17 protons, 18 electrons
Express your answer as an ions

Answer:

juvn hgf   jb ujvi i  junk food sux

Explanation:

Answer:

Mathematical Literacy refers to the ability to reason with quantitative expressions in comparative, proportional and percentage terms. It is this definition that most lends itself to an examination of skill levels across Canada's education system - which ones are required for success in society (in the simplest sense) and which ones are superfluous.

*ANSWER MADE BY AN AI*

Answer: The molarity of iodide ions in given solution is 0.181 M.

Explanation:

Given: Mass = 1.97 g

Volume = 34.2 mL (1 mL = 0.001 L) = 0.0342 L

Molar mass of \(ZnI_{2}\) = 319.22 g/mol

Moles is the mass of substance divided by its molar mass. Hence, moles of \(ZnI_{2}\) are calculated as follows.

\(Moles = \frac{mass}{molar mass}\\= \frac{1.97 g}{319.22 g/mol}\\= 0.0062 mol\)

Molarity is the number of moles of a substance present in liter of a solution.

So, molarity of given solution is calculated as follows.

\(Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.0062 mol}{0.0342 L}\\= 0.181 M\)

Thus, we can conclude that molarity of iodide ions in given solution is 0.181 M.

The solution has a molarity of 0.0924 M.

The number of moles of solute per litre of solution is known as molarity.. For instance, water is both the solution and the solute when table salt is dissolved in it. Each mole of sodium chloride weighs 58.44 grammes. 58.44 grammes of sodium chloride are dissolved in one litre of water to produce one molar solution, or 1M.

Moles of solute per litre of solution is known as molarity (M).

Given: moles of NH3 = 0.355, volume of solution = 3.84 L

Molarity = 0.355 moles / 3.84 L = 0.0924 M

Therefore, the molarity of the solution is 0.0924 M.

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Answer:

uhhhh rephrase that please lol

Answer: this is the correct answer :)

Explanation:

Image shows ;)

The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Answer:

34^8

Explanation:

The arrow in a chemical equation represents the direction of the reaction. It indicates the conversion of reactants into products. The arrow points from the reactant side to the product side, symbolizing the flow of the reaction.

The purpose of the arrow is to visually represent the chemical transformation occurring in the reaction. It shows the relationship between the reactants and products and the direction in which the reaction proceeds. The arrow implies that the reactant molecules are being rearranged and transformed into new substances with different properties.

Chemical equations are used to describe the stoichiometry and balance of reactions. The arrow helps convey this information by illustrating the overall process taking place. It serves as a crucial element in understanding the reaction's composition, reaction conditions, and the substances involved.

Furthermore, the arrow also implies that the reaction can occur in both directions. In reversible reactions, the arrow can be represented as a double-headed arrow, indicating that the reaction can proceed in either direction depending on the conditions.

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Answer:

nitrogen

Explanation:

The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere. Why do I care?

nitrogen is the most abundant gas in the atmosphere

The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

Considering the ideal gas law, the volume occupied by 3.25 moles of an ideal gas at a temperature of 18.00°C is 686.71 L.

An ideal gas is the behavior of those gases whose molecules do not interact with each other and move randomly. Under normal conditions and under standard conditions, most gases exhibit ideal gas behavior.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T), related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

In this case, you know:

Replacing in the ideal gas law:

1.13 atm×V = 3.25 mol× 0.8205 L.atm/K.mol× 291 K

Solving:

V = (3.25 mol× 0.8205 L.atm/K.mol× 291 K)÷ 1.13 atm

V= 686.71 L

Finally, the volume is 686.71 L.

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The final volume V₂=4.962 L

Given

T₁=20 + 273 = 293 K

P₁= 1 atm

V₁ = 4 L

T₂=100+273 = 373 K

P₂=780 torr=1,02632 atm

Required

The final volume

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

V₂=(P₁V₁T₂)/(P₂T₁)

V₂=(1 x 4 x 373)/(1.02632 x 293)

V₂=4.962 L

At STP, 4.00 L of a pure gaseous substance has a mass of 10.0 grams. The molecular weight of this substance is is 56 g/mol.

The ideal gas equation is here:

P V = n RT

where,

P = pressure = 1 atm

V = volume = 4 L

R = 0.082 L atm  /K mol

T = temperature = 273 K

n = (1 × 4 ) / (0.082 × 273)

n = 0.178 mol

mass = 10 g

molecular weight  = moles / mass

                                = 10 / 0.178

                                = 56 g/mol

Thus, At STP, 4.00 L of a pure gaseous substance has a mass of 10.0 grams. The molecular weight of this substance is is 56 g/mol.

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The number of breadths supplied by the 200 atm scuba tanks, found using Boyle's law, taking the air as an ideal gas are as follows;

First tank with 14.2 L volume delivers 1,893.\(\overline 3\) breadths of air

The second tank with 11.4 L volume, delivers 1,520 breadths of air

An ideal gas is a gas that is not subject to particle to particle interactions, and consists of many particles

The given parameters are;

Pressure air in the two scuba tanks, P₁ = 200 atm

Volume of air in the first tank, V₁₁ = 14.2 L

Volume of air in the second scuba tank, V₁₂ = 11.4 L

Volume of air delivered for each breadth, Vₐ = 1.5 L

Pressure of air delivered by the tank regulator, P₂ = 1 atm.

According to Boyle's law, at constant temperature, the pressure  of a given mass of gas is inversely proportional to its volume

Mathematically, we have;

P ∝ V

P₁·V₁ = P₂·V₂

The volume occupied by a given number of breadths, n, Vₙ = Vₐ × n

According to Boyle's law, the number of breadths supplied by the first tank is therefore;

P₁·V₁₁ = P₂·Vₐ·n

Which gives;

\(n = \dfrac{P_1\cdot V_{11}}{P_2 \cdot V_a}\)

Therefore;

\(n = \dfrac{200\times 14.2}{1 \times 1.5}\approx 1893.\overline 3\)

The number of breadths supplied by the first tank is 1,893.\(\overline 3\) breadths

Similarly, the number of breadths supplied by the second tank is given by the formula;

P₁·V₁₂ = P₂·Vₐ·n

\(n = \dfrac{P_1\cdot V_{12}}{P_2 \cdot V_a}\)

\(n = \dfrac{200\times 11.4}{1 \times 1.5}\approx 1893.\overline 3 = 1,520\)

The number of breadths supplied by the second tank is 1,520 breadths

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Answer:

Ammonia

Explanation:

Answer:

nitrogen trihydride

Explanation: correct on edge

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

0.17 atm

Explanation:

Raoult´s law can be applied in solving this problem:

Pa= XaPºa   (a= acetyl bromide in this case)

where Pa = partial pressure acetyl bromide

         Xa = mole fraction of acetyl bromide in the solution

          Pºa=  vapor pressure of pure acetyl bromide = 0.75 atm(given)

Hence we can find the mole fraction of the acetone in the mixture:

Let the number of moles of acetone be a and the number of moles of thiophene be t

Xa = mol of a / ( mol of a + mol of t )        

We now have;

Molar Weight of  a= 112.95 g/mol  

number of moles of a = 51.8 g/mol x 1 mol/122.95 g  =  0.42 moles

Molar Weight of t = 84.14 g/mol  

number of moles of  t = 123 g x  1mol/84.14 g= 1.46 mol

mole fraction of a; Xa = 0.42/ (0.42 + 1.46) = 0.22

Pa = 0.22 x 0.75 atm = 0.17 atm

The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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Answer:

0.877 mL

Explanation:

The box's density would be the ratio of the mass of the box and its volume
which is, (23.23/26.5) mL
or, 0.8766 mL
We must round this down to 3 significant figures,
which will be 0.877 mL

The two major components making up at least 3% each of the human body are magnesium and nitrogen.

Magnesium makes up about 2.4% of the body, while nitrogen makes up about 3.2%. Oxygen, selenium, and cobalt make up smaller percentages of the body, with oxygen making up about 65%, selenium making up 0.19%, and cobalt making up 0.0012%.

Carbon usually forms four single covalent bonds, while hydrogen typically forms one single covalent bond. Therefore, the answer for carbon:hydrogen is 4:1.

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The volume of solution needed if I need to make 2.5 L of a 0.2 M fruit drink solution from the 0.7 M drink solution is 0.714L.

The concentration of a solution can be calculated using the following formula;

McVc = MdVd

According to this question, one needed to make 2.5 L of a 0.2 M fruit drink solution from the 0.7 M drink solution. The final volume needed is as follows:

2.5 × 0.2 = 0.7 × V

0.5 = 0.7V

V = 0.714L

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