A 0.150 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder that has inside radius 5.50 cm. The level of the glycerin is well below the top of the cylinder. Part A If the ice completely melts, by what distance does the height of liquid in the cylinder change

Answers

Answer 1

The question is incomplete. Here is the complete question.

A 0.150 kg cube fo ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.10 cm. The level of the glycerine is well below the top of the cylinder.

Part A

If the ice completely melts, by what distance does the height of liquid in the cylinder change? Express your answer with the appropriate units.

Part B

Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerine before the ice melted?

Answer: Part A: \(\Delta h=\) 327 mm

              Part B: Rise

Explanation: When an object is submerged on a fluid, the fluid exerts a upward force on the object called Buoyant Force. It can be calculated by the following relation:

\(B=\rho_{fluid}gV\)

Part A

Because the ice cube is floating on glycerin, its forces are on equilibrium, which means buoyant and weight are equal:

\(\rho_{fluid}gV=mg\)

Density of glycerine is 1260 kg/m³.

Volume of a cylinder is \(V=\pi.r^{2}.h\)

Solving

\(\rho_{fluid}gV=mg\)

\(\rho_{g}.V=m\)

\(\rho_{g}.\pi.r^{2}.h_{1}=m\)

\(h_{1}=\frac{m}{\rho_{g}.\pi.r^{2}}\)

\(h_{1}=\frac{0.15}{1260.\pi.(0.055)^{2}}\)

\(h_{1}=1.25\) m

After melted, the volume of a mass of water created is

\(\rho_{w}=\frac{m}{V}\)

\(V=\frac{m}{\rho_{w}}\)

Density of water is 10³ kg/m³.

\(\pi.r^{2}.h_{2}=\frac{m}{\rho_{w}}\)

\(h_{2}=\frac{m}{\rho_{w}.\pi.r^{2}}\)

\(h_{2}=\frac{0.15}{1000.(0.055)^{2}.\pi}\)

\(h_{2}=\) 1.58 m

The change in heights is

\(\Delta h=h_{2}-h_{1}\)

\(\Delta h=\) 0.327 m

The distance by which the height of liquid in the cylinder change is 327mm.

Part B:

Water has more density than ice. So, when melted, water will take the place of glycerin more than ice and so, liquid will rise on the cylinder.


Related Questions

13. What bone runs parallel to the fibula?
A. Radius
B. Femur
C. Tibia
D. Ulna

Answers

Answer:

C. Tibia :)

Explanation:

The fibula is the long, thin bone of the lower leg. It runs parallel to the tibia (aka shin bone) and plays a role in stabilizing the ankle and supporting the muscles of the lower leg

What are the different ways the body senses its surroundings?​

Answers

Answer: Smell, touch, feel, look.

Explanation:

please help, i’ll give brainliest!a cheetah, the fastest animal on earth, can run to a maximum speed of 88.1 ft/s. how fast is this in kph? explain your answer with solution.

Answers

Answer:

96.67 kph

Explanation:

To convert 88.1 ft/s to kph (kilometer per hour), we will use the following relationships:

1 km = 3280.84 ft

1 hour = 3600 seconds

Then, 88.1 ft/s is equivalent to:

\(88.1\frac{ft}{s}\times\frac{1\operatorname{km}}{3280.84\text{ ft}}\times\frac{3600s}{1hour}=96.67\frac{\operatorname{km}}{h}\)

Therefore, 88.1 ft/s is equal to 96.67 kph

Compare and contrast the accuracy of eyewitness accounts to the actual events

Answers

Answer: hope it helps

We routinely share first-person accounts of what we've seen or heard ... Accidental eyewitnesses to daily events, ranging from the mundane ... System variables, by contrast, are those that can be controlled by the ... Comparing the diagnostic accuracy of suspect identifications made by actual eyewitnesses ...

Explanation:

what is the value of 3 in
24.635​

Answers

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

What is Place Value?The value of each digit in a number is known as place value.For example the 2 in 125 represent 2 tens or 20, however the 2 in 2103 represent 2 thousands or 2000.Frequently, they will only include the letters like Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, tenths, hundredths, and so on to denote each place.

How to solve this question?

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

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Question 1 of 20:
Select the best answer for the question.
1. What's an example of being proactive in your workouts?
A. Wearing appropriate running shoes for your environment
O B. Choosing to use the next available cardio machine
O C. Going on a run without planning your path ahead of time
O D. Working out twice as long as expected since you're not fatigued
O Mark for review (Will be highlighted on the review page)

Answers

A. Wearing appropriate running shoes for your environment is an example of being proactive in your workouts.

What are the ways of becoming proactive in workouts?

There are several ways to become proactive in workouts:

(1) Set specific goals: Setting specific and measurable fitness goals can help you stay focused and motivated. It can also help you track your progress and make necessary adjustments to your workout routine.

(2) Plan your workouts: Planning your workouts ahead of time can help you stay organized and committed to your fitness routine. This can include scheduling your workouts in advance and creating a workout plan that targets your specific goals.

(3) Track your progress: Tracking your progress can help you stay motivated and see how far you've come. This can include keeping a workout journal, taking progress photos, or using a fitness tracker.

(4) Stay consistent: Consistency is key when it comes to achieving fitness goals. Set a regular workout schedule and stick to it as much as possible.

(5) Listen to your body: Pay attention to how your body feels during and after workouts. If something doesn't feel right, make adjustments or seek guidance from a fitness professional.

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write down the value of

920 kg in g

Answers

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Why are the noble gases the least reactive elements?

Answers

because they have eight valence electrons, which fill their outer energy level.

The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds 
3)Is there any time interval in which no force acts on object.Justify

The velocity time graph of an object mass 50 g is shown in figure study graph and answer1)calculate force

Answers

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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A centigrade and fahrenheit thermometer are placed in hot water. The water is cooled. What fall of temperature will the fahrenheit thermometer register when the centigrade thermometer registers the fall in temperature as 45 degrees?​

Answers

Explanation:

Answer is explained in the above image.

A centigrade and fahrenheit thermometer are placed in hot water. The water is cooled. What fall of temperature

What is the difference between human caused Climate Change and natural
climate cycles?

Answers

Human caused climate change is climate change caused by human made creations such as cars, trucks, factories, and plastic in oceans these all are causing the ozone layer to deteriorate. And natural climate change cycles is any change occurring to the planet's climate either permanently or lasting for long periods of time.

A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?

A.) 31 meters/second

B.) 38 meters/second

C.) 44 meters/second

D.) 55 meters/second

Answers

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

A ball is projected at an angle of 53. If the initial velocity is 48 meters/second, what is the vertical

You use a ruler marked with 1 mm increments to measure the lengths of the height h of a block and find h = 121 mm. According to the half least count rule, what is the uncertainty in your measurement of the height?

Answers

The uncertainty in height is, 0.5 mm.

The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.

Using the half least count rule, the uncertainty in the measurement of the height is,

uncertainty = 1/2 * 1 mm = 0.5 mm

Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,

h = 121 ± 0.5 mm

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A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of 0.060 m/s. After 1.1 minutes, the finch tires of the tortoise's slow pace, and takes flight in the same direction for another 1.5 minutes at 11 m/s. Part A What was the average speed of the finch for this 2.6-minute interval

Answers

Answer:

Average Speed = 6.37 m/s

Explanation:

The average speed is simply given by the following formula:

Average Speed = Total Distance Traveled/Total Time Spent

here,

Total Time Spent = 1.1 min + 1.5 min = (2.6 min)(60 s/min) = 156 s

Now, for total distance, we have to calculate the distance traveled on tortoise and distance traveled while flying, separately. Therefore,

Distance Traveled on Tortoise = (Time spent on Tortoise)(Speed of Tortoise)

Distance Traveled on Tortoise = (1.1 min)(60 s/min)(0.06 m/s) = 3.96 m

Similarly,

Flying Distance = (Flying Time)(Flying Speed) = (1.5 min)(60 s/min)(11 m/s)

Flying Distance =  990 m

Since, total distance is the sum of both distances, therefore,

Total Distance = 3.96 m + 990 m = 993.96 m

Now, using the values in equation of average speed, we get:

Average Speed = 993.96 m/156 s

Average Speed = 6.37 m/s

Luka Doncic throws a ball from a 3-point line distance (6.75 m). The basket is at height
3.05 m. The ball leaves his hands at height 2.80 m at an angle of 45◦ and velocity 8.3 m/s.
Will he score the 3 points?

Answers

Luka Doncic will score the 3 points if he throws a ball from a 3-point line distance (6.75 m) and if the basket is at height of 3.05 m.

Resolving u into its vertical and horizontal components

ux = u cos θ

ux = 8.3 cos 45°

ux = 5.9 m / s

uy = u sin θ

uy = 8.3 sin 45°

uy = 5.9 m / s

H = 3.05 - 2.8

H = 0.25 m

T = uy + √ uy² - 2 g H / g

T = 5.9 + √ 5.9² - ( 2 * 9.8 * 0.25 ) / 9.8

T = 5.9 + √ 34.81 - 4.9 / 9.8

T = 5.9 + 5.47 / 9.8

T = 11.37 / 9.8

T = 1.16 s

R = ux T

R = 5.9 * 1.16

R = 6.8 m

Distance of three point line from the basket = 6.75 m = 6.8 m = R

Therefore, Luka Doncic will score the 3 points

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What is the difiniton of absolute value in science

Answers

Answer: The absolute value of a number is symbolized by two vertical lines as 3 or -3

Please pick me as brainliest please

Answer: the magnetic of a real number without regard to its sign

Explanation: In mathematics, the absolute value or modulus of a real number x, denoted |x| or, is the non-negative value of x without regard to its sign. Namely, |x| = x if x is positive, and |x| = −x if x is negative, and |0| = 0. For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3

Which optical instrument produces a magnified, virtual, and inverted image of small objects?1) a refracting telescope2) a single lens reflex camera3) a microscope4) a pair of binoculars

Answers

Answer:

Microscope

Explanations:

Microscopes are known for magnifying tiny objects

The images produced by a microscope are:

virtual (formed behind the screen)

Inverted

Magnified or enlarged

Therefore, the optical instrument which produces a magnified, virtual, and inverted image is the microscope

Spectra are like the barcodes used at the supermarket checkout; each pattern can be scanned to provide information about the star. The main reason spectra of different stars are different is that the stars have different surface __________. While we know that each _________ leaves a different pattern in the spectrum, mostly the stars have roughly similar ___________, with only a few exceptions. The most common element in all stars is _____________. Astronomers use the patterns in the spectra of stars to sort all stars into categories called ___________; the hottest stars are given the letter __. Objects which are not hot enough for hydrogen fusion to take place in their cores are called ___________.

Answers

The main reason spectra of different stars are different is that the stars have different surface temperatures.

Spectra are like the barcodes used at the supermarket checkout; each pattern can be scanned to provide information about the star. The main reason spectra of different stars are different is that the stars have different surface _temperatures_________.

While we know that each _element________ leaves a different pattern in the spectrum, mostly the stars have roughly similar _compositions__________, with only a few exceptions.

The most common element in all stars is ___Hydrogen__________. Astronomers use the patterns in the spectra of stars to sort all stars into categories called _Spectra class_________

the hottest stars are given the letter _O_. Objects which are not hot enough for hydrogen fusion to take place in their cores are called ___Brown Dwarfs.________.

In physics astronomy,  spectral lines of a star are formed  when the light  from the inner parts of the star bombards  the elements in its atmosphere.The hottest stars are given the letter O while the cooler stars are noted with M.

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Help me please!!!!!!!!!!

Help me please!!!!!!!!!!

Answers

The velocity of the ball just before it hits the ground is 14.0 m/s

Let's solve the problem using the given equation:

\(v^2 = u^2 + 2as\)

We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.

Plugging in the given values, we get:

v^2 = 0 + 2(9.81)(10)

v^2 = 196.2

Taking the square root of both sides, we get:

v = sqrt(196.2)

v = 14.0 m/s

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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)

Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--

If the acceleration of the body is towards the center, what is the direction of the unbalanced force ? Using a complete sentence , describe the direction of the net force that causes the body to travel in a circle at a constant speed.

Answers

Accelerating objects are changing their velocity. Velocity is often thought of as an object's speed with a direction. Thus, objects which are accelerating are either changing their speed or changing their direction. They are either speeding up, slowing down or changing directions. Changing the velocity in any one of these three ways would be an example of an accelerated motion.

fill in the blank. refer to the problem which reads: a test specimen in a tensile test has a gage length of 2.0 ___ for this problem, fracture occurs at a gage length of 2.92 in. determine the percent elongation.

Answers

A test specimen in a tensile test has a gage length of 2.0 inches for this problem, fracture occurs at a gage length of 2.92 in. determine the percent elongation.

Percent elongation is a measure of the deformation or stretching of a material before it fractures. Calculated as percentage increase in length of a material sample after it has been subjected to a tensile test .The formula for percent elongation is:

Percent Elongation = (Final Gauge Length - Original Gauge Length) / Original Gauge Length x 100%

% Elongation = (2.92 in - 2.0 in) / 2.0 in x 100

% Elongation = 46%

Therefore, the percent elongation is 46%.

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The star Antares has an apparent magnitude (brightness) of 1.0, whereas the star Procyon has an apparent magnitude of 0.4.

a.) From just the information above, can you determine which star is more luminous? If yes, which one? If no, why not?

b.) The absolute magnitude (brightness) of Antares is -5.28, and the absolute magnitude of procyon is 2.68. Which star is more luminous Which star is closer?

Answers

Answer:

Below

Explanation:

The LOWER ( or more negative) the APPARENT magnitude the brighter the sky-object is to observer on earth ....so Procyon (part of the Winter Hexagon)  is brighter of the two in the night sky.

At an EQUAL DISTANCE from earth Antares would appear MUCH brighter than Procyon so it must be much further from Earth than Procyon .

   Procyon is closer.   Antares is brighter (absolute mag is lower).

(As a 'Internet check' :    Procyon is 11.45 light years away from Earth and Antares is 554.5 light years away)

A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:

a. the force at the support point
b. the force at the left-hand end.

Answers

Answer:

\(F_l=1140N\)

Explanation:

From the question we are told that:

Length\(l=3.00m\)

Support distance \(d=1.00m\)

Weight of diver \(W_d=500N\)

Weight of board \(W_b=280N\)

Generally the equation for Total Torque is mathematically given by

 \(F_T=W_d-W_b\)

 \(F_T=F_d-f_b\)

 \(F_T=-280-500\)

 \(F_T=-780\)

 \(F_T=780\)

Since we consider the horizontal axis

 \(\sum Y=0\)

 \(Fs-(\frac{1}{2}l*w_b)-(l-w_d)\)

 \(Fs-1.5*280-3*300=0\)

 \(F_s=1920N\)

Therefore  the force at the support point  1.00m from the force at the left-hand

 \(F_l=F_s-F_l\)

 \(F_l=1920-780\)

 \(F_l=1140N\)

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from mars to the sun, then calculate it

Answers

The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * \(10^{8}\) km

P² = a³

P = Orbital period

a = Average distance

P = 1.88 years

a³ = 1.88²

a³ = 3.53

a = 1.52 AU

a = 1.52 * 1.496 * \(10^{8}\) km

a = 2.27 * \(10^{8}\) km

The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * \(10^{8}\) km

Therefore, the average distance from mars to the sun is 2.27 * \(10^{8}\) km

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Which diagram models the position of a soccer ball when it has the greatest amount of gravitational potential energy?

Which diagram models the position of a soccer ball when it has the greatest amount of gravitational potential

Answers

Answer:

C

Explanation:

Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.

We must remember that potential energy is defined as the product of mass by gravity by height

Ep = m*g*h

where:

m = mass [kg]

g = gravity acceleration [m/s²]

h = elevation [m]

So when we have a great value for h in the above equation, we will have a big value for potential energy.

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O is

Answers

The point through which this ray will pass, after refraction by the lens is point D.

What is refraction of light?

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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what is it called when electrons flow in one direction?
A) Parallel Circuit
B) Conductor
C) Series Circuit
D) Insulator

Answers

It’s C series circuit because they let electrons flow freely.

Assuming birdman flies at a height of 78m, how fast should birdman fly to hit the bucket if the bucket is placed 75m from the start of the field?

Answers

The speed of how fast the birdman should be to hit the bucket is 18.8 m/s

The only force acting on the height at which birdman flies is the gravitational force field.

Suppose the initial velocity (u) is parallel to the ground when the time (t) hits the ground.

Then, we can use the second equation of motion to determine the time (t) when the bird hits the ground.

\(\mathbf{S = ut + \dfrac{1}{2}gt^2}\)

\(\mathbf{78 \ m =(0)t + \dfrac{1}{2}(9.8)t^2}\)

\(\mathbf{78 \ m =4.9 t^2}\)

\(\mathbf{t^2 = \dfrac{78 \ m}{4.9 m/s^2} }\)

\(\mathbf{t^2 = 15.918 \ s^2}\)

\(\mathbf{t =\sqrt{ 15.918 \ s}}\)

\(\mathbf{t =3.989\ s}}\)

Now, the speed of how fast the birdman should be to hit the bucket can be determined using;

\(\mathbf{Speed = \dfrac{Distance}{Time}}\)

\(\mathbf{Speed = \dfrac{75 \ m }{3.989\ s}}\)

\(\mathbf{Speed = 18.8 m/s}\)

Therefore, we can conclude that the speed of how fast the birdman should be to hit the bucket is 18.8 m/s

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Artificial satellites in space can help you find locations on
Earth. True or false?

Answers

yes the answer is true

Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.​

Answers

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

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