Answer:
The length of the trip is 780 miles
Step-by-step explanation:
Given
\(Sleep = 15\%\)
\(Distance\ Travelled = 663\)
Required
Determine the length of the trip
If Connor slept for 15% of the trip, then Connor was awake for 85%
This is calculated as:
\(Sleep + Awake = 100\%\)
\(15\% + Awake = 100\%\)
\(Awake = 100\% - 15\%\)
\(Awake = 85\%\)
Represent the required distance with D.
So the expression for when she was awake is:
\(85\% * D = 663\)
Make D the subject
\(D = \frac{663}{85\%}\)
Convert % to decimal
\(D = \frac{663}{0.85}\)
\(D = 780\)
Hence, the length of the trip is 780 miles
Given this explicit equation, what is the common difference?
f(n)=8n+2
Answer:
d = 8Step-by-step explanation:
Common difference is the difference between two consecutive terms:
d = f(2) - f(1)d = 8*2 + 2 - 8*1 - 2 = 16 - 8 = 8Or you can use the slope of the line as common difference, which is 8.
Step-by-step explanation:
\(we \: want \: to \: find \: commen \: differe \: nce \\ so \: put \: n= 1 \: and \: n = 2 \\ then \: calculate \: its \: difference \\ then \\ f(n) = 8n + 2 \\ f(1) = 8 \times 1 + 2 = 8 + 2 = 10 \\ f(2) = 8 \times 2 + 2 = 16 + 2 = 18 \\ f(2) - f(1) = 18 - 10 = 8 \\ 8is \: the \: commen \: difference \\ thank \: you\)
How many bases \($b$\) are there such that \($663_b$\) is prime?
Answer:
none
Step-by-step explanation:
We assume you intend positive rational bases.
\(663_b\) is divisible by 3, so cannot be prime.
Please help me with the questions 4-9, thank you in advance! :)
The radius is 8 inches. What is the circumference?
Answer:
50 inches.
Step-by-step explanation:
Which equals cos A to the nearest hundredth?
0
9.5
11
B
O 0.86
O 1.58
O 0.55
O 0.63
Answer:
cosA ≈ 0.55
Step-by-step explanation:
cosA = \(\frac{adjacent}{hypotenuse}\) = \(\frac{AC}{AB}\) = \(\frac{6}{11}\) ≈ 0.55 ( to the nearest hundredth )
Let u = (1,0, -1), v = (4,3,-2), and w = (2, 3, -2). Find the orthogonal projection of w into the plane spanned by the vectors u and v. Show that the matrix A is orthogonal if and only if its transpose A⁻ is orthogonal.
The transpose of A⁻¹ is the inverse of the transpose of A⁻¹, which implies that if A⁻¹ is orthogonal, then A is orthogonal. Therefore, we have shown that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.
To find the orthogonal projection of vector w into the plane spanned by vectors u and v, we need to calculate the projection vector proj_w(uv).
First, we calculate the normal vector n of the plane. The normal vector is obtained by taking the cross product of vectors u and v:
n = u x v
= (1, 0, -1) x (4, 3, -2)
The cross product can be calculated as follows:
n = ((0)(-2) - (-1)(3), (-1)(4) - (1)(-2), (1)(3) - (0)(4))
= (-3, -6, 3)
Next, we normalize the normal vector n to obtain the unit normal vector n:
n = n / ||n||
= (-3, -6, 3) / √(9 + 36 + 9)
= (-3, -6, 3) / √54
= (-1/√6, -2/√6, 1/√6)
Now, we can calculate the projection of vector w onto the plane using the formula:
proj_w(uv) = w - ((w · n) / (n · n)) * n
The dot product of w and n is given by:
w · n = (2)(-1/√6) + (3)(-2/√6) + (-2)(1/√6)
= -2/√6 - 6/√6 - 2/√6
= -10/√6
The dot product of n and n is:
n · n = (-1/√6)(-1/√6) + (-2/√6)(-2/√6) + (1/√6)(1/√6)
= 1/6 + 4/6 + 1/6
= 6/6
= 1
Substituting these values into the projection formula, we have:
proj_w(uv) = (2, 3, -2) - ((-10/√6) / 1) * (-1/√6, -2/√6, 1/√6)
= (2, 3, -2) + (10/√6)(-1/√6, -2/√6, 1/√6)
= (2, 3, -2) + (-10/6, -20/6, 10/6)
= (2, 3, -2) + (-5/3, -10/3, 5/3)
= (2 - 5/3, 3 - 10/3, -2 + 5/3)
= (1/3, 1/3, -1/3)
Therefore, the orthogonal projection of vector w into the plane spanned by vectors u and v is (1/3, 1/3, -1/3).
Now, let's prove the statement that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.
To prove this, we need to show two conditions:
If A is orthogonal, then A⁻¹ is orthogonal:
If A is orthogonal, it means that A · A⁻¹ = I, where I is the identity matrix.
Taking the transpose of both sides, we have (A · A⁻¹)ᵀ = Iᵀ, which simplifies to (A⁻¹)ᵀ · Aᵀ = I.
This shows that the transpose of A⁻¹ is the inverse of the transpose of A, which implies that if A is orthogonal, then A⁻¹ is orthogonal.
If A⁻¹ is orthogonal, then A is orthogonal:
If A⁻¹ is orthogonal, it means that (A⁻¹) · (A⁻¹)ᵀ = I, where I is the identity matrix.
Taking the transpose of both sides, we have ((A⁻¹) · (A⁻¹)ᵀ)ᵀ = Iᵀ, which simplifies to ((A⁻¹)ᵀ) · (A⁻¹) = I.
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Let three types of consulting services that audit firms are now prohibited from providing to clients that are public companies
The three types of consulting services that audit firms are now prohibited from providing to clients that are public companies are:
1. Bookkeeping services: Audit firms are prohibited from providing bookkeeping services to their audit clients. Bookkeeping involves the recording, organizing, and maintaining of financial transactions.
By prohibiting audit firms from providing bookkeeping services, it helps to ensure independence and objectivity in the audit process. This separation reduces the risk of potential conflicts of interest that could compromise the integrity of the audit.
2. Legal services: Audit firms are also prohibited from providing legal services to their audit clients. Legal services include activities such as drafting legal documents, providing legal advice, and representing clients in legal proceedings.
The prohibition on providing legal services aims to maintain independence and prevent any potential conflicts of interest that could arise if the audit firm were to also provide legal advice or services to the audited company.
3. Financial information systems design and implementation: Audit firms are further prohibited from designing and implementing financial information systems for their audit clients.
This involves the development and implementation of computerized systems that record and process financial data. The prohibition on providing financial information systems design and implementation services helps to avoid any potential bias or lack of objectivity in the audit process,
as the audit firm should remain independent and not be involved in the design and implementation of the systems they are auditing.
By prohibiting audit firms from providing these consulting services, it helps to ensure that the audit process is conducted objectively and independently, without any conflicts of interest.
This enhances the credibility and reliability of financial statements and promotes transparency and trust in the financial markets.
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area of a isocles triangle whose both sides are 5 cm and one side 4cm
Answer:
9.17cm (3s.f.)
Step-by-step explanation:
Using Pythagoras Theorem,
5² = 2² + (Height of Triangle)²
Height of Triangle = 4.5826cm (5s.f.)
Area = ½ × 4 × 4.5826
= 9.1652cm (5s.f.)
= 9.17cm (3s.f.)
If 2 bags or rice cost $3 then how much would 20 bags cost?
Answer:
the answer would be it costs $30 for 20 bags of rice
Step-by-step explanation:
divide $3 by 2 to get $1.50 and then multiply $1.50 by 20 to get $30
Answer:
30 dollars
Step-by-step explanation:
2 x 10 equals 20, so multiply 10 by 3 and you get 30.
round to the nears hundrend .7,666
Answer:
.767
Step-by-step explanation:
0. ones, tens, hundreds, thousands
Parallel, Perpendicular, or Neither?
Answer:
perpendicular :)))))))))))))
Select all that apply.
Describe the transformations.
The yellow circle was translated left 2 units and up 2 units.
The yellow circle was reflected over both axes.
The yellow circle was reflected over the x-axis and translated left 2 units.
The yellow circle was reflected over the y-axis and translated up 2 units.
Answer:
the rise and run would be 2/1 so the transformation would be 2
Step-by-step explanation:
Kuta Software Infinite Algebra 1. Solving Systems of Equations by Substitution. Solve each system by substitution. 1) y=6x-11. -2x-3y=-7. -2x-3(60x-11)=-7
the solution to the system of equations is x = 2 and y = 1.
To solve the system of equations by substitution, we will solve one equation for one variable and substitute it into the other equation.
Given the system of equations:
1) y = 6x - 11
2) -2x - 3y = -7
Step 1: Solve equation (1) for y.
y = 6x - 11
Step 2: Substitute the value of y from equation (1) into equation (2).
-2x - 3(6x - 11) = -7
Step 3: Simplify and solve for x.
-2x - 18x + 33 = -7
-20x + 33 = -7
-20x = -7 - 33
-20x = -40
x = (-40)/(-20)
x = 2
Step 4: Substitute the value of x into equation (1) to find y.
y = 6(2) - 11
y = 12 - 11
y = 1
Therefore, the solution to the system of equations is x = 2 and y = 1.
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The solution to the system of equations y = 6x - 11 and -2x - 3y = -7 is x = 2 and y = 1. This is achieved by substituting y into the second equation, simplifying, and solving for x, then substituting x back into the first equation to solve for y.
Explanation:To solve the system of equations y = 6x - 11 and -2x - 3y = -7 by substitution, we start by substituting the equation y = 6x - 11 into the second equation in place of y, giving us -2x - 3(6x - 11) = -7. Next, simplify the equation by distributing the -3 inside the parentheses to get -2x - 18x + 33 = -7. Combine like terms to get -20x + 33 = -7. Subtract 33 from both sides to obtain -20x = -40, and finally, divide by -20 to find x = 2.
Once we find the solution for x, we substitute it back into the first equation y = 6x - 11. Substituting 2 in place of x gives y = 6*2 - 11, which simplifies to y = 1.
Therefore, the solution to the system of equations is x = 2 and y = 1.
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Consider the following data drawn independently from normally distributed populations: (You may find it useful to appropriate table: z table or t table)
xˉ1 = −17.1
s1^2 = 8.4
n1=22
xˉ2 = −16.0
s2^2 = 8.7
n2 = 24
a. Construct the 90% confidence interval for the difference between the population means. Assume the population va unknown but equal. (Round final answers to 2 decimal places.)
confidence interval is __ to __
The 90% confidence interval for the difference in the population means is -2.51 to 0.31
Calculating the 90% confidence interval for the population mean differenceFrom the question, we have the following parameters that can be used in our computation:
xˉ₁ = −17.1
s₁² = 8.4
n₁ = 22
xˉ₂ = −16.0
s₂² = 8.7
n₂ = 24
Calculate the pooled variance using
P = (df₁ * s₁² + df₂ * s₂²)/df
Where
df₁ = 22 - 1 = 21
df₂ = 24 - 1 = 23
df = 22 + 24 - 2 = 44
So, we have
P = (21 * 8.4 + 23 * 8.7)/44
P = 8.56
Also, we have the standard error to be
SE = √(P/n₁ + P/n₂)
So, we have
SE = √(8.56/22 + 8.56/24)
SE = 0.86
The z score at 90% CI is 1.645, and the CI is calculated as
CI = (x₁ - x₂) ± z * SE
So, we have
CI = (-17.1 + 16.0) ± 1.645 * 0.86
This gives
CI = -1.1 ± 1.41
Expand and evaluate
CI = (-2.51, 0.31)
Hence, the confidence interval is -2.51 to 0.31
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The equation of a line is given below.
6x+2y=4
Find the slope and the y-intercept. Then use them to graph the line
Hence, in answering the stated question, we may say that We can travel slope intercept down 3 units and right 1 unit to acquire another point on the line because the slope is -3.
what is slope intercept?The intersection point in mathematics is the point on the y-axis where the slope of the line intersects. a point on a line or curve where the y-axis intersects. The equation for the straight line is Y = mx+c, where m represents the slope and c represents the y-intercept. The intercept form of the equation emphasises the line's slope (m) and y-intercept (b). The slope of an equation with the intercept form (y=mx+b) is m, and the y-intercept is b. Several equations can be reformulated to seem to be slope intercepts. When y=x is represented as y=1x+0, the slope and y-intercept are both set to 1.
We must solve for y in order to find the slope-intercept form of the equation:
6x + 2y = 4
2y = -6x + 4
y = -3x + 2
As a result, the slope is -3 and the y-intercept is 2.
To graph the line, first plot the y-intercept at the point (0, 2). The slope can then be used to find another point on the line. We can travel down 3 units and right 1 unit to acquire another point on the line because the slope is -3.
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Calculate the test statistic 2
A local retailer currently schedules employees based on the assumption that they serve customers uniformly throughout the week (the same number each day). Management is starting to question this assumption and decides to collect data on the number of customers served each day of the week to
perform a Chi-Square goodness-of-fit test at a 5% significance level.
Monday Tuesday Wednesday Thursday Friday
Number Served 40 33 35 32 60
Total 200
Provided the assumptions of the test are satisfied, calculate the test statistic 2
The value of a Chi-Square goodness-of-fit test at a 5% significance level is 13.45
We need to perform a Chi-Square goodness-of-fit test at a 5% significance level.
First we need to calculate the expected count
expected value = ∑(x)/n
= (40 + 33 + 35 + 32 + 60)/5
= 200/5
= 40
Now we need tocalculate the test statistic value
Observed expected O - E (O - E)^t/E %
40 40 0 0 0
33 40 -7 1.225 9.11
35 40 -5 0.625 4.65
32 40 -8 1.6 11.90
60 40 20 10 74.35
Chi square test is 13.45
Therefore, the value of test statistics is 13.45.
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The price of an object with 13%value added tax is
Rs. 5763. What will be the value added tax amount? Find
9514 1404 393
Answer:
₹663
Step-by-step explanation:
The ratio of the tax to the total is ...
13%/(100%+13%) = VAT/5763
VAT = 5763(0.13/1.13) = 663
The value added tax is ₹663.
What are the components when A=6.00 and the vector makes an angle θ2=120∘ with respect to the positive x-axis? What are the components when A=3.00 and the vector makes an angle θ3=30.0∗ with respect to the negative x axis'?
The components of the vector when A = 3.00 and θ₃ = -30.0° are (2.60, -1.50).
The question requires us to find the components of vectors in two different cases.
We are given the magnitude and angle of each vector with respect to the positive or negative x-axis.Let us start with the first vector.
Given,A = 6.00θ₂
= 120°
We can find the components using the following equations:
x = Acosθ
y = Asinθ
Substituting the values, we get:
x = 6.00cos120°
y = 6.00sin120°
Now, let us simplify these expressions.
x = -3.00
y = 5.20
Therefore, the components of the vector when
A = 6.00 and
θ₂ = 120° are (-3.00, 5.20).
Let us move on to the second vector. Given,
A = 3.00θ₃
= -30.0°
We can find the components using the following equations:
x = Acosθ
y = Asinθ
Substituting the values, we get:
x = 3.00cos(-30.0°)
y = 3.00sin(-30.0°)
Now, let us simplify these expressions.
x = 2.60y
= -1.50
Therefore, the components of the vector when
A = 3.00 and
θ₃ = -30.0° are (2.60, -1.50).
Given,
A = 6.00,
θ₂ = 120°,
A = 3.00,
θ₃ = -30.0°
We use the equations: x = Acosθ
y = Asinθ
For the first vector, we get:
x = 6.00cos120°
y = 6.00sin120°
Simplifying these expressions, we get:
x = -3.00
y = 5.20
Therefore, the components of the vector when
A = 6.00 and
θ₂ = 120° are (-3.00, 5.20).
For the second vector, we get:
x = 3.00cos(-30.0°)
y = 3.00sin(-30.0°)
Simplifying these expressions, we get:
x = 2.60
y = -1.50
Therefore, the components of the vector when A = 3.00 and θ₃ = -30.0° are (2.60, -1.50).
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Katie has a tin of chocolates.
There are 80 chocolates in the tin.
45% of the chocolates have toffee in the middle.
Work out the number of chocolates that have toffee in the middle.
2) The Club Auto Parts Company has just recently been organized. It is expected to experience no growth for the next 2 years as it identifies its market and acquires its inventory. However, Club will grow at an annual rate of 5% in the third and fourth years and, beginning with the fifth year, should attain a 10% growth rate which it will sustain thereafter. The last dividend paid was $0.50 per share. Club has a cost of capital of 12%. What should be the present price per share of Club common stock?
Answer:
$20.84
Step-by-step explanation:
div 1 = $0.50
div 2 = $0.50
div 3 = $0.50 x 1.05 = $0.525
div 4 = $0.525 x 1.05 = $0.55125
years 5 and beyond we need to use the growing perpetuity formula:
stock price = [div 4 x (1 + g)] / (r - g) = ($0.55125 x 1.1) / (12% - 10%) = $30.32
now to determine the current value of the stocks we must calculate the present value of the future dividends and stock price:
stock price = $0.50/1.12 + $0.50/1.12² + $0.525/1.12³ + $0.55125/1.12⁴ + $30.32/1.12⁴ = $0.45 + $0.40 + $0.37 + $0.35 + $19.27 = $20.84
etta is taking notes to create a webpage about healthy eating. rq: why have childhood obesity rates tripled in the united states over the past three decades? - portion sizes have increased and calorie intake has increased 31 percent. - children now eat an average of three snacks per day (up from one per day). - children and adolescents spend an average of 7.5 hours per day watching television or on the internet. what should she add to make these notes more organized?
Etta needs to add the source of the information to better arrange these notes.
A note is a place where information about a specific item is recorded for later reference. The main goals of taking notes are to promote active learning and create study materials for tests. You should be able to organise material into an understandable format that will aid in your learning process by developing note-taking skills.
As a result, it is clear from the question that Etta is making notes for the purpose of creating a webpage about healthy eating. Once her notes have been organised with the relevant facts and information, Etta will need to cite her sources.
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Evaluate 12 - 6+ (14 – 8)^2=
. (1 point)
Answer:
the answer is 42
Step-by-step explanation:
12-6+(14-8)^2
12-6(6)^2
12-6+36
=42
Jina worked 37 hours last month and earned 59 per hour. She spent $15 of her earnings since then. How much money does she have left?
Answer:
$6.83
Step-by-step explanation:
37 x 59 = 2183
Because it is dollars you need to divide it by 100:
$21.83 - 15 = 6.83
It is roughly 8100 miles to fly from California to Australia. If it takes the airplane 15 hours to reach its destination of Australia, what was the average speed of the airplane in feet per hour?
Answer:
540 miles an hour or 2,851,200 Feet an hour
Step-by-step explanation:
Simplify the expression. Write your answer as a power. (thank you)
Answer:
.... The answer is (3.8)^12
The ratio x: y is 1:3
Which of the following statements are correct?
A x is 1/3 of y
B y is 3/4 of (x + y)
x is 1/4 of y
y is 3/4 of x
Answer:
Option A
Step-by-step explanation:
x : y = 1 : 3
This can be also written as
\( \frac{x}{y} = \frac{1}{3} \)
Multiplying y on both the sides
\( = > \frac{x}{y} \times y = \frac{1}{3} \times y\)
\( = > x = \frac{1}{3} \times y\)
Hence , x is one-third of y
Answer:
A and B
x is \(\frac{1}{3}\) of y
AND
y is \(\frac{3}{4}\) of (x+y)
Step-by-step explanation:
x:y is 1:3
=> y is bigger than x
=> y is 3x bigger than x
=> y = 3 lots of x
=> \(y =\) \(3x\)
=> \(\frac{y}{3}\) \(= x\)
=> \(\frac{1}{3} y\) \(= x\)
So x is \(\frac{1}{3}\) of y
y is \(\frac{3}{4}\) of (x+y)
If x = 1 and y = 3 (substitute in values)
=> 3 is \(\frac{3}{4}\) of (4)
=> 3 is \(\frac{3}{4}\)(4)
=> 3 is (\(\frac{3}{4}\)x4)
=> 3 = 3
Therefore, y is \(\frac{3}{4}\) of (x+y) is true
So the answers are:
x is \(\frac{1}{3}\) of y
AND
y is \(\frac{3}{4}\) of (x+y)
What is the approximate area of the shaded sector in the circle shown below
Answer: B
Step-by-step explanation:
The area of a circle is pi*radius^2. But only a diameter is given, so in order to find the radius, you must divide the diameter by 2:
3.6/2 = 1.8
Now, you can plug the radius, 1.8, into the equation pi*radius^2 (\(\pi r^{2}\)):
\(\pi (1.8)^2 = \pi(3.24)\) = about 10.18
Lastly, you must divide the area 10.18 by 2 because you are looking for only half the area.
10.18/2 = 5.09
The area of the shaded region is 5.09 square cm if the radius of the circle is 1.8 cm, option (B) is correct.
What is a circle?It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
We have:
The diameter of the circle = 3.6 cm
The radius of the circle = 3.6/2 = 1.8 cm
Area of shaded region = (180/360)π(1.8)²
Area of the shaded region = 5.089 ≈ 5.09 square cm
Thus, the area of the shaded region is 5.09 square cm if the radius of the circle is 1.8 cm, option (B) is correct.
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The volume of a pyramid varies jointly with the base area of the pyramid and its height. The volume of one pyramid is cubic inches when its base area is square inches and its height is inches. What is the volume of a pyramid with a base area of square inches and a height of inches?.
The volume of a pyramid is 60 inches.
Given that,
A pyramid's volume varies in tandem with both its base area and height. When a pyramid's base is square inches and its height is inches, its volume is cubic inches.
V1 = 35 cubic inches
A1 = 15 square inches
h1 = 7 inches
A2 = 36 inches
h2 = 5 inches
To find : What is V2
The following formula is used to determine a pyramid's volume:
V = (Base Area × Height)/3
V2 = (36 square inches multiplied by 5)/3
V2 = 60 cubic inches
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i know im dumb srry but help plz....
If two angles are complementary, then the
sum of their measures is 90 degrees.
We can find the m<B by taking 90 minus the measure of <A.
So here, we have 90 - 15 which is 75.
So m<A is 75 degrees.
Use the table to write a linear function that relates y to x.
Using the table the linear function that relates y to x is y = 2x/3 + 5
What is linear function?The term linear function refers to functions that represents a straight line in a coordinate plane. Linear functions have variables have do not exponents
How to write the linear functionThe equation of linear function is usually of the form y = mx + c.
c is the y intercept and the value of y when x = 0
Studying the table we start from when x = 0 and y = 5 to solve
hence c =5
using x = -3 and y =- 3
y = mx + c
3 = -3m + 5
3 - 5 = 3m
-2 = 3m
m = -2/3
Therefore the required equation is y = -2x/3 + 5
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