which one of these is correct? and how do I find out?​

Answer:

Blood and water

Explanation:

Answer:

The diameter of the Chlorine atom is 25000 times larger than the diameter of the Chlorine nucleus.

Explanation:

From the question,

The radius of a Cl nucleus is 4.0 fm and radius of a Cl atom is 100 pm.

To determine how many times larger the diameter  of the Chlorine atom is than the diameter of the Chlorine nucleus,

First, we will determine the diameter of the Chlorine atom and the diameter of the Chlorine nucleus.

(NOTE: Diameter = Radius × 2)

For the Chlorine atom

Radius of the Chlorine atom = 100 pm

∴ Diameter of the Chlorine atom = 2 × 100 pm

Diameter of the Chlorine atom = 200 pm

For the Chlorine nucleus

Radius of Chlorine nucleus = 4.0 fm

∴ Diameter of the Chlorine nucleus= 2 × 4.0 fm

Diameter of the Chlorine nucleus = 8.0 fm

Now, we will convert both diameters ( diameter of Chlorine atom and diameter of Chlorine nucleus) to the same unit

For Chlorine nucleus

Diameter of the Chlorine nucleus = 8.0 fm

If 1 fm = 1 × 10⁻¹⁵ m

Then, diameter of the Chlorine nucleus = 8.0 × 1 × 10⁻¹⁵ m

Diameter of the Chlorine nucleus = 8.0 × 10⁻¹⁵ m

For Chlorine atom

Diameter of the Chlorine atom = 200 pm

If 1 pm = 1 × 10⁻¹² m

Then, diameter of the Chlorine atom = 200 × 1 × 10⁻¹² m

Diameter of the Chlorine atom = 200 × 10⁻¹² m

Diameter of the Chlorine atom = 2 × 10⁻¹⁰ m

Now, to determine how many times larger the diameter  of the Chlorine atom is than the diameter of the Chlorine nucleus, we will divide the diameter of the Chlorine atom by the diameter of Chlorine nucleus.

Diameter of Cl atom / Diameter of Cl nucleus = (2 × 10⁻¹⁰ m) / (8.0 × 10⁻¹⁵ m)

(2 × 10⁻¹⁰ m) / (8.0 × 10⁻¹⁵ m) = 25000

∴ Diameter of Cl atom / Diameter of Cl nucleus = 25000

Hence, the diameter of the Chlorine atom is 25000 times larger than the diameter of the Chlorine nucleus.

The diameter of the Cl atom has been 25,000 times larger than the diameter of the Cl nucleus.

To calculate the relationship between the diameter of Cl atom and nucleus, the diameter has to be calculated.

Diameter = 2 \(\times\) radius

Diameter of Cl atom:

Cl atom = 2 \(\times\) 100 pm

Cl atom = 200pm

1 pm = \(\rm 10^-^1^2\) m

200 pm = 200 \(\times\) \(\rm 10^-^1^2\) m

Diameter of Cl nucleus:

Cl nucleus = 2 \(\times\) 4 fm

Cl nucleus = 8 fm

1 fm  = \(\rm 10^-^1^5\) m

8 fm = 8 \(\times\)  \(\rm 10^-^1^5\) m.

The relationship between the Cl atom and the nucleus has been made by taking the ratio of the diameter of the Cl atom to the Cl nucleus.

\(\rm \dfrac{Diameter\;of\;Cl\;atom}{Diameter\;of\;Cl\;nuclues}\;=\;\dfrac{200\;\times\;10^-^1^2}{8\;\times\;10^-^1^5}\)

Diameter of Cl atom = 25000 Diameter of Cl nucleus.

Thus, the diameter of Cl atom has been 25,000 times larger than the diameter of the Cl nucleus.

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a). Thus, the density of the unknown fluid is 720 kg/m³. b).  So, the water layer is at the bottom and the unknown fluid layer is on top in the container. are the answers

Given data Absolute pressure at the bottom of the container of fluid = 140kPa

Depth of the water layer = 20 cm

Depth of the unknown fluid layer = 30 cm

a) Density of the unknown fluid

Let the density of the unknown fluid be ρ2 Formula used

Pressure = Density × gravity × height + Atmospheric pressure

At the bottom of the

container Pressure = Density × gravity × height + Atmospheric pressure

140 kPa = ρ1 × 9.8 m/s² × (0.2 + 0.3) m + atmospheric pressure

Also, Density of water = 1000 kg/m³

We need to find the density of the unknown fluid i.e. ρ2

Thus, the density of the unknown fluid is 720 kg/m³

b) Layer which is on top in the container

Water is denser than the unknown fluid

So, the water layer is at the bottom and the unknown fluid layer is on top in the container.

Hence, option (C) is correct.

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a) The density of the unknown fluid is 478.48 kg/m³.

b) The layer of the unknown fluid is on top of the container.

Given that the absolute pressure at the bottom of a container of fluid is 140 kPa. One layer of fluid is clearly water with a depth of 20 cm. The other mysterious fluid though has a depth of 30 cm. We need to find out the density of the unknown fluid and also identify which layer is on top of the container.

We know that the pressure at the bottom of a container of fluid is given by the formula:

P = hρg

Where,

P is the absolute pressure

h is the depth

ρ is the density

g is the acceleration due to gravity

Substituting the given values in the formula, for water,

P = hρg

140 × 10³ = 20 × ρ × 9.81

ρ = 716.92 kg/m³

Similarly for the other fluid,

P = hρg

140 × 10³ = 30 × ρ × 9.81

ρ = 478.48 kg/m³

Therefore, the density of the unknown fluid is 478.48 kg/m³.

Now, to identify the layer that is on top in the container, we need to compare the densities of the two layers. The layer with the lower density will be on top. Here, we can see that the density of water (which is 716.92 kg/m³) is greater than the density of the unknown fluid (which is 478.48 kg/m³). Therefore, the layer of the unknown fluid is on top of the container.

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A gamma-ray photon has a higher frequency than a radio photon. Therefore, the gamma-ray photon has more energy.

Gamma rays are electromagnetic waves with a wavelength of less than 0.01 nanometers (nm), corresponding to a frequency of greater than 10 exahertz (Hz) or greater than 1020 Hz and photon energy of more than 100 keV.

Radio waves, on the other hand, are electromagnetic waves with a wavelength of between 1 millimeter (mm) and 100 kilometers (km) and a frequency of between 300 megahertz (MHz) and 300 gigahertz (GHz).

Gamma rays have the highest frequency, shortest wavelength, and greatest photon energy of all forms of electromagnetic radiation. As a result, gamma rays are dangerous to living organisms since they may cause tissue harm and ionize atoms and molecules in their path.

Radio waves have the lowest frequency, longest wavelength, and lowest photon energy of all forms of electromagnetic radiation.

As a result, radio waves are less likely to cause tissue harm and ionize atoms and molecules in their path.

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The sets in σ(A,B) are the smallest σ-algebra that contains both A and B.

In probability theory and measure theory, a σ-algebra is a collection of subsets of a given set Ω that satisfies certain properties. The notation σ(A,B) represents the smallest σ-algebra that contains both subsets A and B. This means that σ(A,B) consists of all possible subsets that can be formed by taking the union, intersection, and complement of sets in A and B.

To understand this concept better, let's consider an example. Suppose we have a set Ω = {1, 2, 3, 4} and two subsets A = {1, 2} and B = {2, 3}. The σ-algebra σ(A,B) would include the empty set, the set Ω itself, as well as other subsets such as {1}, {2}, {3}, {1, 2}, {2, 3}, and {1, 2, 3}. It would also include their complements, for example, the complement of {1} would be {2, 3, 4}.

The σ-algebra σ(A,B) is important in probability theory as it allows us to define probability measures and study various properties of events and random variables. By identifying all the sets in σ(A,B), we can determine the range of events that can be analyzed within this framework.

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Answer:

Burning paper

Explanation:

I got it right on the test.

Substances having fixed chemical proportions will have fixed boiling and melting points. This is the reason that Pure substances have specific melting and boiling points because their chemical proportions are fixed. Mixtures melt and boil over a range of temperatures

\(\large\sf\red{♡♡~}\)

Answer:

Products

Explanation:

The materials you end up with in a reaction are called the products of the reaction.

For example;

        A  + B →  C + D

A and B are the reactants

C and D are the products.

Answer:

the answer is a.10

Explanation:

in(No/N) = kt

No = 80 mg

N = 10 mg

t = 30 min

solve for k, then

k = 0.693/t1/2

Substitute k from above and solve for t1/2

10 min is correct.

Radioactive element keeps on decaying over the time. Decay of radioactive element always comes under first order kinetics. The element's half-life of decay of 80mg of a radioactive element decays to 10 mg in 30 mins is 10.04 minutes. The correct option is option A.

Half life tells about the time at which the radioactive material decays to half of its initial concentration.

Mathematically, the initial and final amount of radioactive material can be connected as

ln(No/N) = kt

No =initial amount of radioactive decay= 80 mg

N = final amount of radioactive decay=10 mg

t =time taken to decay= 30 min

K= rate constant

ln( 80 mg/10 mg) = k×30 min

0.069min⁻=k

k = 0.693/half life

half life=10.04min

Therefore the element's half-life of decay of 80mg of a radioactive element decays to 10 mg in 30 mins is 10.04 minutes. The correct option is option A.

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Answer:

Average atomic mass  = 6.93 amu.

Explanation:

Given data:

Percent abundance of lithium -6 = 7%

Percent abundance of lithium - 7 = 93%

Average atomic mass of Li = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (7×6)+(93×7) /100

Average atomic mass =  42+ 651 / 100

Average atomic mass  = 693/ 100

Average atomic mass  = 6.93 amu.

Answer

Explanation

The given balanced half-reaction for an acidic solution:

What to find:

Tha balanced half-reaction for a basic solution.

Step-by-step-solution:

To balance the half-reaction for a basic solution;

1. Add OH⁻ ions to BOTH SIDES to neutralize any H⁺

2. Combine H+ and OH- to make H2O.

3. Simplify by canceling out excess H2O

4. Balance the charges by adding e-

Here's the classification of the ions and allotropes of oxygen based on their ability to be oxidized or reduced:

Oxide ion (O2-) can be reduced but cannot be oxidized.

Peroxide ion ((O2)2-) can be both oxidized and reduced.

Superoxide ion ((O2)-) can be oxidized but cannot be reduced.

Ozone (O3) can be both oxidized and reduced.

Oxygen gas (O2) can neither be oxidized nor reduced under normal conditions.

Note that these classifications are based on the standard electrode potentials for each species, which may vary depending on the specific conditions and environment in which they are found.

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Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution. The determining factors of the formation of a precipitate can vary.

Answer:

See explanation

Explanation:

A simple test that will distinguish flour from sugar is to dissolve the unknown substance in water.

Sugar dissolves in water due to the presence of polar groups in the chemical structure of sugar that are capable of interaction with water.

Flour does not dissolve in water. It rather becomes suspended in water when agitated and settles at the bottom of the container when the suspension is left to stand.

Answer:

B. stored energy

hope this helps!!

Answer:

The answer is below

Explanation:

Here some of the difference between aluminum phosphide and aluminum phosphate

1. Aluminum phosphide is a crystalline solid with either dark gray or yellow color. While Aluminum Phosphate is in a nanopowder form but with a whitish color.

2. Aluminum phosphide is used in the fumigation of plants, while Aluminum phosphate is used in cosmetics, paints, etc.

3. Aluminum phosphide has a compound formula of AlP with a molar mass of 57.9552 g/mol, while Aluminum Phosphate has a compound formula of AlO4P with a molar mass of 121.9529 g/mol

Answer:

H - Cl2 +NaBr -> Br2+2NaCl

Answer:

See explanation

Explanation:

Both BCl3 and BH3 are electron deficient compounds. In these compounds, boron has six instead of eight electrons surrounding it's outermost shell.

BH3 is able to form a dimmer because of the small size of hydrogen atoms which enable them to be fitted between boron atoms. Large size chlorine atoms can not be fitted between boron atoms hence B2Cl6 does not exist.

Answer:

The answer is A.

Explanation:

When acid react with metal carbonate, it will form salt, water and carbon dioxide.

For example :

HCl + CaCO3 → CaCl + H2O + CO2

Answer: The given type of chemical reaction is a double replacement reaction, and each compound has the same set of ions.

Explanation:

When two different compounds chemically react with each other and their ions get exchanged with each other then it leads to the formation of two new compounds. This type of reaction is called double displacement reaction.

For example, \(KBr + AgNO_{3} \rightarrow KNO_{3} + AgBr(\downarrow)\)

Here, both KBr and \(AgNO_{3}\) are ionic compounds that leads to the formation of two new ionic compounds which are \(KNO_{3}\) and AgBr.

Thus, we can conclude that the given type of chemical reaction is a double replacement reaction, and each compound has the same set of ions.

Answer: 4 FeSO4(s) + O2(g) + 10 H2O(l) ---> 4 Fe(OH)3 + 4 H2SO4

Explanation:

FeSO4(s) + O2(g) + H2O(l) = Fe(OH)3 + H2SO4

In other to balance the equation, the total number of atoms of each element on the Left Hand Side (LHS) of the equation must be equal to the total number of atoms on the  Right Hand Side (RHS) of the equation.

Add the following coefficients to the equation;

FeSO4 = Add 4,  H20 = Add 10,  Fe (OH)3 = Add 4 and H2SO4 = Add 4

By doing this, you will discover that the total number of atoms on bothe sides of the equation are balanced; thus we have;

4 FeSO4(s) + O2(g) + 10 H2O(l) ---> 4 Fe(OH)3 + 4 H2SO4

Answer:

...................................

Answer:

jhykkjjhyefghhyuyy. iig jkhg k

The empirical formula of the compound is \(CH_2\)

The amount of C and H present in 100 g of the compound are 86 g and 14 g respectively. Option A.

To determine the empirical formula of polyethylene, we first need to find the ratio of carbon to hydrogen atoms in the compound.

Assuming 100.0 g of polyethylene, we can convert the percentages to masses:

Mass of carbon = 86.0% * 100.0 g = 86.0 g

Mass of hydrogen = 14.0% * 100.0 g = 14.0 g

Moles of carbon = 86.0 g / 12.01 g/mol = 7.163 mol

Moles of hydrogen = 14.0 g / 1.008 g/mol = 13.889 mol

Carbon:Hydrogen = 7.163 mol : 13.889 mol

Therefore, the empirical formula of polyethylene is CH2.

Since the compound is 86% C and 14% H, the amount of C and H present in 100 g of the compound would be 86 g and 14 g respectively.

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Carbon forms four covalent bonds in neutral compounds.

Carbon is an element located in Group 14 of the periodic table and has four valence electrons in its outermost energy level. To achieve a stable electron configuration, carbon can share these valence electrons with other atoms by forming covalent bonds. In a covalent bond, two atoms share a pair of electrons, resulting in a shared electron pair between the atoms.

Since carbon has four valence electrons, it can form up to four covalent bonds. Each covalent bond involves the sharing of one electron pair. By sharing electrons, carbon can complete its octet (or duet in the case of hydrogen) and achieve a more stable configuration. This ability to form four covalent bonds allows carbon to exhibit diverse bonding patterns and form a wide range of compounds, including organic compounds that serve as the building blocks of life.

In summary, carbon forms four covalent bonds in neutral compounds, allowing it to participate in various chemical reactions and form complex molecular structures.

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you decide to test your pillbugs' preference for an acidic environment versus a nonacidic environment. on one side of the chamber you place filter paper moistened with water. Dry filter paper is appropriate to place on the other side to test this variable.

Armadillidiidae (Pillbugs) is a family of woodlice, a terrestrial crustacean group in the order Isopoda. Unlike members of some other woodlice families, members of this family can roll into a ball, an ability they share with the outwardly similar but unrelated pill millipedes and other animals. This ability gives woodlice in this family their common names of pill bugs or roly polies.Other common names include slaters, potato bugs, and doodle bugs. Most species are native to the Mediterranean Basin, while a few species have wider European distributions. The best-known species, Armadillidium vulgare, was introduced to New England in the early 19th century and has become widespread throughout North America.

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The solution with the highest boiling point is Cu(CH3COO)2, followed by Glucose, FeBr3, and Fe(CH3COO)2 with the lowest boiling point.

The boiling point of an aqueous solution is determined by the number of particles present in the solution. The more particles present, the higher the boiling point. This is due to the fact that the particles interfere with the ability of the solvent molecules to escape into the gas phase, thereby requiring more energy (higher temperature) to reach the boiling point.

In the case of the given solutions, we can determine the number of particles by multiplying the molarity (m) by the number of ions produced by each compound when dissolved in water.

For FeBr3, the number of particles is 0.113 m × 4 ions = 0.452
For Fe(CH3COO)2, the number of particles is 9.75×10^-2 m × 3 ions = 0.2925
For Cu(CH3COO)2, the number of particles is 0.160 m × 3 ions = 0.480
For Glucose, the number of particles is 0.420 m × 1 molecule = 0.420

Based on the number of particles, we can match the solutions with the appropriate boiling point:

( C ) 1.0.113 m FeBr3
( D ) 9.75x10^-2 Fe(CH3COO)2
( A ) 3.0.160 m Cu(CH3COO)2
( B ) 4.0.420 m Glucose (nonelectrolyte)

Therefore, the solution with the highest boiling point is Cu(CH3COO)2, followed by Glucose, FeBr3, and Fe(CH3COO)2 with the lowest boiling point.

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The type of mixture whose components are evenly distributed throughout is a homogeneous mixture.

A homogeneous mixture is a mixture in which the components are uniformly distributed throughout. The mixture appears to be the same throughout, and it has the same physical and chemical properties throughout. The composition of the components of a homogeneous mixture is uniform. An example of a homogeneous mixture is a solution of sugar and water. Sugar dissolves in water to form a homogeneous mixture. Another example is salt and water. Salt dissolves in water to form a homogeneous mixture.

However, These are the kinds of combinations where the ingredients are evenly dispersed throughout. In other words, "they are consistent throughout. In a homogenous mixture, we can only see one phase of the substance and components are evenly distributed throughout .

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The empirical formula for the compound is Ca(OH)₂.

To determine the empirical formula of the compound, we need to find the simplest whole-number ratio of the elements present. We can do this by calculating the number of moles of each element and then finding the ratio between them.

Mass of calcium (Ca) = 13.5 grams

Mass of oxygen (O) = 10.8 grams

Mass of hydrogen (H) = 0.675 grams

First, we need to convert the masses of each element to moles using their respective atomic masses.

Atomic mass of Ca = 40.08 g/mol

Atomic mass of O = 16.00 g/mol

Atomic mass of H = 1.01 g/mol

Number of moles of Ca = 13.5 g / 40.08 g/mol = 0.3367 mol

Number of moles of O = 10.8 g / 16.00 g/mol = 0.675 mol

Number of moles of H = 0.675 g / 1.01 g/mol = 0.6693 mol

Next, we need to find the simplest whole-number ratio by dividing the number of moles of each element by the smallest number of moles obtained.

Dividing by 0.3367 (smallest value):

Number of moles of Ca = 0.3367 mol / 0.3367 mol = 1

Number of moles of O = 0.675 mol / 0.3367 mol = 2.005

Number of moles of H = 0.6693 mol / 0.3367 mol = 1.988

Rounding these values to the nearest whole number, we have:

Number of moles of Ca = 1

Number of moles of O = 2

Number of moles of H = 2

Thus, the empirical formula of the compound is Ca(OH)₂.

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Answer:

helps to trap heat in our atmosphere