A sample of helium behaves as an ideal gas as it is heated at constant pressure from 283 K to 358 K. If 70 J of work is done by the gas dur- ing this process, what is the mass of the he- lium sample? The universal gas constant is 8.31451 J/mol · K. Answer in units of g.

Answers

Answer 1

The mass of the helium sample is approximately 0.187 g.

To solve this problem, we can use following formula:

w = nR(T2 - T1)

We can rearrange this formula to solve for n:

n = w / (R * (T2 - T1))

To find the mass of the helium sample, we can use following formula:

m = n * M

where m is the mass of the sample, n is  number of moles of gas, and M is the molar mass of helium.

Substituting the given values into the first equation, we get:

70 J = n * 8.31451 J/mol*K * (358 K - 283 K)

Simplifying this equation, we get:

n = 0.0467 mol

Substituting this value into the second equation, we get:

m = 0.0467 mol * 4 g/mol = 0.187 g

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Related Questions

Help is appreciated, I'm giving One Hundred points if answered, If you answer with unknown links, you will get reported.

Please match the formula and definition with the correct word.

Question 2 options:

= ma


= (v2-v1)/t


= d/t


= m/v


= W/t


= F/d

1.
Speed

2.
Acceleration

3.
Force

4.
Work

5.
Power

6.
Density

Answers

Answer:

Explanation:

1.  Speed = d/t

d = distance

t = time

2. Acceleration = (v2-v1)/t

v2 = final velocity

v1 = initial velocity

t = time

3. Force = ma

m = mass

a = acceleration

4. Work = F•d  (not F/d)

F = Force

d = distance

5. Power = W/t

W = Work

t = time

6. Density = m/V

m = mass

V = volume

Physics Question!!!!!

Physics Question!!!!!

Answers

Answer:

bbibinononobyvtcrxrxextcyvubuvububububububbu

Answer:

im just gettin these points babbbyyyyyy

Explanation:

what must occur within a magnetic material before it exhibts magnetic properties?


a

The material must be of a specific size

b

The material must be charged with electricity

c

The magnetic domains inside the material must be aligned

d

The magnetic material must be created artificially

Answers

Answer:

Option C, The magnetic domains inside the material must be aligned

Explanation:

Magnetic domains determine the magnetic behavior of any substance. Most of the magnetic substances have disoriented magnetic domains due to which they do not behave as magnets until unless an external force is applied to change the orientation of their domains and align them properly.

Hence, option C is correct

A pitcher throws a baseball from the pitcher's mound to home plate in 0.46 s. The
distance is 18.4 m. What was the average speed of the baseball?
a. 40 m/s
b. - 40 m/s
c. 0.03 m/s
d. 8.5 m/s

Answers

The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?

Answers

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.

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An electron is traveling at 2.0E5 m/s parallel to a uniform electric field of 9.11e-3 N/C strength. The electron is traveling to the right. The electric field lines point to the right. What is the speed of the electron (in m/s) after traveling 1.8 meters to the right?

Answers

Answer:

v = 1.85*10^5 m/s

Explanation:

In order to calculate the speed of the electron after it has traveled 1.8m, you first take into account that the electric field generates a desceleration on the electron, because the direction of the electron and electric field are the same.

You use the Newton second law, to calculate the deceleration of the electron:

\(F_e=qE=ma\)      (1)

q: charge of the electron = 1.6*10^-19C

m: mass of the electron = 9.1*10^-31kg

E: magnitude of the electric field = 9.11*10^-3N/C

a: deceleration = ?

You solve the equation (1) for a, and replace the values of the other parameters:

\(a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(9.11*10^{-3}N/C)}{9.1*10^{-31}kg}\\\\a=1.6*10^9\frac{m}{s^2}\)

Next, you use the following formula to calculate the final speed of the electron:

\(v^2=v_o^2-2ax\)      (2)

v: final speed of the electron = ?

vo: initial speed of the electron = 2.0*10^5 m/s

x: distance traveled by the electron = 1.8m

You solve the equation (2) for v and replace the values of the other parameters:

\(v=\sqrt{v_o^2-2ax}=\sqrt{(2.0*10^5m/s)^2-2(1.6*10^9m/s^2)(1.8m)}\\\\v=1.85*10^5\frac{m}{s}\)

The speed of the electron after it has traveled 1.8m is 1.85*10^5 m/s

A motivated mule can accelerate an empty cart of mass m - 180 kg from rest to 5.0 m/s in 10 s.
If the cart is loaded with 550 kg of wood, how long will it take the mule to get the cart to 4.6 m/s? Assume a constant acceleration. Also assume the mule exerts the same force as when the cart is
empty

Answers

When the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

Acceleration of the mule

The acceleration of mule is calculated as follows;

a = v/t

a = 5/10

a = 0.5 m/s²

For constant applied force

F1 = F2

m₁v₁/t₁ = m₂v₂/t₂

(180 x 5) / 10 = (550 x 4.6)/t

90 = 2530/t

t = 2530/90

t = 28.11 s

Thus, when the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

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a hohmann transfer is a fuel efficient transfer orbit to an outer planet. the process requires placing a spacecraft into an elliptical orbit about the sun, such that the perihelion, the point closest to the sun, is at the departure planet and the the aphelion, the point farthest from the sun, is at the arrival planet. the entire trajectory is depicted below.(a) Use Kepler's third law to calculate how long it would take to go from the Earth to Mars on such an orbit. (b) Can such a transfer be undertaken at any time? Explain.

Answers

A chemical rocket may launch a satellite into a Hohmann transfer orbit and maintain it there until it reaches the farthest point in the orbit by performing two very powerful burns.

These chemical rockets aren't very effective, though. They would have perished because it would have taken four weeks to return to Earth orbit.One (very powerful) engine burn is all that the Hohmann transfer orbit requires. But the interval between the two engine burns is nearly half an orbit, or 2 weeks in the event of an Earth to Moon transfer, as opposed to 3 days for the Apollo approach.That translates into four times as much food, oxygen, and cramping in the muscles, which results in increased mass and fuel. Apollo 13 remained on its orbit around the Moon after their oxygen tank exploded, depriving them of electrical power and heating, and returned to Earth after nearly 5 days.

They would have perished if they had been in a Hohmann transfer orbit, which would have taken around 4 weeks to return to.

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Philosophy 203 Do you think it is important to rank moral rules in order of importance? How will you rank your own ethical rules or those of any other system in which you are aware? order

Answers

It can be important to rank moral rules in order of importance because it allows for clear decision-making and prioritization in situations where multiple moral considerations are present. However, ranking moral rules can also be difficult and subjective, as different individuals and cultures may place different values and priorities on different moral principles.

The principle of non-harm, which holds that it is morally wrong to cause harm to others.

The principle of autonomy, which holds that individuals should be free to make their own choices and pursue their own goals.

The principle of fairness and justice, which holds that individuals should be treated equally and that resources and opportunities should be distributed fairly.

The principle of compassion and empathy, which holds that individuals should care for and show concern for the well-being of others.

The principle of responsibility and accountability, which holds that individuals should be held responsible for the consequences of their actions.

It's important to keep in mind that everyone have different moral principles and they might have different order of importance.

It's important to note that this ranking is not definitive, and different individuals and cultures may have different priorities and values when it comes to moral principles.

a ball is thrown straight up into the air with an initial speed of 3.1 m/s. a. After 0.24 seconds what is the ball's velocity and b. what is it's acceleration?

Answers

a. The ball's velocity after 0.24 s is 0.75 m/s

b. The acceleration of the ball is given by the acceleration due to gravity

a. The ball's velocity can be calculated with the following equation:

\( v_{f} = v_{0} - gt \)

Where:

\( v_{f} \): is the final speed =?

\(v_{0}\): is the initial speed = 3.1 m/s

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 0.24 s

The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).

The final speed is:

\( v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s \)

Hence, the ball's velocity after 0.24 s is 0.75 m/s.

b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.  

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Interference Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 12.0 m to the right of speaker A. The frequency of the waves emitted by each speaker is 688 Hz. You are standing between the speakers, along the line connecting them, and are at a point of constructive interference. How far must you walk toward speaker B to move to a point of destructive interference

Answers

Answer:

0.125 m

Explanation:

From wave equations, we know that;

Wavelength;λ = f/v

Where v is speed of sound in air with a constant value of 344 m/s

Frequency;f = 688 Hz

λ = v/f

λ = 344/688

λ = 0.5 m

Constructive interference will occur when the two waves differ by a distance of nλ and when they have the same wavelength.

At constructive interference point, my distance from both speakers will be x.

Since the distance between speaker A and B is 12 m, then;

difference in path is;

nλ = 12 - x - x

nλ = 12 - 2x

Making x the subject, gives;

x = 6 - nλ/2

Plugging in 0.5 for λ gives;

x = 6 - n(0.5)/2

x = 6 - n/4

So, since it's at point 1,we'll label it accordingly.

Thus;

x_1 = 6 - 0.25(n_1)

Now, we know that destructive interference will occur when the two waves differ by a distance of;(½ + n)λ and when they have the same wavelength.

Thus,

12 - 2x = (½ + n)λ

Plugging in 0.5 for λ to give;

12 - 2x = ¼ + n/2

Divide through by 2 to give;

6 - x = ⅛ + n/4

x = 6 - ⅛ - n/4

Since second point, then;

x2 = 5.875 - 0.25(n_2)

To find out how far I must walk toward speaker B to move to a point of destructive interference, it will be;

x1 - x2 which gives;

6 - 0.25(n_1) - 5.875 + 0.25(n_2)

This gives;

0.125 - (0.25(n_1) - 0.25(n_2))

This means that 0.125 m is the distance since I have to subtract difference of 0.25 multiplied by the difference of n_1 and n_2 from 0.125

the pressure at the bottom of a drum in which a liquid is filled up to the height of 2 m is 9000800 PF find the density of liquid field in that drum​

Answers

The density of the liquid in the drum is 459.184 kg/m³.

To find the density of a liquid, we must know its pressure, the depth to which it is filled, and the gravitational acceleration acting on it. Using the equation for pressure at a depth h below the surface of a liquid in a container of height H, P = ρgh, where P is the pressure, ρ is the density, g is the gravitational acceleration, h is the height of the liquid, and H is the height of the container.Let's substitute the given values in the above formula:P = 9000800 Pa; h = 2m; g = 9.8m/s²Therefore, ρ = P/gh = 9000800/(9.8 × 2) ≈ 459184.

This means that the density of the liquid in the drum is 459.184 kg/m³ (kilograms per cubic meter).

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An air puck of mass m1 = 0.21 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.0 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.

Answers

The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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Which is a benefit of using synthetic polymers, such as nylon?
Synthetic polymers are lightweight.
O Synthetic polymers are produced in small
quantities.
Synthetic polymers are biodegradable.
Synthetic polymers are inexpensive to recycle.

Answers

Answer: Synthetic polymers are lightweight.

Explanation:

A  benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.

A polymer is a molecule composed of many repeating subunits.

Synthetic polymers are artificial polymers created by humans.

Most of the synthetic polymers are not biodegradable (unlike natural fibers such as cotton).

Synthetic polymers are classified according to their use into plastics, elastomers and synthetic fibers.

The advantages of synthetic polymers include: hard to break, being lightweight, and they last for a long time.

In conclusion, a benefit of using synthetic polymers is the fact that synthetic polymers are lightweight.

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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?​

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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the magnetic field within a long, straight solenoid with a circular cross section and radius r is increasing at a rate of dbdt.

Answers

If the magnetic field within a long straight solenoid with a circular cross section and radius R is increasing at a rate of db/dt it will give us the magnitude of the induced EMF.

If we consider a long straight current carrying conductor in which the magnetic field is constantly increasing or decreasing with the rate of db/dt.

If the area of the solenoid is A.

Then the magnitude of the induced EMF in the conductor will be given by the relation.

E = Adb/dt

Now, from the above relation we can conclude that the EMF in a conductor is changing with a change in area and also the change in the magnetic field.

We can also rewrite the above relation,

E = dM/dr

Where,

d = BA.

Where,

B is magnetic field and A is the area.

Here, M is collectively called the magnetic flux.

So we can conclude that the rate of change of magnetic flux is directly proportional to the EMF induced in the conductor.

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What are some of the forces affecting rock climbers?​

Answers

Answer:

Gravitational force

Explanation:

Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.

Answer:

Gravity, low oxygen, and rock slides.

Explanation:

Some rock climbers train for years but are hardly prepared for some situations.

Question One
a. Why is it important to calibrate a measuring instrument regularly?
[1 marks]
b. An instrument with a standard signal of 4 mA - 20 mA is installed to measure the volume of
fluid in a cylindrical tank of height 40 m and a diameter of 6 m.
i.
If the sensor for the measurement of the volume should not have a direct contact with
the fluid, what type of sensor would you recommend to be installed?
[1 marks]
ii. Describe how you will calibrate the sensor to be able to measure the minimum and
maximum volume of fluid in the tank.
iii.
iv.
vi.
Attempt all questions.
vii.
[2 marks]
What is the maximum volume of the tank?
[2 marks]
What is the volume of the fluid in the tank if the output signal of the instrument is 14
[2 marks]
mA?
What will be the value of the output signal of the instrument if the volume of the fluid
in the tank is 65% of the maximum capacity of the tank?
[2 marks]
What will be the volume of the fluid if the sensor produces a signal of 17 mA? Express
it as a percentage.
[2 marks]
Comment on the instrument performance if a signal of 15.7 'mA is produced when the
volume of the fluid in tank is 75% of the maximum tank capacity. [2 marks]
type proximity
[1 marks]
c. Distinguish between a capacitive type proximity sensor and an inductive
switch.

Answers

a. It is important to calibrate a measuring instrument regularly for the following reasons:

Accuracy: Over time, measuring instruments can drift from their original calibration due to factors such as environmental conditions, wear, and tear, or component aging.

Compliance: In many industries, calibration is a requirement to comply with quality standards, regulations, and certifications.

Confidence: Calibration instills confidence in the measurement results obtained from the instrument.

b. i. If the sensor for measuring the volume of fluid should not have direct contact with the fluid, a suitable sensor would be a non-contact or remote-level sensor. Examples include ultrasonic sensors, radar sensors, or laser distance sensors. These sensors can measure the distance to the fluid surface without physically touching it.

ii. To calibrate the sensor to measure the minimum and maximum volume of fluid in the tank, the following steps can be taken:

Empty Tank Calibration: With the tank completely empty, the sensor should be calibrated to read the minimum volume of fluid, which is 0 m³, or any other reference point desired.

Full Tank Calibration: The tank should be filled to its maximum capacity. The sensor is then calibrated to read the maximum volume of fluid, which is the volume when the tank is at its full capacity.

iii. The maximum volume of the tank can be calculated using its dimensions. The formula for calculating the volume of a cylinder is:

Volume = π * (radius)² * height

Given the diameter (6 m), we can calculate the radius as 6 m / 2 = 3 m.

Maximum Volume = π * (3 m)² * 40 m

iv. The volume of the fluid in the tank can be determined using the linear relationship between the output signal of the instrument and the volume. Since the signal range is from 4 mA to 20 mA, and this range corresponds to the minimum and maximum volume of the tank, we can create a linear equation or calibration curve relating the output signal to the volume.

v. To calculate the volume of the fluid in the tank when the output signal is 14 mA, we use the calibration curve or linear equation obtained during calibration.

vi. To determine the output signal when the volume of the fluid in the tank is 65% of the maximum capacity, we use the calibration curve or linear equation obtained during calibration.

vii. To determine the volume of the fluid when the sensor produces a signal of 17 mA, we use the calibration curve or linear equation obtained during calibration and express the result as a percentage of the maximum capacity of the tank.

c. Distinguishing between a capacitive type proximity sensor and an inductive switch:

Capacitive Proximity Sensor: A capacitive proximity sensor uses changes in capacitance to detect the presence or absence of an object. It works based on the principle that the capacitance between the sensor and an object changes when the object enters the sensing range.

Inductive Switch: An inductive switch, also known as an inductive proximity sensor, operates on the principle of electromagnetic induction.

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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find the true velocity of the wind.​

Answers

Answer:

The true velocity of wind will be 43.1 km/h.

Explanation:

Given that,

Velocity of motor \(\vec{v_{m}}= 50\hat{j}\ km/h\)

The resultant velocity of wind

\(\ver{v_{r}}=60\hat{i}\times\dfrac{1}{\sqrt{2}}+60\hat{j}}\times\dfrac{1}{\sqrt{2}}\)

Suppose, the true velocity of wind is \(\vec{v_{w}}\).

We need to calculate the true velocity of wind

Using formula of resultant velocity

\(\vec{v_{m}}+\vec{v_{w}}=\vec{v_{r}}\)

\(\vec{v_{w}}=\vec{v_{r}}-\vec{v_{m}}\)

Where, \(\vec{v_{m}}\) = velocity of motor

\(\vec{v_{w}}\) = velocity of wind

\(\vec{v_{r}}\) = resultant velocity

Put the value into the formula

\(\vec{v_{w}}=\dfrac{60}{\sqrt{2}}\hat{i}+(\dfrac{60}{\sqrt{2}}-50)\hat{j}\)

\(\vec{v_{w}}=42.43\hat{i}-7.57\hat{j}\)

The magnitude of true velocity is,

\(v_{m}=\sqrt{(42.43)^2+(-7.57)^2}\)

\(v_{m}=43.0.9\approx 43.1\ km/h\)

Hence,  The true velocity of wind will be 43.1 km/h.

To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find

A ball is thrown vertically upwards with a velocity of 10 m /s from the balcony of a tall building.
The balcony is 15m above the ground and gravitational acceleration is 10m/s^2.
Calculate the time taken for the ball to reach maximum height.

Answers

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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How can you determine the number of neutrons in an atom?

A. Mass number plus number of electrons
B. Atomic number minus mass number
C. Mass number minus atomic number
D. Atomic number plus mass number

Answers

Answer:

B. Atomic number minus mass number

Explanation:

Use a projectile motion kinematic equation for the vertical motion to find the time t that the ball is in the air, from when it leaves the track until it strikes the floor.

Answers

Answer:

The time of flight is \(T = \frac{2 u sin A}{g}\).

Explanation:

Let the initial velocity is u and the angle of projection is A.

Use first equation of motion for vertical motion

Let the time to reach the maximum height is t.

\(v = u - gt\\\\0 = u sin A - gt \\\\t = \frac{ u sin A}{g}\)

Total time of flight is

T =2  t

\(T = \frac{2 u sin A}{g}\)

Which of these forces help protons and neutrons to stay at the center of the Atom

Answers

Strong nuclear force

A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?

Answers

A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the source

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what are the greenhouse gasses in the earth that are primarily responsible for the greenhouse effect on Earth

Answers

Answer:

Water Vapour, Carbon dioxide, methane,nitrous oxide,ozone.

a charge Q exerts a 12 N force on another charge q .if the distance between the charges is doubled , what is the magb of the force exerted on Q by q​

Answers

Answer:

3 N.

Explanation:

If you want to know how much two charges push or pull each other, you can use Coulomb's law. It says that the force F depends on how big the charges are (Q and q) and how far apart they are (r). The bigger the charges and the closer they are, the stronger the force. The smaller the charges and the farther they are, the weaker the force. The exact formula is:

F = k | Q q | / r 2

where k is a number that makes everything work out right. It's about 8.99 × 10 9 N ⋅ m 2 / C 2 .

Now let's say you have two charges that are a certain distance r 0 apart and they have a force F 0 between them. What happens if you move them twice as far apart? The new distance is 2 r 0 and the new force is F 1 . How do F 1 and F 0 compare? Well, you can use Coulomb's law again and divide them:

F 1 / F 0 = (k | Q q | / (2 r 0 ) 2 ) / (k | Q q | / r 0 2 )

If you simplify this, you get:

F 1 / F 0 = (1/2) 2

F 1 / F 0 = 1/4

This means that the new force is only one-fourth of the old force. So if the old force was 12 N, then the new force is:

F 1 = F 0 /4

F 1 = (12 N) /4

F 1 = 3 N

So moving the charges twice as far apart makes the force four times weaker. It goes from 12 N to 3 N.

An acorn falls from rest from the top of a 19m tall oak tree. How long does it take for the acorn to fall to the ground? How fast is the acorn going before it hits the ground?

Answers

Answer:

We can solve this problem using the kinematic equation:

y = 1/2 * g * t^2

where y is the height of the tree, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to fall to the ground.

We can solve for t using:

t = sqrt(2y/g)

Plugging in the values, we get:

t = sqrt(2(19)/9.8)

t = 2.19 seconds

So, it takes 2.19 seconds for the acorn to fall from the tree to the ground.

To find the velocity of the acorn just before it hits the ground, we can use:

v = g * t

Plugging in the values, we get:

v = 9.8 * 2.19

v = 21.46 m/s

So, the acorn is going approximately 21.46 m/s just before it hits the ground.

Explanation:

Which of the following is equivalent to X in the nuclear equation shown below?
90Sr+ 86Kr + p⇒ 108Pd+X+n

Answers

Yes the acceptable move  that proves the two equation are equivalent.

What is equivalent equation?

Equivalent equation are algebraic equations that have identical solutions or roots. Adding or substracting the same number or expression to both side of an equation produce an equivalent equation.

Combine any like terms on each side of to the equation: x-terms with x-terms and constants with of the constants. Arrange the terms in the same by order, usually x-term before the constants. As if all of the terms in to  the two expressions are the  identical, then the two expressions is equivalent.

By observing both equations

In equation A : -3(x+9)=18

Divide the equation A by -3

=> (x+9)=-6

And this result equals to equation B

Hence both equations are equivalent

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Before the coyote begins to fall, what can you tell about the potential and kinetic energy of the roadrunner vs the coyote?

Select all correct responses.

A. Ignoring air resistance and assuming they have the same mass, the kinetic energy of both is equal right before impact with the ground.
B. The potential energy of the one with the most mass is greater than the other.
C. Weight is the same for both, regardless of mass.
D. The potential energy of both are equal.

Before the coyote begins to fall, what can you tell about the potential and kinetic energy of the roadrunner

Answers

Before they begin to fall, the potential energy of the roadrunner and the coyote is the same regardless of their mass. Both the roadrunner and the coyote have zero kinetic energy just before they begin to fall.

What are some illustrations of kinetic and potential energy?

The energy an individual or an object has as a result of motion—in this case, the motion of the falling apple—is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill.

What is the connection between potential difference and kinetic energy?

By virtue of energy conservation, kinetic energy (KE) must be equal to the change in potential energy (qV), or vice versa. The voltage between the plates and the electron's energy are numerically equivalent in electron-volts. A 5000-V potential difference, for instance, results in 5000-eV electrons.

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