Which will have a greater acceleration if they are both thrown with the same force, a 50 g potato or a 400 g potato

Answer:

According to the problem the diameter of the wire , r1

The outer diameter after wrapping , r2 = 7mm

The thickness of the plastic cover , t

Length of the wire = I

The Thermal conductivity of cover = = k

Current pass through the wire = I

Due to current passing voltage dropped, is V

The temperature = T

Heat transfer coefficient = h

The rate at which the heat is generated in the wire,

q= VI = 8 * 10 =80 Watt

Now for calculating the resistance for each medium .

x1 = 1/hA2 = 1/2 x 2π x 0.0035 x 5 =  0.76 K/ W

x2 = ln r2/r1/2πkl = ln 0.0035/0.0015 /2π 0.15 x 5 = 0.179 K/W

Therefore the total resistance ,

R = x1+x2 = 0.76 +0.179 = 0.939 K/W

Now to calculate the temperature at the interface of the wire,

q= R(T - t)

=> 80 = 0.939(T -30- 273)

T = 378.12 K

Critical radius  is r(critical)

r(critical) = K/h = 0.15/12 = 0.0125 m or 12.5 mm

Before joining a fitting and pipe using socket fusion, it is important to ensure that both the fitting and pipe are clean and free from any debris or contaminants. Additionally, the correct size fitting and pipe must be used to ensure a proper fit.

Socket fusion is a method of joining plastic pipes and fittings together by heating the material and then pressing the heated ends together to form a strong bond. Before the socket fusion process begins, it is important to prepare both the fitting and pipe by ensuring they are clean and free from any debris or contaminants.

This can be achieved by using a specialized cleaning tool or wiping the surfaces with a clean cloth. Additionally, it is crucial to use the correct size fitting and pipe to ensure a proper fit and prevent any leaks or issues in the future. Proper preparation of the materials is crucial to ensuring a successful socket fusion joint.

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The volume of material used in making 100 ft of 4 in. type K, copper tubing will be 1443.3 in³ or 0.835 ft³

Volume is a measurement of three-dimensional space that is occupied. It is frequently numerically quantified using SI-derived units or various imperial or US customary units. The definition of length is linked to the definition of volume.

Let's begin by listing out the given variables:

length (l) = 100 ft = 1200 in, nominal size = 4 in

The dimension and physical characteristics of type M copper tubing of nominal size 4 inch are given in the copper tube of industry-standard guide of the design and installation of the piping system is illustrated.

Outer diameter (Do) = 4.125 in ⇒ ro = Do ÷ 2 = 2.0625 in, Inner diameter (Di) = 3.935 in ⇒ ri = Di ÷ 2 = 1.9675 in

calculate the volume of the pipe, we use the formula

V = π(ro² - ri²) * l

V = π(2.0625² - 1.9675²) * 1200

V = 1443.3 in³ or 0.835 ft³

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Answer:

The correct answer is "\(K_c=6.0369 \ MPa\sqrt{m}\)".

Explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

  = 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒  Maximum stress, \(\sigma=\frac{P}{A}\)

                                      \(=\frac{50000}{(\frac{\pi}{4}\times 32^2)}\)

                                      \(=62.20 \ N/mm^2\)

Now,

⇒  Fracture tougness, \(K_c=Y \sigma\sqrt{\pi a}\)

On substituting the values, we get

                                           \(=1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}\)

                                           \(=6.0369 \ MPa\sqrt{m}\)

Answer:

SpaceX

Explanation:

SpaceX successfully launches 60 more Starlink satellites as it continues towards 2020 service debut. SpaceX has launched another big batch of Starlink satellites, the low Earth orbit spacecraft that will provide connectivity for its globe-spanning high-bandwidth broadband internet network.

Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

Answer:

1) ∀x [ Tiger(x) → Fast(x) ]

2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) ∀x [ Prime(x) → Odd(x) ]

4) ∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) ∀xэy [ I(x) → greater (y, x) ]

Explanation:

Translating the statements into first Order Logic and their negations

1)   All tigers are fast. Domain: animals.

∀x [ Tiger(x) → Fast(x) ]

2)  Some tigers are fierce and dangerous. Domain: animals

эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) Every prime number is odd. Domain: positive integers

∀x [ Prime(x) → Odd(x) ]

4)  All prime numbers except two are odd. Domain: positive integers

∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) All fruits are either yellow or red. Domain: produce.

∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) For every integer number, there exist a bigger integer. Domain: integers.

∀xэy [ I(x) → greater (y, x) ]

Answer:

Answer:

1) ∀x [ Tiger(x) → Fast(x) ]

2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) ∀x [ Prime(x) → Odd(x) ]

4) ∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) ∀xэy [ I(x) → greater (y, x) ]

Explanation:

Translating the statements into first Order Logic and their negations

1)   All tigers are fast. Domain: animals.

∀x [ Tiger(x) → Fast(x) ]

2)  Some tigers are fierce and dangerous. Domain: animals

эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) Every prime number is odd. Domain: positive integers

∀x [ Prime(x) → Odd(x) ]

4)  All prime numbers except two are odd. Domain: positive integers

∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) All fruits are either yellow or red. Domain: produce.

∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) For every integer number, there exist a bigger integer. Domain: integers.

∀xэy [ I(x) → greater (y, x) ]

Explanation:

Explanation:

A research report is a well-crafted document that outlines the processes, data, and findings of a systematic investigation. It is an important document that serves as a first-hand account of the research process, and it is typically considered an objective and accurate source of information.

(1) to build knowledge and facilitate efficient learning, (2) to understand various issues, (3) to know the truth and prove lies, and (4) to seek opportunities among others

At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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The correct response is b. Backplane. Backplane server component may be used to add a Host Bus Adapter (HBA) to the system board.

A computer's backplane is a printed circuit board that offers a parallel configuration of expansion sockets or backplane connectors that are all connected pin-to-pin to form a structure known as a bus. There is a restriction dependent on the type of socket being used, yet multiple sockets can be connected. The motherboard of a computer is a printed circuit board, just like a backplane, but it does not have the on-board processing and storage components. A backplane is a board with very little or no active circuitry, in contrast to a motherboard, which assembles all of the computer's essential system parts onto a single printed circuit board. A backplane, also known as a backplane system, is a connector that connects various electrical circuits.

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If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity.

Closing the throttle, turning off the fuel pump, setting the mixture control to idle cutoff, and simply cranking the engine is the most reliable hot start method I've found.

If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity. If you are unable to climb, close both throttles and land straight ahead.

The typical practice for the majority of aircraft would be to abandon takeoff if an engine failed during takeoff. In small aircraft, the pilot should turn the throttles down to idle, activate the speed brakes (if provided), and apply the brakes as needed if the engine fails before VR (Rotation Speed).

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Answer:

up up down down

Explanation:

left right left right b a select start

Answer:

False

Explanation:

It can only survive outside of the body for six days

Answer:

A) condenser pressure = 9.73 kPa,

B) 10242 kw

C) 36.9%

Explanation:

given data

entrance pressure of steam = 12.5 MPa

temperature of steam = 550⁰c

flow rate of steam = 7.7 kg/s

outer pressure = 2 MPa

reheated steam temperature = 450⁰c

isentropic efficiency of turbine( nt ) = 85% = 0.85

isentropic efficiency of pump = 90% = 0.90

From steam tables

at 12.5 MPa and 550⁰c ; h3 = 3476.5 kJ/kg,  S3 = 6.6317 kJ/kgK

also for an Isentropic expansion

S4s = S3 .

therefore when S4s = 6.6317 kJ/kg and P4 = 2 MPa

h4s = 2948.1 kJ/kg

nt = 0.85

nt (0.85) = \(\frac{h3-h4}{h3-h4s}\) = \(\frac{3476.5 - h4}{3476.5 - 2948.1}\)

making h4 subject of the equation

h4 = 3476.5 - 0.85 (3476.5 - 2948.1)

h4 = 3027.3 kj/kg

at P5 = 2 MPa and T5 = 450⁰c

h5 = 3358.2 kj/kg,  s5 = 7.2815 kj/kgk

at P6 , x6 = 0.95  and s5 = s6

using nt = 0.85 we can calculate for h6 and h6s

from the chart attached below we can see that

p6 = 9.73 kPa, h6 = 2463.3 kj/kg

B) the net power output

solution is attached below

c) thermal efficiency

thermal efficiency = 1 - \(\frac{qout}{qin}\) = 1 - ( 2273.7/ 3603.8) = 36.9% ≈ 37%

Answer:

dddddddddddddddddddddddddddddddddddddd

Explanation:

One situation that can make a measurement with a laser inaccurate is measuring to a heavy reflective surface

Reflective surfaces or ground-primarily based totally albedo modification (GBAM) is a sun radiation control technique of improving the Earth's albedo (the cappotential to mirror the visible, infrared and ultraviolet wavelengths of the sun, lowering warmth switch to the floor). The IPCC defined this technique as "whitening roofs, adjustments in land use control (e.g., no-until farming), alternate of albedo at a bigger scale (masking glaciers or deserts with reflective sheeting and adjustments in ocean albedo)."

The maximum famous kind of reflective floor is a kind of roof referred to as the "cool roof". While cool roofs are commonly related to white roofs, they arrive in a lot of hues and substances and are to be had for each industrial and home buildings.

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Your Answer would be A I believe.

The calculated value is 9.5 g/cm³. For the density calculation, we need to know the mass and the volume of the unit cell.

When = = = 90 and a = b = c, we have a cubic lattice; however, if c is greater than a and b (a= b), we have a tetragonal lattice. This lattice is identical to the simplest one, the cubic lattice, which can be simple or primitive cubic or body centered. Likewise, the tetragonal lattice can be primitive or body centered. When they inform us that there are atoms at all four corners and one in the center of the unit cell, we know it's a body-centered lattice.

= 123 g / mol x 1 mol / 6.022 x 10²³  x 2 atoms/unit cell

= 4.1 g x 10⁻²² g/unit cell

Finally, the density is calculated.

d = m/V

= 4.1  x 10⁻²² g /4.3 x 10⁻²³ cm³

= 9.5 g/cm³

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A

It would be B but I say that it isn't because children under 3 should be riding a buckle up just for safety

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Excessive groundwater withdrawal has numerous potential consequences. Subsidence of the surface, the collapse of overlying soils, and other geological phenomena are some of the main responses. The answer to this question is (D) All of the choices are correct.

Water is crucial in everyone's lives and to the planet. Water is, without a doubt, one of the most valuable natural resources on the planet.

However, overexploitation of groundwater has various potential consequences, including:A.

Surface subsidenceB. Swelling of aquifer rocksC. Increased permeability of aquifer rocksD. All of the choices are correct.

From the options given above, All of the choices are correct. Therefore, excessive groundwater withdrawal could cause numerous environmental issues, including subsidence of the surface, the collapse of overlying soils, and other geological phenomena. Excessive groundwater withdrawal might even create a slew of other environmental concerns that will ultimately harm people's lives. Hence, groundwater conservation is necessary.

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Answer: 45

Explanation:just cuase I need to

Passive continental margins are characterized by three major features, which are sedimentary deposits, broad continental shelves, and a lack of tectonic activity.

Firstly, sedimentary deposits are a major feature of passive continental margins, as they accumulate over time due to erosion and sedimentation processes.
Secondly, broad continental shelves are another major feature of passive continental margins, as they are typically wide and gently sloping. These shelves are formed by the deposition of sediments, which can be transported from nearby rivers or eroded from the adjacent continental landmass.
Lastly, a lack of tectonic activity is a defining feature of passive continental margins. Unlike active continental margins, which are located at plate boundaries and experience intense tectonic activity, passive margins are located within a single tectonic plate and experience relatively little deformation or seismic activity.

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Answer:

no not for all that in the set

Explanation:

A V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number: A. 6.

An injector can be defined as a mechanical device that is designed and developed for the introduction of fuel into the internal combustion system of an engine, especially under pressure.

In Engineering, there are two (2) main types of fuel injection system and these include the following:

A sequential fuel injection is typically designed and developed to spray fuel into the internal combustion system of an engine based on the firing order that is configured within it by the manufacturer.

As a general rule, one of the two-paired spark plugs within the internal combustion system of an engine is always designed to have a negative polarity while the other spark plug is designed to have a positive polarity always.

In this context, we can infer and logically deduce that a V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number 6.

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Complete Question:

The coil polarity in a waste-spark system is determined by the direction in which the coil is wound (left-hand rule for conventional current flow) and can't be changed. for example, if a v-8 engine has a firing order of 18436572 and number 1 cylinder is on compression, which cylinder will be on the exhaust stroke?

A. 6

B. 4

C. 8

D. 2

Beth has 444 extra N95 masks and she wants to distribute them among her 777 dearest friends, with each receiving at most one mask. The number of ways to choose a group of 444 people from a group of 777 people, is 2.4 × 10¹⁸ (Option a).

The given problem is related to the concept of permutations and combinations. The total number of ways to distribute 444 extra N95 masks among 777 people is the same as the number of ways to choose a group of 444 people from a group of 777 people, which can be found using the formula:

C(777, 444) = 777!/(444!(777-444)!) = 2400572187891316020 ≈ 2.4 × 10¹⁸.

However, since each person can receive at most one mask, the actual number of ways to distribute the masks is simply the number of ways to choose a group of 444 people from a group of 777 people, which is C(777, 444) = 2400572187891316020 ≈ 2.4 × 10¹⁸. Therefore, the correct option is (a) 2401.

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Beth has 444 extra N95 masks and she wants to distribute them among her 777 dearest friends, with each receiving at most one mask. The problem is to find out in how many ways this can be done.

If each of the 777 friends receives only one mask, then there are 777 ways to distribute the masks. But, Beth has only 444 masks, so 333 friends must go without a mask. In how many ways can she select a group of 333 friends from the 777 friends? Since each friend is either in the group or out of the group, there are 2 possibilities for each friend.

There are `2^777` total ways to select the group. However, we must subtract the 777 ways to select the groups where each of the chosen 333 friends gets a mask. Therefore, there are `2^777 - 777` ways to distribute the masks. The closest answer to this is e) 16384. However, this answer is not correct. The correct answer is f) none of the above.

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Answer:

water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm

Explanation:

Given the data in the question;

A = 200 hectare =  2 × 10⁶ m²

water evaporated Ve = 2 × 10⁶ m² × 3 × 10⁻² = 60000 m³ { in 24 hrs }

Water added by storm in 24hrs Vi = 3 × 24 × 3600 = 259200 m³

now let water released be Vr

ΔV = V_ini - V_final = 0

Vi - Ve - Vr = 0

Vr = Vi - Ve

Vr = 259200 m³ - 60000 m³

Vr = 199200 m³ = 19920000 m² - cm

Vr = 1992 ha-cm

Therefore, water released through the bottom of the reservoir in 24 hrs is 1992 ha-cm

Answer:

One corner ( D )

Explanation:

when dimensioning the location of a house on site the standard and the acceptable procedure is to ; Dimension One corner of the house

Adjacent lots is a term used to describe parcels of the site that meet each other along their boundary lines. and they also include parcels that may be separated by streets