which of the following solutions of glucose (c6h12o6) is isotonic with a 0.1 m nacl solution?

Answers

Answer 1

3.6 %(w/v) solutions of glucose (C₆H₁₂O₆) is isotonic with a 0.1 m nacl solution from the following .

Option C is correct.

                  NaCl Na⁺ + Cl⁻  = 2 particles

mol of 0.1 M NaCl = 0.1 x 2 = 0.2 Osmol NaCl

Glucose does not dissociate to particles so 0.2

                            Mol glucose = 0.2 M glucose

0.2 M glucose = 0.2 mol glucose/1 L solution

                            = 0.02 mol/100 mL

1 mol glucose (C₆H₁₂O₆) = 6 x 12 g + 12 x 1 g + 6 x 16 g

                                 = 180 g glucose

0.02 mol glucose x 180 g glucose = 3.6 g glucose 3.6 g glucose/100 mL solution

1 mol glucose  = 3.6 %(w/v) glucose solution.

Isotonic solution: what is it?

Isotonic solutions are those that have the same concentration of water and solutes as the cytoplasm of the cell. Since there is no net gain or loss of water in an isotonic solution, cells placed there will not swell or shrink. Isotonic is a term used to portray arrangements and science and, once in a while, muscles in human science.

When a solution crosses a semipermeable membrane with the same concentration of solutes as another solution, it is said to be isotonic in chemistry. The utilization of isotonic in human life structures is utilized all the more once in a blue moon

Incomplete question :

Which of the following solutions of glucose (C6H12O6) is isotonic with a 0.1 M NaCl solution?

A. 0.15%(w/v)

B. 0.55%(w/v)

C. 3.6 %(w/v)

D. 5.4%(w/v)

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Related Questions

Using the GC-spectra below determine the distribution of products for each reaction. Briefly describe if one reaction is more selective then the other

Answers

The given GC-Spectra are of two reactions — A and B. Reaction A has two main peaks corresponding to 20% and 40% of the reactants respectively, while Reaction B has four peaks corresponding to 25%, 30%, 35%, and 40% of the reactants.

Reaction A is more selective than Reaction B because it results in a lower percentage of products which can be attributed to the thermodynamics of the reaction. Overall, Reaction A produces fewer products, but the two main peaks correspond to 20% and 40% of the reactants, while Reaction B produces four main products, with the highest one corresponding to 40% of the reactants.

This can be explained by the fact that Reaction B is more exothermic than Reaction A and requires less energy to break the C-C and C-O bonds, allowing for more products to be created. Additionally, Reaction B has a higher reactivity because it produces more radicals which can participate in the reaction, allowing for more products to be formed. Therefore, Reaction B is more selective than Reaction A.

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What bad thing can happen if you try to remove a large amount of solvent quickly under vacuum?.

Answers

When large amount of solvent is quickly removed  under vacuum the separation of the solute and the solvent takes place.

There are many separation techniques that are used, some of the common ones are boiling or evaporating the solvent so that the remaining part is just left with the solute particles. There are some other separation techniques as well such as fractional distillation which separated the solutions based on the boiling points of the solutions.

As mentioned in the above case when we remove a large amount of solvent quickly under vacuum, the separation process becomes very difficult. Because under vacuum means the pressure is reduced because of which liquids vaporize and boil off at lower temperatures; eventually, the solvents come off a lot faster when under vacuum than at atmospheric pressure.

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Enter your answer in the provided box. Calculate the wavelength of a
photon of electromagnetic radiation with a frequency of 61.7 MHz. m

Be sure to answer all parts. Calculate the energy of a photon of
electromagnetic radiation with a wavelength of 582.8 nm. * 10 Report
your answer in scientific notation using the provided boxes.

Answers

we find the energy to be approximately \(3.41 * 10^-19\) Joules is the answer.

To calculate the wavelength of a photon with a frequency of 61.7 MHz, we can use the formula: wavelength = speed of light / frequency. The speed of light is approximately\(3 * 10^8\) meters per second.

Converting the frequency to Hz (\(1 MHz = 10^6 Hz\)), we have \(61.7 * 10^6\)Hz.

Plugging these values into the formula, we get: wavelength =\((3 * 10^8 m/s) / (61.7 * 10^6 Hz).\)

Simplifying, we find the wavelength to be approximately 4.862 meters.

Now, to calculate the energy of a photon with a wavelength of 582.8 nm, we can use the equation: energy = Planck's constant × speed of light / wavelength.

Planck's constant is approximately \(6.63 * 10^-34\) Joule-seconds.

Converting the wavelength to meters (\(1 nm = 10^-9 m\)), we have \(582.8 * 10^-9 m.\)

Plugging these values into the equation, we get: energy =\((6.63 * 10^-34J·s) * (3 * 10^8 m/s) / (582.8 * 10^-9 m).\)

Simplifying, we find the energy to be approximately \(3.41 * 10^-19\) Joules.

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when nh4no3 dissolves in water, the temperature of the solution decreases. what describes the enthalpy and entropy changes of the system and which change drives the process? (a) delta h

Answers

When \(NH_4NO_3\) dissolves in water, the enthalpy of the system decreases, and the entropy of the system increases. The increase in entropy is the driving force of the process, causing the solute to dissolve in the solvent. Option A is the correct answer.

When \(NH_4NO_3\) dissolves in water, it undergoes an endothermic process in which heat is absorbed from the surroundings, causing the temperature of the solution to decrease. This suggests that the dissolution process is driven by an increase in the system's entropy, rather than by a decrease in enthalpy.

The enthalpy change of the system can be determined by measuring the heat of the solution, which is the amount of heat absorbed or released when a solute dissolves in a solvent. In the case of \(NH_4NO_3\), the heat of the solution is positive, indicating an endothermic process in which heat is absorbed. This means that the enthalpy of the system decreases when \(NH_4NO_3\) dissolves in water.

The entropy change of the system can be determined by calculating the difference in the entropy of the solution and the sum of the entropies of the separate components (the solute and the solvent) before mixing. In the case of \(NH_4NO_3\) dissolving in water, the increase in the disorder of the system is driven by the release of ammonium ions and nitrate ions into the solvent. The disorder of the system increases because the ions become more dispersed and move around freely in the solution. This increase in entropy is the driving force of the process.

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Complete question:

Which of the following describes the enthalpy and entropy changes of the system when \(NH_4NO_3\) dissolves in water, and which change drives the process?

a) Enthalpy decreases and entropy increases; entropy change drives the process

b) Enthalpy increases and entropy decreases; enthalpy change drives the process

c) Enthalpy decreases and entropy decreases; enthalpy change drives the process

d) Enthalpy increases and entropy increases; entropy change drives the process

Select the correct answer from each drop-down menu. The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachloride (CCl4) is also nonpolar but is made of larger molecules that are more strongly affected by London dispersion forces. Based on this information, CS2 likely has a melting point and a vapor pressure when compared with CCl4.

Answers

Given the information in the problem, CS2 is more volatile than CCl4. This is because it has a lower melting point and a higher vapor pressure. The drop-down menus should be selected accordingly. So, according to the information given in the problem, the correct answer is (C) a lower melting point and a higher vapor pressure.

London dispersion forces are the only type of intermolecular force that exists between the molecules of carbon disulfide (CS2). This is because carbon disulfide is a non-polar molecule that lacks permanent dipoles due to its symmetric and linear arrangement.

These forces, however, are weak in comparison to other intermolecular forces, which is why carbon disulfide has a low melting point and a high vapor pressure. Carbon tetrachloride (CCl4) is also nonpolar, but it consists of larger molecules that are more strongly affected by London dispersion forces.

The stronger the London forces, the more closely packed the molecules become. This leads to higher melting and boiling points than those of smaller molecules. Carbon tetrachloride has a higher melting point and a lower vapor pressure than carbon disulfide because of its larger molecular size.

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When the coastal land is warmer than the nearby water, what type of breeze it forms?

Answers

Answer: Your answer is a Sea breeze

A sea breeze, much like the majority of weather conditions experienced at the coast, is the result of the contrasting way in which the land and ocean react to changes in temperature

Hope this helps!

Answer:

A sea breeze,

Explanation:

also known as an onshore breeze, occurs because of the differences in air pressure created by the difference in temperature between the ocean or water and the dry land.

a balloon contains 0.5 l of air at 101.5 kpa. you squeeze it to a volume of 0.25 l. what is the pressure of air inside the balloon? responses 0.25 kpa 0.25 kilopascal 50.8 kpa 50.8 kilopascal 102 kpa 102 kilopascal 203 kpa

Answers

The pressure of air inside the balloon is 203 kPa. This is because the pressure of a gas is directly proportional to its volume.

What is directly proportional?

Directly proportional is a mathematical term used to describe a linear relationship between two variables, where a change in one variable is directly reflected by a proportional change in the other variable. For example, if the number of hours a person works increases, the amount of money they earn will also increase proportionally. This linear relationship is also known as a "direct relationship" or a "direct variation".

Since you have halved the volume of the balloon, the pressure has doubled. The initial pressure of 101.5 kPa multiplied by 2 equals 203 kPa.

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A sample of ideal gas at room temperature occupies a volume of 28.0 L at a pressure of 882 torr. If the pressurechanges to 4410 torr , with no change in the temperature or moles of gas, what is the new volume, V?Express your answer with the appropriate units.

Answers

To solve this problem, we could use the Boyle's law since there's a sample of ideal gas and temperature is constant.

Boyle's law tells us that:

Replacing the values of the problem:

The new volume V equals 5.6L.

A sample of ideal gas at room temperature occupies a volume of 28.0 L at a pressure of 882 torr. If the
A sample of ideal gas at room temperature occupies a volume of 28.0 L at a pressure of 882 torr. If the

What does this piece of evidence best support? the collision theory the Maxwell-Boltzmann distribution the effect of pressure on reaction rates the effect of temperature on reaction rates.

Answers

Particles are the smallest units of any state of matter that moves in a medium due to various factors. The particle movement best supports the collision theory.

What is collision theory?

In a reactant, the particles move and collide with each other resulting in some amount of change and the collision between the atoms and the molecules are necessary for a chemical reaction to occur.

This theory of collision is used for the prediction of the rate of the reaction to occur and the chemical changes occurring in a gas or the reactant. This aids in understanding the rate of reaction occurring in a system.

The collision of the particles is proportional and related to the rate of the reaction. The amount of the concentration and their collision affects the rate at which the chemical change will occur.

Therefore, option A. the collision theory is supported here.

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1. To check acidic or basic character of t h e substance
andneutralization
Material Required: Amla, Tamarind, orange, ENO, soap,
window cleaner, china rose as an indicator. Procedure:
1. Take out Amla, tamarind, and orange and check
theircolour in the china rose solution. 2. What are the colour changes of these things?
3. Record your observation. Take out the rest of the
things and check their colour change also in the china
rose solution (indicator). Now mix the solution of any two i. E. One acid and one base
in equal amounts and check the colour of this solution in
china rose solution. Record your observations

Answers

The experiment involves observing the color changes of various substances in the presence of a china rose indicator to determine their acidic or basic nature. The neutralization process can also be observed by mixing an acid and a base and noting the resulting color change.

In this experiment, the aim is to determine the acidic or basic nature of different substances and to observe the neutralization process. The materials required include amla, tamarind, orange, ENO (an antacid), soap, window cleaner, and china rose as an indicator. The procedure is as follows:Take amla, tamarind, and orange and observe their colors in the china rose solution (indicator).Note any color changes that occur in the substances when placed in the china rose solution.Record your observations.Next, take the remaining substances (ENO, soap, window cleaner) and observe their color changes when placed in the china rose solution.Record your observations.To observe neutralization, mix equal amounts of the solution of an acid (e.g., orange juice) and a base (e.g., ENO) and check the color of this solution in the china rose solution (indicator).Record your observations.By observing the color changes in the china rose solution, you can determine whether a substance is acidic, basic, or neutral. Acidic substances will exhibit a different color change compared to basic substances. The color change in the neutralization mixture may indicate a shift towards neutrality.

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How many electrons are actually in the composite band for Fe?
Express your answer numerically as an integer.

Answers

There are 12 electrons in the composite band for Fe.

The number of electrons in the composite band for Fe can be determined by considering its electron configuration. Iron (Fe) has an atomic number of 26, which means it has 26 electrons in total. The electron configuration of Fe is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6.

The composite band includes the valence band and any partially filled bands below it. In the case of Fe, the valence band consists of the 4s and 3d orbitals. Since the 4s orbital can hold up to 2 electrons and the 3d orbital can hold up to 10 electrons, the total number of electrons in the composite band for Fe is 2 + 10 = 12.

Therefore, there are 12 electrons in the composite band for Fe.

The composite band of Fe consists of the valence band and partially filled bands below it. In Fe, the valence band includes the 4s and 3d orbitals. The 4s orbital can hold 2 electrons, and the 3d orbital can hold 10 electrons. Thus, there are 12 electrons in the composite band of Fe.

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how does voltage work in a circuit?​

Answers

Answer:

Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Explanation:

I hope this is right i found it off a website called fluke!

If you have 50mg of a radioactive isotope, how much will remain after 1 Half Life? How much after 2 half lives?

Answers

Answer:The quantity of radioactive nuclei at any given time will decrease to half as much in one half-life. For example, if there were 100 g of Cf -251 in a sample at some time, after 800 years, there would be 50 g of Cf -251 remaining. After another 800 years (1600 years total), there would only be 25 g remaining.

Explanation:

The mass number is equal to the number of blank in the nucleus of the atom

Answers

Answer:

c

Explanation:

suppose a biochemist has 10 ml of a 1.0 m solution of a compound with two ionizable groups at a ph of 8.00. she adds 10.0 ml of 1.00 m hcl, which changes the ph to 3.20. the value of one of the groups is 3.8 and it is known that is between 7 and 10. what is the exact value of ?

Answers

To determine the exact value of pK2 in this case, we can use the relationship between pH and pK, which states that the pH of a solution is equal to the pK of the acid with the lowest concentration when the acid and its conjugate base are in equilibrium.

Here, we know that the pH of the solution dropped from 8.00 to 3.20 after the addition of HCl. We can assume that the second group is now in the acid form since we know that the first ionizable group has a pK of 3.8, and the second group (pK2) is between 7 and 10, we can assume that the second group is now in the acid form.

We can use the relationship between pH and pK to calculate the exact value of pK2:

pH = pK2 = pKw / [H+] = 14.00 - log([H+])

3.20 = 14.00 - log([H+])

Solving for [H+], we find that [H+] = 1.0 x 10^-3.2

Now we can find the value of pK2 as:

pK2 = 14.00 - log(1.0 x 10^-3.2) = 14.00 - (-3.2) = 14.00 + 3.2 = 17.2

Therefore, the exact value of pK2 is 17.2.

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. At time t=0, an aluminum bar (thermal diffusivity k=0.86 ) of length Lcm with completely insulated lateral surfaces and constant thermal properties is removed from boiling water (uB​=100 degrees Celsius). Do the following i), ii), iii) for each of the scenarios, a-d, below i) Write down the initial-boundary value problem. That is, the PDE along with any initial and boundary conditions. ii) Without solving for u(x,t), describe the temperature distribution in the bar as t→[infinity] based on physical intuition. iii) Find the solution as t→[infinity] by solving the appropriate steady state equation. a) The two ends of the bar are immediately immersed in a medium with constant temperature 10 degrees Celsius. b) The end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is completely insulated.

Answers

(i) The initial-boundary value problem for the given scenarios are as follows:

a) Scenario a:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 10, u(L, t) = 10 (constant temperature at the ends)

b) Scenario b:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 0 (temperature at x=0), ∂u/∂x(L, t) = 0 (thermal insulation at x=L)

(iii) The solution for the temperature distribution as time approaches infinity can be found by solving the appropriate steady state equation.

What is the expected temperature distribution in the bar as time approaches infinity?

(i) The initial-boundary value problem formulation states the partial differential equation (PDE) governing the temperature distribution in the aluminum bar, along with the initial condition and boundary conditions.

In scenario (a), both ends of the bar are immersed in a medium with a constant temperature of 10 degrees Celsius, while in scenario (b), the end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is insulated.

(ii) As time approaches infinity, the temperature distribution in the bar tends to reach a steady state.

In scenario (a), the temperature throughout the bar will eventually approach a constant value of 10 degrees Celsius, since both ends are immersed in a medium with that temperature.

In scenario (b), the temperature at x=0 will approach 0 degrees Celsius, while the temperature at x=L will remain constant due to thermal insulation.

(iii) To find the solution as time approaches infinity, we need to solve the appropriate steady state equation.

In scenario (a), the steady state equation is ∂²u/∂x² = 0, which implies that the temperature gradient is zero throughout the bar, resulting in a constant temperature of 10 degrees Celsius.

In scenario (b), the steady state equation is ∂²u/∂x² = 0 with the boundary condition u(0) = 0, which implies a linear temperature distribution from 0 degrees Celsius at x=0 to a constant temperature at x=L due to insulation.

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C4H10(1) + O2(g)→ CO2(g) + H2O(l)
How many moles of O₂ are needed to fully combust 6.77 moles of C4H10?

Answers

?moles O2= 6.77 moles C4H10 x 1moles O2/ 1mole C4H10=> 6.77 moles of O2 are needed.

A seperatory funnel contains the two immiscible liquids water and diethyl ether. Use the given densities to determine which layer is on top and which layer is on the bottom.
solvent density
diethyl ether 0.71
water 0.998

Answers

Based on the given densities, diethyl ether with a density of 0.71 g/mL is less dense than water with a density of 0.998 g/mL. Therefore, the diethyl ether layer will be on top, and the water layer will be on the bottom in the separatory funnel.

To determine which layer is on top and which layer is on the bottom in a separatory funnel containing immiscible liquids water and diethyl ether, you'll need to compare their densities.

Given densities:
- Diethyl ether: 0.71 g/mL
- Water: 0.998 g/mL

Step 1: Compare the densities.
The substance with a lower density will float on top of the one with a higher density.

Step 2: Identify the layers.


Since diethyl ether has a lower density (0.71 g/mL) than water (0.998 g/mL), diethyl ether will be the top layer and water will be the bottom layer in the separatory funnel.

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when svante arrhenius first proposed his acid-base theory, he was a doctoral candidate. his professors thought his ideas were unfounded. within a decade, the arrhenius theory of acid-base was widely accepted and praised within the scientific world. arrhenius defined acids as compounds having ionizable hydrogen and bases as compounds with ionizable

Answers

Svante Arrhenius, as a doctoral candidate, proposed the acid-base theory, which initially faced skepticism from his professors who thought his ideas were unfounded. However, within a decade, the Arrhenius theory was widely accepted and praised in the scientific world. In his theory, Arrhenius defined acids as compounds having ionizable hydrogen, and bases as compounds with ionizable hydroxide ions (OH-).

Arrhenius proposed his theory of acids and bases in 1884 as part of his doctoral thesis. At the time, his ideas were met with skepticism and criticism from his professors and peers, who were more accustomed to the older, classical theories of acids and bases.

However, Arrhenius's theory was eventually accepted and became widely praised within the scientific community. This was in part due to the experimental evidence that supported his theory and the way that it could be used to explain a wide range of chemical phenomena.

In Arrhenius's theory, an acid is a substance that dissociates in water to produce hydrogen ions (H+), while a base is a substance that dissociates in water to produce hydroxide ions (OH-). This theory provided a new and more comprehensive understanding of the behavior of acids and bases and laid the foundation for further research in this area.

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Arrange ionic compounds in order of decreasing amount of energy released in lattice formation .NaF,MgS,TLN and

Answers

The question is incomplete, the complete question is;

Arrange the following ionic compounds in order of decreasing amount of energy released in lattice formation: NaF, MgS, TlN, and CsI.

Answer:

TlN> MgS > NaF > CsI

Explanation:

Recall that lattice energy is the energy evolved when a crystal lattice is formed from its component ions.

The lattice energy depends on the size of the ions. The smaller the sizes of the ions, the larger the lattice energy.

The order of energy released in lattice formation for these compounds is;

TlN> MgS > NaF > CsI

what is:
Na2O+SO2 =
for chemistry​

Answers

Na2SO3 – Sodium sulfite

1. You may be using medium for shoot regeneration from leaf explants of a plant in Expt-5. The plant media may contain the plant growth regulators (hoones) BA and NAA. The molecular weight of BK is 72 A : and NAA is 186. The media is pH to 5.8. (a) Before making the plant media, you found the pH to be 3.6. What would you add quiekly to get it to a pH of 5.8 (give a specific name of the solution)? Why? (1 pt) (b) How much BA will be weighed fot a 1M solution? (Y po) (c) Convert your answer from (b) to mg/ml. (Y/ pt) (d) Convert your answer from (c) to mg 1 . (1 pt) (e) How much BA will be weighed for a 5mM solution? (1/4pt) (f) Convert your answer from (c) to mg/ml. ( /4pt ) (g) Convert your answer from (f) to mg/L. (H/ pt) (h) Your stock solution of BA is 5mM and your working solution is 0.2mg/.. What volume of the stoc be added to 250ml of medium? [Hint: fook at the previous answers Keep to 4 decimal pts.) (3 pts Convert your answer from (h) to μI, and which pipettor will you use to aliquot the B. A? (1 pt)

Answers

(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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A piece of regular computer paper occupies a volume of 15 cubic
centimeters and has a mass of 18.015 grams. What is its density? *

Answers

Answer:

1.00 g/cm³

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 18.015 g

volume = 15 cm³

We have

\(density = \frac{18.015}{15} \\ = 1.000833333...\)

We have the final answer as

1.00 g/cm³

Hope this helps you

an energy bar contains 26 g of carbohydrates and 5g of fat. how many calories will you obtain by eating the bar

Answers

The amount of calories that you will obtain by eating the energy bar is: 149 calories

What are calories?

Calories are a unit of energy measurement that expresses the amount of energy that a food can provide to the body when the food is digested and absorbed.

To solve this problem we must perform the following algebraic operations with the given information

Information about the problem:

1 g of carbohydrates = 4 calories1 g of fat = 9 caloriesCalories (26 g carbohydrates)=?Calories (5 g of fat) =?Calories in the energy bar = ?

Calculating how many calories are in 26 g carbohydrates we have:

Calories (26 g carbohydrates)= 26 * 4 calories

Calories (26 g carbohydrates)= 104 calories

Calculating how many calories are in 5 g fat we have:

Calories (5 g fat)= 5 * 9 calories

Calories (5 g fat)= 45 calories

Calculating how many calories are in the energy bar we have:

Calories (energy bar)= 104 calories + 45 calories

Calories (energy bar)= 149 calories

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the reaction involving zinc metal immersed in a solution of copper ions is called a ____ reaction.

Answers

The reaction involving zinc metal immersed in a solution of copper ions is called a redox reaction.

Redox reaction is a kind of chemical reaction that includes a change in oxidation states of the elements in a chemical reaction. The word "redox" is made up of "reduction" and "oxidation."A reaction in which both reduction and oxidation take place is known as a redox reaction. When a substance loses one or more electrons, it is oxidized. The opposite of reduction is oxidation. An example of a redox reaction is the reaction between zinc metal immersed in a solution of copper ions.Copper ions take electrons from the zinc metal in the solution to become copper atoms in the solution. Zinc ions and copper atoms are created as a result of this. The reaction involving zinc metal immersed in a solution of copper ions is a redox reaction.

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Câu 1: Trong các dung dịch sau, dung dịch nào làm quỳ tím đổi màu xanh?
A. HCl B. H2SO4 C. NaOH D. NaCl
Câu 2: Bazơ nào dưới đây là bazơ không tan?
A. KOH B. NaOH C. Cu(OH)2 D. Ca(OH)2
Câu 3: Trong các chất sau đây, chất nào không phải là muối?
A. HCl B. KCl

Answers

C. NaOH

C. Cu (OH)

A. HCl

how to make sweetened condensed milk from evaporated milk?

Answers

Answer:

Just combine one 12-oz can of evaporated milk and 1-1/2 cups granulated sugar in a sauce pan. Bring the mixture to a boil over medium heat, stirring constantly. Continue cooking, until the sugar dissolves, and the milk thickens slightly. Allow your sweetened condensed milk to cool.

Explanation:

hope this helps

Answer:

Mix one 12-oz can of evaporated milk and 1-1/2 cups granulated sugar. :)

How do spores help the survival of spore-bearing plant?

Answers

They release spores into the air, often carried by the wind. They allow spore bearing plants to replicate themselves in a form of cloning.

Answer:

When weather conditions are ideal, some ferns, algae, moss,and even fungi, release spores into the air, often carried by the wind, by insects or birds until they land. Spores contain both male and female reproductive organs, which allows these plants to replicate themselves in a form of cloning.

Explanation:

in a propanal molecule, an oxygen atom is bonded with a carbon atom. what is the total number of pairs of electrons shared between these atoms?

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The oxygen atom forms a double bond with the carbon atom, which involves sharing two pairs of electrons. However, since the carbon atom is also bonded to two other atoms.

To further explain, a double bond involves sharing four electrons between two atoms, with two of the electrons coming from each atom's valence shell. In the case of the propanal molecule, the oxygen atom has six valence electrons and needs two more to complete its octet, while the carbon atom has four valence electrons and needs four more to complete its octet.

In propanal (also known as propionaldehyde), the oxygen atom forms a double bond with the carbon atom. A double bond consists of two pairs of shared electrons. Therefore, the total number of pairs of electrons shared between these atoms is 2.

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The  two pairs of electrons shared between the oxygen atom and the carbon atom in a propanal molecule.

We can look at the structure of propanal. Propanal has the chemical formula C3H6O, with a carbonyl group (C=O) located on the second carbon atom. In this carbonyl group, the oxygen atom is double-bonded to the carbon atom. Double bonds involve the sharing of two pairs of electrons between atoms. Therefore, in a propanal molecule, the oxygen and carbon atoms share two pairs of electrons.
There are two pairs of electrons shared between the oxygen and carbon atoms in a propanal molecule, due to the double bond in the carbonyl group.

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Plzzzz help I’m begging

Plzzzz help Im begging

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