At a particular place on the surface of the Earth, the Earth's magnetic field has magnitude of 3.65 ✕ 10^−5 T, and there is also a 121 V/m electric field perpendicular to the Earth's surface.
(a) Compute the energy density of the electric field. (b) Compute the energy density of the magnetic field.
Answers
Answer:(a) The energy density of an electric field is given by:
u_E = ε_0 * E^2 / 2
where ε_0 is the permittivity of free space (ε_0 = 8.85 × 10^-12 N^-1 C^2 m^-2), and E is the magnitude of the electric field.
Substituting the given values, we get:
u_E = (8.85 × 10^-12 N^-1 C^2 m^-2) * (121 V/m)^2 / 2 ≈ 6.34 × 10^-8 J/m^3
Therefore, the energy density of the electric field is approximately 6.34 × 10^-8 J/m^3.
(b) The energy density of a magnetic field is given by:
u_B = B^2 / (2 * μ_0)
where B is the magnitude of the magnetic field, and μ_0 is the permeability of free space (μ_0 = 4π × 10^-7 N A^-2).
Substituting the given value of the magnetic field, we get:
u_B = (3.65 × 10^-5 T)^2 / (2 * 4π × 10^-7 N A^-2) ≈ 6.52 × 10^-12 J/m^3
Therefore, the energy density of the magnetic field is approximately 6.52 × 10^-12 J/m^3.
Explanation:
(a) The energy density of the electric field is approximately 6.48 × 10^-8 J/m^3.
(b) The energy density of the magnetic field is approximately 1.27 × 10^-11 J/m^3.
(a) To compute the energy density of the electric field, we use the formula:
u_E = ε_0 E^2 / 2
where u_E is the energy density of the electric field, ε_0 is the electric constant (also known as the permittivity of free space), and E is the magnitude of the electric field.
The electric constant is ε_0 = 8.85 × 10^-12 F/m, and the magnitude of the electric field is E = 121 V/m. Substituting these values into the formula, we get
u_E = (8.85 × 10^-12 F/m) × (121 V/m)^2 / 2 = 6.48 × 10^-8 J/m^3
Therefore, the energy density of the electric field is approximately 6.48 × 10^-8 J/m^3.
(b) To compute the energy density of the magnetic field, we use the formula:
u_B = B^2 / (2μ_0)
where u_B is the energy density of the magnetic field, μ_0 is the magnetic constant (also known as the permeability of free space), and B is the magnitude of the magnetic field.
The magnetic constant is μ_0 = 4π × 10^-7 T·m/A, and the magnitude of the magnetic field is B = 3.65 × 10^-5 T. Substituting these values into the formula, we get:
u_B = (3.65 × 10^-5 T)^2 / (2 × 4π × 10^-7 T·m/A) = 1.27 × 10^-11 J/m^3
Therefore, the energy density of the magnetic field is approximately 1.27 × 10^-11 J/m^3.
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Related Questions
By referring to Standard Method of Measurement 2 (SMM2), explain the following clauses:
i. D.10
ii. D.12.4
iii. D.12.6
iv. D.12.8
Answers
SMM2 refers to the Standard Method of Measurement 2. It is a document that specifies the method and processes used in measuring buildings and civil engineering works. SMM2 is commonly used in the construction industry.
The following are explanations of the clauses under Standard Method of Measurement 2 (SMM2):
i. D.10: This clause under SMM2 relates to the painting of metal and timber surfaces. It stipulates that when painting the surfaces of timber or metal, the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.
ii. D.12.4: This clause under SMM2 refers to the construction of walls using concrete blocks. It states that the concrete blocks used should have a minimum density of 1500 kg/m3. It also outlines specific measurements for the thickness of the mortar to be used for bonding the blocks together. The clause further specifies the measurement of the joint thickness between blocks.
iii. D.12.6: This clause under SMM2 refers to the rendering of walls with a cement mortar mix. It specifies that before rendering, the surface of the wall must be clean, dry, and free of debris. It also outlines specific measurements for the thickness of the rendering to be applied to the wall. The clause then stipulates that the rendering should be finished with a smooth surface that conforms to the architect's specifications.
iv. D.12.8: This clause under SMM2 refers to the painting of interior plastered walls. It stipulates that the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.
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Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.34 kW/m2. How long does it take (in days) for 1.73 ✕ 109 J to arrive on an area of 9.03 m2?
Answers
Given :
Intensity, I = 1.34 kW/m².
Area, A = 3.28 m².
To Find :
Time taken to arrive.
Solution :
Power is given by :
P = I × A
P = 1.34 × 3.28 × 1000 W
P = 4395.2 W
Also, power is given by :
P = E/t
t = E/P
t = 1.73 × 10⁹ J/4395.2 W
t = 393611 s
Converting this time in second to days, we get :
t = 393611/( 24×60×60) days
t = 4.55 days.
Hence, this is the required solution.
State Newton's third law
Answers
Answer:
newtons third law was that every action has an equal and opposite reaction.
12. Which of the following statements is accurate?
A. If an object's velocity is changing, it's experiencing either acceleration or deceleration.
B. If an object's velocity decreases, then the object is accelerating
C. If an objects said to be decelerating, its velocity must be increasing,
D. If an object's velocity remains constant, its acceleration must be increasing.
Answers
Answer:
Option (a) is correct
Explanation:
The acceleration of an object is defined as the rate of change of velocity. Mathematically, it can be written as :
\(a=\dfrac{v-u}{t}\)
Where
v and u are final and initial velocity
It is clear that if there is some change in velocity, it means the object is experiencing either acceleration or deceleration. Hence, the correct option is (a).
Answer:
a
Explanation:
What is a cars acceleration in the direction of motion when velocity changes from 20. M/s to 60. M/s in 10. S
Answers
Answer:
Acceleration, \(a=4\ m/s^2\)
Explanation:
Given that,
Initial velocity, u = 20 m/s
Final velocity, v = 60 m/s
Time, t = 10 s
We need to find the acceleration of the car. It is equal to the change in velocity divided by time.
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2\)
So, the acceleration of the car is \(4\ m/s^2\).
what happens to the molecules when carbon dioxide is heated
Answers
When the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.
CO2 → CO + O
This is the basic reaction expected to happen by carbon dioxide molecules are heated. However it may also disintegrate into C2, O2, C, etc.
Since heat is absorbed in this reaction, it is an example of endothermic reaction. In an exothermic reaction heat is released. These are the basic two types of chemical reactions on basis of heat.
Therefore, when the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.
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_______ is responsible for all the genetic material in living things. DNA Codon Anticodon Replication
A. DNA
B. Codon
C. Anticodon
D. Replication
Answers
A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of . The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.
Answers
Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
\(F\text{ =2}\times10^4\text{ N}\)The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
\(\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}\)The power of the wind will be
\(\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}\)
Air displacement between two air masses of different temperature, pressure, humidity, wind speed and direction, and cloud development is an example of ________ lifting.
Answers
Air displacement between two air masses of different temperature, pressure, humidity, wind speed and direction, and cloud development is an example of frontal lifting.
What is air displacement?
Air displacement is a phenomenon in which one gas or liquid is displaced or pushed out of the way by another gas or liquid. This displacement happens when two fluids of different densities are mixed together, and the force of gravity pulls the denser fluid downward, displacing the lighter fluid upward.
What are air masses?
Air masses are large bodies of air with uniform temperature, humidity, and pressure. They form over a particular region, and their characteristics are influenced by the location of the region, the time of year, and the type of surface they are over.
What is cloud development?
Cloud development is the process by which clouds form from water vapor in the atmosphere. Clouds are made up of tiny water droplets or ice crystals that have formed around particles in the air.
What is frontal lifting?
Frontal lifting is the process by which air is lifted up and away from the surface of the earth along a front or boundary between two air masses of different temperature, humidity, wind speed, and direction. This process can cause clouds to form as the lifted air cools and its moisture condenses into tiny water droplets or ice crystals.
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I need help pls. Solve 1+cos 30º/1-sin 30º. Plz help me
Answers
Answer:
\( \huge \boxed{ \boxed{2 + \sqrt{3}}} \)
Explanation:
to understand thisyou need to know about:trigonometryPEMDASgiven:\( \frac{1 + \cos( {30}^{o} ) }{1 - \sin( {30}^{o} ) } \)tips and formulas:cos(30°)=\(\frac{\sqrt{3}}{2}\)\( \sin( {30}^{o} ) = \frac{1}{2} \)let's solve:\( \sf sustitute \: the \: value \: of \: \sin( {30}^{o} ) and \cos( {30}^{o} ) \\ \sf \frac{1 + \frac{ \sqrt{3} }{2}}{1 - \frac{1}{2} } \)\( \sf simplify : \\ \frac{ \frac{2 + \sqrt{3} }{2} }{ \frac{1}{2} } \)\( \sf simplify(fraction) : \\ \frac{2 + \sqrt{3} }{2} \div \frac{1}{2} \\ \frac{2 + \sqrt{3} }{2} \times 2 \\ \therefore 2 + \sqrt{3} \)an object has volume of 5cm and a mass of 20 g what is the density of the object
Answers
Density =20/5 = 4g/cm^3
a gardener mounts a pot plant on the wall using a metal ring and a chain the ring exerts a horizontal force of 20n on the pot plant and the weight of the pot plant is 30n determine the magnitude of the chain by calculation and construction
Answers
The magnitude of the force exerted by the chain is 36.1 N.
Resultant forcesThe magnitude of the force exerted by the chain must balance the force exerted by the ring and weight of the pot.
The magnitude of the force exerted by the chain is calculated by applying Pythagoras theorem;
\(F_3^2 = F_1^2 + F_2^2\\\\F_3 = \sqrt{F_1^2 + F_2^2} \\\\F_3 = \sqrt{20^2 + 30^2} \\\\F_3 = 36.1 \ N\)
Thus, the magnitude of the force exerted by the chain is 36.1 N.
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Solve for the amount of moles of Cl2 gas in 5.55 x 1024 molecules of Cl2 gas
Help please!
Answers
There are roughly 9.22 moles of Cl2 gas in 5.55 x \(10^{24\) molecules of Cl2 gas.
Divide the given number of molecules by Avogadro's number to get the amount of moles of Cl2 gas.
To solve for the amount of moles of Cl2 gas in 5.55 x \(10^2^4\) molecules of Cl2 gas, we need to use Avogadro's number, which is the number of particles in one mole of a substance.
Avogadro's number is approximately 6.022 x \(10^2^3\) particles per mole.
To find the amount of moles of Cl2 gas, we simply divide the given number of molecules by Avogadro's number.
So, 5.55 x \(10^2^4\) molecules of Cl2 gas divided by 6.022 x \(10^2^3\) particles per mole equals approximately 9.22 moles of Cl2 gas.
Therefore, the amount of moles of Cl2 gas in 5.55 x \(10^2^4\) molecules of Cl2 gas is approximately 9.22 moles.
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Kim's policy remained in force for a certain number of days even though she forgot to pay the premium. the provision that allows this is called?
Answers
Kim's policy remained in force for a certain number of days even though she forgot to pay the premium. the provision that allows this is called grace period provision
If the policyowner fails to make the premium payments due to some issue or reason, the insurance company will not immediately cancel the policy , whereas the company will wait for few days if no action seen than only they will take action on that account .
The grace period provision allots a specifically designated amount of time in which the policyowner has to make the required premium payments after the stipulated due date.
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please help me
sub -physics, topic-laws of motion
Answers
The maximum angular speed of the turntable to avoid slipping is option (2), √(µg/x).
How to determine angular speed?The maximum angular speed of the turntable can be found by equating the centrifugal force with the frictional force acting on the block.
At maximum angular speed, the centrifugal force acting on the block is given by F = mRω², where R = x is the distance of the block from the center and ω is the angular speed of the turntable.
The frictional force acting on the block is f = µN, where N is the normal force on the block.
At maximum angular speed, the normal force N is equal to the weight of the block, N = mg.
Equating the centrifugal force and the frictional force:
mRω² = µN
mRω² = µmg
ω² = µg/R
ω = √(µg/R)
Substituting R = x:
ω = √(µg/x)
Therefore, the maximum angular speed of the turntable so that the block does not slip is given by √(µg/x).
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A monorail starts from rest and accelerates at a rate of 2.2m/s2 for 10s.Then it runs at a constant speed for 74s and then slows down at a rate of 1.5m/s2
Answers
Answer:
d = 4217 m
Explanation:
Case 1.
Initial velocity, u = 0
Acceleration, a = 2.2 m/s²
Let d₁ is the distance in case 1. Using second equation of motion as follows :
\(d_1=ut+\dfrac{1}{2}a_1t_1^2\\\\\text{Here, u =0}\\\\d_1=\dfrac{1}{2}\times 2.2\times 10^2\\\\d_1=110\ m\)
Let d₂ in the distance in case 2. Using second equation of motion as follows :
\(d_2=ut+\dfrac{1}{2}a_2t_2^2\\\\\text{Here, u =0}\\\\d_2=\dfrac{1}{2}\times 1.5\times 74^2\\\\d_2=4107\ m\)
Total distance,
D = d₁ + d₂
D = 110 + 4107
D = 4217 m
Hence, the total distance covered is 4217 m.
A wave has a frequency of 60 Hz and a wavelength of 1.7 meters. What is the speed of this wave? equation, substitution
Answers
Answer:
v = 102 m/s
Explanation:
Given that,
The frequency of a wave, f = 60 Hz
Wavelength = 1.7 m
We need to find the speed of this wave. The formula for the speed of a wave is given by
\(v=f\lambda\)
Substitute all the values,
\(v=60\times 1.7\\\\v=102\ m/s\)
So, the speed of the wave is equal to 102 m/s.
if you 235lb traviling north at 75mph and strike a 150 lb deer going 35mph east what is the force
Answers
We need to use the formula: Force = Mass × Acceleration Let's use the given values to calculate the force exerted on the deer when it is hit by the car. The car weighs 235 lb and it is traveling north at 75 mph. The deer weighs 150 lb and it is going 35 mph east. Force = 44045 lbSince the force is a vector quantity, it has both magnitude and direction.
Step 1: Convert the velocities into feet per second.1 mile = 5280 feet1 hour = 3600 seconds So, the velocity of the car is:75 mph = (75 × 5280) ÷ 3600 = 110 feet/secondThe velocity of the deer is:35 mph = (35 × 5280) ÷ 3600 = 51.3 feet/second
Step 2: Find the components of velocity of the deer. The velocity of the deer is in the east direction, so we need to find its horizontal component, vx, and its vertical component, vy. If the angle between the deer's velocity and the x-axis is θ, then: vx = v × cosθandvy = v × sinθv = 51.3 feet/secondθ = 90° - arctan(0 / 110) = 90°So,vx = 51.3 × cos90° = 0 feet/second vy = 51.3 × sin90° = 51.3 feet/second
Step 3: Find the net velocities of the car and the deer. Since the car is moving north and the deer is moving east, the net velocity of the car and deer together can be found using the Pythagorean theorem. Net velocity = √[(vx + 110)² + vy²]Net velocity = √[(0 + 110)² + (51.3)²]Net velocity = √(12100 + 2631.69)Net velocity = √14731.69Net velocity = 121.3 feet/second
Step 4: Find the net momentum of the car and the deer. Net momentum = (mass of car × velocity of car) + (mass of deer × velocity of deer)Net momentum = (235 × 110) + (150 × 121.3)Net momentum = 25850 + 18195Net momentum = 44045 lb ft/second
Step 5: Find the force exerted on the deer. Force = Net momentum ÷ time Here, time is the duration of the collision which is not given in the problem. We will assume it to be 1 second. Force = 44045 ÷ 1
Force = 44045 lb Since the force is a vector quantity, it has both magnitude and direction. The direction of force is along the line of impact which is not given in the problem.
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A crane does work at the rate of 2.5 x10^3 watts to lift a 200-newton weight vertically for duration of 8.0 seconds. Calculate the height the crane lifts the weight over this time period.
Answers
The height the crane lifts the weight over the time period of 8.0s is 100m when it does work at the rate of \(2.5 *10^3\) watts to lift a 200-newton weight.
Given the rate of work done by crane (P) = \(2.5 * 10^3\)watts
The force exerted to lift a weight (F) = 200N
The duration of which weight was lifted (t) = 8.0s
Let the height the crane lifts the weight during this period = h
Also power is calculated as work done per unit time such that: P = W/t
\(2.5 * 10^3 = W/8.0s\)
\(W = 2*10^4\)
We know that work done on any object = force x distance moved
Work: W = F * d
W = F * h where d = distance = h
\(h = 2 * 10^4/200 = 100m\)
Hence the height the crane lifts the weight over this time period is 100m
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While having a discussion, Technician A says that the longer a conductor is, the more resistance it has and the smaller its diameter, the less resistance it has. Technician B says that the larger its diameter, the less resistance it has. Who is correct
Answers
Answer:
Technician B is correct by saying that the larger diameter (i.e the conductor's diameter), the less resistance it has.
Explanation:
According to the law of electrical resistance, the resistance of a metallic conductor is proportional to the length of the conductor, but inversely proportional to the cross-sectional area of the conductor.
\(R = p\frac{l}{A}\)
where R is the resistance of the conductor.
p is the intrinsic resistivity of the material with which the conductor is made.
l is the length of the conductor.
A is the cross-sectional area of the conductor.
This law simply means that if we increase the length of a conductor, or reduce the area, the electrical resistance of the conductor will increase, and vice versa.
Technician B is correct by saying that the larger diameter (i.e the conductor's diameter), the less resistance it has.
This is because the area of the conductor is proportional to the cross-sectional area. And the larger the cross-sectional area of a conductor, the lesser its resistance will be.
This part of the bike consists of hubs, spokes, rims, and tires (more that answer)
saddle
wheels
crank
brakes
Answers
Answer:
wheels
Explanation:
Answer:
Wheels
Explanation:
I know it says check all that apply so you might think it's more than one, but trust me it's right. I took the test :)
when a shiny chunk of metal with a mass of 1.32 kg absorbs 3250 j of energy, the temperature of the metal increases from 273 k to 292 k. is this metal likely to be silver, lead, or aluminum?
Answers
Answer:
Lead
Explanation:
To figure out if the given metal is silver, lead, or aluminum, we have to calculate its specific heat capacity, which is the heat energy required to raise the temperature of one kilogram of the respective substance by one degree Celsius (or one Kelvin).
To do that, we can use the following formula:
\(\boxed{C = \frac{Q}{m \cdot \Delta T}}\),
where:
• C ⇒ specific heat capacity (J kg⁻¹ K⁻¹)
• Q ⇒ heat energy (J)
• m ⇒ mass of object (kg)
• ΔT ⇒ change in temperature (K)
Using the given information and the formula above, we can calculate the specific heat capacity of the given metal:
\(\mathrm {C = \frac{3250 \ J}{1.32 \ kg \times (292 - 273) \ K }}\)
= 129. 6 J kg⁻¹ K⁻¹
Therefore, the metal is lead, because the specific heat capacity of lead is around 130 J kg⁻¹ K⁻¹, which is very close to the answer we got.
How much does mastering physics cost?
Answers
The cost of using Mastering Physics can vary depending on several factors, such as the institution and the specific course. The cost of these codes can range from $50 to $150 or more, depending on the length of access and the number of courses included.
Some institutions may include the cost of using Mastering Physics as part of their tuition fees. Typically, students purchase access codes that are valid for a certain period. Mastering Physics is an online platform designed to supplement physics courses for students. It provides interactive tutorials, homework assignments, and other educational resources to enhance the learning experience.
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Which of the following is a result of the transfer of energy?
- gravity
- matter
- magnetism
- sound
Answers
Answer: Sound
Explanation: it's asking which of the following is a result of transfer of energy and sound comes from vibrations
a set of related measures or activities with a particular long term aim
Answers
Answer:
program explanation
Explanation:
program explanation
The set of activities having a long-term aim should be a program.
What is the program?A program refers to a set of instructions that a computer follows in order to perform a specific task. At the time When you program a computer, you provide it a set of instructions to make it able to perform a particular task.
So here the program should be considered.
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A dart is thrown horizontally with an initial speed of 19 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ
Answers
Answer:
Explanation:
The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².
Distance PQ covered by the dart can be calculated using the following formula.
s = ut + 1/2 at²
u is initial velocity , a is acceleration and t is time.
Putting the values
s = 0 + 1/2 x 9.8 x .19²
= .1769 m
= 17.69 cm.
HELP ME a hot air balloon is rising upward with a constant velocity of 4.0 m/s. As the balloon reaches a height of 4.0 m above the ground, the balloonist accidently drops a can of pop over the edge of the basket. How long does it take the pop can to reach the ground?
Answers
It takes approximately 1.2 seconds for the pop can to reach the ground after being dropped by the balloonist. To answer your question, we can use the kinematic equation is given below.
h = vi*t + 0.5*a*t²
we need to consider the initial conditions of the falling pop can. When the balloonist accidentally drops the can, it has an initial velocity equal to the upward velocity of the hot air balloon, which is 4.0 m/s. Also, the initial height of the can is 4.0 meters above the ground.
Since the can is now in free fall, it will be acted upon by gravity, which has an acceleration of -9.8 m/s² (negative because it's downward). We can use the following equation of motion to find the time it takes for the pop can to reach the ground:
h = vi*t + 0.5*a*t²
Where h is the height (4.0 m), vi is the initial velocity (4.0 m/s), a is the acceleration due to gravity (-9.8 m/s²), and t is the time we want to find.
Rearranging the equation for t, we get:
t = [(-2*h) / (vi - 0.5*a)]^(1/2)
Plugging in the given values:
t = [(-2*4) / (4 - 0.5*(-9.8))]^(1/2)
t ≈ 1.2 seconds
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An airplane must reach a speed of 88 m/s in order to gain enough lift force need to take off and fly through the air. If it takes a plane 19.7 seconds to reach take-off speed, then what is the plane's acceleration (in m/s2). Express your answer to the nearest 2 decimals.
Answers
Answer:
See below
Explanation:
vf = vo + at vf = final velocity vo = original velocity
88 = 0 + a (19.7)
a = 88/19.7 = 4.47 m/s^2
Light has both a wave and a particle nature. Particles have a wave nature as well, and therefore.
Answers
Light has both a wave and a particle nature. Particles have a wave nature as well, and therefore their position can not be specified with absolute precision
This is a consequence of the Heisenberg uncertainty principle enunciated in 1927, after the works of the French physicist Louis De Broglie who proposed the existence of matter waves, that is to say, that all matter has a wave associated with it.
The uncertainty principle postulates that the fact that each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.
It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.
So, the greater certainty is sought in determining the position of a particle, the less is known about its linear momentum and, therefore, its mass and velocity.
It should be noted that this uncertainty does not derive from the measurement instruments, but from the measurement itself. Because, even with the most precise devices, the uncertainty in the measurement continues to exist.
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What is the centripetal acceleration of an object moving 25 m/s around a 6 m curve?
O 104.2
O 84.2
O 64.2.
O 44.2
Answers
Answer:
Centripetal acceleration = 104.2 (Approx)
Explanation:
Find:
Centripetal acceleration
Given:
Velocity = 25 m/s
Radius r =6 m
Computation:
Centripetal acceleration = v² / r
Centripetal acceleration = 25² / 6
Centripetal acceleration = 104.467
Centripetal acceleration = 104.2 (Approx)