When students brush balloons against their wool sweaters or hair, electrons are moved from the wool or hair to the balloon. As a result, the balloon has a net negative charge, whereas the garment or hair, having shed negative charges, has a net positive charge.
What is net charge?The term "net" refers to the sum after both positive and negative costs have been deducted. So, if something has 321 positive charges and 319 negative charges, the overall charge is 321 - 319 = +2. The overall charge is 37 - 42 = -5 if it includes 37 positive charges and 42 negative charges.
Electrons are negatively charged, whereas protons are favourably charged. Atoms have an identical amount of electrons and protons and have a net charge of zero. This makes atoms always neutral.
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Work and Kinetic Energy
1. A car starts at rest and ends up with 1500 j of K E. How much work was done on it?
2. A motorcycle at rest has 550 J of work done on it what is its final K E
3. A runner has 250 J of K E. A short time later, he has 350 J of K E how much work was done on him?
4. A runner has 250 J of K E. A short time later, he has 150 J of K E. How much work was done on him?
5. A 0.150 kg baseball is moving 30.0 m/s How much K E does it have?
6. A 0.150 kg baseball is moving 20.0m/s a bat hits it doing 15.0j of work on it what is the final K E of the ball?
7. A block is at rest a 40.0 N force directed 38.0 above horizontal pulls the block 8.00m across flat ground how much work was done on the block? what is its final K E
8. A block is moving with 52.0 J of K E A 12.0 N force pulls the block straight forward for 3.00 m How much work was done on the block? what is its final K E?
9. A block is moving with 52.0 J of K E A 12.0 N force pulls the block straight back against the motion for 3.00m how much work was done on the block what is its final K E
10. A 5.00 kg block is moving 6.00 m/s a short time later it is moving at 8.00 m/s what was the starting K E? what was the final K E? how much work was done on the block?
1. The work done on the car is equal to its change in kinetic energy, is 1500 J.
2. The work done on the motorcycle is equal to its change in kinetic energy, is 550 J.
3. The work done on the runner is equal to his change in kinetic energy, is 100 J.
4. The work done is equal to the negative of his change in kinetic energy, is 100 J.
5. The kinetic energy of the baseball is 67.5 J.
What is the work done?The definition of work done includes both the forces applied to the body and the total displacement of the body. A constant force F is present before to this block. The goal of this force is to move the body d meters in a straight line in the force's direction.
The work done on the car is equal to its change in kinetic energy, so W = ΔKE = 1500 J.
The work done on the motorcycle is equal to its change in kinetic energy, so W = ΔKE = 550 J. Since the motorcycle was initially at rest, its final kinetic energy is equal to the work done on it, so KEf = W = 550 J.
The work done on the runner is equal to his change in kinetic energy, so W = ΔKE = 350 J - 250 J = 100 J.
Since the runner's kinetic energy has decreased, negative work must have been done on him. The work done is equal to the negative of his change in kinetic energy, so W = -ΔKE = -150 J + 250 J = 100 J.
The kinetic energy of the baseball is given by KE = 1/2 mv^2, where m is its mass and v is its velocity. Plugging in the given values, we get KE = 1/2 (0.150 kg) (30.0 m/s)^2 = 67.5 J.
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4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,
The child's speed at the lowest point is 5.42 m/s.
At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.
Using the conservation of mechanical energy, we can write:
Potential energy at highest point = Kinetic energy at lowest point
mgh = (1/2)mv²
where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.
First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:
h = (1/2)3.00 m = 1.50 m
Next, we can solve for the child's speed at the lowest point:
mgh = (1/2)mv²
40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²
588 J = 20.0 kg * v²
v² = 29.4 m²/s²
v = 5.42 m/s
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A pool cue strikes a 0.25 kg billiard ball with a force of 22 N. If the felt on the pool table supplies
a force of 7 N what is the acceleration of the billiard ball.
Answer:
Approximately \(0.06\; {\rm m \cdot s^{-2}}\), assuming that the force from the pool cue is horizontal.
Explanation:
As the billiard ball moves forward, the pool table will exert friction on the ball. In this question, it is given that the magnitude of this friction is \(7\; {\rm N}\). If the ball is moving forward, this friction will point backward.
The cue exerts a forward force of magnitude \(22\; {\rm N}\) on the billiard ball. The \(22\; {\rm N}\) forward force from the cue and the \(7\; {\rm N}\) backward force from the table interact with each other. The resultant force on the ball will be \((22\; {\rm N} - 7\; {\rm N}) = 15\; {\rm N}\), forward.
When an object of mass \(m\) experiences a net force of \(F\), the acceleration \(a\) of that object will be \(a = (F / m)\).
Apply unit conversion and ensure that the mass of the billiard ball is in standard units (grams): \(m = 0.25\; {\rm kg} = 250\; {\rm g}\).
In this question, the net force on this billiard ball is \(F = 15\; {\rm N}\). With a mass of \(m = 250\; {\rm g}\), the acceleration \(a\) of this billiard ball will be:
\(\begin{aligned}a &= \frac{F}{m} \\ &= \frac{15\; {\rm N}}{250\; {\rm g}} = 0.06\; {\rm m\cdot s^{-2}}\end{aligned}\).
Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?
Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?
Answer:
The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.
The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.
Explanation:
Why does the modern atomic theory used today represent the best explanation scientists have to offer?
Modern technology supports the current atomic theory.
The model of the atom has not changed much in over 75 years.
The modern atomic theory contains over 200 years of research.
Scientists have not been successful in disproving the atomic theory.
Answer:
The answer is C!
Explanation:
Answer:
C- the modern atomic theory contains over 200 years of research.
Explanation:
a wave travels one complete cycle in20sec and has wavelength of 1000mm.what is the speed
Answer:
20000
Explanation:
Speed = Wavelength x Wave Frequency. In this equation, wavelength is measured in meters and frequency is measured in hertz (Hz), or number of waves per second. Therefore, wave speed is given in meters per second, which is the SI unit for speed.
Why is air resistance friction not useful for an airplane?
A. Causes turbulence
B. Speeds it up
C. Slows it down
D. Creates heat
The correct option is C. Air resistance friction is not useful for an airplane because it slows it down.
What is air resistance?Air resistance is the opposition to motion of an object caused by air flow.
High air resistance may cause turbulence during the motion of an air plane. This can lead to engine failure or some mishap during flight.
Air resistance is also a type of friction between air and another material such as airplane.
Effect of air resistance on airplaneFriction between the air and the plane slows the airplane down. This is known as air resistance, or drag.
The faster an object travels through the air, the more it has to fight against drag.
Thus, air resistance friction is not useful for an airplane because it slows it down.
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If a 0.6 kg object hanging from a spring stretches it by 0.55 m, then by how much will the spring be stretched if a 1.2 kg object is suspended from it?
Answer:
\(1.1\; {\rm m}\) (assuming the mass of the spring is negligible.)
Explanation:
Under the assumptions, the force stretching this spring is equal to the weight of the attached object.
With \(g = 9.8\; {\rm N\cdot kg^{-1}}\), the weight of an object would be proportional to its mass. Doubling the mass of the object from \(0.6\; {\rm kg}\) to \(1.2\; {\rm kg}\) will double its weight.
Assume that this spring satisfies Hooke's Law. The displacement \(x\) of the spring from its equilibrium position would be proportional to the force that stretches the spring. Hence, doubling this force will double the displacement of the spring from \(0.55\; {\rm m}\) to \(1.1\; {\rm m}\).
How much force is required to accelerate a 5 kg mass at 20 m/s^2
Hello!
\(\large\boxed{F = 100N}\)
Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:
F = 5 · 20
F = 100N
A skateboarder traveling with an initial velocity 9.0 meters per second,
what is its final velocity, if with an acceleration of 4 m/s2 completed a time
of 4.0 seconds? *
Answer:
25m/s
Steps:
First, The equation v= u + a * t shows us what we need to find, (the finale velocity).
Second, we substitute the values given:
v= 9m/s + 4m/s2 * 4s
Last, We calculate the values:
Multiply 4m/s2 * 4s = 16m/s
Add 9m/s + 16m/s
Answer: 25m/s
Hope this helps :)
1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
The circled one please
Mark brainliest!!
Answer:
50µs
Explanation:
The conversion is that 1 second equals 1,000,000 micro seconds. Since we have 0.00005 seconds, we will multiply that to a million.
0.00005 * 1,000,000 = 50µs
Keep in mind that 50 only has 1 significant figure because any trailing zeroes before the decimal point do NOT count.
Best of Luck!
0.00005 seconds = 50 μs
Thank you
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 5.5 m/s.
(a) In a stiff-legged landing he comes to a halt in 1.5 ms. Find the average net force that acts on him during this time.
275735 N
(b) When he bends his knees, he comes to a halt in 0.08 s. Find the average force now.
? N
(c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b).
stiff legged landing 275735 N
bent legged landing ??? N
Answer:
a)\(F_{net} =275000N\)
b)\(F_{net}'= 386718.75N\)
Explanation:
From the question we are told that:
Man's Mass \(M=75kg\)
Speed of man \(V_m=5.5m/s\)
a)
Landing time \(t_l=1.5ms\)
Generally the equation for average net force F_{ net} is mathematically given by
\(F_{net} = 75 *5.5 /(0.0015) N\)
\(F_{net} =275000N\)
b)
Landing time \(t=0.08s\)
Generally the equation for average net force\(F_{ net}\) is mathematically given by
\(F_{net}' = impulse /time \\ F_{net}'= \frac{m * u}{t}\)
\(F_{net}'= \frac{75 * 5.5}{0.08}\)
\(F_{net}'= 386718.75N\)
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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What is motivation in your own world
Answer:
Motivation is the process that initiates, guides, and maintains goal-oriented behaviors.
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin
The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.
1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).
2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.
3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.
4. However, the given equation does not explicitly mention resistance.
5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).
6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.
7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).
8. Therefore, V = VR + VL.
9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.
10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.
The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.
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4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air?
Answer:
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.
please help answering A,B,C in screenshots thank you!
The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
To plot the velocity vs. time graph, we'll use the given data points:
Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0
Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0
Let's plot these points on a graph:
Time (s) [x-axis] | Velocity (m/s) [y-axis]
--------------------------------------------
2.0 | 6.0
4.0 | 7.0
6.0 | 8.0
8.0 | 9.0
10.0 | 10.0
12.0 | 11.0
After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.
Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.
Using the formula for calculating the slope of a line:
Slope (k) = (Change in velocity) / (Change in time)
For the first two points:
Change in velocity = 7.0 - 6.0 = 1.0 m/s
Change in time = 4.0 - 2.0 = 2.0 s
Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²
Therefore, the slope of the graph is 0.5 m/s².
Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².
Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).
To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:
d = 0.5 * 1.5 = 0.75 meters
Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
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The probable question may be:
An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.
Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.
Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0
A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will
B. What is the physical significance of the slope value computed in part A?
C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.
Two charged particles, with charges q1 = q and q2 = 4q are located at a distance d = 2cm apart on the x axis A third charged particle, with charge q3 = q is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3. Find the position of charge 3 when q = 10n C
Answer:
0.667 cm
Explanation:
|F_1on3| = |F_2on3|
k×q1×q3/x^2 = k×q2×q3/(d-x)^2
q1/x^2 = q2/(d-x)^2
(d-x)^2/x^2 = q2/q1
(d-x)/x = sqrt(q2/q1)
(2 - x)/x = sqrt(4×q/q)
(2 - x)/x = 2
2 - x = 2x
2 = 3x
x = 2/3
x= 0.667 cm
A +26.3 uC charge qy is repelled by a force
of 0.615 N from a second charge 92 that is
0.750 m away. What is the value of 92?
Include the sign of the charge (+ or -).
(u stands for micro.)
[?] x 10-6 C
Answer:
+1.46×10¯⁶ C
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C
Force (F) = 0.615 N
Distance apart (r) = 0.750 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Charge 2 (q₂) =?
The value of the second charge can be obtained as follow:
F = Kq₁q₂ / r²
0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²
0.615 = 236700 × q₂ / 0.5625
Cross multiply
236700 × q₂ = 0.615 × 0.5625
Divide both side by 236700
q₂ = (0.615 × 0.5625) / 236700
q₂ = +1.46×10¯⁶ C
NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C
Answer:
+1.46
Explanation:
acellus
A cathode ray tube is made of glass with a small amount of some kind of gas in it. It has metal electrodes at each end to pick up an electric current. The electrodes are named "positive” and "negative." What are one of the main uses of this device ? to speed up the flow of current flowing through a wire to examine a beam of charged particles to magnetize different atoms within a space to change the strength of a proton within an atom
One of the main uses of this device is to examine a beam of charged particles
The cathode ray tube is a device used to determine the charge flowing in a gas. When an electric field is set up with the help of metal electrodes, the cathode ray tends to bend towards the positive electrode.
Since the cathode ray bends towards the electrodes, it implies that it has a charge and the electrodes present help us determine the charge of the beam of charged particles and thus examine the beam of charged particles.
So, one of the main uses of this device is to examine a beam of charged particles.
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Answer:
B
Explanation:
What type of energy does sunlight energy turn into when it reaches Earth's Surface.
Solar
Wind
Nuclear
Answer:
Explanation:
solar
For each of the situations described below, the object considered is undergoing some changes. Among the possible changes you should consider are:
(Q) The object is absorbing or giving off heat.
(T) The object's temperature is changing.
(U) The object's internal energy is changing.
(W) The object is doing mechanical work or having work done on it.
(C) The objects chemical energy is changing.
For each of the situations described below, identify which of the four changes are taking place and write as many of the letters Q T U W C (or none) as are appropriate.
1. A cylinder with a piston on top contains a compressed gas and is sitting on a thermal reservoir (a large iron block). After everything has come to thermal equilibrium, the piston is moved upward somewhat (very slowly). The object to be considered is the gas in the cylinder.
Q T U W C
2. Consider the same cylinder as in part 1, but it is wrapped in styrofoam, a very good thermal insulator instead of sitting on a heat reservoir. The piston is pressed downward (again, very slowly), compressing the gas. The object to be considered is the gas in the cylinder.
Q T U W C
3. An ice cube sitting in the open air is melting.
Q T U W C
4. A mixture of two moles of hydrogen gas and one mole of oxygen gas in a thermally insulated vessel is subjected to small spark (contributing negligible energy) and converts to water vapor.
Q T U W C
Explain your reasoning for each of these cases.
Answer:
1.) Q T U W
Explanation:
1.) QTUW
2.) UW
3.) QU
4.) QTUC
According to first law of thermodynamics
dU = Q - W
Where
dU = change in internal energy
Q = heat added
W = work done by the system
2.) UW
Work is been done on the system. The pressure will surely distort the internal energy of the system
Pressure = Force/area.
3.) QU
The melting process begins because the air temperature around the ice cubes is warmer
The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another.
4.) Chemical reaction can be exothermic or endothermic which involves absorption or release of heat. Since it is subjected to small spark, there is definitely a change in internal energy.
In this exercise we have to have knowledge about thermodynamics in order to identify the alternatives that are correctly classified, so we can say that:
1.) QTUW
2.) UW
3.) QU
4.) QTUC
According to first law of thermodynamics:
\(dU = Q - W\)
Where:
dU = change in internal energyQ = heat addedW = work done by the system1.) The first alternative corresponds to:
The object is absorbing or giving off heat.The object's temperature is changing.The object's internal energy is changing.The object is doing mechanical work or having work done on it.In other words QTUW.
2.) The second alternative corresponds to:
The object's internal energy is changing.The object is doing mechanical work or having work done on it.Work happen been finished ahead of the system. The pressure will without doubt deform the internal strength of bureaucracy:
\(Pressure = Force/area\)
In other words UW.
3.) The third alternative corresponds to:
The object is absorbing or giving off heat.The object's internal energy is changing.The softening process begins cause the air coldness of some degree around the frozen water cubes happen warmer The complete frozen water particles take in heat strength from the warmer air, bestowing the piece energy and allowing to happen them to move out each one.
In other words QU.
4.) The fourth alternative corresponds to:
The object is absorbing or giving off heat.The object's temperature is changing.The object's internal energy is changing.The objects chemical energy is changing.Chemical reaction maybe exothermic or endothermic that involves assimilation or release of heat. Since it happen commit small spark, skilled happen certainly a change in within strength.
In other words QTUC
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3. A bald eagle in level flight at a height of 135m drops the fish it caught. If the eagle's
speed is 25.0 m/s how far from the drop point will the fish land?
The horizontal distance travelled by the fish when dropped is 131.25 m.
What is the time of motion of the fish?
The time of motion of the fish from the given height is calculated by applying the following kinematic equation as shown below.
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity = 0t is the time of motion'g is acceleration due to gravityh = 0 + ¹/₂gt²
t = √ ( 2h / g )
t = √ ( 2 x 135 / 9.8 )
t = 5.25 seconds
The horizontal distance travelled by the fish when dropped is calculated as;
X = vt
X = 25 m/s x 5.25 s
X = 131.25 m
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Loud speaker A vibrates 200 times each second. Loud speaker B vibrates 400 times each
second.
a)What is the frequency of the sound produced by Loud speaker A? Give the value and
unit.
b)Which loudspeaker produces higher frequency of vibrations?
Answer:
A. 200 Hz
B. Speaker B.
Explanation:
We'll begin by defining the frequency.
The frequency of a wave is defined as the number of vibrations made in 1 second. Mathematically it can be represented as:
Frequency (f) = number of vibration (n) / time (t)
f = n / t
A. Determination of the frequency produced by loud speaker A.
Number of vibrations (n) = 200
Time (t) = 1 s
Frequency (f) =?
f = n / t
f = 200 / 1
f = 200 Hz
B. Determination of the loudspeaker that produces the highest frequency of vibrations.
We shall determine the frequency produced by each speaker. This is illustrated below:
For speaker A:
Number of vibrations (n) = 200
Time (t) = 1 s
Frequency (f) =?
f = n / t
f = 200 / 1
f = 200 Hz
For speaker B:
Number of vibrations (n) = 400
Time (t) = 1 s
Frequency (f) =?
f = n / t
f = 400 / 1
f = 400 Hz
SUMMARY:
Speaker >>>> Frequency
A >>>>>>>>>> 200 Hz
B >>>>>>>>>> 400 Hz
From the above illustration, speaker B produces the highest frequency of vibration.
Answer:
ANSWER is (B)
Explanation:
jxkalxna,x The correct option is : The water will vibrate with less intensity
A car travels 36 km in 30 minutes. The speed of the car is
Answer:
72km/hr
Explanation:
Speed in Km is usually represented in hours. so if the car is in constant velocity, and if the car travels 36km in 30 min then it travels 72km in 1 hour.
so the speed of the car is 72km/hr
90 V
R₁
60
R2
30
R3
30
Based on the circuit above, what would be the current through the R3 resistor?
In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.
To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.
First, let's consider the parallel combination:
In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.
Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:
I_parallel = V / R3
= 90 V / 30 Ω
= 3 A
So, in the parallel combination, the current through R3 is 3 A.
Now, let's consider the series combination:
In a series combination, the total resistance is the sum of the individual resistances:
R_total = R1 + R2 + R3
= 60 Ω + 30 Ω + 30 Ω
= 120 Ω
To find the current through the series combination, we can use Ohm's Law:
I_series = V / R_total
= 90 V / 120 Ω
= 0.75 A
Therefore, in the series combination, the current through R3 is 0.75 A.
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Note the complete questions is User
90 V R₁=60 R2= 30, R3 = 30
Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.
A baseball and a golf ball have the same momentum. The kinetic energy of the baseball is ________ the golf ball.
Answer:
The kinetic energy of the baseball is GREATER than the golf ball.
Explanation: