You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.

Answers

Answer 1

Complete Question

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.

(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.

   

magnitude            N

direction          

   (b) What maximum force do you need to apply before the refrigerator starts to move?

Answer:

a

   The magnitude  is \(F_f = 339.57 \ N\)

    The direction is  [negative x - axis ]

b

   The maximum force to be applied for the refrigerator to start moving is  

      \(F_{max} = 339.57 \ N\)

Explanation:

From the question we are told that

   The horizontal force applied is \(F_a = 280 \ N\) the direction is  +ve  x-axis

   The mass of the refrigerator is  \(m = 63 \ kg\)

    The coefficient of static friction is  \(\mu_s = 0.55\)

Generally the frictional force exerted on the refrigerator is mathematically represented as

            \(F_f = \mu * m * g\)

=>         \(F_f = 0.55 * 63 * 9.8\)

=>         \(F_f = 339.57 \ N\)

From the value obtained we see that the static force  exerted by the floor on the refrigerator  is  greater than the force (280 N ) exerted by the person and the direction is  -ve x-axis

Generally the maximum force that is to be applied by the person is mathematically  equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis  i.e

         \(F_{max} = F_f = 339.57 \ N\)


Related Questions

The vertical aerial photograph shown is exposed with a 152 mm focal length camera at a flying height of 3000 m (AMSL). If the terrain elevation of A is 50 m (AMSL) and local coordinates of the photo principle point is {x
P

=78898;y
P

=99752}m, determine: a. The photo scale at point A. b. The local coordinates of A.

Answers

The photo scale at point A is approximately 1:19,720.

The local coordinates of point A are approximately

{xA = 78898;

yA = 99751.85} meters.

To determine the photo scale at point A and the local coordinates of point A, we can use the principles of photogrammetry.

a. The photo scale at point A can be calculated using the following formula:

Photo Scale = (Focal Length / Flying Height)

Given:

Focal Length = 152 mm

= 0.152 m

Flying Height = 3000 m

Photo Scale at point A = (0.152 m / 3000 m)

= 0.00005067

Therefore, the photo scale at point A is approximately 1:19,720.

b. To determine the local coordinates of point A, we need to use the principle of collinearity. This principle states that corresponding points in the object space (terrain) and the image space (photograph) are collinear with the perspective center (principal point of the photograph).

Using the local coordinates of the photo principal point (xP = 78898;

yP = 99752) and the photo scale, we can calculate the local coordinates of point A as follows:

Local x-coordinate of point A = xP

Local y-coordinate of point A = yP - (Photo Scale * (Flying Height - Terrain Elevation of A))

Given:

Terrain Elevation of A = 50 m

Local x-coordinate of point A = 78898

Local y-coordinate of point A = 99752 - (0.00005067 * (3000 - 50))

Calculating the values:

Local x-coordinate of point A = 78898

Local y-coordinate of point A = 99752 - 0.1500517

Local x-coordinate of point A = 78898

Local y-coordinate of point A = 99751.8499483

Therefore, the local coordinates of point A are approximately

{xA = 78898;

yA = 99751.85} meters.

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A 10- kilogram box is at static equilibrium and the downward pull of gravity acting on the box is 98 Newton's what is the minimum force that would be required to just pick up the box ?

Answers

Answer:

Explanation:

Now

Look at it this way. This box is in equilibrium... Meaning forces around balanced out.

Now...

The Earth's pull on it is 98N

What Minimum external forces is needed to pick this up....

Now... The Minimum Force is 98N

Why?

Since This Box is under the influence of gravity...

Gravity is acting as a resistance

If you apply a force less than 98N... Let's say 50N on this box... It won't budge because your applied force is less than the resisting force on it(98N).

So We need a force ≥98. So the least force is 98N. Nothing below this will move the Box

Answer 98N.

Answer:

See image

Explanation:

Plato

A 10- kilogram box is at static equilibrium and the downward pull of gravity acting on the box is 98

A 1,500. 0 kg car hits a brick wall with a force of 60. 0 N in 1. 75 seconds. What is the change in the momentum of the car?

Answers

When a 1,500 kg car hits a brick wall with a force of 60.0 N in 1.75 s, the change in the momentum of the car is 105 kg.m/s.

A 1,500 kg car (m) hits a brick wall with a force of 60.0 N (F) in 1.75 s (t). We want to determine the change in the momentum of the car.

What is the impulse-momentum theorem?

The impulse-momentum theorem states that the change in momentum (Δp) of an object equals the impulse (I) applied to it.

This is represented through the following formula.

I = Δp

F × t = Δp

Δp = F × t = 60.0 N × 1.75 s = 105 kg.m/s

When a 1,500 kg car hits a brick wall with a force of 60.0 N in 1.75 s, the change in the momentum of the car is 105 kg.m/s.

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Most planets in our solar system, and many dwarf planets as
well, have moons. What makes a moon different from a planet in
terms of its definition? Which moon of our solar system do YOU
think is the m

Answers

A moon is defined as a natural satellite orbiting around a planet. It is a celestial body that orbits around a planet or a dwarf planet in our solar system. What makes a moon different from a planet is that moons do not orbit around the sun. They orbit around a planet or a dwarf planet instead.

In addition, moons are smaller than planets and do not have their own atmosphere. Moons can be rocky or icy and can be made up of different types of materials such as dust, rock, ice, and gas. They are formed through various processes such as accretion, collision, capture, and fission. Out of all the moons in our solar system, I think that the moon of our Earth is the most interesting.

The moon of the Earth is the only natural satellite of our planet. It is about one-quarter the size of the Earth and is about 238,855 miles away from the Earth. It has a rocky and dusty surface, with many craters, mountains, valleys, and seas. The moon has played an important role in the history of human civilization, serving as a source of light, a calendar, and an object of scientific study. It has been explored by humans and robots, revealing many secrets of its geology, composition, and history.

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a(n) potential is the brief wave of positive electrical charge that sweeps down the axon.

Answers

The term that you are referring to is an action potential. An action potential is a rapid and brief wave of positive electrical charge that sweeps down the axon of a neuron.

It is initiated by a depolarization of the cell membrane and results in the transmission of an electrical signal from one neuron to another.

Action potentials are a crucial part of the nervous system and are responsible for a wide range of behaviors and functions, including movement, sensation, and cognition.

The process of generating an action potential involves a series of changes in the electrical potential across the neuron's cell membrane. Normally, the neuron's membrane has a resting potential, which is a stable negative charge inside the cell compared to the outside.

This resting potential is maintained by the balance of ions, such as sodium (Na+), potassium (K+), and negatively charged proteins, across the membrane.

When a neuron receives a stimulus, it can cause a brief depolarization of the cell membrane. Depolarization is a change in the electrical potential, resulting in a temporary reversal of the charge across the membrane.

This depolarization triggers the opening of voltage-gated ion channels, primarily sodium channels, in the neuron's membrane.

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IF you are in Space and push a bowling what happens to you and the bowling ball?

Answers

Answer:

The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.

Explanation:

I hope this helps! :D

When a rubber cylinder is rubbed with a piece of wool, the cylinder accumulates a negative charge. what can be said about the charge on the wool? why?

Answers

When a rubber cylinder is rubbed with a piece of wool, the cylinder accumulates a negative charge. The charge on the wool would be positive. This occurs as both the rubber and wool exhibit the triboelectric effect.

When two materials rub against each other, electrons are transferred from one to another, causing one material to become positively charged while the other becomes negatively charged. However, the direction of the charge transfer depends on the materials involved. Certain materials, such as wool and rubber, have a greater ability to hold on to electrons, which means that they will accumulate more electrons and become negatively charged.

As a result, the rubber cylinder acquires a negative charge when it is rubbed with wool, while the wool acquires a positive charge. This is because wool has a higher tendency to lose electrons, causing it to become positively charged.The transfer of charge can be explained by Coulomb's law, which states that like charges repel each other, while opposite charges attract each other. The charges on the wool and rubber cylinder will cause them to attract each other, since they have opposite charges.

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A ball is dropped from the top of a building. It initially
moves at 40 m/s. After 0.5 seconds, it moves at 3.8
m/s.
What force is responsible for the slowing of the ball?
air resistance
gravity
normal
tension

Answers

Answer:

Explanation:

I'm assuming you missed the decimal point in the initial velocity and that it should be 4.0 m/s. If after a half of a second it is moving a tiny bit slower, it would be because of air resistance. You can only neglect air resistance if the problems you are doing tell you neglect it.

Answer:

Air resistance

Explanation:

I got it correct on the quiz :)

Will the blue cube sink or float in the liquids?
Will the pink cube sink or float in the liquids?

Will the blue cube sink or float in the liquids? Will the pink cube sink or float in the liquids?

Answers

Answer: the cube will proble sink

but the pink will float

1. A skateboarder is skating over a circular bump. He is at the top of the bump and is
moving rightward. Is the normal force exerted on the skateboarder by the bump greater
than, less than, or equal to the weight of the skateboarder? Explain your reasoning.

Answers

Answer:

The normal force exerted on the skateboarder by the bump is less than the weight of the skateboarder

Explanation:

The given parameters are;

The location of the skateboarder = The top of the circular bump

The direction of motion of the skateboarder = Rightward

Therefore, given than the skateboarder has both horizontal angular motion (moving rightward) and vertical angular motion (over the bump), The effect of the weight of the skateboarder on the ground is reduced by the centripetal forces acting on the skateboarder and the normal force exerted on the skateboarder by the bump is equal to the reduced weight and is therefore less than the actual weight of the skateboarder.

The normal force exerted on the skateboarder is less than the weight due to the effect of centripetal force.

Given data:

The position of skateboarder is at top of the circular bump.

And direction of motion of Skateboarder is towards rightward.

Since, the skateboarder is undergoing the motion over the circular path, then it will have both horizontal angular motion (moving rightward) and vertical angular motion (over the bump).

The effect of the weight of the skateboarder on the ground is reduced by the centripetal forces acting on the skateboarder and the normal force exerted on the skateboarder by the bump is equal to the reduced weight and is therefore less than the actual weight of the skateboarder.

Thus, we can conclude that the normal force exerted on the skateboarder is less than the weight due to the effect of centripetal force.

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Cytoplasm:

A. Is the spherical organelle in the center of the cell

B. Is a sac-like structure

C. Surrounds organelles

D. Is the jelly-like fluid within a cell

Answers

The answer would be c

Answer: D. Is the jelly like fluid within a cell

watch the cell rap

NEED THIS NOW PLEASE!!! I'LL MARK BRAINIEST!!!

Which of these graphs would best model and predict the lifetime of the Sun on the main sequence?

NEED THIS NOW PLEASE!!! I'LL MARK BRAINIEST!!!Which of these graphs would best model and predict the
NEED THIS NOW PLEASE!!! I'LL MARK BRAINIEST!!!Which of these graphs would best model and predict the
NEED THIS NOW PLEASE!!! I'LL MARK BRAINIEST!!!Which of these graphs would best model and predict the
NEED THIS NOW PLEASE!!! I'LL MARK BRAINIEST!!!Which of these graphs would best model and predict the

Answers

As stars get bigger and brighter, the closer they are to their end of life.

Because they have already used all the elements they can in nuclear fusion. Iron cannot be fused, its too heavy.

The most accurate graph here would be the third one.

Descartes and Snell worked around the time of Kepler and Galileo. Is this true or false?

Answers

René Descartes (1596-1650) was a creative mathematician of the first order, an important scientific thinker, and an original metaphysician.

Willebrørd Snell (1591-1626) was a Dutch astronomer, mathematician, and scientist who is famously known for the law of refraction.

Johannes Kepler (1571-1630) was a German astronomer, mathematician, astrologer, natural philosopher, and writer of music.

Galileo Galilei (1564-1642) was an astronomer, physicist, and mathematician who made fundamental contributions to the sciences of motion and astronomy.

Notice that the period of Descartes and Snell overlap with the period of Kepler and Galileo.

Therefore, we can conclude that the given statement is true.

If a net force of 24 Newtons is applied on an object of mass 6
kilograms, what will be the acceleration of the object?
a 2 m/s2
b. 6 m/s2
C 10 m/s2
d 4 m/s2

Answers

Answer:

4 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question

f = 24 N

m = 6 kg

We have

\(a = \frac{24}{6} = 4 \\ \)

We have the final answer as

4 m/s²

Hope this helps you

a certain lake, filled with fresh water, is 40 m deep and located at sea level. what is the absolute pressure (in kpa) at the bottom of the lake?

Answers

A certain lake, filled with fresh water, is 40 m deep and located at sea level. The absolute pressure (in kpa) at the bottom of the lake will be 492.1 kPa

P1 = rho * g * h

rho = density of water

g = acceleration due to gravity

h = depth

P1 = rho * g * h

   = 997 * 9.8 * 40 = 390824  N / \(m^{2}\) = 390.8 kPa

P(absolute pressure) =  Po + P1

  =   101.3 + 390.8  = 492.1 kPa

The absolute pressure (in kPa) at the bottom of the lake will be 492.1 kPa

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Supposet that f(x,y)= The temperature of a sheet of metal (in°C)at the position (z,y) (in cm) Suppose that VJ (2,3)=(5,12) Suppose that an ant is crawling on the pan. At t=5s, the position of the ant is (2,3) cm, and the velocity of the ant is (3, 4) cm/s. For each of the following questions, show how you get your answer.
(a) At t= 5s, at what (instantaneous) rate is the ant warming up (assume the ant always has the same temperature as the metal it is standing on). Your a answer chould be in
(b) At t = 58, at what (instantaneous) rate is the ant warming up per cm it travels? Your answer should be in C
(c) If the position of the ant is (2,3) cm, in which direction should the ant move to maximize the instantaneous rate it warms up? Give your answer as a unit vector.
(d) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c), at what instantaneous rate is it warming up per cm it travles? Give your answer in cm C
(e) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c) with a speed of 4 at what instantaneous rate is it warming up with respect to time? Give your answer in

Answers

Explanation:

the answers are calculated in above pictures

Supposet that f(x,y)= The temperature of a sheet of metal (inC)at the position (z,y) (in cm) Suppose
Supposet that f(x,y)= The temperature of a sheet of metal (inC)at the position (z,y) (in cm) Suppose
Supposet that f(x,y)= The temperature of a sheet of metal (inC)at the position (z,y) (in cm) Suppose

Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan

Answers

SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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Your supervisors at A&L Engineering have tasked you with evaluating the durability of three common materials used in the design of cell phone cases

Answers

A&L Engineering, as an engineer, you've been tasked with evaluating the durability of three common materials used in the design of cell phone cases.

These materials include:Carbon FiberPolycarbonateTPUExplanation:Carbon fiber is a lightweight, durable, and corrosion-resistant composite material. It is often used in the aerospace, automotive, and sporting goods industries.Polycarbonate is a thermoplastic polymer that is strong, shatter-resistant, and lightweight. It is often used in the production of CDs, DVDs, and eyeglass lenses.

TPU (thermoplastic polyurethane) is a flexible, soft material that is abrasion-resistant and provides excellent impact protection. It is often used in the production of phone cases, as well as sporting equipment and medical devices.To evaluate the durability of these materials, you can conduct a series of tests to measure their resistance to impacts, scratches, and bending.

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the area of a rectangle is 105 sq in and the length of one side is 7 in. what is the length of the perimeter?
A. 22 inches
B. 27 inches
C. 35 inches
D. 44 inches
E. 49 inches

Answers

Answer:

\( \huge{ \boxed{44 \: \: \text{inches}}}\)

Explanation:

To find the perimeter of the rectangle, we must first find the width of the rectangle given it's length and area then use it to find the perimeter of the rectangle.

Let the width be represented by w

Area of a rectangle = length × width

From the question.

Area = 105 sq. in

length = 7 in

\(105 = 7 \times w \\ 105 = 7w \: \: \: \: \: \: \\ \\ \frac{105}{7} = \frac{7w}{7} \\ w = 15\)

width = 15 in

Perimeter of a rectangle(p) = 2l + 2w

l is the length of the rectangle

w is the width of the rectangle

\(p = 2(7) + 2(15) \\ p = 14 + 30 \\ \\ p = 44\)

We have the final answer as

44 inches

A car accelerates from 3 m/s to 12 m/s in 20 s.

What is the acceleration of the car?

Answers

Answer:

0.45  [m/s²].

Explanation:

1) formula of the required acceleration is (V-final velocity, V₀-initial velocity, t-elapsed time):

\(a=\frac{V-V_0}{t};\)

2) according to the formula above:

a=(12-3)/20=0.45 [m/s²].

This property of waves is the only property where the relationship between energy and this property are indirect or inverse

Answers

Answer: I don't understand

Explanation:

study and pay attention

Name two ways to decrease the electric force between two charged objects.

Answers

Answer:

Inverse relationships are common in nature. In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Explanation:

Two ways to decrease the electric force between two charged objects:

by lessen charge of the test objects.by increasing distance between test change and source charge.What is coulomb force?

As a result of their electric charge, particles or objects are attracted to or repelled by the Coulomb force, also known as electrostatic force or Coulomb interaction. Charles-Augustin de Coulomb, a French scientist who published the findings of an experimental inquiry into the proper quantitative description of this force in 1785, gave the electric force its name. The electric force is one of the fundamental physical forces.

Positive or negative electric charges that are similar to one another repel one another in a straight line between their centers. Positive and negative charges that are opposite each other are drawn together along a straight line connecting their centers.

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Which is the equivalent of 2000 mm?
a. 200 m b. 2 m c. 0.002 m d. 0.02 m

Answers

2000 mm is equivalent to 2 m. This can be derived from the fact that 1 m = 1000 mm. Thus, 2000 mm would be equal to 2 m since it is twice the length of 1000 mm. This conversion is important in various fields such as construction, engineering, and science where precision is necessary.

It is crucial to be able to convert between different units of measurement in order to make accurate calculations and measurements.The millimeter is a unit of length that is often used to measure small distances such as the thickness of a sheet of paper or the size of a small component. It is part of the metric system, which is a system of units used across the world that is based on multiples of 10.

This system makes it easy to convert between different units since it is based on a consistent set of rules.For example, to convert 2000 mm to meters, we can simply divide by 1000 since there are 1000 millimeters in a meter. This gives us 2 meters, which is the equivalent length in meters of 2000 millimeters.

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for a human eye with a pupil diameter (aperture diameter d) of 0.005 meters, and a focal length of 0.022 meters, there will be a resolution limit due to diffraction at 0.6 microns (10^-6 meters) wavelength. if we space light-sensitive cells on the retina at this spacing, how many retina cells per meter (of retina) are there? blank 1. calculate the answer by read surrounding text. cells/meter. now suppose there are giants which are exactly twice the size of humans in each dimension. so giant eyes have pupils of 0.01 meters, and a focal length of 0.044 meters. how many retina cells per meter should the giants have? blank 2. calculate the answer by read surrounding text. cells/meter g

Answers

There are 8.4616*10^6 retina cells per metre (of retina) in a human eye with an aperture diameter (d) of 0.005 metres and a focal length of 0.022 metres.

Giant eyes have pupils of 0.01 metres and a focal length of 0.044 metres because they have 4.4 cells/min retina cells per metre. Ten different layers make up the retina of vertebrates. From the vitreous body outward, starting at the nearest point: Nerve fibre layer axons of the ganglion cell bodies; inner limiting membrane basement membrane formed by Müller cells. The inverse of the optical power of an optical system, the focal length provides a measurement of how strongly the system converges or diverges light.

V = 0.00580.52*10^-6/0.022

V = 0.11818*10^-6m

Number of cells in 1 m = 1/0.11818*10^-6m

Number of cells in 1 m =  8.4616*10^6 cells/m

N = f/d

N = 0.044/0.01

N = 4.4

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A metal strip 6.70 cm long, 0.880 mm thick, and 0.850 mm wide moves with constant velocity 23.5 cm/s in the positive y direction through a uniform magnetic field of magnitude 2.30 mt that is directed in the negative z direction. what is the potential difference measured across the width of the strip

Answers

The potential difference measured across the width of the strip which is 6.7 cm long, 0.88 mm thick and 0.85 mm wide is 95.6 v.

How to calculate potential difference ?

Using (1), we get the value:  

constant velocity =3.69105 m/s.

v=BE H

= BwV H

(1)where

VH=3.9V,

w=0.8506×7-2.3 m,

and B=1.210-3 T

v= -1.79 ×0.8506×7-2.3 × 3.9

= 95.6 v

Examples of constant velocity?

Motion with constant velocity is the most basic sort of motion (apart from the trivial case where the body under inquiry is at rest). Every time an object moves over a horizontal, low friction surface in daily life, this type of motion takes place.

What else does constant velocity go by?

Uniform velocity is the state in which a body moves through space and time at the same speed. The body is said to be moving at a uniform velocity when its magnitude and direction do not alter over time.

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A laser with wavelength of 0.00005 m is aimed at a mirror with
an angle of incidence of 30°. What is the angle of reflection of
the laser?

Answers

Answer:

this is question is trying to trick you

Explanation:

it gives long words but all you need to know is just a few

the second law of reflection states that the angle of incidence equals to the angle of reflection

so if the angle of incidence = 30

then

the angle of reflection = 30

hope this helps,

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The NEO that is the most current threat to Earth is:

a. 2011 AG5, an asteroid that is 460 feet wide.
b. 2012 DA14, an asteroid with a 150 –; foot diameter.
c. Halley’s Comet
d. None of these are correct.

Answers

Answer:

Finna take your points

Explanation:

The other answer got maxed out ฅ^•ﻌ•^ฅ

Answer:

Niháo wúji si fiueng^^

Explanation:

I just introduced myself in Mandarin^^

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 375-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 1.80 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.75 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.

Answers

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

A box required 800J of work to lift 5 meters off the ground. How many newtons did the box
weigh?

Answers

Answer:

800 Newtons.

Explanation:

Work is defined as the force applied to an object multiplied by the distance over which the force is applied. The formula for work is W = F x d.

In this case, the force required to lift the box is equal to the work done divided by the distance.

F = W / d

F = 800 J / 5 m

To convert Joules to newtons, we need to use the relation 1 Joule = 1 Newton x Meter

F = 800 N

So the box weighed 800 Newtons.

two disks of identical mass but different radii (r and 2 r) are spinning on frictionless bearings at the same angular speed ω0 but in opposite directions. the two disks are brought slowly together. the resulting frictional force

Answers

When two disks of identical mass but different radii are brought slowly together while spinning on frictionless bearings at the same angular speed but in opposite directions, the resulting frictional force increases due to the increase in angular velocity caused by the change in moment of inertia of the system.


Angular momentum is given by the equation L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia of a rotating object depends on its mass and how that mass is distributed around its axis of rotation.

In this scenario, the disks have the same mass but different radii. The moment of inertia of a disk is given by the equation I = (1/2)mr^2, where m is the mass and r is the radius. Since the disks have the same mass, their moments of inertia will be proportional to their radii squared.


Since the disks are rotating in opposite directions, the change in angular momentum due to their interaction will be the sum of their individual angular momenta. The change in angular momentum is given by ΔL = Lfinal - Linitial.

As the disks are brought closer, their moments of inertia decrease. Therefore, in order to conserve angular momentum, the angular velocity ω will increase. This increase in angular velocity results in an increase in frictional force between the disks.


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