WORTH 50 POINTS!!!

A fellow student would like to know how magnets behave when considering their magnetic
poles. Construct a drawing to show how magnetic attraction is different from repulsion. Be sure
to properly label the magnetic poles. Include magnetic field lines to indicate where the magnetic
field is the strongest and weakest

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)

Pressure (P) = Density (ρ) × g × Depth (h)

Given: Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Depth (h) = 6 m

Using the given values, one can calculate the pressure:

Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure

= 58800 kg·m⁻¹·s⁻²

Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:

Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)

Pressure = 580.124 atm

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The energy needed to heat the copper from 25 °C  to 45 °C if the specific heat capacity of copper is 380 J/kg °C is 9880 J

ΔT = T - To

ΔT = Change in temperature

T = Final temperature

To = Initial temperature

T = 45 °C

To = 25 °C

ΔT = 45 - 25

ΔT = 20 °C

q = m C ΔT

q = Heat Energy

m = Mass

C = Specific heat capacity

m = 1.3 kg

C = 380 J / kg °C

q = 1.3 - 380 * 20

q = 9880 J

Therefore, the energy needed to heat the copper to 45 °C is 9880 J

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90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .

Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.

In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.

Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.

Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J

We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:

m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg

Finally, we round the mass to two significant digits and convert it to grammes:

m2 = 90.1 g

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Answer:

The lithosphere is divided into huge slabs called tectonic plates. The heat from the mantle makes the rocks at the bottom of lithosphere slightly soft.

Explanation:

The Earth's lithosphere is broken into many small and large slabs of rock that are known as tectonic plates.

Earth is divided into four parts :

Lithosphere is the rigid and rocky outer portion of earth's surface. It consists of crust and upper mantle.

Asthenosphere is mostly found in the uppermost mantle of earth. It is weak in nature. Hot molten magma comes out from here.

Our earth is broken into 7 major and some minor plates.

7 Major Plates are :

Minor Plates are :

Hence, our lithosphere is divided into many small and large slabs of rock, and they are known as tectonic plates.

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A 9 kg explosive detonates into two fragments, each weighing 3 kg and 6 kg. The kinetic energy of mass 6 kg is 1.92 J, and the velocity of mass 3 kg is 1.6 m/s.

Therefore,

The total momentum of the bomb is unchanged before and after the explosion thanks to the conservation of linear momentum.

0 = 3 × 1.6 + 6v

v = 0.8 m/s

Kinetic energy of mass 6 kg is:

1/2 mv² = 1/2 × 6 × 0.8²

= 1.92 J

Hence, the correct option is c) 1.92J

The complete question is:

A bomb of mass 9kg explodes into 2 pieces of mass 3kg and 6kg. The velocity of mass 3kg is 1.6m/s, the kinetic energy of mass 6kg is :

A) 3.84J

B) 9.6J

C) 1.92J

D) 2.92J

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The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Answer:

-4

Explanation:

Electrons are negative while protons are positive.

To find the charge, add the number of protons to the number of electrons.

6+(-10)

6-10

-4 is the charge

Answer:

ni sin theta i = nr sin theta r       where theta i is the angle of   incidence     and theta  r the angle of refraction

For nr greater than ni   (air to water) theta r must be smaller and the image would be bent towards the normal

Answer:

F= 1.67 x \(10^{-13}\)N

Explanation:

I used this equation:

F = GMm/R²

Where M is mass 1

where m is mass 2

where R is distance

where F is gravitational force

A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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Answer:

\(t=0.0107\ \text{s}\)

Explanation:

\(x=10\cos(6t)\)

Now \(x=8\ \text{cm}\)

Substituting the value of \(x\) in the equation we get

\(8=10\cos6t\)

\(\Rightarrow 0.8=\cos6t\)

\(\Rightarrow \cos^{-1}0.8=6t\)

\(\Rightarrow t=\dfrac{\cos^{-1}0.8}{6}\)    the values here are used found in radians

\(\Rightarrow t=0.0107\ \text{s}\)

So, at \(t=0.0107\ \text{s}\) the value of \(x=8\ \text{cm}\).

Ans. 0.75

To convert watts into kilowatts we must divide it by 1000

so dividing 750W by 1000

we get,

750/1000 = 0.75

hence 750W in kilowatts equals to 0.75

Answer:

Hello

I think the first one is correct.

Explanation:

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 25 N

distance = 3 m

We have

work done = 25 × 3

We have the final answer as

Hope this helps you

Diagram D. shows the sound waves generated by a siren

that is moving with constant speed to the left.

A sound wave is the sample of disturbance caused by the movement of strength journeying thru a medium because it propagates far away from the supply of the sound. Sound waves are created by using object vibrations and bring strain waves, for example, a ringing cellular phone.

Sound waves fall into three classes: longitudinal waves, mechanical waves, and strain waves. keep studying to find out what qualifies them as such. Longitudinal Sound Waves A longitudinal wave is a wave wherein the movement of the medium's debris is parallel to the course of the energy transport. Sound propagates via air or different mediums as a longitudinal wave, in which the mechanical vibration constituting the wave occurs along the direction of propagation of the wave.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

Answer:

a) d = 3.6 km

b) 0.024°

Explanation:

To see the top of a 1 m tall deer over the surface of a 6400 km radius perfect sphere, the angle subtended is

cosθ = 6 400 000 / (6 400 001)

θ = 0.0320293...°

d = Rtanθ = 6 400 000tan0.0320293

d = 3,577.708... m

5 ft = 1.524 m

tanθ = 1.524 / 3577.7

θ = 0.0244063...°

Answer:

yes u are correct

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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Answer:

0 J

Explanation:

Since work done W = PΔV where P = pressure and ΔV = change in volume.

Since the volume is constant, ΔV = 0

So, Work done, W = PΔV = P × 0 = 0 J

So, the work done is 0 J.

Answer:

b

Explanation:

The relative permittivity of the insulator is εr = 1 / 2 = 0.5.

The relative permittivity of the insulator is calculated by applying the equation for the Coulomb force.

F = (kq²) / r²

where;

The initial force equation becomes;

3 = (kq²) / r²

Let's denote the relative permittivity as εr.

The new force equation becomes;

1.5 = (kq² x εr) / r²

Divide the two force equations;

(3 / 1.5) = (kq²) / (kq² x εr)

2 = 1 / εr

εr = 1/2 = 0.5

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Answer:

Given :  

m 1 =0.5 kg        

u 1 =0 m/s                    

m 2=0.005 kg      

u 2=200 m/s              

Let the velocity acquired by the block after the collision be V.

Using conservation of linear momentum before and after the collision :    P i =P f

​∴    m1u 1 +m 2u 2=(m 1+m 2 )V

OR    

0.5×0+0.005×200=(0.5+0.005)V              

⟹V≈1.9  m/s

Answer:

V= 1.9  m/s

Explanation:

I did the test

Hope this helps :)

The type of decay that has no charge associated with it is gamma decay (option C).

Gamma decay is a nuclear reaction with the emission of a gamma ray. A gamma ray is a high frequency/energy electromagnetic radiation emitted as a consequence of radioactivity.

Gamma rays are waves, not particles. This means that they have no mass and no charge.

This, therefore, suggests that when a gamma ray is emitted, no charge is involved.

Unlike alpha and beta decay that involves +2 and -1 charges respectively.

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The battery Peukert constants, n and, are around 1.223 and 2.486, respectively.

Wilhelm Peukert, a German physicist, proposed Peukert's law in 1897, which quantifies a battery's capacity in terms of the rate of discharge. The battery's useful capacity reduces as the rate of discharge rises. The supplied capacity decreases as discharge rate increases.

C = I⁽⁻ⁿ⁾ * t * λ

log(C) = -n * log(I) + log(λ) + log(t)

log(C1) = -n * log(I1) + log(λ) + log(t1)

log(C1) = -n * log(25) + log(λ) + log(10)

Similarly, for the second measurement, we have:

log(C2) = -n * log(I2) + log(λ) + log(t2)

log(C2) = -n * log(45) + log(λ) + log(4)

log(C1) - log(C2) = -n * (log(25) - log(45)) + log(10/4)

Simplifying, we get:

log(C1/C2) = n * log(45/25) + log(2.5)

Substituting the values, we get:

log(25/45) = n * log(45/25) + log(2.5)

Solving for n, we get:

n = (log(25/45) - log(2.5)) / log(45/25)

n = 1.223

log(C1) = -1.223 * log(25) + log(λ) + log(10)

log(C1) = -1.223 * 1.39794 + log(λ) + 1

Solving for log(λ), we get:

log(λ) = log(C1) + 1.223 * 1.39794 - 1

log(λ) = log(25) + 1.223 * 1.39794 - 1

log(λ) = 0.39794

Therefore, λ = 2.486.

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