : 200cm , 188 cm , 175 cm, 160 cm
since the eyes are at 95% level
95% of 200 cm = 190 cm
95% of 160 cm = 152 cm
hence the allowable height of mirror = 200 - ( 5 + 76 ) = 119 cm
and The mirror should be hung 75cm from the floor
Fill in the table below with the properties of acids and bases.
Draw lines between the properties that are the same.
Answer:
1) Acids have a sour taste , Bases have a bitter taste.
2) Acids turn blue litmus paper into red , Bases turn red litmus paper into blue.
3) Acids react with most metals to form Hydrogen gas but only a few base react with a few metals to form Hydrogen gas
4) Both will conduct electricity. Both acids & bases are good electrolytes. Strong acids & bases conduct more electricity than that of weak acids & bases
Fill in the blanks with the properties of acids and bases as follows:
Taste: Acids generally have a sour taste while bases possess a bitter taste.Color change of litmus paper: Acids significantly transform the blue litmus paper into red while bases turn red litmus paper into blue.Reaction with metals to produce hydrogen gas: All acids react with metals in order to produce hydrogen gas while only some bases have this property. Electrical conductivity: Both acids and bases in an aqueous solution considerably conduct electricity. What are the properties of acids?The properties of acids are as follows:
Acids typically react with bases in order to produce salt and water.Acids react with metals to synthesize hydrogen gas.Acids transform the color of certain acid-base indicators.Acids generally have a sour taste. They are good conductors of electricity in an aqueous solution.Therefore, fill in the blanks with the properties of acids and bases are well described above.
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