Who can help me out please I’ll mark brainliest

Answer:

In the middle the narration changes to the inner dialogue of Leamas. We are given the opportunity to be with his thoughts and experience the character for ourselfs

Answer:

The experimental and theoretical probabilities will be completely random because flipping the coin which, of course, has two different sides, the probability is cut perfectly in half.

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Step-by-step explanation:

Answer:

the cost per liter of the paint is equal to 24 8/liter

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The proportion of woodlice with antenna lengths greater than 0.27 inches is approximately 0.3446 (rounded to four decimal places).

We can use the z-score formula to standardize the value of 0.27 and calculate the corresponding proportion.

z = (x - μ) / σ

where x is the antenna length we are interested in, μ is the mean antenna length, σ is the standard deviation, and z is the standardized score.

Substituting the given values, we get:

z = (0.27 - 0.25) / 0.05 = 0.4

Using a standard normal distribution table or calculator, we can find the proportion of values that fall to the right of z = 0.4. This is equivalent to finding the area under the standard normal curve to the right of z = 0.4.

The table or calculator gives us a value of approximately 0.3446.

Therefore, the proportion of woodlice with antenna lengths greater than 0.27 inches is approximately 0.3446 (rounded to four decimal places).

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Answer:d

Step-by-step explanation:

The answer is d. None of the above is true.

To calculate velocity, we need to use the equation:

Velocity = M * P / Y

Given:

M = 1,000

P = 2.25

Y = 2,000

Plugging in the values:

Velocity = 1,000 * 2.25 / 2,000

Simplifying:

Velocity = 2.25 / 2

The result is:

Velocity = 1.125

Therefore, the correct answer is: d. None of the above is true.

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The probability that he misses the train today is 0.135 or 13.5%.

P(Class runs late)=30%=0.30

P(Miss train ∣ Class runs late)=45%=0.45

General multiplication rule:

P(A and B)=P(A)×P(B ∣ A)

Using the general multiplication rule, we then obtain (and using that the student always catches his train if the class ends on time) :-

P( Miss train)=P( Miss train and Class runs late)=P(Class runs late)×P(Miss train ∣ Class runs late)

= 0.30×0.45

= 0.135

= or 13.5%.

So, the the probability that he misses the train today is 0.135 or 13.5%.

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Answer:

Step-by-step explanation:

a2 = -2

a + d  =  -2

a + 6d = 7

-5d  =  -9

d  =  9/5

a = -19/5

an  =  a + ( n-1 ) d

an =  -19/5 + ( n-1 ) 9/5

Answer:

scalene right

Step-by-step explanation:

all side are opposite and there is a 90% so that makes it right

Answer:

900 outfits

Step-by-step explanation:

You just have to multiply them all together :)

New tables created with the make-table query retain the field data type of the underlying table(s).

Tables and graphs are visual representations of data that are used to organize data and reveal patterns and relationships. Tables and graphs are frequently used by researchers and scientists to report research findings.

A make table query retrieves data from one or more tables before loading the results into a new table. That new table can live in the database you're currently working in, or it can be created in a different database. Make table queries are typically used when you need to copy or archive data.

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Answer:

these are the ten numbers :

0 8 2 6 9 2 0 8 0 0

Explanation

to solve for x, isolate it

so

Step 1

Answer:

7y + 4

Step-by-step explanation:

2y+(4+5y)

2y + 4 + 5y

combine y terms:

7y + 4

Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

To determine when tan(theta) is undefined on the unit circle, we need to remember the definition of the tangent function.
Tangent is defined as the ratio of the sine and cosine of an angle. Specifically, tan(theta) = sin(theta)/cos(theta).

Now, we know that cosine can never be equal to zero on the unit circle, since it represents the x-coordinate of a point on the circle and the circle never crosses the x-axis. Therefore, the only way for tan(theta) to be undefined is if the cosine of theta is equal to zero.
There are two values of theta on the unit circle where cosine is equal to zero: pi/2 and 3pi/2.

At theta = pi/2, we have cos(pi/2) = 0, which means that tan(pi/2) = sin(pi/2)/cos(pi/2) is undefined.
Similarly, at theta = 3pi/2, we have cos(3pi/2) = 0, which means that tan(3pi/2) = sin(3pi/2)/cos(3pi/2) is also undefined.
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

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As the true mean moves farther away from the hypothesized value, the probability of a Type II error decreases, leading to a higher probability of correctly detecting a true effect or difference.

As the true mean gets farther away from the hypothesized value in a hypothesis test, the probability of a Type II error (also known as a false negative) will decrease.

In a hypothesis test, the null hypothesis assumes that there is no significant difference or effect, while the alternative hypothesis suggests that there is a significant difference or effect.

A Type II error occurs when we fail to reject the null hypothesis when it is actually false. In other words, it is a failure to detect a true effect.

When the true mean is far away from the hypothesized value, the difference between the observed data and the hypothesized value becomes more pronounced.

This increases the likelihood of obtaining a test statistic that falls in the critical region (the region where we reject the null hypothesis). Consequently, the probability of correctly rejecting the null hypothesis (i.e., the probability of not making a Type II error) increases.

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The issue price of Bondable Inc.'s $100,000, 10-year, 9% bonds that pay interest annually on January 1, when the going market interest rate was 10%, was $92,582.

Bond prices are determined by the market interest rates prevailing at the time of issuance. When the market interest rates rise, bond prices fall, and vice versa. In this case, Bondable Inc. issued 10-year bonds with a face value of $100,000 and a coupon rate of 9% that pays interest annually on January 1. However, the market interest rate was 10% at the time of issuance.

To calculate the issue price of the bonds, we need to use the present value formula, which discounts the future cash flows of the bond at the market interest rate. The formula is:

PV = (C / r) x [1 - 1 / (1 + r)^n] + F / (1 + r)^n

Where:

PV = Present value of the bond

C = Annual coupon payment

r = Market interest rate

n = Number of periods

F = Face value of the bond

Using this formula, we can calculate the present value of the bond as follows:

PV = ($9,000 / 0.10) x [1 - 1 / (1 + 0.10)^10] + $100,000 / (1 + 0.10)^10

PV = $59,383.11 + $33,198.44

PV = $92,581.55

Therefore, the issue price of the bonds was $92,582, which is lower than the face value of $100,000. This is because the market interest rate was higher than the coupon rate of the bonds, making them less attractive to investors. The lower issue price compensates investors for the lower interest rate they will receive compared to the market rate.

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Answer:

1,2,3,4,6,8,12,24

Step-by-step explanation:

Answer:

See attachment

Step-by-step explanation:

Answer:

D. Make the column wider

Step-by-step explanation:

Answer: 3.175%

Step-by-step explanation:

(63/100)(2/1)

Cross multiply = 200

Then divide 200÷63= 3.175

Answer:

39.69%

Step-by-step explanation:

\(\frac{63}{100}\) * \(\frac{63}{100}\) = .3969

Answer:

35% of 300 is 105

Adults=105 , children=195

195 children were present.

Answer:

Step-by-step explanation:

First, you need to be familiar with the volume equation for the object in question.

The equation is \(v= (\frac{\pi r^2h}{2})\)

For the outer  shape we are given the diameter (which is just r*2), making the radius 8

For the the first object the equation becomes\(\frac{\pi(8^2)16}{2}\) which then comes out to 1608.49 which when rounded is 1608

Since we are to assume the shaded object is in the middle, we see that the distance from the shaded object to the other object is 4. So to find the radius of the shaded object we need to subtract 4 from the radius of the bigger object. The radius of the shaded object is 4

Using the same equation above we get that the volume is equal to \(\frac{\pi 4^{2}8 }{2}\) which comes to 201.06 which when rounded is 201

If you need the outer object without the volume of the inner object just subtract 201 from 1608

Two questions about systems aaa and bbb, the given system is:

System aaa: x = -1/3 and y = -7/3
System bbb: x = -1/3 and y = -7/3

To answer two questions about systems aaa and bbb, let's first clarify the given system:

System aaa:
x - 4y = 9

System bbb:
2x + y = -3

Question 1: Solve system aaa.
To solve system aaa, we'll use the method of substitution:

Step 1: Solve one equation for one variable.
From the first equation in system aaa, we can isolate x:
x = 4y + 9

Step 2: Substitute the expression from Step 1 into the other equation.
Substitute the expression for x in the second equation of system aaa:
2(4y + 9) + y = -3

Step 3: Simplify and solve for y.
8y + 18 + y = -3
9y + 18 = -3
9y = -3 - 18
9y = -21
y = -21/9
y = -7/3

Step 4: Substitute the value of y into the expression for x.
Using the first equation in system aaa:
x - 4(-7/3) = 9
x + 28/3 = 9
x = 9 - 28/3
x = (27 - 28)/3
x = -1/3

Therefore, the solution to system aaa is x = -1/3 and y = -7/3.

Question 2: Solve system bbb.
To solve system bbb, we'll use the method of substitution:

Step 1: Solve one equation for one variable.
From the second equation in system bbb, we can isolate y:
y = -2x - 3

Step 2: Substitute the expression from Step 1 into the other equation.
Substitute the expression for y in the first equation of system bbb:
x - 4(-2x - 3) = 9

Step 3: Simplify and solve for x.
x + 8x + 12 = 9
9x + 12 = 9
9x = 9 - 12
9x = -3
x = -3/9
x = -1/3

Step 4: Substitute the value of x into the expression for y.
Using the second equation in system bbb:
y = -2(-1/3) - 3
y = 2/3 - 3
y = 2/3 - 9/3
y = -7/3

Therefore, the solution to system bbb is x = -1/3 and y = -7/3.

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If Joel has brownie with length 7cm and width 5cm , then the Area of the brownie is 35 cm² .

The Area of a Rectangle can be determined by multiplying its length(l) and width(w) . that means "Area is = Length × Width" ;

In the case of Joel's brownie, the length of brownie is 7 centimeters and the width of brownie is 5 centimeters.

So , By multiplying these two measurements, we can find the area of the brownie.

Area = 7cm × 5cm = 35 square cm .

Therefore, the area of the brownie is 35 square centimeters.

The given question is incomplete , the complete question is

Joel has brownie. The length of each brownie is 7cm and the width is 5cm find the area of the brownie .

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Answer:

58.08

Step-by-step explanation:

Answer:

58.08

Step-by-step explanation:

39.67+18.41=58.08

Roger has enough stainless steel pipe to replace the chimney liner, with a slight surplus remaining.

To determine if Roger has enough stainless steel pipe for the chimney liner, we need to convert the given measurements to a consistent unit of measurement. Since the length of the liner required is given in feet, we need to convert the 400 inches of stainless steel pipe to feet.

There are 12 inches in a foot, so 400 inches is equal to 400/12 = 33.33 feet (approximately).

Comparing this converted length of the stainless steel pipe (33.33 feet) with the length of the liner required (33 feet), we can see that Roger does indeed have enough pipe. In fact, he has slightly more than required.

Since the length of the liner required is 33 feet and Roger has 33.33 feet of stainless steel pipe available, there is a surplus of approximately 0.33 feet (about 4 inches) of pipe. This additional length is more than enough to cover any potential measurement errors or adjustments needed during the installation process.

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Step-by-step explanation:

That means the 96 is  75% of your grade

   96 (.75) + 75 (.25) = 90.75  final grade

So

Check option D

Total

Option D is correct

The equation relating x, y, and z is:

z = 0.5 * x * y.

In the given problem, the relationship between x, y, and z can be expressed by the equation z = k * x * y, where k represents the constant of proportionality. By substituting the values of x = 4 and y = 5, when z is equal to 10, we can determine the value of the constant of proportionality, k, and further define the relationship between the variables.

To find the constant of proportionality, we substitute the known values of x = 4, y = 5, and z = 10 into the equation z = k * x * y. This gives us the equation 10 = k * 4 * 5. By simplifying the equation, we have 10 = 20k. To isolate k, we divide both sides of the equation by 20, resulting in k = 0.5. Therefore, the equation relating x, y, and z is z = 0.5 * x * y, meaning that z is directly proportional to the product of x and y with a constant of proportionality equal to 0.5.

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The estimates of β0 and β1 depend on both the old and the new observations.

a) The model in matrix form is Y = Xβ + e where Y is an n x 1 vector of responses, X is an n x 2 matrix of predictor variables, β is a 2 x 1 vector of coefficients, and e is an n x 1 vector of errors. We have X = [1 x1; 1 x2; ... ; 1 xn] where xi is the value of the predictor variable for the ith observation.

b) The normal equations are X'Xβ = X'Y, where X' is the transpose of X. Expanding, we get:

(∑1n1 + ∑1nxi^2)β0 + (∑1nxi)β1 = ∑1nYi

(∑1nxi)β0 + (∑1nxi^2)β1 = ∑1nxiYi

Solving these equations for β0 and β1, we get:

β0 = (1/n) ∑1n(Yi - β1xi)

β1 = (∑1nxiYi - (1/n)(∑1nxi)(∑1nYi)) / (∑1nxi^2 - (1/n)(∑1nxi)^2)

The solution is unique since the matrix X'X is invertible.

c) The least squares estimate of β0 + β1 is given by the sum of the estimates of β0 and β1, which is:

(1/n) ∑1nYi

d) β1 is estimable since there is a unique solution for it.

e) The model in matrix form is Y = Xβ + e where Y is an (n+1) x 1 vector of responses, X is an (n+1) x 2 matrix of predictor variables, β is a 2 x 1 vector of coefficients, and e is an (n+1) x 1 vector of errors. We have X = [1 x1; 1 x2; ... ; 1 xn; 1 xn+1] where xi is the value of the predictor variable for the ith observation.The least squares estimate of β is given by:

β = (X'X)^(-1)X'Y

Expanding, we get:

β0 = (1/(n+1)) * (Σ1^n Yi + Yn+1 - 2β1 * Σ1^n xi - 2xn+1β1)

β1 = (∑1nxiYi + xn+1Yn+1 - (1/(n+1))(Σ1^n xi + xn+1)^2) / (∑1nxi^2 + xn+1^2 - (1/(n+1))(Σ1^n xi + xn+1)^2).

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