a. The total distance travelled is 17.2 km.
b. The total displacement is 15.16 km.
c. The total time taken is 901.1 s.
d. The average speed in m/s is 19.07 m/s.
e. The magnitude of the average velocity is 16.8 m/s.
To calculate the quantities, we need to convert units to ensure consistency.
a. To find the total distance travelled, we sum the distances travelled by boat and car. The boat travels 2.2 km, and the car travels (60 km/h) × (15 min) × (1/60 h/min) = 15 km.
Therefore, the total distance travelled is 2.2 km + 15 km = 17.2 km.
b. The total displacement is the straight-line distance between the starting point and the final destination, taking direction into account. The boat moves east, and the car moves north.
Thus, the displacement is given by the Pythagorean theorem as √((2.2 km)² + (15 km)²) = √(4.84 km² + 225 km²) = √(229.84 km²) ≈ 15.16 km.
c. The total time taken is the sum of the time taken by the boat and the car. The boat takes (2.2 km) / (2.0 m/s) = 1.1 s. The car takes (15 min) × (60 s/min) = 900 s. Thus, the total time taken is 1.1 s + 900 s = 901.1 s.
d. The average speed is given by the total distance travelled divided by the total time taken. Converting km to meters, we have (17.2 km) × (1000 m/km) = 17200 m.
Therefore, the average speed is 17200 m / 901.1 s ≈ 19.07 m/s.
e. The magnitude of the average velocity is the absolute value of the displacement divided by the total time taken.
Thus, the magnitude of the average velocity is 15.16 km / 901.1 s ≈ 0.0168 km/s ≈ 16.8 m/s.
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PLZ HELP, GIVING BRAINLIEST!!
A student uses a 320 Hz tuning fork during a lab investigation into the speed of sound. If the air temperature in the classroom is 20 degrees Celsius, what is the wavelength of the sound waves produced by the tuning fork?
A. 1.07 m
B. 3.43 m
C. 0.933 m
D. 343 m
E. 343 m
Answer:343m
Explanation:
What is the length of the rod as measured by this ruler?
2.0 cm
2.1 cm
2.2 cm
2.3 cm
2.2 CM is your answer
jfkanfnakcndbcnd
Answer:
2.2 cm
Explanation:
milimeters are the little hash marks and there are ten so it is 2.2 cm
1. A wave with a frequency of 10 Hz has a wavelength of 3 meters. At what
wave speed will this wave travel?
Answer:
30 m\ s Ans .....
Explanation:
Data:
f = 10 Hz
w = 3 m
v = ?
Formula:
v = fw
Solution:
v = ( 10)(3)
v = 30 m\ s Ans ........
what is the correct answer?
Answer:
4
Explanation:
I added all of them and them minus the 5.
combination unit is an air conditioner that contains components for cooling and heating in one sheet metal cabinet. True or False
Combination unit is an air conditioner that contains components for cooling and heating in one sheet metal cabinet. this is true statement.
What is combination unit of an air conditioner?Heating and cooling are often taken for granted by most people. In the winter and summer, we'll count on the heating and air conditioning to keep us comfortable. You may be able to save money and have a more comfortable environment with a single system that controls both. We may offer combination heating and air conditioning units at Climate Environmental, which will comprise air conditioning systems and heating units that will supply both warm air and cold air with the touch of a remote control.
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Calculate the speed of a bus that travels a distance of 55 miles in 0.75 hours.
when a light ray passes from water ( n = 1.333) into diamond ( n = 2.419) at an angle of 45 °, its path is
When a light ray passes from water (with a refractive index of 1.333) into diamond (with a refractive index of 2.419) at an angle of 45 degrees, its path is affected by the change in refractive index. Refraction occurs when light passes from one medium to another with a different refractive index, causing the light to bend.
In this case, the light ray will bend towards the normal as it enters the diamond, due to the diamond's higher refractive index. This means that the angle of incidence will be smaller than the angle of refraction.
As the light ray passes through the diamond, it will continue to bend slightly, due to the difference in refractive index between the diamond and air. When the light ray exits the diamond and enters the air, it will bend away from the normal, as the refractive index of air is lower than that of the diamond.
Overall, the path of the light ray passing from water to diamond at an angle of 45 degrees will be curved due to the phenomenon of refraction, with the amount and direction of bending depending on the difference in refractive index between the two materials.
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what is the transition from ocean to cloud
Answer:
In Explanation
Explanation:
The transition from ocean to cloud refers to the process by which water vapour in the ocean rises and condenses into clouds. This process is known as evaporation and is a key component of the water cycle.
Evaporation occurs when the sun's energy heats the surface of the ocean, causing water molecules to gain enough energy to escape into the atmosphere as water vapour. As the water vapour rises, it cools and condenses into tiny droplets, which form clouds. The clouds can be made of water droplets or ice crystals, and they can be observed in the sky in different forms, such as stratus clouds, cumulus clouds, and cirrus clouds.
This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature by reflecting and absorbing solar radiation. Clouds also affect precipitation, as the droplets or crystals in the clouds grow and fall as rain or snow. The transition from ocean to the cloud is also important for the water cycle as precipitation, either in form of rain or snow, replenishes the water in the oceans and rivers.
In summary, the transition from ocean to the cloud is the process by which water vapour in the ocean rises and condenses into clouds, known as evaporation, and is a key component of the water cycle. This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature and affecting precipitation, and replenishing the water in the oceans and rivers.
(Please give brainlist)
PLEASE HELPPP
Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west
Jupiter takes 9.9259 hours to rotate on its axis and has a tangential speed of 12,293 m/s. What is the radius of Jupiter? 7,781.6 km 19,420 km 48,893 km 69,912 km
The radius of Jupiter is 11.37 × 10^6 km (approx).
The correct answer to the given question is option D.
Jupiter is a giant planet in our solar system and takes 9.9259 hours to rotate on its axis. The tangential speed of Jupiter is given to be 12,293 m/s. We are required to find out the radius of Jupiter.
Given Data:
Rotation period of Jupiter, T = 9.9259 hours
Tangential speed of Jupiter, v = 12,293 m/s
Formula Used:
Radius of Jupiter, r = v × T / (2π)
Calculation:
We can find the radius of Jupiter using the above formula.
Substituting the given values in the formula, we get:
r = 12,293 × 9.9259 × 60 × 60 / (2π)r = 71,492,602.68 / (2π)r = 11,371,641.26 km ≈ 11.37 × 10^6 km.
Therefore, the radius of Jupiter is 11.37 × 10^6 km (approx).
Hence, the correct option is 69,912 km.
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Una muestra de agua de 250g de agua se caliento desde 10°C hasta 60°C calcula la cantidad de calor absorbido por el agua el calor especifico del agua es de 4186J/Kj.K
Answer:
Calor absorbido, Q = 52325 Joules
Explanation:
Dados los siguientes datos;
Masa = 250g to kg = 250/1000 = 0.25kg
Temperatura inicial, T1 = 10°C to Kelvin = 273 + 10 = 283K
Temperatura final, T2 = 60°C to Kelvin = 273 + 60 = 333K
Capacidad calorífica específica = 4186 j/kg.K.
Para encontrar la cantidad de calor necesaria;
La capacidad calorífica viene dada por la fórmula;
\( Q = mct \)
Dónde;
Q representa la capacidad calorífica o la cantidad de calor.
m representa la masa de un objeto.
c representa la capacidad calorífica específica del agua.
dt representa el cambio de temperatura.
dt = T2 - T1
dt = 333 - 283
dt = 50 K
Sustituyendo en la fórmula, tenemos;
\( Q = 0.25*4186*50\)
\( Q = 52325 \)
Calor absorbido, Q = 52325 Joules
How long was a 50 W lightbulb left on for if 500,002 J were burned?
" 50 W " means " 50 Watts " or " 50 Joules per second ".
(500,002 J) / (50 J/sec) = 10,000.04 seconds
(That's 2 hours 46 minutes 40.04 seconds.)
Gold atoms find their "birth" inside of huge _________.
Explanation:
he is very keen on taking up and is the age
A 0.41 kg particle moves in an xy plane according to x(t) = - 11 + 1 t - 5 t3 and y(t) = 19 + 3 t - 9 t2, with x and y in meters and t in seconds. At t = 1.4 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
It looks like you're given
\(x(t) = -11\,\mathrm m + \left(1\dfrac{\rm m}{\rm s}\right) t - \left(5\dfrac{\rm m}{\mathrm s^3}\right) t^3\)
\(y(t) = 19\,\mathrm m + \left(3\dfrac{\rm m}{\rm s}\right) t - \left(9\dfrac{\rm m}{\mathrm s^2}\right) t^2\)
The particle's position vector at time \(t\) is given by
\(\vec r(t) = x(t)\,\vec\imath + y(t)\,\vec\jmath\)
Differentiate \(\vec r\) twice to recover the velocity and acceleration vectors.
\(\vec a(t) = \dfrac{d\vec v(t)}{dt} = \dfrac{d^2\vec r}{dt^2} = x''(t)\,\vec\imath + y''(t)\,\vec\jmath \\\\ \implies \vec v(t) = \left(1\dfrac{\rm m}{\rm s} - \left(15\dfrac{\rm m}{\mathrm s^3}\right) t^2\right)\,\vec\imath + \left(3\dfrac{\rm m}{\rm s} - \left(18\dfrac{\rm m}{\mathrm s^2}\right) t\right) \,\vec\jmath \\\\ \implies \vec a(t) = -\left(30\dfrac{\rm m}{\mathrm s^3}\right)t \, \vec\imath - \left(18\dfrac{\rm m}{\mathrm s^2}\right) \,\vec\jmath\)
At \(t=1.4\,\rm s\), the particle has acceleration
\(\vec a(1.4\,\mathrm s) = \left(-42\,\vec\imath - 18\,\vec\jmath) \dfrac{\rm m}{\mathrm s^2}\)
with magnitude
\(\|\vec a(1.4\,\mathrm s)\| = \sqrt{\left(-42\dfrac{\rm m}{\mathrm s^2}\right)^2 + \left(-18\dfrac{\rm m}{\mathrm s^2}\right)^2} \approx 45.695\dfrac{\rm m}{\mathrm s^2}\)
and making an angle \(\theta\) relative to the positive \(x\)-axis such that
\(\tan(\theta) = \dfrac{-18}{-42} = \dfrac37\)
Since both components of the acceleration vector have negative sign, the acceleration points into the third quadrant, so that we add a multiple of 180° after taking the inverse tangent of both sides, namely
\(\theta = \tan^{-1}\left(\dfrac37\right) - 180^\circ \approx -156.801^\circ\)
Now, (a) the magnitude of the net force acting on the particle is, by Newton's second law,
\(F = (0.41\,\mathrm{kg})\|\vec a(1.4\,\mathrm s)\| \approx \boxed{18.735\,\mathrm N}\)
and (b) makes the same angle as the acceleration vector, \(\theta \approx \boxed{-156.801^\circ}\).
At this moment, its velocity vector is
\(\vec v(1.4\,\mathrm s) = \left(-28.4\vec\imath - 22.2\,\vec\jmath\right) \dfrac{\rm m}{\rm s}\)
which (c) makes an angle \(\theta\) such that
\(\tan(\theta) = \dfrac{-22.2}{-28.4} = \dfrac{111}{142}\)
This vector also points in the third quadrant, so
\(\theta = \tan^{-1}\left(\dfrac{111}{142}\right) -180^\circ \approx \boxed{-142.986^\circ}\)
How many cups of water should you drink in a day?
Answer:
about 2.7liters for women and 3.7liters for men
Explanation:
What is the numeric value of the prefix "micro"?
a. 0.00001
b. 0.000001
c. 0.0001
d. 0.001
What is the numeric value of the prefix "micro"?
a. 0.00001
b. 0.000001 ✓"Micro" is a prefix that is used to indicate a value of the factor 10^-6 and means very minute.c. 0.0001
d. 0.001
what revovles around the sun and is made out of rock,ice,gas,and dust?
Answer:
Comets are cosmic snowballs of frozen gases, rock and dust that orbit the Sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the Sun, it heats up and spews dust and gases into a giant glowing head larger than most planets.Hope this is fine for you,,!!Pagkatuto Bilang 2: Anong pagsubok ang ipinakikita sa Ibigay ang tawag sa pagsubok na ito. Gawin ito sa inyong Gawain sa larawan. kuwaderno.
P.E.
Answer:
Three Minute Step Test
Push Up
Zipper Test
Sorry di ko po alam lahat
Suppose you drop a rock into a dark well and, using precision equipment, you measure the time for the sound of a splash to return. Neglecting the time required for sound to travel up the well, calculate the distance to the water if the sound returns in 2. 00 s.
Answer:
Approximately \(19.6\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance is negligible.)
Explanation:
Assume that the air resistance on the rock is negligible. During the descent, the acceleration \(a\) of the rock will be constant: \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\).
It is given that the descent took \(t = 2.00\; {\rm s}\). Let \(x\) denote the displacement (change in position) of the stone. Apply the SUVAT equation \(x = (1/2)\, a\, t^{2}\) to find displacement \(x\!\):
\(\begin{aligned}x &= \frac{1}{2}\, a\, t^{2} \\ &= \frac{1}{2}\, ((-9.81)\; {\rm m\cdot s^{-2}})\, (2.00\; {\rm s})^{2} \\ &\approx (-19.6)\; {\rm m}\end{aligned}\).
Note that \(x\) is negative since the water is below the initial position of the rock. Therefore, the distance to the water will be approximately \(19.6\; {\rm m}\).
The current through a certain heater wire is found to be fairly independent of its temperature. If the current through the heater wire is doubled, the amount of energy delivered by the heater in a given time interval will.
The amount of energy delivered by the heater in a given time interval will be increase by a factor of four
Given:
Current in wire = I
current is double = 2I
To Find:
amount of energy delivered by the heater
Solution:
Scientists define energy as the ability to do work.
The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.
E = Power x Time = P x T
P = (I)^2 x T
E' = (2I)^2 x T
E' 4I^2T
E' = 4E
So, amount of energy delivered by the heater will be four time initial energy
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A mass suspended from a spring is pulled down a distance of 2 feet from its rest position. The mass is
released at time t=0 and allowed to oscillate. The mass returns to this position after 1 second.
Additionally, during a cycle it reaches a maximum height of 2 feet above its rest position.
Sketch a graph of this scenario and write an equation.
Two solid spheres, both of radius 5 cm, carry identical total charges of 2 μC. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume. How do the magnitudes of the electric fields they separately create at radius 4 cm compare? a. EA=EB>0
b. EA>EB=0
c. EB>EA=0
d. 0
e. EA>EB>0
Two solid spheres with identical charge imbalance of 2 C have radii of 5 cm each. A is an excellent conductor, or sphere A. As an insulator, sphere B's charge is dispersed evenly throughout its volume.
A charge is what?
the sum of money required to purchase something, particularly a service: levy/impose/experience a fee You will be charged if you don't cancel the reservation within the allotted time. the cost of sb/sth Do kids pay anything or are they admitted free minimal or modest charge For this service, we charge a small fee.
What does charge mean in physics and chemistry?
August 8, 2017 update. Charge often refers to electric charge in chemistry and physics, which is a conserved feature of some subatomic particles that governs their electromagnetic interaction. An electromagnetic field exerts a force on matter as a result of the physical attribute of charge.
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college physics two teams of seven members each engage in a tug of war. each of the first team’s members has an average mass of 64.0 kg and exerts an average force of 1427 n horizontally. each of the second team’s members has an average mass of 70.0 kg and exerts an average force of 1443 n horizontally. what is the acceleration of the two teams?
The acceleration of Team 1 and Team 2 are 22.3 m/\(s^{2}\) and 20.6 m/\(s^{2}\) respectively.
We have a game of tug of war between two teams.
We have to determine the acceleration of both the teams.
What is Force ?Force is the product of mass and its acceleration for a moving body. Mathematically -
F = ma
According to the question, we have -
TEAM - 1 :
The acceleration of team 1 can be calculated as follows -
F(1) = m(1) a(1)
a(1) = F(1) / m(1) = 1427 / 64 = 22.3 m/\(s^{2}\)
TEAM - 1 :
The acceleration of team 2 can be calculated as follows -
F(2) = m(2) a(2)
a(2) = F(2) / m(2) = 1443 / 70 = 20.6 m/\(s^{2}\)
Hence, the acceleration of Team 1 and Team 2 are 22.3 m/\(s^{2}\) and 20.6 m/\(s^{2}\) respectively.
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A uniform magnetic field B has a strength of 5.5 T and a direction of 25.0° with respect to the +x-axis. A proton (1.602e-19)is traveling through the field at an angle of -15° with respect to the +x-axis at a velocity of 1.00 ×107 m/s. What is the magnitude of the magnetic force on the proton?
The magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.
Given values: B = 5.5 Tθ = 25°q = 1.602 × 10⁻¹⁹ VC = 1.00 × 10⁷ m/s Formula: The formula to calculate the magnetic force is given as;
F = qvBsinθ
Where ;F is the magnetic force on the particle q is the charge on the particle v is the velocity of the particle B is the magnetic field strengthθ is the angle between the velocity of the particle and the magnetic field strength Firstly, we need to determine the angle between the velocity vector and the magnetic field vector.
From the given data, The angle between velocity vector and x-axis;α = -15°The angle between magnetic field vector and x-axis;β = 25°The angle between the velocity vector and magnetic field vectorθ = 180° - β + αθ = 180° - 25° - 15°θ = 140° = 2.44346 rad Now, we can substitute all given values in the formula;
F = qvBsinθF
= (1.602 × 10⁻¹⁹ C) (1.00 × 10⁷ m/s) (5.5 T) sin (2.44346 rad)F
= 4.31 × 10⁻¹¹ N
Therefore, the magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.
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Why is it that an object can accelerate while
traveling at constant speed, but not at constant velocity?
For the same reason that you can skate around a curve at constant speed but not with constant velocity.
The DIRECTION you're going is part of your velocity, but it's not part of your speed.
If the DIRECTION changes, that's a change of velocity.
The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.
And any change of velocity is called acceleration.
imura lifts a box by bending at the knees, then slowly standing up and holding the box away from her body. is this an effective and safe lifting technique?
No, as she kept the box a safe distance from her body. As closely as you can, hug the load to your body.
Which three safe lifting methods are there?Lift gradually by extending your hips and knees (not your back). As you raise, keep your back straight and avoid twisting. Hold the load at the level of your belly button, as near to your body as you can.
Safe lifting technique?Keep the burden as near to your body as you can, if at all possible. Perhaps this is preferable to fiercely clutching it in your hands. As opposed to either entirely flexing your back (stooping) or fully flexing your hips and knees (full/deep squatting), it is ideal to slightly bend your back, hips, and knees at the beginning of the lift.
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at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 a , what is the magnitude of the velocity of the bar?
The magnitude of the velocity of the bar at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A is 24.62 m / s
I = B l v / R
I = Induced current
B = Magnetic field
l = Length of bar
v = Velocity
R = Resistance
I = 1.73 A
B = 1.34 T
l = 0.293 m
R = 5.55 Ω
v = I R / B l
v = ( 1.73 * 5.55 ) / ( 1.34 * 0.293 )
v = 9.6 / 0.39
v = 24.62 m / s
Therefore, the the magnitude of the velocity of the bar is 24.62 m / s
The given question is incomplete. The complete question is :
A 0.293m -long bar moves on parallel rails that are connected through a 5.55 Ω resistor, as shown in the following figure (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.34T that is directed into the plane of the figure. At an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A, what is the magnitude of the velocity of the bar?
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While Rebecca is standing at her locker, she can hear students coming from around the corner. Which wave
interaction explains why she can hear them?
Answer:
Sound waves
Explanation:
The sound waves are bouncing off the walls around the corner
Answer:
Please show the wave interactions to choose from so I can give you an answer
Explanation:
(If diffraction is an answer it should be that!)
kepler's laws hold only for the six planets known in his time.
Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era.
Kepler's laws of planetary motion are fundamental principles that describe the motion of planets around the Sun and were derived based on observational data available to Johannes Kepler during the 16th and 17th centuries. However, these laws are not limited to the six planets known in Kepler's time.
Kepler formulated three laws of planetary motion:
1. Kepler's First Law (Law of Ellipses): Planets orbit the Sun in elliptical paths, with the Sun located at one of the two foci of the ellipse. This law applies to all planets, including those discovered after Kepler's time.
2. Kepler's Second Law (Law of Equal Areas): An imaginary line connecting a planet to the Sun sweeps out equal areas in equal time intervals. This law holds for all planets, regardless of when they were discovered.
3. Kepler's Third Law (Harmonic Law): The square of a planet's orbital period is proportional to the cube of its average distance from the Sun. This law applies to all planets, both the ones known in Kepler's time and the ones discovered later.
Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era. They provide important insights into the motion and behavior of celestial bodies.
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Two friends are pushing an 18-kg crate across the floor. One of them applies a force of 75.0 N to the left, and the crate moves at a constant speed. What force must the other person be applying, and in what direction does the force act?
The force that the other person must apply is 75 N in opposite direction (right).
What is applied force?
Applied force is defined as the force exerted on an object by another body or object.
The force applied by the other person is determined by applying Newton's second law of motion as follows;
F1 - F2= ma
where;
a is acceleration accelerationF1 is the first applied forceF2 is the second applied force in opposite direction to the firstWhen an object moves at constant, acceleration = 0
F1 - F2 = 0
F1 = F2
F1 = 75 N, then F2 = 75 N in opposite direction.
Thus, the force that the other person must apply is 75 N in opposite direction (right).
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