You have —1 ounce of whole wheat grains. How many more ounces do you need to 8
make the recipe?

Answer:

No solution

Step-by-step explanation:

if you replace the y with -2x-6 into the first equation, you will get rid of the x's which it gives you the hint that there is no solution.

The mechanic worked for 5.5 hours to install the new water pump.

Let's assume the mechanic worked for "x" hours to install the water pump.

The cost of the repair work will include the cost of the water pump as well as the labor charges.

The cost of the water pump is given as $249.98.

The labor charges can be calculated by multiplying the hourly rate by the number of hours worked.

So, the labor charges will be $109 multiplied by "x" hours, which is $109x.

Adding the cost of the water pump to the labor charges will give us the total cost of the repair work.

Therefore, we can write the equation as:

$849.48 = $109x + $249.98

Simplifying the equation, we get:

$599.50 = $109x

Dividing both sides by $109, we get:

x = 5.5

Therefore, the mechanic worked for 5.5 hours to install the new water pump.

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Addition of two fractions which are both less than (1/2) must result in a fraction which is always less than 1.

A fraction represents a part of a whole or, more generally, any number of equal parts. A fraction describes how many parts of a certain size there are, for example, one-half, eight-fifths, three-quarters.

Given data

The fractions can be represented as follows;

x < ½   and y < ½

The sum of both of the inequalities is;

x + y < (\(\frac{1}{4}\)) + (\(\frac{1}{4}\))

x + y < ½

Examples are-

\(\frac{1}{5}\)+ \(\frac{2}{3}\) =\(\frac{13}{15}\)

¼ + ½ = ¾

\(\frac{1}{2}\) +\(\frac{1}{3}\) = \(\frac{5}{6}\)

Therefore, Addition of two fractions which are both less than (1/2) must result in a fraction which is always less than 1.

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Answer:

B 4

Step-by-step explanation:

The 4 is in the tens spot in Robin's ticket and if you multiply 40 by 10 you get 400. The 4 is in the hundred spot in Allen's ticket.

There can be 90% confident that the population mean salary of college graduates who took a statistics course is between $60,947.78 and $66,652.22.

To construct a 90% confidence interval for estimating the population means μ of salaries for college graduates who took a statistics course, we can use the formula:

Confidence interval = sample mean ± (critical value) x (standard error)

First, we need to find the critical value from the t-distribution table with a degree of freedom of n-1. Since we have 49 college graduates, our degrees of freedom are 48. Looking at the table, the critical value for a 90% confidence level is 1.677.

Next, we need to find the standard error, which is calculated by dividing the standard deviation by the square root of the sample size. In this case, the standard error is $11,936/sqrt(49) = $1703.05.

Substituting these values into the formula, we get:

Confidence interval = $63,800 ± 1.677 x $1703.05
Confidence interval = $63,800 ± $2852.22

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- BRAINLIEST answerer

The scale factor using in that dilation of the dashed triangle would be = 3:1

A scale factor is defined as the ratio that exists between an original size of an object and the new formed size of the same object.

The formula that can be used to calculate the scale factor ;

Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

Using the base of the triangle from the centre of origin in the graph;

The dimension of the new shape = 18

The dimension of the original shape = 6

scale factor = 18/6 =3

That is, the scale factor = 3:1

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Answer: 5/8

Step-by-step explanation:

To help you with your question, let's break down the different sections of the graph representing Diondre's bike ride. The sections will be based on the descriptions provided. Keep in mind that I cannot see the actual graph, so I will give you general guidelines to identify the sections.

1. When Diondre starts the ride (Section A):
- Look for the initial point on the graph where the speed is zero or very close to zero. This is the beginning of the ride.

2. When Diondre is accelerating (Section B):
- Look for a part of the graph where the speed increases over time. The slope of the graph will be positive in this section, representing an increase in speed.

3. When Diondre maintains a constant speed (Section C):
- Look for a part of the graph where the speed remains the same over time. The slope of the graph will be zero in this section, representing a constant speed.

4. When Diondre is decelerating or slowing down (Section D):
- Look for a part of the graph where the speed decreases over time. The slope of the graph will be negative in this section, representing a decrease in speed.

5. When Diondre stops the ride (Section E):
- Look for the final point on the graph where the speed is zero or very close to zero. This is the end of the ride.

By identifying these sections on the graph, you will be able to describe the different parts of Diondre's bike ride using the given terms.

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Answer:

$2

Step-by-step explanation:

The rate of change is equal to "rise over run"

the rise is: 20

the run is: 10

20/10=2

The counterclockwise circulation around c is 12 and the outward flux through c is zero.

Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.

In this case,

we have a field f=(7x−4y)i+(9y−4x)j and

a square curve c bounded by x=0, x=4, y=0, y=4.

To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.

The curl of f is given by (0,0,3), so the line integral evaluates to 12.

To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.

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Since t cannot be infinity in this case, we conclude that there is no maximum number of items that the worker can produce according to the function.

The number of items produced on the first day can be found by substituting t = 1 into the function P(t):

P(1) = 24 - 24e^(-0.3*1) = 13.24 (rounded to two decimal places)

To find the maximum number of items that the worker can produce, we can take the derivative of the function P(t) with respect to t and set it equal to zero:

P'(t) = 24e^(-0.3t)(0.3) = 7.2e^(-0.3t)

7.2e^(-0.3t) = 0

e^(-0.3t) = 0

t = infinity

However, we can see that as t approaches infinity, P(t) approaches 24. So, we can say that the worker can approach but never exceed 24 items.

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The dimensions of the room will be 12m x 6m.

So, now calculate the dimensions of the room as follows:

Solve as shown:

Therefore, 12m x 6m will be the dimensions of the room.

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Answer:

608 minutes.

Step-by-step explanation:

When you add 8.24 and 11.03 you get 19.27 this number then needs to be multiplied by 32 which leaves us with 616.64. The question asks on average how many minutes James traveled, so I would round to the nearest number which would be 608.

I hope this helped lol

The Attendance was low.

We know, The left edge of the box indicates the lower quartile, representing the value below which the first 25% of the data is located.

Similarly, the right edge of the box represents the upper quartile, indicating that 25% of the data is situated to the right of this value.

From the given box plot we can say that the Attendance was not high because the quartiles located.

Now, from plot we can say that quartiles are clustered towards the left on the number line.

This means that the Attendance was low.

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The value of k that makes the function continuous is k = 5 = 1.

To find the value of k that makes the function continuous, let's consider a function defined by different pieces:

\(\[ f(x) = \begin{cases} x^2 + 1 & \text{if } x < 2 \\ k & \text{if } x = 2 \\ 2x - 3 & \text{if } x > 2 \\ \end{cases}\]\)

For the function to be continuous at x = 2, we need the following conditions to be satisfied:

1. The limit of f(x) as x approaches 2 from the left (x < 2) should be equal to the value of f(x) at x = 2.

2. The limit of f(x) as x approaches 2 from the right (x > 2) should be equal to the value of f(x) at x = 2.

Let's evaluate these limits:

\(\[\lim_{{x \to 2^-}} (x^2 + 1) = 2^2 + 1 = 5\]\\$\[\lim_{{x \to 2^+}} (2x - 3) = 2(2) - 3 = 1\]\)

To ensure continuity, these limits must be equal to the value of f(x) at x = 2, which is k. Therefore, we have k = 5 = 1.

Hence, the value of k that makes the function continuous is k = 5 = 1.

Complete Question - Find the value of k that makes the function continuous by considering a function defined by different pieces.

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If two independent large samples are taken from two populations, the sampling distribution of the difference between the two sample means is normal if populations are non normal and the sample sizes are large.

To test hypotheses about the difference between two populations means we deal with the following three cases.

1) both the populations are normal with known standard deviations.

2)both the populations are normal with unknown standard deviations.

3) both the populations are non normal in which case both the  sample sizes are necessarily large.

So, If two independent large samples are taken from two populations, the sampling distribution of the difference between the two sample means is normal if populations are non normal and the sample sizes are large.

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Answer:

\(3\frac{1}{3}\) or \(\frac{10}{3}\)

Step-by-step explanation:

We could use the combined rate equation to find the combined rate of work.

Combined rate of work formula: \(\frac{1}{t_{b}} = \frac{1}{t_{1} } + \frac{1}{t_{2} }\), where \(t_{1}\) is the individual time for object A, \(t_{2}\) the individual time for object B and \(t_{b}\) is the time for A and B together.

The time it takes Irina to paint the room alone, \(t_{1}\) = 5 hours

The time it takes Paulo to paint the room, \(t_{2}\) = 10 hours

1) Substitute object A (Irina) and B (Paulo) into the formula given above, and change \(t_{b}\) into an \(x\).

\(\frac{1}{{x}} = \frac{1}{5 } + \frac{1}{10 }\)

2) Add the fractions.

\(\frac{1}{x} = \frac{3}{10}\)

3) Solve for the \(x\).

\(x(3) = 1(10)\\3x = 10\\x = \frac{10}{3} \\\)

4) Change them into a mixed fraction.

\(3\frac{1}{3}\)

Note: \(\frac{10}{3}\) or \(3\frac{1}{3}\) are both correct. Write the answer according to the question. In this case, there is no specific rule, so I choose \(3\frac{1}{3}\).

A student's probability of having a sister are 1/2 or 0.5 if they do not have a brother.

Using the above data table, we must determine the likelihood that a student without a brother also has a sister. Analysing the table now

has a sibling: 5

possesses no sisters: 2

has an 18-year-old brother

possesses no brothers: 4

We are looking for the likelihood that a student has a sister and neither a brother (as indicated by the statement "Does not have a brother"). In this instance, there are two children who do not have a brother but do have a sister, making that number the number of positive outcomes.

No matter whether a student has a sister or not, the total number of outcomes is equal to the number of students who do not have a brother. According to the table, there are 4 students without brothers.

As a result, the likelihood that a student who doesn't have a brother will have a sister can be determined as follows:

Probability is calculated as the ratio of the number of favourable outcomes to all possible outcomes.

Probability equals 2/4

Probability equals 0.5 or half.

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Answer:

Fa

Step-by-step explanation:

Answer: 1385.44

Step-by-step explanation:

πr^2*h

Answer:

5

Step-by-step explanation:

to find the answer you need to put this equation into a calculator

the square root of (4-8) squared + (3-6) squared

to find the distance this is put in the distance formula of

the square root of (x2-x1)squared + (y2-y1)squared

a) The optimal size of the production run is approximately 39, units (rounded to the nearest whole number).

b) The average holding cost per year is approximately $1,755.00 (rounded to two decimal places).

c) The average setup cost per year is approximately $24,300.00 (rounded to two decimal places).

d) The total cost per year, including the cost of the lights, is approximately $43,071.00 (rounded to two decimal places).

a) To find the optimal size of the production run, we can use the economic order quantity (EOQ) formula. The EOQ formula is given by:

EOQ = √[(2 * D * S) / H]

Where:

D = Annual demand = 11,700 units

S = Setup cost per production run = $81

H = Holding cost per unit per year = $0.15

Plugging in the values, we have:

EOQ = √[(2 * 11,700 * 81) / 0.15]

= √(189,540,000 / 0.15)

= √1,263,600,000

≈ 39,878.69

Since the optimal size should be rounded to the nearest whole number, the optimal size of the production run is approximately 39, units.

b) The average holding cost per year can be calculated by multiplying the average inventory level by the holding cost per unit per year. The average inventory level can be calculated as half of the production run size (EOQ/2). Therefore:

Average holding cost per year = (EOQ/2) * H

= (39,878.69/2) * 0.15

≈ 2,981.43 * 0.15

≈ $447.22

So, the average holding cost per year is approximately $447.22 (rounded to two decimal places).

c) The average setup cost per year can be calculated by dividing the total setup cost per year by the number of production runs per year. The number of production runs per year is given by:

Number of production runs per year = D / EOQ

= 11,700 / 39,878.69

≈ 0.2935

Total setup cost per year = S * Number of production runs per year

= 81 * 0.2935

≈ $23.70

Therefore, the average setup cost per year is approximately $23.70 (rounded to two decimal places).

d) The total cost per year, including the cost of the lights, can be calculated by summing the annual production cost, annual holding cost, and annual setup cost. The annual production cost is given by:

Annual production cost = D * Cost per light

= 11,700 * 1

= $11,700

Total cost per year = Annual production cost + Average holding cost per year + Average setup cost per year

= $11,700 + $447.22 + $23.70

≈ $12,170.92

Therefore, the total cost per year, including the cost of the lights, is approximately $12,170.92 (rounded to two decimal places).

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Answer:

x^3 + 16x^2 + 64x First, we need to check if there is a greatest common factor (GCF) that we can factor out. In this case, we can factor out "x" since it is a common factor in all the terms: x(x^2 + 16x + 64) Now, we need to factor the quadratic trinomial inside the parentheses. We can do this by finding two numbers that multiply to 64 and add up to 16. These numbers are 8 and 8: x(x + 8)(x + 8) Therefore, the factored form of the trinomial expression is: x(x + 8)^2 I hope this helps!

0 / 350

Answer:

The answer is $20.

Step-by-step explanation:

The way we find how much each cookie is is by dividing 8 by 10. We get 0.8. So now we know each cookie costs 80 cents. So, for 25 cookies, all we need to do is multiply 25 and 0.8. When multiplied, you get the answer $20.

Answer:

She bought 16 pencils

Answer:

\(6(x + 8) = 8x + 36\)

• open the bracket by applying distributive property.

\(6x + 48 = 8x + 36\)

• collect all x terms on left hand side, and constants on the right hand side:

\(6x - 8x = 36 - 48 \\ - 2x = - 12\)

• divide either sides by -2 :

\( \frac{ - 2x}{ - 2} = \frac{ - 12}{ - 2} \\ \\ { \underline{ \underline{ \: \:B): x = 6 \: \: }}}\)

Answer:

x = 4

Step-by-step explanation:

You have a container of lemons. You're sure that you have 8 lemons. And also a total of lemons that is 16 times an unknown number. You know that 14 times an unknown number + 8 makes 16 times that number which is your total lemons. So you move 14x to the other side to get 2x = 8 lemons. Simplifying it gives that unknown number to be 4.

your answer for this question is y=c hope this helps

The complexity, reliability, and context of the evidence collected are some of the reasons why it is not possible to define a simple analytical scheme that can be applied to all types of evidence.

There are several reasons why it is not possible to define a simple analytical scheme that can be applied to all types of evidence.

Firstly, different types of evidence require different analytical techniques, as they have varying degrees of complexity. For example, analyzing DNA evidence requires a different set of analytical tools compared to analyzing physical evidence like fingerprints or footprints.

Secondly, the reliability of the evidence also plays a significant role in the analytical scheme. Some types of evidence may be more subjective than others, and the interpretation of the results may be open to bias or misinterpretation. In such cases, a simple analytical scheme may not provide accurate or reliable results.

Finally, the context in which the evidence is collected also plays a crucial role in determining the analytical scheme. The location, timing, and circumstances of the evidence collection may affect the reliability and accuracy of the results. Therefore, a simple analytical scheme may not be able to accommodate all the variables and nuances of the evidence collected in different contexts.

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