A particle moves in a circle with radius 10 cm and with a uniform speed 1. 3 m/s. What is the centripetal acceleration of this particle?.

(a)  The velocity of the electron that has a wavelength of 3.31 m/s is approximately 1.99 x 10^6 m/s.

(b)  The voltage through which the electron must be accelerated to have this velocity is approximately 15.9 V.

(a) The de Broglie wavelength (λ) of an electron is related to its momentum (p) and mass (m) by the equation:

λ = h / p = h / (mv)

where h is Planck's constant, m is the mass of the electron, and v is its velocity.

Solving for v, we get:

v = h / (mλ)

Substituting the values given in the problem, we get:

v = (6.626 x 10^-34 J s) / [(9.109 x 10^-31 kg)(3.31 x 10^-6 m)] ≈ 1.99 x 10^6 m/s

Therefore, the velocity of the electron is approximately 1.99 x 10^6 m/s.

(b) To calculate the voltage required to accelerate the electron to the velocity calculated in part (a), we can use the formula for the kinetic energy of a particle:

KE = 1/2 mv^2

At the instant the electron exits the accelerating voltage, it has a kinetic energy equal to the potential energy gained from the voltage. Thus, we can set the kinetic energy equal to the potential energy and solve for the voltage:

KE = eV = 1/2 mv^2

Solving for V, we get:

V = KE / e = (1/2)mv^2 / e

Substituting the values given in the problem, we get:

V = (1/2)(9.109 x 10^-31 kg)(1.99 x 10^6 m/s)^2 / (1.602 x 10^-19 C) ≈ 15.9 V

Therefore, the voltage required to accelerate the electron to the given velocity is approximately 15.9 V.

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To calculate the velocity of an electron with a wavelength of 3.31 um, we can use the de Broglie equation: wavelength = h/momentum. where h is Planck's constant and momentum is mass times velocity.

Since we are dealing with an electron, we know the mass is 9.11 x \(10^{-31}\) kg. Rearranging the equation to solve for velocity, we get velocity = momentum/mass = h/(mass*wavelength). Plugging in the values, we get: velocity = (6.626 x \(10^{-34}\) J*s)/(9.11 x \(10^{-31}\) kg * 3.31 x \(10^{-6}\) m) = 2.20 x \(10^{6}\) m/s. So the velocity of the electron is 2.20 x \(10^{6}\) m/s. To find the voltage needed to accelerate the electron to this velocity, we can use the kinetic energy equation: KE = 0.5 * mass * \(velocity^{2}\) = q * V. where KE is the kinetic energy of the electron, q is its charge, and V is the voltage. Since the electron starts at rest, its initial kinetic energy is zero. Rearranging the equation to solve for V, we get V = KE/q = (0.5 * mass * \(velocity^{2}\))/q. Plugging in the values, we get: V = (0.5 * 9.11 x \(10^{-31}\) kg * (2.20 x \(10^{6}\) m/s)^2)/(1.6 x \(10^{-19}\) C) = 106 V. So the electron needs to be accelerated through a voltage of 106 V to achieve a velocity of 2.20 x \(10^{6}\) m/s.

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Answer: Yes I am alive.

To estimate the distance to the nearest black hole of mass 10^(-8) solar masses in the halo of our Galaxy, we can use the mass distribution of dark matter and make some assumptions.

Let's assume that the dark matter is distributed roughly uniformly throughout the Galactic halo.

The approximate density of dark matter in the Galactic halo is estimated to be around 0.4 GeV/cm^3. Considering that the mass of the Milky Way is about 10^12 solar masses and assuming spherical symmetry, we can estimate the volume of the halo as V = (4/3)πR^3, where R is the radius of the halo.

If we assume that all the dark matter in the halo is composed of black holes with a mass of 10^(-8) solar masses, we can calculate the number of black holes in the halo as N = (M_halo/M_bh), where M_halo is the mass of the Galactic halo and M_bh is the mass of an individual black hole.

Using these values, we can estimate the distance to the nearest black hole by assuming an even distribution of black holes in the halo. The nearest black hole would then be at a distance approximately equal to the radius of the halo, R.

As for the frequency of such a black hole passing within 1 AU of the Sun, we can make an order-of-magnitude estimate by assuming that the black holes move randomly through the halo. The timescale for a black hole to pass through a region of size 1 AU can be estimated as t = (1 AU)/(v_bh), where v_bh is the average velocity of the black holes. We can assume a typical velocity of the order of the virial velocity of the Milky Way, which is approximately 220 km/s.

Keep in mind that these estimates are based on assumptions and simplifications, and the actual distribution and behavior of dark matter and black holes in the Galactic halo are still subjects of ongoing research.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question is we have

force = 75 × 12

We have the final answer as

Hope this helps you

Answer:

Radioactive Decay

Explanation:

Answer: There are \(6.25 \times 10^{18}\) protons present in one coulomb of charge​.

Explanation:

Given: Charge on proton = \(1.6 \times 10^{-19} C\)

It is known that the charge on a proton is equal to the charge present on an electron.

Formula used to calculate number of protons is as follows.

Q = ne

where,

Q = charge considered

n = number of protons

e = charge on electron or proton

Substitute the values into above formula as follows.

\(Q = ne\\1 C = n \times 1.6 \times 10^{-19} C\\n = 0.625 \times 10^{19}\\= 6.25 \times 10^{18}\)

Thus, we can conclude that there are \(6.25 \times 10^{18}\) protons present in one coulomb of charge​.

The force of gravity will become one fourth of the original force when the masses of the objects remain the same but their distance of separation doubles.

Force of gravity is an attraction force which holds the object towards the ground surface.

The gravitational force depends directly on the masses of two objects and indirectly on the square of the distance between them.

Let

m₁ and m₂ be the two different masses

r₁ be the initial distance between the the two masses

r₂ be the distance when their separation doubles.

i.e. r₂ = 2r₁

So, according to the formula,

F₁ =   \(\frac{Gm1m2}{r1^{2} }\)

F₂ =   \(\frac{Gm1m2}{r2^{2} }\)

since masses are same:

\(\frac{F1}{F2} = \frac{r2^{2} }{r1^{2} }\)

\(\frac{F1}{F2} = \frac{4r1}{r1}\)

F₁ = 4F₂

F₂ = \(\frac{1}{4}\)F₁

The resultant force is one fourth of the original force.

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The extensions of the middle and lower springs are 0.3209 m and 0.1988 m, respectively, from their unstretched lengths.

We can solve this problem using the concept of equilibrium and the equations of motion. In equilibrium, the weight of each mass is balanced by the force exerted by the spring, so we have:

m₁g = kx₁

m₂g = kx₂

m₃g = kx₃

where g is the acceleration due to gravity, k is the spring constant, and x₁, x₂, and x₃ are the extensions of the three springs from their unstretched lengths.

When the elevator is moving with constant velocity, the forces on the masses are still balanced, so the extensions of the springs are unchanged. However, when the elevator is accelerating, the forces on the masses are no longer balanced, and the extensions of the springs will change. We need to take into account the pseudo-force experienced by the masses due to the acceleration of the elevator.

The pseudo-force on each mass is given by:

F' = m × a

where m is the mass of the object and a is the acceleration of the elevator. For m₁, m₂, and m₃, the pseudo-forces are:

F₁' = m₁a = 3.3 kg × 4.8 m/s² = 15.84 N

F₂' = m₂a = 9.9 kg × 4.8 m/s² = 47.52 N

F₃' = m₃a = 6.6 kg × 4.8 m/s² = 31.68 N

To calculate the new extensions of the springs, we need to add the pseudo-forces to the weights of the masses and then divide by the spring constant. For the upper spring, which is attached to m₁, we have:

kx₁ = m₁g + F₁'

x₁ = (m₁g + F₁')/k

Substituting the values, we get:

x₁ = (3.3 kg × 9.81 m/s² + 15.84 N)/(229.57 N/m) = 0.1003 m

So the upper spring is extended by 0.1003 m from its unstretched length.

For the other two springs, we have:

x₂ = (m₂g + F₂')/k = (9.9 kg × 9.81 m/s² + 47.52 N)/(229.57 N/m) = 0.3209 m

x₃ = (m₃g + F₃')/k = (6.6 kg × 9.81 m/s² + 31.68 N)/(229.57 N/m) = 0.1988 m

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To find the total change in the object's speed between 1.0 s and 1.1 s, we need to calculate the area under the velocity vs. time graph during this time interval. Looking at the given graph, we can see that the velocity of the object starts at approximately -0.2 m/s at 1.0 s and increases to approximately 0.2 m/s at 1.1 s.

The area under this portion of the graph is a trapezoid with a base of 0.1 s and heights of -0.2 m/s and 0.2 m/s, respectively. Therefore, the total change in the object's speed is:

Area = 0.5 x (base1 + base2) x height
     = 0.5 x (0.1 s + 0.1 s) x (0.2 m/s - (-0.2 m/s))
     = 0.01 m/s

Therefore, the total change in the object's speed between 1.0 s and 1.1 s is most nearly 0.01 m/s.

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Answer:

A.) glucose

Explanation:

Answer:

A. glucose

Explanation:

pay attention to the lesson

Answer:

According to Newton's Second Law of Motion :    

Where,

F = Force Applied

m = Mass of the object

a = Acceleration

Now, we will use this law to solve this question.

Given :

Acceleration or a = 15.3 m/s²

Force = 44 N

Mass = ?

Substitute, the given values in the formula.

F = ma

⇒ m = F/a

   m = 44/15.3

m = 2.9 kg

Answer:

7.0 n

Explanation:

When light passes through a double slit, the pattern on the wall would be an interference pattern of light and dark fringes.

If light consisted of classical particles and was sent through a double slit, the pattern on the wall would be a bright blob with no distinct shape. If light is actually a wave that only behaves like a particle in certain situations then, when light passes through a double slit, the pattern on the wall would be an interference pattern of light and dark fringes.What is a double slit?A double-slit experiment is an experiment that demonstrates the wave-like nature of light. Light passes through two small slits that are positioned close together in a double-slit experiment. Two waves emerge from the two slits and interact with each other, producing an interference pattern on a screen. The pattern will consist of a series of alternating bright and dark fringes, known as interference fringes.

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Answer:

For an object resting upon a non-accelerating surface, the normal force is equal to the ... Suppose that a person weighs 800 N and sits at rest upon a table. ... applying a downward force of 200 N. With the additional downward force of 200 N acting upon the person, the total upward force must be 1000 N.

Explanation:

deloer je n'ai pas mla reponse a tas question

Therefore, the statement that "X-ray telescope mirrors are very similar to optical telescope mirrors" is FALSE since they are used for capturing and detecting different wavelengths of light. Optical telescopes detect and focus visible light while X-ray telescopes capture and detect high-energy X-ray radiation.

X-ray telescope mirrors are not very similar to optical telescope mirrors. The two are different because they have different types of wavelengths of light they detect. While optical telescopes reflect and focus visible light to produce images, X-ray telescopes capture and detect high-energy X-ray radiation that is outside the visible spectrum.

What are X-ray telescopes?

X-ray telescopes are scientific instruments that are designed to observe objects in space that emit X-ray radiation. The mirrors of X-ray telescopes are made of a special type of glass or metal that can reflect and focus X-rays in the same way that optical telescopes focus and reflect light. The main function of X-ray telescopes is to gather high-energy X-rays that are emitted by objects in space such as black holes, neutron stars, and other exotic celestial bodies. They can also be used to study the X-ray properties of galaxies, stars, and other astronomical objects.

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To convert the speed from meters per hour to kilometers per hour, you can divide the speed in meters per hour by 1000 to get the speed in kilometers per hour.

In this case, the car is traveling at a speed of 12,000 m/hr. Dividing this speed by 1000 gives us a speed of 12,000/1000=12 km/hr.

So the car is traveling at a speed of 12 km/hr.

Answer:

A derived unit is a SI unit of measurement comprised of a combination of the seven base units. Like SI unit of force is the derived unit, newton or N where N=s21×m×kg. There are some commonly used derived units which includes: 1. Pressure = AreaForce=m2N.

Explanation:

Answer:

Explanation

What exactly do you need? More context to this problem would help me in helping you!

The photoelectric effect is a phenomenon where electrons are ejected from the surface of a material when light is incident upon it. The effect is governed by the energy of the photons and the binding energy of the electrons to the material.

The photoelectric effect is a phenomenon in physics where electrons are ejected from the surface of a metal plate when light of a certain frequency or above falls on it. The energy of the light is transferred to the electrons, which can then overcome the binding energy of the metal and escape from the surface. The ejected electrons are called photoelectrons, and their energy is related to the frequency of the incident light. This effect is important in understanding the nature of light and matter, and has numerous applications in fields such as photovoltaics, photocathodes, and photomultiplier tubes.

Therefore, When light strikes a substance, a phenomena known as the photoelectric effect occurs when electrons are expelled from the material's surface. The energy of the photons and the binding energy of the electrons to the substance determine the outcome.

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Answer:

The answer is B) Double slit

Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.

(hope this helps) :)

Answer:

It has greater accuracy than other nondestructive methods in determining the depth of internal flaws and the thickness of parts with parallel surfaces.

Explanation:

Hope this helps you!

Answer:

They are deflected as Earth’s magnetic field exerts force on them.

Explanation:

(Not for cheating, Just to help)

As solar wind approaches Earth, what happens to the charged electrons?

They are absorbed as Earth’s magnetic field exerts force on them.

They grow stronger as Earth’s magnetic field exerts force on them.

They grow weaker as Earth’s magnetic field exerts force on them.

They are deflected as Earth’s magnetic field exerts force on them.

First, the electron absorbs energy to move to a higher energy level.

To find the pressure caused by piston A on the fluid, we can use the formula:

Pressure = Force / Area

Given that the force exerted by piston A is 1000 N, and the area of each of the four pistons that hold up the car is 0.02 m^2, we can calculate the pressure as:

Pressure = 1000 N / (4 x 0.02 m^2)

Pressure = 25000 N/m^2

So the pressure caused by piston A on the fluid is 25000 N/m^2

Answer:

The correct answer is (d) tv screens. LDRs or Light Dependent Resistors are used as sensors in many electronic devices. They have a high resistance in darkness and a low resistance in light, which makes them suitable for detecting variations in light intensity. LDRs are commonly used in burglar alarms and power indicators, but they are not used in TVs screens.

The hydrogen atom will have 5 values for the azimuthal quantum number, l.

i) A group of quantum states of the hydrogen atom has the principal quantum number as,

n = 5.

Therefore, the possible values of the azimuthal quantum number of the hydrogen atom, l will be,

l = 0, 1 ,2, ..., (n - 1) = 0, 1, 2, ..., (5 - 1) values

l = 0, 1, 2, 3, 4

So, the hydrogen atom will have 5 values for the azimuthal quantum number.

ii) Given that,

The principal quantum number of hydrogen atom, n = 5

Azimuthal quantum number of the hydrogen atom, l = 3

Therefore, the possible values of magnetic quantum number, m will be,

m = -l, ..., 0, ...+l

m = -3, -2, -1, 0, 1, 2, 3

So, the hydrogen atom will have 7 values for the magnetic quantum number.

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Connecting household appliances in series has several disadvantages, including the failure of one appliance leading to the failure of the entire circuit, voltage drop across each appliance, and difficulty adding new appliances to the circuit.

Connecting household appliances in series means that they are connected one after the other in a single circuit. The current flows through one appliance before it flows through the next one.

While this type of connection may work for some types of appliances, it is not practical for most household appliances due to its significant disadvantages.

One significant disadvantage of connecting household appliances in series is that the failure of one appliance can cause the entire circuit to fail. In a series circuit, the current must flow through every appliance to complete the circuit.

If one appliance fails, the circuit becomes incomplete, and all the other appliances in the circuit will stop working. Another disadvantage of connecting household appliances in series is that the voltage drops across each appliance.

As the current flows through each appliance, some of the electrical energy is converted to heat or other forms of energy, causing the voltage to decrease as the current flows through the circuit. This can cause the appliances at the end of the circuit to receive a much lower voltage than they need, leading to their improper functioning.

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The magnetic field outside the solenoid \(B_{\text {out }}\) is zero.

The magnetic field lines are present outside the solenoid, but there are significantly less of them there than there are inside the solenoid. This is known as the flux. As a result, the magnetic field outside is thought to be almost nil. It is more accurate to assume that the magnetic field outside the solenoid is zero if the solenoid is quite long. It is false close to the solenoid's edge. We consider the magnetic field outside the solenoid to be zero for practical purposes. This amount of flux divided by the area outside the solenoids gives the flux density, which is equal to the strength of the field outside the solenoid is zero.

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