In the given scenario, a student's dormitory room number does not represent a numerical value or measurement but rather falls into specific categories or groups. It is considered a categorical variable.
A student's dormitory room number is an example of a categorical variable.
Categorical variables are variables that can be divided into distinct categories or groups. In this case, the room number of a student's dormitory can be categorized into different rooms such as Room 101, Room 102, Room 103, and so on. Each room number represents a specific category or group.
On the other hand, quantitative variables are variables that represent numerical values or measurements. They can be further classified into two types: discrete and continuous. Discrete quantitative variables represent distinct and separate values (such as the number of siblings), while continuous quantitative variables represent a range of values (such as height or weight).
In the given scenario, a student's dormitory room number does not represent a numerical value or measurement but rather falls into specific categories or groups. It is considered a categorical variable.
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What i (1 x ) (3 x 1) (5 x ) (3 x ) in word form?
A. One and three hundred fifty-three thouandth
B. Thirteen and fifty-three hundredth
C. One hundred three and fifty-three thouandth
D. One hundred three and five hundred three thouandth
Word form One hundred three and five hundred three thouandth
How do you write the number in word form? Word form means expressing numbers by spelling them out in words. ⇒ Expanded form means expressing according to place value. This is a little trickier because you have to. think about how much is in each place: ones, tens, hundreds, etc.To write a given number in word form, identify the largest place value, write each number as we would in the ones place based on hundreds, tens, and ones, then write which period the digits fit into, whether it be millions, thousands, etc., but excluding the ones. Repeat this process from left to right100 in words is written as One hundred or simply Hundred. The name of the number 100 in English is “HundredTo learn more about number in word form refers to:
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what is the slope of line 2x-3y=19.
Answer:
\(\frac{2}{3}\)
Step-by-step explanation:
Given Equation of line: y=mx+c,
where m = slope of line.
So, we will have to make y the subject to find the slope.
\(2x-3y=19\\2x-3y-2x=19-2x\\-3y=-2x+19\\y=\frac{-2x+19}{-3} \\y=\frac{2}{3} x-\frac{19}{3}\)
From here, we can see the slope of the line is \(\frac{2}{3}\).
Answer: 2/3
Step-by-step explanation:
2x-3y=19
minus 2x from both sides
-3y=-2x+19
divide both sides by -3
y=2/3x-19/3
slope is 2/3
What percent is equivalent to Two-thirds?
66 and one-third percent
66 and three-fifths percent
66 and two-thirds percent
66 and StartFraction 7 Over 10 EndFraction percent
Answer:
c
yes divided by yes by the yes factor = yes, it is c
PLEASE HELP ASAP!!! will mark
Answer:
x=3 or x=5
Step-by-step explanation:
The answer is where the graph line curve cuts the x-axis (the horizontal line)
it cuts at 3 and 5
What is the value of x in this triangle?
Enter your answer in the box.
x =
Answer:
x=47
Step-by-step explanation:
because the total angles for the triangle are 180
so 31+102=133
so 180-133= 47
help me pleaseeee!!!!!!!
there are six possibilities , the probability of rolling an odd no. is 3 so
\( \frac{3}{6} = \frac{1}{2} \)
please mark me as brainliest
What are the domain restrictions of q^2−7q−8 divided by q^2+3q−4 ?
o q≠1 and q≠−8
o q≠−1 and q≠8
o q≠−1 and q≠4
o q≠1 and q≠−4
The domain restrictions of the expression q²−7q−8/q²+3q−4 are q ≠ -4 and q ≠ 1. (option c)
The denominator of the expression is q²+3q−4. To determine the values that would make the denominator equal to zero, we can set it equal to zero and solve for q:
q² + 3q - 4 = 0
Now, we can factorize the quadratic equation:
(q + 4)(q - 1) = 0
To find the values of q, we set each factor equal to zero and solve for q:
q + 4 = 0 or q - 1 = 0
Solving these equations, we get:
q = -4 or q = 1
So, the values of q that would make the denominator equal to zero are q = -4 and q = 1. These are the values we need to exclude from the domain of the expression to avoid division by zero.
Therefore, the correct answer is option c) q ≠ 1 and q ≠ -4.
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Complete Question:
What are the domain restrictions of q²−7q−8/q²+3q−4?
a) q≠1 and q≠−8
b) q≠−1 and q≠4
c) q≠1 and q≠−4
d) q≠−1 and q≠8
Jennifer is a lifeguard at a swimming pool. She earns $132.54 for 18 hours of working. How much does Jennifer earns per hour.
please answer and explain :)
Answer:
7.36 an hour
Step-by-step explanation:
If she earns that much for 18 h, divide the amount she makes in 18 h by 18 parts because 18h/18 = 1 h. If done properly, you will get $7.36.
in pic (nothing academical)
Answer:
wanna hear a dirty joke?
Step-by-step explanation:
Answer:
lol
Step-by-step explanation:
look below
hqhhahahahahahahahhaha
can you explain to me what a voronoi diagram is?and what are the edges, and other things?
A Voronoi diagram is a division of a plane into areas near each of a given set of objects in mathematics. These things are just infinitely many points in the plane in the simplest scenario (called seeds, sites, or generators). There is a region, known as a Voronoi cell, for each seed that is made up of all points in the plane that are closer to that seed than to any other point. A set of points' Voronoi diagram and Delaunay triangulation are identical.
We are aware that any intersection of half-planes results in a convex region bordered by a collection of linked line segments. Voronoi edges are the line segments that define the limits of Voronoi regions. These edges' termini are known as Voronoi vertices.
Voronoi diagram:
A Voronoi diagram in mathematics is a division of a plane into areas near to each of a given set of objects. These things are simply infinitely many plane points in the most basic scenario (called seeds, sites, or generators).
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Explain how to determine the zeros of f(x)=(x+3)(x-1)
Answer:
x= -3, x = 1
Step-by-step explanation:
Zeros are values of x, when f(x) = 0.
0=(x+3)(x-1)
x+3 = 0, x - 1=0
x= -3, x = 1
Answer:
x = -3, x = 1
Step-by-step explanation:
To determine the zeroes of the factored quadratic equation, we need to look back at its definition. The zeroes are a function are specific x-values that result in a y-value of 0.
In this case, we want the numbers inside of the parantheses to equal 0. If we substitute in x = -3, we get (0)(x - 1), and we know that is just 0. Similarly, if we substitute in x = 1, we get (x + 3)(0), and we know that is just 0.
As such, these are your solutions.
Help!! Ur the best if u can help!
Answer:
A
Step-by-step explanation:
Answer:
A.
Step-by-step explanation:
Hey! So look at 18 on the left-hand side. Then, look at the inches. Also, note that A is the exact same as the graph! Therefor, your answer is A!
Have a great day!
Brainliest please!
Hope this helps friend!
a tank in the shape of a hemisphere has a diameter of 6 feet. if the liquid that fills the tank has a density of 53.3 pounds per cubic foot, what is the total weight of the liquid in the tank, to the nearest full pound?
The total weight of the liquid in the tank, to the nearest full pound, is calculated to be 3,012 pounds.
The volume of a hemisphere with diameter 6 feet is (2/3) x π x (6/2)³ = 56.55 cubic feet.
The weight of the liquid in the tank can be found by multiplying the volume of the liquid by its density:
Weight = Volume x Density = 56.55 x 53.3 = 3,012.32 pounds.
Rounding this to the nearest full pound gives a total weight of 3,012 pounds. Therefore, the total weight of the liquid in the tank is 3,012 pounds (to the nearest full pound).
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Answer:
3014
Step-by-step explanation:
I just did it
not really an academic subject lol just a stoopid inquiry
.
.
does anyone else stay up super late even if they're tired? like you haven't "completed" your day yet. just me?... TT_TT pls help
(my sleep schedule is very messed up) :,)
Answer:
Yes me too! Except I watch movies because I have a feeling they won't be there tomorrow lol
Step-by-step explanation:
Ignore my answer but I need help asap I’m confused
The amount of principal after one month would be B. 72. 67.
How to find the principal ?In order to ascertain the amount of principal after one month, we must compute both the interest and principal segments of the initial monthly payment.
Initially, let us derive the sum for the first month's interest. The yearly rate of interest culminates to 19%; thus, applying the relevant mathematical formula leads to determination of the ensuing monthly interest rate:
= 19 % / 12
= 0. 015833
The interest portion on the payment is:
= 1, 800 x 0. 015833
= $ 28. 50
The principal is therefore:
= 101. 06 monthly payment - 28. 50
= $ 72. 67
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Match the terms to their definition. 1. numerator a number with an integer part and a fraction part 2. mixed number a fraction with a whole number for the numerator and a whole number other than zero for the denominator 3. denominator the number above the fraction line; tells how many parts of the whole exist 4. common fraction a fraction in which the numerator is larger than the denominator 5. like denominators the number under the fraction line; tells how many equal parts the whole was broken into 6. improper fraction
Answer:
numerator - the number above the fraction line; tells how many parts of the whole exist
mixed number - a number with an integer part and a fraction part
denominator - the number under the fraction line; tells how many equal parts the whole was broken into
common fraction - a fraction with a whole number for the numerator and a whole number other than zero for the denominator
like denominators - two fractions with the same denominator
improper fraction - a fraction in which the numerator is larger than the denominator
I need help with these 2 problems, my teacher would like fractions to help explain how I got it... Example (56/100=45/64) =) Thank you in advance!!
We operate as follows:
**First problem:
*We divide the total number of messes by the value of the sum of the ratio.
391 / (14 + 9) = 17
After that, we multiply this value times the ration for the Gooey messes and we will obtain the number of Gooey messes present in the 391 messes:
17 * 14 = 238
So, we can expect 238 Gooey messes.
**Second problem:
*We have 174 purple yogi berries; we will have to calculate the number of berries that represent the 76% if we want to know how many are not purple. We also have the following ration 24:76 here there are 24 purple yogi berries to 76, not purple yogi berries, now we calculate:
\(\frac{24}{76}=\frac{174}{NP}\Rightarrow NP=\frac{174\cdot76}{24}\Rightarrow NP=551\)So, we would expect 551, not purple yogi berries.
Molly's school is selling tickets to a play. On the first day of ticket sales the school sold 7 senior citizen tickets and 11 student tickets for a total of $125. The school took in $180 on the second day by selling 14 senior citizen tickets and 8 student tickets. What is the price each of one senior citizen ticket and one student ticket?
Answer: the price of one senior citizen ticket is $10, and the price of one student ticket is $5.
Step-by-step explanation:
Let's assume the price of one senior citizen ticket is 's' dollars and the price of one student ticket is 't' dollars.
According to the given information, on the first day, the school sold 7 senior citizen tickets and 11 student tickets, totaling $125. This can be expressed as the equation:
7s + 11t = 125 ---(1)
On the second day, the school sold 14 senior citizen tickets and 8 student tickets, totaling $180. This can be expressed as the equation:
14s + 8t = 180 ---(2)
We now have a system of two equations with two variables. We can solve this system to find the values of 's' and 't'.
Multiplying equation (1) by 8 and equation (2) by 11, we get:
56s + 88t = 1000 ---(3)
154s + 88t = 1980 ---(4)
Subtracting equation (3) from equation (4) eliminates 't':
(154s + 88t) - (56s + 88t) = 1980 - 1000
98s = 980
s = 980 / 98
s = 10
Substituting the value of 's' back into equation (1), we can solve for 't':
7s + 11t = 125
7(10) + 11t = 125
70 + 11t = 125
11t = 125 - 70
11t = 55
t = 55 / 11
t = 5
Therefore, the price of one senior citizen ticket is $10, and the price of one student ticket is $5.
what is the cube root of 8/27
Answer:
Cube root of 8/27 is 2/3
\( \sqrt{ \frac{8}{27} } \)
\( = \sqrt{ (\frac{2}{3} {)}^{2} } \)
\( = \frac{2}{3} \)
of a pizza remains, and Seth and Ethan want to split it evenly. What fraction of the original pizza will each get?
Answer:
\(\huge\boxed{\text{Multiply the denominator by 2, or}}\\\\\huge{\boxed{\text{divide the percentage by 2}}}}\)
Step-by-step explanation:
Because there is no fraction or percentage given, simply follow this rule to divide a portion by 2.
Hope it helps :) and let me know if you want me to elaborate(solve with fraction)
A random sample of size 36 is taken from a population with mean 50 and standard deviation 5. What is
When a sample is taken from a population, it is important to understand the characteristics of both the sample and the population. In this scenario, the sample size is 36, meaning that 36 individuals or data points were randomly selected from the larger population.
The population mean is 50, which tells us the average value of the population data. The standard deviation of the population is 5, which indicates the degree of variability in the data.
Using the information provided, we can calculate the standard error of the mean (SEM), which is the standard deviation of the sample mean. The formula for SEM is:
\(SEM = population standard deviation / square root of sample size\)
SEM = 5 / square root of 36
SEM = 5 / 6
SEM = 0.83
Therefore, the standard error of the mean for this sample is 0.83. This means that if we were to take many samples of size 36 from this population, we would expect the mean of each sample to be within 0.83 units of the true population mean of 50.
It is important to note that while this sample may give us some insight into the characteristics of the larger population, it is not necessarily representative of the entire population. To increase the accuracy of our findings, we would need to take multiple random samples and calculate the means and standard errors of each sample.
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Which is the range of the relation y = 2x2 + 3x if the domain is the set {-2, -1, 0}?
A {10,1,0)
B.{-1,-5,0)
c. {2,-1,0)
D. (2. 1.0)
Given:
The function is:
\(y=2x^2+3x\)
Domain is the set {-2, -1, 0).
To find:
The range of the given relation.
Solution:
We have,
\(y=2x^2+3x\)
Substituting \(x=-2\), we get
\(y=2(-2)^2+3(-2)\)
\(y=2(4)+(-6)\)
\(y=8-6\)
\(y=2\)
Substituting \(x=-1\), we get
\(y=2(-1)^2+3(-1)\)
\(y=2(1)+(-3)\)
\(y=2-3\)
\(y=-1\)
Substituting \(x=0\), we get
\(y=2(0)^2+3(0)\)
\(y=0+0\)
\(y=0\)
The range for the given relation is {2, -1,0}. Therefore, the correct option is (c).
Please Help I Will Give Brainliesttt!Select the correct answer. What was the most common rating in the 26-35 age group? Average B. Good C. Excellent D. Poon
Answer:
B. Good
Step-by-step explanation:
26-35 age group:
Excellent - 33/97
Good - 50/97
Average - 5/97
Poor - 9/97
Consider two independent binomial experiments. In the first one, 94 trials had 54 successes.In the second one, 63 trials had 40 successes. Answer the following questions. Use a confidence level of 96%. Use 4 decimal places for each answer. Do not round from one part to the next when performing the calculations, though. Find the point estimate. Find the critical value. Find the margin of error. Find the confidence interval. < p 1 − p 2
The 96% confidence interval for the difference in proportions is (−0.1127, 0.3191)
To compare the proportions of success in two binomial experiments, we can use the two-sample Z-test.
Let p1 be the proportion of success in the first experiment and p2 be the proportion of success in the second experiment. We want to test the null hypothesis H0: p1 = p2 against the alternative hypothesis Ha: p1 ≠ p2.
First, we calculate the point estimate of the difference in proportions:
\(pp1 - p2 = \frac{54}{94} - \frac{40}{63} = 0.1032\)
Next, we find the critical value of the test statistic. Since the confidence level is 96%, we have alpha = 0.04/2 = 0.02 on each tail of the distribution. Using a standard normal distribution table, we find that the critical values are ±2.0537.
The margin of error is given by:
\(ME= z \sqrt{\frac{p1(1-p1)}{n1} +\frac{p2(1-p2)}{n2} }\)
where z* is the critical value, n1 and n2 are the sample sizes of the two experiments. Plugging in the values, we get:
\(ME= z \sqrt{\frac{0.5769(1-0.5769)}{94} +\frac{0.6349(1-0.6349)}{63} }= 0.2159\)
Finally, we can construct the confidence interval for the difference in proportions as:
(p1 - p2) ± ME
which gives us:
0.1032 ± 0.2159
Thus, the 96% confidence interval for the difference in proportions is (−0.1127, 0.3191).
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gelo bought a wallet which costs php250at 12% discount and a belt which costs php230 at 25% discount.how much did he pay in all?
a.php87.50
b.php392.50
c.php3925
d. php8750
Option B : Gelo bought a wallet for PHP 250 with a 12% discount and a belt for PHP 230 with a 25% discount. Gelo paid a total of PHP 392.50 for both items.
First, we need to calculate the amount of the discount for the wallet and the belt. The discount for the wallet is 250 * 12/100 = 30. The discount for the belt is 230 * 25/100 = 57.5.
Next, we subtract the discount from the original price to find the amount paid for each item. The amount paid for the wallet is 250 - 30 = 220. The amount paid for the belt is 230 - 57.5 = 172.5.
Finally, we add up the amount paid for both items to find the total amount paid: 220 + 172.5 = 392.5.
Therefore, Gelo paid a total of 392.5, so the correct answer is (b) PHP 392.50.
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Option B : Gelo bought a wallet for PHP 250 with a 12% discount and a belt for PHP 230 with a 25% discount. Gelo paid a total of PHP 392.50 for both items.
First, we need to calculate the amount of the discount for the wallet and the belt. The discount for the wallet is 250 * 12/100 = 30. The discount for the belt is 230 * 25/100 = 57.5.
Next, we subtract the discount from the original price to find the amount paid for each item. The amount paid for the wallet is 250 - 30 = 220. The amount paid for the belt is 230 - 57.5 = 172.5.
Finally, we add up the amount paid for both items to find the total amount paid: 220 + 172.5 = 392.5.
Therefore, Gelo paid a total of 392.5, so the correct answer is (b) PHP 392.50.
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In a class 18 children are girls A quarter of the children in the class are boys. Altogether, how many children are in the class?
Answer:
24
Step-by-step explanation:
let x be the number of children in the class , then
number of boys = \(\frac{1}{4}\) x , so
x = \(\frac{1}{4}\) x + 18 ( multiply through by 4 to clear the fraction )
4x = x + 72 ( subtract x from both sides )
3x = 72 ( divide both sides by 3 )
x = 24
There are 24 children in the class
hospital noise levels noise levels at various area urban hospitals were measured in decibels. the mean noise level in 180 ward areas was 56.5 decibels, and the population standard deviation is 3.5. find the 98% confidence interval of the true mean. use a graphing calculator and round the answers to one decimal place. < u
The 98% confidence interval for the true mean noise level is approximately (55.9, 57.1).
To find the 98% confidence interval for the true mean noise level, we can use the formula:
CI = mean ± Z * (σ / sqrt(n))
Where:
CI is the confidence interval,
mean is the sample mean,
Z is the z-score corresponding to the desired confidence level,
σ is the population standard deviation,
n is the sample size.
In this case, we have:
mean = 56.5 (sample mean)
σ = 3.5 (population standard deviation)
n = 180 (sample size)
Confidence level = 98%
First, we need to find the z-score corresponding to a 98% confidence level. The remaining 2% is split equally between the two tails of the distribution, so we have 1% in each tail. We can find the z-score using a standard normal distribution table or a graphing calculator. For a 98% confidence level, the z-score is approximately 2.33.
Now we can calculate the confidence interval:
CI = 56.5 ± 2.33 * (3.5 / sqrt(180))
CI = 56.5 ± 2.33 * (3.5 / 13.416)
CI = 56.5 ± 2.33 * 0.261
CI = 56.5 ± 0.607
CI ≈ (55.9, 57.1)
Therefore, the 98% confidence interval for the true mean noise level is approximately (55.9, 57.1).
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Nuclear power plants have redundant components in important systems to reduce the chance of catastrophic failure. Assume that a plant has two gauges to measure the level of coolant in the reactor core and that each gauge has probability 0.01 of failing. Assume that one potential cause of gauge failure is that the electric ca- bles leading from the core to the control room where the gauges are located may burn up in a fire. Someone wishes to estimate the probability that both gauges fail, and makes the following calculation: P (both gauges fail) = P (first gauge fails) P (second gauge fails) = (0.01)(0.01) = 0.0001 What assumption is being made in this calculation? Explain why this assumption is probably not justi- fied in the present case. a. b. c. Is the probability of 0.0001 likely to be too high or too low? Explain.
The assumption being made in the calculation is that the two gauges are independent, which is not justified since both gauges are subject to the same potential cause of failure. The probability of 0.0001 is likely too low.
The assumption made in this calculation is about the failure of one gauge is independent of the failure of the other gauge. This assumption is probably not justified in the present case because the two gauges are connected to the same electric cables, and if a fire destroys the cables, both gauges will fail simultaneously.
The probability of 0.0001 is likely to be too low because the assumption of independence is violated, and the probability of both gauges failing simultaneously is likely to be higher than the product of their individual failure probabilities.
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Element X decays radioactively with a half life of 8 minutes. If there are 450 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 37 grams?
If there are 450 grams of element and half life is 8 minutes, then it will take 28.83 minutes the element to decay to 37 grams
Half life of radio active element = 8 minutes
Initial quantity of radio active element = 450 gram
Final quantity of radio active element = 37 grams
y = a(0.5)^(t/h)
Substitute the values in the equation
37 = 450 (0.5)^(t/8)
Move 37 to left hand side of the equation
37 / 450 = 0.5^(t/8)
Convert the terms to logarithm
t/8 = \(log_{0.5}\frac{37}{450}\)
t/8 = 3.60
t = 8 × 3.60
Multiply the numbers
t = 28.83 minutes
Therefore, the it will take 28.83 minutes to decay to 37 grams
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Choose the highest common factor (HCF) of 6xy^3 and 9x^2y
A= x^2y^3
B= 3xy
C= 54x^3y^4
D=18x^2y^3
Answer:
B= 3xy
Step-by-step explanation:
6xy^3= 2ₓ3ₓ x ₓyₓyₓy
9x^2y= 3ₓ3ₓ x ₓ x ₓ y
common factors = 3, x , y
HCF: 3 ₓ x ₓ y
=3xy