To find the transformations when battery is active and headlight come on.
Explanation:
The battery stores energy in chemical form.
The headlights have electrical light.
Thus, chemical --> electrical light.
Please help quick
LaToya uses 50 newtons (N) of force to pull a 500 N cart. Which statements are correct about calculating LaToya's mechanical advantage? Select all that apply
A The input force is 50 N
B
The output force is 50N
с
The input force is 500 N
D
The output force is 450 N
E
The mechanical advantage is 10
F
The mechanical advantage is 100
F=ma
Newton's second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object's mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.
The statements which are correct about calculating LaToya's mechanical advantage are—The input force is 50 N, the output force is 450 N and the mechanical advantage is 10.Therefore, the correct option is A, D and E.
What is mechanical advantage?Mechanical advantage is the ratio of output force to input force. In this case, LaToya is using a force of 50 N to pull a cart that weighs 500 N. The output force is the weight of the cart minus the force LaToya exerts on it:
Output force = 500 N- 50 N = 450 N
To see why statement F is incorrect, note that the formula for mechanical advantage is:
Mechanical advantage = output force / input force
Substituting the values we found earlier, we get:
Mechanical advantage = 450 N / 50 N = 9
So the mechanical advantage is actually 9, not 100.
Therefore, the correct option is A, D and E.
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An empty jar is pushed open-side down into water so that trapped air cannot escape. As it is pushed deeper, the buoyant force on the jar
Group of answer choices
A: remains the same.
B: decreases.
C: increases.
As it is pushed deeper, the buoyant force on the jar will decrease. The correct option is B
What is buoyant force ?The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force. Upthrust is another name for this upward thrust. A body submerged partially or completely in a fluid appears to shed weight, or to be lighter, due to the buoyant force.
The fluid under which an object is submerged exerts pressure, which is what generates the buoyancy force. Because a fluid's pressure rises with depth, the buoyancy force is always upward.
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Transcribed image text: The position of a ball rolling in a straight line is given by x = 2.0 - 3.6t + 1.7t2 where x is in meters and t in seconds, (a) What do the numbers 2.0, 3.6, and 1.7 refer to? (b) What are the units of each of these numbers? (c) Determine the position of the ball at t = 1.0 s, 2.0 s, and 3.0 s. (d) What is the average velocity over the interval t = 1.0 s to t = 3.0 s? Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining
a) 2.0 represents the initial position of the ball, -3.6 represents the initial velocity of the ball and 1.7 represents the acceleration of the ball.
b)The unit of 2.0 is meters, the unit of -3.6 is meters per second, and the unit of 1.7 is meters per second squared.
c) Position of of ball at t=1, 2, 3 are -1.9, 5.4 and 9.1 meters respectively
d) Average velocity is 5.5 meter per second
Part a
In the equation x = 2.0 - 3.6t + 1.7t2, the number 2.0 represents the initial position of the ball (i.e., the position of the ball at t = 0 seconds), -3.6 represents the initial velocity of the ball (i.e., the velocity of the ball at t = 0 seconds), and 1.7 represents the acceleration of the ball.
Part b
The unit of 2.0 is meters, the unit of -3.6 is meters per second, and the unit of 1.7 is meters per second squared.
Part c
To determine the position of the ball at t = 1.0 s, 2.0 s, and 3.0 s, we simply substitute these values into the equation:
When t = 1.0 s: x = 2.0 - 3.6(1.0) + 1.7(1.0)^2 = -1.9 meters
When t = 2.0 s: x = 2.0 - 3.6(2.0) + 1.7(2.0)^2 = 5.4 meters
When t = 3.0 s: x = 2.0 - 3.6(3.0) + 1.7(3.0)^2 = 9.1 meters
Part d
The average velocity over the interval t = 1.0 s to t = 3.0 s can be calculated by taking the displacement of the ball during this time interval and dividing it by the time interval:
Displacement = x(3.0) - x(1.0) = 9.1 - (-1.9) = 11.0 meters
Time interval = 3.0 s - 1.0 s = 2.0 s
Average velocity = Displacement / Time interval = 11.0 meters / 2.0 seconds = 5.5 meters per second.
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A circuit is made up of a power source, a coil of copper wire, a moving bar
magnet, and conducting wires. Which part could you remove from the circuit
and still have a working electromagnet?
O A. The power source
O B. The coil of copper wire
O C. The moving bar magnet
O D. The conducting wires
Answer:the power source
Explanation:
Answer:
A. The power source
Explanation:
Just took the quiz
Tessa uses a toy slingshot to launch a tennis ball across the park for her dog to fetch. For her first launch, she
uses 100 N of force. Her second launch uses 200 N of force, and her third launch uses 300 N. Which launch had
the greatest acceleration of the tennis ball?
Answer:
See the explanation below.
Explanation:
To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass [kg]
a = acceleration [m/s²]
The mass of the tennis ball will always be the same therefore it will never change.
Now clearing a:
\(a=\frac{F}{m}\)
If the mass of the ball remains the same:
\(a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}\)
We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.
A 8.0-m long wire with a mass of 10 g is under tension. a transverse wave for which the frequency is 570 hz, the wavelength is 0.10 m, and the amplitude is 3.7 mm is propagating on the wire. the maximum transverse acceleration of a point on a wire is closest to?
The maximum transverse acceleration of a point on a wire is closest to is 474100 m/s².
The wave function expression is given as :
y = A cos ( ωt + Ф)
A is the amplitude
ω is the angular frequency
Ф is the phase angle
the seconds derivative of wave function is the transverse acceleration :
a = d²y / dt²
a = - ω² A cos ( ωt + Ф)
the maximum transverse acceleration is given as :
a_max = ω² A
= ( 2πf)² A
= 4 π² f² A
= 4 × ( 3.14)² (570 )² × 3.7
= 474100 m/s²
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when a movie on a film is projected
A specific number of frames per minute are processed by the projector when a motion picture on film is shown.
What is motion and example?Motion is indeed the open borders of a body in relation to time. For instance, the fan, the carpet's dust blowing off of it, the water running from the taps, a ball rolling about, a moving car, etc. Even for the universe is always changing.
Why do you mean by motion?Movement, the act of process of changing or shifting locations or positions. ability to move with the force of a physical human. gait is the term for the way a person walks. a gesture; a movement or shift in posture.
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a 200.0 lb pumpkin is dropped from the roof of a 5-story (15 m) building. assuming it starts from rest and ignoring drag forces, with what speed does it impact the ground below?
A 200.0 lb pumpkin is dropped from the roof of a 5-story (15 m) building. assuming it starts from rest and ignoring drag forces, with what speed does it impact the ground below is as follow:
The potential energy (P.E.) of an object is the energy it has due to its place, and the higher the object's height, the more potential energy it has. As a result, the pumpkin, with a weight of 200.0 lb, is at a height of
5 x 3.28 = 16.4 meters.
Its gravitational potential energy is equal to the product of the mass of the object, the acceleration due to gravity (9.8 m/s²), and its height above the ground. The gravitational potential energy can be calculated as follows:
Gravitational Potential Energy = mgh
where m is the mass, g is the acceleration due to gravity, and h is the height above the ground.
So, Gravitational Potential Energy
= (200.0 lb) x (1 kg/2.2 lb) x (9.8 m/s²) x (16.4 m)
= 1.867 kJ (rounded to three significant figures)
Now, we know that all of this potential energy will be transformed into kinetic energy (K.E.) when the pumpkin is released and starts falling. The kinetic energy formula is:
K.E. = ½mv²
where m is the mass of the object, and v is the velocity (speed) of the object.
Using the above formula, we can calculate the velocity (speed) of the pumpkin when it reaches the ground below.
K.E. = P.E. (since potential energy equals kinetic energy)
½mv² = mgh
We'll substitute in the numbers we've computed so far and solve for v.
v = √(2gh)
Where v is the speed, g is the acceleration due to gravity, and h is the height above the ground.
So, v = √(2gh) = √(2 x 9.8 m/s² x 16.4 m) = 18.2 m/s (rounded to two significant figures)
Therefore, the speed with which the pumpkin strikes the ground is 18.2 m/s.
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The outside mirror on the passenger side of a car is convex and hasa focal length of -5.5 m. Relative tothis mirror, a truck traveling in the rear has an object distanceof 6 m.
(a) Find the image distance of the truck.
1
m
(b) Find the magnification of the mirror.
2
When a lens is focussed at infinity, its focal length is calculated. The focal length of a lens indicates the angle of view (how much of the scene will be caught) and magnification.
(a) Using the mirror equation:
1/f = 1/do + 1/di
where f is the focal length, do is the object distance, and di is the image distance. Plugging in the given values:
1/-5.5 = 1/6 + 1/di
Solving for di:
di = -3.3 m
The image distance of the truck is -3.3 m, which means it is behind the mirror and virtual.
(b) Using the magnification equation:
m = -di/do
Plugging in the values:
m = -(-3.3)/6
m = 0.55
The magnification of the mirror is 0.55, which means the image of the truck is smaller than the actual truck.
So, the image distance of the truck is -3.3 m, and the magnification of the mirror is 0.55.
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name any two instruments based on archimede's principle
Two instruments based on Archimedes' principle
LactometershydrometersExplanation:
Archimedes' principle states -
when a body is partially or completely immersed in a fluid , the fluid exerts an upward force on the body which is equal to the weight of the fluid displaced by the body.OR
when a body is immersed fully of partially in a fluid , it experiences an upward force that is equal to the weight of the fluid displaced by it.Applicatios : Lactometer , hydrometer.
What will be the final velocity of a car, if it starts to move from rest and accelerates at 10 m/s² after 5 seconds ?
Answer:
50m/s.
Explanation:
Answer:
\(V_f=50m/s\)
Explanation:
Use the the formula for final velocity (kinematic equation):
\(V_f=V_i+at\)
Final velocity = Initial velocity + acceleration times time
Given values:
Rest - indicates 0 initial velocity
Acceleration - 10 m/s^2
Time - 5 seconds
Insert the given values:
\(V_f=0+5\times10\)
\(V_f=50m/s\)
A train travel on a straight track passing signal A at 20ms-1. It accelerates uniformly a 3ms-2 and reaches signal B 120m furthe than A. At B, the velocity of the train is?
Since acceleration is uniform, if the velocity at point B is v, then
\(v^2 - \left(20\dfrac{\rm m}{\rm s}\right)^2 = 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)\)
Solve for v :
\(v^2 = \left(20\dfrac{\rm m}{\rm s}\right)^2 + 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m) \\\\ v = \sqrt{\left(20\dfrac{\rm m}{\rm s}\right)^2 + 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)} \\\\ \boxed{v \approx 34 \dfrac{\rm m}{\rm s}}\)
A 2.2 kW electric iron operates normally on a voltage of 220 V.
Fill in the blank.
The current in the iron when it is operating normally is _____ A.
Answer:
Current equals Power divided by Voltage (I=P/V), Power equals Current times Voltage (P=VxI), and Voltage equals Power divided by Current (V=P/I).
P = V I
2.2*10³ = 220 * I
I = 10 amps
If household voltage is 120 volts, what is the resistance created by the light bulb with 0.5 amps of current flowing through it?
Answer:
R = 240 Ω
Explanation:
The resistance created by the light bulb can be calculated by using Ohm's Law:
\(V = IR\\\\R =\frac{V}{I}\)
where,
R = Resistance created by the light bulb = ?
V = Voltage across the bulb = 120 volts
I = current passing through the light bulb = 0.5 A
Therefore,
\(R = \frac{120\ volts}{0.5\ A}\)
R = 240 Ω
a 67.0-kg person jumps from rest off a 3.00-m-high tower straight down into the water. neglect air resistance. she comes to rest 1.10 m under the surface of the water. determine the magnitude of the average force that the water exerts on the diver. this force is non conservative.
Work by gravity plus work by water equals 0 or 2692 = F *1.10 or F = 2447 Newtons
As work-energy, you could:
Since she began and concluded at rest, her initial and final K are both zero. Total work = ΔK.
Gravity: force * distance
mgΔh = 67 * 9.8 * 4.10 = 2692 Joules.
Force * Dist =- F *1.10
Work by gravity + work by water = 0
2692 - F *1.10 = 0
2692 = F *1.10
F = 2447 Newtons!
Because gravity continues to affect her even when she is submerged, take note of the total distance she travels: 3.00 + 1.10!
Work now being done by the water: Because of the force pushing up on her as she descends, the equation is negative. Work is negative when the directions of force and distance are in opposition.
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a runner completes one complete lap around a 400m track, and finishes exactly where she started. what is her linear distance with respect to the starting position?
When a runner completes one lap around a 400m track and finishes exactly where she started, her linear distance with respect to the starting position is zero.
This is because the linear distance is the shortest distance between two points, and in this case, the runner started and ended at the same point.
However, it is important to note that the distance covered by the runner is not zero - she has covered a distance of 400 meters by completing one lap around the track.
It is common for people to confuse linear distance with total distance covered, but they are not the same thing. Linear distance refers to the shortest distance between two points,
while total distance covered refers to the overall distance traveled by an object, regardless of the path taken. In this case, the runner covered a total distance of 400 meters by running one lap around the track,
but her linear distance with respect to the starting position is zero because she ended up at the same point where she started.
In conclusion, the runner's linear distance with respect to the starting position is zero, even though she covered a total distance of 400 meters by completing one lap around the 400m track.
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Which statements about carbon-14 dating are true? Check all that apply. Carbon-14 decays into nitrogen-14. Carbon-14 has a longer half-life than potassium-40. Once a living thing dies, it no longer takes in carbon. Carbon-14 dating is used to date very old volcanic rock. Carbon-14 dating works for fossils as old as 50,000 years.
Answer:
135
Explanation:
I need help with the 1st and the 3rd one plzzzzzzzzzzzzz
Answer for the first one is 2. The answer for the 3rd one is 8
When a cricket ball is thrown vertically upwards, it reaches a maximum height of 15 metres. (a) What was the initial speed of the ball ? (b) How much time is taken by the ball to reach the highest point ? (g=10 ms -2
Answer:
The velocity of the cricket ball is 17.32 m/s
Time is taken by the ball to reach the highest point = 0.8660 seconds
Explanation:
The cricket ball can be seen and treated as a projectile in this case
The maximum height attained by a projectile in motion can be calculated using the formula:
\(h = \frac{v^2 sin^2 \theta }{2g}\)
In any projectile problem, once we know see that the object was released vertically upwards, we need to know that this means that the angle of projection is 90 degrees, and sin 90 is = 1
hence, h will be modified to become
\(h = \frac{v^2 }{2g}\)
\(v = \sqrt{2gh}\)
We are given that h = 15m and g = 10m/s2
\(v = \sqrt{2 \times 10 \times 15} = 17.32m/s\)
The velocity of the cricket ball is 17.32 m/s
B. We can get the time it took to reach the highest point by dividing
time = distance/speed
Time = 15/17.32 = 0.8660 seconds
Water has a high specific heat capacity. This means that a lot of energy is needed to change its temperature. True or false?
Answer:
a true
Explanation:
Water has the high specific heat capacity.
That means it resists to change its temperature when a considerable amount of heat lost or gained
4200J is needed to raise the temperature of 1kg substance by 1 degree Celsius
An astronaut lands on a moon that has one-twentieth the mass of Earth and one-fourth the radius. Find the weight of the astronaut standing on this moon in terms of his Earth weight wE.
wX= wE
The weight of the astronaut standing on the moon, denoted as wX, can be expressed as wX = 1/20 * wE. The weight of an object is given by the product of its mass and the acceleration due to gravity.
The weight of an object is given by the product of its mass and the acceleration due to gravity. Since the astronaut's mass remains the same on both Earth and the moon, we can compare the gravitational forces acting on them.
The gravitational force is inversely proportional to the square of the distance between the two objects. Since the radius of the moon is one-fourth that of Earth, the distance between the astronaut and the center of the moon is also one-fourth. Consequently, the gravitational force experienced by the astronaut on the moon is one-twentieth of that experienced on Earth.
Therefore, the weight of the astronaut on the moon, wX, is one-twentieth (1/20) of their Earth weight, wE.
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When will you say a body is in a) uniform acceleration (b) non uniform acceleration
Answer:
See below ~
Explanation:
Part (a) :
We can say a body is in uniform acceleration if the acceleration of the object remains constant with respect to time throughout its motion.
Part (b) :
We can say a body is non-uniform acceleration if the acceleration of the body varies with respect to time throughout its motion.
A body has weight 600N on the surface of the mars then what is its mass on the same place.
Answer:
\(\boxed{m = 162.16 kg}\)
Explanation:
Given:
Weight = W = 600 N
Acceleration due to gravity = g = 3.7 m/s²
Required:
Mass = m = ?
Formula:
W = mg
Solution:
For m, it'll be
=> m = W/g
=> m = 600/3.7
=> m = 162.16 kg
Answer:
Explanation:
Weight (w) = Mass (m) x Acceleration due to gravity (g)
weight = 600 N
g = 3.72076 ms^-2
m = w / g
m = 600 / 3.72076
m = 161.25737752502176974596587793892 kg
m ≈ 161.3 kg
what is the correct answer?
Answer:
Option (3)
Explanation:
From the graph attached,
Zeros of the function are, x = -3,
Graph of the polynomial touches x axis at x = -3, 1 and 3
Therefore, equation of the given function will be in the form of,
P(x) = \(k(x+3)^a(x-1)^b(x-3)^c\)
Since, graph of the function just touches the x-axis, multiplicity of zero at x = -3 will be even and crosses x-axis so the multiplicity at x = 1 and 3 will be odd.
Therefore, possible function will be,
P(x) = \(k(x+3)^2(x-1)(x-3)\)
Since, y-intercept of the function is at (0, -3),
P(0) = k(0 + 3)²(0 - 1)(0 - 3)
-3 = 27k
k = \(-\frac{3}{27}=-\frac{1}{9}\)
Therefore, given polynomial function is,
P(x) = \(-\frac{1}{9}(x+3)^{2}(x-1)(x-3)\)
Option (3) will be the correct option.
the linear momentum of a bullet-gun system is zero before the gun fires. afterwards: i. the kinetic energy is zero ii. the momentum is zero group of answer choices i & ii i ii neither i nor ii
Answer:
Neither of the two options.
Explanation:
Before a bullet is fired, the momentum of the bullet-gun system is zero because of lack of velocity. After the gun is fired, both gun and bullet acquire velocity making them nonzero. Thus, it is impossible for the kinetic energy to be zero because both the bullet and the gun are in motion. Also, the momentum is nonzero momentum is the product of the mass of an object and its corresponding velocity. Once the bullet is fired, both the bullet and the gun gains momentum thus making it nonzero.
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An electric field exerts force of 2.60 N on a 3.40 x 10-8 C charge. What is the magnitude of the electric field?Group of answer choices7.65 x 107 N/C8.43 x 107 N/C9.05 x 107 N/C12.0 x 107 N/C
ANSWER
\(7.65\cdot10^7N\/C\)EXPLANATION
We want to find the magnitude of the electric field.
To do this, we have to apply the formula for electric field:
\(E=\frac{F}{q}\)where F = force exerted on the charged particle
q = electric charge on the particle
Hence, the magnitude of the electric field is:
\(\begin{gathered} E=\frac{2.60}{3.40\cdot10^{-8}} \\ E=7.65\cdot10^7N\/C \end{gathered}\)The correct answer is the first option.
50 points physics question (multiple choice) Will give brainliest!
There are two systems that contain only the fundamental frequency and they are the systems C and D.
What is fundamental frequency?The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.
From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.
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if a star was moved twice as far away, how bright would it appear?
If a star is moved twice as far away, it would appear one-fourth as bright.
The apparent brightness of a star depends on its distance and the inverse square law. According to the inverse square law, the brightness of an object decreases as the square of its distance increases. If a star is moved twice as far away, its distance from the observer would be doubled.
Applying the inverse square law, the brightness would decrease by a factor of four (2^2). This means the star would appear one-fourth as bright as before. The amount of light reaching the observer decreases as the distance increases, leading to a decrease in apparent brightness. Therefore, moving a star twice as far away reduces its apparent brightness to one-fourth of its original value.
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A student is on a sail boat in the ocean the boat is moving up and down but not moving horizontally she counts that the bait rises and falls 42 times in 60 s
Overlooking a lake is a sailboat. The weight of the boat, the buoyant force (the force created when the boat makes contact with the water and is propelled upward), the wind's forward force, and the water's backward drag are the four forces at work.
What is meant by sailboat?Smaller than a sailing ship, a sailboat or sailing boat is a vessel powered fully or partially by sails. By area and nautical culture, there are differences in what is considered a sailing boat and a ship. International commerce routes were established using sailboats, albeit less reliant power sources have since supplanted this kind of propulsion. Nowadays, recreational sailing is almost the exclusive usage of sailboats. There are numerous options available for both the popular pleasures of cruising and racing. A sailboat is a little boat that travels at the speed of the wind. Sailboats can travel at high speeds when the wind is strong enough. Ahoy! Sailboats, often known as sailing boats in Britain, can have one to five sails.To learn more about sailboat, refer to:
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(b) Complete the sentence about longitudinal
waves.
The vibrations of the air particles are.....
to the
direction of energy transfer.
(C) A stationary car horn emits a sound wave frequency 400 Hz. The wavelength of the wave is 0.85 m. Calculate the speed of sound.
Answer:
see below
Explanation:
b ) the vibrations of the air particles are parallel to the direction of energy transfer.
c) use formula
speed = wavelength x frequency
speed = 0.85 x 400
speed = 340 m/s
hope you get it
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