Answer:
d - A substance made of two or more types of atoms that are not chemically bonded
Explanation:
i got a 100% on the quiz
A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for the projectile to hit the ground, to the nearest tenth of a second. Record your answer in the boxes below. Be sure to use the correct place value.
Answer:
0.6 seconds
Explanation:
The time to fall from height h is ...
t = √(2h/g)
t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s
It would take about 0.6 seconds for the projectile to hit the ground.
Answer:
0.6 seconds
is ur answer :)
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1. If the dielectric becomes damaged it can 'break down' like the air does when lightning strikes. What would happen to the charge on the plates?
2. Here are some statements about how an image is produced and processed in a digital camera.
A) Starting in one corner the charge on each square is moved off the CCD.
B) Light enters the camera.
C) That signal can be stored or sent to a computer or other device.
D) The charges on each square are converted into a digital signal.
E) When the light hits a square on the CCD charge is produced.
a. They are in the wrong order. Write the letters for the statements in the correct order.
b. Explain why there is a delay between taking one photograph with a digital camera and taking the next photograph.
Answer:
Explanation:
A) E) When the light hits a square on the CCD charge is produced
B) A) Starting in one corner the charge on each square is moved off the CCD
C) D) The charges on each square are converted into a digital signal
D) B) Light enters the camera
E) C) That signal can be stored or sent to a computer or other device
b. The delay between taking one photograph with a digital camera and taking the next photograph is due to the time it takes to capture the image and process it into a digital signal. This process includes the capturing of the light entering the camera, the conversion of the charges on each square of the CCD into a digital signal, and the storage or sending of the signal to a computer or other device.
In the figure shown, if angle i is increased, angle r will _____.
Answer: I am assuming it is decreases
Explanation: a straight line is 180 degrees. 2 angles both add up to 180 degrees on a straight line. When one increases, the other has to decrease to keep it 180 degrees on a straight line
Find the net force and direction in the picture below.
Net force = 4 N
Direction is right
Answer: 4N right
Explanation:
A steam power plant operates between the pressure limit of 3.0 Mpa for the boiler and 75 kPa for the condenser. The plant operates in an ideal Rankine cycle with reheater with superheated vapor enters the high pressure turbine at 3 Mpa and 300 oC, and leaves at 1 MPa. Steam is then reheated at constant pressure to 300 oC before it is expanded to 75 kPa in a low pressure turbine. Determine:
a. the moisture content at the inlet of the condanger.
b. the met works per unit mare of steam tomane In Site.
c. the heat transter to the steam in the boter in lal per ke of steam.
d. the thermal efficiency
e. the heat transfer to cooling water passing through the condenser, in kJ per kg of steam flowing.
The dryness fraction is 0.96. Using steam tables the enthalpies at points 2, 3, and 4 can be calculated as 2936.4 kJ/kg, 2892.3 kJ/kg, and 1039.2 kJ/kg, respectively. The value of q is found to be 1438.3 kJ/kg.
a) 0.2, b) 2687 kJ/kg, c) 0.16 kJ/kg.K, d) 32%, e) 2549.52 kJ/kgPart (a): The steam is superheated at 300°C and 3 MPa, using steam tables it can be seen that the dryness fraction is 0.96.Part (b): This can be calculated using the formula shown below. The net work done by the turbine is given as follows: Net work = m (h1 - h2) + m (h3 - h4) Where m is the mass of the steam entering the turbine and h1, h2, h3, and h4 are the enthalpies at the different points in the cycle.h1 is given as 3478 kJ/kg, and using steam tables the enthalpies at points 2, 3, and 4 can be calculated as 2936.4 kJ/kg, 2892.3 kJ/kg, and 1039.2 kJ/kg, respectively.
Substituting the values in the formula gives the answer as 2687 kJ/kg.Part (c): Heat transfer per unit mass of steam to the boiler can be calculated using the formula shown below:q = h1 - h4 The value of q is found to be 1438.3 kJ/kg. Part (d): The thermal efficiency of the cycle can be calculated using the formula shown below: Efficiency = Net work output/ Heat inputHeat input can be calculated as follows: Heat input = m (h1 - h4) + m (h3 - h2) The value of heat input is calculated to be 4485.4 kJ/kg Substituting the values in the formula gives the answer as 32%.Part (e): The heat transfer to cooling water passing through the condenser is given as follows:q = m (h4 - h5)Where h4 is 1039.2 kJ/kg and h5 is 48.72 kJ/kg. The value of q is calculated to be 2549.52 kJ/kg.
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determine a vector expression for the induced electric field for , where is the distance from the central axis.
The vector expression for the induced electric field E is E = (-dΦ/dt) * (1/2πr) * (_r), where Φ is the magnetic flux, r is the distance from the central axis, and _r is the radial unit vector.
To determine the vector expression for the induced electric field, follow these steps:
1. Find the magnetic flux Φ, which is given by the integral of the magnetic field B over the area A: Φ = ∫B⋅dA.
2. Calculate the rate of change of the magnetic flux with respect to time, dΦ/dt.
3. Use Faraday's law of electromagnetic induction, which states that the induced electric field E is equal to the negative rate of change of the magnetic flux: E = -dΦ/dt.
4. Express the electric field E in terms of the distance r from the central axis by using the expression E = (-dΦ/dt) * (1/2πr).
5. Finally, include the radial unit vector _r to express the electric field in vector form: E = (-dΦ/dt) * (1/2πr) * (_r).
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Noting the main sequence turnoff mass in a star cluster allows you to determine its a) distance. b) total mass. c) age. d) radial velocity.
The correct option is c) age. Noting the main sequence turnoff mass in a star cluster provides an estimate of the age of the cluster. The main sequence turnoff point is the point at which stars exhaust the hydrogen in their cores and begin to evolve away from the main sequence.
The mass of the star at the turnoff point is related to the age of the cluster, with higher-mass stars evolving off the main sequence more quickly than lower-mass stars.
Therefore, by determining the mass of stars at the turnoff point, astronomers can estimate the age of the star cluster.
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A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
Complete Question
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
Answer:
The value is \(T_R = 11.8 \ days\)
Explanation:
From the question we are told that
The semi - major axis of the rocky debris \(a_R = 45.0\ AU\)
The semi - major axis of Planet D is \(a_D = 60 \ AU\)
The orbital period of planet D is \(T_D = 18.164 \ days\)
Generally from Kepler third law
\(T \ \ \alpha \ \ a^{\frac{3}{2} }\)
Here T is the orbital period while a is the semi major axis
So
\(\frac{T_D}{T_R} = \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}\)
=> \(T_R = T_D * [\frac{a_R}{a_D} ]^{\frac{3}{2} }\)
=> \(T_R = 18.164 * [\frac{ 45}{60} ]^{\frac{3}{2} }\)
=> \(T_R = 11.8 \ days\)
The orbital period of the rocky debris in space is 12 days.
From Kepler's law, we know that the square of the period of a planet in years is equal to the cube of its mean distance from the sun in astronomical units (AU).
Mathematically;
\(T^2 = r^3\)
Now, we have the mean distance as 45.0 AU, we need to obtain its period.
semi major axis of debris rR= 45.0 AU
semi major axis of planet D rD = 60 AU
Period of planet D TD = 18.164 days
Period of debris TR = ?
\(\frac{TR^2}{TD^2} = \frac{rR^3}{rD^3}\)
\(\frac{rR^3}{rD^3} * TD^2\)
\(TR^2 = 45^3/60^3 * 18.164^2\)
TR = 12 days
Missing parts:
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
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a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
Formula
F = E×Q .......................... Equation 1
Where:
F = Force on the chargeE = Electric FieldQ = chargeFrom the question,
Given:
E = 200 N/CQ = -0.06 CSubstitute these values into equation 1
F = 200(-0.06)F = -12 NNote: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
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Answer: A edge 202694020
Explanation:
what are the eigenvalues of the angular momentum operator? what are the eigenvalues of the projection of the angular momentum on the z-axis?
The eigenvalues of Lz are given by ℏ times the possible values of m. The allowed values of m range from -l to l, inclusive, where l is the orbital angular momentum quantum number.
The eigenvalues of the angular momentum operator are given by the equation L^2 |lm> = l(l+1)|lm>, where L^2 is the square of the angular momentum operator and l(l+1) is the eigenvalue. The eigenvalues of the projection of the angular momentum on the z-axis are given by the equation Lz |lm> = m|lm>, where Lz is the projection of the angular momentum operator on the z-axis and m is the eigenvalue. The eigenvalues of the angular momentum operator and the projection of the angular momentum on the z-axis are related, as the magnitude of the angular momentum L is given by L^2 = Lx^2 + Ly^2 + Lz^2 and the eigenvalues of L^2 and Lz are related to the same quantum numbers l and m.
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the information on a compact disk is scanned by a laser initially at a radius of 2.4 cm and then out to a maximum of 6.0 cm. because the dimensions of the pit information remain constant with radius, the disk motor adjusts so that the tangential velocity remains constant. what is the ratio of the inner to outer rotational frequencies?
The ratio of the inner to outer rotational frequencies is 2.5.
The ratio of the inner to outer rotational frequencies in a compact disk can be calculated using the concept of conservation of angular momentum. When the laser initially scans the disk at a radius of 2.4 cm, the angular velocity of the disk is given by ω1. As the laser moves outwards to a maximum radius of 6.0 cm, the angular velocity of the disk decreases to ω2 due to the conservation of angular momentum. The ratio of the inner to outer rotational frequencies in a compact disk can be found using the concept of conservation of angular momentum and the constant tangential velocity of the disk.
The tangential velocity of the disk, however, remains constant as the dimensions of the pit information on the disk remain constant with radius. This means that the product of the tangential velocity and the radius of the disk is constant, i.e., v1r1 = v2r2.
Using these equations, we can find the ratio of the inner to outer rotational frequencies as
ω1/ω2 = r2/r1 = 6.0 cm/2.4 cm = 2.5.
This means that the inner part of the disk rotates 2.5 times faster than the outer part of the disk. This is because the outer part of the disk has a larger radius and therefore, a larger circumference to cover in the same amount of time as the inner part of the disk.
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Jasmine, a san francisco hot dog vender, has fallen asleep on the job. when an earthquake strikes, her 327 kg hot dog cart rolls down nob hill and reaches point a at a speed of 2.9 m/s. how fast is the hot dog cart going at point b when jasmine finally wakes up?
The speed of the hot dog cart going at point B wen jasmine finally wakes up is 21.36 m/s.
Mass of the cart = m = 327 Kg
Speed of the cart while rolling downhill = v = 2.9 m/s
Height of the hill = h = 50 m
Height at point B = h' = 30 m
Speed of the cart when jasmine wakes up = v' =
Using the conservation of energy theorem,
= sum of kinetic and potential energy initially = sum of kinetic energy finally at point B
= mgh + (1/2)mv² = (1/2)mv'²
= gh + (1/2)v² = (1/2)v'²
= 9.81 X (50-30) + (1/2) X 2.9² = (1/2)v'²
= v'² = 21.36 m/s
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a. If a metal with a higher specific heat was used, would this raise or lower the final water temperature? Explain.b. If 50 g of water was used instead of 100 g, would this raise or lower the final temperature? Explain.
a. Specific heat is a property that determines how much energy a substance needs to absorb to increase its temperature by one degree Celsius. Thus, if a metal with a higher specific heat was used, it would require more energy to increase its temperature compared to a metal with a lower specific heat.
When the metal is placed in contact with the water, the energy is transferred from the metal to the water. Therefore, if the metal has a higher specific heat, it will transfer more energy to the water, resulting in a higher final temperature.
For example, copper has a specific heat of 0.385 J/g°C, while aluminum has a specific heat of 0.903 J/g°C. Thus, if aluminum was used instead of copper, it would result in a higher final temperature of the water.
b. The amount of energy required to raise the temperature of a substance depends on its mass, specific heat, and the temperature difference. If the mass of the substance is lower, it requires less energy to increase its temperature compared to a larger mass.
Thus, if 50 g of water was used instead of 100 g, the same amount of energy would increase the temperature of the water more quickly, resulting in a lower final temperature.
For example, if 100 g of water is heated with 100 J of energy, it would increase its temperature by 1°C. However, if 50 g of water is heated with the same amount of energy,
it would increase its temperature by 2°C. Therefore, using 50 g of water would result in a lower final temperature compared to using 100 g of water.
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calculate approximately how long it takes light to travel from the sun to pluto
It takes approximately 5.5 hours for light to travel from the Sun to Pluto
The distance from the Sun to Pluto varies depending on the positions of the two objects in their orbits, as both the Sun and Pluto are constantly moving. However, on average, the distance from the Sun to Pluto is about 5.9 billion kilometers or 3.7 billion miles.
The speed of light is approximately 299,792 kilometers per second or 186,282 miles per second.
Using these values, we can calculate that it takes approximately 5.5 hours for light to travel from the Sun to Pluto
5.9 billion km ÷ 299,792 km/s
=> 19710 seconds
=> 5.5 hours.
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an old car with worn-out shock absorbers oscillates with a given frequency when it hits a speed bump. ifthe driver adds a couple of passengers to the car and hits another speed bump, is the car's frequency ofoscillation greater than, less than, or equal to what it was before? explain.
An oldcar with worn-out shock absorbers oscillates with a given frequency when it hits a speed bump. If the driver adds a couple of passengers to the car and hits another speed bump. The car's frequency of oscillation will less then if the driver adds a few passengers to the car and hits another speed bump.
When the car hits the speed bump, its undercarriage moves up and down, creating an oscillation. The car's suspension system, which includes shock absorbers, springs, and tires, absorbs and dampens the energy generated by the oscillations. In this case, since the shock absorbers are worn-out, they are less effective in dampening the oscillations.
As a result, the oscillation frequency of the car is greater. If the driver adds a few passengers to the car, the weight of the car increases. When the car hits the speed bump again, the oscillation frequency decreases due to the greater weight. This is due to the fact that the suspension system absorbs more energy due to the added weight, causing the oscillation to be reduced. As a result, the frequency of oscillation of the car is less than what it was before.
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find the magnitude, fnet , of the sum of all forces acting on the block. express fnet in terms of θ and m , along with any necessary constants.
With the addition of any required constants, the magnitude of the total force acting on the block, fnet, can be expressed in terms of and m as follows: fnet = Tcosθ - mg = mg/cosθ * cosθ - mg = mg(1 - cosθ)
To find the magnitude of the sum of all forces (fnet) acting on the block, we need to calculate the vector sum of all the forces acting on the block. The forces acting on the block include its weight (mg) and the tension in the string (T), which is at an angle θ with respect to the horizontal. We can resolve the tension force into its horizontal and vertical components as Tcosθ and Tsinθ, respectively.
Since the block is in equilibrium, the net force acting on the block must be zero. Therefore, we can write:
fnet = Tcosθ - mg = 0
Solving for T, we get:
T = mg/cosθ
Substituting the value of T in terms of mg/cosθ into the vertical component of the tension force (Tsinθ), we get:
Tsinθ = mgsinθ/cosθ = mgtanθ
Therefore, the magnitude of the sum of all forces acting on the block, fnet, can be expressed in terms of θ and m, along with any necessary constants, as:
fnet = Tcosθ - mg = mg/cosθ * cosθ - mg = mg(1 - cosθ)
Alternatively, we can also express fnet in terms of the vertical component of the tension force:
fnet = Tsinθ + mg = mgtanθ + mg = mg(tanθ + 1)
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A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction between the wedge and the block or between the wedge and the horizontal surface.
Find the magnitude, Fnet, of the sum of all forces acting on the block.
Express Fnet in terms of θ and m, along with any necessary constants.
Find the magnitude, Fww, of the force that the wall exerts on the wedge.
Express Fww in terms of θ and m, along with any necessary constants.
Two coils A and B are wound side by side. Coil A has 8120 turns and coil B has 11842 turns. 54% of flux produced by coil A links coil B. A current of 6 A in coil A produces 0.02 mWb, while the same current in coil B produces 0.078 mWb. a) Calculate the mutual inductance and the coupling coefficient. b) Calculate the emf induced in coil B when the current is reversed in 0.015 seconds.
a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.
a) Mutual inductance, M between coil A and coil B can be given as:
M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,
So, K = 0.54
L_A = N_A Φ/I_AL_A
= 8120 × 0.02/6
= 27.07 mH
L_B = N_B Φ/I_BL_B
= 11842 × 0.078/6
= 154.63 mH
M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H
b) The emf induced in coil B can be given as:-
ε = M (dI_B/dt)/L_B
ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V
Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.
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Julie carries an 8. 0-kg suitcase as she walks 18 m along a horizontal walkway to her hotel room at a constant speed of 1. 5 m/s. How much work does julie do in carrying her suitcase?.
Main Answer(final answer)- work done by julie is zero
Supporting answer- The work done by a force is defined as the product of the force's component in the direction of displacement and the magnitude of displacement. Formula. Work can be calculated by multiplying Force by Distance in the force's direction, as shown below. W = F × d.
Body of solution- as Julie walking at constant speed, net work done by her is zero.
Forces acting on suitcase are
1. Gravitational force
2. Force applied by Julie
As gravitational force is perpendicular to displacement, work done by gravity is zero
As work done by Julie and gravity are both zero
final answer -Hence work done by julie is zero
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when calculating the total weight the ladder is to support, you must include:
The weight of the person(s) using the ladder, as well as the weight of any tools or materials being carried up the ladder.
What factors should be considered when calculating the total weight a ladder needs to support?When using a ladder, it is important to calculate the total weight it needs to support to ensure safety and stability. In addition to the weight of the person(s) using the ladder, the weight of any tools or materials being carried up the ladder must also be taken into account.
Neglecting to consider these factors can lead to a ladder being overloaded, which can cause it to become unstable and increase the risk of falls or other accidents.
It is also important to choose the right type of ladder for the job, as different ladders have different weight capacities and maximum load ratings. When in doubt, it is always better to err on the side of caution and choose a ladder with a higher weight capacity than you think you will need.
By taking the time to properly calculate the total weight a ladder needs to support, you can ensure that you are using it safely and reduce the risk of accidents or injuries.
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PLS HELP!!! WILL GIVE BRAINLIEST
Sanzida conducted an experiment that required a wire carrying a current to be wrapped around a metal core. When she placed the South Pole of a bar magnet near the top of the metal rod, she observed the magnet move toward the rod. Which conclusion can Sanzida draw from this experiment?
A) the current in the wire has created a gravitational field with its South Pole at the top of the rod
B) the current in the wire has created a magnetic field with its South Pole at the top of the rod.
C) the current in the wire has created a magnetic field with its North Pole at the top of the rod.
D) The current in the wire has created a gravitational field with its North Pole at the top of the rod
Answer:
did you ever get the answer
The current in the wire has created a magnetic field with its north pole at the top of the rod. This is because the magnetic field influences electric currents. Thus, the correct option is C.
What is a magnetic field?A magnetic field is a vector field which describes the magnetic influence on a moving electric charge, electric current, and magnetic material. A moving charge in a magnetic field which is experienced a force perpendicular to the own velocity and to the magnetic field.
The magnetic field is also referred to as the field where magnetic forces act to shape an electrical current. The only material or body which is capable of altering an electrical current in a magnetic field is the presence of another magnetic field in the space.
Therefore, the correct option is C.
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A student environmental group is creating a campaign for locally sourced energy resources.What would be best for them to feature in their campaign?a coal mine located in their countya farmer with a field of solar panelsa company building a gas pipeline through the towna rancher drilling for oil in a horse pasture
Answer:
A farmer with a field of solar panels.
Explanation:
The closest to a locally sources energy would have been
A coal mine located in their county.
But coal as an energy source is not environmentally friendly due to carbon emission, and should not be what the group should advocate for.
The best bet for them is
A farmer with a field of solar panels.
As solar panels are a source of green energy and green energy is what the environmental group should often and always advocate for
2
A simple circuit contains a battery and a resistor.
Over 3.0 hours, 29 000 C of charge passes through the resistor.
Calculate the current flowing through the circuit during this time.
Give your answer to two significant figures.
Answer:
Approximately \(2.69\; {\rm A}\).
Explanation:
Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:
\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).
Electric current \(I\) is the rate of flow of electric charge.
In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:
\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).
Find the Fourier transform of the function, x(t) = u(t)-2u(t-1)+u(t-2) Q2. Find the Fourier transform of the function using Fourier integral, x(t)=e" u(-t), a > 0 What is the significance of the condition a>0 here?
The Fourier transform of x(t) can be determined as \(1/(j\omega) - 2e^{-j\omega + e^{-2j\omega}\), where j is the imaginary unit. In the case of the function x(t) = \(e^{-a\timest}u(-t),\) where a > 0, the significance of the condition a > 0 is related to the convergence of the Fourier integral.
To find the Fourier transform of x(t) = u(t) - 2u(t-1) + u(t-2), we start by evaluating the transform of each term individually. The Fourier transform of the unit step function u(t) is given by 1/(jω) + πδ(ω), where j represents the imaginary unit, ω is the angular frequency, and δ(ω) is the Dirac delta function.
Using the linearity property of the Fourier transform, we can find the transform of each term in x(t) separately. The first term, u(t), gives us 1/(jω) + πδ(ω). For the second term, u(t-1), we use the time-shifting property of the Fourier transform, which states that \(e^{-j\omega t}\) transforms to E(ω)\(e^{-j\omega t}\), where E(ω) is the Fourier transform of the function. By applying the time-shifting property, we obtain \(-2e^{-j\omega}e^{-j\omega}\). Similarly, for the third term, u(t-2), we have \(-e^{-2j\omega}e^{-j\omega t}\).
Combining these results, the Fourier transform of x(t) is given by 1/(jω) - \(2e^{-j\omega} + e^{-2j\omega}\), where j is the imaginary unit. This represents the frequency domain representation of the original function x(t).
In the case of the function x(t) = \(e^{-a\times t}u{-t}\), where a > 0, the significance of the condition a > 0 is related to the convergence of the Fourier integral. For the Fourier transform to exist, the function must decay sufficiently fast as t approaches infinity. By imposing the condition a > 0, we ensure that the exponential term decays exponentially as t increases, which guarantees convergence of the integral. Without this condition, the Fourier transform may not exist or may yield a result that is not well-defined.
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What do you put in the bowl first? milk or cereal?
Answer:
i put cereal first
Explanation:
cereal
Rank the following objects in order of their circular velocities, from smallest to largest.a. a 5 -kg object orbiting Earth halfway to the Moonb. a 10 -kg object orbiting Earth just above Earth's surfacec. a 15 -kg object orbiting Earth at the same distance as the Moond. a 20 -kg object orbiting Earth one-quarter of the way to the Moon
The required order of circular velocities, from smallest to largest is calculated to be d < a < c < b, where, a, b, c, d are the given options.
The velocity equation for the objects moving in circular motion is given by the equation,
v = √(G m/r)
where,
v is the velocity
G is the Gravitational constant
m is the mass of the object
r is the radius of the orbit
a. A 5 kg object halfway to the Moon circling the Earth
In this case, the radius of the orbit is the half of the distance between the Earth and the moon.
r = distance between earth and moon/2 = 384400000 m/2 = 192200000 m
So, v₁ = √(G m/r) = √(6.67408× 10⁻¹¹ × 5/192200000) = 1.317 × 10⁻⁹ m/s
b. A 10-kilogram object is circling the planet just above its surface
The orbit's radius is similar to the size of the planet Earth.
r = r earth = 6371000 m
So, v₂ = √(G m/r) = √(6.67408× 10⁻¹¹ × 10/6371000) = 1.02 × 10⁻⁸ m/s
c. A 15 kg object circling the Earth at a distance equal to that of the Moon
r = distance between the earth and the moon = 384400000 m
So, v₃ = √(G m/r) = √(6.67408× 10⁻¹¹ × 15/384400000) = 1.61 × 10⁻⁹ m/s
d. A 20 kg object that is circling the Earth and is one-quarter to the Moon
r = 1/4(distance between the earth and the moon) = 384400000 m/4 = 96100000 m
So, v₄ = √(G m/r) = √(6.67408× 10⁻¹¹ × 20/96100000) = 1.17 × 10⁻⁹ m/s
Thus, v₄ < v₁ < v₃ < v₂. And the order of options are d < a < c < b.
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Integrated Concepts:_______.
(a) Calculate the ratio of the highest to lowest frequencies of electromagnetic waves the eye can see, given the wavelength range of visible light is from 380 to 760 nm.
(b) Compare this with the ratio of highest (20,000 Hz) to lowest (20 Hz) frequencies the ear can hear.
a). frequency = (speed) / (wavelength)
The speed of light is around 3 x 10⁸ m/s.
For 380 nm (violet light), frequency = (3 x 10⁸ m/s) / (380 x 10⁻⁹ m)
Frequency = 7.89 x 10¹⁴ Hz
For 760 nm (red light), frequency = (3 x 10⁸ m/s) / (760 x 10⁻⁹/s)
Frequency = 3.94 x 10¹⁴ Hz
The ratio is 2 .
That's 1 octave, or 0.3 of a decade.
b). The ratio of highest/lowest sounds is (20,000 Hz/20 Hz) = 1,000
That's 3 decades, or about 10 octaves.
===> Speaking logarithmically ( ! ), ears are sensitive to a range of sound frequencies that's 10 times as wide as the range of light frequencies that eyes can detect.
Which term is the rate at which work is done?
a. energy
b. power
c. joules
d. force
The rate at which work is completed is indicated by the power word, hence option b is correct. Power, which can be defined as the amount of work done W.
Is the time rate at which the job is completed or energy is given. Energy transferred, expressed as W/t or energy transferred against the time interval t. Work (or energy) per unit time, foot-pounds per minute, joules per second (or watts), and ergs per second are all ways to express power. Work is defined as involving both force applied to the body and displacement of the body. Consider a block that is resting on a horizontal, frictionless floor. A consistent force is acting on this block.
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Answer: B.) power
Explanation: Get dem hearts up:)
body composition is?
Answer: body composition is the proportion of fat and non fat mass in your body.
Explanation:
Answer:
Body composition is the percentage of a body's weight
Explanation:
Body composition is the body's amount of fat relative to fat-free mass. Individuals with optimal body composition are typically healthier, move more easily and efficiently, and generally feel better.
What is a scientific theory?
Answer:
Scientific theories are explanations of some aspect of the natural world based on repeated observations.
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Answer:
The way that scientists use the word 'theory' is a little different than how it is commonly used in the lay public," said Jaime Tanner, a professor of biology at Marlboro College. "Most people use the word 'theory' to mean an idea or hunch that someone has, but in science the word 'theory' refers to the way that we interpret facts.
Explanation:
A tennis player can accelerate a tennis ball at 295m/s² using an average force of
58 N with his racquet. What is the mass of the tennis ball?
answer of the question is into the picture ️