When driving in fog, A. low beam headlights. B. Use high beam headlights for better visibility. C. Use your hour at 10 second intervals. D. Turn on the heat in your vehicle.(1 Point)

Taking into account the Boyle's law, the original pressure of a gas was 2.5 atmospheres and the original volume was 578 mL.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. This is because when the volume decreases, the distance that the particles have to travel is less and therefore more shocks occur in each unit of time, that is, the pressure increases.

Mathematically, if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:

P×V= k

where:

Being an initial state 1 and a final state 2, it is fulfilled:

P₁×V₁= P₂×V₂

In this case, you know:

Replacing in Boyle's law:

2.5 atm ×V₁= 1.7 atm ×850 mL

Solving:

V₁= (1.7 atm ×850 mL)÷ 2.5 atm

V₁= 578 mL

The original volume was 578 mL.

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The magnitude of the force of air resistance, in newtons, on a 55-kg skydiver assuming the force of air resistance is constant can be found using the following formula:

Fr = ma fr = Force of air resistance m = ma a = acceleration

In this case, the acceleration is the acceleration due to gravity which is 9.8 m/s².

To determine the acceleration in this case, we can use the following formula:

Vf² = Vi² + 2aswhere:Vf = final velocity (maximum speed)Vi = initial velocity (0 m/s)s = displacement (height)

Therefore,51² = 0² + 2(9.8)s490 = 9.8s

Simplifying490/9.8 = s50 = sSo the displacement of the skydiver is 50 m.

Thus, the acceleration is calculated as follows:

a = Δv/ΔtwhereΔv = 51 m/s - 0 m/s = 51 m/sΔt = time taken to fall 50 m using the acceleration due to gravity which is 9.8 m/s²Δt = √(2s/a)Δt = √(2(50)/9.8)Δt = 3.18 s So, a = Δv/Δta = 51/3.18a = 16 m/s²

To determine the force of air resistance, we can use the formula Fr = ma Fr = (55)(16)Fr = 880 N

Therefore, the magnitude of the force of air resistance, in newtons, on the skydiver is 880 N.

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One of the first explanations for the high redshifts of quasars was that they were ejected from galaxies at extremely high speeds. Since no quasars with significant blueshifts have been discovered, this hypothesis was dismissed.

It explains why quasars with both blue shifted lines should be expected if they were ejected from neighboring galaxies. By calculating the quasar's redshift, one can determine how big the universe was in comparison to how big it is now. The quasars were identified to have significant radio emission but the appearance of stars.

At first, their visible light looked perplexing, but astronomers soon discovered that they had significantly greater redshifts than stars. Redshifts for the quasars in the currently available spectra range from 15% to over 96% of the speed of light.

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The uncertainty in the position of the proton is 1.1 x 10⁻¹³ m.

The velocity of the proton is calculated as follows;

\(v = \frac{1}{10} \times 3\times 10^8 \ m/s = 3 \times 10^7 \ m/s\)

precision of the velocity, Δv = 0.01 x 3 x 10⁷ = 3 x 10⁵ m/s

The uncertainty in the position of the proton is calculated as follows;

\(\Delta xm\Delta v= \frac{h}{4\pi} \\\\\Delta x = \frac{h}{4\pi m\Delta v} \\\\\Delta x = \frac{6.67 \times 10^{-34} }{4\pi \times 1.67 \times 10^{-27} \times 3\times 10^5} \\\\\Delta x = 1.1 \times 10^{-13} \ m\)

Thus, the uncertainty in the position of the proton is 1.1 x 10⁻¹³ m.

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The SI base unit for the amount of substance is the mole. 1 mole is equal to 1 mole In, or 114.818 grams. Note that rounding errors may occur, so always check the results.

This is the theoretical atomic mass of the Carbon-12 isotope (6 protons and 6 neutrons). This means that the atomic mass or atomic weight (12 grams) of carbon is equal to exactly 1 mole of carbon.

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12, its symbol is “mol”.

One mole of any substance is equal to the value of 6.023 x 10^23 (Avagadro number). It can be used to measure the products obtained from the chemical reaction. The unit is denoted by mol. The formula for the number of moles formula is expressed as.

Number of Moles = Mass of substance / Mass of one mole.

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Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes.

In order to calculate the power expended by Peter and Samantha, we need to use the formula:

Power = Work / Time

where Work is the amount of energy expended and Time is the duration of the activity.

For Peter, the Work done is:

Work = 2,000 calories / 1 hour = 2,000 Joules

For Samantha, the Work done is:

Work = 1,000 calories / 30 minutes = 33.33 Joules

Therefore, Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes. So, Peter exerted the greatest amount of power.  

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The ball will travel more distance when projected or kicked at an angle of 35 degrees.

The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.

R = ( u² sin (2θ ) ) / g

where;

The horizontal distance traveled by the ball when projected at 35 degrees is calculated as;

R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )

R = 18.53 m

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Answer:3000km/h

Explanation:

speed=distance/time

216,000km/72hrs

=3000km/h

Well, first of all, if there are astronauts aboard that ship, I hope they don't try to climb out yet.  If they pointed straight at the moon and covered 216,000 km so far, they still have another 168,000 km to go before they get there.

Average Speed = (distance) / (time)

Speed = (216,000 km) / (72 hours)

Average Speed = 3,000 km/hr

also

Speed = (216,000 km) x (1000m/km) / (72 hr x 3600sec/hr)

Average Speed = 833.33 m/s

There's not enough information given to find the ship's velocity.

Answer:

44.1 m

Explanation:

If two populations live very far from each other and are geographically separated, they are different species.

The main effect is that groups will diverge from one another when they are geographically isolated, both in terms of physical appearance and genetic variation.

Reproductive isolation results from these alterations, which might be brought on by genetic drift or natural selection.

The process by which new species emerge is known as speciation. It happens when populations within a species separate and experience reproductive isolation. A period of geographic separation causes groups from an ancestral population to diverge into distinct species in allopatric speciation.

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Answer:

4.489 m/s

Explanation:

We are given;

Length of rod;L = 51.4 cm = 0.514 m

When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.

Thus; ½mv² = mgh

m will cancel out to give;

v² = 2gh

Where:

g is acceleration due to gravity = 9.8 m/s²

h is the maximum height of the ball which is equal to twice the length of the rod.

Thus, h = 2(0.514) = 1.028 m

v² = 2 × 9.8 × 1.028

v = √20.1488

v = 4.489 m/s

Most operate at altitudes ranging from a few hundred miles above the surface of the planet to as high as 25,000 miles. Each one of these Earth-observing satellites reveals a different piece of the puzzle.

A satellite, also known as an artificial satellite, is a spacecraft that has been put into orbit on purpose. With the exception of passive satellites, most satellites have a means of generating electricity for the equipment they carry, such as radioisotope thermoelectric generators or solar panels.

For a full view of the Earth's disc and to keep the satellites in their geostationary orbit, they are 22,300 miles above the planet's surface. In order to keep their geostationary orbit, geostationary satellites move at a speed of roughly 7000mph.

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a. The ring pushes on the rider with a force of 4.13 × 10^3 N at the top of the ride.

b. The ring pushes on the rider with a force of 5.81 × 10^3 N at the bottom of the ride.

c. The longest rotation period of the wheel that will prevent the riders from falling off at the top is 6.02 s.

A) At the top of the ride, the rider is in circular motion due to the normal force provided by the ring. The force of gravity acts downwards and the normal force acts upwards. The net force acting on the rider at the top is equal to the centripetal force required for circular motion.

The centripetal force is given by:

Fc = mv²/r

where m is the mass of the rider, v is the velocity of the rider in circular motion, and r is the radius of circular motion.

The velocity of the rider can be found from the period of rotation:

T = 2πr/v

v = 2πr/T

Substituting this expression for v into the expression for Fc, we get:

Fc = m(2πr/T)²/r = 4π²mr/T²

At the top of the ride, the normal force is equal to the centripetal force:

Fn = Fc = 4π²mr/T²

Substituting the given values, we get:

Fn = 4π²(59.0 kg)(9.81 m/s²)(9.00 m)/(4.40 s)² = 4.13 × 10³ N

B) At the bottom of the ride, the rider is still in circular motion due to the normal force provided by the ring. The force of gravity acts downwards and the normal force acts upwards. The net force acting on the rider at the bottom is equal to the sum of the centripetal force required for circular motion and the force of gravity:

Fnet = mv²/r + mg

where m is the mass of the rider, v is the velocity of the rider in circular motion, r is the radius of circular motion, and g is the acceleration due to gravity.

Using the same expressions for v and Fc as in part A, we can rewrite the above equation as:

Fnet = Fc + mg = 4π²mr/T² + mg

At the bottom of the ride, the normal force is equal to the net force:

Fn = Fnet = 4π²mr/T² + mg

Substituting the given values, we get:

Fn = 4π²(59.0 kg)(9.81 m/s²)(9.00 m)/(4.40 s)² + (59.0 kg)(9.81 m/s²) = 5.81 × 10³ N

C) The condition for the rider to not fall off at the top of the ride is that the centripetal force required for circular motion is greater than or equal to the force of gravity:

Fc ≥ mg

Substituting the expression for Fc from part A and solving for T, we get:

T ≤ 2π√(r/g)

Substituting the given values, we get:

T ≤ 2π√(9.00 m/9.81 m/s²) = 6.02 s

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Answer: The stratosphere and the troposphere are defined by the variation in temperature with height. Within a troposphere, the temperature drops as altitude increases, and drops fast enough for convection to occur. Whereas within a stratosphere, the temperature rises with increasing altitude. Features of the atmosphere change with altitude: density decreases, air pressure decreases, temperature changes vary. Different temperature gradients create different layers within the atmosphere. The lowest layer is the troposphere where most of the atmospheric gases and all of the planet's weather are located.

Explanation:

Answer:

See the explanation below.

Explanation:

To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass [kg]

a = acceleration [m/s²]

The mass of the tennis ball will always be the same therefore it will never change.

Now clearing a:

\(a=\frac{F}{m}\)

If the mass of the ball remains the same:

\(a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}\)

We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.

The critical angle of the transparent material is 35.3 degrees.

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:

sin(critical angle) = sin(90 degrees) / sin(angle of refraction)

sin(critical angle) = 1 / sin(32 degrees)

sin(critical angle) = 0.574

critical angle = arcsin(0.574)

critical angle = 35.3 degrees

Therefore, the critical angle of the transparent material is 35.3 degrees.

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The new magnitude of the electrostatic force will be 1/25th of the original force, or 0.2 N.

This is because the electrostatic force is inversely proportional to the square of the distance between the charges. Therefore, when the distance is quintupled, the force is reduced by a factor of 25.

The electrostatic force is a force of attraction or repulsion between electrically charged particles, such as electrons and protons. This force is caused by the exchange of photons between the particles, which creates an electric field around the particles.

The electrostatic force is an inverse-square law, meaning that the force decreases with increasing distance between the particles. The force can be attractive or repulsive, depending on the charge of the particles. Attractive forces exist between particles of opposite charge, while repulsive forces exist between particles of the same charge. The electrostatic force is one of the four fundamental forces of nature, along with gravitation, the weak force, and the strong force.

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Increase the frequency of the incident light. The photoelectric effect occurs when light of a sufficient frequency strikes a metal and frees electrons from the metal's surface. The energy of the incident photons must be greater than the energy required to remove the electrons, known as the work function. Thus, increasing the frequency of the incident light will result in higher energy photons, increasing the likelihood of electron ejection in the photoelectric effect.

The kinetic energy of the photoelectrons that are released will grow as the light amplitude increases, according to the wave model of light, yet the measured current will increase as the frequency increases. In contrast to expectations, studies revealed that raising the light's frequency and amplitude raised the current and the photoelectrons' kinetic energy, respectively.

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the magnitude of the magnetic field midway between the two wires is 5.0 × 10−5 T. Hence, option (B) is the correct answer.

Given data:

Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions.

The wires are separated by 0.20 m.The magnetic field midway between the two wires is to be determined.Formula used:

B = (μ₀ * I * i)/(2πd)

Where,B is the magnetic field at the midpoint between two wires,μ₀ is the permeability of free space, which is equal to 4π × 10−7 T∙

m/ I is the current in the first wire, and i is the current in the second wire.d is the separation between the two wires.

Substitute the given values into the above formula,

B = (μ₀ * I * i)/(2πd) = (4π × 10−7 T∙m/A * 20 A * 5 A)/(2π * 0.20 m) = 5.0 × 10−5 T

Therefore, the magnitude of the magnetic field midway between the two wires is 5.0 × 10−5 T. Hence, option (B) is the correct answer.

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Just the pull from the rope's tension acts horizontally on mass 1, functioning as the only force. In this case, T=m1*F/(m1+m2) represents the tension (again, the acceleration is the same because of the rope and the lack of friction, I think).

The blocks with masses of 1 kg and 2 kg lie on a rough horizontal surface and are joined by a spring. It is not strained to any degree. K=2 N/m represents the spring constant. Blocks and a horizontal surface interact with each other with a 0.5 coefficient of friction.

The masses shift in such a way that the string's length between P1 and P2 is parallel to the inclined plane.

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A. the relationship is T = -1840x + 212. B. the boiling point at an altitude of 3,500 feet is approximately 187.6°F. C. the altitude corresponding to a boiling point of 200°F is approximately 0.0065 thousands of feet. D. The point (3.5, 187.6) will represent the boiling point at an altitude of 3,500 feet, and the point (0.0065, 200) will represent the altitude corresponding to a boiling point of 200°F.

(A) To find the relationship of the form T = mx + b, we can use the two given data points: (0, 212) and (10, 193.6).

Let's first convert the altitude from feet to thousands of feet. So, the data points become (0, 212) and (10/1000, 193.6).

Using the slope-intercept form, we have:

T = mx + b

Substituting the values of the two points, we get two equations:

212 = m(0) + b

193.6 = m(10/1000) + b

From the first equation, we find that b = 212.

Substituting this value into the second equation, we have:

193.6 = m(10/1000) + 212

Simplifying, we get:

193.6 - 212 = m(10/1000)

-18.4 = 0.01m

Dividing both sides by 0.01, we get:

m = -18.4 / 0.01

m = -1840

Therefore, the relationship is T = -1840x + 212.

(B) To find the boiling point at an altitude of 3,500 feet (3.5 thousands of feet), we substitute x = 3.5 into the equation

T = -1840(3.5) + 212

T = -6440 + 212

T = 187.6

So, the boiling point at an altitude of 3,500 feet is approximately 187.6°F.

(C) To find the altitude if the boiling point is 200°F, we set T = 200 in the equation and solve for x:

200 = -1840x + 212

-1840x = 200 - 212

-1840x = -12

x = -12 / -1840

x ≈ 0.0065

So, the altitude corresponding to a boiling point of 200°F is approximately 0.0065 thousands of feet.

(D) Graph:

To graph T, we can use the equation T = -1840x + 212.

The graph will have altitude (x) on the x-axis and temperature (T) on the y-axis. Plotting the points (0, 212) and (10, 193.6), and connecting them with a straight line, we can illustrate the answers to (B) and (C) on the graph. The point (3.5, 187.6) will represent the boiling point at an altitude of 3,500 feet, and the point (0.0065, 200) will represent the altitude corresponding to a boiling point of 200°F.

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Maximum error in the result of the sum of measurement is equal to the sum absolute error of the individual observed measurements

(a) The maximum error in D is 0.09

(b) The standard error in D is approximately 0.034

The procedure for arriving at the above values is as follows;

The given measurements and the sited errors are;

A = 15.21 + 0.01

B = 10.82 + 0.05

C = 11.00 + 0.03

D = A + B + C

(a) Required parameter;

To calculate the maximum error in D

The equation for the propagation of error in addition is presented as follows;

Given that we have;

x = a + b

Therefore;

x + ±Δx = (a ± Δa) + (b ± Δb) = a + b ± (Δa + Δb)

∴ Δx = Δa + Δb

From the above formula, we have;

Where;

D = A + B + C

The maximum error in D = The sum of the maximum error in A, B, C

∴ The maximum error in D = 0.01 + 0.05 + 0.03 = 0.09

(b) Required parameter:

To find the standard error in D

The standard error is the sampling distribution's standard deviation, SD

Variance = SD²

The combined variance, SD² = The sum of the squares of individual standard deviations

Given that the standard errors represents the standard deviation, we get;

The combined variance, SD² = 0.01² + 0.05² + 0.03²

The combined variance, SD = √(0.01² + 0.05² + 0.03²) = 0.059

\(Standard \ error = \dfrac{SD}{\sqrt{n} }\)

Where n = 3, for the three measurement, we get;

\(Standard \ error = \dfrac{\sqrt{0.01^2 + 0.05^2 + 0.03^2} }{\sqrt{3} } \approx 0.034\)

The standard error in D is approximately 0.034

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It is important to note that the debate between scientific realism and antirealism is ongoing and complex, with various nuances and perspectives within each position. Different philosophers of science and scientists may hold different views on the nature of scientific terms and their relationship to reality.

According to a scientific realist perspective, scientific terms for unobservable phenomena such as "atom" and "black hole" are seen as referring to entities that truly exist in reality. Scientific realists believe that scientific theories and concepts accurately capture aspects of the world, including unobservable entities and phenomena. They argue that scientific theories provide the best explanation of the natural world and aim to describe the underlying structure and mechanisms of reality.

On the other hand, scientific antirealists hold a different view. They argue that scientific terms that refer to unobservable phenomena do not necessarily correspond to something that exists independently in reality. Antirealists often emphasize the instrumentalist view of science, which suggests that scientific theories are simply tools or frameworks that help us organize and predict observable phenomena, without making claims about the ultimate nature of reality.

Antirealists may argue that scientific theories are subject to revision and change over time as new evidence emerges, suggesting that the terms used to describe unobservable phenomena are not fixed and may not have a one-to-one correspondence with actual entities in reality. They may also highlight the role of social and cultural factors in shaping scientific knowledge, suggesting that scientific terms are influenced by human conventions and interpretations.

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If two objects are experiencing the same amount of force, the accelerations are not necessarily the same.

From Newton's second law,

we have F=ma,

where F is the force acting on the body, m is the mass and a is the acceleration of the body respectively.

Thus, the force of an object depends on both  mass and acceleration. Hence, if the two objects experiencing the same amount of force have unequal masses, then they'll have unequal accelerations. For example, if the force experienced by a golf head and a golf ball are the same, the golf ball experiences greater acceleration due to its smaller mass. Thus if the two objects are experiencing the same amount of force, then the lighter object among the two experiences greater acceleration.

On the other hand, if the two objects experiencing the same amount of force are of equal mass, then both will experience the same amount of acceleration.

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Option A is the most probable configuration for an op amp with five terminals. However, options B, C, and D are also possible, depending on the specific op amp in question and its intended use.

Based on the information provided in the question, we can assume that the op-amp in question has five terminals. The probable functions of these terminals can be determined by looking at the typical configuration of an op-amp.
Option A includes the five most common terminals of an op-amp: non-inverting input, inverting input, output, positive power supply, and negative power supply. These terminals allow the op-amp to amplify an input signal and produce an output signal that is proportional to the input signal.
Option B includes non-inverting input, inverting input, output, feedback, and gain control. Feedback and gain control are additional terminals that can be found in some op-amps, but not all. Feedback allows the op-amp to adjust its output based on the input signal, while gain control allows the user to adjust the amplification factor of the op-amp.
Option C includes positive power supply, negative power supply, output, feedback, and gain control. This configuration is less common than option A but still possible. In this case, the op amp would rely on an external feedback network to adjust its output.
Option D includes non-inverting input, inverting input, output, feedback, and bias. Bias is another additional terminal that can be found in some op-amps. It allows the user to adjust the DC offset of the op amp, which can be useful in certain applications.

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Answer:20 miles

Explanation:

Explanation:

A lightning rod (US, AUS) If lightning hits the structure:-

It will preferentially strike the rod and be conducted to ground through a wire.

Instead of passing through the structure, where it could start a fire or cause electrocution.

The parts of a lightning protection system are air terminals (lightning rods or strike) and all of the connectors and supports to complete the system.

Answer: Uh here

Explanation:

s=h=20

a=g=±10m/s=10m/s (since it is dropped)

v^2-u^2= 2as

v^2=2x10x20 (u=0; it is dropped not thrown)

v=20m/s

for calculating time

we know,

v=u+at

20= 0+ 10xt

t=2seconds

thus, it will attain a speed of 20m/s before touching the ground, but the time taken to reach the ground is 2seconds. Because the velocity is not uniform but acceleration/gravity is. If still there is any confusion. Try the same problem with 80 of height.

The speed of the stone when it reaches point B is: 22.64m/s.

Speed is a measure of how fast an object is moving, usually measured in units of distance per unit time, such as meters per second (m/s), kilometers per hour (km/h), or miles per hour (mph). It is a scalar quantity that describes how quickly an object is changing its position over time.

In order to find the speed of the stone, we have:

The mass of the stone is m = 15kg.

The height of snow hill is \(h_{A}\) = 20m and it is 15m wide.

The speed from point A is \(v_{A}\) = 11m/s.

The force constant is k = 2.50N/m.

The coefficient of kinetic friction and static friction between the stone and horizontal ground are μ\(_{k}\) = 0.20 and μ\(_{s}\) = 0.80 respectively.

As there is no friction between point A and B, the total energy at point A is equal to total energy at point B.

Therefore we get,

E\(_{A}\) = E\(_{B}\)

1/2mv²\(_{A}\) + mgh\(_{A}\) = 1/2mv²\(_{B}\) + mgh\(_{B}\)

v²\(_{B}\) = v²\(_{A}\) + 2g(h\(_{A}\) − h\(_{B}\))

But height at point B is zero i.e. h\(_{B}\) = 0.

Substituting known values in the equation, we have:

v\(_{B}\) =  \(\sqrt{v_A+ 2gh_{A} } }\)

= √[(11m/s)² + 2(9.8m/s²) (20m)] = 22.64m/s

Thus, the speed of the stone when it reaches at point B is 22.64m/s.

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The complete question is:

A 15.0-kg stone slides down a snow-covered hill that is 20 m high and 15 m wide, leaving point A at the top with a speed of 11.0 m/s. There is no friction on the hill between points A and B at the bottom of the hill, but there is friction on the level ground at the bottom of the hill, between B and the wall. After entering the rough horizontal region, the stone travels 100 m and then runs into a very long, light spring with a force constant of 2.50 N/m. The coefficients of kinetic and static friction between the stone and the horizontal ground are 0.20 and 0.80, respectively.

What is the speed of the stone when it reaches point B?