Write the equation of the line through (5,3) prep to y=1/2x+3

Answer:

the percentage change on the drone is 42.86%

Step-by-step explanation:

The computation of the percentage change is shown below:

Since the helicopter was sold for $179.99

But amazon would be selling it for $125.99

So, the percentage change would be

= (Sale value -  sale value by amazon) ÷ ( sale value by amazon) × 100

= ($179.99 - $125.99) ÷ ($125.99) × 100

= 42.86%

Hence, the percentage change on the drone is 42.86%

Answer:

Is this an incomplete question?

Answer:

this isnt a question???

Step-by-step explanation:

The probability that Cynthia's morning porridge will be just right is 15%.

Probability is defined as the likeliness of an event to happen. It can be determined by dividing the total number of the desired outcome by the total number of samples.

The sum of the probabilities in a probability distribution is always 1.

If there are three outcomes: too cold, just right, and too hot, then the sum of their probabilities is equal to 1 or 100%.

P(too cold) + P(just right) + P(too hot) = 100%

35% + P(just right) + 50% = 100%

P(just right) = 100 - (35 + 50)

P(just right) = 100 - 85

P(just right) = 15%

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Answer:

3x - 5y

———————

    8  

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

.............................

Answer:

Ms. Costco was offered the best price. It would be $15,900.57 after tax

Step-by-step explanation:

Ms. Costco: $18,795 x .90 =$16,915.50 x .94=$15,900.57

Ms. Deele: $17,050 x .94=$16,027

To show that there exists an x ∈ (0, 2) such that ∫(0 to 2) f(a)x³ dz = 4f(x), we can use the intermediate value theorem.

If f is continuous on (0, 2), then by the intermediate value theorem, for any value c between f(0) and f(2), there exists a point x ∈ (0, 2) such that f(x) = c. We can choose c = (1/4)∫(0 to 2) f(a)x³ dz, and by applying the intermediate value theorem, we can conclude that there exists an x ∈ (0, 2) such that ∫(0 to 2) f(a)x³ dz = 4f(x).

Let's assume that f is continuous on the interval (0, 2). We want to show that there exists an x ∈ (0, 2) such that ∫(0 to 2) f(a)x³ dz = 4f(x).

Consider the function F(x) = ∫(0 to 2) f(a)x³ dz - 4f(x). Our goal is to prove that there exists an x ∈ (0, 2) such that F(x) = 0.

First, note that F(0) = ∫(0 to 2) f(a)(0)³ dz - 4f(0) = 0 - 4f(0) = -4f(0) and F(2) = ∫(0 to 2) f(a)(2)³ dz - 4f(2) = 8∫(0 to 2) f(a) dz - 4f(2) = 8F(1) - 4f(2).

Since f is continuous on (0, 2), the intermediate value theorem states that if f(0) < c < f(2) (or vice versa), there exists a point x ∈ (0, 2) such that f(x) = c.

We can choose c = F(0)/4 = -f(0) and apply the intermediate value theorem. Since F(0) < F(2) (or vice versa), there must exist an x ∈ (0, 2) such that F(x) = 0, which implies ∫(0 to 2) f(a)x³ dz = 4f(x). Thus, we have shown the desired result.

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Liz went to the store to get a kilo of papas, three kilo tomatoes, and a half kilo of aguacate. Yob Cuarto de Kilo de Cebolla, How Many Kilograms Were All the Vegetables You Bought Weighed

2,40

Dejar:

T = Tomate

n = cebolla

(2 kilograms of t) plus 1 kilogram of n = 8.40

(1 kilogram plus 2 kilograms) equals 7.80.

2t + n = 8,40 - -

t + 2n = 7,80 - -

De (2);

t = 7,80 - 2n

Toggata = 7.80 - 2n en

2 (7,80 - 2n) + n = 8,40

15,6 - 4n + n = 8,40

15,6 - 3n = 8,40

-3n = 8,40 - 15,6

-3n = - 7,2

n = 2,4

t = 7,80 - 2

t = 7,80 - 4,80

t = 3

As a result, the price of 1 kg of celery is $2.40.

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The value of the threshold t that gives a false rejection rate of 0.05 is found to be 5.991. The corresponding probability of false acceptance, or type II error, is computed using the power function of the test and found to be approximately 0.1485.

This is the probability of failing to reject the null hypothesis when the alternative hypothesis is true and the variance is 25.

To determine the value of t that gives a probability of false rejection of 0.05, we need to find the distribution of the test statistic under the null hypothesis H0: σ^2 = 16. The test statistic is:

T = (X1 - μ)² + (X2 - μ)² + (X3 - μ)² / (nσ²)

Under the null hypothesis, T follows a chi-squared distribution with 2 degrees of freedom (n-1). We can use this distribution to find the value of t such that the probability of false rejection is 0.05.

From the tables of the chi-squared distribution, we find that the critical value of T for a false rejection rate of 0.05 is 5.991.

Thus, we reject the null hypothesis if T > 5.991.

The probability of false acceptance, also known as type II error, is the probability of failing to reject the null hypothesis when it is actually false (i.e., when H1: σ^2 = 25 is true). This probability depends on the value of σ^2 and the threshold t.

To find the probability of false acceptance, we need to compute the power of the test, which is the probability of rejecting the null hypothesis when it is false. The power function is given by:

β(σ²) = P(T > t | σ² = 25)

The distribution of T under H1 is also a chi-squared distribution with 2 degrees of freedom, but with a different scale parameter:

T ~ χ^2(2, nσ^2/25)

Using the non-central chi-squared distribution, we can compute the power function:

β(σ²) = Q(√(n/25)(t - 3.2), 2, δ)

where Q is the complementary cumulative distribution function (CCDF) of the non-central chi-squared distribution, δ = √(n)(20-25)/5, and t is the threshold value.

For t = 5.991, we have:

\(δ = √(3)(20-25)/5 = -1.3416\\\\β(16) = Q(√(3/25)(5.991 - 3.2), 2, -1.3416) ≈ 0.1485\\β(25) = Q(√(3/25)(5.991 - 3.2), 2, 0) ≈ 0.4259\)

Therefore, the probability of false acceptance is

P(accept H1 | H1 is false) = β(16) ≈ 0.1485

Note that this is the probability of failing to reject H0 when H1 is true and σ^2 = 25. It is not the probability of accepting H1 when H0 is true and σ^2 = 16, which is 1 - the probability of false rejection.

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Answer:

3.2

Step-by-step explanation:

Answer:

pythagorean theorem !!!!!!

Step-by-step explanation:

0.8²+1.6²=3.2²

0.64+2.56=10.24

THAT means the distance is

\( \sqrt{10.24} \)

=3.2miles

Answer:

A

Step-by-step explanation:

Put '0' in for 's' and solve :

0 = -p^2 + 75 p + 1200

 Use Quadratic Formula with a = -1      b=75      c = -1200

      to find p = ~ 24  OR  52       THE LEAST NUMBER WOULD BE 24

Therefore, the volume of the paper cone to the nearest tenth is 418.7 inches cubed.

The volume of the paper cone that Gretchen made to hold a gift for a friend is given by;V= (1/3)πr²hWhere;r = radius of the paper coneh = height of the paper coneπ = 3.14

Given that;Height of the paper cone (h) = 16 inches Radius of the paper cone (r) = 5 inchesWe are to find the volume (V) of the paper cone to the nearest tenth of an inch.

To obtain the volume of the paper cone, we can substitute the values of r and h in the formula above to obtain;

\(V= (1/3)\pir^2hV\)= \((\frac{1}{3} ) \times 3.14\times5^2 \times16V = (\frac{1}{3} ) \times 3.14\times25\times16V = (\frac{1}{3}) \times 1256V=418.7\)

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Answer:

2291

Step-by-step explanation:

Given: Radius of a city's town hall is equal to 5-mile and about 180,000 people live in a city's town hall

To find: population density per square mile

Solution:

Population density refers to the number of people per unit of area.

Let r denotes radius of the town hall = 5 miles

Area of the town hall = \(\pi r^2=\pi (5)^2=25\,\pi\) square miles

Population density per square mile = Population of a city's town hall/area of the town hall = 2290.9 \(\approx 2291\)

Sophie will be 6 years old. Nichole will be 6+28 = 34

It will take 6 years for that to happen. 

You can find this by setting Nichole's age as x and Sophie's age as x + 28 since she will always be 28 years older. 

Now we are looking for a time that Sophie's age is equal to 2 less than 6 times Nichole's age. So we can set up the below equation. 

6(x) - 2 = x + 28

6x - 2 = x + 28

5x - 2 = 28

5x = 30

x = 6

Answer:

2835

Step-by-step explanation:

Answer:

11 meters

Step-by-step explanation:

Use the formula:

\(V = \pi r^{2} h\)

V = 7599, h = 20, π = 3.14

Plugin the numbers and solve for r

\(7599=3.14(20)r^{2} \\7599=62.8r^{2} \\7599/62.5=62.8r^{2} /62.8\\121=r^{2} \\\sqrt{121}=\sqrt{r^{2} } \\r=11\)

Answer is d. The testable proposed relationship between the variables in the research hypothesis is: "Then people with a high exposure to UV light will have a higher frequency of skin cancer." This portion of the hypothesis specifically establishes the expected connection between UV light exposure and the occurrence of skin cancer, allowing for investigation and data collection to either support or refute the hypothesis.

A hypothesis is a tentative explanation for a phenomenon that is based on prior knowledge and observations. It is essential to have a testable hypothesis to ensure that the research study can be conducted in a rigorous and systematic manner. A testable hypothesis allows researchers to design experiments that can collect data to support or refute the hypothesis. Without a testable hypothesis, researchers may not be able to generate meaningful results that contribute to scientific knowledge.

A critical aspect of hypothesis testing is making clear and specific predictions about the relationship between the variables. In this case, the researchers are predicting that people with a high exposure to UV light will have a higher frequency of skin cancer. This prediction is specific because it defines the level of UV light exposure that is expected to lead to a higher frequency of skin cancer. It is also measurable because the frequency of skin cancer can be quantified through data collection. By making this clear and specific prediction, the researchers can test their hypothesis and determine whether the data support or refute their hypothesis.

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Answer:

Use slope intercept form to find your y intercept and slope. Once you plot your y intercept (0,1), use your slope (3) to go up three units and to the right one unit.

Step-by-step explanation:

hope this helps *_*

Answer:

3v + 2c = $60

v + 2c = $48

Step-by-step explanation:

Let vanilla biscuits be represented by v and chocolate biscuits be represented by c.

Hope this helps! Let me know if you need help solving the simultaneous equations.

Answer:

Carlos has 4 bugs, but Seth has 3 times the amount of bugs Carlos has

         4  x  3  =  12

4-Carlos's bug

3-how many more Carlos has

12-the total amount Carlos has

Answer:

49

Step-by-step explanation:

Simplify the expression such that the variable has a positive exponent.

Substitute x = 7.

The radius of the circle will be 11 units.

A circle is a perfectly round and closed shape consisting of all points equidistant from a central point.

Let r be the radius of the circle and the location of the center of the circle be (h, k). Then the equation of the circle is given as,

(x - h)² + (y - k)² = r²

The equation of the circle is given as,

(x + 14)² + (y + 8)² = 121

(x + 14)² + (y + 8)² = 11²

From the above equation, the center is (-14, -8) and the radius is 11 units.

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The value of x based on the information given in the triangle is D. x = 1.

From the information given, it stated that the triangles are similar.

In this case, both triangles have side 4 and 5. Therefore, we are to find the last side. This will be:

4x - 1 = x + 2

Collect like terms

4x - x = 2 + 1

3x = 3

x = 3/3

x = 1

Therefore, the correct option is D.

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Answer:

x=1

Step-by-step explanation:

Answer:

12.8

Step-by-step explanation:

8÷5/8 is also the same as:

8 x 1/5 x 8

Proof:

Answer:

C

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \(\frac{0-6}{4-0}\) = \(\frac{-6}{4}\) = - \(\frac{3}{2}\) , then

y = - \(\frac{3}{2}\) x + c

the line crosses the y- axis at (0, 6 ) ⇒ c = 6

y = - \(\frac{3}{2}\) x + 6 ← equation in slope- intercept form

multiply through by 2 to clear the fraction

2y = - 3x + 12 ( add 3x to both sides )

3x + 2y = 12 ← equation in standard form

Answer:

I’m doing that exact question right now on a test so I just guessed

Step-by-step explanation:

The temperature at 6pm was of  -5.1ºF.

This problem can be solved by using system of equations.

A system of equations means when there are  two or more variables that are related, and equations are made to find the values of each variable of the problem.

It is given that at 9 am, the temperature was -12.3°F. Between 9am and the noon, the temperature rose 12°F. So, the temperature at noon was of -12.3 + 12 = -0.3ºF.

Also, between the noon and  3pm, the temperature went up 11.5°F. So, at 3 pm, the temperature was of -0.3 + 11.5 = 11.2 ºF.

Further, between 3pm and 6pm, the temperature dropped 16.3°F.So, the temperature at 6 pm was of 11.2 - 16.3 = -5.1 ºF.

Hence, the temperature at 6pm was -5.1°F

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Public opinion data, such as opinion polls, benchmark or tracking polls, entrance and exit polls, can have a significant impact on elections and policy debates.

These polls use various sampling techniques to identify respondents and collect data through mass surveys or focus groups. Sampling errors can occur, but they are usually minimized through proper methodologies. The type and format of questions asked in these polls play a crucial role in shaping the outcomes.

Public opinion data serves as a summary of the collective views and preferences of a population, providing insights into the electorate's sentiment and informing political campaigns and policy debates. Opinion polls, conducted through random or stratified sampling techniques, aim to gauge public opinion on specific issues or candidate preferences. These polls help political parties and candidates understand the concerns and priorities of voters, enabling them to tailor their messages and policies accordingly.

Benchmark or tracking polls, on the other hand, provide longitudinal data by repeatedly surveying the same sample over time. This allows for the analysis of shifting opinions and trends, which can inform campaign strategies and messaging adjustments. Entrance and exit polls, commonly conducted during elections, offer immediate feedback on voters' choices and motivations. They help in understanding the voting patterns of different demographics and identifying key issues that influenced the outcome.

To ensure the reliability of the data, it is crucial to use appropriate sampling techniques that represent the target population accurately. Random sampling, where each individual has an equal chance of being selected, or stratified sampling, which divides the population into relevant groups for representation, are commonly employed methods. However, sampling errors can still occur due to various factors, including non-response bias or sampling bias.

The type and format of questions asked in these polls can significantly impact the results. Careful consideration should be given to the wording, order, and response options provided to minimize bias and capture nuanced opinions. Open-ended questions allow respondents to express their views more freely, while closed-ended questions with pre-determined response options provide standardized data for analysis. The choice of question format should align with the objectives of the poll and the specific information sought.

Overall, public opinion data derived from different types of polls, sampling techniques, respondent identification, and question formats plays a vital role in shaping elections and policy debates. It provides valuable insights into the preferences and concerns of the population, guiding political campaigns, informing policy decisions, and facilitating a more representative and responsive democratic process.

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Answer:

1. X^2+1/2x = \(x(x+\frac{1}{2})\)

2.  X^2+2x-3 = \((x-1)(x+3)\)

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = \((x+1)(x-4)(x+5)\)

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ \(x^{2} + \frac{1}{2}x\)

\(x^{2} + \frac{1}{2}x\) = \(x(x+\frac{1}{2})\)

Hence,  X^2+1/2x = \(x(x+\frac{1}{2})\)

2. X^2+2x-3 ⇒ \(x^{2} +2x-3\)

\(x^{2} +2x-3 = x^{2} +3x-x-3\)

\(x^{2} +3x-x-3 = x(x+3) -1(x+3)\)

\(x(x+3) -1(x+3) = (x-1)(x+3)\)

Hence,  X^2+2x-3 = \((x-1)(x+3)\)

3. (2x-3)^2 ⇒\((2x-3)^{2}\)

\((2x-3)^{2} = (2x-3)(2x-3)\)

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ \(x^{3}+2x^{2} -19x -20\)

\(x^{3}+2x^{2} -19x -20 = (x+1)(x^{2} +x-20)\)

First,

\(x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)\)

∴ \((x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)\)

Hence, X^3+2x^2-19x-20 = \((x+1)(x-4)(x+5)\)

Answer:

80,000

Step-by-step explanation:

To solve this, use the Fundamental Counting Principle.

Simply calculate how many options there are for each digit in the combination, then multiply them to find the total number of combinations.

Total number of different combinations (codes):

⇒ 10 · 10 · 10 · 10 · 8 = 80,000

Last digit have

So Total ways