Which of the following is the best explanation of work?

A. Work occurs when energy acts on an object.

B. Work occurs when a force acts on an object.

C. Work occurs when energy is exerted.

D. Work occurs when a force acts on an object and causes a displacement of that
object.

E. Work occurs when force acts to hold an object in place.

Answers

Answer 1

Answer:

D

Explanation:


Related Questions

How much thermal energy is needed to boil 2.65 kg of water at its boiling
point?
Use Q = mass x latent heat of vaporization.
A. 265 kJ
B. 11.1 kJ
C. 5990 kJ
D. 882 kJ

How much thermal energy is needed to boil 2.65 kg of water at its boilingpoint?Use Q = mass x latent

Answers

Answer: 5990 kJ :)

Explanation: a p e x <3

The amount of thermal energy needed to boil 2.65 kg of water at its boiling point is 5990 kJ. So, the correct answer is option C.

What is thermal energy?

Thermal energy is the energy that is generated by the movement of particles within a substance or system. It is a type of internal energy and is directly related to the temperature of the system. The faster the particles are moving, the more thermal energy the system has. Thermal energy can be transferred from one system to another through the processes of conduction, convection, and radiation. It is a form of energy that is used in many different applications, such as heating homes and buildings, powering engines, and cooking food.

Here in the Question,

To calculate the thermal energy needed to boil the water, we can use the formula,

Q = m x L

where Q is the thermal energy, m is the mass of the water, and L is the latent heat of the vaporization of water.

Q = m x L

Q = 2.65 kg x 2260 kJ/kg

Q = 5990 kJ

Therefore, 2.65 kg of water will require 5990 kJ of thermal energy to reach its boiling point.

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Use the vocabulary words from
“Read It” to complete the
following sentences.

Light from the Sun reaches Earth very
quickly. The (4)_____ is 186,000 miles per
second! We capture sunlight using
(5)_____, which are devices that use the
(6)_____ to convert light to electricity. As
atoms absorb energy, the electrons get
“excited” and release energy as (7)_____.
Whatever light that is not absorbed will
(8)_____ off the surface of the object and
bounce back toward the source.

Use the vocabulary words from Read It to complete the following sentences.Light from the Sun reaches

Answers

Answer:

Light from the Sun reaches Earth very quickly. The (4) speed of light is 186,000 miles per second! We capture sunlight using (5) solar panels, which are devices that use the (6) photovoltaic effect to convert light to electricity. As atoms absorb energy, the electrons get “excited” and release energy as (7) photons. Whatever light that is not absorbed will (8) reflect off the surface of the object and bounce back toward the source.

HURRY!!!
I need helppppp!!!

HURRY!!!I need helppppp!!!

Answers

Answer:

ok i think the answer would be C. or B. hope im right

Larry the Rock was lonely for multiple years. The inertia that Larry possessed intimated those who walked past by it, therefore people never moved Larry.
Larry constantly watched people and cars accelerate past him but sadly he has never had the opportunity to experience acceleration.
But one day, David decides to let Larry experience acceleration and tried to push him. His friend Pancho heard about this and decided to help out. But
because Pancho was not listening in Physics class, he was pushing Larry from the opposite side of David with an equal amount of force and Larry was sad
he still did not get to move.
What type of Equilibrium is Larry going through?
O Static Equilibrium
O Kinetic Equilibrium
O Dynamic Equilibrium
O Geo Equilibrium
O Francesca Equilibrium

Answers

First option is correct.Larry the Rock is going through Static Equilibrium.

In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.

Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.

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It takes 80 J to push a large box 8 m across a floor. Assuming the push is in the same direction as the move, what is the magnitude of the force on the box?

Answers

Answer:

10 N

Explanation:

The magnitude of the force on the box can be found by using the formula

\(f = \frac{w}{d} \\ \)

w is the workdone

d is the distance

From the question we have

\(f = \frac{80}{8} \\ \)

We have the final answer as

10 N

Hope this helps you

Answer:

10

Explanation:

80 divided 8 =10

Light of wavelength λ=0.01nm, is scattered at 1350 from a stationary electron. What is the kinetic energy of the recoiling electron?

Answers

Answer:

198.9 x 10^-16

Explanation:

E = hc/ wavelength

E =(6.63 x 10^-34 x 3 x 10^8)/(0.01 x 10^-9)

E = 198.9 x 10^-16

A wave has a wavelength of 1.5 meters and frequency of 125 Hz. What is the wave speed?

Answers

Just do 1.5 fidvide 125

which of the following can not happen when a light ray strikes a new medium

which of the following can not happen when a light ray strikes a new medium

Answers

Answer:

amplification

Explanation:

reflection can happen

some amount of lighr get absorbed

something gets refracted

but amplification cant

A monkey pushes a rock horizontally on a frictionless table with a net force of 10 N for 2.0 m.
How much kinetic energy does the rock gain?

Answers

Answer:

20.00

Explanation:

if the position of a body is 3m, 6m, 9m, 12m at instant 2s, 4s, 6s, 8s respectively

Answers

Answer:1.5m/s

Explanation:

lol its right

A body is travelling with a velocity 30 m/s².what will be its velocity after 4s?​

Answers

Answer:

70m/s²

Explanation:

we will use the first equation of Dalton to find it

You shake a bottle of soda and take off the cap. If the soda shoots out of the
bottle with a velocity of 17 m/s, how high will it go?
A. 16.9 m
B. 14.7 m
C. 10.6 m
D. 12.2 m

Answers

Answer:  B) 14.7 meters

============================================================

Explanation:

The bottle cap is a projectile, so we'll use the aptly named projectile formula

That formula (the meters version of it anyway) is approximately

h = -4.9t^2 + v*t + s

where,

t = elapsed time in secondsh = height at time tv = starting velocitys = starting height

We'll assume that s = 0, though realistically it's probably going to be a bit larger than this (since the person is holding it above the ground). For the sake of simplicity, we'll stick with s = 0.

We're told that the initial velocity is 17 m/s, which means v = 17.

All of that means the formula mentioned earlier updates into this:

h = -4.9t^2 + 17t

If we were to graph this, or apply the -b/(2a) formula, then you should find that the vertex occurs when t = 1.73469 approximately.

Plug this into the equation we found to get...

h = -4.9t^2 + 17t

h = -4.9(1.73469)^2 + 17(1.73469)

h = 14.7449

h = 14.7

The bottle cap will reach a peak height of approximately 14.7 meters and does so at around the 1.7 second mark. The total flight time is approximately 2*1.7 = 3.4 seconds. This all assumes that the starting height and ending height are both 0 meters off the ground.

The soda will go as high as 14.7 meters. Therefore, option (B) is correct.

What is the conservation of energy principle?

We can solve this problem using the conservation of energy principle, which states that the initial energy of a system is equal to the final energy. At the start, the soda in the bottle has some potential energy due to its position and kinetic energy due to its motion. When the soda shoots out of the bottle, it converts all of its initial energy to potential energy as it reaches its maximum height.

Using the conservation of energy, we can write:

Initial energy = Final energy

\(0.5 * m * v^2 = m * g * h\)

where m is the mass of the soda, v is its velocity, g is the acceleration due to gravity (\(9.8 m/s^2\)), and h is the height it reaches.

Solving for h, we get:

h = \((v^2)/(2g) = (17^2)/(29.8)\)= 14.7 m

Therefore, the soda will go as high as 14.7 meters. Option B is correct.

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A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?

Answers

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=


Please help and explain how to do these types of problems in very confused!!!

Answers

Answer: 1,224 km/h

Explanation:

To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
340 m/s = 1,224 km/h

What is the angular position in radians of the minute hand of a clock at 3:35?
What is the angular position in radians of the minute hand of a clock at 7:00?

Answers

Answer:

Explanation:

As with any measuring program, we need to know the origin.

If we ASSUME that zero radians is to the 12 position, then

there are 60 minutes in one minute hand revolution of an hour and 2π radians in one circle

35/60 = x/2π

x = 70π/60 = 7π/6 radians

at any exact hour, the minute hand points to the 12 so angular position is

0 + (2π)n radians  where n is any whole number.

A motor car accelerates for 10sec to attain a velocity of 20m/s. it continues with uniform velocity for a further 20sec and then decelerates so that it stops in 20sec. calculate
I) acceleration
ii) deceleration
iii) the distance traveled?​

Answers

According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

What is acceleration ?

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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You are driving at 50 m/s when you hit your brakes for 5 seconds. Your new speed is 30 m/s. What was your acceleration?A. 4 m/s2B. 16 m/s2C. -16 m/s2D. – 4 m/s2

Answers

ANSWER:

D. - 4 m/s

STEP-BY-STEP EXPLANATION:

Given:

Final velocity (v) = 30 m/s

Initial velocity (u) = 50 m/s

Time (t) = 5 s

We can determine the acceleration by the following formula:

\(\begin{gathered} a=\frac{\Delta v}{\Delta t}=\frac{v-u}{t} \\ \\ \text{ we replacing:} \\ \\ a=\frac{30-50}{5}=\frac{-20}{5} \\ \\ a=-4\text{ m/s}^2 \end{gathered}\)

The acceleration is equal to - 4 m/s², therefore, the correct answer is D.

How to solve conservation of momentum

Answers

Answer:

Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.

A person can jump a horizontal distance of 1.31 m on the Earth. The acceleration of gravity is 12.3 m/s^2.

a) How far could he jump on the Moon, where the free-fall acceleration is 0.258g Answer in units of m.

b) Repeat for Mars, where the acceleration due to gravity is 0.293g. Answer in units of m.

Answers

Answer:

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

!

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(

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^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

b) On Mars, where the acceleration due to gravity is 0.293g:

Similarly, we need to find the acceleration due to gravity on Mars:

g_Mars = 0.293g_Earth

g_Mars = 0.293(12.3 m/s^2)

g_Mars = 3.61 m/s^2

Using the same formula and rearrangement as in part a, we can find the distance he could jump on Mars:

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.61 m/s^2) / (12.3 m/s^2)

R = 0.223 m

Therefore, he could jump approximately 0.223 m on Mars.

You are a world-famous physicist-lawyer defending a client who has been charged with murder. It is alleged
that your client, Mr. Lawton, shot the victim, Mr. Cray. The detective who investigated the scene of the
crime, Mr. Dibny, found a second bullet, from a shot that missed Mr. Cray, that had embedded itself into a
chair. You arise to cross-examine the detective.
You: In what type of chair did you find the bullet?
Dinby: A wooden chair.
You: How massive was this chair?
Dinby: It had a mass of 20 kg.
You: How did the chair respond to being struck with a bullet?
Dinby: It slid across the floor.
You: How far?
Dinby: Three centimeters. The slide marks on the dusty floor are quite distinct.
You: What kind of floor was it?
Dinby: A wood floor.
You: What was the mass of the bullet you retrieved from the chair?
Dinby: Its mass was 10 g.
You: Have you tested the gun you found in Mr. Lawton's possession?
Dinby: I have.
You: What is the muzzle velocity of bullets fired from that gun?
Dinby: The muzzle velocity is 450 m/s.
With only slight hesitation, you turn confidently to the jury and proclaim, "My client's gun did not fire those
shots!"
(a) How are you going to convince the jury and judge?
(b) Choose one part of your solution and perform a sense-making analysis. Clearly state which sensemaking analysis you’ve chosen and why.

Answers

Answer:

It was not fired from the client's gun because the chair slid only 3 centimeters . If it had been fired from the client's gun the chair would slid 25.82 centimeters.

Explanation:

According to the law of conservation of momentum the momentum of the system before collision must be equal to the momentum of the system after the collision.

M1u1= m2u2

Let M1 = mass of the chair = 20kg

     m2= mass of the bullet= 10g= 0.001kg

      u1= velocity of the chair before collision = zero m/s

      u2 =  velocity of the bullet before collision = zero m/s

         v1= velocity of the chair after collision = ?  m/s  

        v2 =  velocity of the bullet after collision = 450 m/s

After collision their velocities change from u1 to v1 and u2 to v2 so

M1v1= m2v2

v1= m2v2/M1

v1= 0.01 *450/ 20=  0.225 m/s

Now according to the law of conservation of energy the energy of the system before collision must be equal to the energy of the system after the collision.

The energy of the chair after the bullet is hit is

KE of the chair + KE of the bullet=  1/2 (M)(v1)²+ 1/2 m(v2)²=

1/2 ( 20) (0.225 )² + 1/2 (0.01) (450)²

= 0.50625 + 1012.5=  1013.00625 Joules

Frictional force = Coefficient of kinetic force of wood on wood ( M+m) g

                           = 0.2* ( 20.01) 9.8=   39.2196 N

Work done by friction = frictional force * distance

If law of conservation of energy is applied  the KE  must be equal to the work done

KE = W

W= f*d

KE= F*d

d = KE/f= 1013.00625/ 39.2196= 25.82 cm

The chair did not move 25.82 cm .

It only moved 3 centimeter.

Hence the bullet fired was not from the client's gun.

If an object is placed at a distance of 10 cm in front of a concave mirror of focal length 4 cm, find the position and characteristics of the image formed. Also, find the magnification.

Answers

Answer:

Explanation:

Focal length f = - 4 cm

Object distance u = - 10 cm

v , image distance = ?

Mirror formula

\(\frac{1}{v} +\frac{1}{u} = \frac{1}{f}\)

Putting the given values

\(\frac{1}{v} - \frac{1}{10} = - \frac{1}{4}\)

\(\frac{1}{v}= - \frac{3}{20}\)

v = - 6.67 cm .

magnification

m = v / u

= - 6.67 / - 10

= .667

so image will be smaller in size in comparison with size of object .

Characteristics will be that ,

1 ) it will be inverted and

2 ) it will be real image .

Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead.
Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?

Answers

Answer: The acceleration of Kaya is .

Explanation:

Answer:

Kaya's acceleration is 1.41666667.

Explanation:

To find the acceleration we need to subtract the starting speed to the slowed speed. So 14 - 5.5 = 8.5.

Now we divide 8.5 by the time, 6 seconds.

Our final answer is 1.41666667, or rounded, 1.42.


The second step to the scientific method is:
form a hypothesis.
ask a question.
Operform a test.
share the results.

Answers

The second step of the scientific method is to form a hypothesis. Thus, the correct option for this question is A.

What is a Scientific method?

A scientific method may be defined as the complete procedure through which the objectives of any experiment are established facts through testing and experimentation. There are numerous steps of the scientific method exist.

The basic steps of the scientific methods are as follows:

Construct an observation, Form a hypothesis.Making a prediction. Conducting an experiment.Analyzing the results.

It is a systematic and well-regulated approach that involves in obtaining information about a scientific nature or obtaining a desired material or product.

Therefore, the second step of the scientific method is to form a hypothesis. Thus, the correct option for this question is A.

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1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20

Answers

Answer:

(D) x = 93.8 m

Explanation:

v^2 = v0^2 + 2ax

(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x

Solving for x,

x = 93.8 m

Which equation below is not valid for relating velocity,
time, displacement, and constant (or average)
acceleration?

Answers

Answer:(vi^2+d)^2=vf+a^2+2t

Explanation:

Which event is an example of condensation?
• A. A spilled drop of rubbing alcohol disappears.
O B. Fog forms in a valley.
• C. A puddle dries when exposed to the Sun.
D. A lake becomes a skating rink in the winter.

Correct answer B

Answers

Answer:

B. Fog forms in a valley.

Explanation:

With the maximum speed of 40 miles/hr (17.9 m/s) of your car, you can make a turn without slipping at one of the intersections near your home on a normal day. if it is raining, the road is wet and static friction is half of the normal static friction and the kinetic friction is 1/3 of normal kinetic friction. What is the maximum velocity you should have to avoid the slipping at the same intersection?

Answers

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!

HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!

Answers

I side more with B but a’s a good one

A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C​

Answers

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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AcellusVector E is 0.111 m long in a90.0.º direction. Vector Fis0.234 m long in a300° direction.Find the magnitude of theirvector sum.magnitude (m)

AcellusVector E is 0.111 m long in a90.0. direction. Vector Fis0.234 m long in a300 direction.Find the

Answers

Answer:

The magnitude of the vector sum = 0.149 m

The direction = 321.8 degrees

Explanation:

Find the x and y components of vector E

\(\begin{gathered} E_x=\text{ 0.111}\cos 90 \\ E_x=\text{ }0 \\ E_y=\text{ 0.111sin90} \\ E_y=\text{ }0.111 \\ E=E_xi+E_yj \\ E\text{ = 0.111j} \end{gathered}\)

Find the x and y components of vector F

\(\begin{gathered} F_x=\text{ 0.234}\cos 300 \\ F_x=\text{ }0.117 \\ F_y=\text{ 0.234}\sin 300 \\ F_y=\text{ }-0.203 \\ F=F_xi+F_yj \\ F\text{ = 0.117i-0.203j} \end{gathered}\)

The vector sum of E and F is:

\(\begin{gathered} E+F\text{ = 0.111j+(0.117i-0.203j)} \\ E+F=0.117i-0.092j \end{gathered}\)

The magnitude of the vector sum is given as:

\(\begin{gathered} |E+F|=\sqrt[]{0.117^2+(-0.092)^2} \\ |E+F|\text{ = }\sqrt[]{0.022153} \\ |E+F|=\text{ }0.149 \end{gathered}\)

The magnitude of the vector sum = 0.149 m

The direction is given as:

\(\begin{gathered} \theta\text{ = }\tan ^{-1}(\frac{-0.092}{0.117}) \\ \theta\text{ = }\tan ^{-1}(-0.786) \\ \theta\text{ = }-38.2^0 \\ \theta\text{ = -38.2+360} \\ \theta\text{ = }321.8^0 \end{gathered}\)

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