when twice a number is added to 13 the result is 5 find the number​

Answer: We can use the equation to find the number of dimes in Kendall's pocket:

25g + 10d = 150

25 * 4 + 10d = 150

100 + 10d = 150

10d = 50

d = 5

So Kendall has 5 dimes in her pocket.

Step-by-step explanation:

Answer:

x = ± 2√2

Step-by-step explanation:

Assuming "x2" is x^2 or "x squared", the answer can be derived from "square-rooting" both sides.

√ x^2 = √ 8

Then we simplify.

x = ± 2√2

Hope this helps!

Answer:

the answer is A.

Step-by-step explanation:

Don't have time to write the steps now because i am in class but i might later.

Answer:

(- 5, 4 )

Step-by-step explanation:

under a reflection in the line y = x

a point (x, y ) → (y, x ) , then

G (4, - 5 ) → G' (- 5, 4 )

The coordinates of the image of vertex G are (-5, 4)

When reflecting a figure in a line or in a point, the image is congruent to the pre image. A reflection maps every point of a figure to an image across a fixed line. The fixed line is called the line of reflection.

here, we have,

Let us revise some cases of reflection

If the point (x, y) reflected across the x-axis , then its image is (x, -y)

If the point (x, y) reflected across the y-axis , then its image is (-x, y)

If the point (x, y) reflected across the line y = x , then its image is (y, x)

If the point (x, y) reflected across the line y = -x , then its image is (-y, -x)

From the given figure

∵ The line of the reflection is y = x

→ That means we will switch the coordinates of the point to find its image

∵ The coordinates of vertex G are (4, -5)

∴ The x-coordinate = 4 and the y-coordinate = -5

→ Switch the two coordinates

∴ The coordinates of its image G' are (-5, 4)

∴ The coordinates of the image of vertex G are (-5, 4)

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The approximate lateral surface area of the sphere is, 483.1 cm^2.

What is lateral surface area?

The sides of an object, except its base and top, are considered the object's lateral surface. The area of the lateral surface is known as the lateral surface area. Contrast this with the total surface area, which combines the regions of the base and top with the lateral surface area.

Let a sphere has a radius of 6.2 centimeters.

We have to find the lateral surface area of the sphere.

Since,

Lateral surface area of sphere = \(4\pi r^2\)

Here r = 6.2

Plug the value in the above formula

Lateral surface area of sphere

\(= 4\pi (6.2)^2\\= 4\pi (38.44)\\= 483.05\\= 483.1\)

Hence, the lateral surface area of the sphere is, 483.1 cm^2.

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the values of $a$ and $b$,is So, $b - a = 6$.using the smallest and largest integers within this interval. Since "integer" refers to whole numbers (both positive and negative), we can identify $a$ and $b$

let's first solve the given inequality $x^2 - 15 < 2x$. We can rewrite this inequality by moving all terms to one side:

$x^2 - 2x - 15 < 0$

Now, we want to factor the quadratic:

$(x - 5)(x + 3) < 0$

From this factored form, we can see that the quadratic changes sign at x = -3 and x = 5. This means the inequality holds between these values:

-3 < x < 5

Now, we want to find the smallest and largest integers within this interval. Since "integer" refers to whole numbers (both positive and negative), we can identify $a$ and $b$ as follows:

$a = -2$ (the smallest integer greater than -3)
$b = 4$ (the largest integer less than 5)

Finally, we need to find the difference $b - a$:

$b - a = 4 - (-2) = 4 + 2 = 6$

So, $b - a = 6$.

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The diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

A cylinder is a three-dimensional solid figure which has two identical circular bases joined by a curved surface at a particular distance from the center which is the height of the cylinder.

Here, Given area of cylinder = 25π cm²

          Height of cylinder = 11 cm.

Now, Area of Cylinder = 2πrh

                  25π = 2πr X 11

                   25 = 22r

                    r = 25 / 22

                  r = 1.14 cm

Then, diameter = 2r = 2 X 1.14 = 2.28 cm

Now area of wrapper = total surface area = 2πr(r + h)

                                    = 2π X 2.28 (2.28 + 11)

                                   = 4.56π X 13.28

                                   = 60.56π cm²

Thus, the diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

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( t ) = √ 2 t + 1

v ( t ) = √ 2 feet per second

a ( t ) = 0

Answer:

profit : RS 150 and profit % : 3%

Step-by-step explanation:

for profit 10% for loss 4%

s.p will be 2750. s.p will be 2400

Total s.p : 2750 +2400. total s.p : 5150

profit = s.p-c.p. profit%=?

=5150-5000. profit = p /c.p × 100

=150 = 150/5000×100

= 3%

Answer:

120 / 561

Step-by-step explanation:

An automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 were vans. Plant managers are going to select two of these vehicles for a thorough inspection. The first vehicle will be selected at random, and then the second vehicle will be selected at random from the remaining vehicles.What is the probability that two motorcycles will be selected

16/34 X 15 X 33

Answer:

$0.20

Step-by-step explanation:

4 x 1.45 = $5.80

6.00 - 5.80 = 0.20

Answer: $0.20

Step-by-step explanation:

Do 4 *$1.45 = $5.80

This is how much her total was.

She gave $6 in cash.

Subtract.

6-5.80=$.20

The value of the expression 1.6(x-y)² is 40 when x = 10 and y = 5.

The given expression is 1.6(x-y)².

We have to evaluate this expression for x = 10 and y = 5.

To evaluate it, we substitute the given values of x and y into the expression and simplify it.

Let's substitute the values of x and y into the expression:

1.6(x-y)²= 1.6(10-5)²= 1.6(5)²= 1.6(25)= 40

Therefore, the value of the expression 1.6(x-y)² is 40 when x = 10 and y = 5.

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The total revenue that will be maximized is 20 - 2a

From the question, we have the following parameters that can be used in our computation:

Qd = 20 - P

The revenue equation is calculated using

Revenue = Quantity * Price

So, we have

R = Qd * P

This gives

R = (20 - P) * P

Expand

R = 20P - P²

Differentiate

R' = 20 - 2P

Next, we have

Q = a

So, we have

R = 20 - 2a

Hence, the total revenue that will be maximized is 20 - 2a

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Answer:

10 km/h

Step-by-step explanation:

First, convert 150 minutes to hours:

150/60

= 2.5 hours

Then, to find his speed, divide the km by the number of hours:

25/2.5

= 10 km/h

Answer:

10 km / hr

Step-by-step explanation:

We want to find the average speed in kilometers per hour.

We know that Andre cycled 25 kilometers in 150 minutes.

First, we have the convert 150 minutes to hours.

There are 60 minutes in 1 hour, so we can divide 150 by 60.

150/60= 2.5

Next, find the average speed in kilometers per hour.

Divide the kilometers traveled by the hours.

speed = kilometers / hours

Andre cycled 25 kilometers in 2.5 hours.

speed= 25 km /2.5 hrs

speed = 10 km/hr

Andre’s average speed was 10 kilometers per hour.

Hey there! I'm happy to help!

The distance is equal to the speed multiplied by the time. We already have the distance and the speed, so we divide them to get the time.

240/45=5 1/3 hours

However, we want this in minutes. There are 60 minutes in one hour, so we just multiply by 60!

5 1/3×60=320

Therefore, it takes 320 minutes to drive from Orlando to Miami.

Have a wonderful day! :D

Answer:

x= negative 90 i think.

Step-by-step explanation:

Answer:

Part 1:

Domain= {2,3,8,9}

Range = {7,9,14}

Part 2: Yes it is not a function

Step-by-step explanation:

Domain is the first number

Range is the second.

Domain= {2,3,8,9}

Range = {7,9,14} ( Notice that 14 is noted twice so just put it as once and this is not part of the answer)

Function: Is any of the domain numbers the same: Answer Yes it's a function.

Answer:

Answer = 3 1/30

Step-by-step explanation:

91/6 x 1/5 = 91/30

divide = 3 1/30

In the form of mixed number we can write the statement as -  \($1\frac{5}{6}\).

We have \(9\frac{1}{6}\) divided by 5.

We have to write the answer as fraction in mixed form.

A number consisting of an integer and a proper fraction is called a Mixed Number.

According to the question, we have -  \(9\frac{1}{6}\) divided by 5

Let  A = \(9\frac{1}{6}\) divided by 5.

Now -

A =  \(9\frac{1}{6}\) divided by 5

A = \(\frac{55}{6}\) ÷ 5

A = \($\frac{\frac{55}{6} }{5}\)= \(\frac{11}{6}\) = \($1\frac{5}{6}\)

Hence, in the form of mixed number we can write the statement as -  \($1\frac{5}{6}\).

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Write the inequality for the statement and solve for v

It means that v is less than or equal to -4. The solution set for this inequality is:

Answer:

49 cm²

Step-by-step explanation:

Half circle: 1/2 π r² ≈ 1/2 * 3.14 * 16  = 25.12

Rectangle: 3*8 = 24

Add them: 25.12 + 24 ≈ 49

Answer: \(\lim_{x \to \infty} (\frac{sinh(x)}{e^x})\)\(= 0\)

Step-by-step explanation:

\(\lim_{x \to \infty} (\frac{sinh(x)}{e^x})\)

\(\lim_{n \to \infty} \frac{sinh(\infty)}{e^(\infty)}\)

As x approaches infinity, the exponential term e^x becomes much larger than the hyperbolic sine function sinh(x), so the entire expression sinh(x)/e^x becomes very close to zero.

Therefore, the limit of the expression as x approaches infinity is 0:

The curvature of the curve is 14 / (sqrt(53))^3.

To re-parametrize the curve by arc length, we need to find the arc length function s(t) and then express t in terms of s. The arc length function is given by:

s(t) = ∫[a,t] ||r'(u)|| du

Where a is the starting parameter value and r'(u) is the derivative of r(u) with respect to u.

Let's first find r'(t):

r'(t) = (-2sin(t), 2cos(t), 7)

The magnitude of r'(t) is:

||r'(t)|| = sqrt((-2sin(t))^2 + (2cos(t))^2 + 7^2) = sqrt(4sin^2(t) + 4cos^2(t) + 49) = sqrt(53)

Now we can find the arc length function s(t):

s(t) = ∫[0,t] sqrt(53) du = sqrt(53)t

To re-parametrize the curve by arc length, we need to express t in terms of s:

s(t) = sqrt(53)t

Solving for t:

t = s / sqrt(53)

Now we can find the position vector of the curve in terms of s:

r(s) = (2cos(t), 2sin(t), 7t) = (2cos(s / sqrt(53)), 2sin(s / sqrt(53)), 7s / sqrt(53))

To find where you will be after following the curve for 6 units of length (s = 6), substitute s = 6 into the position vector:

r(6) = (2cos(6 / sqrt(53)), 2sin(6 / sqrt(53)), 7(6) / sqrt(53))

To find the curvature of the curve, we can use the formula:

κ = ||r'(t) x r''(t)|| / ||r'(t)||^3

where r''(t) is the second derivative of r(t) with respect to t.

The second derivative of r(t) is:

r''(t) = (-2cos(t), -2sin(t), 0)

Now we can calculate the curvature:

κ = ||r'(t) x r''(t)|| / ||r'(t)||^3

= ||(-2sin(t), 2cos(t), 7) x (-2cos(t), -2sin(t), 0)|| / (sqrt(53))^3

= ||(-14sin(t), -14cos(t), 0)|| / (sqrt(53))^3

= 14 / (sqrt(53))^3

So the curvature of the curve is 14 / (sqrt(53))^3.

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Answer:

A full circle has 360 degrees, which means that 100% of the circle is 360 degrees. First convert the percentage into a decimal. If you multiply 360 by 0.90, you get the degree measure that corresponds to the percentage, which is 324.

Step-by-step explanation:

The percent of students in grade 8 those who like to join dance club is equal to 25%.

Total number of students in grade 8 = 20

Total number of students of grade 8  join in dance club = 5

Percent of students of grade 8 prefer to join dance club

= ( total number of students prefer dance club ) / ( Total number of students in grade 8 ) × 100

Substitute the value in the formula we get,

⇒ Percent of students of grade 8 prefer to join dance club

= ( 5 ) / ( 20 ) × 100

⇒ Percent of students of grade 8 prefer to join dance club  = 0.25 × 100

⇒ Percent of students of grade 8 prefer to join dance club  = 25%

Therefore, percent of grade 8 students who preferred to join dance club is equal to 25%.  

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The above question is incomplete, the complete question is:

What percent of students in grade 8 prefer to join a dance club?

                      Dance club      Hiking club     Total

Grade 7               15                       15                 30

Grade 8               5                        15                  20

Total                    20                     30                    50

Answer:

1. 16

2. 4

3. x = 11

4. (-2, 5)

5. (-10, -5.5)

Step-by-step explanation:

1. Because Q is the midpoint, PQ + QS = PS, and PQ = QS

PQ = 8, so QS = 8

8+8 = 16 = PS

2. QS = 8, and R is the midpoint, so QR is half

8/2 = 4, QR = 4

3. PQ = QS (because Q is the midpoint of PS)

3x - 4 = 29

3x = 33

x = 11

4. midpoint formula: add the two x coordinates, then divide by 2 to get the x coordinate, add the two y coordinates and divide by 2 to get the y coordinate

x coordinate: \(\frac{-9+5}{2} = -2\)

y coordinate: \(\frac{3+7}{2} = 5\)

(-2, 5)

5. Use the midpoint formula again

x coordinate: \(\frac{-12+-8}{2} =-10\)

y coordinate: \(\frac{-7+-4}{2} =-5.5\)

(-10, -5.5)

a) Three circular objects:

Object 1 with a circumference of 20 cm and a diameter of 6.37 cm, Object 2 with a circumference of 40 cm and a diameter of 12.74 cm, and Object 3 with a circumference of 60 cm and a diameter of 19.11 cm.

b) . Each object will have a corresponding point on the graph, such as (6.37, 20), (12.74, 40), and (19.11, 60).

c) The diameter and circumference of a circle cannot be zero.

d) The line will pass through the middle of the plotted points, representing an average trend.

e) Selecting points (6.37, 20) and (19.11, 60) yields a slope of 3.14.

f) The circumference of a circle is always approximately 3.14 times its diameter.

A. Obtain a set of circular objects and measure their circumference and diameter. For example, let's consider three circular objects:

Object 1 with a circumference of 20 cm and a diameter of 6.37 cm, Object 2 with a circumference of 40 cm and a diameter of 12.74 cm, and Object 3 with a circumference of 60 cm and a diameter of 19.11 cm.

B. Plot a graph of circumference versus diameter for the objects. The x-axis represents the diameter, and the y-axis represents the circumference. Each object will have a corresponding point on the graph, such as (6.37, 20), (12.74, 40), and (19.11, 60).

C. The point (0,0) should not be included on the graph. The point (0,0) represents a diameter of 0 and a circumference of 0, which does not make sense in the context of circles. The diameter and circumference of a circle cannot be zero.

D. Draw a smooth line through the middle of the points on the graph. Since we are examining the relationship between circumference and diameter, a straight line should fit the data well. The line will pass through the middle of the plotted points, representing an average trend.

E. Compute the slope of the line. Using the line drawn on the graph, calculate the slope by selecting two points that are far apart on the line. The slope represents the ratio of the change in circumference to the change in diameter. For example, selecting points (6.37, 20) and (19.11, 60) yields a slope of 3.14.

F. The slope of the line, which is approximately 3.14, is a special number for circles known as π (pi). It represents the constant ratio between the circumference and the diameter of any circle. In other words, the circumference of a circle is always approximately 3.14 times its diameter. The value of π is encountered frequently in various mathematical and scientific contexts involving circles and is considered a fundamental constant in mathematics.

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There is sufficient evidence to support the claim of a greater variance for machine 1

Given: n1=25 , n2​=22

The mean is the sum of all values divided by the number of values:

x1=2.95+3.45+...+3.35+3.12/25≈3.3284

x2​=3.22+3.30+...+3.16+3.33​/22≈3.2782

The variance is the sum of squared deviations from the mean divided by n−1. The standard deviation is the square root of the variance:

s1=√(2.95−3.3284)²+....+(3.12−3.3284)²/25−1≈0.2211

s1​=√25−1(2.95−3.3284)2+....+(3.12−3.3284)2​

​≈0.2211

s2=(3.22−3.3284)2+....+(3.33−3.3284)222−1≈0.0768

s2​=(3.22−3.3284)2+....+(3.33−3.3284)2²/22−1​≈0.0768

Determine the hypotheses:

H0=σ12≤σ22

H1​=σ12​>σ22​

Compute the value of the test statistic:

F=\(\frac{S^1_2}{S^2_2}\) =0.2211²/0.0768²≈8.288

The P-value is the probability of obtaining the value of the test statistic, or a value more extreme. The P-value is the number (or interval) in the column title of Table 4 containing the F-value with dfn=25−1=24 and dfd=22−1=21:

P<0.01

If the P-value is less than the significance level, reject the null hypothesis.

P<0.01⇒ Reject H0

Complete Question:

The variance in a production process is an important measure of the quality of the process. A large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance. Conduct a statistical test to determine whether there is a significant difference between the variances in the bag weights for the two machines. Use a .05 level of significance. What is your conclusion? Which machine, if either, provides the greater opportunity for quality improvements?

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There is sufficient evidence to support the claim of a greater variance for machine 1

Given: n1=25 , n2​=22

The mean is the sum of all values divided by the number of values:

x1=2.95+3.45+...+3.35+3.12/25≈3.3284

x2​=3.22+3.30+...+3.16+3.33​/22≈3.2782

The variance is the sum of squared deviations from the mean divided by n−1. The standard deviation is the square root of the variance:

s1=√(2.95−3.3284)²+....+(3.12−3.3284)²/25−1≈0.2211

s1​=√25−1(2.95−3.3284)2+....+(3.12−3.3284)2​

​≈0.2211

s2=(3.22−3.3284)2+....+(3.33−3.3284)222−1≈0.0768

s2​=(3.22−3.3284)2+....+(3.33−3.3284)2²/22−1​≈0.0768

Determine the hypotheses:

H0=σ12≤σ22

H1​=σ12​>σ22​

Compute the value of the test statistic:

F= \(\frac{S_2^1}{S_2^2}\) =0.2211²/0.0768²≈8.288

The P-value is the probability of obtaining the value of the test statistic, or a value more extreme. The P-value is the number (or interval) in the column title of Table 4 containing the F-value with dfn=25−1=24 and dfd=22−1=21:

P<0.01

If the P-value is less than the significance level, reject the null hypothesis.

P<0.01⇒ Reject H0

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Complete Question:

The variance in a production process is an important measure of the quality of the process. A large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance. Conduct a statistical test to determine whether there is a significant difference between the variances in the bag weights for the two machines. Use a .05 level of significance. What is your conclusion? Which machine, if either, provides the greater opportunity for quality improvements?