A cyclist bikes a certain distance in 25 minutes. how long would it take a pedestrian to travel the same distance if he travels 2 2/5 times slower than the cyclist?answer = ___________ minutes and ___________ hours.

Answer:

BC would be 8.

Step-by-step explanation:

40 x 0.2 = 8

(Try graphing on a number line)

Answer:

b

Block B has the greatest density.

Step-by-step explanation:

density = mass/volume

volume = length × width × height

All blacks have the dimensions 7 cm by 3 cm by 1 cm, so the 3 volumes are equal.

Since density = mass/volume, and the volumes are equal, the block with the highest mass has the highest density.

Since all the masses are different, all densities are different.

Answer: Block B

The velocity of the ball at t = 2 is as follows: v(2) = lim t→2 (−16t14)(t − 2) /(t − 2) = -224.

A limit is a mathematical concept that represents the value a function or sequence approaches as the input or index approaches some value or approaches infinity or negative infinity. It may be a single real number or ± infinity, depending on the behavior of the function around the limit point.

Here are the steps for evaluating a limit by factoring:

1: Use algebraic techniques to simplify the expression and cancel out any common factors.

2: Substitute the limiting value of the function. Use direct substitution if possible.

3: If the denominator equals zero after substitution, factor the numerator and denominator, then cancel out any common factors.

4: Use the properties of limits to simplify the expression and evaluate it.

The velocity of the ball at t = 2 is as follows: v(2) = lim t→2 (−16t14)(t − 2) /(t − 2) = -224.

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Answer:

6. xint=-7

    yint=-3

7. xint=-7

yint=-5

Step-by-step explanation:

Answer:

6. (-7,-3)

7. (-7,-6)

Them are the coordinates

The cost of the camera after Natalie uses the coupon is $38.25

Given data in the question;

Natalie uses a 15% off coupon when she buys a camera.

To determine the final price;

Since the coupon is 15% off, that means there is a reduction of 15% off the original price;

Hence

New price = ( 100% - 15% ) × Original price

New price = ( 100% - 15% ) × $45.00

New price = ( 85% ) × $45.00

New price = 0.85 × $45.00

New price = $38.25

Therefore, the new price of camera is $38.25.

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Answer:

3a-27

Step-by-step explanation:

Distribute the 3

3 x a is 3a

3 x 9 is 27

To find the volume of the object, we can integrate the areas of the cross sections perpendicular to the y-axis along the given interval.

First, let's find the limits of integration by setting the two equations for the base equal to each other and solving for y:

-x = y^2 - 26y + 186

Rewriting the equation as a quadratic equation:

y^2 - 26y + 186 + x = 0

This equation represents a parabola. We can find the y-values at the intersection points by using the quadratic formula:

y = (-b ± √(b^2 - 4ac)) / (2a)

For this equation, a = 1, b = -26, and c = 186 + x.

The discriminant, b^2 - 4ac, is given by:

D = (-26)^2 - 4(1)(186 + x) = 676 - 744 - 4x = -68 - 4x

Since we want to find the y-values where the parabola intersects, we need to find the values of x where the discriminant is greater than or equal to 0:

-68 - 4x ≥ 0

-4x ≥ 68

x ≤ -17

Therefore, the limits of integration for x are from -∞ to -17.

Now, we can find the area of each cross section perpendicular to the y-axis. Given that each cross section is a semi-circle, the area of a cross section at a particular y-value will be:

A(y) = (1/2) * π * r^2

where r is the radius of the semi-circle. The radius, in this case, is the difference between the x-values of the two curves:

r = (y^2 - 26y + 186) - (-(y^2 + 2y + 160)) = y^2 - 26y + 186 + y^2 + 2y + 160 = 2y^2 - 24y + 346

The volume of the object is then given by integrating the area function with respect to y over the given interval:

V = ∫[a,b] A(y) dy = ∫[a,b] (1/2) * π * (2y^2 - 24y + 346)^2 dy

where a and b are the limits of integration for y, which we still need to determine.

To find the limits of integration for y, we need to solve the quadratic equation for y:

x = -(y^2 + 2y + 160)

y^2 + 2y + (x + 160) = 0

Using the quadratic formula:

y = (-2 ± √(2^2 - 4(x + 160)))/(2) = (-2 ± √(4 - 4(x + 160)))/(2) = (-2 ± √(-4x - 636))/(2) = -1 ± √(-x - 159)

Since the limits of integration are perpendicular to the y-axis, we consider the y-values that correspond to the endpoints of the base.

Therefore, the limits of integration for y are -1 - √(-x - 159) and -1 + √(-x - 159).

Finally, we can now evaluate the integral:

V = ∫[-∞, -17] (1/2) * π * (2y^2 - 24y + 346)^2 dy

This integration requires further algebraic simplification and evaluation.

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Answer:

tell me if im wrong but. 45?

Step-by-step explanation:

Answer:

Step-by-step explanation:

it should add up to 360°

360=135 + 120 + 7x-64+5x-4+3x+31+4x+15+6x-8     (seems like too much huh)

360=225+25x  ( much better just add the x terms and the constants together)

135 = 25x  ( just subtract 225 from each side of the equation)

5.4 = x  ( divide 135 by 25 )

there is one tangent line to the curve y = x/(x+2) that passes through the point (1, 2), and it touches the curve at the point (-2, -1).

To find the number of tangent lines to the curve y = x/(x+2) that pass through the point (1, 2), we need to determine the points on the curve where the tangent lines touch.

First, let's find the derivative of the curve to find the slope of the tangent lines at any given point:

y = x/(x+2)

To find the derivative dy/dx, we can use the quotient rule:

\(dy/dx = [(1)(x+2) - (x)(1)] / (x+2)^2\)

      \(= (x+2 - x) / (x+2)^2\)

     \(= 2 / (x+2)^2\)

Now, let's substitute the point (1, 2) into the equation:

\(2 / (1+2)^2 = 2 / 9\)

The slope of the tangent line passing through (1, 2) is 2/9.

To find the points on the curve where these tangent lines touch, we need to find the x-values where the derivative is equal to 2/9:

\(2 / (x+2)^2 = 2 / 9\)

Cross-multiplying, we have:

\(9 * 2 = 2 * (x+2)^2\)

\(18 = 2(x^2 + 4x + 4)\)

\(9x^2 + 36x + 36 = 18x^2 + 72x + 72\)

\(0 = 9x^2 + 36x + 36 - 18x^2 - 72x - 72\)

\(0 = -9x^2 - 36x - 36\)

Simplifying further, we get:

\(0 = 9x^2 + 36x + 36\)

Now, we can solve this quadratic equation to find the values of x:

Using the quadratic formula, x = (-b ± √(\(b^2\) - 4ac)) / (2a), where a = 9, b = 36, c = 36.

x = (-36 ± √(\(36^2\) - 4 * 9 * 36)) / (2 * 9)

x = (-36 ± √(1296 - 1296)) / 18

x = (-36 ± 0) / 18

Since the discriminant is zero, there is only one real solution for x:

x = -36 / 18

x = -2

So, there is only one point on the curve where the tangent line passes through (1, 2), and that point is (-2, -1).

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There are two tangent lines to the curve y=x/(x+2) that pass through the point (1,2) and they touch at points (0,0) and (-4,-2). This was determined by finding the derivative of the function to get the slope, and then using the point-slope form of a line to find the equation of the tangent lines. Solving the equation of these tangent lines for x when it is equalled to the original equation gives the points of tangency.

To find the number of tangent lines to the curve y=(x)/(x+2) that pass through the point (1,2), we first find the derivative of the function in order to get the slope of the tangent line. The derivative of the given function using quotient rule is:

y' = 2/(x+2)^2

Now, we find the tangent line that passes through (1,2). For this, we use the point-slope form of the line, which is: y- y1 = m(x - x1), where m is the slope and (x1, y1) is the point that the line goes through. Plug in m = 2, x1 = 1, and y1 = 2, we get:

y - 2 = 2(x - 1) => y = 2x.

Now, we solve the equation of this line for x when it is equalled to the original equation to get the points of tangency.

y = x/(x+2) = 2x => x = 0, x = -4

So, there are two tangent lines that pass through the point (1,2) and they touch the curve at points (0,0) and (-4, -2).

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Answer:

sin θ = 22.62°

cos θ = 22.62°

tan θ = 22.62°

Step-by-step explanation:

From the diagram above

Opposite = 5

Adjacent = 12

Hypotenuse = 13

a) sin θ = Opp/Hypotenuse

sin θ = 5/13

sin θ = 0.3846153846

arc sin 0.3846153846

= 22.619864948°

Approximately = 22.62°

b) cos θ = Adjacent/ Hypotenuse

θ = 12/13

= arccos(0.9230769230769231)

22.619864948°

Approximately = 22.62°

c) tan θ = Opposite/Adjacent

θ = 5/12

= arctan(0.4166666666666667)

= 22.619864948°

= 22.62°

Answer:

the amount of pages (p) required to break even as the office store

The solution of the given initial value problem using Laplace Transform is:

y(t) = -4 cos (7t) + (1/7) sin (7t)

The given initial value problem is, y′′+7y′=0

y(0)=−4,

y′(0)=1

First, using Y for the Laplace transform of y(t), i.e.,

Y=L{y(t)}, find the equation you get by taking the Laplace transform of the differential equation =(0).

The Laplace transform of y′′ + 7y′ is as follows:

L(y′′ + 7y′) = L(0)y''(t) + 7y'(t)

                = s² Y(s) - s y(0) - y'(0) + 7 (s Y(s) - y(0))

                = s² Y(s) - 4s + 1 + 7sY(s) - 7(4) Y(s)

                = s² Y(s) + 7s Y(s) - 29 Y(s)

                = (s² + 7s) Y(s) - 29

                = 0

Y(s)=A​/s+a+B/s+b​

where a < b.

Substitute Y(s) as follows:

(s² + 7s) Y(s) - 29 = 0

=> Y(s) = 29 / (s(s + 7))

Now the partial fraction decomposition of Y(s) can be given as:

Y(s) = A / s + B / (s + 7)

Multiplying both sides by s(s+7),

we get, 29 = A(s+7) + Bs

Equating s = 0, we get, 29 = 7BSo, B = 29 / 7

Equating s = -7, we get, 29 = -7A

Therefore, A = -29 / 7

Thus, Y(s) = -29 / (7s) + 29 / (7s+49)

The solution of the initial value problem using the Laplace transform is given as, y(t) = -29/7 + 29/7 e^(-7t)

Therefore, the solution of the given initial value problem using Laplace Transform is:y(t) = -4 cos (7t) + (1/7) sin (7t)

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a) approximately 500 boxes. b) The reorder point is approximately 76 boxes. c) approximately 8 orders d) total annual cost is approximately $9,059.63 e) approximately $9,003.38

a. Economic Order Quantity (EOQ):

The Economic Order Quantity (EOQ) can be calculated using the formula:

EOQ = sqrt((2 * D * S) / H)

Where:

D = Annual demand

S = Ordering cost per order

H = Holding cost per unit per year

Annual demand (D) = 325 boxes per month * 12 months = 3,900 boxes

Ordering cost per order (S) = $18.00

Holding cost per unit per year (H) = 0.25 * $2.25 = $0.5625

Substituting the values into the EOQ formula:

EOQ = sqrt((2 * 3,900 * 18) / 0.5625)

   = sqrt(140,400 / 0.5625)

   = sqrt(249,600)

   ≈ 499.6

b. Reorder Point (assuming no safety stock):

The reorder point can be calculated using the formula:

Reorder Point = Lead time demand

Lead time demand = Lead time * Average daily demand

Lead time = 7 days

Average daily demand = Annual demand / Working days per year

Working days per year = 360

Average daily demand = 3,900 boxes / 360 days

                    ≈ 10.833 boxes per day

Lead time demand = 7 * 10.833

               ≈ 75.83

c. Number of Orders-per-Year:

The number of orders per year can be calculated using the formula:

Number of Orders-per-Year = Annual demand / EOQ

Number of Orders-per-Year = 3,900 boxes / 500 boxes

                        = 7.8

d. Total Annual Cost:

The total annual cost can be calculated by considering the ordering cost, holding cost, and the cost of the shoe boxes themselves.

Ordering cost = Number of Orders-per-Year * Ordering cost per order

             = 8 * $18.00

             = $144.00

Holding cost = Average inventory * Holding cost per unit per year

Average inventory = EOQ / 2

                = 500 / 2

                = 250 boxes

Holding cost = 250 * $0.5625

            = $140.625

Total Annual Cost = Ordering cost + Holding cost + Cost of shoe boxes

Cost of shoe boxes = Annual demand * Cost per box

                 = 3,900 boxes * $2.25

                 = $8,775.00

Total Annual Cost = $144.00 + $140.625 + $8,775.00

                = $9,059.625

e. If storage space weren't so limited, and the inventory holding costs were reduced to 15% of the unit cost:

To calculate the new total annual cost, we need to recalculate the holding cost using the reduced holding cost percentage.

Holding cost per unit per year (H_new) = 0.15 * $2.25

                                    = $0.3375

Average inventory = EOQ / 2

                = 500 / 2

                = 250 boxes

New holding cost =

Average inventory * Holding cost per unit per year

                = 250 * $0.3375

                = $84.375

Total Annual Cost (new) = Ordering cost + New holding cost + Cost of shoe boxes

Total Annual Cost (new) = $144.00 + $84.375 + $8,775.00

                      = $9,003.375

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Answer:

336

Step-by-step explanation:

120*3 is 360.

360= 24 + ___

360-24 is 336

Answer:

432

Step-by-step explanation:

24+__=120

      144*3

        =432

Hope This Helps, Have a great day!

Answer:

b^4

Step-by-step explanation:

you would just subtract the variables things

b^10-b^6

subtract 10-6 and keep the b

b^4 iis the answer we are learnng these in school right now

Answer:

b^10/b^6= b^4

Step-by-step explanation:

when dividing numbers with exponents, you have to subtract the numerator's exponent by the denominator's exponent to simplify the equation.

Answer:

he can play 12 games

Step-by-step explanation:

but he is gonna have some tokens left over.

Answer:

Please check the question.  I don't see information that tells us how long either must travel before reaching either home.  They are said to be going "in the same direction."  But there is no indication of when they reach Jess' home.  I might not understand the question, but I don't think Raj would drown his car and still make it.

Step-by-step explanation:

Raj lives 25.5 kilometers from Jess.

Given that,

Jess left her home and rode her bike along the road at a constant speed of 18km/h.

Raj left his home 10 minutes after Jess.

First, convert the time into hours,

Jess rode her bike for a total of 40 minutes, which is;

40/60 = 2/3 hours.

Since Raj left 10 minutes after Jess, he only drove for;

40 - 10 = 30 minutes,

which is 30/60 = 1/2 hours.

Now, the distance Jess traveled,

She rode her bike at a constant speed of 18 km/h for 2/3 hours. Therefore, the distance she traveled is:

Distance = Speed × Time

= 18 km/h × 2/3 hours

= 12 km.

Next, the distance Raj traveled,

He drove his car at a constant speed of 75 km/h for 1/2 hour.

Therefore, the distance he traveled is:

Distance = Speed × Time

= 75 km/h × 1/2 hours

= 37.5 km.

Since Raj overtook Jess, so subtract the distance Jess traveled from the distance Raj traveled to find out the number of kilometers from Jess Raj lives:

Distance from Jess = Distance Raj traveled - Distance Jess traveled

= 37.5 km - 12 km

= 25.5 km.

So, Raj lives 25.5 kilometers from Jess.

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We have expressed 3/5 + 2/3 as the ratio of two integers, 19 and 15. Since it can be expressed as a ratio of integers, we can conclude that it is rational.

To show that 3/5 + 2/3 is rational, we need to find a way to write it as a ratio of integers. To do this, we first need to find a common denominator for the two fractions. The least common multiple of 5 and 3 is 15, so we can rewrite the fractions as follows:

3/5 = 9/15

2/3 = 10/15

Now we can add the two fractions:

3/5 + 2/3 = 9/15 + 10/15

Combining the numerators, we get:

3/5 + 2/3 = 19/15

Therefore, we have expressed 3/5 + 2/3 as the ratio of two integers, 19 and 15.

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(a) The firm is operating in the long run, and its supply function is determined by the profit maximization condition.

(b) The firm's input demand functions can be derived from the profit function, and their degree of homogeneity is 1/2. Changes in input prices will impact the firm's input demand.

(c) The market supply function can be derived by aggregating the supply functions of all 40 firms operating in the market.

(d) Given the market conditions and demand function, the total market supply can be calculated.

(a) The firm is operating in the long run because it has the flexibility to adjust its inputs and make decisions based on market conditions. The firm's supply function is determined by maximizing its profit, which is achieved by setting the marginal cost equal to the market price. In this case, the supply function for each firm can be derived by taking the derivative of the profit function with respect to the price of output (p).

(b) The input demand functions for the firm can be derived by maximizing the profit function with respect to each input price. The degree of homogeneity of the input demand functions can be determined by examining the exponents of the input prices. In this case, the degree of homogeneity is 1/2. Changes in the input prices will affect the firm's input demand as it adjusts its input quantities to maximize profit.

(c) The market supply function can be derived by aggregating the individual supply functions of all firms in the market. Since there are 40 identical firms, the market supply function can be obtained by multiplying the supply function of a single firm by the total number of firms (40).

(d) To determine the total market supply, we substitute the given market conditions and demand function into the market supply function. By solving for the market quantity at a given market price, we can calculate the total market supply.

In conclusion, the firm is operating in the long run, and its supply function is determined by profit maximization. The input demand functions have a degree of homogeneity of 1/2, and changes in input prices impact the firm's input demand. The market supply function is derived by aggregating the individual firm supply functions, and the total market supply can be calculated using the given market conditions and demand function.

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The equation of the degree 6 polynomial with a root at 3, a double root at 2, and a triple root at -1, and y-intercept at y = 5 is given as follows:

y = -5/12(x - 3)(x - 2)²(x + 1)³.

The equation of the function is obtained considering the Factor Theorem, as a product of the linear factors of the function.

The zeros of the function, along with their multiplicities, are given as follows:

Then the linear factors of the function are given as follows:

The function is then defined as:

y = a(x - 3)(x - 2)²(x + 1)³.

In which a is the leading coefficient.

When x = 0, y = 5, due to the y-intercept, hence the leading coefficient a is obtained as follows:

5 = -12a

a = -5/12

Hence the polynomial is:

y = -5/12(x - 3)(x - 2)²(x + 1)³.

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Answer:

A

Step-by-step explanation:

So we have the equation:

\(-15=5a+12-2a+6\)

On the right combine like terms:

\(-15=5a-2a+12+6\\-15=3a+18\)

Subtract 18 from both sides. The right cancels:

\((-15)-18=(3a+18)-18\\-33=3a\)

Divide both sides by 3:

\((-33)/3=(3a)/3\\a=-11\)

The answer is A, -11.

Answer:

a = -11

Step-by-step explanation:

-15 = 5a +12- 2a + 6

Combine like terms

-15 = 3a +18

Subtract 18 from each side

-15-18 = 3a+18-18

-33 = 3a

Divide each side by 3

-33/3 = 3a/3

-11 =a

Answer: c=13/2 but as a fraction

Step-by-step explanation:

Answer:

c = 7

Step-by-step explanation:

-2c + 6 = -8

Subtract 6 from both sides

-2c = -14

Divide -2 by both sides

c = 7

The total electrostatic force on the third particle will be 56 N in -x direction.

q1 = +40 μC, x1 = -20 cm = - 0.2 m

q2 = -50 μC, x2 = 30 cm = 0.3 m

q = -4 μC, x = 0

We know that, the electrostatic force between two charges

F = kQ1Q2/d²

k = 9 × 10⁹ Nm²/C²

here, d: distance between two charges

F1 = k(40×10⁻⁶)(-4× 10⁻⁶)/(0.2)²

F1 = - 36 N {(-) sign shows the force is attraction force}

so, the direction of F1 on q is -x-direction

F2 = k(-50×10⁻⁶)(-4× 10⁻⁶)/(0.3)²

F2 = 20 N {Repulsive force because both particles are having negative charge}

so, the direction of F2 on q is in the -x-direction

So Total force F = F1+F2 = 20+36 = 56 N

Therefore, the total electrostatic force on the third particle will be 56 N in the -x direction.

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Square and rhombus have

4 equivalent sides

4 angles

2 pair of congruent sides

2 pair of parallel sides

Answer:

The answer is (39/2)-3=L.

Step-by-step explanation:

Answer:

There’s not

Step-by-step explanation:

It’s 618

Answer:

  C.  142°

Step-by-step explanation:

You want the angle between vectors u=3i+√3j and v=-2i-5j.

There are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:

  u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest

You can find the angles of the vectors individually, and subtract those:

  u = |u|∠α

  v = |v|∠β

  θ = α - β

When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:

  \(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)

This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.

A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.

__

Additional comment

The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.

The dot-product relation will work with 3D vectors as well as 2D vectors.

<95141404393>

Answer:

C. YZ/XZ=ST/RT

Step-by-step explanation:

If the 2 lines are parallel then the slopes should be equal. The slope is rise over run so C is the right answer.

Answer:

c

Step-by-step explanation: