Which distribution is positively skewed?
O A.
OB.
O C.
ח
0 2
4
8 10
5
H
14
HHHH
24
6
8 10 12 14 16 18 20 22 24 26 28 30

The equation of the line that passes through the points (1, 0) and (3, 6) is y = 3x - 3.

To find the equation of a line passing through two points, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope of the line and b is the y-intercept.

Given points:

Point 1: (1, 0)

Point 2: (3, 6)

Step 1: Calculate the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Substituting the coordinates:

m = (6 - 0) / (3 - 1)

m = 6 / 2

m = 3

Step 2: Substitute one of the given points and the slope into the equation y = mx + b to find the y-intercept (b).

Using Point 1 (1, 0):

0 = 3(1) + b

0 = 3 + b

b = -3

Step 3: Write the equation of the line using the slope (m) and the y-intercept (b):

y = 3x - 3

Therefore, the equation of the line that passes through the points (1, 0) and (3, 6) is y = 3x - 3.

This equation represents a line with a slope of 3, indicating that for every increase of 1 unit in the x-coordinate, the y-coordinate increases by 3 units. The y-intercept of -3 means that the line crosses the y-axis at the point (0, -3). By substituting any x-value into the equation, we can determine the corresponding y-value on the line.

Hence, the equation of the line passing through (1, 0) and (3, 6) is y = 3x - 3.

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Answer:

Ignore my handwriting loll

Step-by-step explanation:

Hope this helps! :)

Answer:

Step-by-step explanation:

(99)3 =

(99) x 3 =

(90 + 9) x 3 =

(90) x 3 + (9) x 3 =

90 x 3 + 9 x 3 =

270 + 27 =

297

Hope that helps! :)

-Aphrodite

Step-by-step explanation:

Evaluate (99)^3 using suitable identities.

(99)^3 = (100 - 1)^3

since, (a - b)^2 = a^3 - b^3 - 3ab (a-b)

Where,

Now,

(99)^3

=> (100)^3 - (1)^3 - 3(100)(1)(100 - 1)

=> 1000000 - 1 - 3(100)(100 - 1)

=> 1000000 - 1 - 300 (99)

=> 1000000 - 1 - 29700

=> 970299 Ans.

Answer:

The correct function is

\(f(b) = {b}^{2} - 4\)

Answer:

P(A|B) =  1/2

Step-by-step explanation:

Sample space for B = {10, 20, 30, 40, 50, 60, 70, 80}

where B is even

Total number of elements in sample space = 8

P(A|B) = Probability of a number being 40 or less from the sample space of 8

Sample space for A|B  = {10, 20, 30, 40}

So out of a possible 8 elements in the sample space for B only 4 elements can be chosen for the sample space of A

So P(A|B) = 4/8 = 1/2

Answer:

\(x^{2} -2x-4=0\)

Solving Steps

Use the quadratic formula

\(x=\frac{-(-2)(+/-)\sqrt{(-2)^2-4*1*(-4)} }{2*1}\)

Multiply / Remove the parentheses / Evaluate

\(x=\frac{2(+/-)\sqrt{4+16} }{2}\)

Calculate

\(x=\frac{2(+/-)\sqrt{20} }{2}\)

Separate the solutions

\(x=\frac{2(+/-)2\sqrt{5} }{2} \\x=\frac{2-2\sqrt{5} }2}\)

Simplify

\(x=1+\sqrt{5} \\x=1-\sqrt{5}\)

The mean is 0.477514 (rounded to 6 decimal places).

The standard deviation is 0.288919 (rounded to 6 decimal places).

To calculate the mean and standard deviation, we will use the following formulas:

Mean = (sum of all values) / (number of values)

Standard deviation = sqrt[(sum of (value - mean)^2) / (number of values)]

Using these formulas, we can calculate the mean and standard deviation for the given set of random numbers:

Mean = (0.937776 + 0.270012 + 0.243785 + 0.590701 + 0.824982 + 0.131805 + 0.879337 + 0.741998 + 0.254683 + 0.080259 + 0.419321 + 0.928220 + 0.958430 + 0.980182 + 0.263900 + 0.063119 + 0.762096 + 0.485612 + 0.662900 + 0.362242 + 0.724796 + 0.307736 + 0.305021 + 0.417052 + 0.054337 + 0.323357 + 0.069662 + 0.843387 + 0.353107 + 0.074262 + 0.735596 + 0.175095 + 0.390508 + 0.668932 + 0.029861 + 0.205228 + 0.387740 + 0.962169 + 0.646565 + 0.423914 + 0.754782 + 0.156719 + 0.773113 + 0.546335 + 0.323573 + 0.649740 + 0.214082 + 0.382383 + 0.383982 + 0.030539) / 50 = 0.477514

Therefore, the mean is 0.477514 (rounded to 6 decimal places).

Now we will calculate the standard deviation:

Standard deviation = sqrt[((0.937776 - 0.477514)^2 + (0.270012 - 0.477514)^2 + (0.243785 - 0.477514)^2 + ... + (0.382383 - 0.477514)^2 + (0.383982 - 0.477514)^2 + (0.030539 - 0.477514)^2) / 50] = 0.288919

Therefore, the standard deviation is 0.288919 (rounded to 6 decimal places).

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Answer:

2+1 equal to 4 than 3+1 equal to 4 then 21+6 equals to 27

Answer:

\(\frac{43}{3}\)

Step-by-step explanation:

21/2 + 11/3 + 1/6

Least common multiple of 2 and 3 is 6. Convert \(\frac{21}{2}\) and \(\frac{11}{3}\) to fractions with denominator 6.

\(\frac{63}{6}\) + \(\frac{22}{6}\) + \(\frac{1}{6}\)

Since \(\frac{63}{6} and \frac{22}{6}\) have the same denominator, add them by adding their numerators.

\(\frac{63 + 22}{6}\) + \(\frac{1}{6}\)

Add 63 and 22 to get 85.

\(\frac{85}{6}\) + \(\frac{1}{6}\)

Since \(\frac{85}{6} and \frac{1}{6}\) have the same denominator, add them by adding their numerators

\(\frac{85 + 1}{6}\)

Add 85 and 1 to get 86.

\(\frac{86}{6}\)

Reduce the fraction \(\frac{86}{6}\) to lowest terms by extracting and canceling out 2.

\(\frac{43}{3}\)

Answer: 106

Step-by-step explanation: 12x10=120 7x2=14 120-14=106

Answer:

\(A_{shaded} = 106\ m^2\)

Step-by-step explanation:

Step 1:  Get the area of the inside box

\(A=l*w\)

\(A_{inside\ box} = 7\ m* 2\ m\)

\(A_{inside\ box} = 14\ m^2\)

Step 2:  Get the area of the outside box

\(A = l * w\)

\(A_{outside\ box} = 12\ m * 10\ m\)

\(A_{outside\ box} = 120\ m^2\)

Step 3:  Subtract the inside box from the outside box

\(A_{shaded} = A_{outside\ box} - A_{inside\ box}\)

\(A_{shaded} = 120\ m^2 - 14\ m^2\)

\(A_{shaded} = 106\ m^2\)

Answer:  \(A_{shaded} = 106\ m^2\)

A, B and C working together will finish same piece of work in 10 days

A can do a piece of work in 20 days. That is A is doing the work at a rate of  1 / 20. Therefore

B = 1 / 30

C = 1 / 60

A, B and C working togehter their rate will be added together =

A + B + C =  1 / 20 + 1 / 30 + 1 / 60 = 1 / 10

so they can work together to finish same piece of work in 10 days

Answer:

1=2=3==929061()7292

Answer:

58.333333333333

Answer:

58.3 repeating

Step-by-step explanation:

Answer:

69-46x y57 -8r8o 98-225+

The TRUE statements about the inequality y ≤ 150x - 3100 are:

Inequality refers to a mathematical statement claiming the inequality of two or more mathematical expressions.

The following types and inequality symbols represent inequalities:

Check:

Ordered pairs (40, 2900)

y ≤ 150x - 3100

y ≤ 150(40) - 3100

y ≤ 6,000 - 3100

y ≤ 2900

Thus, the true statements about this inequality are Options A and E.

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The discrete probability distribution is given as follows:

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes.

There are 153 nests, hence the distribution in this problem is constructed dividing each of the amounts by 153, as follows:

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Answer:

0.381mm or 0.015in

Step-by-step explanation:

no. of papers in the stack-700

total length of stack-10.5in

thickness of single piece of paper= 10.5/700= 0.015in=0.381mm

Answer:

Hope it helped brainiest plz

Step-by-step explanation:

7,000,000

200,000

50,000

8,000

600

30

Answer:

8(5*3)+(2*5)+(2*10)=360

Step-by-step explanation:

8(15)+(10)+(20)=

8(45)=

Answer:

The correct to you question is 360

Step-by-step explanation:

Answer:

Smily face=5 lightning=8

Step-by-step explanation:

5+5=10 8x3=24      24+10=34

8x5=40              5x8=40

Answer:

-6 duh its easy right

Step-by-step explanation:

Answer:

Graph D is the correct answer

Step-by-step explanation:

The graph of is attached.

The y-axis of the graph represents the cost, and the x-axis represents the number of minutes.

Also, the slope of is 2, and the y-intercept is 2.

Now let us look at the choices given and determine which graph represents the function .

The first graph has the slope of 2, and a y-intercept of 2, but the y-axis represents minutes, and the x-axis represents cost—this does not match our graph.

The second graph has y-intercept of 3—also not our graph.

The third graph also has a y-intercept of 3—this does match our graph either.

The fourth graph has a y-intercept of 2 and a slope of 2, and its y-axis represents the cost and x-axis represents the minutes—this perfectly matches our graph.

Therefore, the graph that matches our graph is D.

Answer:

Eleven Fourteenths

Step-by-step explanation:

Convert 2/7 into 4/14 to get a common denominator then add 4 and 7 to get 11/14

Answer:

c

Step-by-step explanation:

i took the test

After 4 years of saving $315 per month at 7% annual interest rate, Bernard will have saved approximately $10,864.11.

To calculate the amount that Bernard will have saved after 4 years, we can use the formula for compound interest:

A = P(1 + r/n\()^{(nt)\)

Where:

A = the amount of money Bernard will have saved after 4 years

P = the amount of money Bernard is putting into savings each month = $315

r = the annual interest rate = 7% = 0.07

n = the number of times interest is compounded per year (monthly compounding in this case) = 12

t = the number of years = 4

Substituting the given values into the formula, we get:

A = 315(1 + 0.07/12\()^{(12\times 4)\)

A = 315(1.00583333\()^{48\)

A = 315(1.31564)

A = $10,864.11

Therefore, after 4 years of saving $315 per month at 7% annual interest rate, Bernard will have saved approximately $10,864.11.

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Answer: The area is 3/10

Step-by-step explanation: The area of a rectangle is length*width, so you multiply (6/8)*(4/10), multiply the numerators and denominators. It simplifies to 24/80, then reduce the fraction, you get 3/10.

The two column proof showing that  ΔWXZ ≅ ΔYXZ is as shown below

From the given triangle, we see that;

Given: WX ≅ XY, XZ bisects WXY

Prove: ΔWXZ ≅ ΔYXZ

The two column proof for the above is as follows;

Statement 1;  WX ≅ XY, XZ bisects 2

Reason 1; Given

Statement 2: ∠WXZ ≅ YXZ

Reason 2; Angle bisector

Statement 3; XZ ≅ XZ

Reason 3: Reflexive property of congruence

Statement 4:  ΔWXZ  ≅ ΔYXZ

Reason 4:  SAS Congruence Postulate

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The equation y = \(-0.024x^2\) + 0.0791x + 4.873 represents a quadratic function with a downward-opening parabol

The given expression is a quadratic equation in the form y = -0.024x^2 + 0.0791x + 4.873. Let's analyze its components and characteristics.

The equation represents a quadratic function, where x is the independent variable and y is the dependent variable. The coefficients in front of each term determine the shape, position, and direction of the graph.

The term with the highest power of x is -0.024x^2, which indicates a downward-opening parabola. The coefficient -0.024 determines the steepness of the curve. A negative coefficient means the parabola is concave down.

The term 0.0791x is the linear term and determines the slope of the line. A positive coefficient indicates an upward or positive slope. It affects the overall direction and position of the graph.

The constant term 4.873 is the y-intercept. It indicates the point at which the graph intersects the y-axis when x = 0.

To analyze the graph of the quadratic equation further, we can calculate the vertex. The x-coordinate of the vertex can be found using the formula x = -b/(2a), where a and b are the coefficients of x^2 and x, respectively. In this case, a = -0.024 and b = 0.0791. Substituting these values into the formula, we have x = -0.0791 / (2 * -0.024) ≈ 1.643. By substituting this x-coordinate into the equation, we can find the y-coordinate of the vertex.

Overall, the equation y =\(-0.024x^2 + 0.0791x\) + 4.873 represents a quadratic function with a downward-opening parabola. The specific properties, such as the vertex and other key points, can be determined by further calculations and analysis of the equation.

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The equation describing the relationship between the elapsed time and the amount of glucose remaining in the bag is: g = 120 - 1.02t

What is an equation ?

In mathematics, an equation is a statement that shows the equality between two expressions containing variables. It is typically written as a combination of numbers, variables, and mathematical symbols, such as addition, subtraction, multiplication, and division.

Here is a table comparing the elapsed time with the amount of glucose given to the patient:

Time (minutes) Glucose remaining in bag (cc)

0 120

1 119.98

2 119.96

3 119.94

4 119.92

... ...

t 120 - 1.02t

The equation describing the relationship between the elapsed time and the amount of glucose remaining in the bag is: g = 120 - 1.02t

where g represents the amount of glucose remaining in the bag in cc and t represents the elapsed time in minutes.

Hence,  The equation describing the relationship between the elapsed time and the amount of glucose remaining in the bag is: g = 120 - 1.02t

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