110.94 as a percentage

Answer:

true

Step-by-step explanation:

if you rewrite \(sec\left(\frac{\pi }{2}\:-x\right)\) with trigonometric identities:

\(sec\left(\frac{\pi }{2}\:-x\right)\)    \(=\frac{1}{\sin \left(x\right)}\)

\(\frac{1}{\sin \left(x\right)}\)  \(=\csc \left(x\right)\)

so, yes,  \(sec\left(\frac{\pi }{2}\:-x\right)\)  \(=\csc \left(x\right)\)

hope this helps!!

Answer:

Step-by-step explanation:

1.

\(-7x+16=58\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\-7x+16-16=58-16\\\\-7x=42\\\\\mathrm{Divide\:both\:sides\:by\:}-7\\\\\frac{-7x}{-7}=\frac{42}{-7}\\\\x =-6\)

2.

\(-2x+15=-9\\\\\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}\\\\-2x+15-15=-9-15\\\\-2x=-24\\\\\mathrm{Divide\:both\:sides\:by\:}-2\\\\\frac{-2x}{-2}=\frac{-24}{-2}\\\\x=12\\\)

3.

\(5x-4=36\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\5x-4+4=36+4\\\\5x=40\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}=\frac{40}{5}\\\\x=8\)

4.

\(25-3x=88\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\\\25-3x-25=88-25\\\\\mathrm{Divide\:both\:sides\:by\:}-3\\\\\frac{-3x}{-3}=\frac{63}{-3}\\\\x=-21\)

5.

\(-11=7-x\\\\\mathrm{Add\:}x\mathrm{\:to\:both\:sides}\\\\-11+x=7-x+x\\\\-11+x=7\\\\\mathrm{Add\:}11\mathrm{\:to\:both\:sides}\\\\-11+x+11=7+11\\\\x=18\)

6.

\(65+15x=35\\\\\mathrm{Subtract\:}65\mathrm{\:from\:both\:sides}\\\\65+15x-65=35-65\\\\\mathrm{Divide\:both\:sides\:by\:}15\\\\\frac{15x}{15}=\frac{-30}{15}\\\\x=-2\)

7.

\(\frac{1}{2} x-18=2\\\\\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\\\\frac{1}{2}x-18+18=2+18\\\\\frac{1}{2}x=20\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\\\2\times\frac{1}{2}x=20\times \:2\\\\x=4\)

8.

\(\frac{2}{3}x-10=-12 \\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{2}{3}x-10+10=-12+10\\\\\frac{2}{3}x=-2\\\\Divide\:both\:sides\:by\: 2/3\\\\\frac{2}{3}x\div \frac{2}{3} =-2\div \frac{2}{3} \\\\\frac{2}{3} x\times \frac{3}{2} =-2\times\frac{3}{2} \\\\x =-3\)

9.

\(6-\frac{1}{3}x=-1 \\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-\frac{1}{3}x-6=-1-6\\\\-\frac{1}{3}x=-7\\\\\mathrm{Multiply\:both\:sides\:by\:}-3\\\\\left(-\frac{1}{3}x\right)\left(-3\right)=\left(-7\right)\left(-3\right)\\\\x=21\)

10.

\(4-9x=-14\\\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\\\4-9x-4=-14-4\\\\-9x=-18\\\\\mathrm{Divide\:both\:sides\:by\:}-9\\\\\frac{-9x}{-9}=\frac{-18}{-9}\\\\x=2\)

11.

\(11-x=29\\\\\mathrm{Subtract\:}11\mathrm{\:from\:both\:sides}\\\\-x=18\\\\\mathrm{Divide\:both\:sides\:by\:}-1\\\\\frac{-x}{-1}=\frac{18}{-1}\\\\x=-18\)

12.

\(-9-11x=68\\\\\mathrm{Add\:}9\mathrm{\:to\:both\:sides}\\\\-9-11x+9=68+9\\\\-11x=77\\\\\mathrm{Divide\:both\:sides\:by\:}-11\\\\\frac{-11x}{-11}=\frac{77}{-11}\\\\x=-7\)

13.

\(45+\frac{5}{6}x =50\\\\\mathrm{Subtract\:}45\mathrm{\:from\:both\:sides}\\\\45+\frac{5}{6}x-45=50-45\\\\\frac{5}{6}x=5\\\\\mathrm{Divide\:both\:sides\:by\:}5/6\\\\\frac{5}{6} x\div\frac{5}{6}=5\div\frac{5}{6}\\\\\frac{5}{6}x\times \frac{6}{5}= 5\times\frac{6}{5}\\\\ x=6\)

14.

\(-5x+17=-33\\\\\mathrm{Subtract\:}17\mathrm{\:from\:both\:sides}\\\\-5x+17-17=-33-17\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\\\frac{-5x}{-5}=\frac{-50}{-5}\\\\x=10\)

15.

\(95=-4+33x\\\\-4+33x=95\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\-4+33x+4=95+4\\\\\mathrm{Divide\:both\:sides\:by\:}33\\\\\frac{33x}{33}=\frac{99}{33}\\\\x=3\)

To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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The tabular method is called: cross-tabulation.

Therefore, the tabular method is called: cross-tabulation.

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The amount of wrapping paper that is needed to cover the larger box is equal to 1,323 cm².

In Mathematics and Geometry, a direct proportion simply refers to a mathematical equation which is typically used to represent the equality of two (2) ratios.

By applying direct proportion to the given information, we have the following mathematical equation:

smaller box = larger box

14 cm = 1029 cm²

18 cm = x cm²

By cross-multiplying, we have the following:

14x = 1029 × 18

14x = 18,522

x = 18,522/14

x = 1,323 cm².

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Answer:

B

Step-by-step explanation:

it would be (4^2=16-1=15)/(-4+1=-3)

-15/3=-5

\(( {m}^{2} - 2mn) \div m = m - 2n\)

\( \frac{( {m}^{2} - 2mn)}{m} \)

\( = \frac{ {m}^{2} }{m} - \frac{2mn}{m} \)

\( = m - 2n\)

a) When Lily's age is 20, and Raphael's age is divided by 3 then the expression of Lily's age in terms of h is h < 10.

b) Ethan's age is half of Raphael's age therefore, Ethan's age is half Raphael's age.

a) If Raphael is twice as old as his sister Lily, we can represent their ages as 2h and h, respectively, where h is Lily's age. The sum of their ages is less than 30, so we can write the equation:

2h + h < 30

Combining like terms, we get:

3h < 30

Dividing both sides by 3, we get:

h < 10

This is an expression of Lily's age in terms of h.

b) If Ethan's age is 16, and Raphael's age is twice Ethan's age, we can represent Raphael's age as 2 × 16 = 32.

Ethan's age is 16, which is half of Raphael's age of 32. Therefore, Ethan's age is half of Raphael's age.

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The question is -

Raphael is twice as old as his sister. The sum of their ages is less than 30.

a) Lily's age is 20, and Raphael's age is divided by 3. Write an expression in terms of h for Lily's age.

b) An expression for Ethan's age 16. Write a sentence to describe how Ethan's age compares with Raphael's age.

Answer:

5 gallons

Step-by-step explanation:

If she can do 1/10 gallon per seconds, that means she can do 5/50.

You can write it as this ratio:

1/10 = x/50.

You know that 10 * 5 = 50.

Since it is a constant ratio, it has to be 1 * 5 = x

Since 1 * 5 = 5, Tiffany can fill the pool 5 gallons per 50 seconds.

Answer:

y=17.2x²-226.3x+2184.5

Congruent triangles have equal corresponding sides and angles

Angles RAT and QAS are congruent

Given that:

AR= AQ and RT=QS

Subtract QS from both sides of the second equation

RT-ST=QS-ST

The above equation means that:

RS = QT or

RS = TQ

In triangle ARQ,

Angles R and Q are congruent because the base angles of an isosceles triangle are congruent.

So, we have:

Angle R = Angle Q

Also,

Angle ARS is congruent to ATQ.

The above means that:

Side lengths AT and AS are congruent

So, we have:

AT=AS ---- The base angles of an isosceles triangle ATS

Because of the above highlights,

Angle 1 = Angle 3

Add angle 2 to both sides

Angle 1 + Angle 2 = Angle 3 + Angle 2

So, we have:

Angle RAT = Angle QAS

Hence, angles RAT and QAS are congruent

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Answer:

15) f = 18

3f = 54

6f = 108

16) k = 69

Step-by-step explanation:

15)

3f + 6f + f = 180

10f= 180

f = 18

16)

42 + k + k = 180

42 + 2k = 180

2k = 138

k = 69

Answer:

x=6

Step-by-step explanation:

Answer: 12.81 (look at the image for the explanation)

Step-by-step explanation:

Answer:

I think the answer is A

1,2

Step-by-step explanation:

Continuous compounding formula :

FV = PV e^rt    FV = future value   PV = present value    

                r = decimal interest  rate     t = years

FV = 1000 e^(.045 * 10) = $ 1568.31

The values of x and y in the given system of equations are x = 4.00 and y = 5.00. These values are obtained by solving the system using the method of substitution.

The given system of linear equations is:

0.50x + 0.20y = 3.00 ...(Equation 1)

x + y = 9.00 ...(Equation 2)

To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using the method of substitution:

From Equation 2, we can express x in terms of y:

x = 9.00 - y

Substituting this expression for x in Equation 1, we have:

0.50(9.00 - y) + 0.20y = 3.00

Expanding and simplifying:

4.50 - 0.50y + 0.20y = 3.00

-0.30y = -1.50

Dividing both sides by -0.30:

y = -1.50 / -0.30

y = 5.00

Now, substitute this value of y back into Equation 2 to find x:

x + 5.00 = 9.00

x = 9.00 - 5.00

x = 4.00

Therefore, the values of x and y in the given system of equations are x = 4.00 and y = 5.00.

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(a). The estimation results may not be reliable.

(b). The correct regression model is: Y = Bo + B₁X + u where X is randomized based on covariate W₁ and u is the error term.

(c). The measurement errors are not random, but systematic, they can lead to biased parameter estimates and erroneous statistical inference.

(d).  The variance of the error term is low, the t-statistics will be large, and the hypothesis tests will be more powerful.

(1). The term that contains the information of W in the above regression is B₁X₁. If X, and W, are negatively correlated, then the OLS estimator of B₁ becomes less precise. In other words, the standard errors of the coefficient estimates increase because the covariance between the explanatory variables is negative, and the variance of the OLS estimator increases as a result.

Hence, the estimation results may not be reliable.

(2). A randomized regression model is a regression model in which a treatment is randomly assigned to the subjects in the sample. The model is used to test whether the treatment affects the outcome variable.

The correct regression model is: Y = Bo + B₁X + u where X is randomized based on covariate W₁ and u is the error term.

(3). Yes, measurement errors in the dependent variable can cause problems in the ordinary least square estimation. In this case, the errors are called measurement errors, which are due to inaccuracies in the measurement of the dependent variable.

If the measurement errors are not random, but systematic, they can lead to biased parameter estimates and erroneous statistical inference.

(4). The variance of the error term affects hypothesis testing of the regression in the following way: If the variance of the error term is high, it means that the noise in the data is large, and hence the accuracy of the parameter estimates is low.

As a result, the t-statistics will be small, and the hypothesis tests will be less powerful.

Conversely, if the variance of the error term is low, the t-statistics will be large, and the hypothesis tests will be more powerful.

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(1). The estimation results may not be reliable.

(2). The correct regression model is: Y = Bo + B₁X + u.

(3). The measurement errors are not random, but systematic, they can lead to biased parameter estimates and erroneous statistical inference.

(4).  The variance of the error term is low, the t-statistics will be large, and the hypothesis tests will be more powerful.

(1). The term that contains the information of W in the above regression is B₁X₁. If X, and W, are negatively correlated, then the OLS estimator of B₁ becomes less precise. Hence, the estimation results may not be reliable.

(2). The model is used to test whether the treatment affects the outcome variable. The correct regression model is: Y = Bo + B₁X + u where X is randomized based on covariate W₁ and u is the error term.

(3). Yes, measurement errors in the dependent variable can cause problems in the ordinary least square estimation.

(4). The variance of the error term affects hypothesis testing of the regression in the following way: If the variance of the error term is high, it means that the noise in the data is large, and hence the accuracy of the parameter estimates is low.

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Answer:

the answer is 3.2 because your divide 16 by 5.

Step-by-step explanation:

Producing rDNA involves isolating and cleaving DNA, inserting fragments into a vector, and transforming host cells. rDNA can be introduced via transformation, transfection, or viral vectors. Clinical applications include protein production, gene therapy, vaccines, and diagnostics.

Producing a recombinant DNA (rDNA) vector involves several general steps. Here are the three main steps involved in the process:

Isolation and Cleavage of DNA:

The first step is to isolate the desired DNA fragments from the source organism. This can be done using various techniques such as PCR (Polymerase Chain Reaction) or restriction enzyme digestion. Restriction enzymes are enzymes that cut DNA at specific recognition sites. By using the appropriate restriction enzymes, the desired DNA fragment and a vector DNA can be cut at specific sites. The vector is usually a plasmid, which is a small circular DNA molecule.

Insertion of DNA Fragments into the Vector:

Once the DNA fragments and vector have been cut, they are mixed together and joined through a process called ligation. DNA ligase is used to catalyze the formation of covalent bonds between the ends of the DNA fragments and the vector. This creates a recombinant DNA molecule containing the desired DNA fragment within the vector. The recombinant DNA molecule is then introduced into host cells for replication.

Transformation of Host Cells:

The recombinant DNA molecules need to be introduced into host cells to produce multiple copies of the recombinant DNA. This is typically done using a process called transformation. Host cells, such as bacteria or yeast, are treated in a way that makes them more receptive to taking up the recombinant DNA. Methods for transformation include heat shock, electroporation, or using chemical agents. Once the host cells have taken up the recombinant DNA, they can be grown in culture to produce large quantities of the desired DNA fragment.

Introduction of rDNA into Cells:

Recombinant DNA can be introduced into cells using various methods, depending on the type of cells being targeted. Some common techniques include:

Transformation: As mentioned earlier, host cells, such as bacteria or yeast, can be treated to make them receptive to taking up the recombinant DNA. This can be achieved by exposing the cells to heat shock, electroporation, or using chemical agents.

Transfection: This method is used for introducing rDNA into eukaryotic cells, including animal cells. It involves the use of techniques such as calcium phosphate precipitation, liposome-mediated transfection, or electroporation.

Viral Vectors: Certain viruses, such as retroviruses, adenoviruses, or lentiviruses, can be modified to carry the recombinant DNA. These viral vectors can then infect target cells and deliver the rDNA into the host genome.

Clinical Applications of rDNA:

Recombinant DNA technology has revolutionized biomedical research and has led to numerous clinical applications. Some important applications include:

Production of Therapeutic Proteins: rDNA technology allows for the production of large quantities of therapeutic proteins, such as insulin, growth factors, clotting factors, and monoclonal antibodies. These proteins can be used to treat various diseases, including diabetes, cancer, and genetic disorders.

Gene Therapy: rDNA vectors can be used to deliver functional copies of genes into target cells to correct genetic defects. This holds promise for the treatment of inherited diseases caused by single gene mutations, such as cystic fibrosis and muscular dystrophy.

Vaccine Development: Recombinant DNA technology has been instrumental in the development of vaccines. By expressing specific antigens from pathogens, recombinant vaccines can be created to stimulate an immune response without causing disease.

Diagnostic Tools: Recombinant DNA techniques are used to produce specific DNA or RNA probes for diagnostic purposes. These probes can detect the presence of specific genes or mutations associated with diseases, aiding in early detection and personalized medicine.

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In both the U.S.A. and England, there are only two days of the year that share the same symbol: May 2 (5/2) and February 5 (5/2).

In the United States, the symbol 5/2 is interpreted as the 5th month and 2nd day, representing May 2. On the other hand, in England, 5/2 denotes the 5th day and 2nd month, indicating February 5. To determine how many days of the year have the same symbol in both countries, we need to find the dates that match.

In the U.S., there are 12 months, so there are 12 possible combinations with 5 as the month. However, only May 2 (5/2) coincides with the English interpretation.

In England, there are 31 days in January, so there is no match with the American format. However, in February, there are 28 days (or 29 in a leap year), and February 5 (5/2) aligns with the American interpretation.

Hence, there are only two days of the year that share the same symbol in both the U.S. and England: May 2 (5/2) and February 5 (5/2).

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The confidence interval is used to estimate the average age of all Pokémon players. Option(a) is correct.

A confidence interval displays the probability that a parameter will fall between two values close to the mean. Confidence intervals express the degree of certainty or unpredictability of a sampling technique.

The importance of a proposed (hypothesized) relationship between population statistics (parameters) and their corresponding sample estimators is examined using a hypothesis test, a statistical inference technique.

We employ confidence intervals whenever we want to estimate any parameters.

To Calculate the estimated mean we use the confidence interval formula

(X bar ± Z*σ/√n)

So option (a) is correct.

Therefore confidence interval is used to estimate the average age of all Pokémon players.

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Answer:

15.25 cups per batch

Step-by-step explanation:

Answer:b

Step-by-step explanation:

Answer:

ok I will help you because I am a nice person:)

Answer:

400 + 16 x

Step-by-step explanation:

hope this helps

Answer:

A. Unfavorable variance.

Step-by-step explanation:

A. Unfavorable variance.

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Answer:

It will be the first one

Step-by-step explanation:

Hope this Helped

Answer:

B.2≤x≤5

Step-by-step explanation:

Answer:

Option B is the correct answer

Step-by-step explanation:

\( 2 \leqslant x \leqslant 5\) is the domain of the given problem.

Answer:

B

Step-by-step explanation:

did test got it right

Answer:

pretty sure its B

Step-by-step explanation: