You and your friend see a ball rolling across the floor to the right. Your friend says
that because it is moving to the right, it must have a net force on it pushing it to
the right. Do you agree with her? Why or why not?
Your answer

Answers

Answer 1

Answer:

unforturnitly

Explanation:

step unstepable


Related Questions

An object at rest starts accelerating. If it travels 40 meters to end up going 20 m/s, what was its acceleration. PLEASE SHOW WORK AND I WILL GIVE YOU BRAINLY

Answers

The acceleration of this object is equal to 5 m/s².

How to determine the object's acceleration?

In order to determine the acceleration of this physical object during this distance, we would apply the third equation of motion:

v² = u² - 2as

Where:  

V represents the final velocity.U represents the initial velocity.S represents the distance travelled or covered.a represents the acceleration or deceleration.

By substituting the given parameters into the third equation of motion, we have the following;

v² = u² - 2as

20² = 0² - 2a(40)

80a = 400

Acceleration, a = 400/80

Acceleration, a = 5 m/s².

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A car has four tires that are each inflated to an absolute pressure of 2. 0 x 10^5 Pa. Each tire has an area of 0. 024 m^2 in contact with the ground. How much does the car weigh?


a.


1. 9 x 10^3 N


b.


2. 9 x 10^4 N


c.


1. 2 x 10^3 N



d.


1. 9 x 10^4 N

Answers

According to given information to find the weight of the car, we can use the concept of pressure and area. The car weighs approximately 4.8 x 10³ N.


1. The absolute pressure in each tire is given as 2.0 x 10⁵ Pa.
2. The area of each tire in contact with the ground is given as 0.024 m².

To calculate the weight of the car, we can use the formula:

Pressure = Force / Area

Rearranging the formula, we have:

Force = Pressure x Area

Now, let's plug in the values:

Force = (2.0 x 10⁵ Pa) x (0.024 m²)

Multiply the values:

Force = 4.8 x 10³  N

Therefore, the weight of the car is approximately 4.8 x 10³  N.

Conclusion ,The car weighs approximately 4.8 x 10³  N.

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A bicycle has wheels 26 inches in diameter. A tachometer determines that the wheels are rotating at 160 RPM (revolutions per minute). Find the speed the bicycle is traveling down to the road. (Round your answer to three decimal places.)

Answers

To find the speed at which the bicycle is traveling, we can use the formula that relates the circumference of the wheel to the distance covered in one revolution. By multiplying the circumference by the number of revolutions per minute, we can determine the speed of the bicycle.

The circumference of a circle can be calculated using the formula C = 2πr, where r is the radius of the circle. In this case, the bicycle wheels have a diameter of 26 inches, so the radius is half of that, which is 13 inches. Converting the diameter to inches, the circumference of each wheel is 2π(13) = 26π inches.

Given that the wheels are rotating at 160 RPM, we can multiply the circumference by the number of revolutions per minute to find the distance covered in one minute. This can be converted to the speed in inches per minute.

To obtain the speed in a more common unit, we can convert inches per minute to miles per hour by using appropriate conversion factors. Finally, rounding the answer to three decimal places provides the speed at which the bicycle is traveling down the road.

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If 20N force produces an acceleration of 5ms^-2 In a body then the mass of the body will be:
A.4kg
B.5kg
C.1/4kg
D.1/5kg

Answers

F = ma
m = F/a
m = 20N / 5m/s^2
m = 4kg

Where do you find the atoms with the strongest metallic properties on the periodic table?
A. the upper left
B. the lower right
C. the lower left
D. the lower right

Answers

Answer:

Key Takeaways: Metallic Character​​ These properties include metallic luster, formation of cations, high electrical and thermal conductivity, and ...

Explanation:

The atoms with the strongest metallic properties on the periodic table are found in upper left corner of periodic table. The correct option is A.

The upper left corner of the periodic table is typically where one can find the atoms with the strongest metallic properties. Alkali metals and alkaline earth metals which are renowned for their high electrical conductivity, luster and malleability are found in this region. These elements are easy to lose and easily form positive ions because they have few valence electrons in their outermost energy levels.

Due to growing atomic size and declining electronegativity, metallic properties tend to become more noticeable as you move down and to the left in this region. On the other hand nonmetals and metalloids with stronger nonmetallic properties such as high electronegativity and poor electrical conductivity make up the lower right region.

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A ray of red light in air is incident at an angle of 30. on a

boundary with olive oil. What is the angle of refraction, to the

nearest degree, for this light ray in the olive oil?

a 60

§ 20

C 30°

x

do

e 47

Answers

Answer:

20 degrees.

Explanation:

From Snell’s law of refraction:

sinθ1•n1 = sinθ2•n2

where θ1 is the incidence angle, θ2 is the refraction angle, n1 is the refraction index of light in medium1, and n2 is the refraction index for virgin olive oil. The incidence angle of the red light is θ1 = 30 degrees.

The red light is in air as medium1, so n1 (air) = 1.00029

So, to find θ2, the refracted angle:

sinθ1•1.00029 = sinθ2•1.464

sin(30)•1.00029 / 1.464 = sinθ2

0.5•1.00029 / 1.464 = sinθ2

sinθ2 = 0.3416291

θ2 = arcsin(0.3416291)

θ2 = 19.976 degrees

To the nearest degree,

θ2 = 20 degrees.

an old-fashioned lp record rotates at 33 1/3 rpm. what is its frequency in rev/s

Answers

The frequency of the LP record is approximately 33.33 rev/s.

Frequency refers to the number of occurrences of a repeating event per unit of time. It is a measure of how often a particular event or phenomenon repeats within a given time frame.

In physics, the standard unit of frequency is the hertz (Hz), which represents one cycle per second.

To convert the speed of an LP record from revolutions per minute (rpm) to revolutions per second (rev/s), you can use the following conversion:

1 rev/s = 60 rpm

To find the frequency of an LP record rotating at 33 1/3 rpm, you can divide that value by 60:

( 33¹/₃ / 60 ) = 33.33 rev/s

The frequency of the LP record is approximately 33.33 rev/s.

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According to the graph of displacement vs. time, what is the object's velocity at a displacement of 0.2 meters?

Answers

According to the graph of displacement vs. time, the object's velocity is 0.02 m/s

What is displacement?

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Velocity is the time rate of change of displacement with time.

Given is the displacement 0.2 m and time taken is 10s. So, the velocity is

v = 0.2/10

v = 0.02 m/s

Thus, the object's velocity is 0.02 m/s

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two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. one of the blocks, with a mass of 3.0 kg accelerates downward at 34g.

Answers

the solution provided above assumes idealized conditions such as a massless, frictionless pulley, and a massless rope. In reality, there would be some slight deviations due to factors like friction and the finite mass of the pulley and rope, but this model does not account for those details.

To solve this problem, let's break it down step by step:

1. Determine the acceleration of the system:

The block with a mass of 3.0 kg accelerates downward at 34g. We need to convert this acceleration from g (acceleration due to gravity) to m/s².

Acceleration due to gravity (g) is approximately 9.8 m/s², so 34g would be equal to 34 * 9.8 m/s².

34g = 34 * 9.8 m/s² = 333.2 m/s²

Therefore, the acceleration of the system is 333.2 m/s².

2. Use Newton's second law to find the net force:

The net force acting on the system is equal to the mass of the system (m) multiplied by the acceleration (a).

Since the mass of the system consists of the 3.0 kg block and the other block (let's call it m₂), the total mass of the system is 3.0 kg + m₂ kg.

The net force on the system is given by:

Net force = (3.0 kg + m₂ kg) * (333.2 m/s²)

3. Find the tension in the rope:

The tension in the rope is the force transmitted through it. Since the rope is massless, the tension in the rope is the same on both sides of the pulley.

Let's assume the tension in the rope is T. The tension force on the side with the 3.0 kg block is T, and the tension force on the other side is also T.

4. Write equations of motion for the blocks:

We can now write the equations of motion for each block separately.

For the 3.0 kg block:

The net force acting on the 3.0 kg block is the tension force (T) minus the force due to the mass of the block (m₁ * g).

Net force = T - (3.0 kg * 9.8 m/s²)

Since the block accelerates downward, the equation of motion becomes:

T - 29.4 = (3.0 kg) * (333.2 m/s²)

For the m₂ kg block:

The net force acting on the m₂ kg block is the force due to its mass (m₂ * g) minus the tension force (T).

Net force = (m₂ kg * 9.8 m/s²) - T

Since the block accelerates upward, the equation of motion becomes:

(m₂ kg * 9.8 m/s²) - T = (m₂ kg) * (333.2 m/s²)

5. Solve the equations of motion simultaneously:

Now, you have two equations with two unknowns (T and m₂). You can solve these equations simultaneously to find the values of T and m₂. Once you know these values, you can calculate the tension in the rope and the mass of the second block.

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10. WIMPS and MACHOS cannot be seen or felt.
True
False

Answers

Answer:

false I believe is the right answer

Answer:

True

Explanation:

a jet can travel at 350 m/s.
calculate how far it will travel in :
a) 30 secs
b) 5mins
c) half an hour​

Answers

Explanation:

distance = speed x time

a- d= 350 m/s x 30s

   d= 10500m

b- 5 mins = 300 sec

    d= 350 m/s x 300s

    d= 105000 m

c-  30 mins = 1800 sec

    d= 350 m/s x 1800 s

   d=  630000 m

light of wavelength 447 nm from a he-ne laser passes through a circular aperture and is observed on a screen 2.0 m behind the aperture. the diameter 'of the central bright area is 26.6 cm. what is the diameter of the aperture?

Answers

The light of wavelength 447 nm from a He-Ne laser passes through the circular aperture and  observed on the screen 2.0 m behind the aperture. The diameter of the aperture is  8.2 × 10⁻⁶ m.

The expression is as follows :

Diameter, D = 2.44 × d × λ / D'

Where

λ = wavelength = 447 × 10⁻⁹  m

d = 2 m

D' = 26.6 cm = 0.266 m

D = 2.44 × d × λ / D'

D = ( 2.44 × 447 × 10⁻⁹  × 2 ) / 0.266

D = 8.2 × 10⁻⁶ m

Thus , the diameter of the aperture is  8.2 × 10⁻⁶ m.

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A force of 2 lb stretches a spring 1 ft. An 8-lb weight is attached to the end of the spring and released 4in. above the equilibrium position from rest. If the medium offers a resistance to the motion of the weight numerically equal to 3/2 times the instantaneous velocity, find the equation of motion. Determine if the system is underdamped, overdamped, or critically damped.

Answers

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t)

And the system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

The force required to stretch a spring is directly proportional to the amount the spring is stretched. This relationship is known as Hooke’s Law. It can be expressed mathematically as:

F = -kx

Where F is the force applied to the spring, x is the displacement of the spring from its equilibrium position, and k is the spring constant.

For a mass-spring system under the influence of a damping force, the differential equation governing the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0

where m is the mass of the object attached to the spring, c is the damping coefficient, and k is the spring constant.

The given force of 2 lb stretches the spring by 1 ft, so the spring constant is given by k = F/x = 2/1 = 2 lb/ft.

The 8-lb weight is released 4 in. above the equilibrium position, which is 0.25 ft. The initial displacement is therefore x(0) = 0.25 ft, and the initial velocity is v(0) = 0. The damping force is given by f_d = -3/2v. Using the values given, the differential equation for the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0 (1)

The values of m, k, and c are given by

m = 8/g = 8/32.2 = 0.248 kg

k = 2/lb/ft * 0.4536 kg/lb * 0.3048 m/ft = 0.294 kg/sm = 0.248 kgc = 3/2

The equation of motion is then:

d2x/dt2 + 12.05dx/dt + 1.186x = 0 (2)

where we have substituted the values of m, c, and k into equation (1).

The characteristic equation is:

r2 + 12.05r + 1.186 = 0 (3)

Solving for the roots of the characteristic equation, we find:

r = (-12.05 ± √(12.052 - 4(1.186)))/2= -6.025 ± 2.181i

The roots are complex conjugates, so the solution to the differential equation can be written as:

x(t) = e⁽⁻⁶·⁰²⁵t⁾(C₁ cos(2.181t) + C₂ sin(2.181t)) (4)

The initial displacement and velocity are given by x(0) = 0.25 and v(0) = 0.

Substituting these values into equation (4) and taking the derivative, we get:

x(0) = C₁ = 0.25dx/dt|t=0 = -6.025

C₂ = 0

Solving for C₁ and C₂, we get:

C₁ = 0.25C2 = 0

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t) (5)

The system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

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While driving on a highway, your HMMWV starts to pull to one side. You stop and check your tires – one tire is going flat. There is no spare, but the affected tire has a runflat device installed, and you are only 5 miles from the motor pool. What is your maximum allowable speed when driving with one flat tire?

Answers

Answer:

30 miles people hour (mph)

Explanation:

The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.

In order to have kinetic energy an object must be
1.moving
2. At rest
3.rigid
4.elevated

Answers

To have kinetic energy a object must be A moving

Examine table b then read the statement and choose the best responses. as the resistance increased under 25 v, the current . compared to calculated currents, experimental currents proved to be . currents varied proportionally according to resistance: 10 ω of resistance produced a current of a, while 100 ω of resistance produced a current of a.

Answers

The best responses to the statements are:

a. the current decreased.

b. The Same.

c. 2.5.

d. 0.25.

What is resistance?

In an electrical circuit, resistance is a measure of the resistance to current flow.

The Greek letter omega is used to represent resistance in ohms.

The resistance is inversely proportional to the current.

Thus, the correct options are a. the current decreased.

b. The Same.

c. 2.5.

d. 0.25.

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Answer:

Ye ye answer be below:

Explanation:

~Hope this helps! :)

Examine table b then read the statement and choose the best responses. as the resistance increased under

an object is placed at dist 25cm in front of concave mirror and image has magnification of -2 .find focal length

Answers

Answer:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

=

v

1

+

u

1

−20

1

=

v

1

25

1

v

1

=−

20

1

+

25

1

v=100cm

The image will be real, inverted magnified

Explanation:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

=

v

1

+

u

1

−20

1

=

v

1

25

1

v

1

=−

20

1

+

25

1

v=100cm

The image will be real, inverted magnified

A ball is released from rest from an elevated position and free-falls towards the ground. If it strikes the ground after 4.0 seconds, then what was the height from which the ball was released? Assume negligible air resistance.

Answers

Answer:

80m

Explanation:

because the the initial velocity was zero

H =1/2gt^2

The height from which the ball was released is approximately 78.48 meters.

What is Kinematic equation?

The kinematic equation for the vertical motion of an object under free fall to solve this problem. The equation is:

\(y = 1/2 * g * t^2\)

where y is the vertical displacement, g is the acceleration due to gravity, and t is the time elapsed. At the initial position, the ball is at rest, so its initial velocity is zero.

At the instant the ball strikes the ground, the time elapsed is 4.0 seconds. Therefore, we can substitute the given values into the equation to find the height from which the ball was released:

\(y = 1/2 * g * t^2\\y = 1/2 * 9.81 m/s^2 * (4.0 s)^2\\y = 78.48 meters\)

Therefore, the height from which the ball was released is approximately 78.48 meters.

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a) the electron in a hydrogen atom orbits the proton at a radius of 0.053 nm. what is the electric field due to the proton at the position of the electron?

Answers

The electric field due to the proton at the position of the electron in a hydrogen atom is 2.18 x 10^11 N/C

To determine the electric field due to the proton at the position of the electron in a hydrogen atom, we can use the equation for electric field strength:
E = kq/r^2Where E is the electric field strength, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q is the charge of the proton (+1.6 x 10^-19 C), and r is the distance between the proton and the electron (0.053 nm or 5.3 x 10^-11 m).
Plugging in these values, we get:
E = (8.99 x 10^9 Nm^2/C^2) x (+1.6 x 10^-19 C) / (5.3 x 10^-11 m)^2
Solving for E, we get:
E = 2.18 x 10^11 N/C
Therefore, the electric field due to the proton at the position of the electron in a hydrogen atom is 2.18 x 10^11 N/C.

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The electric field due to the proton at the position of the electron in a hydrogen atom is approximately 5.11 x 10^11 N/C.

To calculate the electric field due to the proton at the position of the electron in a hydrogen atom,

Step 1: Convert the radius from nanometers to meters:
0.053 nm = 0.053 x 10^(-9) m

Step 2: Use Coulomb's Law formula to find the electric field:
E = k * q / r^2
Where E is the electric field, k is Coulomb's constant (8.99 x 10^9 N m²/C²), q is the charge of the proton (1.6 x 10^(-19) C), and r is the radius (0.053 x 10^(-9) m).

Step 3: Plug in the values and solve for E:
E = (8.99 x 10^9 N m²/C²) * (1.6 x 10^(-19) C) / (0.053 x 10^(-9) m)^2
E ≈ 5.11 x 10^11 N/C

The electric field due to the proton at the position of the electron in a hydrogen atom is approximately 5.11 x 10^11 N/C.

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the forces which hold molecules in a water drop are called choose surface tension adhesive or cohesive forces yessfgb​

Answers

Answer:

Cohesion

Explanation:

Cohesion is the force responsible for holding the molecules of water together.

Adhesion is type of force between two different molecules or compounds.

Surface tension allows water molecules or molecules to resist any external force "due" to cohesive forces.

\(\rule[225]{225}{2}\)

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Jupiter’s moon, Ganymede takes 7.15 Earth days to orbit Jupiter. Ganymede is measured to be 7.1 X 10-3 AU from Jupiter’s center. A second moon of Jupiter, Callisto, takes 16.69 Earth days to orbit Jupiter. How far away is Callisto from the center of Jupiter?

Answers

Answer:

0.0124 AU

Explanation:

Ganymede takes 7.15 Earth days to orbit Jupiter. Ganymede is measured to be 7.1 X 10⁻³ AU from Jupiter’s center.

We need to find how far away is Callisto from the center of Jupiter if a second moon of Jupiter, Callisto, takes 16.69 Earth days to orbit Jupiter. Let it is r₂. Using third law of Kepler.

\(T^2\propto r^3\)

i.e.

\((\dfrac{T_1}{T_2})^2=(\dfrac{r_1}{r_2})^3\\\\\dfrac{r_1}{r_2}=(\dfrac{T_1}{T_2})^{2/3}\\\\r_2=\dfrac{r_1}{(\dfrac{T_1}{T_2})^{2/3}}\\\\r_2=\dfrac{7.1\times 10^{-3}}{(\dfrac{7.15}{16.69})^{2/3}}\\\\r_2=0.0124\ \text{AU}\)

So, Callisto is 0.0124 AU from the center of the Jupiter.

WHOEVER GET IT RIGHT GETS 50 POINTS
Imagine you are part of a team planning to send an astronaut on a solar system “road trip.” To plan for this trip, the astronaut’s weight at each destination must be known. On Earth, the astronaut weighs 50 kilograms which is 490 Newtons. Using the data from the table, calculate the missing weight values. (The values for Earth are already known.) Then plot the gravity of each location—the moon, Mars, Earth, and Venus—versus the weight of the astronaut at each location.

Weight in
Newtons
Mass in
Kilograms
Gravity in
m/s2


Moon

50
1.6
Mars

50
3.7
Earth
490
50
9.8
Venus

50
8.8

Click on the grid to add a point. Click and drag a point to move it.
$$
xy
$$

Answers

Answer:

ANSWER BELOW I

                             I

                            V

Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in

m/s2

. For example, for Earth, 445 N = 45.4 × 9.8

m/s2

:Notice that the x-axis values will be gravity in

m/s2

, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).

WHOEVER GET IT RIGHT GETS 50 POINTSImagine you are part of a team planning to send an astronaut on a

Derived quantities depend on...........physical quantity​

Answers

Derived quantities depend on.( fundamental)..........physical quantity

Are you from Nepal?

Answer:

Derived quantities depend on two or more physical quantity.

When an elevator suspended by a cable is descending at a constant velocity?

Answers

The change in velocity for an elevator hanging by a cable that is falling at a constant speed is zero. As a result, there is no net acceleration. The tensile force T exerted by the cable pulling the elevator upward.

when moving down an elevator shaft at a constant speed?

Newton's second rule states that the net force is acting on all of us must be zero because we are descending in the elevator at a constant speed, or Fret =0 F n e t = 0. Our weight (working downward) plus the natural force from our touch with the elevator floor are the only forces at play during the process (acting upward).

If the elevator went up and down at a steady speed, would the tension change?

If the force applied is equal to the gravitational force provided it already has the upward velocity, it will move up with uniform velocity. The tension force gradually builds as the lift slowly rises before returning to its initial amount.

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The human jaw muscle is the strongest in the body for its size. Does this mean that the jaw muscle is the also the overall strongest muscle as well? Explain why or why not. (Our unit is on work and power)

Answers

The sartorius muscle is the solution. A superficial muscle that runs the full length of the leg, the sartorius is involved in the flexion of the knee and hip.

What is Sartorius muscle?

The heart's wall is made up of cardiac muscle, which also causes the heart to contract vigorously. Intestinal, uterine, blood vessel, and internal ocular muscles are all made of smooth muscles.

The epidermis and some skeletal muscles are linked to the bones (muscles in our face). The skeletal muscles' contraction aids in the movement of the limbs and other bodily parts.

Although some estimates go as high as 840, the majority of sources claim that there are over 650 identified skeletal muscles in the human body.

Therefore, The sartorius muscle is the solution. A superficial muscle that runs the full length of the leg, the sartorius is involved in the flexion of the knee and hip.

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20 points and brainlist!!!
Write about a situation where it might be more useful to describe motion using velocity instead of speed.

Answers

Answer:

If you are going someplace, you might want to tell which way you were going and how fast for traffic.

Explanation:

a stretched string has a wave speed v. if the tension on the string is halved and the string is replaced by another with twice the linear density, by what factor will the speed of a wave on the string change?

Answers

If the strain on the rope is half and a new string with twice the density is used, be using the velocities equation to calculate the speed: v=FT=56.40N3.0910 4kg/m=427.23m/s.

Will the factor 2=1055.00N affect the wave's speed on the string?

A stretched string's wave velocity is v. The linear density, or the square root of tension divided by mass per length determines the speed of a waveform on a string. The wave speed of a stretched string is v.

FT=v2=5.78103kg/m(427.23m/s).

What changes to the velocity of the wave on the thread if the strain is doubled?

Considering that the square of the wave's speed on a taut string The frequency of the wave would rise by 2, or the square root of the strain divided by linear density.

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If the particles that make up an object begin to move quickly, their average kinetic energy _____ and the object's temperature _____. Group of answer choices

Answers

Explanation:

If the particles that make up an object begin to move quickly, their average kinetic energy increases the object's temperature rises. Group of answer choices

Question 6
A sample of a fluid has a mass of 150 g and volume of 30 ml. What is the density of this fluid?

Answers

Answer:

The answer is 5 g/mL

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 150 g

volume = 30 mL

We have

\(density = \frac{150}{30} \\ \)

We have the final answer as

5 g/mL

Hope this helps you

If a wave has a wavelength of 10 m and a speed of 2.5×108 m/s (this is 250000000 m/s) what is the frequency of the wave?

Answers

Answer:

The wavelength result is 3 m. Most common velocities: Light in vacuum (air) = 300,000 km/s. Light in water = 225,000 km/s. Sound in air = 340 m/s. Sound

Explanation:

the answer is 3m

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