When the bell in a clock tower rings with a sound of 474 Hz, a pigeon roosting in the belfry flies directly away from the bell.

If the pigeon hears a frequency of 453Hz, what is its speed?

Answers

Answer 1

Answer:

15.44 m/s

Explanation:

Below is the given values:

The bell in rings with a sound = 474 Hz

If the frequency of pigeon hears = 453 Hz

Speed = ?

Use below formula:

Frequency = [(Vs - Vo) / Vs ] x fo

Vs = Speed of sound

Vo = Speed of observer

fo = Sound frequency

Frequency = [(Vs - Vo) / Vs ] x fo

453 = [(343 - Vo) / 343 ] x 474

453 / 474 =  [(343 - Vo) / 343 ]  

0.955 = (343 - Vo) / 343

0.955 x 343 = 343 - Vo

327.56 = 343 - Vo

Vo = 343 - 327.56

Vo = 15.44 m/s


Related Questions

Explain newton's second law in terms of momentum ​

Answers

Newton's second law states that the acceleration of an object is directly proportional to the force applied on it and inversely proportional to its mass. This can be expressed mathematically as F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration.

In terms of momentum, we can define momentum as the product of an object's mass and velocity. Mathematically, this can be expressed as p = mv, where p is the momentum, m is the mass, and v is the velocity.

Using this definition of momentum, we can rewrite Newton's second law as F = dp/dt, where F is the force, p is the momentum, and t is time. This equation tells us that the force applied on an object is equal to the rate of change of its momentum over time.

In simpler terms, this means that the more force applied to an object, the greater the change in its momentum over time, and the more mass an object has, the more force is required to achieve the same change in momentum. Therefore, the second law of motion in terms of momentum tells us how a force applied to an object affects its motion and momentum.

The map below shows major ocean currents in the North Atlantic and North Pacific Oceans. In general, currents flowing toward the
Equator bring cooler waters to some regions, while currents flowing away from the Equator bring warmer waters to other regions.
North
British
Isles
Askan
North Atlantic
Azor
U.S.A
California
Gulf Stream
Loop
n
Canbean
North Equatorial
North Equatorial CC
North Fuatorial
Equator
South Equatorial
Not
South Equatorial
Image courtesy of NOAA
Judging from the map, which region probably has cooler summers than it would without the effect of a nearby ocean current?
A the Central U.S.
B. the British Isles
C. the U.S. East Coast
D. the US West Coast

The map below shows major ocean currents in the North Atlantic and North Pacific Oceans. In general,

Answers

Answer:

d

Explanation:

the US West Coast region probably has cooler summers than it would without the effect of a nearby ocean current.

what is ocean current ?

ocean current can be defined as the horizontal movement of seawater which is produced by gravity, wind, and water density, it play an major role in the determination of climates of coastal regions.

The movement of ocean water is continuous which can be up three types such as Waves, Tides, Currents

The streams of water which flow continuously on the ocean surface in specific directions are called ocean currents, it affect the temperature of ocean water as Warm ocean currents increase the temperature whereas Cold ocean currents decrease the temperature.

The magnitude of the ocean currents is about  few centimeters per second to as much as 4 metres per second and the intensity of the ocean currents generally decreases with increasing depth.

There are two types of ocean currents such as Warm Ocean Currents

and Cold Ocean Currents

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What is the term that describes waves that require a medium through which to travel?

Answers

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

How are the elements in the same row similar

Answers

Answer:

All elements in a row have the same number of electron shells. Each next element in a period has one more proton and is less metallic than its predecessor. Arranged this way, groups of elements in the same column have similar chemical and physical properties, reflecting the periodic law.

can a body have an east velocity while expressing westward acceleration​

Answers

Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?

Answers

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

A rover vehicle weighs 37 N on Mars. How much would the rover weigh on Earth?

Answers

The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

How do determine the weight of the vehicle on earth?

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = 37 NAcceleration due to gravity on Mars (g) = 3.72 m/sMass of rover vehicle =?

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Mass (m) = 9.95 KgAcceleration due to gravity on Earth (g) = 10 m/s² Weight (W) = ?

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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Why is Rome warmer than New York in January

Answers

Answer:

The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.

Explanation:

Brainliest?

I need help with science:

Question 1: Chlorophyll makes some plants look yellow.

True
False
_________________________

Question 2:

Protozoa are a type of unicellular organisms.

True
False
__________________________________
Question 3:

Nerve cells carry oxygen to the body.

True
False
______________________________________

Question 4:

The__ is the basic unit of all living things.

Options:

nucleus
cell
___________________________

if you answer these all right:
( if u want brainlist's answer this question then ask another random question on your page so u can give me brainlist back, also i need to people to answer so i can chose one of you guys to give the brainlist's to, deal or no?)

no links and ill give good points so u better not steal them or ill report...

Answers

I pretty sure number 3 is false

A force of 1.50 N acts on a 0.20kg trolley so as to accelerate it along an air track
The track and force are horizontal and in line . How fast is the trolley going after acceleration from rest through 30cm , if friction is negligible​

Answers

Answer:

2.12m/s

Explanation:

Given parameters:

Force on trolley  = 1.5N

Mass of trolley  = 0.2kg

Unknown:

Velocity of the trolley  = ?

Solution:

To solve this problem, we first find the acceleration of the trolley;

          Force  = mass x acceleration

         Acceleration  = \(\frac{Force }{mass}\)

Insert the parameters and solve;

          Acceleration  = \(\frac{1.5}{0.2}\)   = 7.5m/s²

Now to find the acceleration;

  Initial velocity  = 0m/s

  v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

  Distance  = 30cm and this is 0.3m

     v² = 0² + 2(7.5)0.3  = 4.5

     v = √4.5 = 2.12m/s

A ball rolled along a horizontal surface comes to rest in a distance of 72m in 6s. Its initial velocity
and deceleration are
and​

Answers

Answer:

1. Initial velocity = 24 m/s

2. Deceleration = –4 m/s²

Explanation:

From the question given above, the following data were obtained:

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

1. Determination of the initial velocity.

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) =?

s = (u + v)t / 2

72 = (u + 0) × 6 / 2

72 = u × 3

Divide both side by 3

u = 72 / 3

u = 24 m/s

2. Determination of the deceleration.

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 24 m/s

Deceleration (a) =?

v = u + at

0 = 24 + (a × 6)

0 = 24 + 6a

Collect like terms

0 – 24 = 6a

–24 = 6a

Divide both side by 6

a = –24 / 6

a = –4 m/s²

Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed speeding up or slowing down

Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed

Answers

a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.

What do you understand by force and friction?

Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.

Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.

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It takes less effort to lift a piano with a pulley. If the piano is lifted 3 meters, then...

Answers

It takes less effort to lift a piano with a pulley. If the piano is lifted 3 meters, then the distance traveled by the load is 3 m.

What is output force?

Output force is the force exerted on an object by a simple machine.

If the output force is greater than the input force, the mechanical advantage is greater than 1.

The mechanical advantage ratio is output force divided by input force. The larger the mechanical advantage, the easier it is to do work.

Mathematically, the output force of a simple machine is given as;

output force = load x distance moved by load

Thus, it takes less effort to lift a piano with a pulley. If the piano is lifted 3 meters, then the distance traveled by the load is 3 m.

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1 point
Kinetic friction is defined as a force that acts between moving surfaces. A
body moving on the surface experiences a force in the opposite direction
of its movement. A student is investigating the motion of a block sliding
down a ramp onto the floor. The diagram below shows the block at five
points during the investigation. The block is at rest at point V. The student
releases the block so that it slides down the ramp and stops at point Z.
Which of the following best explains where kinetic friction is acting on the
block?

Answers

Answer:

Explanation:

Not sure what your options are but anything that says something like

"at the block surface in contact with the ramp along the line from V to Z"  is probably a good shot.

Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of m A = 17.0 kg and an initial velocity of v 0A = 8.00 m/s, due east. Object B, however has a mass of m B = 29.0 kg and an initial velocity of v 0B = 5.00 m/s, due north. Find the magnitude and direction of the total momentum of the two-object system after the collision.

Answers

Answer:

pf = 198.8 kg*m/s

θ = 46.8º N of E.

Explanation:

Since total momentum is conserved, and momentum is a vector, the components of the momentum along two axes perpendicular each other must be conserved too.If we call the positive x- axis to the W-E direction, and the positive y-axis to the S-N direction, we can write the following equation for the initial momentum along the x-axis:

       \(p_{ox} = p_{oAx} + p_{oBx} (1)\)

We can do exactly the same for the initial momentum along the y-axis:

       \(p_{oy} = p_{oAy} + p_{oBy} (2)\)

The final momentum along the x-axis, since the collision is inelastic and both objects stick together after the collision, can be written as follows:

       \(p_{fx} = (m_{A} + m_{B} ) * v_{fx} (3)\)

We can repeat the process for the y-axis, as follows:

       \(p_{fy} = (m_{A} + m_{B} ) * v_{fy} (4)\)

Since (1) is equal to (3), replacing for the givens, and since p₀Bₓ = 0, we can solve for vfₓ as follows:

       \(v_{fx} = \frac{p_{oAx}}{(m_{A}+ m_{B)}} = \frac{m_{A}*v_{oAx} }{(m_{A}+ m_{B)}} =\frac{17.0kg*8.00m/s}{46.0kg} = 2.96 m/s (5)\)

In the same way, we can find the component of the final momentum along the y-axis, as follows:

       \(v_{fy} = \frac{p_{oBy}}{(m_{A}+ m_{B)}} = \frac{m_{B}*v_{oBy} }{(m_{A}+ m_{B)}} =\frac{29.0kg*5.00m/s}{46.0kg} = 3.15 m/s (6)\)

With the values of vfx and vfy, we can find the magnitude of the final speed of the two-object system, applying the Pythagorean Theorem, as follows:

      \(v_{f} = \sqrt{v_{fx} ^{2} + v_{fy} ^{2}} = \sqrt{(2.96m/s)^{2} + (3.15m/s)^{2}} = 4.32 m/s (7)\)

The magnitude of the final total momentum is just the product of the combined mass of both objects times the magnitude of the final speed:

       \(p_{f} = (m_{A} + m_{B})* v_{f} = 46 kg * 4.32 m/s = 198.8 kg*m/s (8)\)

Finally, the angle that the final momentum vector makes with the positive x-axis, is the same that the final velocity vector makes with it.We can find this angle applying the definition of tangent of an angle, as follows:

       \(tg \theta = \frac{v_{fy}}{v_{fx}} = \frac{3.15 m/s}{2.96m/s} = 1.06 (9)\)

       ⇒ θ = tg⁻¹ (1.06) = 46.8º N of E

Gwen releases a rock at rest from the top of a 40-m tower. If g = 9.8 m/s2 and air resistance is negligible, what is the speed of the rock as it hits the ground?

Answers

Answer:

\(28\; \rm m \cdot s^{-1}\).

Explanation:

Short Explanation

Apply the SUVAT equation \(\left(v^2 - u^2) = 2\, a \, x\), where:

\(v\) is the final velocity of the object,\(u\) is the initial velocity of the object, \(a\) is the acceleration (should be constant,) and\(x\) is the displacement of the object while its velocity changed from \(v\) to \(u\).

Assume that going downwards corresponds to a positive displacement. For this question:

\(v\) needs to be found.\(u = 0\) because the rock is released from rest.\(a = g = 9.8 \; \rm m\cdot s^{-2}\).\(x = 40\; \rm m\).

Solve this equation for \(v\):

\(\displaystyle v = \sqrt{2\, a\, x + u^2} = \sqrt{2\times 9.8 \times 40} = 28\; \rm m \cdot s^{-1}\).

In other words, the rock reached a velocity of \(28\; \rm m\cdot s^{-1}\) (downwards) right before it hits the ground.

Explanation

Let \(v\) be the velocity (in \(\rm m \cdot s^{-1}\)) of this rock right before it hits the ground. Under the assumptions of this question, it would take a time of \(t = (v / 9.8)\) seconds for this rock to reach that velocity if it started from rest and accelerated at \(9.8\; \rm m \cdot s^{-2}\).

Note that under these assumptions, the acceleration of this rock is constant. Therefore, the average velocity of this rock would be exactly one-half the sum of the initial and final velocity. In other words, if \(u\) denotes the initial velocity of this rock, the average velocity of this rock during the fall would be:

\(\displaystyle \frac{u + v}{2}\).

On the other hand, \(u = 0\) because this stone is released from rest. Therefore, the average velocity of this rock during the fall would be exactly \((v / 2)\).

The displacement of an object over a period of time is equal to the length of that period times the average velocity over that period. For this rock, the length of this fall would be \(t = (v / 9.8)\), while the average velocity over that period would be \((v / 2)\). Therefore, the displacement (in meters) of the rock during the entire fall would be:

\(\displaystyle \left(\frac{v}{2}\right) \cdot \left(\frac{v}{9.8}\right) = \frac{v^2}{19.6}\).

That displacement should be equal to the change in the height of the rock, \(40\; \rm m\):

\(\displaystyle \frac{v^2}{19.6} = 40\).

Solve for \(v\):

\(v = 28\; \rm m \cdot s^{-1}\).

Once again, the speed of the rock would be \(28\;\rm m \cdot s^{-1}\) right before it hits the ground.

Will a roller coaster with a higher starting point be a faster ride? Why or why not

Answers

Answer:

yez

Explanation:

A smoke detector is an electronic fire-protection device that automatically senses the presence of smoke as a key indicator of fire and creates a loud sound as a warning. In 3-5 sentences, describe what is happening inside a photoelectric smoke detector as soon as smoke enters it

Answers

Answer:

Photoelectric-type alarms aim a light source into a sensing chamber at an angle away from the sensor. Smoke enters the chamber, reflecting light onto the light sensor; triggering the alarm.

Explanation:

nfpa.org is the website with theanswer

Light hits a mirror at a 45° angle. It will be reflected at an angle _____.

equal to 45°
greater than 45°
less than 45°

Answers

Light hits a mirror at a 45° angle. It will be reflected at an angle equal to 45°

According to law of reflection, when a light ray falls on a surface that is smooth, the angle of reflection will be equal to the angle of incidence. The incident ray, the reflected ray and the normal to the surface all will lie in the same plane.

Reflection is the process in which a light ray gets bounced back after falling on a surface. The angle between in the incident ray and the normal to the surface is known as angle of incidence. The angle between in the reflected ray and the normal to the surface is known as angle of reflection.

Therefore, light hits a mirror at a 45° angle. It will be reflected at an angle equal to 45°

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5. A spring of k-500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.

5. A spring of k-500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a

Answers

The kinetic energy of the brick equal the elastic potential energy at the top of the hill. Using this, the speed of the brick is 14 m/s.

What is elastic potential ?

The elastic potential of a spring is directly proportional to the squire of the displacement.

Then,

p = 1/2 k x²

Given that, spring constant k = 500 N/m

height of the hill x = 2 m

weight of the load = 100 N

then mass = 100N/9.8 m/s² =10.20 Kg.

At the top of the hill, kinetic energy of the hill is equal to the elastic potential.

then, 1/2 mv² =  1/2 k x²

speed v of the brick  = √kx²/m

v = √(500 N/m × 2 m²/10.20 kg)

  = 14 m/s.

Therefore, the speed of the brick at the top of the hill is 14 m/s.

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How is thermal energy being transferred when steam rises from a beaker of boiling water?
O A. Conduction
• B. Radiation
O c. Translation O D. Convection

Answers

Answer:

d. convention

Explanation:

hope this helped

answers D. convection

Please Help with this

Please Help with this

Answers

Answer: c is correct

Explanation: i did this

if an object isn't moving the forces are acting on the object are: A. not present B. unbalanced C. balanced D. accelerated

Answers

C. Balanced I remember taking this test 2yrs ago

The kinematic viscosity of oxygen at 40 °C and a pressure of 160 kPa is 0.104 stokes. Determine the dynamic viscosity of the oxygen at this temperature and pressure. (Ro₂ = 0.2598 kPa.m³/kg.K)

Answers

The dynamic viscosity of oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

The dynamic viscosity of a fluid is equal to its kinematic viscosity multiplied by its density.

Given:

Kinematic viscosity of oxygen at 40°C and 160 kPa = 0.104 stokes

Density of oxygen at 40°C and 160 kPa = (160000 Pa / 0.2598 kPa.m³) = 616.55 kg/m³ (using ideal gas law)

Using the formula:

Dynamic viscosity = Kinematic viscosity * Density

We get:

Dynamic viscosity of oxygen = 0.104 stokes * 616.55 kg/m³ = 64.17 × 10⁻⁶ Pa.s

Therefore, the dynamic viscosity of the oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

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what is the frequency of a wave that had a wavelength of 15m and is traveling at 135 m/s

Answers

V=f x wavelength
f=v/wavelength
=135/15=9 Hz

A ball is thrown vertically upwards with a velocity of 10 m /s from the balcony of a tall building.
The balcony is 15m above the ground and gravitational acceleration is 10m/s^2.
Calculate the time taken for the ball to reach maximum height.

Answers

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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We all have a tendency to make illusory correlations from time to time. Try to think of an illusory correlation that is held by you, a family member, or a close friend. How do you think this illusory correlation came about and what can be done in the future to combat them?

Answers

Answer:

Thats a personal question

Explanation:

It asks about you

(illusion is something you think is there but is not)

Seeing the dirty look on a friend's face, we assume that he is angry with us, but he may be having a bad day, or may be thinking something that is reflected in his face. We should always ask someone instead of assuming.

What is an illusory correlation?

Illusory correlation is defined as the phenomenon of assuming a relationship between variables even when no such relationship exists where a false association can be made because rare or novel events are more prominent and therefore attract one's attention.

Illusory correlation occurs when two different variables occur at the same time, with an unproven connection made on the basis of little evidence. An example of this would be when a person has a bad experience with a lawyer and they immediately assume that all lawyers are bad people.

Thus, we should always ask someone instead of assuming.

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we can find the current, i, in the circuit by using ohm's law (generalized for alternating currents), v

Answers

The current, i, in the circuit by using ohm's law (generalized for alternating currents), v is  \(\begin{aligned}& I= \\& \quad 0.4000+0.8000 i\end{aligned}\)

What is circuit?

An electronic circuit is composed of individual electronic components, such as resistors, transistors, capacitors, inductors and diodes, connected by conductive wires or traces through which electric current can flow.

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we can find the current, i, in the circuit by using ohm's law (generalized for alternating currents),

Refraction studes show that the Moho is depressed about 10 km beneath the center of the Hawaiian Islands. Assuming that this is the value of wo and that h=34 km, E= 70 GPa, v = 0.25. Pm Pw 2300 kg m-3, and g = 10 m s -2 determine the maximum bending stress in the lithosphere.

Answers

the maximum bending stress in the lithosphere is 202 MPa

hear

Given that Hite 34 km

12 2 70 9 Pa

N 2 0. 25

ρm- ρw= 2300 kgm 3

3 = 10 ms - 2

Moh depressed about 10km beneath the centre or Islands .

We know, flexural rigidity

Equation

D=E/12 (1 - V 2 )

be neath the center of Isla g

=70 x 109 pa x 103 x ( 10 m ) 312 (1 - 0.0625 )

=70 x 1021- Nm

=12X 019375Fox 10 212

=2 6: 222 x 102 Mm

Again , total maximum bending stress in the

lithosphere 6 = = 90 - ( 8 m - Pm ) 8 u

Where , Applied load of upper Surface of lithosph

We Replaced manthe rock thickness = 34 1

Bending stress = 6. 222 x 10' Alm- 2300 108 x 10->52 x 34 km

=n3 4

= 6. 2327 10 1/m- 230 0 kg x 10 m 2 x 34 x103 x]

=2 6 . 222 x 102/ nim - . 2300 X10 x 34x103 Pa

= 6222x1021 am 2 x 18 Alm

34x 34 x 34x( 103) ,m 3

6:222 X 102 Mm

2

3 4 x 3 4x34 x 109 m 3

2 6 .222 x 1012 na

34 x 34 x 39

6. 222

- x 10 2 pa

39, 304

2 0. 000 ( 5 8 307 10 - Pas

158, 83 X 108 pa .

-'. Bendig stress - 15.83 x108 pa . 782 x 10 Pa

2 15. 53 x108 pa - 7. 8 2x108 pc

Bendig stress=202 M Pa

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45:56
Which of these is an example of acceleration?

a bicyclist turning around a corner
a car traveling south with its cruise control set
a bus traveling north at 25m/s
a helicopter waiting to take off

Answers

Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

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