When a treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure, therefore, the tension in the ropes is 921.2 N.
Given, Mass of the treasure chest (m) = 94.0 kg
Acceleration due to gravity (g) = 9.81 m/s²
We can determine the tension force (T) exerted by each rope using the following equation:
T = mg/2
Here, we are given that the treasure chest is being lifted using two ropes. Therefore, the weight of the chest is distributed equally between the ropes.
Hence, substituting the given values, we get:
T = (94.0 kg)(9.81 m/s²)/2T
= 462.3 N
Therefore, the tension force exerted by each rope is T = 462.3 N.
Therefore, the tension in the ropes is 921.2 N.
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A small dense ball with mass is thrown with initial velocity at time from a location we choose to call the origin. Air resistance is negligible.
(a) Velocity is zero (b) the time is 0.918 sec (c) the time is 1.836 sec (d) the distance is 14.688 m (e) the angle in degree is 0 degree.
a) When the ball reaches its maximum height, its velocity is entirely in the vertical direction (y-axis) and has no horizontal component (x-axis or z-axis). The velocity vector at this point is <0, vy, 0>, where vy is the vertical component of velocity.
b) To find t when the ball reaches its maximum height, we can set the vertical component of velocity vy = 0, and use the equation of motion for vertical motion:
vy = v0y - gt
where v0y = 9m/s is the initial vertical velocity, g = 9.8 m/s^2 is the acceleration due to gravity, and t is the time since the ball was thrown.
0 = 9 - 9.8t
t = 9/9.8 = 0.918 s
c) The time t when the ball's height y returns to zero can be found by setting y = 0 in the equation of motion for vertical motion:
y = v0y x t - (1/2) x g x t^2
0 = 9t - 4.9t^2
4.9t^2 = 9t
t = 9/4.9 = 1.836 s
d) At the time calculated in part (c), when the ball's height y returns to zero, the range of the trajectory (x) can be found by using the equation of motion for horizontal motion:
x = v0x x t
x = 8 x 1.836 = 14.688 m
e) The angle in degrees with respect to the positive x-axis of the velocity at the time calculated in part (c) is found by using the horizontal component of the velocity vector.
The horizontal component of the velocity vector is vx = 8 m/s.
The angle of the velocity vector with respect to the positive x-axis is found by using the arctangent function.
angle = a tan(vy/vx) = a tan(0/8) = 0 degrees.
It's important to note that the range is the maximum distance that the ball travels horizontally, and it is reached at the time when the ball's height y returns to zero.
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Question - A small dense ball with mass 0.9 kg is thrown with initial velocity <8,9,0>m/s at time =0 from a location we choose to call the origin (<0,0,0>m). Air resistance is negligible.
(a) When the ball reaches its maximum height, what is its velocity?
(b) When the ball reaches its maximum height, what is time ?
(c) At a later time the ball's height has returned to zero, which means that the arithmetic average value of from =0 to this time is zero. At this instant, what is the time ?
(d) At the time calculated in part (c), when the ball's height returns to zero, what is distance? (This is called the range of the trajectory.)
(e) What is the angle in degrees with respect to the positive x-axis of the velocity at the time calculated in part (c)? Present your answer as a positive value less than 360.
a small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbanked road. if the frictional force required to keep the small car on the road without skidding is f, then the frictional force required to keep the large car on the road without skidding is
Answer:
f/2
Explanation:
In this case the force that is necessary to keep the object moving in a curved path and that is directed inward toward the center of rotation, centripetal force = f
f= m × centripetal acceleration
centripetal acceleration = V^2/r
Therefore f = m (2v)^2 /r --------1
If frictional force required to keep the large car on the road = F
F= 2m (v)^2/ r----------2
Now Divide 1st equation by 2nd one
f/F = m (2v)^2/2m(v)^2
f/F = 2
F= f/2
A) Reproduction or theft of a DBPR real estate license exam B) Failure to account or deliver escrow funds C) Provide inaccurate and out-of-date rental information for compensation D) False and misleading advertising
The violation is a third-degree felony is Reproduction or theft of a real estate license exam, option C.
A misdemeanor is typically regarded as a lesser offense while a felony is typically regarded as a serious offense. The expression "crime" started from English custom-based regulation (from the French middle age word "félonie") to depict an offense that brought about the seizure of a sentenced individual's property and products, to which extra disciplines including the death penalty could be added; Misdemeanors were the other names for crimes. A person can be referred to as a felon or a convicted felon after being found guilty of a felony in a court of law.
The federal government defines a felony as a crime that carries a sentence of death or imprisonment for more than one year in the United States, where the distinction between felony and misdemeanor is still widely used. It is considered a misdemeanor if the penalty is less than one year. The grouping depends on a wrongdoing's likely sentence, so a wrongdoing stays named a crime regardless of whether a litigant indicted for a lawful offense gets a sentence of one year or less. Other factors, like the degree of seriousness or the context, are used by some states to classify crimes.
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Complete question:
Which violation is a third-degree felony?
A) Provide inaccurate and out-of-date rental information for compensation
B) Failure to account for and deliver escrow funds
C) Reproduction or theft of a real estate license exam
D) False and misleading advertising
If you thrust a magnet into a closed loop of wire, the loop will
a.rotate
b.have current in it
c.both of the above
d. none of the above
If you thrust a magnet into a closed loop of wire, the loop will have current in it. So the correct option is B.
What is a magnet?A magnet is a body with a magnetism that can attract different irons that can be given naturally or artificially. Magnets can have their magnetic field continuously and this field can attract materials or repel them, this will depend on the magnetic permeability of the compound. The magnetic field of the images will be oriented towards the south pole and the north pole and each of these will be attracted by their opposites.
Not all magnets have permanent magnetism, this depends on whether they are going to be magnetized to be permanent or if they will only have temporary functionality.
By pushing a magnet in a closed circuit of wire, a magnetic field will be generated in which a current will flow in the turns of wire.
Therefore, we can confirm that the correct option is B. have current in it.
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What is used to measure power
Answer:
Electricity is measured in units of power called Watts,
hope this helps
have a good day :)
Explanation:
b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir
Answer:
rs 900
Explanation:
the process is given
Which statements best describe X-rays?
Answer:x rays are electromagnetic waves.
x rays are transverse waves
x rays travel at the speed of light
Explanation:
You are researching a fungus that can kill banana plants. Which source is
likely to have the least reliable information?
A. An article in a popular science magazine
B. A press release about research on the fungus posted on the
website of a university
C. A posting about the fungus on a social media site
D. A report about the fungus on a nightly news show
Answer:
B
Explanation:
what could i say except ur welcome
Two large parallel conducting plates carry charges of equal magnitude and opposite charge. When you place a point charge q = +3.60 nC between the plates, the force on the point charge is 22.0 μN. What is the magnitude of the surface charge density on either plate? Express your answer with the appropriate units.
Answer:
The magnitude of the surface charge density on either plate is approximately 5.41 × 10⁻⁸ C/(m²)
Explanation:
The magnitude of the charge on each of the conducting plates = Equal
The orientation of the charges on each plate = Opposite charges
The magnitude of the point charge placed between the plates = +3.60 nC
The force acting on the point charge, q = 22.0 μN
Therefore, we have;
F = E × q
E = F/q = 22.0 μN/+3.60nC = 6,111.1111 V/m
We have;
\(E = \dfrac{\rho }{\epsilon_0}\)
Where;
ρ = The surface charge density
ε₀ = Absolute permittivity ≈ 8.85 × 10⁻¹² C²/(N·m²)
Therefore, we have;
ρ = E × ε₀ = 6,111.1111 V/m × 8.85 × 10⁻¹² C²/(N·m²) = 5.40833332 × 10⁻⁸ C/(m²)
∴ The magnitude of the surface charge density on either plate, ρ ≈ 5.41 × 10⁻⁸ C/(m²).
when diving deeper than 40 feet, it is generally advantageous to breathe pure oxygen. true or false
These mixtures are carefully formulated to reduce the risk of oxygen toxicity and allow for safe and efficient diving at greater depths. False.
When diving deeper than 40 feet, it is not advantageous to breathe pure oxygen. In fact, it can be dangerous and potentially lethal if done for prolonged periods. Oxygen toxicity can occur, which can lead to seizures, unconsciousness, and even death. Instead, divers use specialized gas mixtures that contain a lower percentage of oxygen and higher percentages of other gases such as nitrogen and helium.
When diving deeper than 40 feet, it is generally not advantageous to breathe pure oxygen. Breathing pure oxygen at such depths can lead to oxygen toxicity, which can cause serious health issues or even death. Instead, divers typically use a mixture of gases, such as Nitrox or Trimix, which contain lower concentrations of oxygen and help reduce the risk of oxygen toxicity.
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A 2.3-kg toy locomotive is pulling a 1.4-kg caboose. The frictional force of the track on the caboose is 0.46 N backward along the track. If the train is accelerating forward is 3.1 m/s2, what is the magnitude of the force exerted by the locomotive on the caboose
The net vertical force on the caboose (C) is
∑ F[v, C] = F[n, C] - (1.4 kg) g = 0
where F[n, C] is the magnitude of the normal force exerted by the track on the caboose; so we have
F[n, C] = (2.3 kg) g = 13.72 N
which means the coefficient of kinetic friction µ between the caboose and the track is
F[f, C] = 0.46 N = µ (13.72 N) ⇒ µ = (0.46 N) / (13.72 N) ≈ 0.034
and presumably the coefficient is the same for the locomotive.
The net vertical force on the locomotive (L) is
∑ F[v, L] = F[n, L] - (2.3 kg) g = 0
where F[n, L] is the magnitude of the normal on the locomotive, so that
F[n, L] = (2.3 kg) g = 22.54 N
and so the locomotive is opposed by a frictional force with magnitude
F[f, L] = µ (22.54 N) ≈ 0.76 N
Taking the locomotive and caboose together, the net horizontal force on the system is
∑ F[h] ≈ - F[f, C] - F[f, L] + F[engine] = (2.3 kg + 1.4 kg) (3.1 m/s²)
Solve for F[engine] :
F[engine] ≈ (3.7 kg) (3.1 m/s²) + 0.46 N + 0.76 N ≈ 13 N
a bare roof on a warmly heated home on a snowy day indicates
A bare roof on a warmly heated home on a snowy day indicates that the home has effective insulation and heat management systems.
Proper insulation prevents heat from escaping through the roof, keeping the interior of the home warm and comfortable. As a result, the snow on the roof does not melt quickly, because the warm air inside the house does not directly come into contact with the snow on the roof. Additionally, an efficient heating system maintains a consistent indoor temperature, ensuring the home remains energy-efficient and reduces heating costs.
A bare roof also reduces the risk of ice dams, which occur when snow melts and refreezes at the edge of the roof, potentially causing water damage to the home. In conclusion, a bare roof on a warmly heated home on a snowy day is a positive sign that the house has effective insulation and heating systems in place. This ensures energy efficiency, reduced heating costs, and protection from potential damage caused by ice dams.
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Which law of motion states that for every action, there is an equal and opposite reaction?
a. Law of Inertia
b. Law of Interaction
c. Law of Acceleration
d. Law of Gravitation
Answer:
\(\huge\boxed{\sf Law \ of \ Interaction}\)
Explanation:
Newton's Third Law of Motion States that:
"For every action, there is a reaction which is equal in magnitude but opposite in direction."
Newton's third law is also called "Law of Interaction".
Hope this helped!
~AnonymousHelper1807Explanation:
The law of Interaction
A car travels around an unbanked highway curve (radius 0.15 km) at a constant speed of 25 m/s. What is the magnitude of the resultant force acting on the driver, who weighs 0.80 kN
The magnitude of the resultant force acting on the driver, who weighs 0.80 kN
What is resultant force:The total amount of force acting on the object or body along with the direction of the body.
The formula for the resultant force vector is given by Newton's Second law. F=ma.
here
speed, v = 25 m/s
radius, r = 0.15 km = 150 m
weight, w = 0.80 kN = 800 N
we know that,
W = m*g
800 = m * 9.8
m = 800 / 9.8
m = 81.63 kg
magnitude of the resultant force:
F = m*v^2 / r
F = 81.63 * 25^2 / 150
F = 340.13 N
F = 0.34 kN
hence,
The magnitude of the resultant force acting on the driver, who weighs 0.80 kN
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An ice skater is going into a spin. To simplify the system, the skater’s body (legs, torso, head) has a moment of inertia of 1.719kgm^2. Each hand-arm can be modeled as a point of mass of 5.0kg. At the beginning of the spin, the masses are rotating at 0.50m/s with their arms extended so that the center of mass of the hand-arm is 0.60m from the axis of rotation. For the finale, the skater pulls their arm inward so that the hand-arm is 0.20m from the axis of rotation. What is the angular velocity of the skater during the finale?
The angular velocity of the skater during the finale is 2.18 rad/s.
The conservation of angular momentum is a principle in physics that states that the total angular momentum of a system remains constant if no external torques act on the system. Mathematically, this can be expressed as L1 = L2, where L1 is the initial angular momentum of a system, L2 is the final angular momentum of the system, and the total torque acting on the system is zero. This principle is analogous to the conservation of linear momentum, which states that the total linear momentum of a system remains constant if no external forces act on the system. The conservation of angular momentum is an important principle in many areas of physics, including mechanics, electromagnetism, and quantum mechanics.
We can use the conservation of angular momentum to solve this problem. The initial angular momentum of the skater and the hand-arms is given by:
L1 = I1 * w1
where I1 is the moment of inertia of the skater's body, and w1 is the initial angular velocity. Since the hand-arms are extended, their moment of inertia can be neglected.
When the skater pulls their arms inward, the moment of inertia of the system decreases. The final moment of inertia is given by:
I2 = I1 + 2md^2
where m is the mass of each hand-arm, d is the distance of the hand-arm from the axis of rotation, and we multiply by 2 since there are two hand-arms.
The final angular velocity w2 can be found by equating the initial and final angular momentum:
L1 = I1 * w1 = I2 * w2
Substituting the expressions for I1, I2, and simplifying, we get:
w2 = w1 * I1 / (I1 + 2m(d2^2 - d1^2))
where d1 is the initial distance of the hand-arm from the axis of rotation (0.60 m), and d2 is the final distance of the hand-arm from the axis of rotation (0.20 m).
Substituting the given values, we get:
w2 = 0.50 m/s * 1.719 kgm^2 / (1.719 kgm^2 + 2 * 5.0 kg * (0.20 m^2 - 0.60 m^2))
w2 = 2.18 rad/s
Therefore, The skater's angular velocity during the grand finale is 2.18 rad/s.
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If the forces acting on an object are balanced, wihat must be true about the motion of this object?
Just need the two left on the bottom to be written because the app is acting up for me
ANSWER:
STEP-BY-STEP EXPLANATION:
We have the following:
• Electromagnetic waves are waves that can travel through the vacuum of outer space. Mechanical waves, unlike electromagnetic waves, require the presence of a material medium in order to transport their energy from one place to another.
,• Waves (electromagnetic and mechanical) can transfer energy over long distances since they do not need to move matter the entire distance.
,• Radiation is the transfer of energy through electromagnetic waves
Knowing the above, we can match the concepts as follows:
A particle of mass 6 kg travels along a straight line under the influence of a force F. The velocity of the particle is 4 m/s at t = 0 s and 10 m/s at time t = 2 s. Determine the impulse that the force applies to the particle between time t = 0 and t = 2s. Provide only a value without units.
The impulse that the force applies to the particle between time t = 0 and t = 2s is 36.
Let us consider the formula for Impulse.
Impulse= FΔt
where,F = force Δt = time interval
From the given problem,Particle mass, m = 6 kg
Particle velocity at t=0s,
u = 4 m/s
Particle velocity at t=2s,
v = 10 m/s
Δt = t2 - t1
= 2 - 0
= 2 s
The acceleration can be found out using the formula below.
a = (v - u) / Δta
= (10 - 4) / 2
= 3 m/s²
From Newton's second law of motion, force is given as
F = ma
= 6 × 3
= 18
we can find the impulse that the force applies to the particle between time t = 0 and t = 2s by using the formula above.
Impulse= FΔt= 18 × 2= <<18*2=36>>36
The impulse that the force applies to the particle between time t = 0 and t = 2s is 36.
Therefore, the answer is 36 without units.
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How can you get acceleration when talking about speed?
Answer:
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).
Explanation:
Max kicks a soccer ball with average force of 1400 N, and his foot remains in contact with the ball for a time of 0.0079 seconds. What is the impulse of this force?
Considering the definition of impulse, the impulse of the force is 11.06 N×s.
ImpulseImpulse is a term that quantifies the overall effect of a force acting over time.
In other words, the mechanical impulse of a force relates said force to the duration of its action. It is a vectorial magnitude that has the direction and sense of the force that produces it.
The impulse I is the product between a force and the time during which it is applied:
I= force× time
The unit of the impulse is the N×s (newton per second).
This caseIn this case, you know:
Force= 1400 NTime= 0.0079 secondsReplacing in the definition of impulse:
I= 1400 N× 0.0079 s
Solving:
I= 11.06 N×s
The impulse of the force is 11.06 N×s.
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1)What is the gain (unit conversion) at the output of the plant model and explain how you come up with that value?
I got Amplitudeout/Amplitudein=350/1=gain=350... Not sure if this is correct...
2)Show the Simulink diagram and circle the section that represent your external Quanser plant. What are the input and output?
3)What is the transfer function of the plant?
The Gain block will be used to adjust the acceleration due to gravity, g, and the Sine Wave function will be used to provide a sinusoidal input to the system. The output of the system will be ф(t).
Initial is an adjective that is used to describe something that occurs at the beginning or start of a process. It can be used to describe the first letter of a person's name, the first letter of a word, or the first stage or step in a process. For example, you might say “She signed her initial at the bottom of the contract” or “The initial step in the process is to research the topic.” Initial can also be used as a noun to refer to the first letter of a person's name or the first letter of a word.
The differential equation in ф describing the motion of the mass m is given by: m×d×dφ + m×g×l sinφ = 0.To build the system in Simulink, we will use an "Integrator" block, a "Gain" block, and a "Sine Wave" function. The Integrator will be used to integrate the differential equation to solve for the angular position ф(t). The Gain block will be used to adjust the acceleration due to gravity, g, and the Sine Wave function will be used to provide a sinusoidal input to the system. The output of the system will be ф(t).
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What happens to digital signals sent wirelessly over long distances?
A. The signals become stronger the farther they are from the
recipient.
B. The signals change so that data are less likely to be reliable.
C. The signals become weaker as they move away from the source.
D. The signals are more likely to be affected by noise.
Answer: C!! <3
Explanation: (a p e x)
In wireless transmission, the digital signals become weaker as they move away from the source. Hence, option (C) is correct.
What is wireless transmission of digital signals?Although most people take wireless data transfer for granted, when one stops to think about how it truly works, it does appear miraculous. Of course, there is a scientific explanation that a non-WLAN expert can comprehend.
In essence, the manipulation of radio waves allows for wireless data transmission. These waves are produced by creating electrical pulses in a natural way. Then, in order to transmit sound or data, these radio waves might have their amplitude or frequency altered. This procedure can be enhanced to increase the amount of data that can be communicated and the speed at which it can be transmitted.
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What does motion mean
Answer:
Motion:
Motion is when an object is changing position with respect to its surrounding.
Example:
=> A cyclist riding a cycle (cyclist is in motion.)
=> Fan moving (fan is in motion.)
\(\rule[225]{225}{2}\)
Hope this helped!
~AH1807the tank above is full of water that has a density of 62.4 lbs per cubic foot. how much work is done in filling the tank from the bottom?
The amount of work done in filling the tank from the bottom is equivalent to the weight of the water in the tank, which is approximately 186,720 ft-lbs.
To calculate the amount of work done in filling the tank, we need to determine the weight of the water in the tank first. The weight of the water is equal to its volume multiplied by its density.
Given that the tank is full of water, the volume of water in the tank is equal to the volume of the tank itself. The volume of the tank can be calculated by multiplying its length, width, and height. Assuming the dimensions of the tank to be 10 feet (length) x 10 feet (width) x 10 feet (height), the volume of the tank would be:
Volume = Length x Width x Height
Volume = 10 ft x 10 ft x 10 ft
Volume = 1,000 cubic feet
Now that we know the volume of the water in the tank, we can calculate its weight by multiplying it by the density of the water. Given that the density of the water is 62.4 lbs per cubic foot, the weight of the water would be:
Weight = Volume x Density
Weight = 1,000 cubic feet x 62.4 lbs per cubic foot
Weight = 62,400 lbs
Therefore, the amount of work done in filling the tank from the bottom would be equivalent to the weight of the water in the tank, which is approximately 186,720 ft-lbs (62,400 lbs x 3 feet, assuming the water is being lifted a distance of 3 feet from the bottom of the tank to the top).
In conclusion, the amount of work done in filling the tank from the bottom is equivalent to the weight of the water in the tank. This weight can be calculated by multiplying the volume of water in the tank by its density. Given the dimensions of the tank and the density of the water, we have determined that the amount of work done in filling the tank from the bottom is approximately 186,720 ft-lbs.
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highly impermeable subsurface layers such as compacted clay or shale that don't transmit ground water freely are known as ________.
Highly impermeable subsurface layers such as compacted clay or shale that don't transmit groundwater freely are known as aquitards. Aquitards are subsurface geological formations that exhibit low permeability, preventing or restricting the flow of groundwater.
These layers act as barriers or confining layers, limiting the vertical movement of water through the Earth's subsurface. Aquitards are typically composed of materials with low hydraulic conductivity, such as compacted clay or shale.
The impermeable nature of aquitards is due to their fine-grained composition, which reduces the interconnected pore spaces necessary for groundwater flow. When water encounters an aquitard, it is impeded or slowed down, leading to the accumulation of water above the layer.
This creates a confined or semi-confined aquifer, where water is stored under pressure. Aquitards play a crucial role in groundwater management and protection. They act as natural barriers that prevent the contamination and excessive depletion of groundwater resources. Their impermeability helps maintain water quality by reducing the risk of pollutants infiltrating the underlying aquifers.
Aquitards also influence the behavior of groundwater systems, controlling the movement and distribution of water within the subsurface.
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Why does a ball not bounce back up to its original height?
Answer:
Gravity
Explanation:
A 80 N horizontal force is applied to a 20.0 kg block at rest on a horizontal surface where µS = 0.6.? What is the magnitude of the force of friction on the block?
Answer:
The frictional force on the block is 118 N.
Explanation:
Given;
horizontal force applied on the block, f = 80 N
mass of the block, m = 20.0 kg
coefficient of friction, μ = 0.6
The frictional force on the block is calculated as;
F = μR
F = μ(mg)
F = 0.6(20 x 9.81)
F = 117.7 N
F = 118 N.
Therefore, the frictional force on the block is 118 N.
After rubbing the hair on your head with a balloon, you determine there are 2.4 x 1018 electrons on your head. What is the charge, in coulombs (C), of your head?
Answer:
q = 0.384 C
Explanation:
The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:
\(q = ne\)
where,
q = total charge on head = ?
n = total no. of electrons on the head = 2.4 x 10¹⁸
e = charge on 1 electron = 1.6 x 10⁻¹⁹ C
Therefore,
\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)
q = 0.384 C
a block of mass m is floating in a container of liquid and is partially submerged. the block is then replaced by a block of mass 2m . which of the following describes two forces that are a newton's-third-law force pair whose magnitudes are the same for the two situations? responses
In both situations, the two forces that form a Newton's third-law force pair with equal magnitudes are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
When a block is floating in a container of liquid, it experiences two forces: the weight of the block and the buoyant force exerted by the liquid. The weight of the block is given by the equation:
\(\[ F_{\text{{weight}}} = mg \]\)
where m is the mass of the block and g is the acceleration due to gravity. The buoyant force exerted by the liquid on the block is equal to the weight of the liquid displaced by the block. It can be calculated using Archimedes' principle:
\(\[ F_{\text{{buoyant}}} = \rho V_{\text{{submerged}}} g \]\)
where \(\( \rho \)\) is the density of the liquid and \(\( V_{\text{{submerged}}} \)\) is the volume of the block that is submerged in the liquid.
When the block is replaced with a block of mass 2m , the weight of the block doubles while the buoyant force remains the same. Therefore, the two forces that form a Newton's third-law force pair with equal magnitudes in both situations are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
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What is the efficency of a sertain engine whose hot resevoir is 700 celsius and the cold reservoir is 230 celsius
The efficiency of a certain engine can be determined using the Carnot Cycle equation. The efficiency of an engine is proportional to the difference in temperature between the hot reservoir and the cold reservoir.
The efficiency can be calculated using the following formula:
η = (Th - Tc) / ThWhere,η = efficiency of the engine
Th = temperature of the hot reservoir
Tc = temperature of the cold reservoir
Given that the temperature of the hot reservoir is 700°C and the temperature of the cold reservoir is 230°C.
Therefore,η = (700 - 230) / 700η = 0.67The efficiency of the engine is 0.67 or 67%. In other words, only 67% of the heat energy is converted into mechanical energy while the remaining 33% is lost as waste heat.
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