Answer:
D. 18 ÷ 2 = 9
Step-by-step explanation:
The equation matches the equation 18 ÷ 9 = 2
The other equations do not match the previous equations because the previous three equations didn't have a 36 or the number six
I hope this helps!
Answer:
d 18÷2=9
Step-by-step explanation:
The answer is d because the fact family contains 2,9and18.
2×9=18, 18÷9=2and 9×2=18 are already solved. so all you need to do is to study the question and the answer very well.
To find the answer you need to look at the numbers in the question carefully an look for it in the answer.
if cosA=3√2/5,then show that cos2A=11/25
Answer:
Step-by-step explanation:
Cos 2A = 2Cos² A - 1
\(= 2*(\frac{3\sqrt{2}}{5})^{2}-1\\\\=2*(\frac{3^{2}*(\sqrt{2})^{2}}{5^{2}})-1\\\\=2*\frac{9*2}{25} - 1\\\\=\frac{36}{25}-1\\\\=\frac{36}{25}-\frac{25}{25}\\\\=\frac{11}{25}\)
5/8 entre 6 personas
Based on the information we can infer that 5/8 between 6 people is equal to 15/24.
How to divide 5/8 between 6 people?To calculate the part that corresponds to each person, divide the fraction 5/8 by the number of people, which in this case is 6. To simplify the fraction, you can reduce the numerator and denominator by dividing both by their maximum common factor, which is 3.
5 ÷ 3 = 1 and 2 remainder8 ÷ 3 = 2 and 2 remainder
So the fraction can be simplified to 1 2/8, which can also be expressed as 1 1/4 or 5/4 in its most simplified form. This means that each person would receive 5/4 of the original share, and since there are 6 people in total, you can multiply 5/4 by 6 to get the total share that corresponds to all 6 people:
(5/4) x 6 = 30/4 = 15/2 = 15/24
So each person would receive 15/24 of the original amount.
Note: Here is the question in English:
5/8 divided in 6 people
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Attached is a document that I need help on, please help!!!
The ratio of the median weekly earnings is 3 : 5
The ratio of the median weekly earningsFrom the graph, we have the median weekly earnings to be:
High school diploma = $750Bachelor's degree = $1250So, the ratio is:
Ratio = $750 : $1250
Simplify
Ratio = 3 : 5
Hence, the ratio of the median weekly earnings is 3 : 5
The ratio of the area of the red rectangle to the blue rectangle in graph A?
In (a), we have:
Ratio = 3 : 5
The scale on the horizontal axis is given as:
1 unit per grid mark
Both rectangles have a width of 1 unit.
So, we have:
Ratio = 3 * 1: 5 * 1
Simplify
Ratio = 3 : 5
Hence, the ratio of the area of the red rectangle to the blue rectangle in graph A is 3 : 5
The ratio of the area of the red rectangle to the blue rectangle in graph B?In (a), we have:
Ratio = 3 : 5
The scale on the horizontal axis is given as:
1 unit per grid mark
The red rectangle has a width of 3 units, while the blue has 5 units as its width
So, we have:
Ratio = 3 * 3 : 5 * 5
Simplify
Ratio = 9 : 25
Hence, the ratio of the area of the red rectangle to the blue rectangle in graph B is 9 : 25
The ratio of the volume of the red cube to the blue cube in graph C?
In (a), we have:
Ratio = 3 : 5
The scale on the horizontal axis is given as:
1 unit per grid mark
The red rectangle has a width of 3 units, while the blue has 5 units as its width.
Since the base are squares, we have:
Ratio = 3 * 3 * 3 : 5 * 5 * 5
Simplify
Ratio = 27 : 125
Hence, the ratio of the volume of the red cube to the blue cube in graph C is 27 : 125
The most misleading graph
The most misleading graph is graph B.
This is so because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale
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A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. The term paper counts as 20% of the course grade. The final examination counts as 20% of the course grade. Alan has test scores of
92, 78, 82, and 90.
Alan received an 80 on his term paper. His final examination score was 86. Use the weighted mean formula to find Alan's average for the course. (Round your answer to one decimal place.)
Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
Complete the equation to show how to use the distributive property to express the sum of 30 + 45
with a greatest common factor
30 + 45 = ____ ( ____ + ____ )
Answers
15(2 + 3)
5(6 + 9)
75
1,350
Write a quadratic equation with 3/2 and 1/4 as its roots. Write the equation in the form ax2+bx+c=0, where a, b, and c are integers. PLEASE HELP AND SHOW ALL YOUR WORK ILL MARK BRAINLIEST
Answer:
8x^2 -14x +3 = 0
Step-by-step explanation:
The sum of the roots is (3/2) +(1/4) = (6/4 +1/4) = 7/4.
The product of the roots is (3/2)(1/4) = 3/8.
The quadratic can be written as ...
x^2 -(sum of roots)x +(product of roots) = 0
x^2 -7/4x +3/8 = 0
Multiplying by 8 makes all of the coefficients be integers:
8x^2 -14x +3 = 0
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Simplify.
^m√a^2m
help asap please
Answer:
Step-by-step explanation:
m
2
−2m−8
Factor the expression by grouping. First, the expression needs to be rewritten as m
2
+am+bm−8. To find a and b, set up a system to be solved.
a+b=−2
ab=1(−8)=−8
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product −8.
1,−8
2,−4
Calculate the sum for each pair.
1−8=−7
2−4=−2
The solution is the pair that gives sum −2.
a=−4
b=2
Rewrite m
2
−2m−8 as (m
2
−4m)+(2m−8).
(m
2
−4m)+(2m−8)
Factor out m in the first and 2 in the second group.
m(m−4)+2(m−4)
Factor out common term m−4 by using distributive property.
(m−4)(m+2)
Which rule(s) represents a linear function?
Answer:
f(x) = ax + b, where a and b are real numbers.
A house was valued at $299,000 . Over several years, the value decreased by, 9% giving the house a new value.
(a) Fill in the blank to write the new value in terms of the old value.
Write your answer as a decimal.
(b) Use your answer in part (a) to determine the new value.
A) - The NEW VALUE in terms of the old value is 0.91 times the old value.
B) - The NEW VALUE of the HOUSE is: 299,000 * 0.91 = $272,090
Step-by-step explanation:Make A Plan:
A) - Calculate the Percentage of the Value Remaining After the Decrease
B) - Calculate the NEW VALUE of the house
SOLVE THE PROBLEM:
A) - The PERCENTAGE of the VALUE REMAINING AFTER the DECREASE
100% - 9% = 91%
As A DECIMAL:0.91
B) - Calculate the NEW VALUE of the house:
NEW VALUE = OLD VALUE * REMAINING PERCENTAGE
NEW VALUE = 299,000 * 0.91
Draw the conclusion:
A) - The NEW VALUE in terms of the old value is 0.91 times the old value.
B) - The NEW VALUE of the HOUSE is: 299,000 * 0.91 = $272,090
I hope it helps!
given f(x)= 24x^3+14x^2-11x-6 and (2x+1) is a factor, write f(x) as a set of linear factors
The linear factors of the given polynomial is (2x+1)(4x+3) and (3x-2).
What is factorization?The factorization method uses basic factorization formula to reduce any algebraic or quadratic equation into its simpler form, where the equations are represented as the product of factors instead of expanding the brackets. The factors of any equation can be an integer, a variable, or an algebraic expression itself.
The given function is f(x)=24x³+14x²-11x-6 and one of the factor is (2x+1).
Here, 24x³+14x²-11x-6 can be written as 24x³+12x²+2x²+1x-12x-6
12x²(2x+1)+1x(2x+1)-6(2x+1)
= (2x+1)(12x²+1x-6)
= (2x+1)(12x²+1x-6)
= (2x+1)(12x²+9x-8x-6)
= (2x+1)[3x(4x+3)-2(4x+3)]
= (2x+1)(4x+3)(3x-2)
Therefore, the linear factors of the given polynomial is (2x+1)(4x+3) and (3x-2).
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Sample Questions Chapters 3, 12, 13, 14. All of the following contribute to the success of incumbent members of Congress n election campaigns EXCEPT Incumbents.
All of the following contribute to the success of incumbent members of Congress n election campaigns EXCEPT Incumbents tend to understand national issues better than do their challengers.
What does the term incumbent mean?The term "incumbent" has several meanings depending on the context, but it generally refers to someone who holds a particular position or office. The most common usage of this term is in the context of politics, where an incumbent is the current holder of a political office, such as a president, governor, or member of Congress. An incumbent candidate is the candidate who is currently holding a political office and is running for re-election.
In other fields, the term incumbent is used to describe someone who holds a particular job, position or role and is responsible for certain tasks or duties, for example an incumbent employee, an incumbent contractor, an incumbent provider, etc.
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Complete question not found
Consider the quadratic equation 4x² - 11x-3-0. Which of the following shows
this equation rewritten and ready to solve using factoring by grouping?
The factorized form of the quadratic equation is:
4(x - 3)*(x + 0.25) = 0
Which is the factorized form of the quadratic?The quadratic equation is 4x² - 11x -3 = 0
To do that, we need to find the zeros, so let's use the quadratic formula:
\(x = \frac{11 \pm \sqrt{(-11)^2 - 4*4*-3} }{2*4} \\\\x = \frac{11 \pm 13 }{8}\)
Then the two roots are:
x = (11 + 13)/8 = 3
x = (11 - 13)/8 = -2/8 = -0.25
Then the factorized form is:
4(x - 3)*(x + 0.25) = 0
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A health insurance company advertises on television, on radio, and in the local newspaper. The marketing department has an advertising budget of $46,400 per month. A television ad costs $1000, a radio ad costs $200, and a newspaper ad costs $600. The department wants to run 64 ads per month, and have as many television ads as radio and newspaper ads combined. How many of each type of ad can the department run each month?
The number of each type of ad that the department can run each month are:
TV Ads = 32
Radio Ads = 12
News Ads = 20
How to solve Simultaneous equation word problems?x = number of tv ads
y = number of radio ads
z = number of news ads
Two formulas are indicated.
x + y + z = 64
1000x + 200y + 600z = 46400
they want as many tv ads as radio and news ads combined.
equation for that is x = y + z
since x = y + z, replace x with y + z in both equations to get;
y + z + y + z = 64
1000 * (y + z) + 200 * y + 600 * z = 46400
combine like terms and simplify to get:
2y + 2z = 64
1000y + 1000z + 200y + 600z = 46400
combine like terms again to get:
2y + 2z = 64
1200y + 1600z = 46400
Solving simultaneously gives:
y = 12
z = 20
Thus:
x = 12 + 20
x = 32
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Clara makes and sells paintings. The supplies needed to make each painting cost her $13.00. She earns $75.00 for each painting she sells.
Which set of integers best represents these values?
Answer:
im not sure, but i think its 88$-13$=75
Step-by-step explanation:
x-13$=75$=>x=88$
The annual 6th grade field trip costs $1,800. Write an
equation to represent the cost per student if the costs are
shared equally.
Answer:
$1,800 ÷ x= y
This is the best I can do without the knowledge of how many students are going.
A video game enthusiast is planning to attend a convention
where the latest technologies, products, and games will be show-
cased. There is a $75 registration fee to attend the convention.
She plans to stay at a hotel with a daily rate of $210 and spend
$30 on meals per day.
Create an equation to represent her expenses for the convention
based on the number of days she will be in attendance. Then,
use your equation to answer the following question.
How much will she spend to attend the convention for 3 days?
Answer:
240x + 75, $795 for 3 days
Step-by-step explanation:
$75 is not affected by the number of days she will be there, meanwhile, hotel and meal costs are. So, we will use x to represent the number of days and create an equation.
210x + 30x + 75
Then we can combine like terms
240x + 75
Using our new equation, we can solve for the total cost of 3 days.
240(3) + 75 = 795
3 days will cost $795
Jessie has three one-gallon containers. The first one has 1/5 of a gallon of juice, the second has 1/5 gallon of juice and the third has 1/5 gallons of juice. How many total gallons of juice does Jesse have?
use a number line to solve 5+7
Write the equation in function form:
8x + 4y = 20
It takes Natalie five hours to tar a roof. Imani can tar the same roof in ten hours. How long would it take them if they worked together? Round your answer to the nearest hundredth. A. 3.51 hours B. 2.77 hours C. 3.33 hours D.4.3 hours
Answer:
C. 3.33 hours
Step-by-step explanation:
Use the algebra work equation:
\(\frac{1}{tb}\) = \(\frac{1}{t1}\) + \(\frac{1}{t2}\), where tb is the time to work together, t1 is the time it takes one person, and t2 is the time it takes the other person
Plug in the values we know:
\(\frac{1}{tb}\) = \(\frac{1}{5}\) + \(\frac{1}{10}\)
\(\frac{1}{tb}\) = \(\frac{4}{20}\) + \(\frac{2}{20}\)
\(\frac{1}{tb}\) = \(\frac{6}{20}\)
20 = 6tb
3.33 = tb
So, it would take them 3.33 hours when working together.
84.4% of what number is 19.412?
Answer: 22.4402
Step-by-step explanation:
Answer:
84.4% of 23 is 19.412.
Step-by-step explanation:
Let the unknown number be x.
Now, 84.4% of x = 19.412.
∴ (84.4 ÷ 100) × x = 19.412.
By simplifying the equation,
x = (19.412 × 100) ÷ 84.4
x = 1941.2 ÷ 84.4
∴ x = 23
Thus, 84.4% of 23 is 19.412.
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Sarah enrolled $10,000 worth of debt with National Debt Relief. We negotiated with the creditors and reduced the debt by 50%. Sarah’s fee for our services was 25% of the enrolled debt ($10,000). How much did Sarah end up saving after reducing her debt and paying us our fee?
The total amount Sarah end up saving after reducing her debt and paying us our fee is $2,500.
PercentageAmount of debt = $10,000Percentage reduction = 50%Amount of reduction = 50% × $10,000
= 0.5 × 10,000
= $5,000
Cost of services = 25% of $10,000
= 25/100 × 10,000
= 0.25 × 10,000
= $2,500
Total savings = Amount of debt - Amount of reduction + Cost of services
= 10,000 - 5,000 + 2,500
= $2,500
Therefore, the total amount Sarah end up saving after reducing her debt and paying us our fee is $2,500.
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Please anyone that can help me
Answer:
\(|\frac{x}{y} |\)
Step-by-step explanation:
Pre-SolvingWe are given the following expression: \(\sqrt\frac{x^3y^5}{xy^7}\), where x > 0 and y > 0.
We want to simplify it.
To do that, we can first simplify what is under the radical, then take the square root of what is left.
Recall that when simplifying exponents, we don't want any negative or non-integer radicals left.
SolvingTo simplify what is under the radical, we can remember the rule where \(\frac{a^n}{a^m} = a^{n-m}\).
So, that means that \(\frac{x^3}{x} = x^2\) and \(\frac{y^5}{y^7} = y^{-2}\) .
Under the radical, we now have:
\(\sqrt{x^2y^{-2}}\)
Now, we take the square root of both exponents to get:
\(|xy^{-1}|\)
The reason why we need the absolute value signs is because we know that x > 0 and y > 0, but when we take the square root of of \(x^2\) and \(y^{-2}\) , the values of x and y can be either positive or negative, so by taking the absolute value, we ensure that the value is positive.
However, we aren't done yet; remember that we don't want any radicals to be negative, and the integer of y is negative.
Recall that if \(a^{-n}\), that is equal to \(\frac{1}{a^n}\).
So, by using that,
\(|x * \frac{1}{y} |\)
This can be simplified to:
\(|\frac{x}{y} |\)
Plz help i need help
Answer: answer is (-2.-4)
Step-by-step explanation:
Answer:(-2,-4)
Step-by-step explanation:
It is given that point P is located at (6,-4). Since point S is located 8 units to the left, you can subtract 6 by 8. You would end up with (-2,-4) as a result.
Rationalize the denominator of \(\frac{\sqrt{-36} }{(2-3i)+(3+2i)}\)
Answer:
all work is shown and pictured
Solve the formula for v: A=Z+vg
V=
Answer:
(a-z)/g =v
Step-by-step explanation:
Answer:
v = (A-Z)/g
Step-by-step explanation:
you would put A-Z over g
A = Z + vg
Subtraction property of equality
A-Z = vg
division property of equality
(A-Z)/g = v
Symmetric property of equality
v = (A-Z)/g
Beinggreat78, you really are GREAT like seriously. You chose the right name
Answer:
D
Step-by-step explanation:
becasue one is shaded in so it's is going to be a mixed number and there is 15 other shaded blocks so 15/100 is 3/20 so the answer is 1 and 3/20
Answer:
D
Step-by-step explanation:
All work and the answer is provided in the attached screenshot! :)
Write an explicit formula for an, the nth term of the sequence 30, 35, 40
Answer:
The sequence is increasing by 5 at each step. So, we can write:
a1 = 30
a2 = 30 + 5 = 35
a3 = 30 + 25 = 40
a4 = 30 + 35 = 45
a5 = 30 + 4*5 = 50
We notice that the nth term is given by:
an = 30 + (n-1)5
So, the explicit formula for the nth term is:
an = 25n + 5
Simply this 2^x +3 /-2^x
the simplest fοrm οf the given expressiοn is - (1+3/ 2ˣ).
What is pοlynοmials?Using variables and cοefficients, pοlynοmials are algebraic expressiοns. The term "indeterminates" is sοmetimes used tο describe variables. The terms Pοly and Nοminal, which tοgether signify "many" and "terms," make up the wοrd pοlynοmial.
When expοnents, cοnstants, and variables are cοmbined using mathematical οperatiοns like additiοn, subtractiοn, multiplicatiοn, and divisiοn, the result is a pοlynοmial (Nο divisiοn οperatiοn by a variable). The expressiοn is categοrized as a mοnοmial, binοmial, οr trinοmial based οn the number οf terms it cοntains.
\(2^x +3 /-2^x\)
divide by \(2^x\)
(1+3/ 2ˣ) / (1)
- (1+3/ 2ˣ).
Hence the simplest form of the given expression is - (1+3/ 2ˣ).
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