Determine the pH of 1 x 10^-2 the NaOH.
a. 2.0
b. 4.0
c. 8.0
d. 12.0

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

D BIOMASS ENERGY

Explanation:

Most biomass requires arable land to develop. This means

that land used for biofuel crops such as corn and soybeans

are unavailable to grow food or provide natural habitats.

Forested areas that have matured for decades (so-called

“old-growth forests”) are able to sequester more carbon

than newly planted areas.

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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Answer: 41.0

Explanation: When you multiply the two numbers you get 41 but you need to have the same amount of significant numbers as the number in the problem with the least significant numbers. I hope this helps

Answer:

The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.

Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law for the overall reaction : R = k[O₃]²/[O]

The equations are :

O₃  ---->   O₂  +  O   fast

O₃  +   O  --->  2O₃   slow

a) The overall reaction is given as :

2O₃  ---->   3O₂

b) The intermediates within the mechanism is O.

c)  The order with respect to each reactant is 2

d) slow step rate : k[O][O₃]

at equilibrium, kc = [O][O₂] / [O₃]

The rate law = R = k[O₃]²/[O]

Thus, Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law expression for the reaction : R = k[O₃]²/[O]

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Cations and anions have atomic masses that are almost identical to those of neutral elements. Ca(NO3)2 is an example of a formula. The formula/molecular mass is determined by adding the masses of the constituent elements in the right ratios.

How are the molecular mass and formula calculated?

By applying the relevant compound's chemical formula and atomic masses learned from the periodic table. The compound's formula or molecular mass is determined by adding the atomic masses in the right ratios. Which of the following statements best encapsulates the proper way to name a binary covalent compound? - With its roots and the prefix -ide, the second element is given a name.

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One mole of H₂ reacts with one mole of Cl₂ to give 2 moles of hydrogen chloride gas. The volume of H₂ that will completely react with Cl₂ is 22.4 litres.

In the International System of Units, the mole is the unit of amount of a substance. It is specified that the mole contains exactly 6.022 * 10²³ elementary particles such as atoms, ions or molecules, similar to how a dozen denotes twelve.

At standard temperature and pressure (STP), one mole of any gas occupies a volume of 22.4 litres. From the given equation, the molar ratio of hydrogen and chlorine is 1:1. Since 22.4 litres of chlorine gas is used, then similarly, 22.4 litres of hydrogen gas must also be used up to give 2 moles of the product, hydrogen chloride gas.

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10.8

7.2mol*3/2=10.8mol.

10.8 moles of H₂SO₄ is required for the reaction.

The balanced equation for the reaction is given below:

From the balanced equation above,

2 moles of Al required 3 moles of H₂SO₄.

Finally, we shall determine the number of mole of H₂SO₄ required to react with 7.20 moles of Al.

This can be obtained as follow:

From the balanced equation above,

2 moles of Al required 3 moles of H₂SO₄.

Therefore,

7.20 moles of Al will require = \(\frac{7.2 X 3}{2} \\\\\) = 10.8 moles of H₂SO₄

Thus, 10.8 moles of H₂SO₄ is required for the reaction.

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Answer:

Stretching is the lengthening and contraction is the shortening

Explanation:

Unless it's asking for eccentric as the stretching and concentric as the shortening

The answer is 1ml. The answer is 1ml because of calibration of this graduated cylinder

Answer:

1 mL

Explanation:

According to your definition, it is the difference between marked spaces divided by the # of spaces between marked values.

Difference between 2 marked values: 5 mL

# Of Spaces between marked values: 5

Calibration: 5 mL / 5 mL = 1 mL

Answer:

A

Explanation:

.75 + .25 + 1.25 = 2.25 atm

1 atm is 760 mm hg

2.25 * 760 = 1710 mm HG

Answer:

\(\huge\boxed{\sf 2.25\ atm = 1710\ mm\ of\ Hg}\)

Explanation:

Partial pressure of gas A = 0.75 atm

Partial pressure of gas B = 0.25 atm

Partial pressure of gas C = 1.25 atm

Total partial pressure = 0.75 atm + 0.25 atm + 1.25 atm

= 2.25 atm

We know that:

1 atm = 760 mm of Hg

Multiply 2.25 to both sides

2.25 atm  = 760 × 2.25 mm of Hg

2.25 atm = 1710 mm of Hg

\(\rule[225]{225}{2}\)

Answer:

16

Explanation:

Refer to the attachments

The binding energy of the electrons (also known as the work function of the surface) is determined as 2.43 x 10⁻¹⁹ J.

The binding energy of the electrons is also known as work function of the metal and it is calculated as follows;

Ф = E - K.E

where;

Ф = hf - 86.2 kJ/mol

Ф = hc/λ - 86.2 kJ/mol

Ф = (6.63 x 10⁻³⁴ x 3 x 10⁸ )/515 x 10⁻⁹   -  86.2 kJ/mol

Ф = 3.86 x 10⁻¹⁹ J - (86200 J/mol)/(6.02 x 10²³)

Ф = 3.86 x 10⁻¹⁹ J - 1.43  x 10⁻¹⁹ J

Ф = 2.43 x 10⁻¹⁹ J

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Answer:

                                                                2CO(g) + O2(g) ⇌ 2CO2(g)

Increasing the concentration of CO -         ↓         ↓                 ↑

Increasing the concentration of CO2 -       ↑         ↑                 ↓

Explanation:

The given reaction is

2CO(g) + O2(g) ⇌ 2CO2(g)

a) When the concentration of CO is increased, the stress is relieved as the reaction that consumes the added CO occurs more rapidly than its reverse reaction, for example., the forward reaction rate increases. The equilibrium will shift in favor of the product. However, the concentration of reactants (CO and O2) decreases and product concentration (CO2) increases.

b) When the concentration of CO2 is increased, the stress is relieved as the reaction that consumes the added CO2 occurs more rapidly than its reverse reaction, for example., the rate of backward reaction increases. The equilibrium will shift in favor of the reactant. Therefore, the concentration of reactants (CO and O2) increases, and the product concentration (CO2) decreases.

Hope this helps!

Answer:

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where:

P1 = 1 atm (pressure of nitrogen gas in the first container)

V1 = 300 cm^3 (volume of the first container)

T1 = 3°C + 273.15 = 276.15 K (temperature of the nitrogen gas in the first container, converted to Kelvin)

P2 = 0.8 atm (pressure of nitrogen gas in the second container)

V2 = ? (volume of the second container, what we want to find)

T2 = 25°C + 273.15 = 298.15 K (temperature of the nitrogen gas in the second container, converted to Kelvin)

Plugging in the values, we get:

(1 atm x 300 cm^3) / 276.15 K = (0.8 atm x V2) / 298.15 K

Simplifying and solving for V2, we get:

V2 = (1 atm x 300 cm^3 x 298.15 K) / (0.8 atm x 276.15 K)

V2 = 1309.5 cm^3

Therefore, the volume of the larger container is approximately 1309.5 cm^3.

The chemical name for the compound CH3CH₂CH₂CH3 is butane.

Alkanes are any acyclic saturated hydrocarbon with a carbon to carbon single bond e.g. methane, ethane etc.

Alkanes have a general molecular formula of CnH2n+2. The number of carbon atoms determines the name of the alkane member.

According to this question, a chemical compound with the molecular formula; CH3CH₂CH₂CH3 is given. This compound posseses 4 carbon atoms and 10 hydrogen atoms, hence, is butane.

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Answer:

When the concentration of a reactant increases, there will be more chemical present. Due to more reactant particles moving together, more collisions are allowed to happen and with that, the rate of the reaction is increased. So, the higher the concentration of reactants, the faster the reaction rate will be.

Hope this helped you! :)

Heat is added to ice at 0 °C. Explain why the temperature of the ice does not change. What does change?When heat is added to ice at 0°C, the temperature of the ice does not change. This happens because all the heat energy is used up in overcoming the intermolecular forces of attraction (hydrogen bonds) that exist between the water molecules in ice.

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Question: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution?

Explanation and answer:

2KHP + Ba(OH)2 ---> 2H2O + Ba(KP)2

you need 2 moles of KHP to neutralise 1 mole of Ba(OH)2

moles KHO = mass / molar mass  

= 2.43 g / 204.22 g/mol  

= 0.0118989 mol

moles Ba(OH)2 = 1/2 x moles KHP

= 0.005949 mol

Molarity Ba(OH)2 = moles / Litres

= 0.005949 mol / 0.0213 L

= 0.279 M (3 sig figs)

a) A combound which contains only Carbon and Hydrogen. There are covalent bonds between atoms. Hydrogen form one single bond and Carbon forms four covalent bonds. Carbon bonds can be single, double or triple bonds.

  All hydrocarbons are organic compounds, but organic compound can include atoms of other elements.

b)  Alkyne has a  covalent triple bond between two carbon atoms. Simplest alkyne is ethyne HCCH.  

b) Alkane contains only Carbon and  Hydrogen and there are single bonds

  between atoms. Simplest alkane is methane CH4.

c) An alkene has one double bond between Carbon atoms. Simplest

alkene is ethene  H2C=CH2.

Answer:

Bacteria can use sexual and asexual repoduction

Explanation:

The molecular formula of the compound is determined as P₂F₄.

Molecular formula tells us which atoms and how many of each type of atom are present in the molecule.

Molar mass of CaF₂ is 78.07 g/mol(0.2631 g  CaF₂) × (1 mol  CaF₂ / 78.07 g  CaF₂) = 0.00337 mol  CaF₂

2F- + Ca₂+ →  CaF₂

(0.00337 mol  CaF₂) × (2 mol F / 1 mol  CaF₂) = 0.00674 mol F

As, Molar mass of F is 18.9984 g/mol

So, (0.00674 mol F) × (18.9984 g F / 1 mol F) = 0.12805 g F

1 mmHg = 0.00131578947 atm

(97.3 mmHg) × (0.00131578947 atm / 1 atm) = 0.128 atm

(378 cm³) × (1L / 1000 cm³) = 0.378 L

Now, T = 77 + 273 = 350 K

As, PV = nRT

n(PxFy) = PV / RT

n(PxFy) = (0.128 atm × 0.378 L) / (0.0821 L atm mol-1 K-1 × 350 K) = 0.001684 mol

n(PxFy) = 0.001684 mol

n(PxFy) = m(PxFy) / M(PxFy)

M(PxFy) = m(PxFy) / n(PxFy) = (0.2324 g) / (0.001684 mol) = 138 g/mol

m(PxFy) = m(P) + m(F)

0.2324 g = m(P) + 0.12805 g

m(P) = 0.2324 - 0.12805 = 0.10435

m(P) = 0.10435 g

Molar mass of P is 30.9737 g/mol

so, (0.10435 g P) × (1 mol P / 30.9737 g P) = 0.003369 mol P

Now, n(P) : n(F) = 0.003369 mol : 0.00674 mol = 1 : 2

Therefore, empirical formula of PxFy is PF₂

Molar mass of PF₂ 68.9705 g/mol

Molecular formula of PxFy is ( PF₂)n

n = M(PxFy) / M( PF₂) = (138) / (68.9705) = 2

Therefore, the molecular formula of PxFy is P₂F₄.

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Cytoplasm: gel like environment which allows organelles to move about the cell

Golgi bodies: packages and ships materials out of the cell

Cell membrane: controls what goes in and out of the cell

Chloroplast: makes food for plant cells using sunlight

Lysosome: breaks down waste, food, and worn out cell parts

Mitochondria: breaks down food to release energy for the cell

Nucleus: contains the cell's DNA and is the control center of the cell

Endoplasmic reticulum: transports materials within cell; process lipids

Vacuole: stores water, waste and food

Ribosome: make proteins

From the question, we will need to assume the temperature don't change.

In this case, assuming the gas behaves as an ideal gas, we can use the Boyle's Law to answer.

The Boyle's Law says that the product of the pressure and volume of an ideal gas, at constant temperature, is a constant:

But the volume and pressure have to be on the same unit.

First, lets convert the final pressure of 2.50 atm to kPa. We can do that by multiplying the atm value by 101.325:

Now, we can apply the Boyle's Law:

So, its volume will be approximately 1.48 L.

There are numerous ways to determine whether lead is present in an ore. Atomic absorption spectroscopy is a popular approach. With this method, an ore sample is dissolved in acid and then atomized in a flame or plasma.

The sample's atoms will absorb light at particular wavelengths that are peculiar to the element under investigation. The amount of light absorbed can be used to calculate how much lead is present in the sample. Inductively coupled plasma mass spectrometry and X-ray fluorescence spectroscopy are further techniques. It is crucial to remember that these procedures call for specialized tools and training, thus they ought to only be carried out in a lab by qualified experts.

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Answer:

flooding

Explanation:

since heavy rainfall, if its greater than usual

this causes flooding

hope this helps:)

The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.

This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).

In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).

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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.

We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.

In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.

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