To approximate the value of √4.7 within 10^-5 using the Taylor series expansion, we need to determine the number of terms required. We can use the Taylor series expansion of the square root function centered at a value of interest (a) to calculate the approximate value. By evaluating the derivatives of the function and plugging them into the Taylor series formula, we can determine the number of terms needed and estimate the error in the approximation.
To begin, we calculate the derivatives of the square root function. Since we are approximating the value of √4.7, we can choose a = 4.7. By evaluating the derivatives of the square root function at a = 4.7, we can calculate the nth term of the Taylor series expansion using the formula:
nth term = f^(n)(a) / n! * (x - a)^n
Using the given table, we can calculate the nth term for n = 0, 1, 2, 3, 4, 5, and 6. Additionally, we can evaluate the cumulative sum of the Taylor series approximation and check if it is within the desired tolerance of 10^-5.
To estimate the error in the approximation, we can use the absolute value of the first omitted term. By evaluating the (n+1)th term and calculating its absolute value, we can obtain an estimate of the error.
By analyzing the calculated terms and the cumulative sum, we can determine the number of terms required to approximate √4.7 within 10^-5. This number represents the order of the Taylor series expansion. The resulting approximate value of √4.7 can be obtained by evaluating the cumulative sum of the Taylor series at the desired number of terms.
In summary, the process involves calculating the derivatives, plugging them into the Taylor series formula, evaluating the terms, and checking the cumulative sum. The error estimate is obtained by evaluating the absolute value of the first omitted term. The final approximation and the number of terms required provide an accurate estimate of √4.7 within the desired tolerance.
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Show that each statement is false by providing a comterexample
Answer:
Step-by-step explanation:
One
Length = 16
Width = 1
Two
<P = 120
<Q = 30
<R = 30
Three
xy = 45
yz = 1
Four
<1 = 45
<2 = 45
Linda has to buy stickers, erasers, and a pencil. She can only spend $3. A sticker costs $0.35, an eraser costs $0.99, and a pencil costs $0.59. Can Linda buy 3 stickers and 2 erasers?
[Use the inequality 0.35x + 0.99y + 0.59 ≤ 3]
Answer:
No
Step-by-step explanation:
Step 1: Understand the inequality
The inequality 0.35x + 0.99y + 0.59 ≤ 3 contains 2 variables 'x' and 'y'. We can see the 'x' is multiplied by 0.35 which is the price of a sticker which means 'x' represents how many stickers Linda is buying. The 'y' is multiplied by 0.99 which is the price of a eraser which means 'y' is how many erasers Linda is buying. We ignore the 0.59 as that's the price for a pencil but Linda doesn't buy a pencil
Step 2: Sub in the values
\(0.35(3)+0.99(2)<3\\1.05+1.98<3\\3.03<3\)
Step 3: Interpret the answer
Because the equality isn't true we can conlude Linda doesn't have the money to buy 3 stickers and 2 erasers
Answer:
no
Step-by-step explanation:
0.35x3=$1.05
0.99x2=$1.98
add $0.59+$1.98+$1.05
=$3.62
Use the data table below to create the given scatter plot, then fill in the guided sentence below. I just need the sentence.
Using visual interpretation of the plot trend, the scatter plot shows positive correlation.
A positive correlation is depicted by a positive slope or trend line on a scatter plot. The trend of the scatter plot slopes upward which establishes a positive association.
If the slope is otherwise negative, such that the trend line slopes downward, then we have a negative association or relationship.
Therefore, the scatter plot shows positive relationship.
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Ariana 0.45 of the groups and Alex ate 35% of them if there was 18 grapes left how many were in the container at first
The original number of grapes present in the container was 50.35.
To determine the number of grapes Ariana ate.
then, we'll find the number of grapes Alex ate.
Finally, we'll use the remaining grapes to determine the original number of grapes present in the container.
Let us solve the problem now.
Let the original number of grapes be x. Ariana ate 0.45 of them.
Number of grapes Ariana ate = 0.45x
Alex ate 35% of the remaining grapes after Ariana ate.
Number of grapes Alex ate = 35% of (x - 0.45x)= 35/100(x - 0.45x)= 0.35(0.55x)= 0.1925x
The number of grapes remaining = 18.Number of grapes remaining after both Ariana and
Alex ate = x - 0.45x - 0.1925x= 0.3575x= 18
Hence, we can determine that:0.3575x = 18x = 18/0.3575x = 50.35
The original number of grapes present in the container was 50.35.
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2 Use a five-variable Karnaugh map to find the minimized SOP 15 expression for the following logic function: F(A,B,C,D,E) = Σm(4,5,6,7,9,11,13,15,16,18,27,28,31)
The minimized Sum of Products (SOP) expression for the given logic function F(A, B, C, D, E) with the specified minterms is obtained as f(A, B, C, D, E) = A'BCD'E' + A'B'C'D'E + A'BC'D'E + ABCD'E.
To find the minimized SOP expression using a five-variable Karnaugh map, we first plot the minterms on the map. The minterms are given as m(4,5,6,7,9,11,13,15,16,18,27,28,31). Next, we group adjacent 1s on the Karnaugh map to form groups of 2, 4, 8, or 16 cells. Each group represents a term in the minimized SOP expression.
After grouping the 1s on the Karnaugh map, we can identify the essential prime implicants, which are the groups that cover a single minterm. In this case, the group covering m(31) is an essential prime implicant.
Next, we fill in the remaining cells that are not covered by the essential prime implicant with 1s and group them to form additional terms. We can choose the groups that cover the remaining minterms while minimizing the number of terms in the expression.
Using these groups, we can generate the minimized SOP expression, which is f(A, B, C, D, E) = A'BCD'E' + A'B'C'D'E + A'BC'D'E + ABCD'E. This expression represents the logic function F(A, B, C, D, E) with the given minterms in a minimized form using the Sum of Products (SOP) representation.
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A cube has 5 green sides and 1 red side. If you were to roll the cube 10 times, what would be the approximate probability of rolling 2 reds and 8 greens?
0 20. 0%
O 14. 3%
O 38. 5%
O 29. 1%
The approximate probability of rolling 2 reds and 8 greens is 14.3%. The answer is O 14.3%.
The probability of rolling a red side is 1/6 and the probability of rolling a green side is 5/6. The number of ways of getting 2 reds and 8 greens in any order is given by the binomial coefficient:
C(10, 2) = 45
The probability of getting 2 reds and 8 greens in any order is:
(1/6)^2 * (5/6)^8 * C(10, 2) ≈ 0.143 = 14.3%
Therefore, the approximate probability of rolling 2 reds and 8 greens is 14.3%. The answer is O 14.3%.
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In the diagram of
△
△LPN below, QM
∥
∥PN, LQ=5, QP=35, and LM=10. What is the length of LN?
One letter is selected from the word " UNNECESSARY" .Find the probability of (a)an 'R' (b)an'E' (c)an 'O' (d)a 'C
Answer: A. 1/11
B. 2/11
C. 0
D. 1/11
Hope this helps!
The wire is 25 feet long is stretched from the top of a flagpole to the ground at a point 15 feet from the base of the pole .how high is the flag pole
Answer:
20 feet
Step-by-step explanation:
Using Pythagoras rule:
25^2 - 15^2
625 - 225
400
√400 = 20 feet
Use cylindrical coordinates to evaluate ∫∫∫ E√x^2 + y^2 dV, where E is the region inside the cylinder x^2 + y^2 = 25 and between the planes z = 1 and z = 4.
The integral Ex2 + y2 dV, where E is the area within the cylinder x2 + y2 = 25 and between the planes z = 1 and z = 4, may be evaluated using cylindrical coordinates. The integral may be assessed as 5(2)(3) = 30 by rewriting it as 0 5 0 2 1 4 E d d dz.
Cylindrical coordinates can be used to evaluate integrals such as the one given. In cylindrical coordinates. The integral can then be written as ∫∫∫ E√x^2 + y^2 dV, where E is the region inside the cylinder \(x^2 + y^2 = 25\) and between the planes z = 1 and z = 4.Using the properties of cylindrical coordinates, the integral can be rewritten as ∫ 0 5 ∫ 0 2π ∫ 1 4 Eρ dρ dθ dz. This can be evaluated using the triple integral ∫ 0 5 ∫ 0 2π ∫ 1 4 ρ dρ dθ dz. The integral can then be evaluated as follows:
= 5(2π)(3)
= 30π
Therefore, the integral ∫∫∫ E√\(x^2 + y^2\) dV can be evaluated as 30π.
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a random survey. of seventh and eighth graders was conducted to determine the number of each student has the results are shown statement about populations is not supported by information in the graph
Answer:
I believe the answer is 8th graders.
Step-by-step explanation:
When solving a system of linear equations, try to algebraically form one equation that has only one variable. T/F
False. Solving a system of linear equations requires solving for multiple variables.
To solve for a single variable, you would only need to solve one equation.
To solve a system of linear equations, you need to use methods such as elimination, substitution, or graphing. For example, consider the system of equations:
3x + y = 7
2x - y = 4
To solve this system, you could use elimination by adding the equations together. This would give you the equation 5x = 11. To solve for x, you would then divide both sides by 5, giving you x = 11/5.
Once you have solved for x, you can substitute this value into either of the original equations to solve for y. In this example, substituting 11/5 for x into the first equation would give you 3(11/5) + y = 7. Simplifying this equation gives you y = -2/5.
Therefore, the solution to this system of linear equations is x = 11/5 and y = -2/5.
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Which congruence theorem can be used to prove △abc ≅ △def? aas asa hl sas
As per the congruence theorem, we have proved that ΔABC ≅ΔDEF.
In math congruence theorem states that if all the three sides of one triangle are equal to all the three sides of another triangle, then both the triangles are congruent to each other.
Here we need to prove ΔABC ≅ΔDEF by using the congruence theorem.
Here we have given that ΔABC and ΔDEF,
=> ∠B≅∠E [right angle]
So, we have obtained that
=> ∠A≅∠D
As we know that there is two angles and one non included side of ΔABC is congruent the two corresponding angles and one non- included side of ΔDEF, therefore, by AAS congruence rule.
So, based on the given fact we have identified that
=> ΔABC ≅ΔDEF
Therefore, the AAS congruence postulate defined that the triangles are congruent if two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.
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-(3z+4)=6z-3(3z+2) how do you determine whether or not the answer is no solution or identity?
The equation on solving by factoring method yields no solution.
In this question,
A no solution equation is also known as contradiction. This type of equation is never true, no matter what we replace the variable with. There is no value that will ever satisfy this type of equation.
The equation is -(3z+4)=6z-3(3z+2)
Solving the equation by factoring gives,
⇒ -(3z+4) = 6z-3(3z+2)
By distributive property,
⇒ -3z - 4 = 6z - 3(3z) - 3(2)
⇒ -3z - 4 = 6z - 9z - 6
⇒ -3z - 4 = -3z - 6
On rearranging the equation,
⇒ -3z + 3z = -6 + 4
⇒ 0 = -2
Here LHS is not equal to RHS. Thus the equation on solving by factoring method yields no solution.
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a recent survey reported that small businesses spend 24 hours a week marketing their business. a local chamber of commerce claims that small businesses in their area are not growing because these businesses are spending less than 24 hours a week on marketing. the chamber conducts a survey of 58 small businesses within their state and finds that the average amount of time spent on marketing is 22.7 hours a week. assuming that the population standard deviation is 6.1 hours, is there sufficient evidence to support the chamber of commerce’s claim at the 0.02 level of significance?
chamber of commerce’s claim at the 0.02 level of significance, z = -1.75
What is z test?
If the data is distributed normally, a z test can be used to determine whether the means of two populations differ from one another. The z test statistic's value must be determined, together with the null hypothesis and alternative hypothesis setups, for this reason. On the z critical value, the decision criterion is based. The distribution graph is divided into acceptance and rejection zones during hypothesis testing by the z critical value. The null hypothesis can be rejected if the test statistic lies inside the rejection region; otherwise, it cannot.
a recent survey reported that small businesses spend 24 hours a week marketing their business.
these businesses are spending less than 24 hours a week on marketing. the chamber conducts a survey of 58 small businesses within their state and finds that the average amount of time spent on marketing is 22.7 hours a week.
assuming that the population standard deviation is 6.1 hours.
Given n = 93, u =24, x' = 23, α=5.5
z = x'- u / α(/√n) = (23-24/5.5/√5) = -1.75
Hence, chamber of commerce’s claim at the 0.02 level of significance, z = -1.75
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Please I need this help?
Answer:
6.35
Step-by-step explanation:
Need help asap.
The GDP of a country goes down as people spend more money and businesses make more products.
True or false
Answer:
I'm gonna say false
GDP or Gross Domestic Profit is the money that is being spent/made inside the country. So it stands to reason that if people are spending more, the GDP would go up.
Hope this helps!
arrange the given steps in the correct order to prove that 3n6, 3^k 3^k+1 < (k+1)!
3^k+1 < (k+1) * 3^k
For n = 7.3^7 = 2187 < 7! + 5040
3^k=1 < (k+1) * k!
3^k+1 = 3 * 3^k
The correct order of steps to prove the inequality 3^n < (n+1)! for n = 7 is as follows: 3^k < (k+1) * k!, 3 * 3^k = 3^(k+1), 3^(k+1) < (k+1) * 3^k; For n = 7, 3^7 = 2187: 2187 < 7! + 5040.
To prove the inequality 3^n < (n+1)! for n = 7, we can follow these steps:
Start with the assumption that 3^k < (k+1) * k! is true for some positive integer k.
Multiply both sides of the inequality by 3 to get 3^(k+1) < 3 * (k+1) * k!.
Simplify the right side to obtain 3^(k+1) < (k+1) * (k+1) * k!.
Rewrite (k+1) * (k+1) as (k+1)^2.
By substitution, we have 3^(k+1) < (k+1)^2 * k!.
Now, consider the case where n = 7. We substitute k = 6 in the inequality.
Evaluating both sides of the inequality for n = 7, we find that 3^7 = 2187.
Calculate (7+1)! = 8! = 40320.
Compare the values: 2187 < 40320.
Since 2187 is indeed less than 40320, the inequality holds true for n = 7.
Therefore, we have successfully shown that 3^n < (n+1)! for n = 7.
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Is line used to define an angle?
Yes, line is used to define an angle.
What is an angle measure?When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.
When two straight lines or rays intersect at a single endpoint, an angle is created.
The vertex of an angle is the location where two points come together.
The common point is referred to as the vertex.
The length of the angle formed when two rays or arms intersect at a common vertex is known as an angle measure in geometry.
A straight line is a straight angle.
Therefore, two lines are used to define an angle.
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Trigonometry to solve for missing angles or side
Answer:
Step-by-step explanation:
take 55 degree as reference angle
using tan rule
tan 55=opposite/adjacent
1.42=37/x
x=37/1.42
x=26.05
A sample of phosphorus-32 has a half-life of 14.28 days.
If 55 g of this radioisotope remain unchanged after approximately 57 days, what was the mass of the original sample?
:
Using the radioactive decay formula: A = Ao*2^(-t/h), where
A = resulting amt after t time
Ao = initial amt (t=0)
t = time
h = half-life of substance
The mass of the original sample of phosphorus-32 was approximately 717.7 grams.
To solve this problem, we can use the radioactive decay formula:
A = Ao * 2^(-t/h)
Where:
A = resulting amount after time t
Ao = initial amount (at t=0)
t = time
h = half-life of the substance
In this case, we are given that the half-life of phosphorus-32 is 14.28 days. We want to find the initial mass, represented by Ao.
After approximately 57 days, 55 g of phosphorus-32 remain unchanged. Let's plug these values into the equation:
55 = Ao * 2^(-57/14.28)
To solve for Ao, we can isolate it by dividing both sides of the equation by 2^(-57/14.28):
55 / 2^(-57/14.28) = Ao
Using a calculator to evaluate 2^(-57/14.28), we find that it is approximately 0.07666.
Therefore, the initial mass, Ao, is:
Ao = 55 / 0.07666 ≈ 717.7 g
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I NEED ANSWER ASAP I WILL GIVE BRAINLIEST IF RIGHT
Question 9
3 pts
2
1
3
4
If m_1 equals (4x + 2) and m-3 equals (5x - 15), what is the value of x?
16
0 14
15
17
Ann made $143 for 11 hours of work.
At the same rate, how many hours of work would she have to work to make $243
Answer:
22 hours
Step-by-step explanation:
So, 143 equals eleven hours. 143 plus 143 would equal 243. So, you have two 143s which means you should multiply the 11 hours by two. 11x2 equals 22.
Convert the following repeating decimal to a fraction
.01
Answer:
If this is the decimal: 0.0101010101 (going on forever), then the fraction is 1/99If this is the decimal: 0.011111111111 (but the 1's go on forever), then the fraction is 1/90I hope this helps!
Halla X
Para una practica de 11 mins q-q
Determine whether the given function is linear. If the function is linear, express the function in the form
f(x) = ax + b.
(If the function is not linear, enter NOT LINEAR. )
f(x) =
1
2
(5x − 3)
f(x) =
The given function is not linear as it does not satisfy the property of additivity. Therefore, it cannot be expressed in the form f(x) = ax + b.
To determine if the given function is linear, we need to check if it satisfies the two properties of linearity:
1. Additivity: f(x + y) = f(x) + f(y) for all x and y.
2. Homogeneity: f(cx) = cf(x) for all x and scalar c.
Let's check if f(x) = (1/2)(5x - 3) satisfies these properties:
Additivity:
f(x + y) = (1/2)(5(x + y) - 3) = (1/2)(5x + 5y - 3)
f(x) + f(y) = (1/2)(5x - 3) + (1/2)(5y - 3) = (1/2)(5x + 5y - 6)
Since (1/2)(5x + 5y - 3) is not equal to (1/2)(5x + 5y - 6), the function does not satisfy additivity, and therefore it is not linear.
So the answer is:
NOT LINEAR.
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will give brainliest please help
8+ 6t-3t+ t
Answer:
4(2+t)
Step-by-step explanation:
A term is a single mathematical expression. We can see in this expression there are four terms, each separated by an operation:
8, 6t, -3t, and 1.
Coefficients are the numbers that multiply variables. You can also just think of them as the number in front of any variable. Here we see we have two terms with variables:
6t, -3t
and therefore our coefficients are:
6, -3
Constants are numbers that are, well, constant - you could also just think of them as "normal" numbers. We can see in this expression you have two:
8, 1
Like terms are terms of the same type. We have two like terms with a variable in them:
6t, -3t
and two like terms that are constants:
8, 1
Which of the six trigonometric functions has a period of \(2\pi\) and passes through the point \((\pi, 0)\)?
Answer:
i need points rq thanks so much
Step-by-step explanation:
imma go waste these points now
Answer:
x
Step-by-step explanation:
Given AHAN = AJMS. If mZH = (3x + 22), mZA== (3x+22)", m_A = (2x+5)°, and m2J = (5x – 16)°,determine mZM.
PLEASE HELP ME OUT WITH METRIC CONVERSIONS!!!!!!
Answer:
1. 5,000,000
2. 0.05632
3. 0.00031
4. 2,200
5. 2,500
6. 0.157963
7. 1,114
8. 4.001
9. 8.88
10. 250.89 m = 250,890 mm
11. 63,360
12. 1.009
13. 1,000
14. 0.00005
15. 0.0000007 m = 0.0000000007
Step-by-step explanation:
Answer:
Step-by-step explanation:
5000km = 500000m
56.32ml = 0.05632l
0.0031mm = 0.00031cm
22Hg = 2200g
0.025kg = 25,000mg
157.963 = 0.157963km
1.114 = 1114ml
4001mg = 4.001g
0.888L = 8.88 Dl
0.25089km = 250.89m = 250,890mm
63.36g = 0.06336mg
1009dg = 1.009 Hg
100cm = 1000mm
0.05ml = 0.00005l