your mother, who is a self-described chocolate addict, phones you. she has read in the newspaper a summary of a research study suggesting that the consumption of a moderate amount of bittersweet chocolate reduces the risk of heart disease in older women. you ask her who funded the research. She says doesn't know and asks you why it would matter.

Alkyne chemistry refers to the branch of chemistry that deals with triple bonds between carbon atoms. Due to the presence of pi-electrons that are not tightly bound, alkynes undergo addition reactions.

Alkynes have a triple bond, which makes it possible to add halogens, water, and other substances to them through an addition reaction. A series of steps are used to create addition goods. The development of addition products is caused by the stability of vinylic cations. Asymmetric alkynes must adhere to Markovnikov's rule in order to conduct addition reaction. Below are a few addition reactions of alkynes that are explained: Alkenes are created when alkynes react with dihydrogen in the presence of catalysts like Pt/Pd/Ni. Alkanes are created when the produced alkenes further react with dihydrogen.

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Answer:

Approximately \(43.9\%\) by mass.

Explanation:

Look up relevant relative atomic mass data on a modern periodic table:

Calculate the formula mass of \(\rm ZnSO_4\), \(\rm H_2O\), and \(\rm ZnSO_4\cdot 7\, H_2O\):

\(M(\rm ZnSO_4) \approx 65.38 + 32.06 + 4 \times 15.999 = 161.436\; \rm g \cdot mol^{-1}\).

\(M(\rm H_2O) \approx 2 \times 1.008 + 15.999 = 18.015\rm g \cdot mol^{-1}\).

\(M(\rm ZnSO_4\cdot 7\, H_2O) \approx 161.436 + 7 \times 18.015 \approx 287.541\; \rm g\cdot mol^{-1}\).

In other words, each mole of \(\rm ZnSO_4\cdot 7\, H_2O\) formula units has a mass of approximately \(287.541\; \rm g\).

However, that one mole of \(\rm ZnSO_4\cdot 7\, H_2O\) also contains seven moles of \(\rm H_2O\) molecules, which has a mass of approximately \(7 \times 18.015 = 126.105\; \rm g\).

Calculate the mass ratio of water in this compound:

\(\begin{aligned}& \%m(\text{water}) \\ &= \frac{m(\text{water})}{m(\text{compound})} \times 100\% \\ &\approx \frac{126.105\; \rm g}{287.541\; \rm g} \times 100\%\approx 43.9\%\end{aligned}\).

Answer:

d.) granulated

Because the granulated sugar has a greater surface area.

Answer:

N₂ + 3H₂ → 2NH3

4Fe + 2Cl₂ → 4FeCl

Explanation:

This equations are now balanced

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Answer:

750mL

Explanation:

According to this question, a container which has the capacity to hold 3 L water already has 2.25 L water in it. This means that the container needs (3 - 2.25) = 0.75L to get filled up completely.

However, this question needs the volume of water needed to fill the container in milliliter (mL). To do this, we say;

1L = 1000mL

0.75L = 0.75 × 1000

= 750mL

Therefore, 750mL of water can still be added to fill up the container completely.

The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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The alcohol product of the reduction of 2-methyl3-pentanone with  1. LiAlH₄ diethyl ether 2. H₂O is B ) racemic mixture.

The reduction of the 2 - methyl-3- pentanone with the LiAlH₄  diethyl ether is given as follows :

                                    1. LiAlH₄ diethyl ether

CH₃ - CH - C - CH₂ -CH₃   ---------------->               CH₃ - CH₂ - CH - CH₂ -CH₃

          |       ||                        2. H₂O                                  |          |

        CH₃   O                                                                  CH₃    OH

2 - methyl-3- pentanone                                       2 - methyl-3- pentanol

This compound is the optically inactive and thus, form the racemic mixture. the optically inactive means it does not rotate the plane polarized light.

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The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j.  25°C is the final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using several temperature scales, which traditionally drew on different reference locations.

The most popular scales include the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

q = m×c×ΔT

4130 = 52×4.184×(T2- 10C)

T2= 25°C  

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Answer:

4

9

4

6667 animals

Explanation:

Answer:

Mass=Moles × RFM

Mass= 0.28M× 164

Mass= 45.92 grammes

Answer:

B) purple loosestrife plants growing in the same wet areas as cattail plants

Explanation:

Competition between members of two species means that two different species are "fighting for" or desire the same resource. This resource could be shelter, food, territory, etc.

An organism cannot compete if it is already dead, so that eliminates answer choices A and C. Answer choice D is wrong because these are two organisms of the same species.

Answer choice B is correct because there are two different species competing for one area of land.

The formula for the given molecule is: C₂NO₂H₅ which is the chemical formula for ethyl nitrite

Ethyl nitrite is an organic compound with the molecular formula CH₃CH₂ONO. It is a colorless, sweet-smelling liquid that is used primarily in the pharmaceutical industry as a vasodilator, which means it helps to widen blood vessels and increase blood flow.

Ethyl nitrite is also used in the production of some types of polymers and as a reagent in organic synthesis. However, it is important to handle this compound with care, as it is highly flammable and can be toxic if ingested or inhaled in large amounts.

Sure, here's some additional information about ethyl nitrite:

Ethyl nitrite has a variety of medical uses. It is sometimes used to treat heart conditions, such as angina and heart failure, as well as pulmonary hypertension. It is also sometimes used to treat cyanide poisoning and methemoglobinemia, a condition in which the blood is unable to transport oxygen properly.

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Answer:

Explanation:

Here, we want to get the molar volume of the gas

At STP, 1 mole of a gas occupies a volume 0f 22.4 dm^3

The conditions at STP are 273K

Answer:

Explanation:

The molar mass of a given substance corresponds and pertains to the unit mole of the mass substance which is stated in g/mol

no of moles of H = mass of H/molar mass of H

= 2 kg/ 2 g/mol

= 2000 g/ 2 g/mol

= 1000 moles

moles of O2 = mass (O2)/ molar mass (O2)

= 2 kg/ 32 g/mol

= 2000 g / 32 g/mol

= 62.5 moles

Total moles present = (1000 + 62.5) moles

= 1062.5 moles

= 1.063 kmol

Total mass = 2kg + 2kg

= 4 kg

no of moles = mass/molar mass

molar mass = mass/ no of moles

molar mass = 4 kg/ 1.063 kmol

molar mass = 3.763 kg/kmol

The specific volume of the final mixture can be determined by the relation:

\(v_{mixture}=\dfrac{ V}{m}\)

where;

V = 3 m³

m = 4 kg

\(v_{mixture}=\dfrac{ 3 \ m^3}{4 \ kg}\)

= 0.75 m³/ kg

For the final volume, The molar specific volume is:

\(v_M = M_{mixture} *v_{mixture}\)

where;

\(M_{mixture} = 3.763\)

\(v_{mixture} = 0.75 \ m^3/ kg\)

∴

\(v_M = 3.763 \ kg/mol \times 0.75 \ m^3/kg\)

\(\mathbf{v_M = 2.82 \ m^3/kmol}\)

Answer: 313.4 I think

Explanation:

sorry if i got it wrong i tried my best

Answer:

it equals up 30 to 35 for me

Explanation:

sorry if its wrong

Answer:

Atomic emission is more sensitive to flame instability than atomic absorption because during atomic emission, the intensity of the emitted light is proportional to the concentration of the element being measured. If the flame is unstable, it can cause fluctuations in the intensity of the light being emitted, which can lead to errors in the measurement of the element's concentration. In contrast, in atomic absorption, the intensity of the absorbed light is measured, which is less sensitive to flame instability since the amount of light absorbed by the element is proportional to its concentration regardless of the flame's stability.

Answer:

Atomic emission is more sensitive to flame instability than atomic absorption because atomic emission is based on the analysis of light emitted from excited atoms in the flame. In contrast, atomic absorption is based on light absorption by the flame's particles.

Flame instability can lead to changes in the temperature and pressure of the flame, which can affect the excited states of the atoms in the flame. When the flame is unstable, it can cause fluctuations in the number of excited atoms and the length of time they stay excited. This, in turn, can lead to fluctuations in the amount of light emitted by the excited atoms, making it more difficult to accurately measure the analyte concentrations in the sample using atomic emission spectroscopy.

On the other hand, atomic absorption spectroscopy is less sensitive to flame instability because the light absorption by the atoms in the flame is not as dependent on the excitation states of the atoms. The atoms in the flame absorb light at specific wavelengths regardless of their excited states. Hence, fluctuations in the excited state populations have less of an impact on the absorption signal. However, atomic absorption spectroscopy can still be affected by other factors, such as changes in the temperature and pressure of the flame and the presence of other interfering species in the sample.

Answer:

The procedure to use the adding scientific notation calculator is as follows: Step 1: Enter two scientific notation numbers in the respective input field Step 2: Now click the button “Solve” to get the result Step 3: Finally, the addition of the given numbers will be displayed in the output field

Explanation:

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Answer:

Determine the number by which to increase the smaller exponent by so it is equal to the larger exponent.

Increase the smaller exponent by this number and move the decimal point of the number with the smaller exponent to the left the same number of places. ...

Add or subtract the new coefficients.

Just use google bro

Explanation:

Answer:

B) hydraulics

Explanation:

Answer:

hydraulics

Explanation:

i got it right the test on apex

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Answer:

I think the answer is 12.0107 u and 6 (6 as the atomic number) and (12.0107 u as the atomic mass).

Explanation:

I Hope this helps.

Answer:

Three double bonds and no lone pairs of electrons- trigonal planar

Two single bonds and two lone pairs of electrons-bent

Five single bonds and no lone pairs of electrons- trigonal bipyramidal

Three single bonds and one lone pair of electrons- trigonal pyramidal

Two double bonds and no lone pairs of electrons - linear

Four single bonds and no lone pairs of electrons- tetrahedral

Six single bonds and no lone pairs of electrons- octahedral

Explanation:

The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.

The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.

Answer:

Below

Explanation:

120 days = 3 half lives of 40 days

so the count of A   will go    120 000 ==>  60 000==> 30 000==> 15 000

  the isotope A that changed to B is then:

         120 000 - 15000 = B count = 105 000

Answer:

403.2 L of O2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCI + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the decomposition of 12 moles of KClO3. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 12 moles of KClO3 will decompose to produce = (12 × 3)/2 = 18 moles of O2.

Thus, 18 moles of O2 is produced.

Finally, we shall determine the volume of O2 produced from the reaction. This can be obtained as illustrated below:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of O2 occupies 22.4 L at STP.

Therefore, 18 moles of O2 will occupy = 18 × 22.4 = 403.2 L at STP.

Thus, 403.2 L of O2 is produced from the reaction.

If the original pressure was 1.00atm ,the final pressure would be 0.777atm.

What is given in question?

Initial Presure,P1 = 1.00atm

Final Presure,P2 = ?

Initial volume,V1 = 24.0

Final volume,V2 = 35.0l

Initial temperature,T1 =263.0k

Final temperature,T2 =298.0k

\(\frac{P1V1}{T1}\)  = \(\frac{P2 V2}{T2}\)

\(\frac{1.00 * 24.0}{263.0 }\) = \(\frac{P2 * 35.0}{298.0}\)

P2 = 0.777atm

Therefore, the final pressure be is 0.777atm.

Hence 0.777atm is a correct answer.

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Explanation:

We know: the density of Hg = 13.5g/ml = 13.5kg/L

lb to kg

Answer:

The correct answer is A.

Answer:

A. 466 g of BaSO₄.

B. 2.25 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

BaO + H₂SO₄ —> BaSO₄ + H₂O

Next, we shall determine the mass of H₂SO₄ that reacted and the mass of BaSO₄ produced from the balanced equation. This can be obtained as follow:

Molar mass of H₂SO₄ = (2×1) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Mass of H₂SO₄ from the balanced equation = 1 × 98 = 98 g

Molar mass of BaSO₄ = 137 + 32 + (16×4)

= 137 + 32 + 64

= 233 g/mol

Mass of BaSO₄ from the balanced equation = 1 × 233 = 233 g

SUMMARY:

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 233 g of BaSO₄.

A. Determination of the mass of BaSO₄ produced by the reaction of 196 g of H₂SO₄.

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 233 g of BaSO₄.

Therefore, 196 g of H₂SO₄ will react to produce = (196 × 233) /98 = 466 g of BaSO₄.

Thus, 466 g of BaSO₄ were obtained from the reaction.

B. Determination of the number of mole of H₂O produced by the reaction of 345 g of BaO.

We'll begin by calculating the number of mole in 345 g of BaO. This can be obtained as follow:

Mass of BaO = 345 g

Molar mass of BaO = 137 + 16 = 153 g/mol

Mole of BaO =?

Mole = mass /Molar mass

Mole of BaO = 345 / 153

Mole of BaO = 2.25 moles

Finally, we shall determine the number of mole of H₂O produced from the reaction. This can be obtained as follow:

BaO + H₂SO₄ —> BaSO₄ + H₂O

From the balanced equation above,

1 mole of BaO reacted to produce 1 mole of H₂O.

Therefore, 2.25 moles of BaO will also react to produce 2.25 moles of H₂O.

Thus, 2.25 moles of H₂O were obtained from the reaction.